On Mar 26, 2013, at 6:50 PM, Michael Budnick wrote:
> I am working on a gene expression microarray dataset, each sample has been
> taking from animal A and animal B on the same type of microarray.
>
> I would like to take the mean of these columns and create a dataset with
> columns with data
Hi All,
I am using canonical correspondence analysis to compare a community
composition matrix to a matrix of sample spatial relationships and
environmental variables. In order to parse out how much variance is
explained purely by space (S/E) or the environment (E/S) I am using a
conditional (parti
I am working on a gene expression microarray dataset, each sample has been
taking from animal A and animal B on the same type of microarray.
I would like to take the mean of these columns and create a dataset with
columns with data which are means of the corresponding rows of A and B
For exampl
Hi,
Try this: (Used the old data folder)
Compares the spec counts of sub directory with each other.
directory<- "/home/arunksa111/dados"
GetFileList <- function(directory,number){
setwd(directory)
filelist1<-dir()[file.info(dir())$isdir]
direct<-dir(directory,pattern = paste("MSMS_",num
You're welcome.
On 26/03/13 17:12, Patrick Connolly wrote:
On Tue, 26-Mar-2013 at 05:05PM +0900, Pascal Oettli wrote:
|> Hi,
|>
|> You are right. The following should solve that problem:
|>
|> plot(0, 0, pch = "")
|> text(0, .5, expression(Temperature~(degree*C)))
That does it, and is perfect
This is working perfectly now…thanks a lot for your help.
On 27/03/2013, at 2:36 AM, "Law, Jason" wrote:
> Try this:
>
> library(plyr)
> library(ggplot2)
> library(lubridate)
> data<-read.csv("http://dl.dropbox.com/u/4236038/test_cumu.csv";)
> data$Date <- as.Date(data$Date)
> cumu <- ddply(d
Thanks for the reply Achim.
The reason I suspect autocorrelation is because I think that within the
same neighborhood, homes sold a few months back are likely to impact the
price of homes sold subsequently. In fact the DW test and Breusch-Pagan
test come out to be significant. So even though the d
Thanks MW! Your comments were very helpful. I also see how the NextMethod()
works now.
On Mar 25, 2013, at 5:03 AM, R. Michael Weylandt wrote:
> On Mon, Mar 25, 2013 at 6:51 AM, Francisco J. Bido wrote:
>> Hi, I'm new to OOP in R so please forgive the naiveness of some of the
>> question
HI Elisa,
You need to review the formulas. Some of them (especially between 84 & 85 or 4
& 84 is not making sense, possibly typos). I changed it according to the
pattern of the formulas.
source("ElisaNew.txt")
#mat1 # dataset
res<-do.call(cbind,lapply(seq_len(nrow(mat1)),function(i)
do.call(
On Mar 26, 2013, at 2:51 PM, C W wrote:
> Dear list,
>
> I am a little confused as to when to use apply, sapply, tapply, vapply,
> replicate. I've encountered this several times,
> This is time, this is what I am working on,
>
> mat <- matrix(c(seq(from=1, to=10), rnorm(10)), ncol=2)
>
> a=1;
On Tue, 26 Mar 2013, SHISHIR MATHUR wrote:
Hello:
My dataset set contains several thousand rows of data, with each row
containing information for a house. The variables include the sale price of
the house, the quarter and year of sale, the attributes of the house, and
the attributes of the neigh
Hello,
The correct syntax would be
sapply(1:10, function(i) newfun(x=mat[i, 1], y=mat[i, 2], a=a, b=b))
Hope this helps,
Rui Barradas
Em 26-03-2013 21:51, C W escreveu:
Dear list,
I am a little confused as to when to use apply, sapply, tapply, vapply,
replicate. I've encountered this sev
Hello:
My dataset set contains several thousand rows of data, with each row
containing information for a house. The variables include the sale price of
the house, the quarter and year of sale, the attributes of the house, and
the attributes of the neighborhood and the city in which the house is
loc
Dear list,
I am a little confused as to when to use apply, sapply, tapply, vapply,
replicate. I've encountered this several times,
This is time, this is what I am working on,
mat <- matrix(c(seq(from=1, to=10), rnorm(10)), ncol=2)
a=1; b=5
newfun <- function(x, y, a, b)
{
x*y+a+b
}
sap
Do you want a histogram of the length distribution, or a barplot of
the actual lengths?
Either way,
myrle$lengths
will get it, if myrle is the output of rle().
