Re: [R] problem in installing reshape2 (urgent)

Suggestion: follow instructions appropriate for your OS (see CRAN) to install the current version of R. (2.15.2) --- Jeff NewmillerThe . . Go Live... DCN:Basics: ##.#. #

[R] problem in installing reshape2 (urgent)

Dear R users, In order to install reshape2 package, I gave the following command: install.packages("reshape2",dep=TRUE) However, it is not getting installed. The message that I am getting is: Warning: dependencies ‘plyr’, ‘stringr’, ‘testthat’ are not available trying URL ' http://ftp.ctex.org

Re: [R] Question: write an R script with help information available to the user

A related approach which, if memory serves, was originally in S eons ago, is to define a "doc" attribute of any function (or object, for that matter) that you wish to document that contains text for documentation and a doc() function of the form: doc <- function(obj) cat(attr(obj,"doc")) used a

Re: [R] Split xts data set into weeks

Your example of the problem is not reproducible [1]. This behavior could arise due to small discrepancies in the index values, or from specifying "frequency" instead of "f" as the second argument, our perhaps you have found a bug that only your data triggers. Any verification of what your proble

Re: [R] Question: write an R script with help information available to the user

On Sat, Feb 2, 2013 at 6:31 PM, Chee Chen wrote: > Dear All, > > I would like to ask a question on how to incorporate into an R script help > information for the user. I vaguely recall that I saw some instructions on an > R manual, but am not able to figure them out. Hereunder is the basic setti

Re: [R] Question: write an R script with help information available to the user

The normal expectations of an R user is that useful functions you want to share are in packages, which include help files. There is no way to both avoid the package development process and offer help to the user within R. Read the Writing R Extensions document for the most up-to-date information

[R] Question: write an R script with help information available to the user

Dear All, I would like to ask a question on how to incorporate into an R script help information for the user. I vaguely recall that I saw some instructions on an R manual, but am not able to figure them out. Hereunder is the basic setting: 1. I finished writing an R script, my_script.r, that

[R] Split xts data set into weeks

Hi I am trying to use split() to split a xts data set into weeks, but the result seems not right. original data is as following: > head(xec) Open HighLow Close mean 2011-02-28 112.34 113.34 111.96 112.87 112.6275 2011-03-01 112.89 113.71 112.75 112.80 113.0375 2011-03-02 1

Re: [R] Nested loop and output help

Dear R help moderator, My name is Thomas and I am new here. I am wondering if my post violated some of the rules of posting here. If so can you please let me know what I have done so that I can repost? I reread the posting guidelines and don't see anything that I violate. I have been reading a gre

[R] Fortan to R

Dear UseRs, How can i connect my FTN95 fortran compiler with R in window 7?Thanks in Advance, Elisa [[alternative HTML version deleted]] __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/list

Re: [R] Filter according to the latest data

On Fri, Feb 1, 2013 at 8:05 AM, nalluri pratap wrote: > library(sqldf) > > sqldf("select * > from k1 > group by No > having max(Date)") > HAVING is only used to select groups and only works by chance in this example but if the data were to change then it would likely not work. Try this instead.

Re: [R] vectorisation

Hello, Try the following. set.seed(4315) ml <- data.frame(matrix(sample(1:50,80, replace=TRUE),20,4)) mm <- apply(ml, 2, cumsum) s2 <- starts <- data.frame(matrix(0,600,4)) for (i in 1:4){ starts[,i][mm[,i]] <- 1 } s2[] <- lapply(seq_len(ncol(mm)), function(i) {s2[,i][mm[,i]] <- 1; s2[

Re: [R] vectorisation

Hi, Not sure this helps: ml <- data.frame(matrix(sample(1:50,80, replace=TRUE),20,4)) mm <- apply(ml, 2, cumsum) starts<- data.frame(matrix(0,600,4)) starts1<- data.frame(matrix(0,600,4)) for (i in 1:4){ starts1[,i][mm[,i]] <-1 } starts2<-as.data.frame(do.call(cbind,lapply(1:4,function(i) {star

Re: [R] Why replacement has length zero? And How can I fix it?

Hi: No offense, but this is code is inefficient on several levels. Firstly, a loop is unnecessary (see below); secondly, ifelse() is a vectorized function and you're attempting to apply it to each row of DataSet. Try this instead, given dput(DataSet) structure(list(Age = c(-0.552450789929175, -

Re: [R] create and save a simulated dataset

Hello, Once you formulate the problem properly, it's not hard to solve it in R. Bert's questions should be answered before continuing. I'll make two assumptions, not present in your post. All diameters are assumed independent and to follow the same uniform distribution. (iid scenario; the two

Re: [R] create and save a simulated dataset

Is this a homework problem? (We don't do homework here). What is missing from your query is any specification of what you mean by "random," which, by itself, is meaningless. It also might be the case that the trees within each stand are correlated in some way -- perhaps they should to be more simi

Re: [R] Why replacement has length zero? And How can I fix it?

