Hello everyone,
My dataframe (Soil Type) looks something like this
Granitic Hills 16-20 PZ
Loamy Upland 16-20 PZ
Sandy Loam Upland 12-16 PZ / Sandy Loam, Deep 12-16 PZ
Loamy Upland 12-16 PZ / Sandy Loam Upland 12-16 PZ
Loamy Upland 16-20 PZ
I want to separate them at "/", but when there is jus
Hi all,
I'm working on a seemingly trivial problem that I can't figure out how
to implement in R. I'd be most grateful for any help here.
I want to do the following: first, randomly assign each of n units to
one of g groups of size n/g. Then, randomly re-assign each of the n
units to a different
johannes rara writes:
> Thanks, the audience is mainly Java developers who develop tailored
> software for many domains. I think that they would like to have some
> answers to these kind of questions:
>
> - why should I learn R?
> - what are the specific use cases where one might think of using R
Hi,
Thanks a lot. I learned that the ROC used in my area was a modified
one like you mentioned, but i want to stick to that if i want to put my
result to such community. I was new to this topic and R, you guided me a
lot and made me to understand. thank you.
I've read several replies to this question already and they seem to have
missed the one point that most irritated the Java programmers to whom I
tried to teach R. They HATED the "object-oriented" material, both S4 and
especially S3, as it did not match the style of OO programming that had
been poun
On Mon, Aug 20, 2012 at 5:57 PM, Greg Snow <538...@gmail.com> wrote:
> I think the big unique thing about R is that it is both an interactive
> environment and a programming language. A new user can start it,
> enter some data, and compute same basic statics without ever
> "programming". A more a
Thank you very much David!! Works perfectly!
--
View this message in context:
http://r.789695.n4.nabble.com/change-axis-label-from-100-100-to-100-100-tp4640855p4640859.html
Sent from the R help mailing list archive at Nabble.com.
__
R-help@r-project.
Rui's solution certainly works, but don't fear namespaces.
For a simple package, you basically just write
export(xxx)
for all the "main" functions and
import(yyy)
for all the packages yyy you use.
If you have S3 methods, it's also important to register those as
S3method(plot, zzz)
If you ar
On Aug 20, 2012, at 5:43 PM, fawda283 wrote:
Hi guys, i need help. I have an axis that runs from -100 -75, -50,
-25, 0 25,
50, 75, 100. I need to somehow hide or remove the '-' in the axis
label. Is
there anyway to do this?? I would still like R to think of the left
side of
my graph as neg
Hi guys, i need help. I have an axis that runs from -100 -75, -50, -25, 0 25,
50, 75, 100. I need to somehow hide or remove the '-' in the axis label. Is
there anyway to do this?? I would still like R to think of the left side of
my graph as negatives, but visually appear as though they are not neg
Hello,
I believe that the simplest way (the one I allways use) is to have the
invisible functions' names start with a period.
.aux <- function(x) # user doesn't see it, R CMD check doesn't force
.Rd file
Hope this helps,
Rui Barradas
Em 20-08-2012 22:06, Eva Prieto Castro escreveu:
Hi,
On Aug 20, 2012, at 5:06 PM, Rui Barradas wrote:
Hello,
Try the following.
g <- factor(c(rep("blue",10),rep("green",10),rep("red",10)),
levels = c("blue", "green", "red"))
plot(y~x, col=levels(g)[g])
plot(y~x, col=as.character(g))
It's not necessary to embed the color names in the factor
Hello,
Try the following.
g <- factor(c(rep("blue",10),rep("green",10),rep("red",10)),
levels = c("blue", "green", "red"))
plot(y~x, col=levels(g)[g])
plot(y~x, col=as.character(g))
Hope this helps,
Rui Barradas
Em 21-08-2012 00:49, Hans Thompson escreveu:
I have been trying to find a way
I have been trying to find a way to label my cluster with the colors I want
using factors. I am not having a good time. I can make the plot I'm
looking for but how can I make it so I specify that my ordered factors have
ordered colors (1= "blue", 2="green", 3="red")?
x <- c(rnorm(10,1,1),rnorm(1
On 2012-08-20 12:24, Tal Galili wrote:
Hello all,
I am trying to understand the different results I am getting from the
following 3 commands:
chisq.test(c(62,50), p = c(0.512,1-0.512), correct = F) # p-value = 0.3788
binom.test(x=62,n=112, p= 0.512) # p-value = 0.3961
2*(1-pbinom(62,112, .512))
I think the big unique thing about R is that it is both an interactive
environment and a programming language. A new user can start it,
enter some data, and compute same basic statics without ever
"programming". A more advanced user can write their own function to
automate common procedures or im
Hi Sergio,
'names' are just an attribute of your list.
