What did the maintainer say (see the posting guide and indeed the R FAQ
for where to report BUGS)? He is Cc:ed here.
This is not necessarily a bug: R functions can change their arguments
(but we do expect that to be prominently documented). KalmanLike is one
user-visible example.
On 05/08
Hi,
I need to remove collinear variables to my Near-Infrared table of spectra.
What package can I use?
Something simple, because I am a novice about statistic.
Thank you.
Best regards,
Roberto
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Hi,
I'm having issues with what I believe is a bug in the MCMCpack's
MCMCmetrop1R function. I have code that basically looks like this:
posterior.sampler <- function(data, prior.mu){
log.posterior <- function(theta) log.likelihood(data, theta) +
log.prior(prior.mu, theta)
post.samples <- MC
Dear all
I came across ptproc package on following website:
http://www.biostat.jhsph.edu/~rpeng/software/index.html
Actually I downloaded it on the contributors website and tried to install
it manual but R wont unzip it. It is not available on CRAN project.
I use R 2.15.1 and windows vista on my
dear userR:
I am trying to plot two dependent variables in the same plot in ggplot2.
because these two variables have very different magnitude, I have to use a
second Y axis. I hope one variable to be line and the other to be barchart.
The x axis is continuous. Yet since I have to make barchart, I
Jeff jp.pair.com> writes:
> I'm hoping that this is a relatively easy question for someone
> familiar with the lme4 package. I'm accustomed to using HLM
> software and writing a simple 2 level [null] equation like this:
>L1 - Yij = b0 + e
>L2 - b0 = B00 + u0
>The following comm
Take a look at ?expand.grid
Michael
On Aug 4, 2012, at 5:03 PM, "alijk1989 [via R]"
wrote:
>
>
> Thanks again for the help looks like this will be useful for what I'm doing.
> Is there any way to use combn to return combinations of values with
> themselves:
>
> e.g.
>
>> combn(1:3,2)
>
>
Thanks again for the help looks like this will be useful for what I'm doing.
Is there any way to use combn to return combinations of values with
themselves:
e.g.
>combn(1:3,2)
[,1] [,2] [,3] [,4] [,5] [,6]
[1,]111 2 2 3
[2,]1 232 3 3
Hello,
I have a data set that looks like this:
name G-ID test_id g-id g
1 00077464 C_068131 C_068131 OC_068131-
2 00051728 C_044461 C_044461 OC_044461-
3 00058738 C_050343 C_050343 OC_050343-
4 00059239 C_050649 C_050649 OC_050649-
5 1761 C_000909 C_000909 OC
Hi
can any body please help me to programme this formula:
a[j]= E[j]-sum from l=i to i-1 (exp{(B0 B1*row matrix*) (z[l]*column
matrix*) } x[l]) / sum from l=i to n
it s complicate for me ; hope you can help me
thank you a lot
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You may be able to get around zero cells using a an MCMC approach such as with
MCMCglmm.
On Aug 4, 2012, at 15:30, Sacha Viquerat wrote:
> On 08/04/2012 07:57 PM, Joshua Wiley wrote:
>> Hi Sacha,
>>
>> You're right that this is not an R related question really (would be better
>> somewhere l
Hello,
You can coerce the result to the input shape by assigning the dim
attribute by hand.
string.ans <- sweep(m, c(2,3), stat, string.fun)
dim(string.ans) <- dim(m)
string.ans
Or put this in a function.
# An abbreviation and the complete function name
sweep.ch <- sweep.character <-
functio
Thank you for your comment. I suspected that a model with well defined
predictors should work fine with a glm procedure.
Thanks again
K
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Sent from the R help mailing list archive at Nabble.
thanks a lot
sorry for the mistake that i do in exponential, i am "francophone"
and for the programme if we want to apply the "power rule " condition we use
log(vi).
it works thank yo
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Hi,
I would like to use sweep to "sweep out" proportions and confidence intervals
for an array, however when I supply a function which returns a string
(containing something like "9% (3-18%)") I get back a list instead of an array,
here is a simplified example:
# example showing that swe
Hi there! I'm following an awesome guide to working with spatial data
(http://www.frankdavenport.com/blog/2012/6/19/notes-from-a-recent-spatial-r-class-i-gave.html)
and am running into an error that I can't figure out how to fix.
