Hello
I have a question on the seasonal decomposition based on Loess smoothing
(called "stl") for the R statistics package.
I am wondering how to calculate value of AIC (Akaike Information Criterion)
for the seasonal decomposition by stl in R.
Thanks,
[[alternative HTML version deleted]
Dear List,
If I build a model based on training set, and calculate the predictive AUC
on test set using that model, how should I calculate the 95%CI for this
predictive AUC using bootstrap method? The SE should be calculated on
training set or test set, or combine them together? I feel confused ab
On 13/04/2012 04:26, Suresh Kumar wrote:
Hi,
I am unable to install "robust" package (g++ compile error occurs) if the
g++ version is 4.7. However, for g++ 4.6 i am able to install. I was trying
to do this in Ubuntu 12.04.
R 2.15 itself was installed from the PPA,
https://launchpad.net/~marutte
Hi, Joseph:
What are your priorities regarding the US lobbying database?
At
"http://www.senate.gov/legislative/Public_Disclosure/LDA_reports.htm";, I
see 4 links:
* Search the Lobbying Database (LD-1, LD-2)
* Download a Lobbying Docum
Dear list
If I calculate the C-index after 10-fold cross-validation based on Cox
model, which statistic test should I used to compare two C-statistic
values.I means I use cross-validation to obtain a predictive probability for
each individual, then combine all the probabilities to calculate the
C-
Marion Wenty gmail.com> writes:
> I have got a question concerning the underlying numerical codes when
> reading an SPSS file into R.
>
> I used the package foreign and when I look at a variable I get the verbal
> codes.
>
> I would like to know how it is possible to get the underlying numeric
Hi,
I am unable to install "robust" package (g++ compile error occurs) if the
g++ version is 4.7. However, for g++ 4.6 i am able to install. I was trying
to do this in Ubuntu 12.04.
R 2.15 itself was installed from the PPA,
https://launchpad.net/~marutter/+archive/rrutter.
Is it a bug?
thanks
s
Hello:
I've been using "Rprofile.site" for several years to set the
repos environment variable as follows:
options(repos=c(CRAN='http://cran.cnr.berkeley.edu',
CRANextra='http://www.stats.ox.ac.uk/pub/RWin') )
However, R 2.15.0 is not recognizing this. Instead,
Michael originally suggested ?outer. I think that was enough in this
case (no need for mv or sapply):
wlpk3 <- outer(k3,wl,'+')
ln.phiDIC <- log(k1)+k2/wlpk3
phiDIC<- t(exp(ln.phiDIC))
colnames(phiDIC)<- stations
str(phiDIC)
Cheers
On Thu, Apr 12, 2012 at 8:58 PM, R. Michael Weylandt
wrote:
>
Hi all,
I've been using a custom summary function to optimise regression model
methods using the caret package. This has worked smoothly. I've been using
the default bootstrapping resampling method. For bagging models
(specifically randomForest in this case) caret can, in theory, uses the
out-of-b
Strange, that isn't the error I get:
> mouter(wl, k1, k2, k3, FUN = function(w, k1, k2, k3) k1 *exp(k2 / (w + k3)))
Error in FUN(X, Y, ...) : argument "k2" is missing, with no default
Still, it's a problem with my mouter() function which was only tested
on binary operators (and then only really
Dear List
Is there a package for leapfrog plotting (Hamiltonian Monte Carlo
estimation) in R? I tried the actual "LEAPFrOG" package which doesn't
actually give the plot like this one?
http://xianblog.files.wordpress.com/2010/09/hamilton.jpg
How doe one plot this in R? So, there semi-circle and
On Fri, Apr 13, 2012 at 11:37 AM, pdb wrote:
> I am running a series of scripts sequentially and they all need some global
> parameters. These will be included in a file in a known sub directory as the
> scripts themselves.
>
> The scripts need to be run by anyone without ANY editing.
