In MySQL
SELECT INET_ATON('127.0.0.1')
returns the integer 2130706433
Is there a function in R to reverse that, ie so that something like
ip <- inet_ntoa(2130706433)
would put '127.0.0.1' into ip?
greetings, el
__
R-help@r-project.
Hi Arun,
Your script works but it does not do what I was after. To be a bit more
specific, this the table FA in which Im working on ( but the original one
has 34 fatty acids instead of 3: C14.0, C15.0, and C15.1).
SampleC14:0C15:0C15:1
L1 Control0.4565091920.4695626870.774909216
L1 Control0.51398
Jim Lemon wrote:
> On 04/23/2014 11:58 PM, m.r...@5-cent.us wrote:
>> This really isn't about R, but configuring R. We're running R 3.0.2-1,
>> the current default package, on CentOS 6.5 On a long-running job, R is
>> creating files in /dev/shm: each set of three files are named (8 hex
>> digits)-(
Aren't those files support for named semaphores (made with sem_open())?
Packages like BH and RSQLite contain calls to sem_open. Is your long-running
R process using such a package?
I don't think you would want to delete those files, but perhaps you can look
into
whatever R package creates them
Hi Marta,
If you need random selection, you could use:
do.call(rbind,lapply(split(dat2,dat2$field1),function(x)
x[sample(1:nrow(x),dat1$field2[!is.na(match(dat1$field1,x$field1))],replace=FALSE),]))
A.K.
On Tuesday, April 22, 2014 1:45 PM, arun wrote:
Hi Marta,
It's not clear whether you w
Hi,
Please use ?dput() to show the datasets as one of the rows (Id "four") in first
dataset didn't show 11 elements.
df1 <- structure(list(Id = c("one", "one", "two", "two", "three", "three",
"three", "four", "five", "five"), col1 = c("a1", NA, "b1", "b1",
NA, NA, "c1", "d1", "e1", NA), col2
HI,
I guess you got an output like this using my script:
##Please use ?dput() to show the example data.
FA <- structure(list(Sample = c("L1 Control", "L1 Control", "L1 Control",
"BBM Control", "BBM Control", "BBM Control", "L1 Ash", "L1 Ash",
"L1 Ash", "BBM Ash", "BBM Ash", "BBM Ash"), C14.0 = c
Regardless of whether this is possible, it seems like a bad idea (side effects
in a functional programming environment). If you want to do something special
in startup then write a different function that does that stuff and then call
the desired functions explicitly when you want them to be cal
Thanks Duncan! Yes, I considered taking advantage of .First, but was
concerned that the .First defined by the site profile could be masked by a
possible .First defined by the user profile (I neglected to mention that
"--no-init-profile" [sic] in the example I gave was a simplify
Unfortunately, that doesn't help as it removes axis lines. It looks like I
can't use segments3d() without knowing what the bounds are of the current
axes and I don't know what to call to expose those.
Thanks again for your help, though, I appreciate it. Hopefully this gets
fixed in a future releas
I am making an rgl-based 3d plot. It works fine, except when I try to
remove axis value labels and tick marks with axes3d(labels=FALSE,
ticks=FALSE):
---
rgl.open()
offset <- 50
par3d(windowRect=c(offset, offset, 1280+offset, 1280+offset))
rm(offset)
rgl.clear()
rgl.viewpoi
Dear Mickael,
assignInMyNamespace() is a standard R function, in the tools package, and so
with up-to-date versions of R and the Rcmdr package, you should not be
experiencing this problem. Can you provide some more information, such as the
operating system you're using, the R version (current i
On 04/23/2014 11:58 PM, m.r...@5-cent.us wrote:
This really isn't about R, but configuring R. We're running R 3.0.2-1, the
current default package, on CentOS 6.5 On a long-running job, R is
creating files in /dev/shm: each set of three files are named (8 hex
digits)-(4 hex digits)-(4 hex digits)-
Hi,
I've made a matrix with my first row being nest numbers and my second row
being a score for individuals in that nest. Row after that contain the
difference in score for that individual and its neighbour - i assigned a
formula to each element (thus all the columns have different lengths, but
On 23/04/2014 4:09 PM, Simon Kiss wrote:
Hello:
I have a .csv file that includes some character strings (open ended survey
responses) that includes some apostrophe. Using read.csv() the file reads in
just fine, except upon being read in the apostrophes are displayed with the
double-slash, i.e.
