On 16/08/14 11:01, David Winsemius wrote:
On Aug 15, 2014, at 3:11 PM, Rolf Turner wrote:
I tried RSiteSearch("convex hull") just now, as an experiment, and
it seemed to work just fine. I think that the Universe is picking
on Dave (instead of on me, for once!). :-)
RSiteSearch("conve
On Aug 15, 2014, at 2:56 PM, Charlotte de Vries wrote:
> David Winsemius comcast.net> writes:
>
>>
>>
>> On Aug 15, 2014, at 8:06 AM, Charlotte de Vries wrote:
>>
>>> Hey there!
>>>
>>> I'm having problems with the same code, but I get a different error:
>>
>> This is apparently yet anoth
David Winsemius comcast.net> writes:
>
>
> On Aug 15, 2014, at 8:06 AM, Charlotte de Vries wrote:
>
> > Hey there!
> >
> > I'm having problems with the same code, but I get a different error:
>
> This is apparently yet another example demonstrating why the Posting Guide
suggests that you i
On Aug 15, 2014, at 3:11 PM, Rolf Turner wrote:
> On 16/08/14 05:10, Jeff Newmiller wrote:
>> I use RSiteSearch regularly with no problems. Perhaps I have just had
>> a lucky streak? I wonder what the odds are... :-)
>
>
>
>
>> On August 15, 2014 8:55:40 AM PDT, David Winsemius
>> wrote:
>>>
On 16/08/14 05:10, Jeff Newmiller wrote:
I use RSiteSearch regularly with no problems. Perhaps I have just had
a lucky streak? I wonder what the odds are... :-)
On August 15, 2014 8:55:40 AM PDT, David Winsemius
wrote:
On Aug 15, 2014, at 8:15 AM, Jeff Newmiller wrote:
Not really sure
On 16/08/14 02:51, Bob O'Hara wrote:
I've been struggling for half a day on what should be a simple problem...
I have a data frame of lat/long coordinates that describe a region, and I
want to draw a polygon around them so I can use that as a boundary (to be
thrown at INLA, but those details are
On 16/08/14 01:29, Joshua Wiley wrote:
On Wed, Aug 13, 2014 at 7:41 AM, Rolf Turner mailto:r.tur...@auckland.ac.nz>> wrote:
On 13/08/14 07:57, Ron Michael wrote:
Hi,
I would need to get a clarification on a quite fundamental
statistics property, hope expeRts here w
Both the suggestions I got work very well, but what I didn't realize is that NA
values would cause serious problems. Where there is a missing value, using the
argument na.last=NA to order just returns the the order of the factor levels,
but excludes the missing values, but I have no idea where
On Aug 15, 2014, at 8:06 AM, Charlotte de Vries wrote:
> Hey there!
>
> I'm having problems with the same code, but I get a different error:
This is apparently yet another example demonstrating why the Posting Guide
suggests that you include the text of any earlier posting to which you want u
Hi Tom,
You could try:
library(stringr)
str_extract(x, perl("(?<=[A-Za-z]{4}/).*(?=/[0-9])"))
#[1] "S01-012"
A.K.
On Friday, August 15, 2014 12:20 PM, Tom Wright wrote:
Hi,
Can anyone please assist.
given the string
> x<-"/mnt/AO/AO Data/S01-012/120824/"
I would like to extract "S01-012"
A similar post was found in stackoverflow
(http://stackoverflow.com/questions/25328311/how-to-avoid-change-string-to-number-automaticlly-in-r),
which already got an accepted reply.
A.K.
On Friday, August 15, 2014 2:18 PM, Wenlan Tian wrote:
I was trying to save some string into a matrix, bu
Hi Bob,
You probably want to have a look at the package alphahull.
Cheers,
Tsjerk
On Fri, Aug 15, 2014 at 5:25 PM, Clint Bowman wrote:
> Your question seems to need an answer to, "How do you find a convex hull
> on a sphere?" Google has many references.
>
> Clint BowmanI
Dear members,
I am experiencing a strange error using the dredge function of the package
MuMIn. I am not sure what is happening here as this script worked in the past
and I have no idea about this new error, I do not have any NA in my data.
> full_m<- gam(nep~ s(depth, k=4) + s(sed, k=4) + s(sl
I was trying to save some string into a matrix, but it automatically
changed to numbers (levels). How can i avoid it??
Here is the original table:
trtmeans M1 0 12.16673 a2 111 11.86369 ab3 125 11.74433 ab4
14 11.54073 b
I wanna to save to a matrix like:
J0001 a ab ab b
But, what i
Hey there!
I'm having problems with the same code, but I get a different error:
Error in .C("spline_coef", method = as.integer(method), n = n, x =
as.double(x), :
"spline_coef" not available for .C() for package "stats"
I'm using R3.1.0 on windows 8 and I've never used R before, so I migh
I have been using a process like the following to create polygons that
(closely) surround a non-convex set of points.
buf1 <- gBuffer(tmpb.ne, width=bstart, byid=TRUE)
buf2 <- gUnaryUnion(buf1)
buf <- gBuffer(buf2, width=bshrink)
These functions are from the rgeos package. In my case, tmpb
Perhaps use approx() separately for each patient.
