Dear Rui,
Thanks for your time.
I have a question though, when I run the 5 regression, whose outputs are
stored in lm.list[i], I only get the coefficients for the Intercept,
Price, Trend & Seasonality as below
> lm.list[1]
[[1]]
Call:
lm(formula = as.formula(fmla), data = tryout)
Hi
I have data for events in rows, with columns for person and date. Each
person may have more than one event;
tC <- textConnection("
Person date
bob 1/1/00
bob 1/2/00
bob 1/3/00
dave1/7/00
dave1/8/00
dave1/10/00
kevin 1/2/00
kevin 1/3/00
kevin 1/4/00
")
data <- rea
Shouldn't you be sending this to the maintainer?
--
David.
On Sep 26, 2012, at 9:03 PM, 王柏元 wrote:
> Hello~
>
> Did any one have used the package 'orcutt' ?
>
> I find that it can not work smoothly in a single variable regression. I use
> the example following, it function very well.
>
Hello~
Â
Did any one have used the package 'orcutt' ?
Â
I find that it can not work smoothly in a single variable regression. I use the
example following, it function very well.
Â
But when I regress "cons" on "price" (use the
"reg1<-lm(cons~price+income+temp)") , then  use "reg11<-cochr
Hi Guys, Both of your ways worked. Thanks a lot for your help! Best,Zhengyu
> Date: Wed, 26 Sep 2012 16:28:29 -0700
> From: smartpink...@yahoo.com
> Subject: Re: [R] replace string values with numbers
> To: zhyjiang2...@hotmail.com
> CC: r-help@r-project.org; dwinsem...@comcast.net
>
> Hi,
>
>
Hi everybody.
I use to work with monthly data, however this is my first time working with
weekly data.
I have 4 data bases with monthly data and 1 with weekly data, so I want to
convert my weekly to monthly data in order to have the same periodicity in
all of them.
I've read that package xts can
Hi,
You can also try these:
Gene<-read.table(text="
P1 P2 P3
CG CG GG
-- -- AC
-- AC CC
AC -- AC
",header=TRUE,sep="")
Gene<-sapply(Gene,as.character)
Gene<-data.frame(gsub("GG","3",Gene))
Gene
# P1 P2 P3
#1 CG CG 3
#2 -- -- AC
#3 -- AC CC
#4 AC -- AC
# str(Gene)
#'data.frame': 4 obs.
Please check if your independent variables or Xs are independent.
If they are not that can affect the sequential decomposition.
--
View this message in context:
http://r.789695.n4.nabble.com/Anova-problem-with-order-of-terms-in-model-tp791744p4644320.html
Sent from the R help mailing list arch
Actually the problem occurred in the command:
names = substr (filenames, 1, 7)
As the file's names are:
Dados1.raw, Dados2.raw, ..., Dados11.raw, Dados12.raw, ..., Data 35.raw
the program doesn't work. A quick way to make it work is rename the files to:
Dados01.raw, Dados02.raw, ..., Dados11.r
Hello,
In the help page for ?hclust you will see the return values. It has an
element order, "a vector giving the permutation of the original
observations suitable for plotting".
From the first example on that page:
hc <- hclust(dist(USArrests), "ave")
plot(hc)
ix <- hc$order
rownames(USArre
Check the return values for hclust using ?hclust (particularly the
value order):
> set.seed(42)
> x <- matrix(rnorm(100), nrow=25)
> outp <- hclust(dist(x))
> plot(outp)
> outp$order
[1] 9 6 16 1 7 24 25 3 14 11 12 20 18 19 23 4 10 5 17 13 22 2
15 8 21
You could use this to reorder the d
Hi,
I didn't notice problems with this.
> Will your data be read in correctly if you do away with the colClasses
> argument to read.delim (or read.table)?
