Thanks Arun and Rui for help. Will try with your suggestion and get back if
the problem persist.
On Sep 19, 2012 5:41 PM, "Rui Barradas" wrote:
> Hello,
>
> Your code is reproducible and completely explains the issue, thanks.
> First I had the impression of a well organized question.
> Then I've
Try this;
help(anova)
I have used this in R-2.14.1
It has worked fine for me. Hope it works for you as well.
Best,
Heramb
On Thu, Sep 20, 2012 at 1:40 AM, Rui Barradas wrote:
> Hello,
>
> I had a problem seeing the help pages with R 2.14.(0 or 1? I don't
> remember) on Windows 7.
> Then I re
Try this,
library(RCurl)
library(XML)
site<-"
http://www.wateroffice.ec.gc.ca/graph/graph_e.html?mode=text&stn=05ND012&prm1=3&syr=2012&smo=09&sday=15&eyr=2012&emo=09&eday=18
"
URL<-getURL(site)
Text=htmlParse(URL,asText=T)
This will give you all the web dat in an HTML-Text format.
You can use
Hi All,
I have used windows R.
We can also write like this:
A <- read.csv("C:/Users/Anthi/Desktop/R/A.csv",header=TRUE)
On Wed, Sep 19, 2012 at 8:09 PM, Marc Schwartz wrote:
>
> On Sep 19, 2012, at 9:26 AM, Rui Barradas wrote:
>
> >
> > Em 19-09-2012 15:01, Sarah Goslee escreveu:
> >> On W
It does that automatically. Just assign the names you want to the data.frame
before you compute the correlation matrix:
> x <- data.frame(matrix(rnorm(100), ncol=5))
> colnames(x) <- c("A", "B", "C", "D", "E")
> y <- cor(x)
> y
A B C D E
A 1.000
Hello,
?colnames
Regards,
Pascal
Le 20/09/2012 11:48, Kristi Glover a écrit :
Hi R User,
I calculated a correlation matrix and I was trying to give a same name for rows
and columns (heading) in the correlation matrix. But, I was not able to do so.
Would you mind let me know how I can assign
Hi R User,
I calculated a correlation matrix and I was trying to give a same name for rows
and columns (heading) in the correlation matrix. But, I was not able to do so.
Would you mind let me know how I can assign the same name for the heading of
row and columns in the matrix?
I appreciate fo
Thank you Thomas,
So you think a t-test is more adequate to use in this case ?
Rad
On Sep 19, 2012, at 8:43 PM, Thomas Lumley wrote:
> On Thu, Sep 20, 2012 at 5:46 AM, Mohamed Radhouane Aniba
> wrote:
>> Hello All,
>>
>> I am writing to ask your opinion on how to interpret this case. I hav
On Thu, Sep 20, 2012 at 5:46 AM, Mohamed Radhouane Aniba
wrote:
> Hello All,
>
> I am writing to ask your opinion on how to interpret this case. I have two
> vectors "a" and "b" that I am trying to compare.
>
> The wilcoxon test is giving me a pvalue of 5.139217e-303 of a over b with the
> alter
Both solutions work great. Thank you for your help.
--
View this message in context:
http://r.789695.n4.nabble.com/Merging-two-or-more-frequency-tables-tp4643663p4643692.html
Sent from the R help mailing list archive at Nabble.com.
__
R-help@r-projec
HI,
Inspired from Rui's function:
Slightly modified:
fun1<-function(x,...){
z<-paste(unlist(list(x,...)),collapse=" ")
tsum<-table(strsplit(tolower(z),"\\W"))
tsum}
fun1(x,y)
# age belief darkness epoch foolishness incredulity
# 2 1 1 2
A few general comments about stepwiseAIC and a suggestion of how to select
models
a) Apart form the problem, that stepwise selection is not a garanty to get the
best model, you need to have a lot of data to avoid overfitting if your model
includes 7 parameter plus interactions (> 10 observatio
Hello,
Inline.
Em 19-09-2012 19:56, frauke escreveu:
Hi,
thank you for taking the time and reading my question. My question is
twofold:
1. I have several matrices with variables and one matrix with water levels.
I want to predict the water level with the data in the other matrices.
