Hi Adam,
I guess below code would help you achieve the desired ouput.
> colnames(data[,which(apply(data,2,FUN = function(x){any(x>0.5)}))])
Happy Learning!
Vikash
On Wed, Oct 15, 2014 at 5:53 PM, adam.n.jenkin...@gmail.com <
adam.n.jenkin...@gmail.com> wrote:
>
>
> Hi what I have is a large e
Hi Stephen,
Try out lapply(). It would help you loop through all data frames and sum.
Regards,
Vikash
On Thu, Oct 16, 2014 at 1:58 AM, Stephen HK Wong
wrote:
> Dear All,
>
> I have many 50 objects they are all dataframes. Each dataframe has many
> rows and four column. I simply want to do an
Hi
It will be even worse with age, try to contact optician :-)
If you want to get better answer you need to provide more info about your file,
what you did and how it failed.
Cheers
Petr
> -Original Message-
> From: r-help-boun...@r-project.org [mailto:r-help-bounces@r-
> project.org]
Hi
First of all you shall transfer your data to R.
Maybe it can be solved by apply but in your case I would use for cycle
Let say your data frame is named doc
lll<-vector(nrow(doc), mode="list")
for(i in 1:nrow(doc)) lll[[i]]<-colnames(doc)[(which(doc[i,]>0))]
Cheers
Petr
> -Original Mess
Don¹t know exactly what you mean by ³passing the value of Mon from the
command prompt², but it could be
At the R prompt:
> Mon <- ¹31-may-2014¹
> source(mainCall.R)
If, on the other hand, you mean shell prompt, then within R see
?commandArgs
On 10/15/14, 11:21 AM, "Abhinaba Roy" wrote:
>Hi
Dear All,
I have many 50 objects they are all dataframes. Each dataframe has many rows
and four column. I simply want to do an addition of 3rd and 4th column and save
the result into 5th column. Since there are many dataframes, I don't want to do
it one by one, is there a way to loop through
Thanks Simon!
That worked!
I did not constrain my k as you suggested, but when I saw my results, my
degrees of freedom are not larger than 1, the REML is negative and all
covariates are not significant (what it does not make sense). Is there
something wrong?
Here's the results of summary (a2)
Fa
Hi Simon,
The result of sessionInfo() is:
R version 3.1.0 (2014-04-10)
Platform: x86_64-w64-mingw32/x64 (64-bit)
locale:
[1] LC_COLLATE=Portuguese_Brazil.1252 LC_CTYPE=Portuguese_Brazil.1252
[3] LC_MONETARY=Portuguese_Brazil.1252 LC_NUMERIC=C
[5] LC_TIME=Portuguese_Brazil.1252
attached base pac
Rodrigo,
OK, it looks as if your mgcv help files/manual are somehow out of sync
with the package version you have loaded. 'betar' is only available from
mgcv 1.8. If you update to the current mgcv from CRAN then this problem
should be solved.
best,
Simon
ps. beta regression is only availabl
Can you give the result of typing
sessionInfo()
in the session where this happens, please?
On 15/10/14 16:48, Rodrigo Tardin wrote:
Hi all,
I am not sure if this is the right place for this question or if there is
one more specific.
Anyway, I hope somebody can help me.
I am trying to run a GAM
There is this great document called the R Reference that comes with the
software in which you can search for "command" and find the answer.
There is also a useful function called apropos that can search the help files
from the R prompt. Try apropos("command").
There is also a manual for this ma
Hello There!
I have an issue reading a large text file and parsing it. I would be
grateful if you let me you can help me about? Thanks.
Javad
[[alternative HTML version deleted]]
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailma
Hi what I have is a large excel doc (100 columns, 350 row) with data values
from 0-1. The end goal is for each row to have a list of colnames of which
columns contain values >0. I've been tinkering around with apply mostly and
some other functions, any help offered would be greatly appreci
Hi all,
I am not sure if this is the right place for this question or if there is
one more specific.
Anyway, I hope somebody can help me.
I am trying to run a GAM with beta distribution from mgcv package.
My dependent variable is a proportion continuously ranging from 0 to 1
(whales density) and
Hi R-helpers,
I have a R script (mainCall.R) which takes the value of an object *'Mon'*
as '31-may-2014' or '31-aug-2014' .
How can I run the R script by passing the value of Mon from the command
prompt?
Any help will be appreciated
Regards,
Abhinaba
[[alternative HTML version deleted]
On Wed, 15 Oct 2014, David L Carlson wrote:
I haven't looked at the source so I don't know exactly what is going on,
but I think I have a work around:
plot(winters.acomp, main="Winters Creek", cex=0.5)
pdf("winters-pdf.pdf")
ellipses(mean=mn, var=vr, r=r, steps=72, thinRatio=NULL, aspanel=FAL
Have you looked at recent entries in the system log files in /var/log,
especially /var/log/kern.log?
Bill Dunlap
TIBCO Software
wdunlap tibco.com
On Wed, Oct 15, 2014 at 1:51 AM, wrote:
> On 2014-10-14 15:40, Sven E. Templer wrote:
>>
>> Prevent graphic menues with:
>> options(menu.graphics = F
twodays <- c(filter(x,c(1,1),sides=1))
might be more efficient with memory than the embed approach, which might be
important if more than two days were of interest.
---
Jeff NewmillerThe .
