I'll look into the Intervals idea. The data.table code posted might not
work (because I don't believe it would put the rows in the correct order if
the chromosomes are interspersed), however, it did make me think about
possibly assigning based on values...
*SOLUTION*
mapfile <- data.frame(Name =
I'll look into the Intervals idea. The data.table code posted might not
work (because I don't believe it would put the rows in the correct order if
the chromosomes are interspersed), however, it did make me think about
possibly assigning based on values...
Something like:
mapfile <- data.table(Na
> On Jan 30, 2016, at 3:24 PM, Bert Gunter wrote:
>
> (Ill give it a try, but more expertise than I have may be needed)
>
> Works fine for me (on OS X).
>
> Take a look at ?pdf . I believe the font family in use (Helvetica is
> the default) needs to have the (Adobe) symbol font as font 5. What
(Ill give it a try, but more expertise than I have may be needed)
Works fine for me (on OS X).
Take a look at ?pdf . I believe the font family in use (Helvetica is
the default) needs to have the (Adobe) symbol font as font 5. What
family are you using?
To see what families are available, use:
Sorry, there's a mistake, there's a missing comma, it should be
df[df$date >= '2012-01-01'& df$date <= '2013-12-31', ]$A
Rui Barradas
Citando ruipbarra...@sapo.pt:
> Hello,
>
> Try
>
> df[df$date >= '2012-01-01'& df$date <= '2013-12-31']$A = etc
>
> Hope this helps,
>
> Rui Barradas
>
>
> C
> On Jan 29, 2016, at 10:30 PM, lily li wrote:
>
> Hi R users,
>
> I have a data frame, and I generate a date column like this:
> df$date = seq(as.Date('2012-01-01'), as.Date('2014-12-31'))
>
> df
> A B C
> 1 2 1
> 2 2 3
> 3 2 4
>
> So the data frame has 4 columns now. But when I w
Hello,
Try
df[df$date >= '2012-01-01'& df$date <= '2013-12-31']$A = etc
Hope this helps,
Rui Barradas
Citando lily li :
> Hi R users,
>
> I have a data frame, and I generate a date column like this:
> df$date = seq(as.Date('2012-01-01'), as.Date('2014-12-31'))
>
> df
> A B C
> 1 2 1
>
I think the error message is pretty clear. Your calculations are attempting to
allocate more memory than you have available. As to what is causing your code
to do this, only someone familiar with your code could possibly tell.
B.
(Read the posting guide, please - and don't post in HTML :-)
On
Hi, Doesanyone use the 'betatree' function in the betareg package to do a kind
of falsediscovery rate (FDR) test for a set of many p values? I wasthinking to
compare the beta parameters of the true distribution of about 1000p values with
p values of permuted data, and test whether the two distr
Hi R users,
I have a data frame, and I generate a date column like this:
df$date = seq(as.Date('2012-01-01'), as.Date('2014-12-31'))
df
A B C
1 2 1
2 2 3
3 2 4
So the data frame has 4 columns now. But when I want to change the values
of column A for specific dates, such as 2012-01-01
Hi
I am running a ordinal logistic regression, however its giving me an error
like
Error: cannot allocate vector of size 58.8 GbIn addition: Warning
messages:1: In rep.int(c(1, numeric(n)), n - 1L) :
Reached total allocation of 8057Mb: see help(memory.size)2: In
rep.int(c(1, numeric(n)), n - 1L
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