>
> Question
On Apr 12, 2012, at 7:37 PM, pdb wrote:
I am running a series of scripts sequentially and they all need some
global
parameters. These will be included in a file in a known sub
directory as the
scripts themselves.
The scripts need to be run by anyone without ANY editing.
Question is:
Is t
On Apr 12, 2012, at 3:49 PM, Aye wrote:
Okay, i got this far:
f <- function(x) 0.25*x^2 + 6.47*x -32.6
g <- function(x) 0.99*x^2 -6*x -195
h <- function(x) 0.77*x^2 +14*x -495
j <- function(x) 0.001*x^2 + 65*x -785
k <- function(x) 0.9*x^2 -2*x -63
Hi everybody,
I'm learning R and statistics and wanted to use a real case scenario for my
study... however a colleague is convinced my use of the linear regression
function is incorrect.
Could you please help clarify if what I'm doing is wrong? And in particular
why is wrong?
I was thinking to
Dear Duncan,
I'm now home and have access to Windows and Mac OS X systems, but not Ubuntu.
scatter3d(prestige ~ income + education | type, data=Prestige) works perfectly
fine on both the Windows and Mac systems, as do the rgl.spheres() and
spheres3d() commands that you suggested trying.
I thin
h! thank you a lot for your effort and help.
i preferred a 3d view of the surface in order to see how well it fits the
real data (from the file). i will play around with the functions you have
mentioned and post my results or further problems. this will probably take a
few days :(
can anybody ans
highlight.js generally allows for more sophisticated highlighting. I
believe this might be the reason why people at Kaggle are looking for
it. Thanks for the pointer anyway!
On 04/12/2012 07:25 AM, Yihui Xie wrote:
There are numerous JS libraries for syntax highlighting. I have never
tried hig
Hi,
Do you know whether it is possible to use wildcards in download.file()?
For example:
url = "ftp://abc.com/*.*"; # to download all the files in the ftp folder
download.file(url,destfile=...) # does not work, any solutions?
Thanks!
JIng
__
R-help@r-
Hey all,
I am trying to generate a number of vectors with string combinations. The
below code solves my initial problem, however I would prefer not hardcoding
the positions of the 'objects' as in the future the number of 'objects'
could increase. Is there a way to loop over these objects and gener
Hi and thank you for your time.
I got this error when trying your function.
mouter(wl, k1, k2, k3, FUN = function(w, k1, k2, k3) k1 *exp(k2 / (w + k3)))
"Error in k3/(w + k3) : 'k3' is missing"
Regards,
Phil
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I am running a series of scripts sequentially and they all need some global
parameters. These will be included in a file in a known sub directory as the
scripts themselves.
The scripts need to be run by anyone without ANY editing.
Question is:
Is there a command to return the directory of the c
Hi.
Yes, that was about scatterplot.
Your suggestion is what I really want.
Works excellent!!
Thank you very much.
Your question about the values and the headers...
I'm trying to develop new clustering algorithm.
I'm changing this algorithm's parameter and trying to "tune it up" in
dependency of
Dnia czwartek, 12 kwietnia 2012 08:51:06 Michael Friendly pisze:
> The same data, with the proper citations to Michelson(1882) and
> Stigler(1977) are contained in the HistData package as data(Michelson)
> See
> library(HistData)
> example(Michelson)
That is not much of relief, given that this par
Okay, i got this far:
f <- function(x) 0.25*x^2 + 6.47*x -32.6
g <- function(x) 0.99*x^2 -6*x -195
h <- function(x) 0.77*x^2 +14*x -495
j <- function(x) 0.001*x^2 + 65*x -785
k <- function(x) 0.9*x^2 -2*x -636
plot(x, f(x), xlab="Elemente in der R
I found this...
https://stat.ethz.ch/pipermail/r-help/2009-January/184745.html
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_
Hi,
I am trying to test whether the maximum likelihood (ML) estimates of a
parameter from the the results of running 'optim', are different. After
searching the R-help archives, I have seen only 2 prior posts where a less
detailed question has been asked about "general hypothesis testing after
'opt
Hi John,
On Wed, Apr 11, 2012 at 17:07, email mail wrote:
> I have looked at the bnlearn and deal packages for infering bayesian
> network. Can anyone suggest any other suitable package for constructing
> bayesian gene regulatory network using gene expression data?
