I've recently wanted to analyze some data sets of growth curves; so, I decided
to try out the grofit package the dataset inputting gave me some issues.
I've been trying to replicate the example from the grofit package with
R
> foo <- ran.data(100, 25)
> time <- foo$time
> data <- foo$data
On 09/08/14 06:25, Fix Ace wrote:
I have 16 files and would like to check the information of their first two
lines, what I did:
ls(pattern="P_")
[1] "P_3_utr_source_data" "P_5_utr_source_data"
[3] "P_exon_per_gene_cds_source_data" "P_exon_per_gene_source_data"
[5] "P_ex
The obvious suggestion is to not repack the package file.
You should also be sure to read the Posting Guide, which points out that this
is a plain text mailing list (HTML is not a what-you-see-is-what-we-see format).
---
Jeff
I re-zipped it because when I downloaded from GitHub, it had the actual
glassbox folder within the glassbox-master folder, so I zipped that
glassbox folder because my understanding was the install.package function
only works on zipped files.
And it does seem like it installed within my R library (
On 07/08/2014 07:21, Joshua Wiley wrote:
Hi Ryan,
It does work, but the *apply family of functions always pass to the first
argument, so you can specify e2 = , but not e1 =. For example:
sapply(1:3, `>`, e2 = 2)
[1] FALSE FALSE TRUE
That is not true:
gt <- function(x, y) x > y
> sapply(
On Aug 8, 2014, at 1:29 PM, James Holland wrote:
> Running R 3.03 on Windows 7
>
> I am trying to install a package from a github repository.
>
> https://github.com/google/glassbox
>
> I downloaded the repository as a zip file, extracted it to get the glassbox
> folder and re-zipped it with 7-
On Aug 8, 2014, at 11:28 AM, Fix Ace wrote:
> I recently tried to run some sample code from R package: circlize,
> and got an error message (please see below) = > library(circlize) >
> circos.genomicInitialize(df) > df = data.frame(name = c("TP53", "TP63",
> "TP73"), + start = c(7565097, 1
On Fri, 8 Aug 2014 06:26:35 AM carol white wrote:
> Hi,
> Is there any way to take one color of each color family from a color
> palettes like rainbow? For ex, if there are different blues
differentiated
> by intensity, hue etc, taking one of them. In this case, when using
> rainbow(n), then how t
On Sat, Aug 9, 2014 at 9:56 AM, Patrick Burns
wrote:
> On 07/08/2014 07:21, Joshua Wiley wrote:
>
>> Hi Ryan,
>>
>> It does work, but the *apply family of functions always pass to the first
>> argument, so you can specify e2 = , but not e1 =. For example:
>>
>> sapply(1:3, `>`, e2 = 2)
>>>
>> [
I re-zipped it because when I downloaded from GitHub, it had the actual
glassbox folder within the glassbox-master folder, so I zipped that
glassbox folder because my understanding was the install.package
On Aug 8, 2014, at 1:29 PM, James Holland wrote:
> Running R 3.03 on Windows 7
>
> I am tryi
> for(i in ls(pattern="P_")){ head(get(i), 2)} # Should work.
You also need to use print(head(...)) if you want to see the printed
output from each iteration.
Bill Dunlap
TIBCO Software
wdunlap tibco.com
On Fri, Aug 8, 2014 at 4:36 PM, David Winsemius wrote:
>
> On Aug 8, 2014, at 11:25 AM,
On Aug 8, 2014, at 11:25 AM, Fix Ace wrote:
> I have 16 files and would like to check the information of their first two
> lines, what I did:
>
>
>> ls(pattern="P_")
> [1] "P_3_utr_source_data" "P_5_utr_source_data"
> [3] "P_exon_per_gene_cds_source_data" "P_ex
Running R 3.03 on Windows 7
I am trying to install a package from a github repository.
https://github.com/google/glassbox
I downloaded the repository as a zip file, extracted it to get the glassbox
folder and re-zipped it with 7-zip.
I then ran
#-Start code---#
I have 16 files and would like to check the information of their first two
lines, what I did:
> ls(pattern="P_")
[1] "P_3_utr_source_data" "P_5_utr_source_data"
[3] "P_exon_per_gene_cds_source_data" "P_exon_per_gene_source_data"
[5] "P_exon_source_data"
I recently tried to run some sample code from R package: circlize,
and got an error message (please see below) = > library(circlize) >
circos.genomicInitialize(df) > df = data.frame(name = c("TP53", "TP63",
"TP73"), + start = c(7565097, 189349205, 3569084),
+ end = c(7590856, 189615068, 3652
On Thu, Aug 7, 2014 at 9:32 AM, amarjit chandhial
wrote:
> Hello,
> runSum calculates a running sum looking back a fixed distance n, e.g. 20.
> How do I calculate a dynamic runSum function for an xts object?
