Hi
Please cc your mails to r help. Users are around the world and you could have
response oslo from others.
You need to put NA in a missing good or bad letter. I would probably do merging
instead of do.call but there may be other options.
Something like that.
> l1<-sample(letters[1:10], 5)
>
> mod_c <- aov(dv ~ myfactor_c + Error(subject/myfactor_c), data=mydata_c)
>
> summary.lm(mod_c)
> Error in if (p == 0) { : argument is of length zero>
You called the lm method for summary() on an object of class c("aovlist",
"listof"). You should not expect a method for one class to work on an
Hi Cristiano,
Might be the data you have for "dv". I don't seem to get the problem.
dv<-sample(1:6,15,TRUE)
subject<-factor(rep(paste("s",1:5,sep=""),each=3))
myfactor_c<-factor(rep(paste("f",1:3,sep=""),5))
mydata_c<-data.frame(dv,subject,myfactor_c)
mod_c<-aov(dv~myfactor_c+Error(subject/myfacto
Dear all,
I am trying to visualize the regression coefficients of the linear model
that the function aov() implicitly fits. Unfortunately the function
summary.lm() throws an error I do not understand. Here is a toy example:
dv <- c(1,3,4,2,2,3,2,5,6,3,4,4,3,5,6);
subject <-
factor(c("s1","s1
In hopes of isolating parts of a time series where my indicator is
above zero I have filled those rows where the indicator is <= 0 with
NAs. I was hoping this would leave blank gaps when I plotted using
chartSeries(blanked, theme = 'white'), but chartSeries closes up the
gaps. ggplot, however, l
Hi,
I am pleased to announce version 3.1.0 of the 'maps' package which has a few
important changes and additions.
CHANGES:
- The 'world' map has been adapted: it now doesn't contain any lakes anymore.
Most visible effect is the Great Lakes on the Canada/USA border.
- Major lakes are now ava
Range of values is a standard mathematical concept, unrelated to the number of
values in your data set. Consider using the summary function to learn about
the range of your data.
Also, read the Posting Guide (which warns you to use pain text in formulating
your emails to the list to avoid cor
It should cover the range of values - from below the minimum to above
the maximum of your data.
One break would do it, or 10, or whatever. It doesn't matter how many
breaks you have, it matters that they have a sufficient range.
So you might make breaks like
seq(floor(min(x)), ceiling(max(x)), leng
Dear R users,
as my first post for this mailing list, I'd like to ask questions about 'break'
in cut.default.
I am using pheatmap in RStudio. Pheatmap is a function to draw clustered
heatmap in R.
According to the manual, breaks is 'a sequence of numbers that covers the range
of values in d
Better:
mom["PC_Q_m3","value"]
Read about indexing in R .
Bert
On Tuesday, February 16, 2016, MAURICE Jean - externe <
jean-externe.maur...@edf.fr> wrote:
> I went further !
>
> I could give a name to each row based on column 2 in the read.table
> command and then access to the value by :
>
You can add the argument na.print=" " to print() to make
the missing values print as " " instead of as NA. Some,
but not all print methods support this. E.g.,
> print(c(1,2,NA,4,5,NA), na.print="-")
[1] 1 2 - 4 5 -
> print(matrix(c(1,2,NA,4,5,NA),2), na.print="-")
[,1] [,2] [,3]
[1,]
Hi,
I found the error.
Thanks in advance
On Wed, Feb 17, 2016 at 4:01 PM, Shane Carey wrote:
> Hi,
>
> Im trying to append rows to a data frame using smartbind
>
> I have 3 dataframes:
>
> > dim(DATA_WH)[1] 235 24> dim(DATA_GW)[1] 3037 41> dim(DATA_NFGWS)[1] 2485
> > 62
>
> B<-smartbind(
Hi,
Im trying to append rows to a data frame using smartbind
I have 3 dataframes:
> dim(DATA_WH)[1] 235 24> dim(DATA_GW)[1] 3037 41> dim(DATA_NFGWS)[1] 2485
> 62
B<-smartbind(DATA_NFGWS,DATA_WH)
However I get the following error:
Error in `[.data.frame`(block, , col) : undefined colum
R 3.2.4 "Very Secure Dishes", the wrap-up release of R-3.2.x is now scheduled
for March 10
R 3.3.0 "Supposedly Educational", is scheduled for April 14.