The GeneNet package from Korbi
On 12/04/2012 2:27 PM, John Fox wrote:
Dear René,
I've confirmed that the spheres aren't coloured correctly on my Ubuntu system
(the first colour is used for all of the spheres), and I know that this works
right on Windows, as you mentioned. I'm curious to try it on my Mac, but don't
have tha
Dear All
I am unhappy to report that rgl_0.92.879 gives the following error:
Error : .onLoad failed in loadNamespace() for 'rgl', details:
call: dyn.load(file, DLLpath = DLLpath, ...)
error: unable to load shared object '/Library/Frameworks/
R.framework/Versions/2.15/Resources/library/rgl/l
On Wed, 2012-03-28 at 01:43 -0700, millerjeremya wrote:
> I’m working on a canonical correspondence analysis using Vegan.
> I’m new to this. I would like to control the shapes and colors for each of
> my individual display points and can’t figure out the syntax.
This comes up so often it is /the
Hello,
Due to exploration of the JIT capabilities offered through the {compiler}
package, I came by the fact that using enableJIT(2) can *slow* the rpart
function (from the {rpart} package) by a magnitude of about 10 times.
Here is an example code to run:
library(rpart)
require(compiler)
enable
Hi, I am unable to install the package rJava. I tried doing what the output
suggests, but it doesn't help. How can I get R to find/recognize my Java
installation? I am running R-2.15.0.
waichler@snow> sudo R CMD javareconf
Java interpreter : /usr/bin/java
Java version : 1.6.0_22
Java home
May be of use too:
The R Foundation for Statistical Computing, R: Regulatory Compliance
and Validation Issues - A Guidance Document for the Use of R in
Regulated Clinical Trial Environments, August 17, 2008
[http://www.r-project.org/certification.html]
/Henrik
On Thu, Apr 12, 2012 at 1:06 PM, Th
On 04/12/2012 09:55 PM, Gavin Rudge wrote:
Hi, I've been looking at ways to make pyramid plots in R. I like the
pyramid.plot method in plotrix as it seems the simplest to use and building
them in ggplot looks a bit more code intensive than I'd like, being as I'm new
to R. This package does p
Hi,
you can use the curve() function for this. It is dedicated to plotting
functions.
Here is an example
# turn your functions into r functions
f <- function(x) 0.25 * x^2 + 6.47 * x -32.6
g <- function(x) 0.99*x^2 -6*x -195
j <- function(x) 0.77*x^2 + 14*x -495
k <- functi
All:
R is used by the NOAA/U.S. National Weather Service to generate graphics
representing real-time hydrologic ensemble (probabilistic) forecasts. Go
to: http://www.erh.noaa.gov/mmefs/ to see.
It is also used in research and development for forecast verification and
analyses for the calibration
I'm not quite sure what you are asking -- when you say an XY plot I
presume you mean a scatter plot of X against Y, but how do the values
underneath the headers play in? Do you just want different symbols?
With a little bit of data wrangling, I think this actually seems quite
well suited to the gg
You can also get the official getting started tutorial by typing
help.start() at the command prompt.
Michael
On Thu, Apr 12, 2012 at 2:52 PM, steven mosher wrote:
> Welcome to R and the list.
>
> Others may suggest books ( Nutshell was my first ) but first there are
> some things that will h
It seems that your first problem is syntax:
2x
will thrown an error, while
2*x
won't.
Google around for a good intro tutorial (there's the main one you can
access by typing help.start() and it's quite good) and these sorts of
things will be explained.
You might also want to use the curve func
Hi all,
Could you please help me? I am looking for such a function for the
multi-variate case in R...
Alternatively, is it straightforward to write such a function in R?
Thanks alot!
