A.K.
Thanks for the reply. Will give it a try...
Jac
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View this message in context:
http://r.789695.n4.nabble.com/Importing-renaming-columns-and-exporting-mulitple-csv-files-in-R-tp4676951p4676959.html
Sent from the R help mailing list archive at Nabble.com.
___
Hi,
Try:
If the files are all in the same working directory,
#for example
list.files() # 3 files in my WD
#[1] "file1.csv" "file2.csv" "file3.csv"
lapply(list.files(),function(x) {names1<-read.csv(x,header=TRUE);
names(names1)[c(19,23)]<- c("Redundant","Reef % cover"); dat1<-
subset(names1,
Hi All,
I have 1029 *.csv files that I would like read individually into R, delete
some columns and rename others, and then export individually using the
original file names.
I have written some script to do this for an individual file (script below),
but cannot get it to loop through all the fi
Dear Filipe
On 25 September 2013 14:23, Filipe Ribeiro wrote:
> Hello everybody!
>
> I'm having some trouble to compute maximum likelihood
> estimations using maxLik package and I hope that you
> could give me a hint.
> The main problem is that I'm not able to get a result not
> even close to the
Hello,
I am mildly annoyed each time I use a PDF doc of an R package that the
table of contents hyperlinks are *only* on the page numbers. To activate
a hyperlink, one must carefully scan sideways from the text item wanted
to the far right of the page and click on a tiny box. Multiply that mild
Hello,
Please post in plain text, as kindly requesting by the R-help posting
guide. Your code is completely messy.
Regards,
Pascal
2013/9/26 mahesh samtani
> Hello,
> I am trying to add a less than equal to symbol in a ggplot2 legend text.
> See sample code below. I have tried using the expre
Hello,
I am trying to add a less than equal to symbol in a ggplot2 legend text.
See sample code below. I have tried using the expression function and
\u2264. I also tried adding labels to legend.text under theme.
Neither of these 3 options work.
Please help,
Mahesh
++
Extra.column
megha patnaik wrote
> Dear All,
>
> I am trying to use the felm function in the lfe package. However it does
> not seem to deal with missing values the way the lm function does. I wish
> to tell it na.omit or na.action = na.omit but it does not recognize this.
> I
> need to allow for missing value
Dear all,
a few weeks ago I have seen a package containing the so called "endive
dataset" first appeared in Besag (1978) "Some Methods of Statistical
Analysis for Spatial Data," Bulletin of the International Statistical
Institute, 47, 77-92. Now I would need to use the dataset, but I can no
lo
On Sep 25, 2013, at 5:55 AM, steric wrote:
It was just a question to see if it was possible on a large data
set. I
wasn't looking for a flame war. New strategy is simply new strategy.
Half of
my time spent on R is trying to find a better way.
If you say why you want to do a global test wit
Ira,
You may try also with ?ddply()
dat2<-
data.frame(S1=rep(Pred1[,1],ncol(Pred1)-1),variable=rep(colnames(Pred1)[-1],each=nrow(Pred1)),Predict=unlist(Pred1[,-1],use.names=FALSE),Actual=unlist(Actual1[,-1],use.names=FALSE),stringsAsFactors=FALSE)
identical(dat,dat2)
#[1] TRUE
dat2New<- dat2[!(
I'm pretty sure that your answer has nothing to do with what the OP was
asking about.
OTOH it's up to the OP to make it clear what he ***is*** asking and he
did not do that.
cheers,
Rolf Turner
On 09/26/13 01:00, João Pedro Alves wrote:
x<-seq(0,2*pi,by=0.01)
y<-cos(x)
plot(x,y,
On 09/25/13 16:10, David Winsemius wrote:
There is quite a bit of misinformation about the "need for normality",
some of it presented by Six Sigma "experts" or even by college
professors who should know better. One might even say that if you
don't know how to check for normality then there i
On 25/09/2013 22:29, Ben Bolker wrote:
Erich Neuwirth univie.ac.at> writes:
I just installed R on a Mac without any traces of earlier versions.
It exhibited a well know problem:
Not 'well known' (sic) at all: most of us do not break our OS X. We
don't have reproduction instructions (see t
Erich Neuwirth univie.ac.at> writes:
>
> I just installed R on a Mac without any traces of earlier versions.
> It exhibited a well know problem:
>
> WARNING: You're using a non-UTF8 locale, therefore only ASCII
> characters will work.
> Please read R for Mac OS X FAQ (see Help) section 9 and
Hello,
I was wondering if weighting has been added to glmmadmb as of yet? I found
a post about a year ago that it it hadn't been implemented yet but I was
hoping the documentation may just have not yet caught up.
