Hi Michael,
Have a look at my.symbols in the TeachingDemos package.
Jim
On Sat, Jun 4, 2016 at 4:19 AM, Michael Weber
wrote:
>
> Dear R users,
>
> I have been using R for several years and really appreciate all the
> developments which have been done. Maybe you can help me with the following
>
Dear R users,
I have been using R for several years and really appreciate all the
developments which have been done. Maybe you can help me with the
following problem:
I would like to plot full circles together with half circles in the
same plot. Unfortunately, the size of the different U
Thank you Jeff. Solved.
On Fri, Jun 3, 2016 at 12:47 AM, Jeff Newmiller
wrote:
> ?merge
>
> Pay attention to the all-whatever parameters.
> --
> Sent from my phone. Please excuse my brevity.
>
> On June 2, 2016 7:04:47 PM PDT, Ashta wrote:
>>
>> I have 2 data sets. File1 and File2. Some records
Thanks, ldply got me a data frame straight away. But it filled empty
spaces with NA and merge no longer works.
> ldply(mylist)
name red green
1 sample1 20NA
2 sample1 NA15
3 sample2 10NA
4 sample2 NA30
> mydf <- ldply(mylist)
> merge(mydf[1,],mydf[2,])
[1] name red gre
Hello,
Sorry, forget my first answer, I misunderstood what you wanted.
Let's try again.
First of all you have a typo in your second sample2, you wrote 'sample
2' with a space.
Now try this.
fun2 <- function(n){
merge(lst[[n]], lst[[n + 1]])
}
N <- which(seq_along(lst) %% 2 == 1)
lst2 <- l
You can use ldply in the plyr package to bind all the data.frames together
(a regular loop will also work). Afterwards you can summarise using ddply
Hope this helps
Ulrik
Ed Siefker schrieb am Fr., 3. Juni 2016 21:10:
> aggregate isn't really what I want. Maybe tapply? I still can't get
> it
Hello,
Maybe something like the following.
lst <-
list(data.frame(name="sample1", red=20), data.frame(name="sample1",
green=15), data.frame(name="sample2", red=10), data.frame(name="sample
2", green=30))
fun <- function(DF){
data.frame(name = DF[, 1], color = colnames(DF)[2], colnum = DF
aggregate isn't really what I want. Maybe tapply? I still can't get
it to work.
> length(mylist)
[1] 4
> length(names)
[1] 4
> tapply(mylist, names, merge)
Error in tapply(mylist, names, merge) : arguments must have same length
I guess because a list isn't an atomic data type. What function wi
This website might be of help:
http://www.biostat.jhsph.edu/~estuart/propensityscoresoftware.html
confidential to sas, spss, stata, and sudaan users: heavy doses of those
programs may cause statococcal infection. time to transition to R.
-- Anthony Damico --
-Original Message-
From: R
On 03/06/2016 2:27 PM, Bert Gunter wrote:
See the "Writing R Extensions" manual that ships with R.
You might also want to consider Hadley Wickham's roxygen2 package,
which allows one to include the Help information as specially
formatted comments within the code files themselves. The package wil
I manually constructed the list of sample names and tried the
aggregate call I mentioned.
Merge works when called manually, but not when using aggregate.
> mylist <- list(data.frame(name="sample1", red=20), data.frame(name="sample1",
> green=15), data.frame(name="sample2", red=10), data.frame(na
Hi All:
> On Jun 3, 2016, at 11:33 AM, jlu...@ria.buffalo.edu wrote:
>
> There is a video tutorial on the RStudio web site showing how to create R
> packages within RStudio. Hadley Wickham also has a book on creating R
> packages.
>
And I would add that Hadley has kindly put the book onlin
There is a video tutorial on the RStudio web site showing how to create R
packages within RStudio. Hadley Wickham also has a book on creating R
packages.
Bert Gunter
Sent by: "R-help"
06/03/2016 02:27 PM
To
suparna biswas ,
cc
r-help
Subject
Re: [R] Request for help
See the "Wri
Use regular expressions:
?grep
?regexp
(The answer is simple, but I think it is worthwhile to learn about
this on your own. Others may disagree and supply you the exact
answer).