>
> Jean
>
>
>
> "Silvano Cesar da Costa" wrote on 09/26/2012 09:11:33 AM:
>>
>> Hi,
>>
>> I have 35 data files for reading. I would like ge
On Wed, Sep 26, 2012 at 3:11 PM, RCar wrote:
> All,
> Relatively new R user so this is probably an easy question to answer.
> I am able to generate a cluster for my dataset using hclust() then ploting
> the data with plot().
> This results in an image with a dendrogram with my sample names along t
On Sep 26, 2012, at 6:13 PM, Rui Barradas wrote:
> Hello, again.
>
> I forgot, but the subject line also says "same axes", not just same axes
> scale.
> If you want all densities on the same graph, use ?matplot (matrix plot).
If you use matplot , presumably just plotting the y-values, you wil
My vote for R-Studio. Very elegant design and great functionality. However if
coming from languages like Java and others then eclipse is better. R-Studio
have dedicated section for Mac user which you will find useful.
Best Regards,
Bhupendrasinh Thakre
Sent from my iPhone
On Sep 26, 2012, at
Hello, again.
I forgot, but the subject line also says "same axes", not just same axes
scale.
If you want all densities on the same graph, use ?matplot (matrix plot).
Rui Barradas
Em 27-09-2012 02:08, Rui Barradas escreveu:
Hello,
Something like this?
sag <- matrix(rnorm(1e3 * 9), ncol = 9)
On Sep 26, 2012, at 6:06 PM, David Winsemius wrote:
>
> On Sep 26, 2012, at 5:48 PM, Steven Wolf wrote:
>
>> Hi everyone,
>>
>> I've recently moved from using a windows machine to a Mac (some might call
>> it an upgrade, others not…I'll let you be the judge). Once I started using
>> Notepad
Hello,
Something like this?
sag <- matrix(rnorm(1e3 * 9), ncol = 9)
d.list <- apply(sag, 2, density)
xrange <- range(sapply(d.list, function(d) range(d$x)))
ymax <- max(sapply(d.list, function(d) max(d$y)))
op <- par(mfrow=c(3,3))
for(i in 1:9)
plot(d.list[[i]], xlim = xrange, ylim = c(0,
On Sep 26, 2012, at 5:48 PM, Steven Wolf wrote:
> Hi everyone,
>
> I've recently moved from using a windows machine to a Mac (some might call it
> an upgrade, others not…I'll let you be the judge). Once I started using
> Notepad ++ on my windows machine, I really began to like it. Unfortunat
Hello,
I have two Random Forest (RF) related questions.
1. How do I view the classifications for the detail data of my training
data (aka trainset) that I used to build the model? I know there is an object
called predicted which I believe is a vector. To view the detail for my testset
I
On Sep 26, 2012, at 5:48 PM, Steven Wolf wrote:
> Hi everyone,
>
> I've recently moved from using a windows machine to a Mac (some might call it
> an upgrade, others not…I'll let you be the judge). Once I started using
> Notepad ++ on my windows machine, I really began to like it. Unfortunat
Have you looked at aquamacs? (emacs for the mac).
its at aquamacs.org.
albyn
On 2012-09-26 17:48, Steven Wolf wrote:
Hi everyone,
I've recently moved from using a windows machine to a Mac (some might
call it an upgrade, others not…I'll let you be the judge). Once I
started using Notepad ++ on
Good Evening-
I have a set of nine scenarios I want to plot to see how the distribution
is changing, if one tail is getting larger in certain scenario, currently I
am using this code
colnames<-dimnames(sag_pdfs)[[2]]
par(mfrow=c(3,3))
for(i in 1:9) {
d<-density(sag[,i])
plot(d,type="n", mai
Duncan Murdoch wrote on 09/26/2012 05:35:00 PM:
> > ...
