I have been using XLConnect to write multisheet Excel without any problems.
Sent from my iPad
On May 19, 2012, at 21:32, Spencer Graves
wrote:
> Hello, All:
>
>
> The "writeFindFn2xls" function in the "sos" package tries to write an
> Excel file with 3 sheets ('PackageSum2', 'findFn',
Thank you Simon,
Yes this was in the library(car). There were no negative values in the
scatterplot graph or negative limits displayed.
Q-2 Are you sure the lines from the scatterplot are not this?:
solid green line: linear regression
solid red line: non-linear regression
upper dashed red line: u
Hello, All:
The "writeFindFn2xls" function in the "sos" package tries to
write an Excel file with 3 sheets ('PackageSum2', 'findFn', 'call').
Unfortunately, it is often unable to do this because of configuration
problems that are not easy to fix. I've found 3 contributed packages
that
On May 19, 2012, at 6:58 PM, jacaranda tree wrote:
Hi all,
I have been struggling with ANOVAs on R. I am new to R, so I created
a simple data frame, and I do some analyses on R just to learn R and
then check them on SPSS to make sure that I am doing fine. Here is
the problem that I've run
Will
y[order(match(y,x))]
[1] 9 8 11 2 1
do?
Regards
Søren
-Original Message-
From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org] On
Behalf Of Lars Bishop
Sent: 20. maj 2012 01:05
To: r-help@r-project.org
Subject: [R] Help with ordering values
Hi,
Is it possibl
Hello,
Could you post the output of
dput(head(settlepw, 10))
dput(head(hatch, 10))
Just copy the output and paste it in a post. These functions give the first
10 lines (head) and the structure of your datasets.
I'm asking this because with the two example datasets you gave in an earlier
post, pl
Hey,
Thanks for the reply. I tried tod do change this in two ways:
-with the formula, as you recommended (and after reading ?strptime some
similar formulas as well), but this did not help.
-by replacing the date to the form dd/mm/yy. But this didn't change anything
to the plot layout as well.
The
Hi all,
I have been struggling with ANOVAs on R. I am new to R, so I created a simple
data frame, and I do some analyses on R just to learn R and then check them on
SPSS to make sure that I am doing fine. Here is the problem that I've run into:
when we use the aov function, it uses SS Type I as
Hi,
Is it possible to use x and y below to produce the vector shown in
desired.result (which represents the values in y ordered according to
the order specified by x)? Ideally the solution must be efficient in
terms of timing as I'm dealing with *very* long vectors.
x <- c(7, 6, 5, 9, 4, 14, 8,
On 12-05-18 2:23 PM, David Winsemius wrote:
On May 18, 2012, at 10:52 AM, Duncan Murdoch wrote:
On 12-05-18 5:15 AM, gholi bahrami wrote:
Dear Sir/Madam
I am a BSc student studying statistics in Ferdowsi University of
Mashhad,Iran.
Translating R messages to Farsi is my thesis and I have alrea
Many thanks to Baptiste Auguie (off list), Bill Dunlap, Bert Gunter,
Gabor Grothendieck,
and Paul Johnson for their interesting and informative responses to my post.
The main item to note is that I was piling on unnecessary baggage by using
plot(1:10,xlab= eval(expression(parse(text=xNm))
On 12-05-18 12:56 PM, jaimie villanueva wrote:
hi
someone can show me how can i get the source code of a function. Is a S4
class or Method. (I'm not an expert in R environment)
Exactly, Function "ugarchsim" from library (rugarch).
I need to know (in detailed ) how the variance and mean ecuation
Paul Johnson wrote
> power <- "gamma" ; x <- "Waist Size (cm)" ; y <- "Weight (kg)" # invalid R
> names
> plot(0, main=bquote(.(as.name(x))^.(as.name(power))/.(as.name(y
>
> It appears to me that 2/3 of the as.name usages are not needed, at
> least not in R 2.15 on Debian Linux.
>
> This wor
On May 19, 2012, at 5:00 PM, Sparks, John James wrote:
Dear R Helpers,
I am getting an error message from the try function that I don't
understand so I am hoping that someone can help.
I am scraping from web pages, but sometimes they disappear. When that
happens I need to control for it with
Dear R Helpers,
I am getting an error message from the try function that I don't
understand so I am hoping that someone can help.