[[alternative HTML version deleted]]
__
R-help@r-project.o
It's hard to respond without making it seem like an advertisement for
Revolution Analytics, but helping companies and government
organizations standardize on R (specifically, Revolution R) for data
analysis is something we specialize in. The (partial) list of our
customers using Revolution R at
ht
Wrong list. Post to R-sig-mixed-models
-- Bert
On Thu, Apr 12, 2012 at 12:34 PM, Eiko Fried wrote:
> Very interesting book!
> However, it doesn't cover multivariate models (I have 9 moderately
> correlated, categorical dependent variables).
>
> Again, I'm trying to find out whether 5 time-varyin
Very interesting book!
However, it doesn't cover multivariate models (I have 9 moderately
correlated, categorical dependent variables).
Again, I'm trying to find out whether 5 time-varying variables
(dichotomous; five different life events "yes"/"no"; subjects can have
several life events at the s
Perhaps ?outer -- well, not outer directly, but a multivariate outer
-- I keep this one around for personal use:
`mouter` <- function(..., FUN = "*"){
dotArgs <- list(...)
FUN <- match.fun(FUN)
if(length(dotArgs) == 1L)
return(unlist(dotArgs))
if (length(dotArgs) == 2L)
Slightly on topic, just yesterday, the CFPB announced they'll be using
R in their work: http://blog.revolutionanalytics.com/applications/
Depending on the scale of your organization, it may not be the
open-source nature that's quite the problem of the "IT Gang" but
rather the support (or lack ther
Just a joke -- since you post through Nabble instead of being a list
subscriber, the vast majority of us didn't see your original post and
instead only saw your "cry for help"
Michael
On Thu, Apr 12, 2012 at 10:08 AM, helin_susam wrote:
> Sorry, I did not understand. What does it mean " call 999
Hi,
At the moment I am studying R at school.
But I found this site very useful to explain the plot functions to me:
http://www.harding.edu/fmccown/r/
Maybe that can help you too?
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Welcome to R and the list.
Others may suggest books ( Nutshell was my first ) but first there are
some things that will help you
both in programming and getting help on the list.
You should post executable code in your question. So, build a toy example
of the data.frame you have
and show what
Hey there,
I want to plot 5 parabola functions, which happen to be
f(x) = 0.25x² + 6,47x -32.6
g(x)=0.99x² -6x -195
j(x)= 0.77x² +14x -495
k(x)=0.001x² + 65x -785
l(x) = 0.9x² -2x -636
in the same graph. Sadly I even do not really understand how to plot just
one graph
Dear all,
I have been searching far and wide for a solution to the problem of
negative intracluster correlation in the case of a binomial response
variable (also known as under-dispersion). Prentice (1986)
(http://www.jstor.org/stable/2289219) developed an extension of the
beta-binomial model whic
Dear Terry
 here is the survreg line from which I understand that "gender" is significant
survreg(formula = Surv(dias, status) ~ trat * sexo * rep, dist = "weibull")
                  Value    Std. Error     Â
z       p
sexom           -0.2187
Sorry, I did not understand. What does it mean " call 999" ?
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R-help@r-project.org maili
Thanks to all for your help! That works!
Orange
On Sat, Apr 7, 2012 at 7:25 PM, Gabor Grothendieck
wrote:
> Yes, I had fixed that on my end but didn't notice I had copied the old
> version. I think its obvious enough that anyone will fix it
> themselves. Regards.
>
> On Sat, Apr 7, 2012 at 7:
Hi every one. I have a exponential function (3 fitting parameters) that I
would like to use to produce data (6 series) without having to use a loop.
Here
wl = seq(300,500,1)
k1 = c(1.2e-6, 4.9e-6, 9.6e-6, 2.7e-10, 6.7e-8, 7.44e-6)
k2 = c(726, 352, 128, 5232, 1538, 128)
k3 = c(-176, -224, -257, 88
Hi Gang,
I realize this post is not directly related to programing issues with R,
however, it appears this may be the best place to ask my question.