> > I'd like to have the code source files from the 'local' git repository
> > without modification, where 'local' could mean c:\yada\ for one
person,
> > m:\my documents\wetlands\ for another, and
l:\foo\bar\sharedRemote\wet\ to
> > anothe
Hi everyone,
I've recently moved from using a windows machine to a Mac (some might call it
an upgrade, others not…I'll let you be the judge). Once I started using
Notepad ++ on my windows machine, I really began to like it. Unfortunately,
I'm not sure what the free text editor options are for
On 12-09-26 8:25 PM, Curt Seeliger wrote:
Folks,
A small group of us are working together to develop a set of R functions
to support data management and analysis using Eclipse/StatET in a Windows
environment. We are using Git/EGit for version control. We work within
our own repository and occas
Folks,
A small group of us are working together to develop a set of R functions
to support data management and analysis using Eclipse/StatET in a Windows
environment. We are using Git/EGit for version control. We work within
our own repository and occasionally push to a common remote location.
You could use filter(..., filter=rep(1,5)) to get running sums of length 5
to get your answer. The following calls filter once to get the sum of
the negative values in each window and once to get the number of negative
values in each window, then divides to get the means.
f <- function(x, n=5) {
Hello,
Try the following.
sapply(seq_len(nrow(dat) - 4), function(i){
w <- window(dat$value, start = i, end = i + 4)
mean(w[w < 0])})
Hope this helps,
Rui Barradas
Em 26-09-2012 16:38, Eko andryanto Prakasa escreveu:
haiii
i want to know, is there any script in R to measure loopin
If your previously posted code worked with files all having the same
number of columns, and if your data is read in correctly without the
colClasses argument, then I think the following code should work.
for(i in names){
filepath = file.path("~/Silvano/Dados", paste(i, ".raw", sep=""))
On 26 Sep 2012, at 16:11 , Silvano Cesar da Costa wrote:
> Hi,
>
> I have 35 data files for reading. I would like get a program for
> performing reading of 35 files at once.
> All are of the type: Dados1.raw, Dados2.raw and so on.
>
> If the files have the same number of columns, I can read wit
On Sep 26, 2012, at 2:27 PM, David Winsemius wrote:
>
> On Sep 26, 2012, at 12:52 PM, JiangZhengyu wrote:
>>
>> Hi everyone, I have a data frame Gene with SNPs eg. P1 P2 P3
>> CG CG GG
>> -- -- AC
>> -- AC CC
>> AC -- AC I tried to replace all the GG with a value 3.
>> Gene[Gene=="GG
On Sep 26, 2012, at 12:52 PM, JiangZhengyu wrote:
>
>
>
>
> Hi everyone, I have a data frame Gene with SNPs eg. P1 P2 P3
> CG CG GG
> -- -- AC
> -- AC CC
> AC -- AC I tried to replace all the GG with a value 3.
> Gene[Gene=="GG"]<-3 It always give me: Warning in `[<-.factor`(`*tmp
On Sep 26, 2012, at 11:23 AM, Rui Barradas wrote:
> Hello,
>
> If I understand it correctly, something like this will get you what you want.
>
>
> d <- Sys.Date() + 1:4
> d2 <- sample(d, 2)
> dat <- data.frame(id = 1:6, date = c(d, d2), value = rnorm(6))
>
> aggregate(dat, by = list(dat$date)
All,
Relatively new R user so this is probably an easy question to answer.
I am able to generate a cluster for my dataset using hclust() then ploting
the data with plot().
This results in an image with a dendrogram with my sample names along the
bottom. Great!
However, I now need a way to get th
?duplicated
Clint BowmanINTERNET: cl...@ecy.wa.gov
Air Quality Modeler INTERNET: cl...@math.utah.edu
Department of Ecology VOICE: (360) 407-6815
PO Box 47600FAX:(360) 407-7534
Olympia, WA 98504-7600
Dear Paul,
Many thanks, that solved it.
Cheers,
Marius
Paul Murrell writes:
> Hi
>
> On 25/09/2012 6:10 p.m., Marius Hofert wrote:
>> Dear Paul,
>>
>> Thanks. Redrawing the points solves it for the minimal example, but
>> what happens if you have plot(.., type="b") like below?