I am scraping from web pages, but sometimes they disappear. When that
happens I need to control for it with some sort of function.
This web page is parsed without a
That means it calls compiled C code so you'll need to download the
source code from CRAN to see it. It will be somewhere in the
rugarch/src/ directory, but you'll have to find it manually or with a
good editor/IDE -- you're out of R now.
The primitive() means that .C is itself a primitive function
On May 19, 2012, at 3:32 PM, Chris North wrote:
Hi there,
I'm working on a for loop to perform some simple calculations on data.
However, I'm having trouble extracting components from my data frame
using
names pulled off a list to reference headers. I'm relatively new to
R, but
I've done s
Hi there,
I'm working on a for loop to perform some simple calculations on data.
However, I'm having trouble extracting components from my data frame using
names pulled off a list to reference headers. I'm relatively new to R, but
I've done some programming in various other languages, and have don
You need to specify that you want a binary download - make sure to
read help("download.file"), particular that of argument 'mode'.
Alternatively, use downloadFile() in the R.utils package which
download as binary by default.
/Henrik
On Sat, May 19, 2012 at 7:22 AM, sagarnikam123 wrote:
> i use
On May 19, 2012, at 12:36 PM, bets wrote:
Sorry, I hoped this was already clear enough.
Below you offer two examples of console output without naming the
objects from which they came or the code you are attempting to us.
(Also in the all-to-typical manner of those posting through Nabble
i use download.file() ,it works good for package source code
t<-available.packages(type="source") #all packages(list) from repository in
source code ".tar.gz" format
length(t[,2]) #total packages--> 3796
#package source file download
for( i in seq_along(t[,1]) ) {
download.file(
paste(t[i,"Repo
On Sat, May 19, 2012 at 2:16 PM, Paul Johnson wrote:
> On Sat, May 19, 2012 at 11:07 AM, William Dunlap wrote:
>> parse(text=paste(...)) works in simple cases but not in others. The
>> fortune about it is there because it is tempting to use but if you bury it
>> in a general purpose function it
On Sat, 19 May 2012 09:50:27 +0200
Hans W Borchers wrote:
> JWDougherty surewest.net> writes:
>
> > Can someone point me to an implementation of the "runs up and runs
> > down" test, or does such beast exist in R? From web searches the
> > "runs up and runs down" test is commonly used for testi
Sorry, I hoped this was already clear enough.
Oké, here are the first rows of the relevant part of the data:
Datum week T.local
29/06/111 19.272420
5/07/11 2 19.305034
13/07/113 17.766046
20/07/114
On May 19, 2012, at 7:46 AM, Ross, Stephanie wrote:
Hi All,
I have a question regarding contingency tables. I would like to
calculate the mean and standard deviation of a continuous variable
from my own dataset based on the percentages of a contingency table
I obtained from a scientific
On Sat, May 19, 2012 at 11:07 AM, William Dunlap wrote:
> parse(text=paste(...)) works in simple cases but not in others. The
> fortune about it is there because it is tempting to use but if you bury it
> in a general purpose function it will cause problems when people
> start using nonstandard n
parse(text=paste(...)) works in simple cases but not in others. The
fortune about it is there because it is tempting to use but if you bury it
in a general purpose function it will cause problems when people
start using nonstandard names for variables. bquote(), substitute(),
call(), and relative
On 19.05.2012 17:40, bets wrote:
Hey,
I'm doing my thesis and I need to produce a lot of plots. With 2 I have a
problem that I can't get past:
http://r.789695.n4.nabble.com/file/n4630611/question.png
The left one has lines instead of dots. All I want is a basic line (it's a
time series). So
On 19.05.2012 15:34, Allen wrote:
Hello,
Can someone help me on how to make a subset of my dataframe using two dates.
This is what I have tried, but no data is being excluded in the new frame.
six_months<-subset(Two_years, vdate>2011-01-01|vdate<2011-07-01)
Convert the *string* "2011-01-01
Hi Teo:
On May 19, 2012, at 6:57 AM, mala10af wrote:
> Hi all,
>
> I am a student and I ma writing my master thesis about oil and gasoline
> options. In my master thesis I would like to estimate some parameter of the
> oil market. I base my pricing models according to Schwartz (1997). In order
>
On Sat, May 19, 2012 at 9:31 AM, peter dalgaard wrote:
> "Best practice" is a bit contentious, but several people have found that the
> tcltk package offers a path of low resistance.