If all elements of your list are of the same type (i.e. integer in your
example) you may try something like 'unlist (li)' or even
'as.numeric(unlist(li))'.
This will give you the values you wanted.
An other approach is organizig your data n
Søren Højsgaard math.aau.dk> writes:
>
> Is this what you want?:
>
Yes, that is exactly what I wanted!
Thanks,
--Sergio.
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R
Dear R help,
## Example from
http://stat.ethz.ch/R-manual/R-patched/library/survival/html/frailty.html
# Random institutional effect
coxph(Surv(time, status) ~ age + frailty(inst, df=4), lung)
I am trying to understand what exactly happens when method=df is used ? The
R documentation pages says
Thanks. These are all extremely helpful suggestions and much appreciated.
On Mon, 20 Aug 2012 14:30:05 -0700, Peter Ehlers
wrote:
On 2012-08-20 12:27, William Dunlap wrote:
paste() is ok, but it must be enclosed in expression(),
just like the case that worked.
plot(-15:15,15:-15)
text(x=
Hi,
As I told you some days ago, finally I could build the package, but I have one
doubt: my source code has a lot of functions, but the users only need some of
them (the others are auxiliar functions), so there must be a way in order to
make invisibel the auxiliar functions. I think I can do
Hi Sergio,
'names' are just an attribute of your list.
If all elements of your list are of the same type (i.e. integer in your
example) you may try something like 'unlist (li)' or even
'as.numeric(unlist(li))'.
This will give you the values you wanted.
An other approach is organizig your data n
Hi Marc, Steve, and Nicolas,
Thanks for your replies. This is working now. Looks like the information was
readily available online. Probably is in my books too. Likely missed it due to
time pressure.
Appreciate your help.
Thanks,
Paul
--- On Mon, 8/20/12, Marc Schwartz wrote:
> From: Mar
Inline
-- Bert
On Mon, Aug 20, 2012 at 3:19 PM, Julio Sergio Santana
wrote:
> I wonder if there exists some kind of inverse of the "names" primitive in
> R. Let me explain what do I mean:
>
> If I create a list:
> -> li <- list(a=1, b=2, c=3, d=4)
> then I can have:
> -> names(li)
> [1] "a
Is this what you want?:
> li <- list(a=1, b=2, c=3, d=4)
> li
$a
[1] 1
$b
[1] 2
$c
[1] 3
$d
[1] 4
> unlist(li)
a b c d
1 2 3 4
> unname(unlist(li))
[1] 1 2 3 4
Regards
Søren
-Original Message-
From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org] On
Behalf Of Juli
I wonder if there exists some kind of inverse of the "names" primitive in
R. Let me explain what do I mean:
If I create a list:
-> li <- list(a=1, b=2, c=3, d=4)
then I can have:
-> names(li)
[1] "a" "b" "c" "d"
which is, I guess, some kind of vector, since
-> typeof(names(li))
[1] "char
Two possible solutions:
1. Redefine the LaTeX environment so it allows wrapping (see listings
for example);
2. Manually break your long string into shorter pieces and paste()
them together, e.g. paste('long', 'long', 'string')
Regards,
Yihui
--
Yihui Xie
Phone: 515-294-2465 Web: http://yihui.nam
On 2012-08-20 12:27, William Dunlap wrote:
paste() is ok, but it must be enclosed in expression(),
just like the case that worked.
plot(-15:15,15:-15)
text(x=5, y=4.5, expression(test^1) )
text(x=1, y=11, expression(paste("This is a ", test^1, " of the Emergency Broadcast
System.")))
plotmath
Hi there: I'm preparing a report in RStudio 0.96.330 on a Mac OS. I'm running R
2.15.0
I understand from Ross Ihaka's document
(http://www.stat.auckland.ac.nz/~stat782/downloads/Sweave-customisation.pdf)
that you can modify the line length of Sweave output by a call to
options(wdith=x).
This
For what (little) it's worth, writeOGR() is working for me
OS X 10.6.8
rgdal_0.7-12
May be time to ask on r-sig-geo.
