Hi,
I just noticed that you also have all is.na() or !is.na() subsets. To do that:
mydatatest <- structure(list(CaseID = structure(1:8, .Label = c("1605928",
"1605943", "1605945", "1605947", "1605949", "1605951", "1605952",
"1605953"), class = "factor"), Structure = structure(c(1L, 1L,
3L, 2L,
If you want to identify the combination of columns:
names1 <- unlist(lapply(seq(length(vec1)-1),function(i) {x1 <-
as.data.frame(combn(vec1,i),stringsAsFactors=FALSE); unlist(lapply(x1,
function(x) {indx <- vec1 %in% x; paste(paste(paste0("!is.na","(",
vec1[!indx],")"),collapse=" & "), paste(p
Hi,
May be this helps:
res <- lapply(seq(length(vec1)-1),function(i) {x1 <-
as.data.frame(combn(vec1,i),stringsAsFactors=FALSE); lapply(x1, function(x)
{indx <- vec1 %in% x; nisna <- paste(paste0("!is.na","(",
vec1[!indx],")"),collapse=" & ");isna <- paste(paste0("is.na","(",
vec1[indx],")"),c
Hi R users,
This isnt a R-specific issue, per-se, but I thought that this list would have
some helpful input on this topic. First, a bit of background. I am working on
a project which is interested in following approx 1000 students each semester,
and collects about 15 different measurements
Hi,
You could also try:
library(plyr)
ddply(mutate(sardat,sec=as.numeric(gsub(".*:(.*)\\..*$","\\1",sardat$V1))),.(sec),
numcolwise(mean))
# sec V2 V3 V4 V5 V6
#1 46 15.0 3.80 11.20 4.60 17.8
#2 47 14.28571 4.428571 9.857143 3.428571 16.85714
I am analyzing some data that came from demographic health surveys. The
data contain information for individuals within households, that are
located within clusters, that are located within survey years, that are
located within countries. We are trying to find the best model from a
subset of pred
I'm trying to count the number of combinations of columns containing data &
not containing data as described below. I"m not sure how to do this in R
and need some help.
#get TRUE/FALSE count of various combinations of columns per CaseID or per
Structure
mydatatest <- data.frame (CaseID = c("16059
Hello,
There is no package called "Rhipe" on R CRAN
Any web search engine is your friend: https://www.datadr.org/install.html
Regards,
Pascal
On Wed, Mar 19, 2014 at 12:34 AM, karthik wrote:
> Hello,
>
> I have ubuntu 12.04 OS with R 3.0.2 version. My problem is I am getting
> message like "
Hello,
Please have a look at the "xts" package.
Please don't post in HTML.
Regards,
Pascal
On Wed, Mar 19, 2014 at 12:26 AM, Satish Anupindi Rao
wrote:
> Hi,
> I have a zoo object with the first column as index. The columns have not been
> named yet... but that I can change. It looks like thi
On 03/19/2014 02:26 AM, Satish Anupindi Rao wrote:
Hi,
...
I would like to find the mean of the V2 to V6 columns on a per second interval.
Would anyone please be able to help me with a function and implementation for
that please?
Hi Satish,
If you don't care about the location of the interva
On 19/03/14 10:59, Prof Brian Ripley wrote:
On 18/03/2014 21:41, Rolf Turner wrote:
I am currently having, uh, difficulties, with the latest version of
lme4, which I did not have with an elderly version that I was using
previously. To check things out I installed the elderly version in a
dire
On 18/03/2014 21:41, Rolf Turner wrote:
I am currently having, uh, difficulties, with the latest version of
lme4, which I did not have with an elderly version that I was using
previously. To check things out I installed the elderly version in a
directory called "AltRlib", in my home directory.
This really belongs on the R-devel list, in so far as it is an R issue
at all.
The most likely explanation is that you have a mismatch between your
readline headers and library. That symbol needs readline >= 6.0.
On 18/03/2014 18:53, Fong Chun Chan wrote:
Hi,
I am trying to install the new
I am currently having, uh, difficulties, with the latest version of
lme4, which I did not have with an elderly version that I was using
previously. To check things out I installed the elderly version in a
directory called "AltRlib", in my home directory.
I kept the latest version (1.1-5) i
We cannot help you. You claim to have set the working directory but cannot find
the file you expect to be there. Either you have failed to set the directory
correctly, or the file is not where you think it is... and since we do not have
access to your computer we have no way to tell you which ca
Perfect. Thanks!