?rle
tells you that:
‘rle()’ returns an object of class ‘"rle"’ which is a list with
components:
lengths: an integer vecto
> -Original Message-
> From: r-help-boun...@r-project.org [mailto:r-help-bounces@r-
> project.org] On Behalf Of Newbie1234
> Sent: Tuesday, March 26, 2013 2:03 PM
> To: r-help@r-project.org
> Subject: [R] Feed rle() output to hist()
>
> I want to make a histogram from the lengths vector wh
Hi Rui,
Thanks for trying. I know about the beside. The reason I want them stack with
various colors is that the 4 stacks represent the number of students on each
quartiles on a test.
Have a terrific Tuesday!
François
On 26 Mar 2013, at 21:45, Rui Barradas wrote:
> Hello,
>
> I forgot to
Hi David,
Thanks a lot for your advice and helping me tricking barplot. It totally work.
Have a great evening!
François
On 26 Mar 2013, at 21:43, David L Carlson wrote:
> You will have to trick barplot into thinking you have four groups:
>
>> wmod <- cbind(c(w[,1], 0, 0), c(0, 0, w[,2]))
>> b
Hi
I am trying to investigate the effect of topic (conversational context - 3
variants) on the linguistic production (code - 4 variants) of 16 speakers.
I want to run a mixed effects model with (speaker - 16 variants) and (word
500+ variants) as random effects to see whether they improve the model
I want to make a histogram from the lengths vector which is part of the
output of rle. But I don't know how to access that vector so that I use it
as an argument of hist(). What argument must I use so that I use the
lengths vector as an input to hist()?
Example output is:
Run Length Encoding
On Mar 26, 2013, at 12:38 PM, netra timalsina wrote:
> Hei,I am writing a zoo object and then loading it shows the following error
> message.any suggestion would be appreciated? #create zoo seriesreg.zoo <-
> zooreg(1:100, seq(from=as.Date("1999-01-01 "),'along.with'=100, by= "1 day"))
> #write
Second item in Google, searching for "Liddle Exact test McNemar test" was
"cran.r-project.org/web/packages/exact2x2/vignettes/exactMcNemar.pdf"
Guess you should have looked before asking.
Clint BowmanINTERNET: cl...@ecy.wa.gov
Air Quality Modeler INTERNET:
Proceeding to
www.rseek.org
and searching for
Liddle Exact Test
seems to provide at least one helpful result.
Sarah
On Tue, Mar 26, 2013 at 4:34 PM, gokhanocakoglu wrote:
> Dear friends,
> I am searching a code for Liddle Exact test which is equavelent to McNemar
> test...
> thanx for your att
Dear friends,
I am searching a code for Liddle Exact test which is equavelent to McNemar
test...
thanx for your attention for know
--
View this message in context:
http://r.789695.n4.nabble.com/Need-code-for-Liddle-Exact-test-tp4662549.html
Sent from the R help mailing list archive at Nabble.c
On 03/26/2013 12:52 PM, Peter Ehlers wrote:
Sooner or later most R beginners are bitten by this all too
convenient shortcut. [I.e. the use of $-extraction] As an R newbie,
think of R as your
bank account: overuse of $-extraction can lead to undesirable
consequences. It's best to acquire
You do exactly the same thing, just in the box in the lower left corner
(just above the Apply button) you need to scroll down and select "editorbg"
for the background and "editortext" for the text color.
On Fri, Mar 22, 2013 at 8:14 PM, Pfeiffer, Steven (pfeiffss) <
pfeif...@mail.uc.edu> wrote:
Petr,
Thanks. Wow! So little code for something that would require at least two
nested loops in C. Now I need to extract the output of rle() and feed it to
hist() if I want to draw a histogram (which I do). Can you give me any
comments on that?
N
--
View this message in context:
http://
Hei,I am writing a zoo object and then loading it shows the following error
message.any suggestion would be appreciated? #create zoo seriesreg.zoo <-
zooreg(1:100, seq(from=as.Date("1999-01-01 "),'along.with'=100, by= "1 day"))
#write zoo series write.zoo(reg.zoo ,file= "test.Rdata") #load
Hello,
I forgot to add that if you use argument beside = TRUE, you can have as
many colors as there are bars, but this is not the kind of graph you
want. (This behavior makes a lot of sense if you look at the underlying
code for barplot.)
