What did the OpenStreetMap maintainer say (see the posting guide)?
Hint: he and the raster maintainer are aware of their problem, and a
correction is way overdue.
The issue is not Ubuntu vs Mac but the order in which packages are
installed (and for binary packages that is when they were instal
I was looking for something like shown on the map:
http://upload.wikimedia.org/wikipedia/commons/8/88/World_Time_Zones_Map.png
Information about local daylight savings times would also help.
The data are from ships, supposedly in local time, but no time-zone info is
given. A function that would
Hi,
I believe the function you are looking for is:
which("yourdata" == 0, arr.ind = T)
The "arr.ind" parameter in the "which" function will return you a
matrix with row, column indices for where there are 0's in your
dataset.
set.seed(6584)
data <- matrix(sample(c(0,1), 36, replace = T), nc = 6
Hi,
I'm a novice in R and I was trying to play with OpenStreetMap package as in a
few examples on the web. And the examples worked on my Mac but on Ubuntu
(12.04) they fail to work. The simplest one is:
library(OpenStreetMap)
library(rgdal)
map <- openmap(c(70,-179), c(-70,179))
plot(map)
(Open
Hi Arun,
I get the following error when I enter the command:
library(reshape2)
Error in library(reshape2) : there is no package called âreshape2â
Any ideas?
Thanks again.
On Fri, Sep 20, 2013 at 3:09 PM, arun kirshna [via R] <
ml-node+s789695n4676569...@n4.nabble.com> wrote:
> Hi Eli
Hello all,
I´m have a very large data frame (more than 5 million lines) as below (dput
example at the end of mail):
Station Antenna TagDateTime Power Events
1 1 2 999 22/07/2013 11:00:2117 1
2 1 2 999 22/07/2013 11:33:4731 1
3 1 2
Hi,
Try this:
set.seed(248)
lst1<- lapply(1:1000,function(i) matrix(
sample(0:1,15*100,replace=TRUE),ncol=100,dimnames=list(paste("Island",LETTERS[1:15]),
paste0("D",sprintf("%04d",1:100)
lst2<-lst1[sapply(lst1,function(x) any(colSums(x)==0))]
##The above steps are just to create some ma
Depending on what your doing perhaps with() could help?
Or assuming a data.frame or matrix, score[ , 25] will give you Score$X25
If you would supply a bit more information (and code) about what you are doing
we probably can help more.
John Kane
Kingston ON Canada
> -Original Message-
Once you learn to use dput() I am sure someone will be happy to help you.
http://stackoverflow.com/questions/5963269/how-to-make-a-great-r-reproducible-example
John Kane
Kingston ON Canada
> -Original Message-
> From: elaine.kuo...@gmail.com
> Sent: Sat, 21 Sep 2013 07:14:38 +0800
> T
Dear list
I have a matrix composed of islandID as rows and speciesID as columns.
IslandID: Island A, B, C
.O (15 islands in total)
SpeciesID: D0001, D0002, D0003
.D0100 (100 species in total)
The cell of the matrix describes presence (1) or absence (0) of the species
in an island.
Now I
Thanks Duncan. I have no knowledge of SAS, though many in industry use it.
I hope R would expand its usage to more at the industry level.
Mike
On Fri, Sep 20, 2013 at 12:17 PM, Duncan Murdoch
wrote:
> On 20/09/2013 11:52 AM, C W wrote:
>
>> Dear R community,
>> I am having trouble changing the
Hi,
Are you using Linux? If so, you may use ImageMagick and try your luck
using
convert filename.whatever.format filename.tiff
There are lots of options in ImageMagick. (Read the manual.)
I have done this in the past, and it has worked. However, your exact
situation may be different, so sorry
On Sep 20, 2013, at 8:02 AM, carlisle thacker wrote:
I have data that provide longitude, latitude, and local date and
time but
no information about the corresponding time zone. How to identify
the time
zone so they can be converted to a common date/time?
Perhaps as an approximation you c
HI,
we are pleased to announce 2 weeks intensive training in:
*SPATIO-TEMPORAL ANALYSIS AND BIG DATA PROCESSING USING FREE AND OPEN
SOURCE SOFTWARE*
16-20 December 2013 & 20-24 January 2014
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Over the few decades there has been an explosio
Thanks I'm lookin for yur example
-Message d'origine-
De : r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org] De
la part de arun
Envoyé : vendredi 20 septembre 2013 18:11
À : R help
Objet : Re: [R] Compare two subsequent rows based on specific values of a
string
Hi,
May be
On Sep 20, 2013, at 11:17 AM, Duncan Murdoch wrote:
> On 20/09/2013 11:52 AM, C W wrote:
>> Dear R community,
>> I am having trouble changing the tick marks on y-axis to every 5 units? I
>> have the following:
>>
>> x <- c(12, 16, 6, 23, 27, 8, 5, 19, 23, 13, 16, 8)
>>
>> y <- c(29, 29, 23, 3
If you make no further assumptions then this question is not solvable. For
example we use standard time in our data collection systems even though legal
time here applies daylight savings offset in the summer. In some cases I have
seen data collected from sites in multiple time zones recorded in
Hey all,
I've fitted two GAMs to some data using mgcv. The only difference between the
two models is that one includes an additional smooth term (the smooth terms are
s(x), s(y) and s(log(y)), the difference being that one model contains s(y) as
additional term whereas the other one only contai
Hi,
I am struggling to save my figures as TIFF files (yes, the yournal only accept
TIFF and not any other format).