On Tue, Mar 18, 2014 at 2:26 PM, Thomas Lumley wrote:
> On Tue, Mar 18, 2014 at 12:43 PM, Dustin Fife wrote:
>
>> I've got a dataset with really long column names (e.g.,
>> CYJ.OSU.OAV.UJC.BUT.RDI). What I'd like to do is replace the fourth period
>> with a break ("\n") so that
Hi,
I would like to download discharge data for thousands of rivers from this
website: http://ida.water.usgs.gov/ida/available_records.cfm?sn=1234
I have managed to fill in the blank spaces in the form (start and end time)
using
library(RCurl)
url1<-"http://ida.water.usgs.gov/ida/available_
On Tue, Mar 18, 2014 at 12:43 PM, Dustin Fife wrote:
> I've got a dataset with really long column names (e.g.,
> CYJ.OSU.OAV.UJC.BUT.RDI). What I'd like to do is replace the fourth period
> with a break ("\n") so that when it plots, it will not run off the page.
> Here's what I've got so far:
>
>
#if you want to just extract the columns of dat1 using vector1, you can just
use:
dat1[,vector1]
A.K.
On Tuesday, March 18, 2014 1:13 PM, arun wrote:
Hi,
Not sure about your expected output. May be this helps:
vector1 <- c("LA_A", "LA_B", "G_A")
dat1 <- setNames(as.data.frame(matrix(1:20,
Hello
When i run this command i get the error as shown below.I also changed my
working directory and set it where ever i want but still its
hopeless.please help me
>counts <- read.table("NewBrain.tab", header=TRUE, row.names=1)
Error in file(file, "rt") : cannot open the connection
In addition: War
Hello,
I have ubuntu 12.04 OS with R 3.0.2 version. My problem is I am getting
message like "Rhipe packages is not available for R version 3.0.2".
Please let me know in case you have a workaround or any solution for
installing Rhipe in R 3.0.2 (for Ubuntu).
Regards,
Karthik
--
View this me
Hi,
I was trying to gather/combine the results returned from the mclapply function.
This is how I do it if only one data object is returned:
#= This works fine ===
library(multicore)
frandom1 <- function(iter,var1 = 3,var2 =2){
mat <- matrix(rnorm(var1*var2),nrow=var1,ncol=var2)
Dear all,
I am trying to use the nonlinear quantile regression which involves copula
functions. Following the Frank copula example provided in the "quantreg"
vignette I try do do the same using the Normal (Gaussian) copula. The
problem is that the "nlrq" algorithm stops by giving the following err
Hi,
I have a zoo object with the first column as index. The columns have not been
named yet... but that I can change. It looks like this :
V2 V3 V4 V5 V6
2014-03-14 22:41:46.988804 10 2 8 3 14
2014-03-14 22:41:46.991126 13 4 9
Hi,
I am trying to install the newest version of R-3.0.3 from source and I've
been successful in the configuration using this command:
./configure --enable-R-shlib --with-x=no
--prefix=/home/fcchan/usr/local/R-3.0.3
When I run make, I run into this issue:
gcc -std=gnu99 -I../../src/extra/zlib -
I've got a dataset with really long column names (e.g.,
CYJ.OSU.OAV.UJC.BUT.RDI). What I'd like to do is replace the fourth period
with a break ("\n") so that when it plots, it will not run off the page.
Here's what I've got so far:
create fake names function
fake.names = function(x){
pas
Not exactly automatic, but if you are using Windows:
1. Open a blank spreadsheet in Excel
2. write.table(cor(nums2), file="clipboard-128", sep="\t") # In
R
3. Paste the clipboard into the spreadsheet
Package xlsx can write Excel format files, but does not put them
directly into Excel.
For the se
In line
John Kane
Kingston ON Canada
> -Original Message-
> From: pavnee...@yahoo.co.uk
> Sent: Tue, 18 Mar 2014 10:10:38 +
> To: r-help@r-project.org
> Subject: [R] Fwd: R basic data manipulation Queries
>
>
>
>
>
>
> Sent from Samsung Mobile
>
> Original message ---
Jonathan:
As David said, this is a key aspect of S4 (there are others, of
course). But it can be "simulated" in S3, I think, albeit inelegantly.
You merely have to extend the class of "object", the fitted object you
dispatch on, and then write an appropriate method for this extended
class. e.g.
On Mon, Mar 17, 2014 at 4:08 AM, David Winsemius wrote:
> S3 classes only dispatch on the basis of the first parameter class.