>
> You can use
Hi everyone, I have a data frame Gene with SNPs eg. P1 P2 P3
CG CG GG
-- -- AC
-- AC CC
AC -- AC I tried to replace all the GG with a value 3.Gene[Gene=="GG"]<-3
It always give me: Warning in `[<-.factor`(`*tmp*`, thisvar, value = 3) :
invalid factor level, NAs generated Does a
Hello,
If I understand it correctly, something like this will get you what you
want.
d <- Sys.Date() + 1:4
d2 <- sample(d, 2)
dat <- data.frame(id = 1:6, date = c(d, d2), value = rnorm(6))
aggregate(dat, by = list(dat$date), FUN = tail, 1)
Hope this helps,
Rui Barradas
Em 26-09-2012 16:19,
Hi,
I encountered a very strange error with R (2.14.1).
I tried to build an R package and eventually worked (passing all the checks
etc.). Then, I tried this command "R CMD INSTALL --binary pkg", which
supposedly "installs and produce a binary source archive (*.zip) for use on
Windows only."
Sorry, but in my previous post I've confused the columns. It's by
REQ.NR, not by date
REQ.NR <- 1:4
REQ.NR <- c(REQ.NR, sample(REQ.NR, 2))
dat <- data.frame(date = Sys.Date() + 1:6, REQ.NR = REQ.NR, value =
rnorm(6))
aggregate(dat, by = list(dat$REQ.NR), FUN = tail, 1)
Rui Barradas
Em 26-09-
Hi all,
I have seen that R can be switched on to a Broker called IB.
There is another one similar to IB that permits to make a "code" and send
orders to broker to buy or sell stocks?
Can be done trough R, writte in excel and trough API sell/buy to the broker?
Can someone send me an example (eas
Will your data be read in correctly if you do away with the colClasses
argument to read.delim (or read.table)?
Jean
"Silvano Cesar da Costa" wrote on 09/26/2012 09:11:33 AM:
>
> Hi,
>
> I have 35 data files for reading. I would like get a program for
> performing reading of 35 files at once
This might be quicker.
Para.5C.sorted <- Para.5C[order(Para.5C[, 1]), ]
Para.5C.final <- Para.5C.sorted[!duplicated(Para.5C.sorted$REQ.NR), ]
If your data are already sorted by date, then you can skip the first step
and just run
Para.5C.final <- Para.5C[!duplicated(Para.5C$REQ.NR), ]
Jean
ww
Adding on to what Sarah has said, your function appears to limit the
functions that can be passed to it, but it does not. The character strings
"mean" and "median" will fail, but passing the function name directly will
work:
> Scale <- function(x, method=mean,...) {
>scl <- method
>scl(x,
On Sep 26, 2012, at 8:50 AM, John Kane wrote:
> Strange, I have never used it but presumably you are using the package
> ‘survey’? The manual suggests summary(xx) should work.
>
> What results or error messages do you get?
She didn't return a model object as fit1. She return only the results
Hello,
You define a 2nd version of Scale with the dots argument but do not use it.
Scale2 <- function(x, method=c("mean", "median"),...) {
scl <- match.fun(method)
scl(x, ...) # Here!
}
Scale2(ex, method=median, na.rm=TRUE) # both return
Scale2(ex, method="median", na.rm=TRUE) # the
On 26/09/2012 2:39 PM, Alexander Shenkin wrote:
Hello All,
I need a script to perform different actions depending on the file from
which it was source()'d. Thus, my script needs a way to figure out from
whence it was sourced.
There seems to be some relevant information in sys.calls() (see belo
On Sep 26, 2012, at 8:28 AM, David L Carlson wrote:
>> subtest <- subset(test, Name. %in% c("PKB123", "PKB22", "PKB23", "PKB32",
> "CTV19", "CTV20", "PKB11", "PKB11"))
>> subtest
>Name. Score performance Environment.
