Hi all,
I have two data sets similar like below and wanted to merge them with variable
"deps". As this is a sample data with small sample size, I don't have any
problem using command merge. However, the actual data set has ~60,000
observations with a lot of repeated measures. For example, for a
The default row.names on a data.frame made by the core-R data.frame
function are of the the form c(NA, -NROW(dataFrame)). The dplyr package
has a 'data_frame' function that uses c(NA, +NROW(dataFrame)) instead. The
tibble package also has a data_frame function, but it uses the negative
length.
A
Always reply-to-all to keep the mailing list informed... I don't do private
consulting online.
You look like you have plain text worked out, but we still cannot run your
code.
Read the Posting Guide and [1]. You cannot attach Excel files here (and many R
users can't or won't do that anyway)
Dear,
You have to store your data as a Time-Series (ts), first. To define a column of
data as ts, you may use this:
library(timeSeries)Nile <- read.csv(file.choose(), header=F)#If your data is
monthly, you may define the frequency as 12, for annual ts set freq. as 1.
#If your data starts from for
Not reproducible. Use dput to generate R code form of your data along with the
code that gave you the error, and set the email to plain text only when you
send it so it doesn't get corrupted when the html is stripped on the mailing
list.
--
Sent from my phone. Please excuse my brevity.
On Jun
Your code is corrupt because you failed to send your email in plain text
format.
You also don't appear to have all data needed to reproduce the problem. Use the
dput function to generate R code form of a sample of your data.
--
Sent from my phone. Please excuse my brevity.
On June 17, 2016 1
Dear R users,
Can anyone help me with mann-kendall trend test? I tried to use the newest
packages 'trend', and the function mk.test, but had problems in applying
the input data.
For example, res <- mk.test(Nile), Nile is a time-series data. But when I
use my dataset, with one column which is a ti
By mistake, I sent it earlier to the wrong address.
-- Forwarded message --
From: Priyank Dwivedi
Date: 17 June 2016 at 14:50
Subject: Matrix Constraints in R Optim
To: r-help-ow...@r-project.org
Hi,
Below is the code snippet I wrote in R:
The basic idea is to minimize error b
And you can check what David and Jeff suggested like this:
intersect( df$COUNTRY, world_map$region )
If they have any values in common, that command will show them. (Note that
I said values in common, not countries in common.)
WARNING:
It appears that you have each country appearing more than on
> On Jun 17, 2016, at 1:06 PM, ch.elahe via R-help wrote:
>
> Hi all,
> I want to use world map in ggplot2 and show my data on world map. my df is:
>
>
>$ COUNTRY : chr "DE" "DE" "FR" "FR" ..
>
>$ ContrastColor : int 9 9 9 9 13 9 9 9 9 ..
>
>$ quant :
You should look at your own data before you post. The information in COUNTRY is
not the same as the information in region.
Also, dput is better than str for posting questions.
--
Sent from my phone. Please excuse my brevity.
On June 17, 2016 1:06:29 PM PDT, "ch.elahe via R-help"
wrote:
>Hi a
> On Jun 17, 2016, at 11:34 AM, T.Riedle wrote:
>
> Thank you very much.
> Here is the error message.
>
>> WriteXLS(coefar,ExcelFileName = "R.xls",SheetNames="test")
> Error in WriteXLS(coefar, ExcelFileName = "R.xls", SheetNames = "test") :
> 'x' must be the name of a data frame, the name of
Hi all,
I want to use world map in ggplot2 and show my data on world map. my df is:
$ COUNTRY : chr "DE" "DE" "FR" "FR" ..
$ ContrastColor : int 9 9 9 9 13 9 9 9 9 ..
$ quant : Factor w/ 4 levels "FAST","SLOW",..I need to merge my
df with world_map data
...
and adding, perhaps, to what David and Jeff told you:
Let ctr = c(ctr.lat, ctr.long) be the center of a bird colony (this
can be vectorized for many centers).
Then you need to figure out how much change in latitude and longitude
a distance of 500 meters is at that ctr (I think latitudes are e
Thank you very much.
Here is the error message.