I can manage to save a simple plot as TIFF at the correct dpi (I need at least
600dpi) and compression works. Only not for my own plot. Everything looks
distorted. I have read Stac
Hi,
May be this helps:
dat1<- read.table(text="x1 x2 x3 x4
1 xz ab cd ef
2 ab fz cd ef
3 ab cd dy dx",sep="",header=TRUE,stringsAsFactors=FALSE)
dat1$changes_to_row_above<- sapply(seq_len(nrow(dat1)),function(i)
{x1<-dat1[,i]%in% dat1[,i-1];if(any(x1))
On 20/09/2013 11:52 AM, C W wrote:
Dear R community,
I am having trouble changing the tick marks on y-axis to every 5 units? I
have the following:
x <- c(12, 16, 6, 23, 27, 8, 5, 19, 23, 13, 16, 8)
y <- c(29, 29, 23, 34, 38, 24, 22, 34, 36, 27, 33, 27)
plot(x, y, pch=19)
Should I change ylim
I initially posted this question to one of the StackExchange sites, and they
suggested that I repost my problem here.
After using ezANOVA as my primary way of specifying mixed ANOVAs, I've hit a
stumbling block when it come to adding a covariate to the model. I am using an
ANCOVA in order to de
hi
probably a silly mistake, but I expected gam to minimise the penalised
deviance.
thanks
greg
set.seed(1)
library(mgcv)
x<-runif(100)
lp<-exp(-2*x)*sin(8*x)
y<-rpois(100,exp(lp))
plot(x,y)
m1<-gam(y~s(x),poisson)
points(x,exp(lp),pch=16,col="green3")
points(x,fitted(m1),pch=16,cex=0.5,col="bl
Hi everyone!
I have now been using odfWeave() for a while in order to make some word
document reports of my data. I have encountered a problem when I try to
organize my program script into some functions. It seems that if I use the
odfWeave() within a function, then odfWeave() is not able to acces
please ignore this, I see the error.
greg
> hi
>
> probably a silly mistake, but I expected gam to minimise the penalised
> deviance.
>
> thanks
>
> greg
>
> set.seed(1)
> library(mgcv)
> x<-runif(100)
> lp<-exp(-2*x)*sin(8*x)
> y<-rpois(100,exp(lp))
> plot(x,y)
> m1<-gam(y~s(x),poisson)
> points
I have data that provide longitude, latitude, and local date and time but
no information about the corresponding time zone. How to identify the time
zone so they can be converted to a common date/time?
Thanks,
Carlisle
[[alternative HTML version deleted]]
__
Hello everyone,
R beginner, I am confronted with the need to use Rmpf.
In my first scripts I made use of
X=read.table(file.choose(), header=FALSE, sep=",",dec=".")
X=as.matrix(X)
to load into a matrix data from file before matrix use.
How can I do to load the same data in a "mpfrMatrix".
Is
Dear R community,
I am having trouble changing the tick marks on y-axis to every 5 units? I
have the following:
x <- c(12, 16, 6, 23, 27, 8, 5, 19, 23, 13, 16, 8)
y <- c(29, 29, 23, 34, 38, 24, 22, 34, 36, 27, 33, 27)
plot(x, y, pch=19)
Should I change ylim=c(0,40), and then use axis()?
I kep
or
with(score.plot(X1, X2))
Clint BowmanINTERNET: cl...@ecy.wa.gov
Air Quality Modeler INTERNET: cl...@math.utah.edu
Department of Ecology VOICE: (360) 407-6815
PO Box 47600FAX:(360) 407-7534
Olympia,
On Sep 13, 2013, at 11:21 PM, E Joffe wrote:
Hi David,
First I ordered the levels of each factor in a descending order
based on
frequency.
Then, I used the following code to generate a matrix from the
dataframe with
dummy variables and subsequently run the glmnet (coxnet)
## tranform c
On Fri, Sep 20, 2013 at 10:10 AM, Preetam Pal wrote:
> I have 25 variables in the data file (name: score), i.e. X1,X2,.,X25.
>
> I dont want to use score$X1, score$X2 everytime I use these variables.
>
attach(score)
plot(X1, X2) # etc. etc.
-Aaron
[[alternative HTML version delete
Dear R help list,
I was just wondering whether there is a way to cluster the documentation files
of data sets in the package documentation index file, so that common prefixes
such as "dat..." are not necessary.