Same directory permissions
Simple somewhat diagnostic test would be to try writing somewhere else,
such as a subdirectory.
-Don
--
Don MacQueen
Lawrence Livermore National L
On Mon, 20 Aug 2012, William Dunlap wrote:
This is where summary(as.d) can give information that str(as.d)
does not.
Bill,
Ah, ha! That finds the error: all observations are in one era. I did not
notice that before. A valuable lesson for me.
Thank you very much,
Rich
Hi Paul,
On Mon, Aug 20, 2012 at 4:13 PM, Paul Miller wrote:
> Hello All,
>
> Hope people won't mind my posting a LaTeX question here. I know a lot of
> people who use R are also using LaTeX. I'm in a bit of a rush to complete a
> document and am having trouble with one aspect of the formatting
Steve,
I tried to replicate your error, but couldn't do it. The code below works
just fine for me. Does it for you?
# create an example data frame
Bridges <- data.frame(CONDITION=1:5, TRAFFIC=rnorm(5), WEATHER=rnorm(5))
# create new variable "LOG_COND"
Bridges$LOG_COND = log(Bridges$CONDITION
Here you go:
\caption[Results for Random Forest Model Using Scoring Data]{Results for Random
Forest Model Using Scoring Data (N = 700)}
but all you really need to know about latex is there:
http://en.wikibooks.org/wiki/LaTeX.
Nico
On 20 Aug 2012, at 22:13, Paul Miller wrote:
> Hello All,
>
On Aug 20, 2012, at 3:13 PM, Paul Miller wrote:
> Hello All,
>
> Hope people won't mind my posting a LaTeX question here. I know a lot of
> people who use R are also using LaTeX. I'm in a bit of a rush to complete a
> document and am having trouble with one aspect of the formatting.
>
> I'm c
Hello All,
Hope people won't mind my posting a LaTeX question here. I know a lot of people
who use R are also using LaTeX. I'm in a bit of a rush to complete a document
and am having trouble with one aspect of the formatting.
I'm creating a list of tables using:
\listoftables
I also have som
Hello, I have question about referencing a variable that I created in a
dataframe, and I am hoping the experts on here can be of assistance. I have
a dataset of highway bridges with approximately 10,000 observations. I
imported these into R in the form of a dataframe called "Bridges".
I am interes
On Aug 20, 2012, at 11:08 AM, Debarghya Mukherjee
wrote:
> Dear sir,
> For my statistical work I have installed R. But for
> analyzing an image in R I have to install jpeg packages. So I have to
> input command install.packages(‘jpeg’). But error occurred: jpeglib.h
> file not foun
You likely need to use your package manager to install something like
jpeglib-dev
or some such. (I don't know the name Fedora uses)
Michael
On Mon, Aug 20, 2012 at 11:08 AM, Debarghya Mukherjee
wrote:
> Dear sir,
> For my statistical work I have installed R. But for
> analyzing a
Actually the second example should just be
> with(mydata, barplot(rbind(female, male), names.arg=opinion,
beside=TRUE, cex.names=.8, legend.text=TRUE))
rbind() instead of t(cbind())
---
David
> -Original Message-
> From: r-help-boun...@r-project.org [mailto:r-help-bounces@r-
> pro
paste() is ok, but it must be enclosed in expression(),
just like the case that worked.
plot(-15:15,15:-15)
text(x=5, y=4.5, expression(test^1) )
text(x=1, y=11, expression(paste("This is a ", test^1, " of the Emergency
Broadcast System.")))
plotmath only works on expressions, not on the strings
Hello all,
I am trying to understand the different results I am getting from the
following 3 commands:
chisq.test(c(62,50), p = c(0.512,1-0.512), correct = F) # p-value = 0.3788
binom.test(x=62,n=112, p= 0.512) # p-value = 0.3961
2*(1-pbinom(62,112, .512)) # p-value = 0.329
Well, the binom.test w
Thanks, the audience is mainly Java developers who develop tailored
software for many domains. I think that they would like to have some
answers to these kind of questions:
- why should I learn R?
- what are the specific use cases where one might think of using R?
- in which area R is good for?
-
On Aug 20, 2012, at 11:35 AM, Brian Kriegler wrote:
I would like to insert a superscript in a body of text (e.g., a
title or axis label), where the superscript is not necessarily at
the end of the text. For example, suppose a title read, "This is a
Test^1 of the Emergency Broadcast System
Sure but which way?
