Hi
use list and numeric indexing. As you did not provide reproducibe example here
is possible way.
dat <- data.frame(w=abs(rnorm(10)), LC09=round(runif(10)*10),
LC10=round(runif(10)*10))
lll <- vector("list", 2)
k=0
for(i in 2:3) {
k=k+1
lll[[k]] <- rep(dat$w, dat[,i])
}
names(lll)<-names(dat[,
> On Mar 22, 2015, at 9:18 PM, Alemu Tadesse wrote:
>
> Dear All,
>
> I am wondering if you have an R script or know an R package for an average
> wind direction
>
pkg:circular
> Best,
>
> Alemu
>
> [[alternative HTML version deleted]]
R is a plain text mailing list.
—
David Winse
Dear All,
I am wondering if you have an R script or know an R package for an average
wind direction
Best,
Alemu
[[alternative HTML version deleted]]
__
R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see
https://stat.ethz.ch/mai
I'm using a mac with OSX Yosemite (10.10.2), running the latest version of R
(3.1.3). But I've been having this same issue since Mavericks came out, using
all of the different versions of R that have come out since Mavericks.
Often (approximately 15% of the time I would say), whenever I use a f
So... wrote my first script, rather than just using the interactive
console. I think I got everything working more or less the way I want,
but I'm sure there's a ton of room for improvement. Specifically in the
way of automation - but thats where I kind of ran out of steam. Any
suggestions w
Dear Boris,
Thanks very much, have a great week.
Best regards
Antônio Olinto
Fisheries Institute
São Paulo, Brasil
2015-03-21 21:09 GMT-03:00 Boris Steipe :
> ... just for completeness - the more concise way: (no need to go through
> names()).
>
> boxplot(mydata[,order(apply(mydata,2,median)
On Mar 22, 2015, at 1:12 PM, Luca Meyer wrote:
> Hi Bert,
>
> Maybe I did not explain myself clearly enough. But let me show you with a
> manual example that indeed what I would like to do is feasible.
>
> The following is also available for download from
> https://www.dropbox.com/s/qhmpkkrejjk
Hi Bert,
Maybe I did not explain myself clearly enough. But let me show you with a
manual example that indeed what I would like to do is feasible.
The following is also available for download from
https://www.dropbox.com/s/qhmpkkrejjkpbkx/sample_code.txt?dl=0
rm(list=ls())
This is usual (an ext
Nonsense. You are not telling us something or I have failed to
understand something.
Consider:
v1 = c("a","b")
v2 = "c("a","a")
It is not possible to change the value of a sum of values
corresponding to v2="a" without also changing that for v1, which is
not supposed to change according to my und
Well, first off, you have no variable called "Name". You have lost the state
names as they are rownames in the matrix state.x77 and not a variable.
Try this. It's ugly and I have no idea why I had to do a cbind() but it seems
to work. Personally I find subset easier to read than the indexing ap
You could use a search engine to find other people's solutions to this problem.
Or you could just try again.
Unfortunately, if you want help here, your explanation is simply too brief. The
normal expectation here is that you provide a reproducible example. Since R
works by accepting text comman
Sorry forgot to keep the rest of the group in the loop - Luca
-- Forwarded message --
From: Luca Meyer
Date: 2015-03-22 16:27 GMT+01:00
Subject: Re: [R] Joining two datasets - recursive procedure?
To: Bert Gunter
Hi Bert,
That is exactly what I am trying to achieve. Please noti
Hi Bert,
Thanks again for your assistance.
Unfortunately when I apply the additional code you suggest I get B=40.23326
& C=-8.66603 and not B=29 & C=2.56723. Any idea why that might be
happening?
Please see below or on
https://www.dropbox.com/s/qhmpkkrejjkpbkx/sample_code.txt?dl=0 the code I
am
restart R.
-- Bert
Bert Gunter
Genentech Nonclinical Biostatistics
(650) 467-7374
"Data is not information. Information is not knowledge. And knowledge
is certainly not wisdom."
Clifford Stoll
On Sun, Mar 22, 2015 at 2:11 AM, adeela uaf wrote:
> Hi,
> I was downloading some shape files in R
Your data frame contains no column named "Name" .
Maybe what you want is
rownames(all.states)[all.state$Frost>150]
However, what you clearly need to do is stop posting until you have
done your homework by spending some time with one of the many good R
tutorials that are out there (possibly Intro
Oh, wait a minute ...
You still want the marginals for the other columns to be as originally?
If so, then this is impossible in general as the sum of all the values
must be what they were originally and you cannot therefore choose your
values for V3 arbitrarily.
Or at least, that seems to be wha
Hello All,
I have finally addressed all the cmd issues with my package build "bondlab." I
would like to thank everyone that took the time to answer my questions. I have the
following question: Currently the package has a non-standard directory/folder structure.
The non-standard folders are
Hi,
I was downloading some shape files in R then I use the package lsmeans in R
but I received the message "R for winfows GUI front end has stopped working
" . What I have to do to overcome this problem
[[alternative HTML version deleted]]
__
R-
Hi, I'm just learning my way around R. I got a bunch of states and would
like to access to get all of the ones where it's cold. But when I do the
following, I will get the following error:
> all.states <- as.data.frame(state.x77)
> cold.states <- all.states[all.states$Frost > 150, c("Name", "Fro
I would have thought that this is straightforward given my previous email...
Just set z to what you want -- e,g, all B values to 29/number of B's,
and all C values to 2.567/number of C's (etc. for more categories).
A slick but sort of cheat way to do this programmatically -- in the
sense that it
Hi Bert, hello R-experts,
I am close to a solution but I still need one hint w.r.t. the following
procedure (available also from
https://www.dropbox.com/s/qhmpkkrejjkpbkx/sample_code.txt?dl=0)
rm(list=ls())
# this is (an extract of) the INPUT file I have:
f1 <- structure(list(v1 = c("A", "A", "A
21 matches
Mail list logo