Rui Barradas
Em 26-03-2013 19:39, Rui Barradas escre
You will have to trick barplot into thinking you have four groups:
> wmod <- cbind(c(w[,1], 0, 0), c(0, 0, w[,2]))
> barplot(wmod, main="2012", col=c("red", "green", "blue", "pink"))
--
David L Carlson
Associate Professor of Anthropology
Texas A&M Unive
Hello,
According to the code in file src/R/graphics/barplot.R, barplot() will
draw column by column, and threfore use as many colors as rows in the
matrix. Those colors will be reused for all bars. So I'm not seeing an
easy way of doing what you want using base graphics. Not without
changing
Dear all,
I have a 2 by 2 matrix and I would like to do a barplot with it. (so 2 bars
with each having 2 stacks.). I would like to have one colors per stack, so 4
different colors total.
The problem is that R is only given me 2 colors (the same two for the bottom
stack and the same two for th
> -Original Message-
> From: r-help-boun...@r-project.org [mailto:r-help-bounces@r-
> project.org] On Behalf Of Duncan Murdoch
> Sent: Tuesday, March 26, 2013 11:32 AM
> To: Santosh
> Cc: r-help@r-project.org
> Subject: Re: [R] suggestions about import SAS Transport files to R.
>
> On 26/0
On 26/03/2013 1:57 PM, Santosh wrote:
Dear Rxperts!
My colleagues used SAS PROC COPY to generate the xpt files that could be
read by the available "xpt" file reading packages in R. However, I am
unable to use the R packages for reading SAS transport files generated
through SAS PROC CPORT. I have
Hi Santosh,
On Tue, Mar 26, 2013 at 1:57 PM, Santosh wrote:
> Dear Rxperts!
>
> My colleagues used SAS PROC COPY to generate the xpt files that could be
> read by the available "xpt" file reading packages in R. However, I am
> unable to use the R packages for reading SAS transport files generated
Yes I believe that was the problem. Same question asked here:
https://github.com/yihui/knitr/issues/162#issuecomment-9017997
BTW, for future reference, this question was cross-posted at
http://stackoverflow.com/questions/15640353/execution-halted-when-i-use-knitr-and-rscript-with-opts-chunk
Regar
Dear Rxperts!
My colleagues used SAS PROC COPY to generate the xpt files that could be
read by the available "xpt" file reading packages in R. However, I am
unable to use the R packages for reading SAS transport files generated
through SAS PROC CPORT. I have tried SASxport, Hmisc, and foreign.
An
If the OP wanted a list output and if the data is what it looks like, may be
this helps.
dat1<-read.table(text="
ID Prod1 Prod2 Prod3 Prod4 Prod5
01 A - B - C
02 - F - G -
03 H - -
> -Original Message-
> From: r-help-boun...@r-project.org [mailto:r-help-bounces@r-
> project.org] On Behalf Of ankur verma
> Sent: Tuesday, March 26, 2013 10:22 AM
> To: r-help@r-project.org
> Subject: [R] Shifting cells and removing blanks
>
> Hi ,
>
> I've been struggling with this pro
On 26/03/2013 12:26 PM, Marcus Nunes wrote:
Hello all,
I wrote a bash script in Mac OS that takes my .rnw file, knit it and then
makes a .pdf. To knit my file, I'm using the command
Rscript -e "library(knitr); knit('file.rnw', encoding='utf8')"
and everything works fine. However, I don't want
Hey Jean,
This appears to have worked!! Thank you so much, this is an immense help to
me.
Best
On Tue, Mar 26, 2013 at 11:33 AM, Adams, Jean wrote:
> Thanks. That helps.
>
> Using the example data you sent, I came up with this loop. See if it does
> the trick for you.
>
> niter <- 2
> nspp <-
On 26.03.2013 15:10, Bismark Kofi wrote:
Please can someone explain to me how to use randomLCA in R for an analysis.
I tried using it and had this error (copied below) which indicated my
patterns must consist of 0 or 1. I assume I am doing something wrong.
Yes, not using 0 and 1?
