Dear fellow R users.
I have released version 1.2.8 of the psych package. This replaces 1.2.4 from
the April release.
The more important changes
o Modified score.irt so that subjects who miss all items or pass all
items are given an estimate based upon the (product) of the
On 12-09-10 2:03 AM, Diviya Smith wrote:
Hi there
I have an Rscript and I am looking for a way to install a package
non-interactively. In Rscript {Utils}, I saw an example which does
something like this, however this does not seem to work for my particular
example. I am trying to install the fol
Hi
On 07/09/12 09:35, Benjamin Tyner wrote:
Update: seems one way to skin this cat is to add
gp = gpar(fontfamily="mono")
to the viewport() call itself. If anyone has any suggestions for a
robust way to extract this piece information from the key grob itself
(it's nested several levels deep
Hi,
I have two matrices. (same size, same number of rows,
same names for the rows - one has data in sorted
order, another one master data in unsorted order. I need to
combine both).
Rows names of Matrix A
P, Q, R, S, T, U, V ...(some order) - each row has 4 values
Row names of Matr
On 10/09/12 01:52, Fred wrote:
Thanks Arun,
I can manage something with that, just need then to delete the first raw
with photoshop !
Huh? WTF?
If you're doing that then you're doing something completely wrong
and not understanding how R works.
You didn't include the context of your question
Hi,
I am trying to find a simple way to numerically solve a system of two
equations equal to zero with two unknowns (x_loc and y_loc). Here is a mock
data set and below it, the equations I need to solve.
theta<-c(180,135,90)/(2*pi)
x<-c(0,0,15)
y<-c(20,0,0)
0 =
-sum((y_loc-y)*(sin(theta)*(x_loc-
Hi there
I have an Rscript and I am looking for a way to install a package
non-interactively. In Rscript {Utils}, I saw an example which does
something like this, however this does not seem to work for my particular
example. I am trying to install the following package in an Rscript
(without switc
On Sep 9, 2012, at 7:04 AM, STADLER Frederic wrote:
> Hey, I am still working on my heat map (for those who are read my previous
> post about row.names)∑
> Now, I would like to save my heat map.2 in .png or .tiff in order being able
> to work on the picture in photoshop, but it doesn't work.
>
Just to add, I did not know that the speed of data access is so much
different in matrix and dataframes. This is one for the future.
Thanks again Jim :)
-Shivam
On Mon, Sep 10, 2012 at 3:29 AM, Shivam wrote:
> Thanks a lot Jim, it works a treat. Just had to change the date format
> in the mCALL
Thanks a lot Jim, it works a treat. Just had to change the date format
in the mCALL as well. But you saved me 80 hours of fretting and
frustration. Really thankful for it.
Regards,
Shivam
On Mon, Sep 10, 2012 at 1:33 AM, jim holtman wrote:
> How about an improvement to 16 seconds. The first thi
Hello,
Em 09-09-2012 18:36, Fred escreveu:
hey Sarah,
thanks for your help !!
Of Course I put the second quote also (I forgot to put it on the last post).
Sorry, I don't get the my.plot.code...
What Sarah meant is that you must put your.plot.code between the
instructions that open and close
How about an improvement to 16 seconds. The first thing to do is to
convert you data to a matrix because accessing data in a dataframe is
very expensive. If you run Rprof on your code you will see that all
the time is spent in retrieving the information. Converting to a
matrix and using matrix a
Dear All,
I need to sum a column from another dataframe based on the row values
of one dataframe. I am stuck in a loop trying to accomplish it and at
current speed it will take more than 80 hours to complete. Needless to
say I am looking for a more elegant/quicker solution. Really need some
help h
Try adding the parameter xpd=TRUE to your legend() statement. Without
reproducible code it is pretty hard to be sure what the problem is.
--
David L Carlson
Associate Professor of Anthropology
Texas A&M University
College Station, TX 77843-4352
>
Mr Stadler,
On 9 September 2012 10:36, Fred wrote:
> But I don't have any files called "heatmap.2.png " on my computer.
> I really don't understand why I don't get anything !
>
What does getwd() print out as a path? Check there for the your file. -- H
--
Sent from my mobile device
Envoyait de
Hey Jeff, sorry for the "it just doesn't work", but it's really what it
does...
I can't find any file called heatmap.2.png on my computer after creating my
heatmap.2 (that I can see on Quartz) and typing:
> png("heatmap.2.png")
Maybe I should add, that I am working on mac with MAC OS X (v.10.8.1).
hey Sarah,
thanks for your help !!
Of Course I put the second quote also (I forgot to put it on the last post).
Sorry, I don't get the my.plot.code... # I'm new in R and use it only to
draw heatmaps right now.