I am putting forward a request that R be considered "approved" software in
my organization. Never an easy task, this is made much more difficult
This is my wrong, I am so sorry for this. I just wanted to ask something
which I did not know. Thanks for answer.
Regards
Helin.
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Thank you very much. I started R again and loaded less libraries and it
worked! I didn't know about this problem, the next time, I'll check for
this before looking a whole afternoon for alternative methods ;).
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Hi All.
I have problem with generating series of plots. In detail:
I have file of data which I insert into dataframe:
data<-read.table("file.txt", header=TRUE, sep=" ")
Data in this file are prepared in such a way, that the header of each
column has a value of one of examined parameter - somethi
Hi,
I want to calculate pointwise mutual information between "label" 2-gram, and
words in my corpus "1-gram". Any suggestions as to how to go about it?
l =label
w = word
C = reference collection
I want to calculate following:
p(w,l| C)
p(w| C)
p(l | C)
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htt
The formula is created sepearately and data is created for the formula and
then use the modelling lm
-
Thanks in Advance
Arun
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Hi all,
I'm just getting started in R. My problem is the following:
I have a data frame (v1) with lots of production data measurements.
Each row contains a single measurement ('ARI_MIT') with a timestamp. I
want to "lump" the data by months with their mean and standard
deviation.
I have already
Hi everyone,
I read your messages and I tried some things out.
The Data2 is filled with NA.
So what I did was:
NameFile.csv$Data2[is.na(NameFile.csv$Data2)] = log2Values
And now it worked. :)
Seems like I needed to replace it, and not only write it.
Thanks.
--
View this message in con
Dear René,
I've confirmed that the spheres aren't coloured correctly on my Ubuntu system
(the first colour is used for all of the spheres), and I know that this works
right on Windows, as you mentioned. I'm curious to try it on my Mac, but don't
have that handy at the moment.
I also looked at
Hi Jokel,
On Thu, Apr 12, 2012 at 7:57 AM, Jokel Meyer wrote:
> Dear R communitiy,
>
> I am trying to use multiple functions for aggregation within a function
> call for dcast. However this seems to result in an error. Also I have not
> managed to make dcast() work with fun.aggregate=sd. Please f
Dear R-list,
I am in the process of translating a long function written in Matlab
into R (mainly because I am a big of fan of R, and folks will not
have to pay to use it :). In the translation of this function
I got stack because they use spdiags, which, as far as I can tell
it is not available i
Hi Marion,
I don't have access to SPSS, so it would be hard for me to figure this
out for you. I would think that string variables would be imported as
strings or factors even when use.value.labels is true, but can't
verify that.
Good luck,
Ista
On Thu, Apr 12, 2012 at 7:59 AM, Marion Wenty wro
Alison,
You've got two geneids with two periods (instead of just one period).
gene.list <- strsplit(as.character(Rumino_Reps_agreeWalign$geneid),"\\.")
Rumino_Reps_agreeWalign[sapply(gene.list, length)!=2, ]
geneid count_Conser count_NonCons count_ConsSubst
count_NCSubst
74
I do something similar my script is structured as follows: perhaps it will
help
library(car)
library(rgl)
library(mgcv)
scatter3d(MADep2009 ~ MADwet2009 + MedAD2009 | as.factor(VegClass), data =
SFCN,
sphere.size=1.5, surface=FALSE, parallel=FALSE, elliposiod=TRUE,
surface.col=c("green", "red", "
Is this what you mean?
x <- rnorm(12)
histogram(x)
histogram(x, scales=list(x=list(at=c(-1, 1), labels=c("minus one", "one"
On Thu, Apr 12, 2012 at 9:28 AM, carol white wrote:
> Hello,
> Is it possible to selectively display labels on a histogram?
>
> Thanks
>
> Carol
>
>[[alterna
Gavin,
Thank you for this example. I would use the as.pyramidLikert function in
the HH package.
The resulting plot is a standard lattice plot, so any fine tuning uses that
standard lattice features.