> In
> otherwords, I want to calculate a running sum at each point in time
> looking back
On 08-08-2014, at 16:12, K Aravindhan wrote:
> Dear Team,
> I am getting this error while running the boot-strapping functions.
>
do you really have to post identical messages within 4 to 5 minutes?
One message is enough and be patient and wait!
Berend
>
Dear Sven,
I am running into this exact some problem in Ubuntu 14.04. I have R
3.1.1 freshly installed and OpenJDK 7 (I do not need BLAS, as far as I
know).
Trying to install rj and rj.dg I get the exact same error messages as
you were getting "Error: cannot determine complete Java config". Were
Hello all,
In glmnet package, cv.glmnet is giving error
>data(iris)
>df<-data.frame(iris$Sepal.Length, iris$Sepal.Width, iris$Petal.Length,
iris$Petal.Width)
>x<- as.matrix(df)
>y<- as.numeric(iris$Species)
>fit = glmnet(x, y, family = "multinomial", type.multinomial = "grouped")
>plot(fit, xvar =
Dear Team,
I am getting this error while running the boot-strapping functions.
==
mod.db.hub<-glm(TOTAL~1+IPD,family="poisson",data=db)
fit<-fitted(mod.db.hub)
e<-residuals(mod.db.hub)
X<-model.matrix(mod.db.hub)
boot.huber.fixed<-function(data,indi
Anyone know of an R package that will allow me to do an inverse
Gaussian/Wald distribution transform of my data (reaction times)? Thanks!
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide
Dear Team,
I am getting this error while running the boot-strapping functions.
==
mod.db.hub<-glm(TOTAL~1+IPD,family="poisson",data=db)
fit<-fitted(mod.db.hub)
e<-residuals(mod.db.hub)
X<-model.matrix(mod.db.hub)
boot.huber.fixed<-function(data,indi
?rainbow
?col2rgb
rainbow(8)
col2rgb(rainbow(8)[5])
col2rgb(rainbow(8)[5])[1]
col2rgb(rainbow(8)[5])[2]
col2rgb(rainbow(8)[5])[3]
On Fri, Aug 8, 2014 at 6:26 AM, carol white wrote:
> Hi,
> Is there any way to take one color of each color family from a color palettes
> like rainbow? For ex, if
I think your question is too vague to answer since we don't know what you are
trying to do or how many colors you need. The easy answer is that you don't
need to use rainbow() at all, just use color names:
mycolors <- c("red", "green", "blue", "violet")
and you will have one of each. For exampl
You might take a look at the RColorBrewer package.
Sarah
On Fri, Aug 8, 2014 at 9:26 AM, carol white wrote:
> Hi,
> Is there any way to take one color of each color family from a color palettes
> like rainbow? For ex, if there are different blues differentiated by
> intensity, hue etc, taking
I would suggest not using pie charts and not trying to make 1000 color
distinctions. Also read all of my original post and do some research.
> cols <- hsv(.6, seq(0, 1, length.out=1000), .9)
> pie(1:1000, labels="", col=cols, border=NA)
David
From: carol white [mailto:wht_...@yahoo.com]
Sent: F
Professor Ripley
You asked “how that managed to give TRUE? (I apologize for the mangled quotes —
the error occurred with plain quotes).
All that I can say is that R versions <= 3.1.0 allowed my code to execute
without error. The bug report appears to address the issue. I typically
review Dalg
Hi,
Is there any way to take one color of each color family from a color palettes
like rainbow? For ex, if there are different blues differentiated by intensity,
hue etc, taking one of them. In this case, when using rainbow(n), then how to
select 1 color of each family, for ex 1 blue, 1 red etc?
Using dput() to provide your data is enormously easier.
Assuming the original column names of your data frame correspond to
the ColMap column of the second data frame, it's very straightforward:
mat <- structure(list(A = c(0.01, -2, -4), B = c(0.2, 1.4, -3), C = c(-0.3,
2.3, -2), D = c(0.8, 3.1,
Hi:
I am requesting help on matrix mapping.
I have a matrix that is 5000 rows x 3000 columns in R env.
Matrix:
A BC D E
S1 0.01 0.2 -0.3 0.8-1
S2 -21.4 2.3 3.1-2
S3 -4 -3-2
On 07/08/2014 23:37, Fisher Dennis wrote:
R 3.1.1
OS X (and Windows)
Colleagues
I have some code that manages files. Previously (as late as 3.1.0), the
command:
file.info(FILENAME)$mtime == “”
yielded T/F
Now, it triggers an error:
Error in as.POSIXlt.character(x, tz, ...) :
Hello,
In your email, you speak about foreach()%dopar%, but in your script,
it is foreach()%do%.
Best,
Pascal
On Thu, Aug 7, 2014 at 7:19 PM, André Ziervogel
wrote:
> Dear R people,
>
> I’ve been doing some hpc using R and openmpi. Unfortunately I’ve encoutred a
> major problem and it’s nature
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