>
Additionally check gWidgets.
Liviu
__
R-help@r-project.org mailing
R has four "Kalman" functions -- type apropos("Kalman") to see them --
then you can get info about any of them in particular by typing ?
funcname or running example(funcname) to see worked examples.
Beyond the scope of your question, you also might be interested in
this: http://cran.r-project.org/
Hey,
I'm doing my thesis and I need to produce a lot of plots. With 2 I have a
problem that I can't get past:
http://r.789695.n4.nabble.com/file/n4630611/question.png
The left one has lines instead of dots. All I want is a basic line (it's a
time series). So I used the type="l" command, but tha
It works now :)
thank you!
--
View this message in context:
http://r.789695.n4.nabble.com/weighted-averages-for-two-variables-tp4630589p4630610.html
Sent from the R help mailing list archive at Nabble.com.
__
R-help@r-project.org mailing list
https://s
Dear R Users,
I am facing a problem analyzing an incomplete block design with two
replicates. As you can see in the attached .xls file, the factor2 (6
levels) nested within factor1(two levels) nested within replicates all were
chosen as random effects in the statistical model (see below). Note tha
This is the output that i got
> dput( head(allspecies, 20) )
structure(list(Year = c(1980L, 1980L, 1980L, 1980L, 1980L, 1980L,
1980L, 1980L, 1980L, 1980L, 1980L, 1980L, 1981L, 1981L, 1981L,
1981L, 1981L, 1981L, 1981L, 1981L), Quarter = c(1L, 1L, 1L, 1L,
1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L,
Hi all,
I am a student and I ma writing my master thesis about oil and gasoline
options. In my master thesis I would like to estimate some parameter of the
oil market. I base my pricing models according to Schwartz (1997). In order
to get those data a I need to run a Kalman filter algorith with mx
Hello,
Can someone help me on how to make a subset of my dataframe using two dates.
This is what I have tried, but no data is being excluded in the new frame.
six_months<-subset(Two_years, vdate>2011-01-01|vdate<2011-07-01)
or all data is excluded
six_months<-subset(Two_years, vdate>2011-01-01
Hello,
Thanks.
The revised 'by' I had posted works with me.
An alternative, more complicated, is using split/sapply.
sapply(split(allspecies, allspecies$Year), function(x)
weighted.mean(x$Depth, x$CPUE))
Rui Barradas
__
R-help@r-project.org
On Sat, May 19, 2012 at 11:09 AM, Jeff Newmiller
wrote:
> library (zoo)
> ?na.approx
>
> Note that you need to define an index (time base) to go along with your data,
> but that could be as simple as a sequence of integers.
Actually na.approx in the zoo package has a default method that works
wi
library (zoo)
?na.approx
Note that you need to define an index (time base) to go along with your data,
but that could be as simple as a sequence of integers.
---
Jeff NewmillerThe . .
..and a final addendum:
xnm <- quote(gamma)
## makes xnm the name gamma not the string "gamma"
plot(0,xlab = bquote( .(xnm))
-- Bert
On Sat, May 19, 2012 at 7:23 AM, Bert Gunter wrote:
> ... and here is another incantation that may be informative.
>
> xnm<- as.name("gamma') ## This does the
I don't think it's part of the standard install -- I certainly didn't
get it with Simon's [Mac] CRAN build and when I did download it it's
marked with priority "NA" -- so no need to worry there.
Best,
Michael
On Sat, May 19, 2012 at 10:36 AM, Bert Gunter wrote:
> ?install.packages
> This funct
Hello,
Post a data example, it will give us something to work on, and give you
better answers.
dput( head(allspecies, 20) )
Then copy the output of this and paste it in your post.
As for your problem, considering it's description, and untested (no
data), maybe
result <- by(allspecies, all
?install.packages
This functionality may also be available from a menu in an R GUI, e.g.
on WIndows. But as you failed to provide your system details -- as
requested by the posting guide -- we can't say.