> 10 CTV19 2 0.52740797 0.53639048
> 11 CTV20 3 0.05
Hello All,
I need a script to perform different actions depending on the file from
which it was source()'d. Thus, my script needs a way to figure out from
whence it was sourced.
There seems to be some relevant information in sys.calls() (see below).
However, I need to get at the name of the fil
On 26/09/2012 11:03 AM, Li, Jianying (NIH/NIEHS) [C] wrote:
Hi,
I encountered a very strange error with R (2.14.1).
I tried to build an R package and eventually worked (passing all the checks etc.). Then, I tried
this command "R CMD INSTALL --binary pkg", which supposedly "installs and produce
Hi,
You have some basic confusion here, and a problem likely caused by an
object named scl that exists in your global environment.
On Wed, Sep 26, 2012 at 11:56 AM, K. Brand wrote:
> Esteemed R UseRs,
>
> Regarding specifying arguments in functions and calling functions
> within functions:
>
> #
I would like to fit regression models of the form
y ~ ns(x, df=splineDF)
where splineDF is passed as an argument to a wrapper function.
This works fine if the regression function is lm(). But with lme(),
I get two different errors, depending on how I handle splineDF
inside the wrapper function
I'm trying to teach myself about Bayesian Networks and am working with the
following data and the bnlearn package.
I understand the conceptual aspects of BNs, but I'm not sure how to specify
the response variables in R when constructing
a dag plot. I've cecked ?hc and done numerous google searches
Hi,
I am looking to run a script which calls other functions from other scripts.
Such as in script 1 I may have function f1 which then calls functions f2,
f3, f4 which are found in script 3 and then f4 also calls function f6 which
can be found in script 3 etc.
What I am looking to do is to create
Thank you PIKAL Petr,
This is used when you have a big data base of a national sample. So, this
factor is a variable that uses the sample in order to obtain information about
all the people of the country. Similar of getting a real approach about what's
going on in the total population. I don'
Dear R experts,
I have an R script that creates multiple scripts and submits these
simultaneously to a computer cluster, and after all of the multiple
scripts have completed and the output has been written in the
respective folders, I would like to automatically launch another R
script that works
Hi,
I encountered a very strange error with R (2.14.1).
I tried to build an R package and eventually worked (passing all the checks
etc.). Then, I tried this command "R CMD INSTALL --binary pkg", which
supposedly "installs and produce a binary source archive (*.zip) for use on
Windows only."
haiii
i want to know, is there any script in R to measure looping averageif (like in
the excel) ...
for example:
i have a vector
rowvalue
10
22
3-3
4-2
51
6-2
i want to measure the average of the vector for negative value with window
esti
Hi,
I have 35 data files for reading. I would like get a program for
performing reading of 35 files at once.
All are of the type: Dados1.raw, Dados2.raw and so on.
If the files have the same number of columns, I can read with the
following commands:
rm(list=ls())
filenames = list.files(path="~/S
HI,
Try this:
vec1<-"GALAXY ACE S 5830"
vec2<-"S 5830 GALAXY ACE"
vec3<-"R GALAXY 5812 ACE"
vec11<-paste(sort(unlist(strsplit(vec2," "))),collapse="_")
vec22<-paste(sort(unlist(strsplit(vec2," "))),collapse="_")
vec11
#[1] "5830_ACE_GALAXY_S"
vec22
#[1] "5830_ACE_GALAXY_S"
identical(vec11,
I have several thousand rows of shipment data imported into R as a data
frame, with two columns of particular interest, col 1 is the entry date, and
col 2 is the tracking number (colname is REQ.NR). Tracking numbers should be
unique but on occassion aren't because they get entered more than once.