See the help
Hi ,
I've been struggling with this problem. Initially I thought something like
a na.locf would help but I'm at a dead end. I have a data set like this:
ID Prod1 Prod2 Prod3 Prod4 Prod5
01A - B- C
02 - F - G
On 26.03.2013 14:49, Shane Carey wrote:
Hi,
Is it possible to use par() within par()? Something like:
par(mfcol=c(2,2),mar=c(4.5,4.5,2,2))
op <- par(las=1,xaxs="r",mai=c(1,0.75,1,1))
plot(hist(x),main="",xlim=c(0,100),xaxt="n",yaxt="n",xlab="",ylab="",border="white")
axis(1,at=c(0,20,40,60,80
Hello all,
I wrote a bash script in Mac OS that takes my .rnw file, knit it and then
makes a .pdf. To knit my file, I'm using the command
Rscript -e "library(knitr); knit('file.rnw', encoding='utf8')"
and everything works fine. However, I don't want the ## characters in my
final document. I test
Hi,
it was very kind of you to help me again.
Your code works, and the reason I was using the limits as that is that my
dataset is slightly different than the one I used for showing the problem here.
More specifically this is my dataset
Browse[1]> str(keep)
num [1:153899, 1:3415] -98.6 -95.8 -9
I did a multcompBoxplot like this:
> xzx <-multcompBoxplot(DESC_COMP ~ CLONETRAT,data = data.cerato,
+ sortFn = "median", decreasing=TRUE,
+ horizontal=FALSE, compFn = "TukeyHSD",
+ plotList=list(
+ boxp
Try this:
library(plyr)
library(ggplot2)
library(lubridate)
data<-read.csv("http://dl.dropbox.com/u/4236038/test_cumu.csv";)
data$Date <- as.Date(data$Date)
cumu <- ddply(data,.(year(Date)),transform, cumRain = cumsum(Rainfall))
ggplot(cumu, aes(x = yday(Date), y = cumRain, color = factor(year(Dat
HI,
I am not sure about the error. I modified the script and added 12 (hopefully
all the locations) and didn't had any problems.
dat1<- read.csv("rate.csv",sep=",")
res<- do.call(cbind,lapply(seq_len(nrow(dat1)),function(i)
do.call(rbind,lapply(split(rbind(dat1[i,],dat1[-i,]),1:nrow(rbind(dat1
On 3/26/2013 7:21 AM, Kerry wrote:
> Thank you Jason! actually, there have been two solutions and one is yours
>
> setting row.names=F works great, additionally what Ive been having problems
> with is the European version of Word 2010. Apparently it sets delimiters of
> ";" instead of "," as in
Please can someone explain to me how to use randomLCA in R for an analysis.
I tried using it and had this error (copied below) which indicated my
patterns must consist of 0 or 1. I assume I am doing something wrong.
Please help.
> library(lattice)
> library(boot)
Attaching package: boot
The
Thank you very much for taking the time to read my jumbled email.
I was usually pretty good with following directions but not lately very sorry!
I don't know why I never thought of exiting R and restarting. Thanks it's now
working.
Lin
> Subject: Re:
Hi, sorry I can't provide the reproducible code - the formula is currently
being worked on for a research paper so I can't really give out details in
that regard.
That being said, k is initialized to 1 at the beginning of the loop. n has
various values (whole numbers, 0 or greater, no upper limit).
You can use the par function instead.
require('vioplot')
data1<-rnorm(100)
data2<-rnorm(10)
data3<-rnorm(1000)
par(cex.lab=2, cex.axis=2)
vioplot(data1,data2,data3)
Best,
Nello
-Original Message-
From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org] On
Behalf Of Alaio
On 26-03-2013, at 16:25, Sahana Srinivasan
wrote:
> Hi,
> I'm using R to do a series of calculation and I have gotten several
> warnings that say "NaNS produced". Whatever I could read on line gives me
> an idea that this warning is produced when the number is use is a negative
> log or otherwi
Only positive values of n are allowed into the loop...
More importantly, is n ever larger than 52??? Because that results in nk2<0
(for k=1) and undefined gamma(nk2). Same goes for sn, if n>100.
Next time you may also want to write a reproducible example!
-Original Message-
From: r-help
Thanks. That helps.
Using the example data you sent, I came up with this loop. See if it does
the trick for you.
niter <- 2
nspp <- 11
ntrees <- 22
lnbm <- matrix(NA, niter, ntrees)
for(i in 1:niter) {
for(j in 1:ntrees) {
k <- j1data$its==i & j1data$spp==predictdata$spp[j]
lnbm[i, j] <- j1dat
Hi,
I'm using R to do a series of calculation and I have gotten several
warnings that say "NaNS produced". Whatever I could read on line gives me
an idea that this warning is produced when the number is use is a negative
log or otherwise mathematically problematic.