Detailed schedules are published on developer.r-project.org.
For the Core Team
Peter D.
--
Peter Dalgaard, Professor,
Center for Statistics,
Searching for DICOM at www.rseek.org turns up a few options for
working with that image format.
But with no idea of what you want to do with them, we can't help with
the analysis. You will need to develop some clear objectives, do some
reading in how you might use R to accomplish those objectives,
> Is it possible to get object where missing values aren't replaced with NAs?
Not with read.table, if they are really missing. But you can replace them later
- see below - and if they are marked you can change what read.table considers
to be 'missing'.
> Is it possible to replace NAs with empty
Hi
Seems to me that it is time for you to go through R intro. I do not remember
myself using such weird construction.
mom["PC_Q_m3",]$value
You are lucky that you do not have duplicated values in your second column as
in this case you would get error
Error in `row.names<-.data.frame`(`*tmp*`,
Hi,
May be its reading your file and taking time which depends on size of the file
that you are reading.
Please explore ‘data.table’ library to read big files in few seconds.
If you attempt to close the application while execution had been in progress
for sometime it would take time most of the
Assuming it is a character variable
test <- c("a", NA, "b")
> test
[1] "a" NA "b"
> test[is.na(test)] <- " "
> test
[1] "a" " " "b"
but if it is numeric this as, as others have said, almost certainly not
what you really wanted to do
On 17/02/2016 10:04, Jan Kacaba wrote:
In my original data
Hi
I have this enhanced ls function, which evaluates size of objects generated by
myself or by other functions sitting in my environment.
ls.objects <- function (pos = 1, pattern, order.by)
{
napply <- function(names, fn) sapply(names, function(x) fn(get(x,
pos = pos)))
names <-
Beside of Adrian's answer, R can simply manage NAs but you need to deal with
"empty space" on your own.
See
?is.na
?na.omit
Cheers
Petr
> -Original Message-
> From: R-help [mailto:r-help-boun...@r-project.org] On Behalf Of Adrian
> Du?a
> Sent: Wednesday, February 17, 2016 2:01 PM
> T
Deb,
I assume you have already seen the great introduction to leaflet here ...
http://rstudio.github.io/leaflet/
You may find these two answers on stackoverflow helpful ...
http://stackoverflow.com/a/28240058/2140956
http://stackoverflow.com/a/29118680/2140956
Jean
On Tue, Feb 2, 2016 at 5:28
On Wed, Feb 17, 2016 at 12:04 PM, Jan Kacaba wrote:
> In my original data a csv file I have missing values. If I use read.table
> the missing values are replaced by NAs.
>
That is the normal way of dealing with missing values, in R.
Is it possible to get object where missing values aren't repl
I went further !
I could give a name to each row based on column 2 in the read.table command and
then access to the value by :
mom["PC_Q_m3",]$value
It’s great
Jean
Ce message et toutes les pièces jointes (ci-après le 'Message') sont établis à
l'intention exclusive des destinataires et les
Dear Team,
Every now and then I face some weird issues with R. For instance it would
not read my csv file or any other read.table command and once I would close
the session and reopen again it works fine.
It have tried using rm(list=ls()) & gc() to free some memory and restart R
Also
In my original data a csv file I have missing values. If I use read.table
the missing values are replaced by NAs.
Is it possible to get object where missing values aren't replaced with NAs?
Is it possible to replace NAs with empty space?
[[alternative HTML version deleted]]
_
I need some more help !