Basically,
Hi,
Try this:
a <- data.frame(table( cut( Sys.time() + seq(0,82800,3600), "60 mins")
b <- data.frame(a$Var1)
str(b)
#'data.frame': 24 obs. of 1 variable:
# $ a.Var1: Factor w/ 24 levels "2012-09-19 18:03:00",..: 1 2 3 4 5 6 7 8 9 1
b1<-within(b,{a.Var1<-as.POSIXct(a.Var1,format="%Y-%m-%d %H:%
Hello,
Try the following.
fun <- function(x, ...){
z <- Reduce(paste, list(x, ...))
tsum <- table(strsplit(tolower(z), "\\W"))
tsum
}
x <- "It was the age of wisdom it was the age of foolishness it was the
epoch of belief"
y <- "it was the epoch of incredulity it was the season of
HI,
Try this:
dt0<-data.frame(t0)
dt1<-data.frame(t1)
res1<-merge(dt0,dt1,by="Var1")
res2<-aggregate(Freq.x+Freq.y~Var1,data=res1,sum)
colnames(res2)[2]<-"Freq"
res3<-rbind( dt0[!dt0$Var1%in%res2$Var1,],dt1[!dt1$Var1%in%res2$Var1,] ,res2)
row.names(res3)<-1:nrow(res3)
xtabs(Freq~Var1,data=res3)
Dear R users
lqmm version 1.02 is now on CRAN. lqmm provides commands for estimation of
linear quantile regression models with random effects. Commands for independent
and count data are also available. A few bugs have been fixed since lqmm 1.0.
Updates of this package are (usually) made availa
Thank you David - you put me into right direction.
Back to normal, problem sorted.
I've missed a single quote in 'annot' data when I imported it from file
using read.table function with the default 'quote' argument. quote="\""
did the trick.
Many thanks
-Igor
On Wed, 2012-09-19 at 14:55 -0700,
Hello,
Your code is reproducible and completely explains the issue, thanks.
First I had the impression of a well organized question.
Then I've read point 4.
4. The sequence 1:1 starts and ends at 1. You don't need b[1:1, 1:1],
b[1, 1] will do.
Then you assign a different value to 'b'. This ti
On Sep 19, 2012, at 8:55 AM, Tinus Sonnekus wrote:
> Hi All,
>
> I am trying to reproduce this using R instead.
>
> [image: Full-size image (38 K)]
>
>
> I tried using the following code
>
> *SChla <- read.csv("SM_Chla_data.csv")*
>
> *Atlantis <- SChla[16:66,]*
> *head(Atlantis)*
> *
> *
>
On Sep 19, 2012, at 12:20 PM, Igor Chernukhin wrote:
> Hi David -
> Thank you for your reply. You are probably right. The last 'normal' line
> doesn't have a double quote closed. There is the complete line below:
>
> -8<
> "4657","1599
Hi List Members,
This is a very stupid problem but I am not able to know what the solution
can be.
I am trying to run a query like below
*Program Flow :*
1. a <- data.frame(table( cut( Sys.time() + seq(0,82800,3600), "60 mins")
)) # It generates the 60 minute intervals. Thanks David
2. b <-
Dear R-users,
I would like to announce the release of the new package JMbayes
available from CRAN (http://CRAN.R-project.org/package=JMbayes). This
package fits shared parameter models for the joint modeling of normal
longitudinal responses and event times under a Bayesian approach using
JAGS,
Hello,
I had a problem seeing the help pages with R 2.14.(0 or 1? I don't
remember) on Windows 7.
Then I realized that after a command like print, Rgui would first
display an error message saying that the temp directory used by help
didn't exist. The solution I've found was to manually create
Hello,
Try the following.
x <- rnorm(100)
hist(x, xaxt = "n")
axis(1, at = pretty(x), pos = 0)
Hope this helps,
Rui Barradas
Em 19-09-2012 18:51, firespot escreveu:
Hi,
So I plot a histogram using the built-in hist function:
hist(rnorm(100), ...).