Rich
> ## install.packages("HH") ## if necessary
> library(HH)
> mydata <- cbind(mpop,fpop)[10
Hi
the solution with linear programming works very well!
Even if I take more 'realistic' matrices with dimensions of about 25x60,
the calculation of the basis goes well (if I increase the number of
iterations to 1000).
Meanwhile I also found an algorithm for an exact calculation of the extreme
ray
Dear List,
I don't get scatter3d to color the sheres according to the '|' argument.
library(car)
scatter3d(prestige ~ income + education|type, data=Prestige)
The spheres on my screen are all colored the same and they are not
conditional on Prestige$type.
On the other hand: Fit3d and Ellipse3d ar
Hi
>
> No, data labels on the histogram bars. labels = T in hist displays all
data labels.
You could find it probably quicker in documentation.
Plotting command usually creates (invisibly) the object which can be saved
and changed.
h<-hist(x)
h is list which you can use or modify
for insta
I would suggest using the XLConnect package so that you can read/write
the Excel files directly. You can read in the files to a dataframe,
make your transformations and then write the result back out to the
Excel file.
On Thu, Apr 12, 2012 at 11:29 AM, Nordlund, Dan (DSHS/RDA)
wrote:
>> -Ori
> -Original Message-
> From: r-help-boun...@r-project.org [mailto:r-help-bounces@r-
> project.org] On Behalf Of Yellow
> Sent: Thursday, April 12, 2012 2:18 AM
> To: r-help@r-project.org
> Subject: [R] How insert data to a column in existing csv file?
>
> I was working with some excel file
Dear users,
I'm quite a new french R-user, and I have a problem about doing a
correlation matrix.
I have temperature data for each weather station of my study area and for
each year (for example, a data file for the weather station N°1 for the year
2009, a data file for the N°2 for the year 2010,
No, data labels on the histogram bars. labels = T in hist displays all data
labels.
thanks
From: Petr PIKAL
Cc: "r-h...@stat.math.ethz.ch"
Sent: Thursday, April 12, 2012 4:03 PM
Subject: Re: [R] selective labels display on histogram
Hi
>
> Hello,
> Is i
Hi,
h <- "CataDog"
sub("","",h)
see http://en.wikibooks.org/wiki/R_Programming/Text_Processing for more
information.
Regards!
__
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https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www
This is the R-help mailig list, not Nabble, hence quote the original
message!
Anyway, the answer is: See ?options and its argument "nwarnings".
Uwe ligges
On 12.04.2012 14:49, helin_susam wrote:
Any help ?
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There are numerous JS libraries for syntax highlighting. I have never
tried highlight.js yet, but I wrote something for SyntaxHighlighter
which might be easily translated to highlight.js:
http://yihui.name/en/2010/09/syntaxhighlighter-brush-for-the-r-language/
Regards,
Yihui
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Phone: 5
swertie voila.fr> writes:
> I am trying to do contrasts after applying a binomial mixed effect model
> with the function lmer. I have to extract the fix effect values, but as I
> write fixef(model), I get this error message:
>
> Error in UseMethod("fixef") :
> no method for 'fixef' with objec
Hi,
> The code I have used is
>
>> summary(prefdata)
>> prefdata[prefdata>5]=NA
>> summary(prefdata)
>> prefdata2=as.matrix(prefdata[3:22])
>> stats=paf(prefdata2)
> [1] "One of your variables is a constant. Constants are disallowed as
> part of
could you provide some data / sample data you used fo
Hi
>
> Hello,
> Is it possible to selectively display labels on a histogram?
What labels?
Like that?
x<-rnorm(1)
hist(x)
hist(x, axes=F, xlab="bla", ylab="ble", main="bleble")
axis(1, at=c(-4, -1, 1, 4))
Regards
Petr
>
> Thanks
>
> Carol
>
>[[alternative HTML version deleted]]
>
Hi
>
> Any help ?
