RStudio questions belong on the RStudio support website. It is fine software,
but it is off-topic here.
---
Jeff NewmillerThe . . Go Live...
DCN:Basics: ##.#. ##.#. Liv
On Jun 23, 2013, at 22:30 , Sarah Goslee wrote:
> Hi,
>
> If you're doing exactly as described below, then you need to add the
> data argument to wilcox.test so R knows where to find beforesmall and
> aftersmall. But if so, that's a rather uninformative error message.
>
> Saraj
Not really, if
On Jun 23, 2013, at 7:24 PM, Norman Jessup wrote:
> David,
>
> Thank you. You are correct - I was inadvertently accessing an old version.
> Deleting the old and re-installing means I can fire up R V3.0.1 which runs
> fine.
>
> However, I still can't get R Studio to start up, receivng the
David,
Thank you. You are correct - I was inadvertently accessing an old
version. Deleting the old and re-installing means I can fire up R
V3.0.1 which runs fine.
However, I still can't get R Studio to start up, receivng the following
message:
ERROR r error 4 (R code execution error) [
On Jun 23, 2013, at 1:54 PM, Sérgio Henrique almeida da silva ju wrote:
> I created a program that breaks a database in several other banks. But in
> this program I save this several banks in txt so now I'd like save in xls,
> but I don't know how.
>
> I tried for (nm in Nms) write.table(Res[[nm
Hello,
To work with xls files, check out package XLConnect. The vignette
explains how to use it rather well.
Also, don't use attach() It can be confusing and a source for errors.
Hope this helps,
Rui Barradas
Em 23-06-2013 21:54, Sérgio Henrique almeida da silva ju escreveu:
I created a pr
Argh!! I use those all the time! I can't believe I overlooked something
so obvious! Unfortunately, the pastebin was an abstraction of another
problem I was having that WAS, in fact, creating a formula in another
environment and passing it into the function the where data object was
created and m
What I mean is, I have a data set consisting of 3 columns x, y, z. X, Y
represent the location and Z represents depth. X, Y stay the same at some
locations but z changes. Because X, Y don't change at some locations, I
cannot convert to raster.
I need to create a .grd file so that the fault can be
I all,
I'm new on this list, so sorry if I do something wrong. Anyway, I have a
problem with the installation of the package StatDA.
Typing install.package("StatDA") I receive the error:
ERROR: configuration failed for package ‘MBA’
* removing ‘/home/matteo/R/i686-pc-linux-gnu-library/3.0/MBA’
I am trying to learn to tune a svm model in R.
I'm using the sonar data set used by David Mease in his Google Tech
Talk video. I downloaded the data from his site. There are 130
observations in the training set. I am able to run a svm model. But
when I try to run this command:
tune_svm <-tune.sv
On Jun 23, 2013, at 1:50 PM, Shane Carey wrote:
> Hi,
>
> I have a 3-d geology problem. I have an xyz fault data set. I am able to
> view the data set in R using plot3-d
That cannot be a function name, since it is invalid syntax.
> but cannot create a raster from it. I
> need to create a raste
Hello,
Sorry, I forgot to Cc the list.
Rui Barradas
Em 23-06-2013 21:44, Rui Barradas escreveu:
Hello,
See if the following does what you want.
lapply(seq_len(obsv), function(i) adf.test(df[df$ID == i, 3]))
Hope this helps,
Rui Barradas
Em 23-06-2013 19:12, Olga Musayev escreveu:
Short
On Jun 23, 2013, at 11:34 AM, ruth parker wrote:
> Hi,
> I've been trying to run a wilcox paired test on some data
> beforesmall aftersmall
> [1,]63.5 512.0
> [2,]54.5 237.5
> [3,]52.5 161.5
> [4,]78.0 153.5
> [5,]53.5 68.0
> [6,]
Hi,
I have a 3-d geology problem. I have an xyz fault data set. I am able to
view the data set in R using plot3-d but cannot create a raster from it. I
need to create a raster and export so that it can be read in arcscene. Can
anybody help?