Now the y-axis starts at its lower end at
I am new to R and am looking to merge two or more frequency tables into one.
I have searched around but have been unable to find exactly what I need.
I have two frequency tables obtained from two sample texts
t0<-table(strsplit(tolower("It was the age of wisdom it was the age of
foolishness it wa
Hi,
thank you for taking the time and reading my question. My question is
twofold:
1. I have several matrices with variables and one matrix with water levels.
I want to predict the water level with the data in the other matrices.
Basically,
* mod<-lm(matrix1 ~ matrix2+matrix3)*
( What looks like
Hello,
I remember this dataset from not a long time ago. Please use dput() to
post your data and do not use formatting to post code.
As for the question, though your example is not reproducible (it doesn't
run) see
http://gallery.r-enthusiasts.com/graph/contour_plot_%3Cbr%3EMaunga_Whau_Volc
Hi Jim -
Thank you for your reply.
-8<
> str(annot)
'data.frame': 6895 obs. of 4 variables:
$ id : int 231803 231804 231805 231810 231811 231816 231818
177697 223131 231823 ...
$ kogdefline : Factor w/ 1898 levels "17
Hi David -
Thank you for your reply. You are probably right. The last 'normal' line
doesn't have a double quote closed. There is the complete line below:
-8<
"4657","159998",133.10761487064,185.450704462326,80.7645252789532,0.43550400907
Hi,
So I plot a histogram using the built-in hist function:
hist(rnorm(100), ...).
Now the y-axis starts at its lower end at 0 (very sensible, of course)
and that's where the baseline for the rectangles of the histogram is
drawn, but the x-axis itself is offset a bit to the lower. I.e. there
Dear R-help community,
I am unable to access help files when using the typical
"?function.of.interest" command.
For example, if I type "?anova", Internet Explorer opens, but I am never
connected to the usual page describing the nuances of the anova function.
This is a new problem (just started o
Hello All,
I am writing to ask your opinion on how to interpret this case. I have two
vectors "a" and "b" that I am trying to compare.
The wilcoxon test is giving me a pvalue of 5.139217e-303 of a over b with the
alternative "greater". Now if I make a summary on each of them I have the
followi
I am trying to pull a subset form a large group of FASTA sequences. I need
to pull them based on the annot and write.fasta them. I have my subset
annot titles in a .csv. What is the way to go about this? I tried pulling
the sequences from a .csv but then MEGA 5 was not happy when i tried to put
the
HI,
May be "brew" package helps you.
You can also check this link
(http://learnr.wordpress.com/2009/04/09/ggplot2-sales-dashboard/).
A.K.
- Original Message -
From: XINLI LI
To: r-help
Cc:
Sent: Wednesday, September 19, 2012 11:48 AM
Subject: [R] R package for dashboard
What pack
I am not sure if it is possible to provide a data set sufficient to fit this
model and reproduce the error. However, I noticed that the warnings no
longer show up when the number of predictors for b0 and b1 in b0~ and
b1 ~ is small (3 to 5). Could this be an effect too many
"subcoefficien
"if I knew how to reproduce the problem, I would have known what was going on."
This is a worthless excuse. You are the one with the example in front of you.
I grant that paring it down to email size can take some time, but every second
of that time is worthwhile, and at least half the battle i
Excellent point! Thanks.
-- Bert
On Wed, Sep 19, 2012 at 12:00 PM, Berend Hasselman wrote:
>
> On 19-09-2012, at 20:02, Bert Gunter wrote:
>
>> Well, following up on this observation, which can be put under the
>> heading of "Sometimes vectorization can be much slower than explicit
>> loops" , I
On 19-09-2012, at 20:02, Bert Gunter wrote:
> Well, following up on this observation, which can be put under the
> heading of "Sometimes vectorization can be much slower than explicit
> loops" , I offer the following:
>
> firsti <-function(x,k)
> {
> i <- 1
> while(x[i]<=k){i <- i+1}
> i
> }
> * jim holtman [2012-09-19 13:58:08 -0400]:
>
> At least provide a reproducible example by creating the problem with a
> subset of 'z' and 'mycountry'
if I knew how to reproduce the problem, I would have known what was going on.