> dput(mydata)
structure(list(opinion = structure(c(4L, 5L, 1L, 2L, 3L), .Label = c("50-50
Chance",
"A good chance", "Almost certain", "Almost no chance", "Probably Not"
), class = "factor"), female = c(96, 426, 696, 663, 486), male = c(98,
286, 720, 758, 597)), .Names = c("o
I think you would find it more useful to take a look at John Chambers'
book: Software for Data Analysis: Programming with R. Much more
authoritative and comprehensive than you are likely to get here.
-- Bert
On Mon, Aug 20, 2012 at 11:02 AM, johannes rara wrote:
> My intention is to give a pres
As a language, there are some nifty things about function arguments:
http://blog.moertel.com/articles/2006/01/20/wondrous-oddities-rs-function-call-semantics.
Lexical scoping + first class functions also come to mind.
If we are thinking about libraries, graphics:
http://addictedtor.free.fr/graphi
I would like to insert a superscript in a body of text (e.g., a title or
axis label), where the superscript is not necessarily at the end of the
text. For example, suppose a title read, "This is a Test^1 of the
Emergency Broadcast System" where there is a superscript 1 after the word
Test.
All,
Is there a way to get a barplot with beside for the following without
reshaping mydata?
opinion <- c("Almost no chance", "Probably Not","50-50 Chance","A good
chance","Almost certain")
female <- c(96,426,696,663,486)
male <- c(98,286,720,758,597)
mydata<-data.frame(opinion,female,male)
Th
Dear sir,
For my statistical work I have installed R. But for
analyzing an image in R I have to install jpeg packages. So I have to
input command install.packages(‘jpeg’). But error occurred: jpeglib.h
file not found. What should I do? I use fedora 17.Please help me.
HI,
Slightly different way:
unlist(lapply(apply(mat,1,count),function(x) max(x[2])))
#[1] 2 1 2 1 1 2 2 2 2 1 2 1 2 2 2 1 1 1 2 2
- Original Message -
From: PIKAL Petr
To: Sam Dekeyser ; "r-help@r-project.org"
Cc:
Sent: Monday, August 20, 2012 10:08 AM
Subject: Re: [R] select most
Hi
> -Original Message-
> From: r-help-boun...@r-project.org [mailto:r-help-bounces@r-
> project.org] On Behalf Of penguins
> Sent: Monday, August 20, 2012 1:15 PM
> To: r-help@r-project.org
> Subject: Re: [R] Remove several numbers from a sequence
>
> Hi!
>
> Both yy[!(yy %in% xx)] and
many thanks for lots of different solutions. I have a couple of very large
data frames but using the unique identifier for each row and Arun's solution
zz[is.na(match(zz$z1,xx$x1)),]
has worked perfectly,
Thanks!
--
View this message in context:
http://r.789695.n4.nabble.com/Remove-severa
My vote:
1. Symbolic function arguments:
fn = function(a, b)
{
a/b
}
fn(b=10, a=2)
2. Names for elements of a vector and matrices
v = c(a=1, b=2)
v['a'] = v['a'] * 2
same for matrices
3. about 10,000 user-contributed packages on CRAN
4. weird things like
a = numeric(10)
a[1:10] = 1:2
On Mon, 20 Aug 2012, David Winsemius wrote:
I see no evidence from what you have posted that the function "obtains a
censored ratio > 0.8". The error messages says there were missing values.
You might consider looking at :
David,
Missing values were removed from the data before reading into
My intention is to give a presentation about R programming language
for software developers. I would like to ask, what are the things that
make R different from other programming languages? What are the
specific cases where Java/C#/Python developer might say "Wow, that was
neat!"? What are the thin
On Mon, 20 Aug 2012, William Dunlap wrote:
You get this error if the factor given as the group argument
has any unused factor levels. E.g.,
with(Golden, cenboxplot(Blood, BloodCen,
factor(DosageGroup,levels=c("Low","High",""
Error in if ((length(obs[censored])/length(obs)) > 0.8) { :
m
You get this error if the factor given as the group argument
has any unused factor levels. E.g.,
> library(NADA)
> data(Golden)
> with(Golden, cenboxplot(Blood, BloodCen,
> factor(DosageGroup,levels=c("Low","High",""
Error in if ((length(obs[censored])/length(obs)) > 0.8) { :
missing valu
On Aug 20, 2012, at 9:22 AM, Rich Shepard wrote:
On Thu, 16 Aug 2012, David L Lorenz wrote:
The cenboxplot function uses cenros to estimate the censored
values. The
cenros function requires at least 2 uncensored observations to be
able to
do the regression. The cenros function does issue a
The akima package does interpolation and there are probably others as well.
