Thanks S. Ellison.
Finally, Ihad some time to test it. Thanks for your clarification.
Just one more question:
You say:
Your regexes are on multiple lines and include whitespace and linefeeds.
For example you are not testing for
" .*forum.*|.*buy.*"; you are testing for
" .*forum.*|
On 7 November 2015 at 19:37, Robert Sherry wrote:
| Warning message: package ‘XML’ is not available (for R version 3.1.2)
That is your problem.
You are running R 3.1.2. That is old and outdated. CRAN has packages --
which may on occassion impose a '>=' relation. That is the case here.
Yo
Thanks for the response. I am currently using Windows 7. I tried the
following command:
install.packages("XML", repos = "http://www.omegahat.org/R";)
and I got:
Installing package into ‘C:/Users/Bob/Documents/R/win-library/3.1’
(as ‘lib’ is unspecified)
Warning: unable to acces
Bob,
On 7 November 2015 at 15:27, Robert Sherry wrote:
>
> I am trying to use the package quantmod to get option quotes in R.
> Therefore, I executed the following two commands:
> library ("quantmod" )
> getOptionChain("AAPL")
> The first one worked but the second one produced th
I am trying to use the package quantmod to get option quotes in R.
Therefore, I executed the following two commands:
library ("quantmod" )
getOptionChain("AAPL")
The first one worked but the second one produced the following error
message:
Error in getOptionChain.yahoo
Numerical gradient approximations are being used in your call, so my
guess is that the "epsilon" has made (parameter + epsilon) an
inadmissible argument for your likelihood. If you can supply analytical
gradients, the issue has a good chance of going away. Otherwise, you'll
need to use bounds or tr
Hi,
I am trying to obtain power of Likelihood ratio test for comparing gamma
distribution against generalized gamma distribution. And so I need maximum
likelihood estimates of Generalized gamma distribution with three parameters. I
wrote code as follows.
require(bbmle)
library("bbmle")
requ
Thanks to Jim and to Petr for their suggestion.
Stefano
Da: PIKAL Petr [petr.pi...@precheza.cz]
Inviato: giovedì 5 novembre 2015 15.02
A: Stefano Sofia
Cc: r-help@r-project.org
Oggetto: RE: [R] How to change name of pdf output of function windRose in
opena
many thanks for replying,
yes I am kindly accept my pardon, I mistaken the rows from each other many
thanks I will read them.
Ragia
> Date: Sat, 7 Nov 2015 07:48:36 -0800
> Subject: Re: [R] group by function
> From: bgunter.4...@gmail.com
> To: ragi..
??
Row 4 has i = 2 and Measure_id =4 and therefore has value divided by
the max of all values with that i and Measure_id, which is 1. Row 7
has i =2 and Measure_id =2, and so is divided by the max value in all
rows with those values of i and Measure_id, which is 2. etc. So either
you do not unders
Dear group,
kindly, I have the following data frame
structure(c(2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 1, 2,
3, 4, 5, 1, 2, 3, 4, 5, 1, 2, 3, 4, 5, 1.5, 2, 1, 0, 2, 2, 1.5,
0, 0, 1, 1, 2, 0, 1, 2), .Dim = c(15L, 3L), .Dimnames = list(
NULL, c("i", "Measure_id", "value")))
it has 3 c
> On 07 Nov 2015, at 04:56 , Mohammad Tanvir Ahamed via R-help
> wrote:
>
> Hi,
> i want to read a file on every 0.5 (or less) second. How can i set this time
> loop to read a file ?
> Any idea will be appreciated . Thanks . Tanvir Ahamed
Sys.sleep() if exact timing is not too critical. Oth
?Sys.sleep
Jim Holtman
Data Munger Guru
What is the problem that you are trying to solve?
Tell me what you want to do, not how you want to do it.
On Fri, Nov 6, 2015 at 10:56 PM, Mohammad Tanvir Ahamed via R-help <
r-help@r-project.org> wrote:
> Hi,
> i want to read a file on every 0.5 (or les
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