> Could something like this be happening?
precisely, thanks!
>>
> * William Dunlap [2012-09-19 18:20:50 +]:
>
> Why don't you try that and tell us if it works?
Because in my wildest dreams it did not occur to me that this could be
valid code in any programming language.
It appears to be valid R, which seems to be out-perling Perl at every turn.
However, i
I don't.
You are getting to be a regular around here, so you should know better by now.
Please stop posting non-reproducible sample code.
---
Jeff NewmillerThe . . Go Live...
DCN:
Why don't you try that and tell us if it works?
Bill Dunlap
Spotfire, TIBCO Software
wdunlap tibco.com
> -Original Message-
> From: Sam Steingold [mailto:sam.steing...@gmail.com] On Behalf Of Sam
> Steingold
> Sent: Wednesday, September 19, 2012 10:48 AM
> To: r-help@r-project.org; Will
R doesn't know whether the missing (NA) value is 6 or not, so by
default it returns it so the user can make up her own mind.
If you're using square brackets for subsetting, you need to explicitly
handle NA cases. If using subset(), the default behavior is to remove
them.
?"["
explains this.
Sara
On 19/09/2012 1:50 PM, Sam Steingold wrote:
I see this:
--8<---cut here---start->8---
> length(which(is.na(z$language)))
[1] 0
> locals <- z[z$country == mycountry,]
> length(which(is.na(locals$language)))
[1] 229
--8<---cut here---end--
Thanks, Sarah, your answer is, indeed, revealing:
--8<---cut here---start->8---
> z <- data.frame(a=c(1,2,3),b=c(5,6,NA))
> z
a b
1 1 5
2 2 6
3 3 NA
> z[z$b==6,]
a b
2 2 6
NA NA NA
--8<---cut here---end--->8---
why
Well, following up on this observation, which can be put under the
heading of "Sometimes vectorization can be much slower than explicit
loops" , I offer the following:
firsti <-function(x,k)
{
i <- 1
while(x[i]<=k){i <- i+1}
i
}
> system.time(for(i in 1:100)which(x>.99)[1])
user syste
At least provide a reproducible example by creating the problem with a
subset of 'z' and 'mycountry'
Could something like this be happening?
> x <- data.frame(country = 1:5, language = 1:5)
> mycountry <- NA
> z <- x[x$country == mycountry,]
> z
country language
NANA NA
NA.1
Well, you have no reproducible example, but I suspect either of these
will fix it:
locals <- z[z$country == mycountry & !is.na(z$country),]
locals <- subset(z, country == mycountry)
Sarah
On Wed, Sep 19, 2012 at 1:50 PM, Sam Steingold wrote:
> I see this:
> --8<---cut here-
I see this:
--8<---cut here---start->8---
> length(which(is.na(z$language)))
[1] 0
> locals <- z[z$country == mycountry,]
> length(which(is.na(locals$language)))
[1] 229
--8<---cut here---end--->8---
where are those locals with
cool, thanks!
Still, I wonder if there is a way to pass all args as is from a function
downward (like in a lisp macro); something like
sorted.table <- function (...) { tab <- table(...); ... }
> * William Dunlap [2012-09-19 16:26:08 +]:
>
> Here is one way:
>
>> sorted.table <- function(x, n
Dear R users,
I'm plotting 5 loess smooth lines in one paragraph. Since the publisher
does not print colorful pictures, I differentiate them by using different
line types. I'm wondering if there are other options to make the graph more
readable. It is really difficult for readers to tell the diffe
It would also be helpful if you could provide the output of 'str' for
all the objects that you are using.
e.g., str(statdata)str(extra)
Also in creating your data.frame, use "stringsAsFactors = FALSE":
extra = data.frame(kogdefline=rep(NA,n)
, kogClass = rep(NA,n)
, kogGroup = rep(
On Sep 19, 2012, at 9:12 AM, Igor wrote:
> Good afternoon all -
>
> While making a steady progress in learning R after Matlab I encountered
> a problem which seems to require some extra help to move over.