Hello:
I have a .csv file that includes some character strings (open ended survey
responses) that includes some apostrophe. Using read.csv() the file reads in
just fine, except upon being read in the apostrophes are displayed with the
double-slash, i.e. 'I've' becomes 'I\\'ve'. I'd like to pri
Hi,
You could try:
Lines1 <- readLines(textConnection("---CLUSTER 1 ---
3
4
5
6
---CLUSTER 2 ---
9
10
8
11"))
indx <- grepl("CLUSTER", Lines1)
res <- data.frame(Object=Lines1[!indx], Cluster=
as.numeric(as.character(factor(cumsum(indx)[-which(indx)],
labels=gsub("\\D+","",Lines1[indx])
re
Sir I have this problem,
> res <-
maxLik(logLik=loglik1,start=c(a=1.5,b=1.5,c=1.5,dee=2),method="BFGS")
There were 50 or more warnings (use warnings() to see the
first 50)
> summary(res)
"Maximum Likelihood estimation
BFGS maximisation, 0 iterations
Return code 100: Initial value out of range."
On Wed, 23 Apr 2014, Paul Miller wrote:
Am intested in using R to analyze censored cost data.
Paul,
What are censored cost data? Too high to be affordable; too low to cover
materials?
My best guess so far is the NADA package. Not sure if this is the best
thing to do what I need though.
Hello All,
Am intested in using R to analyze censored cost data. Looks like I'd need to
estimate some means and associated variances. I've got a few papers describing
this. These talk about the use of re-weighted estimators (Lin), inverse
probability weighted estimators (Bang-Tsiatis), phase-ba
Can you provide some sample data and the family of curves that you
would like to fit?
Reproducible examples greatly increase your chances of receiving a
useful response.
On Wed, Apr 23, 2014 at 12:33 AM, andreas betz wrote:
> Hello,
>
> is it possible to fit a group of curves simultaneously to a
I would suggest you post this to the Bioconductor list. You might also
have a look at the CRAN gR task view if you haven't already done so --
though no guarantees of finding what you want here, of course.
Cheers,
Bert
Bert Gunter
Genentech Nonclinical Biostatistics
(650) 467-7374
"Data is not in
Hi I'm working with the illumina HT-12v4 array and after using LIMMA some of
the most significant probes that come up are in genes that have been
discontinued on NCBI (ie LOC732450). Is there a way to filter my data of these
probes prior to statisitcal analysis?
Thanks,
.kripa
Are there any packages implementing graph search algorithms?
I'm looking for the equivalent of matlab findshortestpath in the
bioinfomatics toolbox.
Thanks,
Tom
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do
> library(bayesm)
> Rd <- utils:::.getHelpFile(?rwishart)
> tools::Rd2ex(Rd)
Or you could use example() to get a character vector of the example
code in a help file.
library(bayesm)
example(rwishart, give.lines=TRUE)
Bill Dunlap
TIBCO Software
wdunlap tibco.com
> -Original Message
After install the package RCMDR, I try to load it and it always apears the same
error message:
Error : .onAttach failed in attachNamespace() for 'Rcmdr', details:
call: Commander()
error: could not find function "assignInMyNamespace"
Error: package/namespace load failed for 'Rcmdr'
I hav
Hey everyone, Im new to R and this forum so I apologize in advance for any
ambiguity in my question. What I want to do is create a spatiotemporal object
(class st) out of an esri shapefile with multiple features and csv file
containing data in long format (each row is one observation in space-t
This really isn't about R, but configuring R. We're running R 3.0.2-1, the
current default package, on CentOS 6.5 On a long-running job, R is
creating files in /dev/shm: each set of three files are named (8 hex
digits)-(4 hex digits)-(4 hex digits)-(4 hex digits)-(12 hex digits), and
then sem.(same
Hi all !
I am look for some efficient method to compute the derivative of
exponential matrix function in R. For example, I have a simple matrix like
log.Sigma <- matrix(c(par1, rho, rho, par2),2,2)
require(Matrix)
Sigma <- expm(log.Sigma)
I want some method to compute the derivatives of Sigma
Solved again.
index(time) in case anyone wants to know.
Nothing like posting to the list to solve a problem!
Thanks,
Erin
On Wed, Apr 23, 2014 at 8:11 AM, Erin Hodgess wrote:
> Hello!
>
> I have the following xts object:
>
> > time
> [,1]
> 2000 Q11
> 2000 Q22
> 2000 Q3
Hello!
I have the following xts object:
> time
[,1]
2000 Q11
2000 Q22
2000 Q33
2000 Q44
2001 Q15
2001 Q26
2001 Q37
2001 Q48
I would like to access the date stamp values. I've tried dimnames and
rownames, but no success.
Any advice would be much appreciat
Many thanks Jim. It works for my large data set!