I'm getting this error while usin
Hi
I am using violin plots (type of boxplots) and I am trying to increase the
font size in the plots.
It looks like that the violin plots do not work as "normal" plots as the cex
parameters are ignored.
You can have a loot at the code below
require('vioplot')
data1<-rnorm(100)
data2<-rnorm
Hello,
If i were to embed R (in C), i could over ride
ptr_R_ShowMessage = Re_ShowMessage;
ptr_R_WriteConsoleEx =Re_WriteConsoleEx;
where Re_ShowMessage,Re_WriteConsoleEx are my own functions.
How would i do this in a package?
I would like the flexibility of having my function be called /every-t
I'm experiencing odd graphics device behavior running R 2.15.3 on Ubuntu.
Regardless of what I try like:
require(stats)
plot(cars)
lines(lowess(cars))
plot(sin, -pi, 2*pi)
for example, the graphics device fills the entire screen with the graphic
and a very large font. When I shrink the graphics d
Hello,
I just wanted to know if there's any package that implements
error-correcting output code algorithms for multiclass ensemble
problems.
thank you in advance.
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEAS
On 26/03/2013 13:02, Kevin E. Thorpe wrote:
I encountered the same problem. I emailed the maintainer last week but
have not yet received a response.
I don't see a BWidget package on CRAN either.
It is not an R package: it is a Tcl/Tk extension. The rpanel maintainer
has been asked to add it
Hi,
Forgot to add a line:
sumNew1<-rowSums(sapply(mycombos2,function(x) values1[x]))
names(sumNew1)<- row.names(mycombos2) ##
identical(sumNew1,sum1)
#[1] TRUE
Just checked with vectors of length 25
set.seed(25)
values1<-rnorm(25)
values2<-rnorm(25)
values3<-rnorm(25)
mycombos<-expand.grid
Hi,
Is it possible to use par() within par()? Something like:
par(mfcol=c(2,2),mar=c(4.5,4.5,2,2))
op <- par(las=1,xaxs="r",mai=c(1,0.75,1,1))
plot(hist(x),main="",xlim=c(0,100),xaxt="n",yaxt="n",xlab="",ylab="",border="white")
axis(1,at=c(0,20,40,60,80,100),line=-1,cex.axis=0.7,padj=-1.5)
par(ne
HI,
You could also try this:
set.seed(25)
values1<-rnorm(10)
values2<-rnorm(10)
values3<-rnorm(10)
mycombos<-expand.grid(1:10,1:10,1:10,1:10)
mycombos1<- mycombos
mycombos<-mycombos[!(mycombos$Var1 == mycombos$Var2),]
mycombos<-mycombos[!(mycombos$Var1 == mycombos$Var3),]
mycombos<-mycombos[!(m
I encountered the same problem. I emailed the maintainer last week but
have not yet received a response.
I don't see a BWidget package on CRAN either.
On 03/26/2013 04:31 AM, Juergen Rose wrote:
update.packages(checkBuilt = TRUE) fails with:
update.packages(checkBuilt = TRUE)
rpanel :
Ve
Hi,
library(plyr)
df1<-count(df)
rep(df1[,1],df1[,2]*100)
count(as.character(rep(df1[,1],df1[,2]*100)))
# x freq
#1 A 200
#2 B 200
#3 C 200
#4 D 400
#5 F 400
A.K.
- Original Message -
From: Katherine Gobin
To: r-help@r-project.org
Cc:
Sent: Tuesday, March 26, 2013 4:12 AM
Subjec
There are two ways to view weights. One is to treat them as case weights, i.e., a weight
of 3 means that there were actually three identical observations in the primary data,
which were collapsed to a single observation in the data frame to save space. This is the
assumption of survfit. (Most
Thank you Jason! actually, there have been two solutions and one is yours
setting row.names=F works great, additionally what Ive been having problems
with is the European version of Word 2010. Apparently it sets delimiters of
";" instead of "," as in the English/USA version. This is something
update.packages(checkBuilt = TRUE) fails with:
> update.packages(checkBuilt = TRUE)
rpanel :
Version 1.0-6 installed in /usr/lib64/R/library built under R 2.15.0
Version 1.1-1 available at http://mirrors.softliste.de/cran
Update (y/N/c)? y
trying URL
'http://mirrors.softliste.de/cran/src/contr
It would be helpful to see what your data frames look like ... perhaps you
could share the first few rows of each with us.
dput(head(j1data))
dput(head(predictdata))
Jean
On Mon, Mar 25, 2013 at 9:29 PM, Curtis Burkhalter <
curtisburkhal...@gmail.com> wrote:
> Hello,
>
> I'm working on a prob
Dear Sir,
Thanks a lot for your great help. I couldn't have figured it out.