Disclaimer: I am very much an R n00b
Here is the r script I am runn
Joshua Wiley gmail.com> writes:
>
> In addition to Bert's suggestion of r sig mixed models
> (which I second), I would encourage you to create a
> more detailed example and explanation of what you hope to accomplish.
> Sounds a bit like an auto regressive
> structure, but more details would be
Hello,
Vous êtes française?
It shows, in english it would be 'exponential', with an 'a'.
Worked with me, after reading the manual.
dataexp <- read.table(text="
vi Ti
1 265.79
2 26 1579.52
3 26 2323.70
4 28 68.85
[...]
73 380.39
74 381.13
75 380.09
76 382.38
", he
On Aug 4, 2012, at 10:45 AM, hafida wrote:
Dear R-community,
I have tried to estimate an EXPONENTIEL accelerated failure time(AFT)
power rule model with time-independent . For that purpose, I have
used
the eha package.
Please, consider this example:
vi Ti
1 265.79
2 26 1579.
Dear R-community,
>
> I have tried to estimate an EXPONENTIEL accelerated failure time(AFT)
> power rule model with time-independent . For that purpose, I have used
> the eha package.
> Please, consider this example:
vi Ti
1 265.79
2 26 1579.52
3 26 2323.70
4 28 68.85
5 28
HI,
I guess this will be more appropriate:
tfr<-read.table(text="
14/12/2000 15/12/2000 18/12/2000 19/12/2000 20/12/2000 21/12/2000
22/12/2000 25/12/2000 26/12/2000 27/12/2000 28/12/2000 29/12/2000
01/01/2001 02/01/2001 03/01/2001 04/01/2001 05/01/2001 08/01/2001
09/01/2001 10/01/2
Hi,
Try this:
tfr<-read.table(text="
14/12/2000 15/12/2000 18/12/2000 19/12/2000 20/12/2000 21/12/2000
22/12/2000 25/12/2000 26/12/2000 27/12/2000 28/12/2000 29/12/2000
01/01/2001 02/01/2001 03/01/2001 04/01/2001 05/01/2001 08/01/2001
09/01/2001 10/01/2001 11/01/2001 12/01/2001 1
Hi Sacha,
You're right that this is not an R related question really (would be better
somewhere like crossvalidated.com).
If basically everyone catches 0/1 birds, then I would consider dichotomizing:
Y <- as.integer(caught >= 1)
then check cross tabs to make sure there are no zero cells betwe
In addition to Bert's suggestion of r sig mixed models (which I second), I
would encourage you to create a more detailed example and explanation of what
you hope to accomplish. Sounds a bit like an auto regressive structure, but
more details would be good.
Cheers,
Josh
On Aug 4, 2012, at 9:34
Hello,
Works with me:
x <- scan(what = "character", text = "14/12/2000 15/12/2000 18/12/2000
19/12/2000 20/12/2000 21/12/2000
22/12/2000 25/12/2000 26/12/2000 27/12/2000 28/12/2000 29/12/2000
01/01/2001 02/01/2001 03/01/2001 04/01/2001 05/01/2001 08/01/2001
09/01/2001 10/01/2001 11
Hi all,
I´m trying to convert as a data frame (with format "date") this copied
excel column of dates (exposed below), I have tried to save them in a txt
file
tfr<-read.table("tfra.txt")
tfr<-data.frame(tfr)
I have tried several things, as date, so on, but always error.
And it makes
Error en as.
Sounds like generalized linear mixed modeling (glmm) to me. Try
posting to the r-sig-mixed-models list rather than here to increase
the likelihood of a useful response.