Best wishes,
Alrik
Dr. Al
You haven't said yet, what object your 'data file' is. If you mean a data.frame
I would use colnames(dataName) <- c("Col1Name", "col2Name", ….)
Best
Simon
On Sep 20, 2013, at 4:10 PM, Preetam Pal wrote:
> Hi,
>
> I guess this is pretty basic.
>
> I have 25 variables in the data file (name: s
You are close--think "names", not "titles", as in rownames or colnames (no
reason to completely spell out column). Summary already gave you the
column names, so type "?rownames" to learn more.
Clint BowmanINTERNET: cl...@ecy.wa.gov
Air Quality Modeler INTE
Hi,
I guess this is pretty basic.
I have 25 variables in the data file (name: score), i.e. X1,X2,.,X25.
I dont want to use score$X1, score$X2 everytime I use these variables.
Is there a way I can rename all these variables as simply X1,X2,.X25
without writing 25 lines of code, one line
library(stringr)
read.table(text=gsub("[()]","",str_trim(input[input!=""])),sep="",header=FALSE,stringsAsFactors=FALSE)
# V1 V2 V3
#1 6.2 httpd 18
#2 4.0 httpd 11
#3 4.0 httpd 11
#4 3.3 httpd 9
#5 4.2 httpd 12
#6 4.2 httpd 12
#7 4.2 httpd 12
#8 4.2 httpd 12
#9 4.2 httpd 12
A.K.
- O
Replying with some code.
input<- readLines(textConnection("
6.2 httpd (18)
4.0 httpd (11)
4.0 httpd (11)
3.3 httpd (9)
4.2 httpd (12)
4.2httpd (12)
4.2 httpd (12)
4.2 httpd (12)
4.2 httpd (12)
"))
data<-input[input!=""]
> data
[1] " 6.2 httpd (18)" "
Hi Elio,
Try this:
library(stringr)
lines1<-str_trim(gsub("\t"," ",readLines("elio.txt")))
lst1<-lapply(split(lines1,cumsum(lines1=="")),function(x) x[x!=""])
lst2<- lapply(lst1[lapply(lst1,length)>0],function(x)
as.matrix(read.table(text=x,row.names=1)))
names(lst2)<- paste0("m",seq_along(lst
Can you point to any function in specific?
On Fri, Sep 20, 2013 at 12:10 PM, Pascal Oettli wrote:
> Hello,
>
> Please have a look at:
> http://cran.r-project.org/web/views/TimeSeries.html
>
> Regards,
> Pascal
>
>
>
> 2013/9/20 Indrajit Sengupta
>
>> I am trying to replicate ARIMA models in R
Hi,
it seems the following works as needed...
Mat[,colnames(Mat)=="a"]
Olivier.
On Fri, 20 Sep 2013 16:22:37 +0530
Christofer Bogaso wrote:
> Hello again,
>
> I have one question on subscripting matrix. Let say I have following
> matrix:
>
> > Mat <- matrix(1:9, 3)
> > colnames(Mat) <- c("a
On 20-09-2013, at 12:52, Christofer Bogaso wrote:
> Hello again,
>
> I have one question on subscripting matrix. Let say I have following matrix:
>
>> Mat <- matrix(1:9, 3)
>> colnames(Mat) <- c("a", "b", "a")
>> Mat
> a b a
> [1,] 1 4 7
> [2,] 2 5 8
> [3,] 3 6 9
>
>
> Now I want to fetc
Hello again,
I have one question on subscripting matrix. Let say I have following matrix:
> Mat <- matrix(1:9, 3)
> colnames(Mat) <- c("a", "b", "a")
> Mat
a b a
[1,] 1 4 7
[2,] 2 5 8
[3,] 3 6 9
Now I want to fetch data for colnames 'a'.I did following:
> Mat[, "a"]
[1] 1 2 3
However it
Hi,
as far as I know, there is no limitation on data size in regard to foreach. You
should reserve though enough memory for your application on the cluster (via
ulimit -s unlimited and ulimit -v unlimited).
Furthermore I would check the following:
Check if there are two versions of R on the c
Hi
> -Original Message-
> From: r-help-boun...@r-project.org [mailto:r-help-bounces@r-
> project.org] On Behalf Of David Winsemius
> Sent: Friday, September 20, 2013 6:39 AM
> To: ivanc010
> Cc: r-help@r-project.org
> Subject: Re: [R] Need help to find out the name of my columns and rows
>
Package news (see below for general description of functionality)
depmixS4 version 1.3-0 has been released on CRAN. See the NEWS file
for an overview of all changes. The most important user-visible
changes are:
1) more compact pretty-printing of parameters in print/summary of
(dep)mix objects (fo
On 19/09/2013 15:28, Prigot, Jonathan wrote:
Sadly, I am limited to the Solaris 10 system. I wish that I could use
Linux, the world uses it.
What does that have to do with this?
The CRAN check farm uses gfortran 4.8 on a Solaris 10 system. g77 is
not the native compiler there, nor is that us
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