A minor distinction: S3 classes only dispatch on the basis on *one* of the
parameters. The person who writes the generic gets to choose, and for
predict() it is the first
David:
Thanks! Is it generally frowned upon (if I'm Incorporating this into
a package) to "override" a generic function like "predict", even if I
plan on making it a pass-through function (same parameters, and if the
data type doesn't match my "weird" data type, it will simply pass the
parameters
Hello,
http://www.chikyu.ac.jp/precip/products/index.html
HTH,
Pascal
On Tue, Mar 18, 2014 at 10:09 PM, eliza botto wrote:
> Thankyou very much indeed.My limited knowledge of R is forcing me to ask you
> that how did you know the following information (AphroJP, 123°E-146°E,
> 24°N-46°N, resolu
Thankyou very much indeed.My limited knowledge of R is forcing me to ask you
that how did you know the following information (AphroJP, 123°E-146°E,
24°N-46°N, resolution 0.05x0.05 i.e. 440 rows x 460columns)? Thanks,
Eliza
> From: kri...@ymail.com
> Date: Tue, 18 Mar 2014 21:39:58 +0900
> Subjec
Hello,
It is not around the world. It is only for Japan (AphroJP,
123°E-146°E, 24°N-46°N, resolution 0.05x0.05 i.e. 440 rows x 460
columns). You can store in a Raster* object then extract the grid
points you need, with the coordinates.
HTH
Pascal
On Tue, Mar 18, 2014 at 9:21 PM, eliza botto
Dear all,
I wasn't successful in finding any related "bug" or "wish" report on
bugs.r-project.org, svn.R-project.org/R/trunk/doc/NEWS.Rd, or RSeek
regarding the following:
The code of stats:::print.aov contains the two commands
cat("Residual standard error: ", sapply(sqrt(ss/rdf), format), "
Hi
So perhaps doing neilist == pfriends is the same as doing neilist ==
rep(pfriends, 9)?
neilist <- c(13, 15, 28, 29, 30, 13, 14, 15, 28, 30, 43, 44, 45, 14, 15, 29,
44, 45)
pfriends <- c(13, 15)
cbind(neilist == pfriends, neilist == rep(pfriends, 9))
[,1] [,2]
[1,] TRUE TRUE
[2,
On 18/03/2014 7:14 AM, Thomas wrote:
Does anyone know why this is happening? Which() is picking up the
indices of the numbers 13 and 15 in neilist, but it's missing out the
13 at index 6.
Thank you,
Thomas Chesney
> neilist
[1] 13 15 28 29 30 13 14 15 28 30 43 44 45 14 15 29 44 45
> pf
Hi Pascal,
Your code worked out perfectly but I have one question though. You wrote that
you did not use stations. What if I want to read stations as i am only
interest in a part of data. I need it because the file has data for 202400
stations around the globe and I am only interest in data of 2
... and it is also missing the 15 at position 15.
Can't explain but
> which( neilist %in% pfriends )
should give you what you want.
On Tuesday 18 March 2014 11:14:08 Thomas wrote:
> Does anyone know why this is happening? Which() is picking up the
> indices of the numbers 13 and 15 in
I think you want to do
which(neilist %in% pfriends)
-Original Message-
From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org] On
Behalf Of Thomas
Sent: Tuesday, March 18, 2014 6:14 AM
To: r-help@r-project.org
Subject: [R] Which() missing a number
Does anyone know why
Sent from Samsung Mobile
Original message
Subject: R basic data manipulation Queries
From: Pavneet Arora
To: pavnee...@yahoo.co.uk
CC:
Hello Guys
I am new in R, so please excuse the really basic questions. I have tried
reading numeral tutorials, but I am still stuck.
Q
Does anyone know why this is happening? Which() is picking up the
indices of the numbers 13 and 15 in neilist, but it's missing out the
13 at index 6.
Thank you,
Thomas Chesney
> neilist
[1] 13 15 28 29 30 13 14 15 28 30 43 44 45 14 15 29 44 45
> pfriends
[1] 13 15
> which(neilist==pfrie
On 14-03-17 8:43 PM, Mike Miller wrote:
On Mon, 17 Mar 2014, Duncan Murdoch wrote:
On 14-03-17 6:22 PM, Mike Miller wrote:
Thanks! Another thing I've figured out: Use of "drop0trailing=T" in
format() fixes the .0 stuff that I didn't like:
write.table(format(data[1:10,], digits=5, trim=
Dear Pascal, Dan and Macqueen,
Thankyou very much for your help. With pascal' code I was managed reading the
file.
Thanks,
Eliza
> From: kri...@ymail.com
> Date: Tue, 18 Mar 2014 08:51:01 +0900
> Subject: Re: [R] open unknown file format in R
> To: eliza_bo...@hotmail.com
> CC: r-help@r-project.
Good morning everyone,
I am looking for a package in R cran to fit a double logistic curve like
this:
http://en.wikipedia.org/wiki/File:Dsigmoid.png
but the packages I've found are not running for my data, in particular:
"phenex" package is specifical for NDVI data,
"FlexParamCurve" is really i
On Mon, 17 Mar 2014 15:18:50 -0700 Jinsong Zhao wrote
> Hi there,
>
> I hope to rotate the Y label of axis(4) with -90 degree. I can typeset
> the Y label using text() with srt = -90. However, I cannot get the
> coordinate of the position that mtext() used.
>
<...cut...>
locator(1) # Works
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