HOWEVER ... something appears to be rotten in Denmark (with apologies
to Peter D.). IIRC, RODB
... and here is another incantation that may be informative.
xnm<- as.name("gamma') ## This does the parsing
plot(0, xlab =bquote(.(xnm))
The initial puzzle is that if you just set
xnm <- "gamma"
bquote will insert the string "gamma" rather than the symbol. After
all, that's what plotmath sees
Hello,
You are not using dates.
> 2011-01-01
[1] 2009
> 2011-07-01
[1] 2003
> as.Date(2011-07-01)
Error in as.Date.numeric(2011 - 7 - 1) : 'origin' must be supplied
> as.Date("2011-07-01")
[1] "2011-07-01"
The error is because as.Date is seeing 2003 as a number, the number of
days since an uns
Hello,
The error is that you are trying to use the number of rows of a
character string.
TOWERS[1], TOWERS[2], etc, are not data frames. Use a print statement
before the line that throws the error to check it.
Your problem can be solved along the lines of what follows.
Note that I've put all
David,
See corr.test in the psych package.
Bill
On May 18, 2012, at 9:35 AM, David Studer wrote:
> Hi everybody!
>
> Does anyone know how to obtain a inter-item-correlation-table
> (with p-values or significance-levels)? (as SPSS does, either spearman or
> pearson)
>
> Repeatedly using cor.
On 05/19/2012 07:44 AM, SteveQ wrote:
I am using the following:
library(RODBC)
chan = odbcConnectExcel("rats-lda")
rats.lda = sqlFetch(chan, "data")
close(chan)
And getting the following error message:
library(RODBC)
Error in library(RODBC) : there is no package called ‘RODBC’
The above erro
i have time series as
1.3578511
0.5119648
1.3189847
0.9214787
1.2272616
4.9167998
1.2272616
1.2272616
0.8854192
2.3386331
1.6132899
0.2030302
0.8426226
1.2277843
NA
1.3189847
1.3578511
0.8530141
2.3386331
1.0541099
0.7747481
0.5764672
1.3189847
1.2160533
1.2272616
0.6715839
0.9651803
1.6132899
1.20
Hi All,
I have a question regarding contingency tables. I would like to calculate the
mean and standard deviation of a continuous variable from my own dataset based
on the percentages of a contingency table I obtained from a scientific article.
dataset<- data.frame(cbind(case=rep(0:1,5), x1=c(1
I am using the following:
library(RODBC)
chan = odbcConnectExcel("rats-lda")
rats.lda = sqlFetch(chan, "data")
close(chan)
And getting the following error message:
> library(RODBC)
Error in library(RODBC) : there is no package called ‘RODBC’
> chan = odbcConnectExcel("rats-lda")
Error: could not
Thanks Simon. I have other vectors in the CSV file so after naming my
latitude and longitude x and y, I tried this. The first two lines run fine
but I get error in the second line.
r <- raster(as.matrix(F1))
extent(r) <- extent(xmin, xmax, ymin, ymax)
F1<-data.frame(x, y,z)
Error in function (cl
Hi R users,
I have a dataset with multiple variables and i'm trying to weigh average
depths for fish species per year by their abundance (CPUE. I have tried the
weighted.mean function but as i have two columns for the x value the lenghts
differ with the w (CPUE). How do I solve this problem?
So f
mh, I have read about the package before, but it does not help me a
much I dont know how to do this?
Zitat von Erich Neuwirth :
You might want to give the packages animation a try.
On May 19, 2012, at 11:47 AM, c...@mail.tu-berlin.de wrote:
Hi,
I want to do an interactive plot in R:
I ha
This already in your question:
"+init=epsg:4326"
That is equivalent to "+proj=longlat +ellps=WGS84" just looked up via the
EPSG code. A good site to explore this topic is spatialreference.org
On Saturday, May 19, 2012, Belay Gebregiorgis wrote:
> Hello everyone,
>
> I want to get a 1km by lkm g
On May 18, 2012, at 20:19 , Patrick Callier wrote:
> Hi all,
>
> I am running 64-bit R 2.15.0 on windows 7. I am trying to use read.delim
> to read from a file that has 2-byte unicode (CJK) characters.