You could also fit a parametric, semi-parametric, or local model to
the observed data and use the predicted values from the model for the
interpolations (see the loess function for one option that might work
well for you).
On Thu, 16 Aug 2012, David L Lorenz wrote:
The cenboxplot function uses cenros to estimate the censored values. The
cenros function requires at least 2 uncensored observations to be able to
do the regression. The cenros function does issue a warning when there are
more than 80% censored data, b
>> on the whole, it seems to me that character
>> input gets used as factor data so much of the time when it is
>> used at all that the default stringsAsFactors=TRUE setting
>> seems the more sensible default.
>
> I disagree with this last point. Just think of the number of
> questions to this
Like most Ubuntu/R users, you probably have a CRAN mirror in your sources.list.
Ubuntu comments out all third-party sources during an upgrade to avoid
debugging nightmares where the third-party software interferes with Ubuntu
standard package upgrade scripts. This net result is that R generally
On Mon, Aug 20, 2012 at 7:27 AM, cindy.dol wrote:
> I use sqldf to join 2 dataframes from 2 distinct databases : a and b come
> from old sqldf's.
>
> sqldf("select a.*, b.*, case a.QTY when null then b.QTY else a.QTY end as
> NEW_QTY"
> from a inner join b on a.OBJECT=b.OBJECT")
>
> R doesn't unde
Dear Nooshin,
most attachments will not make it into the list. Please upload it somewhere and
link to it instead.
alternatively you could post reproducible code to generate your plot so far.
On 20.08.2012, at 15:53, nooshin bahar wrote:
> Hello guys,
>
> I want to increase contrast of colors i
Hi
?rainbow
?jet.colors
?RColorBrewer
Regards
Petr
> -Original Message-
> From: r-help-boun...@r-project.org [mailto:r-help-bounces@r-
> project.org] On Behalf Of nooshin bahar
> Sent: Monday, August 20, 2012 3:53 PM
> To: r-help@r-project.org
> Subject: [R] colorful plot
>
> Hello guy
Hi
It is really a typical example of a question which has probably very simple
solution but hardly anybody can give you a rasonable answer.
How your data look like?
What is the structure of your data?
set.seed(1)
x<-sample(1:4, 60, replace=T)
mat<-as.factor(x)
dim(mat) <- c(20,3)
> sapply(appl
Hello,
Can somebody help me on a colour question?
I have a levelplot made with the following syntax:
library(lattice)
inp <- read.csv("hoenne1", header = TRUE)
levelplot(z~x*y, data = inp, region = TRUE, pretty = TRUE, col.regions
= terrain.colours)
The file "hoenne1" contains the data. I'll give
Hi,
Try this:
dat1<-read.table(text="
1 0 1
2 1 2
3 0 3
4 1 4
5 0 5
6 1 6
7 0 7
8 1 8
9 0 9
10 1 10
",sep="",header=FALSE)
dat2<-dat1[,-1]
combn((subset(dat2,V2==0))$V3,2)
[,1] [,2] [,3] [,4] [,5] [,6] [,7] [,8] [,9] [,10]
[1,] 1 1 1 1 3 3 3
Hello guys,
I want to increase contrast of colors in my matrix plot.
I attached final plot with heatmap.
How I could increase contrast with 9 kind of color.
Thanks
Nooshin
[[alternative HTML version deleted]]
__
R-help@r-project.org mailing li
I use sqldf to join 2 dataframes from 2 distinct databases : a and b come
from old sqldf's.
sqldf("select a.*, b.*, case a.QTY when null then b.QTY else a.QTY end as
NEW_QTY"
from a inner join b on a.OBJECT=b.OBJECT")
R doesn't understand "when null". I tried with "when NA", "when '' ", "when
'
Hi,
Try this:
A<-data.frame(FID=c("a","a","b","b","c","c","d","d","d","d"))
B<-read.table(text="
FID Age
a 5
b 7
c 9
d 3
",sep="",header=TRUE)
library(plyr)
join(A,B,type="inner")
Joining by: FID
FID Age
1 a 5
2 a 5
3 b 7
4 b 7
5 c 9
6 c 9
7
Just to say, i still consider it wrong (what is called the fpr there simply
isn't the fpr, and the graph will not be what is commonly known as an ROC
curve), at least the definition list puts down slightly different names for it.