> WriteXLS(coefar,ExcelFileName = "R.xls",SheetNames="test")
Error in WriteXLS(coefar, ExcelFileName = "R.xls", SheetNames = "test") :
'x' must be the name of a data frame, the name of a list of data frames, a
data frame object, a list object of
This is mostly a domain-specific question about coordinate conversion and
algebra, not really about R. However, there are packages that could be useful
for this problem that are discussed in the CRAN "Analysis of Spatial Data" Task
View [1] and on the R-sig-geo mailing list [2].
Some points to
> On Jun 17, 2016, at 11:23 AM, T.Riedle wrote:
>
> Thank you very much, Peter. I played a bit and found a solution.
>> rollingarmaols<-rollapply(data,width=36,function(data)
>> ar(data,order.max=1,method="ols"))
>> coefar<-apply(rollingarmaols, 1, getElement, "ar")
>> head(coefar,50)
> [1] 0.
Thank you very much, Peter. I played a bit and found a solution.
> rollingarmaols<-rollapply(data,width=36,function(data)
> ar(data,order.max=1,method="ols"))
> coefar<-apply(rollingarmaols, 1, getElement, "ar")
> head(coefar,50)
[1] 0.9430692 0.9140253 0.9236898 0.9426744 0.9465110 0.9318470 0.
I'm no expert here but I have recently been playing with the package
'geosphere' it contains plenty of options to calculate distance
between two coordinates specified as lat and long.
install.packages('geosphere') # only needed once
library(geosphere)
coord1 <- c(43.60923,-79.322799)
coord2 <- c(
> On Jun 17, 2016, at 10:26 AM, Alice Domalik wrote:
>
> Hi List,
>
> I'm working with some bird tracking data, and to filter the data set, I need
> to exclude points taken at the colony.
> I would like to exclude coordinates from within a 500 meter radius of a point
> centered on the colon
This would be a good question for R-sig-geo.
To do it properly, there would be a few steps:
1. transform from lat/long (units=degrees) to projected coordinate system
(units = meters)
2. find one of the R functions for calculating distances (there are
several)
3. subset the data according to you
Hi List,
I'm working with some bird tracking data, and to filter the data set, I need to
exclude points taken at the colony.
I would like to exclude coordinates from within a 500 meter radius of a point
centered on the colony.
However, as an R novice, I'm not sure how to accomplish this.
My
I don't know exactly what you mean, but perhaps this will get you started:
This:
subset(Data, X4==1 & X5==1, select=c(X1, X2, X3))
will extract the continuous variables in the cross-tabulation cell for
which X4 and X5 are both equal to one. Similar commands will extract the
other cells.
Of course
Hi all,
When checking an R package, I get:
|Consider adding importFrom("datasets","CO2")
(this data set is used in some example code)
However, when I add the suggested 'importFrom' statement to NAMESPACE
(using roxygen2), I get
|
|Error :object ‘CO2’ is not exported by 'namespace:datasets'|
||
You can make a step-number variable with cumsum(grepl("^Step ", ...)) and
use it as the splitting variable in split. E.g.,
> dat <- read.table(yourFile, stringsAsFactors=FALSE, sep="|",
colClasses=c("NULL", "character", "character", "character"),
col.names=c("Junk","Date","Time","Type"))
> dat <-
Your request is not clear. If you want to analyze the numeric variables by the
groups formed by the categorical variables, try something like this.
> # Create reproducible data
> set.seed(42)
> x <- data.frame(matrix(rnorm(75, 5), 25), X4=sample(0:1, 25,
+ replace=TRUE), X5=sample(0:1, 25, repla
Ooops. I can change that real quick.
Any help on the problem itself Ranjan?
Thanks!
On Fri, Jun 17, 2016 at 9:22 AM, Ranjan Maitra <
maitra.mbox.igno...@inbox.com> wrote:
> You need to send e-mail from a properly identifiable address (which has a
> correct name/e-mail address) and not a made-up
Hi
did you try table or xtabs?
Cheers
Petr
> -Original Message-
> From: R-help [mailto:r-help-boun...@r-project.org] On Behalf Of Gafar
> Matanmi Oyeyemi
> Sent: Friday, June 17, 2016 2:25 PM
> To: r-help@r-project.org
> Subject: [R] Obtaining and extracting cells sample in cross-tabulat
You need to send e-mail from a properly identifiable address (which has a
correct name/e-mail address) and not a made-up scam address. You can easily be
reported for impersonation!
