Giorgio Garziano [Tue, Sep 22, 2015 at
10:24:25PM CEST]:
Hi,
to test randomness of time series whose values can only be +1 and -1, are all
following
randomness tests applicable or only a part of ?
I don't know the details of all those tests but the general problem is
that the alternative
I guess the confusion here is the relationship between knitr::pandoc()
and rmarkdown::render(). The error message you saw was from
rmarkdown::render(), which requires Pandoc 1.12.3. The easiest way to
go to use rmarkdown (I mean the R package rmarkdown) is to use
RStudio, and you don't even need to
On Sep 23, 2015, at 9:21 AM, Jon Arsenault wrote:
> I've been banging my head against the wall a bit with this and would be
> ecstatic if someone could help.
>
> Initial data:
>
> Response Dose
> 1 285.17 0.125
> 2 377.65 0.250
> 3 438.99 0.500
> 4 338.46 1.000
> 5
On Sep 23, 2015, at 4:13 AM, Ryszard Czermiński wrote:
> I am trying to use R Markdown, but call to render() gives me an error:
> Error: pandoc version 1.12.3 or higher is required and was not found.
>
> As I understand [http://yihui.name/knitr/demo/pandoc/] pandoc is a function
> defined in kni
On Sep 23, 2015, at 10:09 AM, raoman ramirez wrote:
> well i have info<-read.csv(file, header=T)
> and i want try thatmodel<-lm(info[1]~info[2])
> is for metod backward selection but i don't know how
Can you explain why you want to apply backward selection to a model with a
single predictor ve
On 24/09/15 01:57, Rory Wilson wrote:
In reply to Rolf Turner and Jean Adams who have been helping me:
This does appear to be an issue with NA values in the non-factor
variables. In the (non-reproducible) example below, we can see that
removing the NAs solves the problem. However, from what I ca
I think the OP wanted rows where all values were greater than .9.
If so, this works:
> set.seed(42)
> dst <- dist(cbind(rnorm(20), rnorm(20)))
> dst2 <- as.matrix(dst)
> diag(dst2) <- NA
> idx <- which(apply(dst2, 1, function(x) all(na.omit(x)>.9)))
> idx
13 18 19
13 18 19
> dst2[idx, idx]
On Tue, 22 Sep 2015, John Sorkin wrote:
Charles,
I am not sure the answer to me question, given a dataset, how can one
compare the fit of a model of the fits the data to a mixture of two
normal distributions to the fit of a model that uses a single normal
distribution, can be based on the g
> mm <- cbind(1/(1:5), sqrt(1:5))
> d <- dist(mm)
> d
1 2 3 4
2 0.6492864
3 0.9901226 0.3588848
4 1.250 0.6369033 0.2806086
5 1.4723668 0.8748970 0.5213550 0.2413050
> which(as.matrix(d)>0.9, arr.ind=TRUE)
row col
3 3 1
4 4 1
5 5 1
1 1 3
1 1
Hi all!
I am having problems with using SVM in R
I have a data frame `trainData` which contains 198 rows and looks like
Matchup Win HomeID AwayID A_TWPCT A_WST6 A_SEED B_TWPCT B_WST6
B_SEED2010_1115_1457 1 1115 1457 0.531 5 16 0.567 4
16
2010_1124_1358 1 1124
Dear All,
Suppose you have a distance matrix stored like a dist object, for
instance
x<-rnorm(20)
y<-rnorm(20)
mm<-as.matrix(cbind(x,y))
dst<-(dist(mm))
Now, my problem is the following: I would like to get the rows of mm
corresponding to points whose distance is always larger of, let's say,
0
On 9/23/2015 5:57 AM, Therneau, Terry M., Ph.D. wrote:
Thanks for all for the comments, I hadn't intended to start a war.
My summary:
1. Most important: I wasn't missing something obvious. This is
always my first suspicion when I submit something to R-help, and it's
true more often than not
Hi ,
I am using randomForest model in R .
For large number of tree my program takes long time to complete .
In "randomForest" function i can use "do.trace=TRUE" to see the real time
progress . Sample out put in real time on R console is as follows
ntree OOB 1 2 3 4
well i have info<-read.csv(file, header=T)
and i want try thatmodel<-lm(info[1]~info[2])
is for metod backward selection but i don't know how
thanks for help
[[alternative HTML version deleted]]
__
R-he
I've been banging my head against the wall a bit with this and would be
ecstatic if someone could help.
Initial data:
Response Dose
1 285.17 0.125
2 377.65 0.250
3 438.99 0.500
4 338.46 1.000
5 227.87 2.000
6 165.96 0.010
7 302.92 0.125
8 418.50
In reply to Rolf Turner and Jean Adams who have been helping me:
This does appear to be an issue with NA values in the non-factor variables. In
the (non-reproducible) example below, we can see that removing the NAs solves
the problem. However, from what I can see to this point, there does not see
> Hi all,
>
> Hope I can Explain:
>
> I want to "run" online some function (code written by me) so that this code
> "saves" an output file on my server and my html webpage read the file R
> plots and save (really manually I would run R function, open Filezilla, and
> pass the output png o jpg fil
Dear Michael,
I found some of the errors, but others I wasn’t able to.