Thanks
--
Shane
[[alternative HTML version d
By the way, you could use
lm(x ~ y + z, data=someData, weights=weight)
instead of
lm(x ~ y + z, data=someData, weights=someData$weight)
as 'weight' will be looked for in someData before any environment.
(You still don't want to get into the habit of passing formula strings to lm.)
Bill Dunl
HI,
May be this helps:
dat1<- read.table(text="
beforesmall aftersmall
63.5 512.0
54.5 237.5
52.5 161.5
78.0 153.5
53.5 68.0
50.5 65.5
69.0 52.0
76.0 59.0
68.0 66.5
75.5 66.5
67.0 45.5
81.0 54.5
49.0 44.0
51.0 42.5
53.0
Hi,
If you're doing exactly as described below, then you need to add the
data argument to wilcox.test so R knows where to find beforesmall and
aftersmall. But if so, that's a rather uninformative error message.
Saraj
On Sun, Jun 23, 2013 at 2:34 PM, ruth parker wrote:
> Hi,
> I've been trying t
Your web site had
WeightsBreaks <- function(){
someData <- data.frame(x = rnorm(20, 5, 1),y = 1:20 + runif(20),z =
70:51, weight = 0.05)
print( ls())
ModObject <- lm('x~y + z', data = someData, weights = someData$weight)
}
and I got the result
> print(WeightsBreaks())
[1] "s
1. acf already has a na.action argument which should be used instead
of the acf(na.omit(x)) construction.
2. But more to the point, acf(x,na=na.omit) may very well be complete
nonsense (see ?acf for hints at this). How to handle estimate
covariances with missingness and, more particularly, how to
Hi,
I've been trying to run a wilcox paired test on some data
beforesmall aftersmall
[1,]63.5 512.0
[2,]54.5 237.5
[3,]52.5 161.5
[4,]78.0 153.5
[5,]53.5 68.0
[6,]50.5 65.5
[7,]69.0 52.0
[8,]
Hi,
The acf function requires that you specify how to deal with NAs in your
data. By default, it uses na.fail ("Error in *na.fail.default*(as.ts(x)) :
missing values in object). Try using na.action=na.pass as an argument.
While this will pass over your NAs, make sure that you understand how that
w
Hello,
I'm running into what I believe is a scoping issue having to do with the
environment in which the weights argument is evaluated in lm. From the lm
documentation "All of weights, subset and offset are evaluated in the same
way as variables in formula, that is first in data and then in the
en
Short question: Is it possible to use statistical tests, like the Augmented
Dickey-Fuller test, in functions with for-loops? If not, are there any
alternative ways to scale measures?
Detailed explanation: I am working with time-series, and I want to flag
curves that are not stationary and which di
HI,
dat1<- read.csv("AMS3.csv",sep="\t",row.names=1)
pdf("AMS3_acf.pdf")
lapply(dat1,function(x)acf(na.omit(x)))
dev.off()
A.K.
From: Zilefac Elvis
To: arun
Cc: R help
Sent: Sunday, June 23, 2013 1:51 PM
Subject: Re: [R] Apply acf to data frame contain
On Sun, 23 Jun 2013, hck wrote:
Dear all, I try to conduct a SEM / two stage least squares regression with
the following equations:
See ivreg() in package "AER" or tsls() in "sem".
hth,
Z
First: X ~ IV1 + IV2 * Y
Second: Y ~ a + b X
therein, IV1 and IV2 are the two instruments I would like
Hi,
Thanks so much for the quick reply.
It worked on your data but failed on mine.
Attached is my data.