> Basically I want to merge a data from biological statistical dataset
> with annotation da
Usually the source of such errors is the data you provide to the function.
Since you have not followed the posting guide and provided a reproducible
example, we are under a significant handicap in troubleshooting your problem.
--
Thanks again,
I run the script with the postForm(site, disclaimer_action="I Agree") and
it does not seem to do anything,
the webpage is still the disclaimer page thus I am getting the error below
Error in function (classes, fdef, mtable) :
unable to find an inherited method for function "readHT
One of the package which I know of is rgooglevis. However there should be some
more in the same line.
Copying it to the list so someone else also chime in for answer.
Best Regards,
Bhupendrasinh Thakre
Sent from my iPhone
On Sep 19, 2012, at 11:52 AM, XINLI LI wrote:
> Thank you very much
I am using the gnls procedure in nlme package to fit a nonlinear model as:
nl.fit<-gnls(Y ~ b0*exp(b1/X),
data = data1,
params=list(
b0~p1+I(p1^2)+p2+I(p2^2)+p3+I(p3^2)+p5+p6
b1~p8+p2+I(p2^2)+p3+p9+p10+p11),
star
Good afternoon all -
While making a steady progress in learning R after Matlab I encountered
a problem which seems to require some extra help to move over.
Basically I want to merge a data from biological statistical dataset
with annotation data extracted from another dataset using an 'id'
crossre
Hello-
I'm receiving an error when I try to export a dataframe into Access
2010 containing a date field using sqlSave. The error I'm receiving
is:
[RODBC] Failed exec in Update
22018 39 [Microsoft][ODBC Microsoft Access Driver]Invalid character
value for cast specification
I can export all other
I nominate Jim's answer below for the fortunes package.
On Wed, Sep 19, 2012 at 3:50 AM, Jim Lemon wrote:
> Sri krishna Devarayalu Balanagu wrote:
>>
>>
>> Suppose I want the output as "Trial and a sheet" without quotes
>> x=c("a", "b", "c")
>> print("Trial and x[1] sheet")
>>
>> Getting "Tr
Here is one way:
> sorted.table <- function(x, name = if (is.list(x))names(x) else
> deparse(substitute(x))[1]) {
+tab <- table(x)
+names(dimnames(tab)) <- name
+tab <- tab[tab > 0]
+sort(tab, decreasing=TRUE)
+ }
> digits <- factor(trunc(100*log2(1:20)%%.1), levels=0:9)
> sorted.
Function
--8<---cut here---start->8---
sorted.table <- function (vec) {
tab <- table(vec)
tab <- tab[tab > 0]
sort(tab, decreasing=TRUE)
}
--8<---cut here---end--->8---
does what I want but it prints "vec" instead of the
Depends on your requirement . Who is going to use it. Do you want something
like running in browser or something like excel or somewhat different like Tcl
tk.
Best Regards,
Bhupendrasinh Thakre
Sent from my iPhone
On Sep 19, 2012, at 10:48 AM, XINLI LI wrote:
> What package can be used to pr
Le mercredi 19 septembre 2012 à 15:23 +, William Dunlap a écrit :
> The original method is faster than which.max for longish numeric vectors
> (in R-2.15.1), but you should check time and memory usage on your
> own machine:
>
> > x <- runif(18e6)
> > system.time(for(i in 1:100)which(x>0.99)[1]
Hi All,
I am trying to reproduce this using R instead.
[image: Full-size image (38 K)]
I tried using the following code
*SChla <- read.csv("SM_Chla_data.csv")*
*Atlantis <- SChla[16:66,]*
*head(Atlantis)*
*
*
Seamount Station Depth Pico Nano Micro Total_Chdbar Latitude
Longitud
You don't need to use the getHTMLFormDescription() and createFunction().
Instead, you can use the postForm() call. However, getHTMLFormDescription(),
etc. is more general. But you need the very latest version of the package
to deal with degenerate forms that have no inputs (other than button cli
I find myself doing
--8<---cut here---start->8---
tab <- table(...)
tab <- tab[tab > 0]
tab <- sort(tab,decreasing=TRUE)
--8<---cut here---end--->8---
all the time.