Thanks,
Trevor Davies
[[alternative HTML version deleted]]
___
Hi,
May be you can try this:
obj_name<- load("arun.RData")
Pred1<- get(obj_name[1])
Actual1<- get(obj_name[2])
library(reshape2)
dat<-cbind(melt(Pred1,id.vars="S1"),value2=melt(Actual1,id.vars="S1")[,3]) #
to reshape to long form
colnames(dat)[3:4]<- c("Predict","Actual")
dat$variable<- as.cha
I just installed R on a Mac without any traces of earlier versions.
It exhibited a well know problem:
WARNING: You're using a non-UTF8 locale, therefore only ASCII characters will
work.
Please read R for Mac OS X FAQ (see Help) section 9 and adjust your system
preferences accordingly.
The infor
Hi A.K.,
This is exactly what I needed:
x <- data.frame(Month = airquality$Month, Day = as.character(airquality$Day))
y <- aggregate(x$Day ~ x$Month, data = x, paste, collapse = ", ")
write.table(y, "y.txt", row.names = FALSE, quote = FALSE, sep = '\t')
The trick is to use collapse in the aggreg
Hello,
I have a question on sp package.
I drew pixel heat maps of continental U.S. using insurance litigation data.
If an insurance claim is litigated at a certain location, 1 is assigned;
otherwise 0 is assigned. I have assigned a value between 0 and 1 to each
pixel on my map using inverse-dista
Hi,
my english is not the best, i hope its comprehensible. Can i ask here in
german too?
my problem:
I have plottet a curve with weibull1.4. I want to define a value on the
y-axis and get the value of the x-axis for the plotted curve.
This is my command:
library(drc)
effect<-c(0,22.84,40.74,54.
Dear List,
I am having difficulty running the ps() function when variables are stored
as factors and was hoping someone could provide some advice on how to
proceed.
I am running propensity score matching as outlined in:
Greg Ridgeway, Dan McCarey, Andrew Morral, Lane Burgette and Beth A
I guess you meant something like:
res2<- sapply(y,function(i) outer(x,x,i))
row.names(res2)<- row.names(res)
identical(res2,res)
#[1] TRUE
#or is there any shorter way?
A.K.
From: Bert Gunter
To: arun
Cc: R help
Sent: Wednesday, September 25, 2013 11:46 AM
Hi,
sorry for the double posting, but it seems my text was gone...
I'm running a code which does some alignment between data.
Now I want to follow the alignment while looping over the data.
I'm aware of the animation package, and saw the (easy) example where a plot
is animated by calling 100 t
Hi,
I'm running a code which does some alignment between data.
Now I want to follow the alignment while looping over the data.
I'm aware of the animation package, and saw the (easy) example where a plot
is animated by calling 100 times plot.
Is it possible to use this trick also for printing
A cute problem. Is it homework?
Hint: ?outer
(will provide a much simpler solution than those given below)
-- Bert
On Wed, Sep 25, 2013 at 8:34 AM, arun wrote:
> Hi,
> You could also try:
> res1<-sapply(y,function(i) {x1<- expand.grid(x,x);fun1<- function(a,op,b){
> f1<- match.fun(FUN=op); f1(
Hi,
You could also try:
res1<-sapply(y,function(i) {x1<- expand.grid(x,x);fun1<- function(a,op,b){ f1<-
match.fun(FUN=op); f1(a,b)};fun1(x1[,1],i,x1[,2])})
row.names(res1)<- row.names(res)
identical(res1,res)
#[1] TRUE
A.K.
- Original Message -
From: arun
To: R help
Cc:
Sent: Wedne
Hi,
May be this helps:
y<- aggregate(Day~Month,data=x,paste,collapse=",")
write.table(y,"file.txt",quote=FALSE)
A.K.
- Original Message -
From: "Lietz, Haiko"
To: "'r-help@r-project.org'"
Cc:
Sent: Wednesday, September 25, 2013 9:10 AM
Subject: [R] Multiple vector elements into one
Perhaps ?dput
-- Bert
On Wed, Sep 25, 2013 at 6:10 AM, Lietz, Haiko wrote:
> Hi all,
>
> I want to collapse multiple elements of a vector into a single
> comma-separated character element. I only know how to create a list of the
> original elements, but I have not managed to write this into a
x<-seq(0,2*pi,by=0.01)
y<-cos(x)
plot(x,y,type='l')
On 25-09-2013 13:22, Babak Bastan wrote:
Hi experts
Can some one tell me, how can I implement Cosine window in r? Is there a
function for that?
[[alternative HTML version deleted]]
__
R-hel
DO NOT DO THIS!
This is a complete misuse of R.
R is not a macro/scripting language that constructs language expressions to
be evaluated (although it can do this). Rather, it is a functional language
that uses functions that build new objects from inputted objects and
parameters. I would strongly
It was just a question to see if it was possible on a large data set. I
wasn't looking for a flame war. New strategy is simply new strategy. Half of
my time spent on R is trying to find a better way.