-- Bert
On Sat, Aug 4, 2012 at 3:55 AM, doctoratza wrote:
> Hello everyone,
>
> i would like to ask if everyone knows how to pe
Just to follow up on what Michael wrote:
I cannot reproduce that error. For example, this all works as intended:
data(dat.bcg)
dat <- escalc(measure="RR", ai=tpos, bi=tneg, ci=cpos, di=cneg, data=dat.bcg,
append=TRUE)
rma(yi, vi, mods = ~ alloc, data=dat) ### 'alloc' automatically converted to
On Sat, Aug 4, 2012 at 9:12 AM, Sacha Viquerat
wrote:
> Hello!
> I am doing an analysis on a questionnaire of hunters taken in 4 different
> districts of some mysterious foreign country. The aim of the study was to
> gather info on the factors that determine the hunting success of a
> peculiarly b
Hello,
Try the following.
id.groups <- with(dat, cut(ID, breaks=0:ceiling(max(ID
sp <- split(dat, id.groups)
regressors <- grep("en", names(dat))
models <- lapply(sp, function(.df)
lapply(regressors, function(x) lm(.df[["S"]] ~ .df[[x]])))
mod.summ <- lapply(models, function(x) lapply(
On 04.08.2012 12:18, Ivette wrote:
http://r.789695.n4.nabble.com/file/n4639158/elgas2.csv elgas2.csv
http://r.789695.n4.nabble.com/file/n4639158/histogramselgas.R
histogramselgas.R
Hello,
I want to plot 9 histograms, and I prepare the data for this operation with
the usual command,
sapply(x, is
Klaus: John Kane is right to point out that the procedure will
depend on your OS. It will also depend on what interface you use
for entering text into R.
All the letters you need for Faroese are present in the basic
iso-8859-1 Western European character set (also known as ISO-Latin1)
which should
Hi R- User
I have very big data set (5000 rows). I wanted to make classes based on a
column of that table (that column has the data which is continuous .) After
converting into different class, this class would be Unique ID. I want to run
regression for each ID.
For example I have a data set
>
Hello!
I am doing an analysis on a questionnaire of hunters taken in 4
different districts of some mysterious foreign country. The aim of the
study was to gather info on the factors that determine the hunting
success of a peculiarly beautiful bird in that area. All variables are
factors, i.e.
http://r.789695.n4.nabble.com/file/n4639158/elgas2.csv elgas2.csv
http://r.789695.n4.nabble.com/file/n4639158/histogramselgas.R
histogramselgas.R
Hello,
I want to plot 9 histograms, and I prepare the data for this operation with
the usual command,
sapply(x, is.numeric), then I get a confirmatio
Hello everyone,
i would like to ask if everyone knows how to perfom a glm partial likelihood
estimation in a time series whrere dependence exists.
lets say that i want to perform a logistic regression for binary data (0, 1)
with binary responses which a re the previous days.
for example:
logis
At 17:03 03/08/2012, cpanderson wrote:
Wolfgang,
Thanks for your quick response. You are correct- indeed I had inadvertently
left out that i had set intercept = FALSE in rma.
Dear Christopher,
It does help if you paste in the exact code you used, see also below
Following your suggestions, I
Depends on your OS probably.
I would just add a Faroese keyboard to my Ubuntu setup and switch between my
normal keyboard and Faoese as required.
John Kane
Kingston ON Canada
> -Original Message-
> From: klausflemlo...@mail.tele.dk
> Sent: Fri, 3 Aug 2012 10:08:48 -0700 (PDT)
> To: r-
Hello,
Inline.
Em 04-08-2012 09:34, David Winsemius escreveu:
On Aug 3, 2012, at 10:00 AM, tgodoy wrote:
Hi, I'm a new user or R and I try to concatenate a several rows
according
with the value in a column.
this is my data.frame and I want to concatenate my data.frame
according with
the c
On Aug 3, 2012, at 10:00 AM, tgodoy wrote:
Hi, I'm a new user or R and I try to concatenate a several rows
according
with the value in a column.
this is my data.frame and I want to concatenate my data.frame
according with
the column "b" and make a new data.frame with the information in the
HI,
Try this:
#Reformatted the ddply results to match your desired output.
dat1<-read.table(text="
a b c d
E001234 TSA IP234 like_domain
E001234 TSB IP234 like_domain
E001234 TSC IP234 like_domain
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