Hi all;
I am working with a data set, pH of a lake water, and there is some gap in
my data. I it possible to predict these gaps by neural network? If so
please help to use the right code.
Many thanks.
--
Best Regards
Javad Bayat
M.Sc. Environment Engineering
Alternative Mail: bayat...@yahoo.
> On Nov 13, 2015, at 5:34 PM, Val wrote:
>
> Hi all,
> I have a data frame called "df" it's dimension is
>
> dim(df)
> [1] 9540634 38
>
>> From this data frame the variable * df$X1 *has about 78, 000 unique
> values and *df$region *has two classes. I am trying to do the following
Hi all,
I have a data frame called "df" it's dimension is
dim(df)
[1] 9540634 38
>From this data frame the variable * df$X1 *has about 78, 000 unique
values and *df$region *has two classes. I am trying to do the following
operation
The goal is reshaping the variable from long to wid
On 13/11/2015 2:34 PM, writetoh...@gmail.com wrote:
Dear all,
I am solving a problem about setting a knots in function smooth. spline. I am
not very sure how to set a knot points in this. I understand it accept only
number of points, but not distances between them. Can you help me how to
spe
1. I am not an expert on smoothing splines, but what you are trying to
do seems unwise. See e.g. Chapter 5 of Hastie et. al. "The Elements of
Statistical Learning."
2. However, could you not do what you want by setting some of the
weights, w, to 0?
Cheers,
Bert
Bert Gunter
Bert Gunter
"Data is
Dear all,
I am solving a problem about setting a knots in function smooth. spline. I am
not very sure how to set a knot points in this. I understand it accept only
number of points, but not distances between them. Can you help me how to
specify the distances?
Thanks a lot.
Regards!
On 13/11/2015 8:11 AM, Ilgaz S wrote:
Hello everybody, I am new to R and I discovered something that suprise me
and I have a question about it.
Today I wanted to return a bit array which represents this:
if( arbitrary point above the line)
return TRUE
else
return FALSE
First I tough
On 13/11/2015 12:53 PM, ALBERTO VIEIRA FERREIRA MONTEIRO wrote:
I have another environment question.
I understand why this works as expected:
f.factory <- function()
{
y <- 2
fname <- paste("plus", y, sep = ".")
f <- function(x) x + y
assign(fname, f, envir = globalenv())
}
f.facto
Hello everybody, I am new to R and I discovered something that suprise me
and I have a question about it.
Today I wanted to return a bit array which represents this:
if( arbitrary point above the line)
return TRUE
else
return FALSE
First I tought I would use for loop and access every el
This has been eating at me for a very long time. From everything I understand,
the plm package does not yet allow robust standard errors to be calculated for
the Hausman-Taylor using the coeftest command you would for other estimators
(i.e. pooled, within, random). This is of course the error th
Make a new environment for each function and populate it with
the variables that your functions require. local() is a convenient
way to do this:
f.factory3 <- function(destinationEnvir = globalenv())
{
for (y in 2:3) {
fname <- paste("plus", y, sep = ".")
f <- local(function(x) x + y, e
I have another environment question.
I understand why this works as expected:
f.factory <- function()
{
y <- 2
fname <- paste("plus", y, sep = ".")
f <- function(x) x + y
assign(fname, f, envir = globalenv())
}
f.factory()
plus.2(2) # 4
and I also understand why this does NOT work:
f.f
You are absolutely right, Ista - it's not haven's fault, my bad.
Of course, it's the attr function and exact = TRUE.
Thank you so much!
Dimitri
On Fri, Nov 13, 2015 at 10:00 AM, Ista Zahn wrote:
> Why do you think this is a bug in have? To the contrary, I don't think
> this has anything to do wit
Thanks Terry but the error persists. See:
> library(foreign)> library(survival)> library(VGAM) > mypareto <-
> list(name='Pareto',+ init= function(x, weights,parms){+
> alpha <- length(x)/(sum(log(x)))#this is a MLE for alpha+
> c(media <-(
Why do you think this is a bug in have? To the contrary, I don't think
this has anything to do with haven at all. The problem seems to be
that attr does partial matching by default. Check it out:
> attr(x, "labels") <- c("foo", "bar", "baz")
> attr(x, "label")
[1] "foo" "bar" "baz"
and see ?attr
We intend to have a patch release on December 10, nickname will be "Wooden
Christmas-Tree". The detailed schedule will be made available via
developer.r-project.org as usual (later today).
For the R Core Team,
Peter D.
___
r-annou...@r-project.org ma
Hi Christopher,
If you want to plot the movements of cells, perhaps a look at the help page
for color.scale.lines (plotrix) will get you started.
Jim
On Fri, Nov 13, 2015 at 8:47 PM, PIKAL Petr wrote:
> Hi
>
> What does it mean "to monitor". If you want to compute path length for
> each cell i
Hi
What does it mean "to monitor". If you want to compute path length for each
cell it seems to me that it is a simple problem of trigonometry
sqrt(a^2+b^2) = c
is a length of a segment between two points. a and b can be computed by
differencing x and y coordinates.
If I read your data
tempx<
Hello,
I am a student and I only have basic knowledge of R. I have been given the task
of having to monitor cells' migration in 2 dimensions. I have been given 2
files one containing the the X-coordinates and the other contains the
Y-coordinates of the cells. There are 50 cells and there moveme
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