--
View this message in context:
http://r.789695.n4.nabble.com/Checking-a-large-data-set-for-no
Hello all,
I'd like to use the Bioconductor motifStack function to align multiple DNA
sequence motifs as PWMs (Position Weight Matrices).
1.Requires both ghostscript, and the R function grImport for converting.
postscript files. - Have 64 bit GS 9.10 and R 3.01 is installed in 64 bit
Windows
Hello everybody!
I'm having some trouble to compute maximum likelihood estimations using maxLik
package and I hope that you could give me a hint.
The main problem is that I'm not able to get a result not even close to the
ones given by glm() directly, and the second one is: "Error in maxNRComput
Hi all,
I want to collapse multiple elements of a vector into a single comma-separated
character element. I only know how to create a list of the original elements,
but I have not managed to write this into a text file, which is necessary.
To illustrate, let's use the airquality dataset and ext
Thanks for your help, and sorry for mis-posting.
JD
On Wed, Sep 25, 2013 at 3:18 AM, Matthew Dowle wrote:
> Very sorry to hear this bit you. If you need a copy of names before
> changing them by reference :
> oldnames <- copy(names(DT))
> This will be documented and it's on the bug list
Also, Instead of ?attach, you could try ?with or ?within
aa$z<- with(aa,eval(parse(text=bb)))
aa$z
#[1] 3 7 11
aa<- within(aa,z<- eval(parse(text=bb)))
aa
# x y z
#1 2 3 3
#2 4 5 7
#3 6 7 11
A.K.
- Original Message -
From: arun
To: R help
Cc:
Sent: Wednesday, September 25, 201
Hi,
Change:
aa$z<- eval(parse(text=bb))
aa
# x y z
#1 2 3 3
#2 4 5 7
#3 6 7 11
A.K.
I want to create a new column to a data frame using a formula from another
variable:
Example:
I have a data set "aa" is;
x y
2 3
4 5
6 7
My R code is;
>bb <- "x+y-2"
>attach(aa)
>aa$
Hi experts
Can some one tell me, how can I implement Cosine window in r? Is there a
function for that?
[[alternative HTML version deleted]]
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the pos
The build system rolled up R-3.0.2.tar.gz (codename "Frisbee Sailing") this
morning.
The list below details the changes in this release.
You can get the source code from
http://cran.r-project.org/src/base/R-3/R-3.0.2.tar.gz
or wait for it to be mirrored at a CRAN site nearer to you.
Binaries
Hi
If you did
PLEASE do read the posting guide http://www.R-project.org/posting-
guide.html
you could find
No binary attachments except for PS, PDF, and some image and archive formats
(others are automatically stripped off because they can contain malicious
software). Files in other formats and
> Martin Maechler
> on Wed, 25 Sep 2013 11:08:07 +0200 writes:
> Michel
> on Tue, 24 Sep 2013 12:22:10 +0200 writes:
>> Hello, Thanks for your answer The file does not contains
>> numbers in high precision but all the calculation applied
>> to these data wil
Looks like graph cannot be attached.
Mohan
From: mohan.radhakrish...@polarisft.com
To: r-help@r-project.org
Date: 09/25/2013 12:41 PM
Subject:[R] Space between x-axis ticks
Sent by:r-help-boun...@r-project.org
Hi,
I am trying to clearly show the values in t
> Michel
> on Tue, 24 Sep 2013 12:22:10 +0200 writes:
> Hello, Thanks for your answer The file does not contains
> numbers in high precision but all the calculation applied
> to these data will be
> In attachment a text file containing some lines And her
> few va
Very sorry to hear this bit you. If you need a copy of names before
changing them by reference :
oldnames <- copy(names(DT))
This will be documented and it's on the bug list to do so. copy is
needed in other circumstances too, see ?copy.
More details here :
http://stackoverflow.com/q
Hi
It is mostly question of personal preference. Factors have some nice features
when manipulating with levels, sorting, and/or using numeric annotation.
However when you want to add some new value to factor it is trickier than with
plain string vectors. Maybe it is time to look into R-intro ex
Hi,
I am trying to clearly show the values in the x-axis in the
attached graph. The tick marks are too close and the labels are blurred.
plot(as.numeric(data$Var1),data$Freq,ylim=c(0,700),col="green",type="o",ylab="Number
of connections",las=2,lwd=2.5,xaxt="n",xlab="IP")
axis(1,at
Hi,
Try:
x<- 1:4
y<- c("*","/","-","+")
res<-sapply(y,function(i) {x1<-expand.grid(x,x);
unlist(lapply(paste0(x1[,1],i,x1[,2]),function(u) eval(parse(text=u})
row.names(res)<- as.character(interaction(expand.grid(x,x),sep="_"))
head(res)
# * / - +
#1_1 1 1.0 0 2
#2_1 2 2.0 1 3
#3_1 3
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