I am wondering if the "drop 0" (and maybe even sort?) can be e
What package can be used to produce dashboard in R?
Thanks and Regards,
Xin
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide comme
The original method is faster than which.max for longish numeric vectors
(in R-2.15.1), but you should check time and memory usage on your
own machine:
> x <- runif(18e6)
> system.time(for(i in 1:100)which(x>0.99)[1])
user system elapsed
11.641.05 12.70
> system.time(for(i in 1:100)w
Hi,
Thanks Michael, but i think this is even slower.
x <-sample(2000)
which(x < 5)[1]
which.max(x < 5)
system.time(for(i in 1:100) which.max(x < 5))
User System verstrichen
60.84 13.70 86.33
system.time(for(i in 1:100) which(x < 5)[1])
User Syste
?which.max
---
Jeff NewmillerThe . . Go Live...
DCN:Basics: ##.#. ##.#. Live Go...
Live: OO#.. Dead: OO#.. Playing
Research Engi
On Wed, Sep 19, 2012 at 3:20 PM, Mike Spam wrote:
> Hi,
>
> I was looking for a function like "which()" but only returns the first
> argument.
> Compare:
>
> x <- c(1,2,3,4,5,6)
> y <- 4
> which(x>y)
>
> returns:
> 5,6
>
> which(x>y)[1]
> returns:
> 5
>
> which(x>y)[1] is exactly what i need. I d
Thank you for your help Duncan,
I have been trying what you suggested however I am getting an error when
trying to create the function fun<- createFunction(forms[[1]])
it says Error in isHidden I hasDefault :
operations are possible only for numeric, logical or complex types
On Wed, Sep 19, 2012
Hi,
I was looking for a function like "which()" but only returns the first argument.
Compare:
x <- c(1,2,3,4,5,6)
y <- 4
which(x>y)
returns:
5,6
which(x>y)[1]
returns:
5
which(x>y)[1] is exactly what i need. I did use this but the dataset
is too big (~18 mio. Points).
That's why i need a more
On Sep 19, 2012, at 6:26 AM, PIKAL Petr wrote:
> Hi
>
> because you need to evaluate it.
>
> print(paste("Trial and" ,eval(x[1]), "sheet"))
The eval is superfluous, since paste() already evaluates its unquoted arguments.
> print(paste("Trial and", x[1], "sheet"))
[1] "Trial and a sheet"
--
On Sep 19, 2012, at 9:26 AM, Rui Barradas wrote:
>
> Em 19-09-2012 15:01, Sarah Goslee escreveu:
>> On Wed, Sep 19, 2012 at 9:53 AM, Frans Marcelissen
>> wrote:
>>> Hi,
>>> Should'nt it be A <- read.csv("C:Users\\Anthi\\Desktop\\R\\A.csv",
>>> header=TRUE)
>>> (c:\\ becomes c:\ In general
Em 19-09-2012 15:01, Sarah Goslee escreveu:
On Wed, Sep 19, 2012 at 9:53 AM, Frans Marcelissen
wrote:
Hi,
Should'nt it be A <- read.csv("C:Users\\Anthi\\Desktop\\R\\A.csv",
header=TRUE)
(c:\\ becomes c:\ In general I think it is better to use / and //)
Frans
No idea; I was copying the ori
On Wed, Sep 19, 2012 at 9:53 AM, Frans Marcelissen
wrote:
> Hi,
> Should'nt it be A <- read.csv("C:Users\\Anthi\\Desktop\\R\\A.csv",
> header=TRUE)
> (c:\\ becomes c:\ In general I think it is better to use / and //)
> Frans
No idea; I was copying the original poster's version. In this case,
On 19/09/2012 6:30 AM, Kyran Graham wrote:
Hi,
Sorry for posting a question that has been asked before but I couldn't
quite find the right answer in previous help topics.