Thanks again.
Regards
Katherine
--- On Tue, 26/3/13, D. Rizopoulos wrote:
From: D. Rizopoulos
Subject: Re: [R] Counting various elemnts in a vactor
To: "Katherine Gobin"
Cc: "r-help@r-project.org"
Date: Tuesday,
Hi Shane.
I don't know. I am not clear on what you are asking. I would think that it
would but can you supply some stripped-down code for people to have a look at?
See https://github.com/hadley/devtools/wiki/Reproducibility and/or
http://stackoverflow.com/questions/5963269/how-to-make-a
I hve not used Tinn-R in a while (I'm currently running Ubuntu) but I think
that you can just click in the left margin to select the line.
John Kane
Kingston ON Canada
> -Original Message-
> From: f...@dmu.dk
> Sent: Mon, 25 Mar 2013 11:33:28 +0100
> To: r-help@r-project.org
> Subject:
For 1) see reply just sent to R help...
"Re: [R] Use pcls in "mgcv" package to achieve constrained cubic spline"
(I'm assuming you mean to fix the value of the smooth at a particular
knot location - i.e. to impose a constraint like f(t_0) = b).
For 2) try 'model.matrix', or 'predict.gam' with a
Actually, you might as well use "gam" directly for this (has the
advantage that the smoothing parameter will be chosen correctly subject
to the constraint). Here is some code. Key idea is to set the basis and
penalty for the spline up first, apply the constraint, and then use gam
to fit it...
Yup, Ive tried all these things and I think Johns might be the best
approach,
thanks
On Tue, Mar 26, 2013 at 11:01 AM, PIKAL Petr wrote:
> Hi
>
> maybe
> axis(3, (x)^10)
>
> Regards
> Petr
>
> > -Original Message-
> > From: r-help-boun...@r-project.org [mailto:r-help-bounces@r-
> > proj
Thanks! ?View does indeed state "The object is then viewed
in a spreadsheet-like data viewer, a read-only version of
'data.entry', which is what I was looking for!
Ted.
On 26-Mar-2013 10:23:59 Blaser Nello wrote:
> Try ?View()
>
> -Original Message-
> From: r-help-boun...@r-project.org [m
Hi
maybe
axis(3, (x)^10)
Regards
Petr
> -Original Message-
> From: r-help-boun...@r-project.org [mailto:r-help-bounces@r-
> project.org] On Behalf Of Shane Carey
> Sent: Tuesday, March 26, 2013 11:19 AM
> To: r-help@r-project.org
> Subject: [R] How do I show real values on a log10 histo
On 13-03-26 6:19 AM, Shane Carey wrote:
Hi,
I have a histogram with values logged to the base 10
hist(log10(x),breaks=60)
How do I show the log values on the x-axis and a second x-axis showing the
real values?
I think it's hard to compute nice locations automatically, but if you
compute th
Something like this? It does an extra y-axis but the principle is the same for
an x-axis
# Create the data to be graphed
x<-1:10
y1<-x
y2<-x^2
# Set the par values
op <- par(las=1,xaxs="r",mai=c(1,0.75,1,1))
# Draw first plot
plot(x,y1,xlim=c(0,
Hi,
I have a histogram with values logged to the base 10
hist(log10(x),breaks=60)
How do I show the log values on the x-axis and a second x-axis showing the
real values?
Thanks
--
Shane
[[alternative HTML version deleted]]
__
R-help@r-proj
Try ?View()
-Original Message-
From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org] On
Behalf Of Ted Harding
Sent: Dienstag, 26. März 2013 11:09
To: r-help@r-project.org
Subject: [R] edit.data() read-only?
Greetings All.
The function edit.data() allows a convenient s
Sorry, I meant "data.entry()", not "edit.data()" (the latter due
to mental cross-wiring with "edit.data.frame()").
I think that Nello Blaser's suggestion of "View" may be what I
seek (when I can persuade it to find the font it seeks ... )!
With thanks, Barry.
Ted.
On 26-Mar-2013 10:20:59 Barry R
On Tue, Mar 26, 2013 at 10:09 AM, Ted Harding wrote:
> Greetings All.