Cheers,
Bert
Bert Gunter
"The trouble with having an open mind is that people keep coming along
and sticking things i
See the "Writing R Extensions" manual that ships with R.
You might also want to consider Hadley Wickham's roxygen2 package,
which allows one to include the Help information as specially
formatted comments within the code files themselves. The package will
then generate the Help files from this inf
I have a list of data as follows.
> list(data.frame(name="sample1", red=20), data.frame(name="sample1",
> green=15), data.frame(name="sample2", red=10), data.frame(name="sample 2",
> green=30))
[[1]]
name red
1 sample1 20
[[2]]
name green
1 sample115
[[3]]
name red
1 sample
Hello togehter,
maybe anyone can help me with a little problem.
I have the following column in an data.frame (called TEST)
VERSION
1abc (9.2 -> 10.0)
2def (10.2 -> 11.0)
3ghi (7.4 -> 8.4)
4jkl (10.2 -> 10.4)
5mno (8.1 -> 9.0)
I now need the code for the following resul
Hi,
Do you know any R-package for Kernel matching using the propensity scores?
I really appreciate your help.
Thanks,
Shyam Basnet
Sweden
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Dear Sir/Madam
Myself Suparna Biswas, a research scholar from the
department of Mathematical Sciences, Tezpur University, Assam, India. I am
working under the supervision of Dr. Santanu Dutta, Associate Professor,
Department of Mathematical Sciences, Tezpur University, Assam,
Dear Vinay,
As you can see from the df for the model (i.e., LR chisquare), which is 39 in
SAS and 52 using sem() in the sem package, you fit very different models in the
two programs. It's consequently unremarkable that you got different results --
and not just for the GFI but for everything. T
OK -- thanks. I used to compile from source routinely, but could never
get thee 'hand rolled' version of R to play nice with some external
applications (specifically, jags, and openbugs).
On 6/2/2016 5:41 PM, Marc Schwartz wrote:
On Jun 2, 2016, at 10:35 AM, Evan Cooch wrote:
Updated my R i
> On Jun 3, 2016, at 6:03 AM, Juan Andres Hernandez
> wrote:
>
> Can anybody explain me this weird result?
> a=3
> as.integer(a)
> 1] 3
>
> a=(3/10)/0.1
> a
> [1] 3
>
> as.integer(a)
> [1] 2
>
> Thank's in advance
>
> Juan A Hernández
See:
https://cran.r-project.org/doc/FAQ/R-FAQ.html
Can anybody explain me this weird result?
a=3
as.integer(a)
1] 3
a=(3/10)/0.1
a
[1] 3
as.integer(a)
[1] 2
Thank's in advance
Juan A Hernández
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Hi
you either made typo in your post or in your real evaluation of your dates.
> d1 <- strptime("2000-01-01", format="%Y-%m-%d")
> d2 <- strptime("01/01/2000", format ="%d/%m/%Y")
> d1==d2
[1] TRUE
>
However, I am not sure why you fiddle with as.numeric and what do you mean by
bin dates.
Regard
Hi! All.
I'm not much familiar with R.
So I tried to find a R function or packages that could work with my problems.
What I wonder is,
Whether there is any R function or package that includes the cluster analysis
considering with the weighted attribute.
I saw several papers that dealt w
Hi Tjun Kiat,
This seems to work:
daily_date<-as.Date(paste("2000-01",1:28,sep="-"),"%Y-%m-%d")
weekly_date<-as.Date(paste(c(1,8,15,22,28),"01/2000",sep="/"),
"%d/%m/%Y")
cut(daily_date,breaks=weekly_date,include.lowest=TRUE,
labels=paste("Week",1:4))
Jim
On Fri, Jun 3, 2016 at 6:00 PM, TJUN
> Dariush Ashtab
> on Thu, 2 Jun 2016 17:57:14 +0430 writes:
["accidentally" to R-core .. should have gone to R-help -- and
hence answered here]
> Dear R project I need stats package for optimization in
> simulated annealing but i can not download. please guide
> me.
Dear Ross,
On Friday, 3 June 2016, > wrote:
>
> I find that repeating the command gives very different results for the
> same
set of evidence.
Some variability in the results is expected since they are Monte Carlo
estimates.
What is happening in your case is, I think, that your evidence has a
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