Esteemed R UseRs,
Regarding specifying arguments in functions and calling functions
within functions:
## beginning ##
## some data
ex <- rnorm(10)
ex[5] <- NA
## example function
Scale <- function(x, method=c("mean", "median")) {
scl <- method
scl(x)
}
## both return NA
Scale(ex, method=m
You need to use the match function if you want to specify result sort order or
duplication.
test[ match(c( "PKB123", "PKB22", "PKB23","PKB32", "CTV19", "CTV20", "PKB11",
"PKB11" ),test$Name.), ]
---
Jeff Newmiller
I think I know considerably less than you do but have a look as the sp package.
I think you are referring to and object type SpatialPolygonsDataFrame" from
the package
sp or which that package will produce.
Good luck. Now to install rgdal.
John Kane
Kingston ON Canada
> -Original Mes
Shamelessly stealling Richard Heiberger's data set I'd suggest another way
using ggplot2 which you would need to install
library(ggplot2)
dataN <- data.frame(GE_distance=rnorm(260),
Diet_B=factor(rep(1:13, each=20)))
p <- ggplot(dataN , aes(Diet_B, GE_distance, colour = Di
Strange, I have never used it but presumably you are using the package
‘survey’? The manual suggests summary(xx) should work.
What results or error messages do you get?
John Kane
Kingston ON Canada
> -Original Message-
> From: cacamende...@gmail.com
> Sent: Wed, 26 Sep 2012 12:39:46
This does not work at all...
On Wed, Sep 26, 2012 at 12:04 PM, John Kane wrote:
> summary(fit1) perhaps/
>
> John Kane
> Kingston ON Canada
>
>
>> -Original Message-
>> From: cacamende...@gmail.com
>> Sent: Wed, 26 Sep 2012 11:39:30 -0300
>> To: r-help@r-project.org
>> Subject: [R] Retrie
Clumsy but this should do it.
aa$set <- rep("a", length(aa$position))
bb$set <- rep("b", length(bb$position))
(mydata <- rbind(aa,bb))
p <- ggplot( mydata , aes( position, count, colour = set )) + geom_line()
p
John Kane
Kingston ON Canada
> -Original Message-
> From: jim
> subtest <- subset(test, Name. %in% c("PKB123", "PKB22", "PKB23", "PKB32",
"CTV19", "CTV20", "PKB11", "PKB11"))
> subtest
Name. Score performance Environment.
10 CTV19 2 0.52740797 0.53639048
11 CTV20 3 0.05298615 0.04856818
12 PKB11 4 0.90037809 0.79427806
1
summary(fit1) perhaps/
John Kane
Kingston ON Canada
> -Original Message-
> From: cacamende...@gmail.com
> Sent: Wed, 26 Sep 2012 11:39:30 -0300
> To: r-help@r-project.org
> Subject: [R] Retrieve regression summary results after rq
>
> Hi all,
>
> I am using quantile regression with svy
Does your dataset have any missing data? (without a reproducible
example we can only guess).
If it does then you may be fitting the same model to different subsets
of the data between the 2 methods.
On Tue, Sep 25, 2012 at 9:03 AM, Maximilian Lklweryc
wrote:
> Hi,
> I want to make model selectio
Some like this help?
mydata$modnew <- cut(mydata$moderator, 7)
ggplot(mydata, aes(x=predictor, y=outcome, color=modnew)) +
geom_point() + stat_smooth(method=lm, se=TRUE, fullrange=T)
John Kane
Kingston ON Canada
> -Original Message-
> From: dadr...@gmail.com
> Sent: Wed, 26 Sep 2012
Hi all,
I am using quantile regression with svy design. I want to retrieve
summary regression statistics (std error, p-value), since I don't have
any in my output:
Commands:
clus1_d<- svydesign(id=~cd002_co, weights=~wtper, strata=~str, data=data)
bclus1<-as.svrepdesign(clus1_d,type="bootstrap",
Hi,
On Sep 26, 2012, at 8:07 AM, Magnus Eriksson wrote:
> I'm trying to upload a file using RCURL:s ftpUpload() to a ftp-server using
> the following command:
>
>> ftpUpload("'VERY.ODD.FILE.NAME(+1)'",to="ftp://x.x.x.x/",";'
>> VERY.ODD.FILE.NAME(+1)'",userpwd="USER:PASSWORD")
> OK
> 0
>
> T
I have forwarded your message to the R-help list.