Hi for the loop section runif needs curved brackets Try IAP <-NA for (i in 1:Sample.Size){ if (DataSet$SES[i]>0) { IAP[i] <- ifelse(runif(1)>0.75, 1, 0) # High SES, higher chance to be in Treatment # } else { IAP[i] <- if

Re: [R] Reading .rdata files

On 13-02-02 2:23 PM, Andrew DeCarlo wrote: Hello, I am a developer working on extracting information from .rdata files using java. I have been looking through the documentation a lot trying to figure out how to read these files, but am a bit stuck at the moment. I have generated two .RDATA file

[R] create and save a simulated dataset

Hello, I am trying to learn how to create a simulated dataset of a forest stand: I must simulate 10 stands, for each of the stands I have been creating a random number of trees. For each tree I should create a random diameter. The problem I have is that I cannot use a matrix because the length of

Re: [R] Change default order of colors & line types

You can change colors by manually creating your own palette. You can start with the Set1 color palette from RColorBrewer, then move the values. You then use this new palette in your plot: library(RColorBrewer) numGroups <-5 #here is where you define the size of your color palette customPalette

[R] VAR simulation help

Hi Everyone, I am a new comer to R circle. I am trying to simulate a VAR estimation. The problem is given above in the image. Assume that the errors are iid and normally distributed. Here the number of observations x1=x2=64. I've writ

Re: [R] Choice of text for intermediate level R programming course

I recommend The Art of R Programming: A Tour of Statistical Software Design, by Norman Matloff, No Starch Press. It is only 40 bucks so your students will appreciate that. As far as content goes, it covers just about everything, you can view a sample chapter, detailed ToC, and index at the websit

[R] Reading .rdata files

Hello, I am a developer working on extracting information from .rdata files using java. I have been looking through the documentation a lot trying to figure out how to read these files, but am a bit stuck at the moment. I have generated two .RDATA files from StatTransfer and have noticed that the

[R] vectorisation

Hi I'm trying to set up a simulation problem without resorting to (m)any loops. I want to set entries in a data frame of zeros ('starts' in the code below) to 1 at certain points and the points have been randomly generated and stored in a separate data.frame ('sl'), which has the same number of

Re: [R] Loading a list into the environment

Thanks all! list2env was exactly what I was looking for. As an FYI (and please correct me if I'm wrong), if you want to load a list into the current environment, use: myvariables <- list(a=1:10,b=20) loadenv <- list2env(myvariables ,envir=environment()) a b --j On Fri, Feb 1, 2013 at 5:49 PM,

Re: [R] use name (not values!) of a dataframe inside a funktion

Another R-ish way of modifying an object with a function is to use 'replacement functions' (there must be other names, I'm not sure what the standard is) that let you use syntax like someProperty(myData, ...) <- newProperty To do this define a function called `someProperty<-` whose last argume

Re: [R] Mixed Models: Contribution of random variable to final estimate

Luis Reino isa.utl.pt> writes: > > Dear all, > We want to test if the invasiveStatus is predicted by the amount > (quant) of animals arriving to a country of a certain species > (taxonid). We are using lmer to perform the model. In general lmer questions belong on r-sig-mixed-mod...@r-proje

Re: [R] Armadillo error in R extension

Dear Michael, during the last days of programming I came across RcppArmadillo (Rcpp) and for my kind of work this is indeed pretty interesting. So, I will take a closer look today what it is about and how it works. As a C++ programmer though, I am still interested why compilation of my package

[R] Mixed Models: Contribution of random variable to final estimate

Dear all, We want to test if the invasiveStatus is predicted by the amount (quant) of animals arriving to a country of a certain species (taxonid). We are using lmer to perform the model. The model is: lmer(invasiveStatus~I(log(quant+1))+I(log(inDegree+1))+(1|taxonid)+(1|country), family=binom

Re: [R] Question on "plotCI" function

On 02/02/2013 02:21 AM, li li wrote: Thanks so much for the reply, Ista. I used "plotrix" library. Here is my example: xx<- seq(0.05, 0.95, by=0.05) lower<- c(-2.896865, -2.728416, -2.642574, -2.587724, -2.548672, -2.518994, -2.495409, -2.476031, -2.459662, -2.445513, -2.433014, -2.421739, -2.4

Re: [R] order function

I agree with Duncan.   may be you need this   format(output[order(output[,3]),],scientific=T)   Pratap --- On Sat, 2/2/13, Duncan Murdoch wrote: From: Duncan Murdoch Subject: Re: [R] order function To: "Kripa R" Cc: r-help@r-project.org Date: Saturday, 2 February, 2013, 4:19 AM On 13-02-01