Ranjan
On Fri, 17 Jun 2016 08:51:59 -0500 Narendra Modi wrote:
> Hello,
> Resending this message in "Plain-text
Hello,
Resending this message in "Plain-text".
Thank you for the add to the list.
I have written a R snippet to solve a non-linear problem using Optim solver.
The parameters to be solved are supposed to be in a matrix form as attached
such that summation of columns is <=1 except for the first c
Hello everyone,
I'm writing a function in R but was stalked.
I have a data set that contains mixture of categorical and continuous
variables. I want to use the categorical variables to cross-tabulate the
data and extract the observations in the resulting cells that contain only
continuous variables
I also need the significance value
Thanks
On Fri, Jun 17, 2016 at 11:11 AM, boB Rudis wrote:
> Did you try:
>
> cor(mat, method="kendall", use="pairwise")
>
> That only provides the matrix (so the equiv of the $r list component),
> but that seems to be all you need.
>
> On Fri, Jun 17, 2016
Did you try:
cor(mat, method="kendall", use="pairwise")
That only provides the matrix (so the equiv of the $r list component),
but that seems to be all you need.
On Fri, Jun 17, 2016 at 5:47 AM, Shane Carey wrote:
> Hi,
>
> I was hoping someone could help me. I was wondering are there any l
Hi Shane,
Try the "Kendall" package.
Jim
On Fri, Jun 17, 2016 at 7:47 PM, Shane Carey wrote:
> Hi,
>
> I was hoping someone could help me. I was wondering are there any libraries
> available to undertake a kendall correlation on a matrix of data, in the
> same way as what can be undertaken with
Hi,
I was hoping someone could help me. I was wondering are there any libraries
available to undertake a kendall correlation on a matrix of data, in the
same way as what can be undertaken with the rcorr function:
cormatrix = rcorr(as.matrix(A), type='spearman')
cordata = melt(cormatrix$r)
ggplot(
On Fri, 17 Jun 2016, Matthias Weber writes:
> Hello togehter,
>
> i have short question, maybe anyone can help me.
>
> I have a data.frame like this one:
>
>NO ORDER
> 1 1530 for Mr. Muller (10.0 -> 11.2)
> 2 1799 for Mr Giulani
> 3 1888 for Mr. Marius (11.2
Dear Mat,
You can use grepl() to select based on are regular expression.
subset(data3, grepl("\\(.*\\)", ORDER))
Best regards,
ir. Thierry Onkelinx
Instituut voor natuur- en bosonderzoek / Research Institute for Nature and
Forest
team Biometrie & Kwaliteitszorg / team Biometrics & Quality Assur
Hello togehter,
i have short question, maybe anyone can help me.
I have a data.frame like this one:
NO ORDER
1 1530 for Mr. Muller (10.0 -> 11.2)
2 1799 for Mr Giulani
3 1888 for Mr. Marius (11.2 -> 12)
I need a solution, which only contains the values in br
Hi
Your approach seems to me rather tricky
This should work
make_bv <- function(dataset, input_variables) {
dd <- which(names(dataset) %in% input_variables)
dat<-dataset[,dd]
x <- 10^(ncol(dat):0)
result <- cbind(dataset, binary_vec=x[1]+rowSums(sweep(dat, 2, x[-1], "*")))
result}
make_bv(dat
Hi Greg
Seems to me that spending some time with R tutorial would be way forward for
you.
Something like that could work, but without some fake (but resembling real)
data it is untested.
result <- data.frame(ss=rep(NA, nrow(ref)), ll= rep(NA, nrow(ref)), mm= rep(NA,
nrow(ref)))
for (i in 1:n
> Hi Tom,
>
> thanks for your reply.
>
> Yes, that's exactly what I am looking for. I did not know about the automatic
> type conversion in R.
>
> #-- cut --
> ds_example <-
> structure(
> list(
> year2013 = c(0, 0, 0, 1, 1, 1, 1, 0),
> year2014 = c(0,
>0,
Hi again!
According to '?xyf', the function is expecting following parameters:
(1) data = a matrix, with each row representing an object.
So, please ensure that your data is a matrix
(2) Y = property that is to be modelled. In case of classification, Y is
a matrix of zeros, with exactly one '
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