I received this error:
"Error in acf(na.omit(x)) : 'lag.max' must be at least 0
In addition: Warning message:
In split.default(x = seq_len(nrow(x)), f = f, drop = drop, ...) :
data length is n
Hi,
May be this helps:
set.seed(24)
A <- matrix(sample(c(NA,rnorm(1500)),1500,replace=FALSE),nrow=500)
par(mfrow=c(ncol(A),1))
lapply(split(A,col(A)),function(x) acf(na.omit(x)))
A.K.
- Original Message -
From: Zilefac Elvis
To: "r-help@r-project.org"
Cc:
Sent: Sunday, June 23, 2013
Hi,
I have a data frame with each column representing a separate site.
Following this code, I can apply acf to all columns in A. 'A' contains randomly
generated data.
A <- matrix(rnorm(1500),nrow=500)
par(mfrow=c(ncol(A),1))
lapply(split(A,col(A)), acf)
#OR
lapply(split(A,col(A)), function(snow
Hi,
i am tryng to run Bagging SVM but I have a problem. I do Bagging SVM based
on algoritm bagging Trees by Breiman. I get the following error and I think
I am wrong in calculating err.mean and err.vote. I also have difficulty in
making the plot.
> library(e1071)
> gendata <- function(N=30,p=5,r=.
Dear all, I try to conduct a SEM / two stage least squares regression with
the following equations:
First: X ~ IV1 + IV2 * Y
Second: Y ~ a + b X
therein, IV1 and IV2 are the two instruments I would like to use. the
structure I would like to maintain as the model is derived from economic
theory.
I get lubridate objects with the same decimal seconds while they are
different in the input char:
require(lubridate)
options("digits.secs"=3)
options("digits.secs")
$digits.secs
[1] 3
dias <- c("140613","140613")
moment <- c("100545.5", "100545.6")
paste(dias,moment)
[1] "140613 100545.5" "140613
Hello,
Sorry I forgot to Cc the list.
And I had forgotten the case where x == 0.
extract <- function(x){
e <- ifelse(x == 0, 0, floor(log10(x)))
m <- x/10^e
list(mantissa = m, exponent = e)
}
extract(c(0, 1.234e12, 12345678901234, 123e123))
Hope this helps,
Rui Barra
On 23/06/2013 12:59, Uwe Ligges wrote:
On 23.06.2013 01:50, Dr. T. Imam wrote:
Hi,
I am new to this forum, and hopefully am sending the post to the right
avenue (and in the appropriate format).
I am planning to prepare a (to be commercially sold) book in near future,
in which I expect to use
On 23.06.2013 01:50, Dr. T. Imam wrote:
Hi,
I am new to this forum, and hopefully am sending the post to the right
avenue (and in the appropriate format).
I am planning to prepare a (to be commercially sold) book in near future,
in which I expect to use some screenshots from R (running on Win
On 13-06-23 5:54 AM, Søren Højsgaard wrote:
Dear all,
Given a number
x<-1.234e12
is there a built-in function for extracting 1.234 and 12 ?
I don't think so, but it is not hard to build them from log10:
mantissa <- function(x) {
if (x == 0) 0
else {
log <- log10(abs(x))
10^(log
On 23/06/2013 10:54, Søren Højsgaard wrote:
Dear all,
Given a number
x<-1.234e12
is there a built-in function for extracting 1.234 and 12 ?
No, because that is not how the number is stored (and in fact the value
stored is a binary fraction with a slightly different value).
The following
Dear all,
Given a number
x<-1.234e12
is there a built-in function for extracting 1.234 and 12 ?
The following "hack" seems clumpsy:
> a<-strsplit(format(x, scientific=T),"e")[[1]]
> a
[1] "1.234" "+12"
> as.numeric(a[1])
[1] 1.234
> as.integer(a[2])
[1] 12
Regards
Søren
___
Hello R experts and Vegan users, I am re-posting my msg as I didn't get any
reply. I am not sure if it was not sent properly. Please help.
Sorry for repeated post.
I want to do ordination plots using vegan metaMDS.
I have a where many cells have zero values.
Data structure:
X[1:10,1:14]
H
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