But your new example, with times 1, 2, 6, 8 does not match your first
example with times 0, 3, 9. Nor had you mentioned having multiple patients
before. So it is difficult to understand what you are really asking for.
None the less, approx() does
On Aug 15, 2014, at 11:56 AM, Tom Wright wrote:
> WOW!!!
>
> What can I say 4 answers in less than 4 minutes. Thank you everyone. If
> I can't make it work now I don't deserve to.
>
> btw. the strsplit approach wouldn't work for me as:
> a) I wanted to play with regex and
> b) the location i
Must be another lucky streak. :-)
---
Jeff NewmillerThe . . Go Live...
DCN:Basics: ##.#. ##.#. Live Go...
Live: OO#.. Dead: OO#..
I use RSiteSearch regularly with no problems. Perhaps I have just had a lucky
streak? I wonder what the odds are... :-)
---
Jeff NewmillerThe . . Go Live...
DCN:Basics: ##.#.
Hello,
I don't believe you need an extra package for that. Try
sub("\\/mnt\\/AO\\/AO Data\\/([-[:alnum:]]*)\\/.+", "\\1", x)
or, with package stringr,
str_match(x,"\\/mnt\\/AO\\/AO Data\\/(.+)\\/.+")
Hope this helps,
Rui Barradas
Em 15-08-2014 17:18, Tom Wright escreveu:
Hi,
Can anyone p
WOW!!!
What can I say 4 answers in less than 4 minutes. Thank you everyone. If
I can't make it work now I don't deserve to.
btw. the strsplit approach wouldn't work for me as:
a) I wanted to play with regex and
b) the location isn't consistent.
Nice to see email support still works, not everyt
On Aug 15, 2014, at 11:18 AM, Tom Wright wrote:
> Hi,
> Can anyone please assist.
>
> given the string
>
>> x<-"/mnt/AO/AO Data/S01-012/120824/"
>
> I would like to extract "S01-012"
>
> require(stringr)
>> str_match(x,"\\/mnt\\/AO\\/AO Data\\/(.+)\\/+")
>> str_match(x,"\\/mnt\\/AO\\/AO Data
> -Original Message-
> > x<-"/mnt/AO/AO Data/S01-012/120824/"
>
> I would like to extract "S01-012"
> gsub("/mnt/AO/AO Data/(.+)/.+", "\\1", x)
#does it, as does
> gsub("/mnt/AO/AO Data/([\\w-]+)/.+", "\\1", x, perl=TRUE)# \w is perl RE;
> the default is POSIX, which would be.
>
Hi,
Can anyone please assist.
given the string
> x<-"/mnt/AO/AO Data/S01-012/120824/"
I would like to extract "S01-012"
require(stringr)
> str_match(x,"\\/mnt\\/AO\\/AO Data\\/(.+)\\/+")
> str_match(x,"\\/mnt\\/AO\\/AO Data\\/(\\w+)\\/+")
both nearly work. I expected I would use something lik
Great! Thanks
Sent from my LG G Flex, an AT&T 4G LTE smartphone
-- Original message--
From: Jorge I Velez
Date: Fri, Aug 15, 2014 8:54 AM
To: Sohail Khan;
Cc: Jim Lemon;R Help;
Subject:Re: [R] reshape a dataset
If that's the case, you could do the following:
d <- with(skdat, table(ID,
No wonder I didn't understand your constraints... you didn't state them. In
fact, I think you still haven't stated them. Perhaps you need a map outline?
Or, you could just create a polygon manually? Isocline of a two-D kernel
density estimate or kriging fit? Manually partition your data into reg
On Aug 15, 2014, at 8:15 AM, Jeff Newmiller wrote:
> Not really sure I understand your constraints, but perhaps
>
> RSiteSearch("convex hull ")
RSiteSearch has really been broken for some time now. (You get the headers but
the links are all broken. A more effective way of searching the existin
Your question seems to need an answer to, "How do you find a convex hull
on a sphere?" Google has many references.
Clint BowmanINTERNET: cl...@ecy.wa.gov
Air Quality Modeler INTERNET: cl...@math.utah.edu
Department of Ecology VOICE:
Unfortunately my region isn't convex, and I don't want to end up predicting
the distribution of a forest-dwelling bird in the Atlantic ocean...
Bob
On 15 August 2014 17:15, Jeff Newmiller wrote:
> Not really sure I understand your constraints, but perhaps
>
> RSiteSearch("convex hull ")
>
> mi
Not really sure I understand your constraints, but perhaps
RSiteSearch("convex hull ")
might help?
---
Jeff NewmillerThe . . Go Live...
DCN:Basics: ##.#. ##.#. Live Go
You don't show us your function call, so it is hard to be certain what the
problem is. Have you read the manual page?