>
> The function edit.data() allows a convenient spreadsheet-like
> view of a dataframe with too many rows/columns to fit on the
> screen (especially when there are many columns). Very useful
> when scanning through a dataset (r
Greetings All.
The function edit.data() allows a convenient spreadsheet-like
view of a dataframe with too many rows/columns to fit on the
screen (especially when there are many columns). Very useful
when scanning through a dataset (row & column are conveniently
identified by the labels at the side
Hi,
Thanks for the answer.
It looks like that the mutate what I was missing so long..
That's my current attempt
Data<-matrix(data=rnorm(900,80,20),nrow=30,ncol=30)
Lengths<- 15
library(reshape2)
library(ggplot2)
require('plyr')
tdm <- melt(Data)
tdm <- mutate(tdm, col = cut(value, seq(15, 90, by=
try this:
df <- c("F", "C", "F", "B", "D", "A", "D", "D", "A", "F", "D", "F", "B",
"C")
tab <- table(df)
tab
rep(names(tab), 100 * tab)
I hope it helps.
Best,
Dimitris
On 3/26/2013 9:12 AM, Katherine Gobin wrote:
> Dear R forum
>
> I have a vector say as given below
>
> df = c("F", "C",
Dear R forum
I have a vector say as given below
df = c("F", "C", "F", "B", "D", "A", "D", "D", "A", "F", "D", "F", "B", "C")
I need to find
(1) how many times each element occurs? e.g. in above vector F occurs 4 times,
C occurs 2 times etc.
(2) Depending on the number of occurrences, I ne
On Tue, 26-Mar-2013 at 05:05PM +0900, Pascal Oettli wrote:
|> Hi,
|>
|> You are right. The following should solve that problem:
|>
|> plot(0, 0, pch = "")
|> text(0, .5, expression(Temperature~(degree*C)))
That does it, and is perfectly readable. Now why didn't I think of that?
I knew there h
Hi,
You are right. The following should solve that problem:
plot(0, 0, pch = "")
text(0, .5, expression(Temperature~(degree*C)))
HTH,
Pascal
On 26/03/13 16:55, Patrick Connolly wrote:
On Tue, 26-Mar-2013 at 04:20PM +0900, Pascal Oettli wrote:
|> Hi,
|>
|> Is it what you are looking for?
|>
On Tue, 26-Mar-2013 at 04:20PM +0900, Pascal Oettli wrote:
|> Hi,
|>
|> Is it what you are looking for?
|>
|> plot(0, 0, pch = "")
|> text(0, .5, expression(Temperature~(degree ~ C)))
That produces an unwanted space between the degree symbol and the C.
The search continues.
Thanks
|> text(0,
Hi
> -Original Message-
> From: r-help-boun...@r-project.org [mailto:r-help-bounces@r-
> project.org] On Behalf Of Martin Labadz
> Sent: Tuesday, March 26, 2013 6:44 AM
> To: r-help@r-project.org
> Subject: [R] Plot cumulative sums of rainfall per year
>
> Hi @all,
>
> I am biting my nai
On Sat, 23-Mar-2013 at 10:10PM +0100, Rui Esteves wrote:
|> Hello,
|>
|> I have a trained Back Propagation Neural Network model in weka. I
|> would like to re-evaluate the NN using R with a given input. How
|> can I do this? I could not find an example of RWeca that applies to
|> NN
As the doc
Hi,
Is it what you are looking for?
plot(0, 0, pch = "")
text(0, .5, expression(Temperature~(degree ~ C)))
text(0, .4, substitute(paste(Temperature, B * degree, "C)"), list(B = "
(")))
Hope this help,
Pascal
On 26/03/13 16:12, Patrick Connolly wrote:
I'm interested in using a regular brac
Debugging nested loops is something we try to avoid in R, because there are
usually more efficient ways to accomplish things.
Does this do what you want?
hist(rle(diff(z)<0)$lengths)
---
Jeff Newmiller
Hi
slightly better, the error messages are starting from
if ((x[j] * x[j-1] < 0){
one parentheses more here
However R is not C and using built in functions is preferable to programming
your own.
Just as a guess isn't combination of sign and rle
I'm interested in using a regular bracket with the degree symbol as an
axis label but it's somewhat simpler to show what I mean in a text
statement.
> plot(0, 0, pch = "")
If I'm easy to please, this would suffice:
> text(0, .5, expression(Temperature * degree ~ C))
But I'm not that easily pleas
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