What else exactly do you need then though? you now know how to plot
Hi!
Both yy[!(yy %in% xx)] and yy[is.na(match(yy,xx))] work a treat!
Developing this topic can anyone tell me how to extract rows which are not
replicated across 2 data frames. For example:
z1<-c(1,2,3,4)
z2<-c(5,6,7,8)
zz<- data.frame(cbind(z1,z2))
x1<-c(3,4)
x2<-c(7,8)
xx<- data.frame(cbind(x
Hallo,
I was about to upgrade Ubuntu 11.10 to 12.04 when I saw that this would mean
that the package 'r-base-dev' would be removed. What exactly does this imply?
Will R be still working correctly after the upgrade? Will the pacakge
automatically be reinstalled (it didnt appear in any other list
Hi,
I would like to select the most frequent value level in a set of three
variables.
Three different observators have judged hair color in study subjects. Mostly
they judge the same color, sometimes there is a slight difference. I want to
know what most of the observators have chosen (so at l
I found a solution to this problem myself by searching further and
experimenting with some functions.
I ended up with a for-loop which iterates over the cases. It generates a table
per case, and selects the most frequent (i.e. the value corresponding with the
highest frequency) choice, which c
On 10/08/2012 16:53, John C Nash wrote:
WinXP says
OS reports request to set locale to "en_US.UTF-8" cannot be honored.
Sigh.
Yes, Windows has no UTF-8 locales: they are all 8-bit or DBCS (which is
ASCII plus 2-byte codes for CJK languages). You can work in UTF-16 in
any locale, but lots
Hi
> -Original Message-
> From: r-help-boun...@r-project.org [mailto:r-help-bounces@r-
> project.org] On Behalf Of Rui Barradas
> Sent: Monday, August 20, 2012 2:03 PM
> To: S Ellison
> Cc: r-help
> Subject: Re: [R] Opinion: Why I find factors convenient to use
>
> Hello,
>
> Em 20-08-20
Whether I use stringsAsFactors=FALSE or stringsAsFactors=TRUE tends to rely on
where my data are coming from. If the data are coming from our Oracle
databases (well controlled data), I import the with stringsAsFactors=TRUE and
everything is great. If the data are given to me by a fellow in the
Hello,
I've followed your link (thanks) and in the presence of ties the value
of R's cor.test, method = "kendall", in package stats and kendall_tau_b
in the link are the same. If you have ties, cor.test will issue a
warning but that is relative to the p-value only, the reported tau,
under "sa
Hello,
Em 20-08-2012 12:30, S Ellison escreveu:
-Original Message-
Over the years, many people -- including some who I would
consider real expeRts -- have criticized factors and
advocated the use (sometimes exclusively) of character
vectors instead.
Exclusive use of character vector
Dear R helpers,
What to say ? thank you very much for your very interesting algorithmic
suggestions!
Everything is fine now
Have a nice day,
Best,
On 20 August 2012 03:50, William Dunlap wrote:
> Yes, if the Special_Dates are not sorted then f4 needs to sort them.
> Perhaps closestValue shoul
> -Original Message-
> Over the years, many people -- including some who I would
> consider real expeRts -- have criticized factors and
> advocated the use (sometimes exclusively) of character
> vectors instead.
Exclusive use of character vectors is not going to do the job.
The con
read ?plot.default and look at what frame.plot does.
> -Original Message-
> From: r-help-boun...@r-project.org
> [mailto:r-help-boun...@r-project.org] On Behalf Of ARI BEN
> Sent: 18 August 2012 15:22
> To: r-h...@stat.math.ethz.ch
> Subject: [R] plot only x- and y-axis with origin, no
Thanks for your help, John!
I don't know how I missed the Data, Active Data Set sequence.
Todd
From: John Fox [via R] [ml-node+s789695n464068...@n4.nabble.com]
Sent: Friday, August 17, 2012 10:51 PM
To: Easton, Todd
Subject: Re: Making data in R available to Rcmd
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