On 3/29/2015 11:10 PM, Partha Sinha wrote:
I have 1000 data points. i want to take 30 samples and find mean. I
also want to repeat this process 100 times. How to go about it?
Regards
Parth
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The argument 'K' is missing since you are only passing four arguments to
the phi() function, but you defined it with five formal parameters. It
looks like the argument 'j' is not necessary in the function. It is an
unnecessary carry-over from the summation notation and it is never used
in th
I have 1000 data points. i want to take 30 samples and find mean. I
also want to repeat this process 100 times. How to go about it?
Regards
Parth
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https://stat.ethz.ch/mailman/listinfo/
This looks like a specific Macintosh error that appears at random intervals.
I get it at random, and unreproducible times. I reported it (or
perhaps a close relative)
to the r-sig-mac list in September 2014.
Rich
On Sun, Mar 29, 2015 at 9:59 PM, Rolf Turner wrote:
> On 30/03/15 11:52, Ian Lest
On 30/03/15 11:52, Ian Lester wrote:
I’m a novice and this message looks like it shouldn’t be ignored. Someone who
knows what they’re doing should probably take a look.
Thanks
Ian Lester
logfat.lm<-(lm(body.fat~log(BMI)))
plot(logfat)
Error in plot(logfat) : object 'logfat' not found
plot(lo
There are two issues:
1) Damage was done to accuracy in the calculation of t(X) %*% X
Where the mean to SD ratio is large, maybe even of the order of
100 or so, centre that column.
2) pseudo inverse() goes awry with columns of X that are of the
order of large negative (or, I expect, +ve) powers of
That is an adequate solution. It's always better if R package authors don't
hard-code graphics parameters, though.
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PLEASE do read the postin
I’m a novice and this message looks like it shouldn’t be ignored. Someone who
knows what they’re doing should probably take a look.
Thanks
Ian Lester
>logfat.lm<-(lm(body.fat~log(BMI)))
> plot(logfat)
Error in plot(logfat) : object 'logfat' not found
> plot(logfat.lm)
Hit to see next plot:
Hit
Hi,
I would like to know if someone has any idea to use RAnalyticFlow and Rstudio
together, i.e., use the nice flowchart system of RAnalyticFlow within the great
interface of Rstudio ? I searched on the internet but without success ...
This would simplify/clarify so much my codes ! :)
Thank for
Hi T.,
Your translation of the formula looks okay, and the error message is about
a missing argument. Perhaps you have not included the necessary arguments
to "phi" in the call to "mls".
Jim
On Sun, Mar 29, 2015 at 11:59 PM, T.Riedle wrote:
> Hi everybody,
> I am trying to generate the formula
David Crow cide.edu> writes:
>
> Hi, R users-
>
> I'm estimating random effects models with cross-level interactions; I want
> to interact each of a vector of level-1 variables with each of a vector of
> level-2 variables. Here's the code:
>
>
> #create data frame with le
Hi, R users-
I'm estimating random effects models with cross-level interactions; I want
to interact each of a vector of level-1 variables with each of a vector of
level-2 variables. Here's the code:
#create data frame with level-1 variables
k <- as.data.frame(cbind(robo, asa
RiGui business.uzh.ch> writes:
>
[snip]
> I am terribly sorry for the code not being reproducible, is the
> first time I am posting here, I run the code several times before I
> posted, but...I forgot about the library used.
Thanks for updating.
> To answer to your questions:
>
>> How d
RiGui business.uzh.ch> writes:
>
[snip]
> I am terribly sorry for the code not being reproducible, is the
> first time I am posting here, I run the code several times before I
> posted, but...I forgot about the library used.
Thanks for updating.
> To answer to your questions:
>
>> How do
> On 28 Mar 2015, at 18:52 , RiGui wrote:
>
> Thank you for your replies!
>
> I am terribly sorry for the code not being reproducible, is the first time I
> am posting here, I run the code several times before I posted, but...I
> forgot about the library used.
>
> To answer to your questions:
Hi everybody,
I am trying to generate the formula shown in the attachment. My formula so far
looks as follows:
phi <- function(w1, w2, j, k, K){
zaehler <- (k/K)^(w1-1)*(1-k/K)^(w2-1)
nenner <- sum( ((1:K)/K)^(w1-1)*(1-(1:K)/K)^(w2-1))
return( zaehler/nenner )
}
Unfortunately something must be w
Thank you for your replies!
I am terribly sorry for the code not being reproducible, is the first time I
am posting here, I run the code several times before I posted, but...I
forgot about the library used.
To answer to your questions:
How do you know this answer is "correct"?
What I am doing
DR. UWE LIGGES
I have sent turkish real Gdp data (1998-2013) in annex.
Turkey has lived two crises in this period, in 2001 and 2008. You can see
in data.
My problem is to indicate these dates any statistic test as a structural
change or point change.
Sincerely
Engin
2015-03-28 23:04 GMT+01:00 Uw
Thanks for that Ben, I appreciate it a lot.
I have another question if you don't mind taking the time to answer it. I
want to create a subset from dataset called "datafile5" with only the
variables "Date," "PM2.5 mean concentration," "SITE_LONGITUDE," and
"SITE_LATITUDE," dating only in September
On Sat, 28 Mar 2015, Bert Gunter wrote:
Once you have looked at the data and chosen change points to test
based on the data, the tests for change points are invalid (unless you
make appropriate adjustments for post hoc tests).
And no, I am not making this up. Consult any competent statistician.
> On 28 Mar 2015, at 18:28 , Ben Bolker wrote:
>
> peter dalgaard gmail.com> writes:
>
>>
>>
>>> On 28 Mar 2015, at 00:32 , RiGui business.uzh.ch> wrote:
>>>
>>> Hello everybody,
>>>
>>> I have encountered the following problem with lm():
>>>
>>> When running lm() with a regressor close
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