>
> Here is an example of the data (it is tab-delimited if that gets messed up):
> HITId HIT
I presume you mean car::scatterplot
A1) plot is a generic function for plotting 'things' and scatterplot
is a specific tool provided by that library
A2) from the documentation one infers that
1) the straight line is a regression line
2) the other lines are produced using loess
provided you get the call to read.table (or perhaps read.csv) right
and presuming that file contains only the image data, you should
be able to say:
r <- raster(as.matrix(read.csv("file.csv")))
extent(r) <- extent(xmin, xmax, ymin, ymax)
and not worry about the projection (if it is plain old deci
First, what was going wrong:
#this creates a character vector, not an object containing your data sets
TOWERS <- c("TOWER1","TOWER2","TOWER3","TOWER4","TOWER5","TOWER6","TOWER7")
for(i in 1:7){
# this creates a variable named "TOWER.i" (not "TOWER.1, TOWER.2,
..., TOWER.7)
# which will ge
You might want to give the packages animation a try.
On May 19, 2012, at 11:47 AM, c...@mail.tu-berlin.de wrote:
> Hi,
> I want to do an interactive plot in R:
> I have a time series and I can plot it in the normal way:
>
> plot(modifieddate,timeseries,type="l",xlab="Date",ylab="values", main="ti
Hello everyone,
I want to get a 1km by lkm grid raster image using my csv data. If I call
latitude=a, longitude=b and preciptation=c.
a<-(1,2,3,4,5)
b<-(6,7,8,9,10)
c<-(10,20, 30,40, 50)
Then I found an example in r help which goes like
pts = read.table("file.csv",..)
library(sp)
library(rg
Hi,
I want to do an interactive plot in R:
I have a time series and I can plot it in the normal way:
plot(modifieddate,timeseries,type="l",xlab="Date",ylab="values", main="title")
(modifieddate is the values for the date on the x axis)
The aim now is, that I want to do a Latex Presentation, whe
On Sat, May 19, 2012 at 1:18 AM, Rolf Turner wrote:
>
> I had such good luck with my previous question to r-help, (a few minutes
> ago) that I thought I would try again with the following query:
>
>> Suppose I have
>>
>> xNm <- "gamma"
>>
>> I would like to be able to do
>>
>> plot(1:10,xlab
Thank you very much!!
On May 18, 2:22 pm, David Winsemius wrote:
> On May 18, 2012, at 3:26 PM, Giggles wrote:
>
> > I am a newbie and can't figure out how to recode a numeric value. In
> > my data (pharm311), I have a column called "explain" and I need to
> > find all the 6's and change it to NA
Thanks so much! I thought R places NA for missing values. I'll have to
read up on it more. Thanks again!
On May 18, 2:23 pm, Marc Schwartz wrote:
> On May 18, 2012, at 2:26 PM, Giggles wrote:
>
> > I am a newbie and can't figure out how to recode a numeric value. In
> > my data (pharm311), I have
Dear Peter
thank you for your suggestions.
the design is balanced in terms of birds per group or sex, but not for brood.
I can't do averages because (i) siblings from a same brood are randomly
allocated to
different experimental groups, (ii) this would drastically reduce the power of
analysis.
so
On May 18, 2012, at 16:15 , David Costantini wrote:
> Sorry about that.
> Basically I have two fixed factors (experimental group and sex) and a random
> factor
> (brood). I need the random factor to control for pseudoreplication because I
> have siblings,
> which are pseudoreplicates because sh
Hi R-listers,
Q1) What is the difference between the scatterplot and plot function?
Q2) I am able to make a graph with the scatterplot function:
scatterplot(DevelopIndex ~ Veg,
+ data = Turtle,
+ xlab = "Vegetation border (m)",
+ ylab = "Embryonic developme
Hi all,
I am a beginner R user and need some help with a simple loop function.
Currently, I have seven datasets (TOWER1,TOWER2...TOWER7) that are all in
the same format (same # of col and headers). I am trying to add a new column
(factor) to each dataset that simply identifies the dataset. Ultima
JWDougherty surewest.net> writes:
> Can someone point me to an implementation of the "runs up and runs
> down" test, or does such beast exist in R? From web searches the
> "runs up and runs down" test is commonly used for testing pseudo-random
> number generators and in simulations. John C. Davi
On May 19, 2012, at 01:45 , Noah Silverman wrote:
> Hello,
>
> I need to design a fairly simple front-end for someone to use an R script
> system that I've built. My thought was to just use the text based menus
> available in the base R package, perhaps in some kind of loop.
>
> How have oth
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