You should also send your replies to the R-help list and not just to the
person(s) who replied.
Berend
On 26-09-2012, at 15:44, Kizito Omala wrote:
> Hello Berend,
>
> I got the code from google, pasted in the script editor run it and all is
I'm trying to treat a continuous variable as discrete for plotting
multiple regression lines in a scatterplot as a function of the level
on the moderating variable. In the example below, there is only one
regression line plotted to the whole data. I would like a separate
regression line for each
Mike,
You could use bootstrapping. See for example the function boot() in
pacakge boot.
library(boot)
?boot
Jean
Michael Eisenring wrote on 09/25/2012 04:54:29
AM:
>
> Dear R-help members.
> Maybe this is not the right platform to ask this, but I'm looking
> desperately for a test which
On 26-09-2012, at 13:24, Kizito Omala wrote:
> Dear all,
>
> I have just downloaded a package 'prob' and also loaded it using
> library(prob). Whereas function 'tosscoin' works very well the other
> functions like 'gbinom' for graphing density functions does not work.
> I get the message:
>
>
Thank you!
Am 26.09.2012 13:31, schrieb Jim Lemon [via R]:
> On 09/26/2012 08:53 PM, Tagmarie wrote:
>
> > Hello,
> > I tried for about three hours now to solve this problem but I can't
> figure
> > it out. I am sure someone knows how do it. At least I hope so.
> >
> > I have a data frame somewha
HI,
Try this:
DF$Station[DF$number%in%c(1,7,11,16)]<-"V1"
DF$Station[DF$number%in%c(4,14,20)]<-"V2"
DF$Station[DF$number%in%c(3,17,19)]<-"V3"
DF
# number data Station
#1 1 1 V1
#2 4 2 V2
#3 7 3 V1
#4 3 4 V3
#5 11 5 V1
#6
I'm trying to upload a file using RCURL:s ftpUpload() to a ftp-server using the
following command:
> ftpUpload("'VERY.ODD.FILE.NAME(+1)'",to="ftp://x.x.x.x/",";'
> VERY.ODD.FILE.NAME(+1)'",userpwd="USER:PASSWORD")
OK
0
The file I'm trying to upload is a very simple text-file but with a bit we
HI,
Just to add to Jim's solution with data.table()
myframe<- data.frame (ID=c("Ernie", "Ernie", "Bert", "Bert"),
Timestamp=c("24.09.2012 09:00", "24.09.2012 09:00", "24.09.2012 10:00",
"25.09.2012 10:00"), Hunger=c("1","5","2","2"), Temp=c("25","30","27","28")
)
library(data.table)
myframe1<
Hello,
'if' is not vectorized, it only uses the first value of the multiple
condition. 'ifelse' is vectorized and in your case use nested ifelses.
DF <- data.frame(number=c(1,4,7,3,11,16,14,17,20,19),data=c(1:10))
v1 <- c(1,7,11,16)
v2 <- c(4,14,20)
v3 <- c(3,17,19)
DF$Station <- ifelse(DF$n
Dear all,
I have just downloaded a package 'prob' and also loaded it using
library(prob). Whereas function 'tosscoin' works very well the other
functions like 'gbinom' for graphing density functions does not work.
I get the message:
> gbinom(20,0.3)
Error: could not find function "gbinom"
How d
Dear all,
is there a specific package and reference book for plotting Jointly
distributed random variables?
Kindly help.
Kizito.
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Yes this is it!
Thank you for your help Berend!