I am trying to set my library path to a user-specified library
("C:/Users/K/Documents/Work/RLib"). I have used
.libPaths("C:/U
Hi,
Should'nt it be A <- read.csv("C:Users\\Anthi\\Desktop\\R\\A.csv",
header=TRUE)
(c:\\ becomes c:\ In general I think it is better to use / and //)
Frans
-Oorspronkelijk bericht-
Van: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org]
Namens Sarah Goslee
Verzonden: w
Hello,
Try ?read.csv.
dat <- read.csv("C:\\Users\\Anthi\\Desktop\\R\\A.csv")
Note that unlike what happens with load() you'll need an explicit
assignment.
Hope this helps,
Rui Barradas
Em 19-09-2012 09:54, Anthi Oikonomou escreveu:
> Hi,
> I am trying to import csv file in R console
> I have
Hi,
load() is for R's binary data files. You need to use read.csv(), as
you tried, but probably with the complete path.
A <- read.csv("C:\\Users\\Anthi\\Desktop\\R\\A.csv", header=TRUE)
Sarah
On Wed, Sep 19, 2012 at 4:54 AM, Anthi Oikonomou wrote:
> Hi,
> I am trying to import csv file in R co
Hi,
Sorry for posting a question that has been asked before but I couldn't
quite find the right answer in previous help topics.
I am trying to set my library path to a user-specified library
("C:/Users/K/Documents/Work/RLib"). I have used
.libPaths("C:/Users/K/Documents/Work/RLib") but when I check
Hi,
I am trying to import csv file in R console
I have saved my data in a file on the desktop named R and here is my
problematic script
> load("C:\\Users\\Anthi\\Desktop\\R\\A.csv")
Error: bad restore file magic number (file may be corrupted) -- no data
loaded
In addition: Warning message:
file A
hi,
I wanted to convert a graph into image and display it in browser,
i got the image in the given folder and everything is coming out well but
the image is not being displayed,
even the error or warning is not being given so i dont know what exactly i
have made mistake in the code,
please can any
Sri krishna Devarayalu Balanagu wrote:
Suppose I want the output as "Trial and a sheet" without quotes
x=c("a", "b", "c")
print("Trial and x[1] sheet")
Getting "Trial and x[1] sheet"
Can anyone help?
And for your sins in not reading the documentation:
cat(paste(rev(c("sheet",x[1],"and
> -Original Message-
> From: ridav...@gmail.com
> Sent: Wed, 19 Sep 2012 00:42:50 +0200
> To: ruipbarra...@sapo.pt
> Subject: Re: [R] [newbie] aggregating table() results and simplifying
> code with loop
>
> Hi dear R-helpers,
>
> I really appreciate your "coding the answers" to (my) qu
Hi
because you need to evaluate it.
print(paste("Trial and" ,eval(x[1]), "sheet"))
Regards
Petr
> -Original Message-
> From: r-help-boun...@r-project.org [mailto:r-help-bounces@r-
> project.org] On Behalf Of Sri krishna Devarayalu Balanagu
> Sent: Tuesday, September 18, 2012 11:41 AM
>
Hi
I did not see any answer yet but can you explain what you mean by factor
expansion? Something like expand.grid?
Petr
> -Original Message-
> From: r-help-boun...@r-project.org [mailto:r-help-bounces@r-
> project.org] On Behalf Of Jose Bustos Melo
> Sent: Wednesday, September 12, 2012
Dear all,
I encounter some discrepancies when comparing the deviance of a weighted and
unweigthed model with the AIC values.
A general example (from 'nls'):
DNase1 <- subset(DNase, Run == 1)
fm1DNase1 <- nls(density ~ SSlogis(log(conc), Asym, xmid, scal), DNase1)
This is the unweight
On Wednesday, September 19, 2012, Jul_biologyGrad wrote:
> Thanks everyone for the help! I pulled together a bunch of your suggestions
> to get the result that I needed. I'm posting my final code below. Probably
> not the most efficient way of doing things but gets the job done in a way
> that a n
Dear list,
I am trying to impute the two level data, I have a question about a warning.
Could you give me some suggestions please? Thank you very much.
Here is my code and output of mice package:
> ini <- mice(try, maxit=0)
> pred=ini$pred
> pred
FAC1_1 FAC2_1 FAC3_1 FAC4_1 FAC5_1
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