Try a different mirror.
--
Sent from my phone. Please excuse my brevity.
On May 12, 2016 9:45:02 PM PDT, Mikko Hurme wrote:
>Hi!
>
>I also have problems when I try to install packages. I use R (v. 3.3.0)
>on
>iMac (v. 10.11.4).
>For instance:
>
>> install.packages("doBy")
>Warning: unable to ac
Hi!
I also have problems when I try to install packages. I use R (v. 3.3.0) on
iMac (v. 10.11.4).
For instance:
> install.packages("doBy")
Warning: unable to access index for repository
http://ftp.sunet.se/pub/lang/CRAN/src/contrib:
cannot open URL 'http://ftp.sunet.se/pub/lang/CRAN/src/contrib
On Thu, 12 May 2016 13:19:54 -0400
"yoursurrogate...@gmail.com" wrote:
> Hello, I can't post my code since it's on a work computer.
>
> But basically, I have a dataframe that has two columns, one is a
> string and the other is an integer. I want to turn this into a
> vertival barplot where on t
Martin Morgan, I tried an HTTP mirror and it worked.
What could be the problem and how to fix?
Also, should I ignore the warning about ignoring environment value of R_HOME?
Thanks.
On Thu, May 12, 2016 at 5:59 PM, Tom Hopper wrote:
> setInternet2() first thing after launching R might fix that.
>
setInternet2() first thing after launching R might fix that.
> On May 12, 2016, at 07:45, Alba Pompeo wrote:
>
> Hello.
>
> I've tried to run R, but I receive many warnings and can't do simple
> stuff such as installing packages.
>
> Here's the full log when I run it.
>
> http://pastebin.com
Ok, the horizontal names work here. Thanks.
> On May 12, 2016, at 1:31 PM, William Dunlap wrote:
>
> Does this do what you want?
>
> z <- data.frame(Name=c("One","Three","Twelve","Eleven"), Count=c(1,3,12,11))
> with(z, barplot(Count, names=Name, horiz=TRUE))
> with(z, barplot(Count, names=Nam
You are missing a reproducible example. We don't care what is on your home or
work computer... we just need to have clear communication, so make up some data
that shows the problem and some code to go with it. You MIGHT have to show
some data that does not have the problem in order to highlight
Does this do what you want?
z <- data.frame(Name=c("One","Three","Twelve","Eleven"), Count=c(1,3,12,11))
with(z, barplot(Count, names=Name, horiz=TRUE))
with(z, barplot(Count, names=Name, horiz=TRUE, las=1))
Bill Dunlap
TIBCO Software
wdunlap tibco.com
On Thu, May 12, 2016 at 10:19 AM, yoursurr
Hello, I can't post my code since it's on a work computer.
But basically, I have a dataframe that has two columns, one is a string and the
other is an integer. I want to turn this into a vertival barplot where on the
x-axis I have the string in the first columb and then the plot will display th
On 05/12/2016 07:45 AM, Alba Pompeo wrote:
Hello.
I've tried to run R, but I receive many warnings and can't do simple
stuff such as installing packages.
Here's the full log when I run it.
http://pastebin.com/raw/2BkNpTte
Does anyone know what could be wrong here?
do you have any success
Lorenzo:
This is a complicated and subtle question that I believe is mostly
about statistical methodology, not R. I would suggest that you post
your query to stats.stackexchange.com rather than here in order to
determine *what* you should do. Then, if necessary, you can come back
here to ask about
Looks to me like something outside of R is blocking network access by R. That
could be anything from you don't have networking setup to some security policy
or firewall configuration. I doubt this will be the right place to resolve
those issues.
--
Sent from my phone. Please excuse my brevity.
Dear All,
Please have a look at the code at the end of the email.
It is just an example of regression based on glmnet with some
artificial data.
My question is how I can evaluate the uncertainty of the prediction
yhat.
It looks like there are some reasons for not providing a standard
error estima
Hello.
I've tried to run R, but I receive many warnings and can't do simple
stuff such as installing packages.
Here's the full log when I run it.
http://pastebin.com/raw/2BkNpTte
Does anyone know what could be wrong here?
Thanks a lot.
__
R-help@r-p
I don't see any reason why a loop is out of the question, and
answering would have been much easier if you'd included the requested
reproducible data, but what about this?
This solution is robust to pairs from idcell being absent in censDist,
and to the difference from A to B being different than
Hello,
I have a sample of 1327 locations, each one idetified by an id and a
numerical code.
I need to build a spatial matrix, say, M, i.e. a 1327x1327 matrix
collecting distances among the locations.
M(i,i) should be 0, M(i,j) should contain the distance among location i and
j
I shoud use data
Hi Martin,
many thanks for following-up on my question.
I did it again:
## capture all the output to a file.
zz <- file("C:/Temp/all.Rout", open = "wt")
sink(zz)
sink(zz, type = "message")
try(log("a"))
## back to the console
sink(type = "message")
sink()
close(zz)
This works.
I tried several
> Hi Sarah,
> yes, I followed your suggestion.
I doubt that you followed it correctly. Sarah's advise is
usually really very sound -- and your code below is *not* :
> If I do exactly what is in the example of the documentation:
> sink("C:/Temp/sink-examp.txt")
> i <- 1:10
> outer(i, i, "*")
> s
> On 5/11/2016 2:23 PM, Jan Kacaba wrote:
> > Here is my attempt at function which computes margins from positions.
> >
> > require("stringr")
> > require("dplyr")
> >
> > ends<-seq(10,100,8) # end margins
> > test_string<-"Lorem ipsum dolor sit amet, consectetuer adipiscing
> > elit. Aliquam in
Nice solution Jim, thank you.
2016-05-12 2:45 GMT+02:00 Jim Lemon :
> Hi again,
> Sorry, that should be:
>
> chop_string<-function(x,ends) {
> starts<-c(1,ends[-length(ends)]+1)
> return(substring(x,starts,ends))
> }
>
> Jim
>
> On Thu, May 12, 2016 at 10:05 AM, Jim Lemon wrote:
>> Hi Jan,
>>
Hi Henrik, Jim, Sarah, Duncan,
Hi All,
I have tried the built-in solution using PowerShell:
$lockedFile="C:\Windows\System32\wshtcpip.dll"
Get-Process | foreach{$processVar = $_;$_.Modules | foreach{if($_.FileName
-eq $lockedFile){$processVar.Name + " PID:" + $processVar.id}}}
It did not show
Duncan suggested to use the argument explicitly and combine it with
the missing function which is for this problem also my preferred
solution:
image.2 <- function(x, col , breaks, ...){
# function is manipulating colors (adding a few)
# since it changes colors it needs to update breaks if def
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