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Dear colleagues:
I am working with binary mixed models using lme4 package and everything works
fine until I try to spatialize the fitted models using grids predictors. I have
used the "predict" function from RASTER package and the RSAGA functionalities,
but always I have the same error: "Error
On 09/26/2012 05:00 AM, r-help-requ...@r-project.org wrote:
I generated predicted risk of death for each subject in the study by
means of Cox proportional hazards model at 8 year of follow-up, a time
point at which follow-up was more than 90% complete. It is possible to
extrapolate to 10-year t
Here is one of the places that you need a 'factor' to create the
ordering you want; notice the statement that I added:
> equity_data = data.frame(security_id = c("Air", "Air", "Air", "Air"
+ , "Air", "Air", "Air", "Air", "Air", "Air", "Air", "Air", "AB"
+ , "AB", "AB", "AB", "AB",
Here is another technique to use, especially if you have a long list
of replacement values:
> DF <- data.frame(number=c(1,4,7,3,11,16,14,17,20,19),data=c(1:10))
>
> # create a list of replacement values; if you have a lot and
> # you can create them automagically, then it is easier
> replace <- l
Hello,
Why do you have Hunger and Temp recorded as characters? Between double
quotes?
myframe <- data.frame (ID=c("Ernie", "Ernie", "Bert", "Bert"),
Timestamp=c("24.09.2012 09:00", "24.09.2012 09:00", "24.09.2012 10:00",
"25.09.2012 10:00"), Hunger=c("1","5","2","2"), Temp=c("25","30","27","2
On 26-09-2012, at 09:59, Loukia Spineli wrote:
> Dear all,
>
> I am trying to construct 25x31 different matrices of 2x2 dimension. Here
> is the problem:
>
> we have the following matrix
> matrix(c(54+s0,
> 43+s1, 56-s0, 67-s1), nrow=2, nc
Hello,
Try the following.
#cnames <- names(tryout) # in your code, use this one
cnames <- c("Volume", "Price1", "Price2", "Price3", "Price4", "Price5",
"Trend", "Seasonaliy")
price <- cnames[grep("Price", cnames)]
resp <- cnames[1]
regr <- cnames[7:8]
#lm.list <- vector("list", 5)
for(i in 1
On 09/26/2012 08:53 PM, Tagmarie wrote:
Hello,
I tried for about three hours now to solve this problem but I can't figure
it out. I am sure someone knows how do it. At least I hope so.
I have a data frame somewhat like this:
myframe<- data.frame (ID=c("Ernie", "Ernie", "Bert", "Bert"),
Timestam
On Wed, Sep 26, 2012 at 3:36 PM, maxbre wrote:
> sorry for my slow reply, this is what I worked out so far…
>
> my reproducible example and the code
>
> test<-structure(list(site = structure(c(1L, 1L, 1L, 1L, 1L, 1L, 2L,
> 2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 3L,
> 3L, 3L, 3
On 26-09-2012, at 12:49, jeff6868 wrote:
> Hi everyone,
>
> I have a small problem in my R-code.
>
> Imagine this DF for example:
>
> DF <- data.frame(number=c(1,4,7,3,11,16,14,17,20,19),data=c(1:10))
>
> I would like to add a new column "Station" in this DF. This new column must
> be automa
Dear R helpers
I have following two data.frames viz. equity_data and param.
equity_data = data.frame(security_id = c("Air", "Air", "Air", "Air", "Air",
"Air", "Air", "Air", "Air", "Air", "Air", "Air", "AB", "AB", "AB", "AB", "AB",
"AB", "AB", "AB", "AB", "AB", "AB", "AB", "AD", "AD", "AD", "AD
Hello,
I tried for about three hours now to solve this problem but I can't figure
it out. I am sure someone knows how do it. At least I hope so.
I have a data frame somewhat like this:
myframe <- data.frame (ID=c("Ernie", "Ernie", "Bert", "Bert"),
Timestamp=c("24.09.2012 09:00", "24.09.2012 09:
Thanks to all of you.
The three advices helped me a lot - solved my problem and thank you Sarah
for the hint with rseek.org. Didn't know that one.
Have a great day,
Tagmarie
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