?predict.glm
Have you used the newdata= argument? If not, you should know that R's ability
to read your mind will not be available until the 4.0 release.
David Carlson
-
I've been struggling for half a day on what should be a simple problem...
I have a data frame of lat/long coordinates that describe a region, and I
want to draw a polygon around them so I can use that as a boundary (to be
thrown at INLA, but those details aren't important). The coordinates are
alm
On Wed, Aug 13, 2014 at 7:41 AM, Rolf Turner
wrote:
> On 13/08/14 07:57, Ron Michael wrote:
>
>> Hi,
>>
>> I would need to get a clarification on a quite fundamental statistics
>> property, hope expeRts here would not mind if I post that here.
>>
>> I leant that variance-covariance matrix of the
If that's the case, you could do the following:
d <- with(skdat, table(ID, lettertag))
d <- data.frame(cbind(ID = rownames(d), d))
rownames(d) <- NULL
d
HTH,
Jorge.-
On Fri, Aug 15, 2014 at 8:22 PM, Sohail Khan wrote:
> Thanks Jim and Jorge,
> Clever solutions, the final output is a list.
>
It works :) Thanks so much! I tried searching a lot but I guess i missed
this fact!
On Thu, Aug 14, 2014 at 4:35 PM, Gabor Grothendieck wrote:
> On Thu, Aug 14, 2014 at 3:47 PM, Sneha Bishnoi
> wrote:
> > Hi All!
> >
> > I am trying to increment date column of data frame so as to merge it with
On 13 Aug 2014, at 20:49 , (Ted Harding) wrote:
> Indeed, this topic has got me wondering how many times I may have
> blindly used sd(x) in the past, as if it were going to give me the
> standard (sum(x - mean(x))^2)/length(x) result!
At the risk of flogging a horse that has been dead for the
On Fri, 15 Aug 2014 06:22:53 AM Sohail Khan wrote:
> Thanks Jim and Jorge,
> Clever solutions, the final output is a list.
> How do I covert it back a dataframe?
> -Sohail
>
as.data.frame(newskdat)
or for Jorge's
as.data.frame(res)
Jim
__
R-help@r-pr
Thanks Jim and Jorge,
Clever solutions, the final output is a list.
How do I covert it back a dataframe?
-Sohail
On Fri, Aug 15, 2014 at 5:37 AM, Jorge I Velez
wrote:
> Dear Sohail,
>
> Using Jim's data set skdat, two more options would be
>
> # first option
> d <- with(skdat, table(ID, lettert
Dear Sohail,
Using Jim's data set skdat, two more options would be
# first option
d <- with(skdat, table(ID, lettertag))
names <- colnames(d)
d <- c(list(rownames(d)), lapply(1:ncol(d), function(i) as.numeric(d[,i])))
names(d) <- c('ID', names)
d
# second option
d <- with(skdat, table(ID, letter
Thanks Jeff for the suggestion - will explore the predict function. So far
I was working on the fitted() function but it seems to generate fitted
(response) values only for predictor values in the original data set, not
for values beyond that.
I never intended to spam the mailing list. I re-posted
On Thu, 14 Aug 2014 06:08:51 PM Sohail Khan wrote:
> Hi
> I have data set as follows:
> A 92315 A 35018 A 56710 B 52700 B 92315 B 15135 C 35018 C
52700
> I would like to transform this data set into:
> ID 92315 35018 56710 52700 15135 A 1 1 1 0 0 B 1 0 0 1 1 C 0 1 0
1 0
> I looked i
On Thu, 14 Aug 2014 09:53:31 PM Pfauth, Mary C wrote:
> Hello R users,
> I am new to R and, so far, am finding it relatively easy to use. I
have
> run into what seems to me to be an odd problem. I have tried using
the
> "import" and calendarPlot" functions while in the open air package. I
ge
Hi Don.
The reason I want to do this is that I have the recorded infusion rate of time
1, 2, 6, 8 but I have the recorded response of time 1.5, 3, 4, 12. Notice that
the time does not match between the two. Ultimately I want to plot Response VS
Infusion Rate. If I just use xyplot between the tw
Hi
I have data set as follows:
A 92315 A 35018 A 56710 B 52700 B 92315 B 15135 C 35018 C 52700
I would like to transform this data set into:
ID 92315 35018 56710 52700 15135 A 1 1 1 0 0 B 1 0 0 1 1 C 0 1 0 1 0
I looked into reshape package to no avail.
I would appreciate any suggestio
Hello R users,
I am new to R and, so far, am finding it relatively easy to use. I have run
into what seems to me to be an odd problem. I have tried using the "import" and
calendarPlot" functions while in the open air package. I get a message returned
stating "unable to find function." I know
On 15/08/2014 2:40 am, Peter Langfelder wrote:
> On Wed, Aug 13, 2014 at 11:57 PM, Peter Brady
> wrote:
>> > Hi All,
>> >
>> > I've inherited some R code that I can't work out what they've done. It
>> > appears to work and give sort of reasonable answers, I'm just trying to
>> > work out why they
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