Best Regards
Nico
On Wed, Apr 23, 2014 at 1:45 PM, jim holtman wrote:
> try this:
>
> > x <- readLines(textConnection("---CLUSTER 1 ---
> + 3
> + 4
> + 5
> + 6
> + ---CLUSTER 2 ---
> + 9
> + 10
> + 8
> + 11"))
> >
> > # create a list of where t
try this:
> x <- readLines(textConnection("---CLUSTER 1 ---
+ 3
+ 4
+ 5
+ 6
+ ---CLUSTER 2 ---
+ 9
+ 10
+ 8
+ 11"))
>
> # create a list of where the 'clusters' are
> clust <- c(grep("CLUSTER", x), length(x) + 1L)
>
> # get size of each cluster
> clustSize <- diff(clust) - 1L
>
> # get cluster numb
Frede
Thank you for the explanation, now I better understand how to write functions
like this,
Andras
[[alternative HTML version deleted]]
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PLEASE do read th
Well if
1= f(x)
then
1 - f (x) = 0
So to find the x that solves the first equation you just need find the root of
1 - f (x) due to the second equation.
That's pretty simple mathematics.
Please check your equation and the values of the parameters you have from your
source since I was just co
On 22/04/2014, 8:59 PM, Benjamin Tyner wrote:
Greetings,
Is there any way to programmatically detect whether a piece of code is
being run within the initial (Startup) sourcing of the site profile?
For example, say I have a site profile, "/path/to/Rprofile.site". Is
there any function "my_func"
Thank you a lot Jim. Much cleaner now!
On 23.04.2014 12:01, Jim Lemon wrote:
On 04/23/2014 07:54 PM, Bea GD wrote:
Dear R users,
I've got over a hundred R objects in the workspace. They all follow a
pattern for years and months. Like this:
TT_1981_1, TT_1981_2, TT_1981_3, . . . . TT_1981_12
.
Frede
Thank you very much for the help. Indeed, I am trying to do exactly what you
wrote the code for. I may have caused some confusion though as a result of a
typographic error in my equation: the result of the equation should EQUAL to
the value of 1. I see you have inputted the equation into
On 04/23/2014 07:54 PM, Bea GD wrote:
Dear R users,
I've got over a hundred R objects in the workspace. They all follow a
pattern for years and months. Like this:
TT_1981_1, TT_1981_2, TT_1981_3, . . . . TT_1981_12
.
.
.
TT_2010_1, . . .
If now, I'd like to remove a selection of them, how is th
Dear all, I have object where I stored clusters in the following manner:
---CLUSTER 1 ---
3
4
5
6
---CLUSTER 2 ---
9
10
8
11
Now want to format the data in the following way:
Object Cluster
31
41
51
61
9 2
10 2
8
Dear R users,
I've got over a hundred R objects in the workspace. They all follow a
pattern for years and months. Like this:
TT_1981_1, TT_1981_2, TT_1981_3, . . . . TT_1981_12
.
.
.
TT_2010_1, . . .
If now, I'd like to remove a selection of them, how is the best way to
do it? Currently I nee
Have a look at the knitr package. http://yihui.name/knitr/demo/minimal/
Best regards,
ir. Thierry Onkelinx
Instituut voor natuur- en bosonderzoek / Research Institute for Nature and
Forest
team Biometrie & Kwaliteitszorg / team Biometrics & Quality Assurance
Kliniekstraat 25
1070 Anderlecht
Belg
Dear Frede,
Sorry for the late reply, yesterday I was out of office.
Thanks so much for your code! It has just compacted in a few lines what
I had written in several 'paragraphs'!
To be honest, I'm not familiar to work with lists in R. I think one of
its main advantages is the reduced size o
Sorry I should have been more clearer. Let me repharse.
At the moment I have a loop that plots a histogram of the variable, along
with rug and super-imposed normal curve over it. It does that for a lot of
variables in the dataset and then compiles them into a pdf. Whereby each
page on the pdf c
Sorry I made a copy and paste error. To get all the details of the curves
between 0 and I had to use:
E <- seq(0,10, len = 2000)
Sorry for the inconvenience.
Yours sincerely / Med venlig hilsen
Frede Aakmann Tøgersen
Specialist, M.Sc., Ph.D.
Plant Performance & Modeling
Technology & Service
Hi Andras
I suppose you want to find the real root of your equation if such exists for
the particular settings of the parameters. For that you can use uniroot().
So define a function based on your equation like this:
f <- function(E, D1, D2, IC501, IC502, ECON, ALPHA, M1, M2){
1 - D1/(IC501
Hello,
I can use mvpart function of library "mvpart" to get a decision tree. The
output of decision tree could be something like the following. I can use it
to manually calculate deviance explained by the variable in the first split
as below. There should be an easy way to tabulate deviance explai
Hello,
is it possible to fit a group of curves simultaneously to an equation with
some parameters shared among the curves others fit for each curve
individually. Several commercial software programs like Originlab have this
option often referred to as global fit. I would appreciate any advice or
r
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