And my huge huge problem concerns OR and OR confidence interval :(
New Corrected code:
casedata <-read.spss("tas_05112008.sav")
tas.data<-data.frame(casedata)
#Delete patients that were not discha
> -Original Message-
> From: r.tur...@auckland.ac.nz
> Sent: Wed, 23 Sep 2015 13:26:58 +1200
> To: pda...@gmail.com
..
> I would say that this phenomenon ("Excel does it") is *overwhelming*
> evidence that it is bad practice!!! :-)
Fortune?
_
Hi Rolf: I have read a decent amount about the AIC but that was a long,
long time ago. I too am no expert on it and John should read some of the
AIC literature John: There's one whole supposedly great text just on AIC
but I don't have it. Link is here. Of course, it's
absurdly expensive but do
Dear useRs,
1) how to configure the plot command into windows device by default in
RStudio?
2) in layout panels, how to config for one panel to start in "minimized
mode" ?
(i would like to see only the "Environment panel" opened and only the
headers of the other panel) when start RStudio.
TI
Dear Rosa
Can you remove all the code which is not relevant to calculating the
odds ratio so we can see what is going on?
On 23/09/2015 16:06, Rosa Oliveira wrote:
Dear Michael,
I found some of the errors, but others I wasn’t able to.
And my huge huge problem concerns OR and OR confidence
On 23/09/2015 7:13 AM, Ryszard Czermiński wrote:
> I am trying to use R Markdown, but call to render() gives me an error:
> Error: pandoc version 1.12.3 or higher is required and was not found.
>
> As I understand [http://yihui.name/knitr/demo/pandoc/] pandoc is a function
> defined in knitr, whic
Thanks for all for the comments, I hadn't intended to start a war.
My summary:
1. Most important: I wasn't missing something obvious. This is always my first
suspicion when I submit something to R-help, and it's true more often than not.
2. Obviously (at least it is now), the CSV standard
On Tue, Sep 22, 2015 at 2:55 PM, bgnumis bgnum wrote:
> Hi all,
>
> Hope I can Explain:
>
> I want to "run" online some function (code written by me) so that this code
> "saves" an output file on my server and my html webpage read the file R
> plots and save (really manually I would run R functio
> On Sep 23, 2015, at 6:13 AM, Ryszard Czermiński
> wrote:
>
> I am trying to use R Markdown, but call to render() gives me an error:
> Error: pandoc version 1.12.3 or higher is required and was not found.
>
> As I understand [http://yihui.name/knitr/demo/pandoc/] pandoc is a function
> define
I am trying to use R Markdown, but call to render() gives me an error:
Error: pandoc version 1.12.3 or higher is required and was not found.
As I understand [http://yihui.name/knitr/demo/pandoc/] pandoc is a function
defined in knitr, which I have installed and it has pandoc() function
defined.
L
Dear Rosa
It would help if you posted the error messages where they occur so that
we can see which of your commands caused which error. However see
comment inline below.
On 22/09/2015 22:17, Rosa Oliveira wrote:
Dear all,
I’m trying to compute Odds ratio and OR confidence interval.
I’m re
Dear r-help list,
I work with EEG/ERP data and this is the first time I am using LMM to
analyze my data (using lme4).
The experimental design is a 2X2: one manipulated factor is agreement,
the other is noun (agreement being within subjects and items, and noun
being within subjects and between i
Good evening,
I have a very basic knowledge of how to use R and am struggling with my
code to fit a Gompertz-Makeham model to data. The code and error message is
as follows:
> data <- hmd.mx("AUS","mkeas...@hotmail.com","1Mrkqazwsx", "country")
Warning message:
In hmd.mx("AUS", "mkeas...@hotmail.
Dear all:
I use R(version 3.2.2)'s parallel processing code as follows:
cat("parall cal rtic:",nListLink,
",params:",length(arimaPreParams),"start...","\n")
cl <- makeCluster(getOption("cl.cores", 12));
system.time({
res <- parLapply(cl,1:
> Hadley Wickham
> on Sun, 20 Sep 2015 14:23:43 -0400 writes:
> The problem is that within.data.frame calls as.list.environment with
> the default value of all.names = FALSE. I doubt this is a deliberate
> feature, and is more likely to be a minor oversight.
Indeed;
Thank
On Tue, Sep 22, 2015 at 3:10 PM, bgnumis bgnum wrote:
> Hi all,
>
> I want to plot this data on file.txt that has this format
>
> 01/01/2000;970,1877
> 02/01/2000;970,2224
> 03/01/2000;969,0336
> 04/01/2000;958,3023
> 05/01/2000;952,8527
>
> I´m trying to plot with quantmode with this code but it
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