Break down your problem into parts:
# compute two-day totals. I use filter here, but there are many ways
twoDayTotal <- function (x, init = 0)
{
# init lets you supply rainfall from day previous to first in x
filter(c(init, x), c(1, 1))[-length(x)]
}
# compute the first time a logical vect
On Wed, 15 Oct 2014, David L Carlson wrote:
I haven't looked at the source so I don't know exactly what is going on,
but I think I have a work around. While running your example I noticed
that ellipse() does not just add the ellipse to the plot produced by
plot(), it replots the figure. However,
A couple of observations:
1) I'm not sure what the variable i is doing, looks like you are trying
to loop through years but perhaps you left that bit of code out for
clarity.
2) On the first loop of i you are assigning the values of
Samaru56[sow_day,] to all values in Samaru56. For future loops all
I haven't looked at the source so I don't know exactly what is going on, but I
think I have a work around. While running your example I noticed that ellipse()
does not just add the ellipse to the plot produced by plot(), it replots the
figure. However, just running ellipse() without plot() gener
it might be slightly different, but i think the result is very close to a
tsl result (which hasn't been implemented).. could you use this?
mns<-svyby(~api00+api99, ~stype, rclus1, svytotal,covmat=TRUE)
vcov(mns)
On Wed, Oct 15, 2014 at 9:27 AM, Daniela Droguett <
daniela.droguett.l...@gmail.c
I believe the backslash is not considered an escape character by the extended
RE library used by R (perl=FALSE), so it is being treated as a literal. This
means that the last ] is outside the character class and is the atom that the *
applies to.
gsub("^([[:alnum:]\\[\\]]*).*", "\\1", "a]]]rra
Hi,
I would like to apply the vcov function from the survey package for the
variables api00 and api99 grouped by the stype variable which can assume H,
M and E categories.
From the code in the survey package manual:
data(api)
dclus1<-svydesign(id=~dnum, weights=~pw, data=apiclus1, fpc=~fpc)
r
Hi, this sound like u are calculating cummulative rainfall, this can also be
done in excel, then import the matrix to R, hope can help,
Franklin, Maseno, Kenya.
On Wednesday, October 15, 2014 1:02 PM, PIKAL Petr
wrote:
Hi
twodays <- rowSums(embed(Samaru56$Rain,2))
gives you sum of rain
I just found a curious behaviour of regexp and I'd like to share with y'all.
gsub("^([[:alnum:]\\[\\]]*).*", "\\1", "array[n] <- 10", perl=T) #
works as expected ("array[n]")
gsub("^([[:alnum:]\\[\\]]*).*", "\\1", "array[n] <- 10", perl=F) #
doesn't work ("a")
I didn't find anything in the docum
Hi
is
> plot(11:20, ylim=c(0,40))
> abline(h=40)
>
what you want?
Regards
Petr
> -Original Message-
> From: r-help-boun...@r-project.org [mailto:r-help-bounces@r-
> project.org] On Behalf Of PO SU
> Sent: Tuesday, October 14, 2014 11:33 AM
> To: R. Help
> Subject: [R] how to ajust y-a
Hi
twodays <- rowSums(embed(Samaru56$Rain,2))
gives you sum of rain in 2 cosecutive days
sel <- which(twodays>20)
gives you vector of row numbers in which above condition results in TRUE value
Samaru56[sel,]
selects these rows
Regards
Petr
> -Original Message-
> From: r-help-boun...
Hi,
You probably missed the "na.pad" argument of the "lag" function (for
zoo objects).
?zoo:::lag.zoo
Regards,
Pascal
On Wed, Oct 15, 2014 at 6:00 PM, jpm miao wrote:
> Hi,
>I could not find a nice lag operator on zoo object. Perhaps there is,
> but I just couldn't find it. Basically I want
On Wed, 15 Oct 2014, jpm miao wrote:
Hi,
I could not find a nice lag operator on zoo object. Perhaps there is,
but I just couldn't find it.
See ?lag.zoo.
Basically I want the operator to return the
lagged zoo object (with one or more variables ) with the original date. For
example, if I wr
did you check the connection in R via for example:
head(readLines("http://cran.r-project.org/web/licenses/GPL-3";))
which should yield:
[1] "GNU GENERAL PUBLIC LICENSE"
[2] " Version 3, 29 June 2007"
[3] ""
[4] " Copyright (C) 2007 Free Software Foundati
Hi,
I could not find a nice lag operator on zoo object. Perhaps there is,
but I just couldn't find it. Basically I want the operator to return the
lagged zoo object (with one or more variables ) with the original date. For
example, if I write lag(x, -3), then I got the lagged series, but the fir
On 2014-10-14 15:40, Sven E. Templer wrote:
Prevent graphic menues with:
options(menu.graphics = FALSE)
Same response after a pause: 'Killed'
or and define repositories:
options(repos = c(CRAN = "http://cran.r-project.org";))
Same response after a pause: 'Killed'
_
How to estimate paremeters the of loglogistic,lognormal and 2 parameter
exponential distributions in R using fitdistr function.
[[alternative HTML version deleted]]
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-
Dear All,
i am solving the following problem in my work.
The first day from April 01 that gets more than 20 mm on a single day, or
totalled
over 2 consecutive days. i.e April 01 = 92th day of the year.
The column of interest is "Rain".
> head(Samaru56)
Year Day Rain
1 1928 10
2 1928 2
36 matches
Mail list logo