Call 999
Regards
Petr
>
> --
> View this message in context: http://r.789695.n4.nabble.com/number-of-
> warnings-tp4550325p4551760.html
> Sent from the R help mailing list archive at Nabble.com.
>
> __
> R-help@r-project.org mailin
Dear all,
This is probably more related to statistics than to [R] but I hope someone
can give me an idea how to solve it nevertheless:
Assume I have a variable y that is a function of x: y=f(x). I know the
average value of y for different intervals of x. For example, I know that
in the interval[0
Hello,
I am trying to do contrasts after applying a binomial mixed effect model
with the function lmer. I have to extract the fix effect values, but as I
write fixef(model), I get this error message:
Error in UseMethod("fixef") :
no method for 'fixef' with objects of class "mer"
Has anybody s
Any help ?
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Hello,
Is it possible to selectively display labels on a histogram?
Thanks
Carol
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Hello R users,
I am analizing survival data (mostly uncensored) and want to extract the
most out of it.
Since I have more than one factor, I?ve read that the survival regression
can help to test the interactions between factors, and then decide how to do
the comparis
On 12.04.2012 13:53, Uwe Ligges wrote:
On 12.04.2012 13:49, John S wrote:
Thanks Berend for your answer!
I read the documentation but I don’t understand filename
="Rplot%03d.tif" ?
Do you mind sending me what you tried?
This is a bug in R. I'll take a look.
I think I have a fix, will
Hi Rainer
Thanks for an alternative. For the record I tried
your latex solution on my Windows 7
\usepackage[utf8x]{inputenc}
but it failed on the Alt-248
Regards
Duncan
At 19:13 12/04/2012, you wrote:
I also had the same problem.
Being on Linux, I prefer Walmes' command line method but
The same data, with the proper citations to Michelson(1882) and
Stigler(1977) are contained in the HistData package as data(Michelson)
See
library(HistData)
example(Michelson)
On 4/11/2012 7:42 AM, Duncan Murdoch wrote:
On 12-04-11 12:43 AM, Křištof Želechovski wrote:
http://finzi.psych.upenn
Hi Duncan
Thank you for the tips
I tried
\usepackage[latin1]{inputenc}
but it still bailed up.
tried showNonASCII on the file with the ° typed
as Alt-248 (used to doing as DOS value)
becomes Alt-176 in ASCII
% 1° line
resulted in
483: % 1 line
The showNonASCII is a nifty function
Duncan
Ah.. forget it, something must have gone wrong while i was testing (probably
messed up some apply()). Seems you can just subtract the returned means - i
hope at least.
Am 12.04.2012 um 14:30 schrieb Jessica Streicher:
> Hi!
>
> I'm doing a PCA on some testdata (only 2 features) currently to s
On 12-04-12 12:13 AM, Duncan Mackay wrote:
At 12:03 12/04/2012, you wrote:
I had the same problem! So, as I'm a linux user,
I prefer use linux terminal. On terminal I type this to compile
R CMD Sweave --encoding=utf-8 myfile.Rnw
and the compilation is successful. Try to set the encoding opti
Hi, I've been looking at ways to make pyramid plots in R. I like the
pyramid.plot method in plotrix as it seems the simplest to use and building
them in ggplot looks a bit more code intensive than I'd like, being as I'm new
to R. This package does pretty much what I need it to do, however I ca
Hello.
I am running a multivariate multilevel mixed effects model, and am trying
to understand what the interaction term tells me.
A very simplified version of the model looks like this:
model <- lmer (phq ~ -1 + as.factor(index_phq) * Neuro + ( -1 +
as.factor(index_phq)|UserID), data=data)
The
>I have dataset with n variables, say n =3 x y z
>the formula should be form = x+y+z+x*x +x*y+x*z +y*y + y*z+z*z
>my code has to for loop
>Is there any way to reduce two loops
> for (i in 1:n)
> {
> for (j in i:n)
> {
>dat= cbind(dat,dat[,i]*dat[,j])
> }
> }
Yes; use
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