Data.frame is working great but for one thing : once the file has been read, I
can’t modify a ‘string’ column. This is, I suppose, because the column is a
factor.
But I get an error when I write :
> mim = read.table(file = "GESDYN_COMPLET_parametres.txt", row.names = "cl
Hi
There is probably better solution but I would aggregate
lll <- aggregate(ltrfreq$letterfreq, list(ltrfreq$letter, ltrfreq$type), sum)
order
ooo<-order(lll$x, decreasing=T)
split and sapply
lll<- lll[ooo,]
lll <- lapply(split(lll, lll$Group.2), head, 8)
and do.call rbind to get 8 letters fo
Hi Jean,
the 'unused argument (stringAsFactors = FALSE)' gives you a good clue. It
tells you, that you are passing an unexpected argument to the read.table
function.
In this case the argument is stringsAsFactors (string in plural).
I don't know how you modify the columns, but the factors should
Hi
You can use either search within CRAN or Task Views. Both can suggest
appropriate packages. Do not expect that we can decide which function/package
you shall use for your data.
I found among others:
https://cran.r-project.org/web/packages/mix/mix.pdf
but there are plenty of packages which
It will be included in the next version of devtools - it's totally
do-able, but no one has done it yet.
Hadley
On Wed, Feb 17, 2016 at 6:44 PM, Jeff Newmiller
wrote:
> AFAIK the answer is no. That would be one of the main drawbacks of depending
> on github for packages. It isn't really a packag
To R-help users:
I want to use ggplot two plot summary statistics on the frequency of
letters from
a page of text. My data frame has four columns:
(1) The line number [1 to 30]
(2) The letter [a to z]
(3) The frequency of the letter [assuming there is 80 letters per line]
(4) The factor 'type': b
Pls always respond to the list, which I have cc'ed.
It sounds like you want us to teach you R and statistics. You need to do
this yourself, using local resources or available tutorials and courses on
the web. Some recommendations for this can be found here:
https://www.rstudio.com/resources/train
Pls do not repeat posts. That's spam.
This list has a no homework policy. Your query seems to be homework. Ergo,
you should not expect a response unless you clarify that it is not.
Bert
On Tuesday, February 16, 2016, Moss Moss wrote:
> I am working on "Discrimination and Classification Using
Hi Guys,
I could need some help here. I have a set of 3d points (x,y,v). These
points are not randomly scattered but lie on a surface. This surface can be
taken as a calibration plane for x and y -values. My goal is to quantify
this surface and than predict the v-values for given pairs of x- and
y
I am working on "Discrimination and Classification Using Both Binary
and Continuous Variables".
Please, how can I use R-programming in running the following:
(1) Location Model
(2) Misclassification
(3) Error Rate
(4) Etc
I have R i386 3.2.2 installed to in my system. How do I trace
statistical t
Hi Ulrik and Rui,
Both solutions work but data.frame is the way i’ll go because there is an
advantage that I was’nt aware at the beginning : we can save the data.frame in
a text file, modify this file with notepad, …
Thank you very much
Jean
Ce message et toutes les pièces jointes (ci-après
Hai,
I have some DICOM format images for my project. Can you please help me
how can I read it by using R and how to analyse the images?
Regards
Vidu
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Hello
I am constructing a symmetric matrix with library "corpcor". In the
codes below, I am able to construct a symmetric matrix of order 3 and
4. However, the 5 x 5 matrix does not seem right? Help?
Thanks.
> library(corpcor)> r <- 1:3> rr <- vec2sm(r, diag = F)> rr <-
> rr[upper.tri(rr)]> r
I am working on "Discrimination and Classification Using Both Binary
and Continuous Variables".
Please, how can I use R-programming in running the following:
(1) Location Model
(2) Misclassification
(3) Error Rate
(4) Etc
I have R i386 3.2.2 installed to in my system. How do I trace
statistical t
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