Well, I did forget the dev.off(). # but I got
null device (1) # when quartz is turned o
If I run the whole code and click on the addition menu and then click Add,
the error comes. But not when I just call add(). So I guess the problem is
not with the rpanel package. Also tried panel["vars"] instead of panel$vars.
no luck. Same error when I call the add function from the rpanel GUI.
Hi All,
I have been trying to get to plot my PCA legend outside of the PCA plot,
but success still alludes me.
Can you guys please advise how I can achieve this. I used locater() to
obtain coordinates for below the Comp.1 axis. Using these coordinates the
legend disappears.
Below is the code for
https://github.com/TomRoche/GEIA_to_netCDF/commit/62ad6325d339c61ac4e7de5e7d4d26fa21ed918c
>> # - Rscript ./netCDF.stats.to.stdout.r netcdf.fp="./GEIA_N2O_oceanic.nc"
>> var.name="emi_n2o"
>> # fails
>> # + Rscript ./netCDF.stats.to.stdout.r 'netcdf.fp="./GEIA_N2O_oceanic.nc"'
>> 'var.name="emi
Hello,
This solves my problem in a horribly inelegant way that works:
df <- data.frame(n=newInput$n, iter=newInput$iter, Error=newInput$Error,
Duality_Gap=newInput$Duality, Runtime=newInput$Acc)
df_last <- aggregate(x=df$iter, by=list(df$n), FUN=max)
names(df_last)[names(df_last)=="Group.1"] <-
> I would like to change the
> subset clause to be iter %% 500 _or_ the record is the last per n
If your data.frame df is sorted by n you can define the function
isLastInRun <- function(x) c(x[-1] != x[-length(x)], TRUE)
and use it as
subset(df, iter %% 500 == 0 | isLastInRun(n))
Bill Dun
Hi Jeff,
Thanks for your help, but this doesn't work, there are two problems. First and
most important I need to keep the last _per category_ where my category is n
and not the last globally. Second, there seems to be an issue with the subset
variation that ends up not filtering anything ... bu
dfthin <- df[ c(which(iter %% 500 == 0),nrow(df) ]
or
dfthin <- subset(df, (iter %% 500 == 0) | (seq.int(nrow(df)==nrow(df)))
N.B. You should avoid using the name "df" for your variables, because it is the
name of a built-in function that you are hiding by doing so. Others may be
confused, an
"It just doesn't work" could mean anything... and for those of us for whom it
does work, that leaves a lot of possible differences between your case and
ours. This is your cue to read the Posting Guide.
Some issues I have encountered:
If you are using Windows, and you have opened a graphics fil
Normally the workflow is:
png("heatmap.png") # don't forget the second quote, as you did below
my.plot.code # whatever you need to draw the heatmap
dev.off() # people often forget this step - did you?
You'll probably want to adjust the size and resolution settings for
png() to get the desired hig
Hey, I am still working on my heat map (for those who are read my previous post
about row.names)
Now, I would like to save my heat map.2 in .png or .tiff in order being able to
work on the picture in photoshop, but it doesn't work.
I'am using (as I have found on some forum)
> png("heatmap.2.png)
Thanks Arun,
I can manage something with that, just need then to delete the first raw
with photoshop !
Thanks
Fred
--
View this message in context:
http://r.789695.n4.nabble.com/Problem-with-duplicates-in-row-names-tp4642518p4642604.html
Sent from the R help mailing list archive at Nabble.co
Hello,
I bumped into the following funny use-case. I have too much data for a given
plot. I have the following data frame df:
> str(df)
'data.frame': 5015 obs. of 5 variables:
$ n : Factor w/ 5 levels "1000","2000",..: 1 1 1 1 1 1 1 1 1 1 ...
$ iter : int 10 20 30 40 50 60
On 09/09/2012 12:14 AM, Zhang Qintao wrote:
Hi, All,
I am trying to use R to make the following type of boxplot while I couldn't
find a way to do it.
My dataset looks like X1 Y1 X2 Y2 SPLIT. The split highlights my
experiment details and both x and y are continuous numerical values. I
need
I am working on the r panel package. Now if i have a function that uses a
radiogroup button, and if i attempt to run the function from inside the
rpanel menu, i get this error:
Error in panel$intname : $ operator is invalid for atomic vectors
However if i run the function per se i.e. not from in
My stupdity I made a late edit for clarity and forgot to run it to be sure I
had changed everything.
It should read:
tabx <- ddply(meltx, .(Seamount, variable), summarize, mean = mean(value),
sd = sd(value))
My appologies.
John Kane
Kingston ON Canada
> -Original Message-
> From:
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