Hi all, I have been using ggplot for a few months and ran into this
porblem, I am trying to use ggplot in a for loop and it is not working. if
I do the following:
data=as.data.frame(cbind(rnorm(10),rnorm(10),rnorm(10)))
pp=ggplot(data, aes(x=(1:10), y=data[,1]))
pp=pp+geom_line(aes(x=
random selection of cells in raster based on distance from xy locations
Hi,
I am trying to sample a raster for random cells that occur within a
specific distance of point locations. I have successfully found multiple
ways of doing this but have memory issues with very large datasets. To
overcome
mrzung gmail.com> writes:
>
> Hi, all
>
> I am using gWidgets for making gui, and in trouble with closing gwindow.
>
> I want to close gwindow "A" by automatically when I click a button in
> gwindow "A" that loads another gwindow "B" .
>
> for example.
>
> A<-gwindow(visible=FALSE)
> open<-g
Here is your example. The table you displayed in gigawiz ignored the
two-way factor structure
and interpreted the data as a single factor with 6 levels. I created the
interaction of
a and b to get that behavior.
## your example, with data stored in a data.frame
tmp <- data.frame(x=c(76, 84, 78,
Hi, all
I am using gWidgets for making gui, and in trouble with closing gwindow.
I want to close gwindow "A" by automatically when I click a button in
gwindow "A" that loads another gwindow "B" .
for example.
A<-gwindow(visible=FALSE)
open<-gbutton(cont=A,"open new
window",handler=function(h,..
Authenticated access is sometimes a little harder than a simple
download -- the RCurl package provides tools that will be helpful, but
you'll need to tailor things to the sort of authentication used on the
other end. getURL iprovides one example of password authentication in
the examples. If you ar
Give a reproducible example (use dput()) and someone will be able to
help you. Otherwise, we're just guessing at what your data looks like.
Also, ?plot or ?matplot might help. Particularly, see the second
example for matplot. It might be what you are looking for.
A lesson of all this is though, p
You should have the following statement as part of your startup for R:
options(error=utils::recover)
When an error occurs, you will be at the stack frame where is happens
and you can examine the values of the variables that you are using and
this should help a lot in tracking down your problem.
On 2012-04-04 14:25, z2.0 wrote:
json_dir is a list of JSON lists mapping lat/long route points between
locations using CloudMade's API.
post_url is the URL of the HTTP request
for (n in json_dir) {
i = i + 1
if (typeof(json_dir[[i]]) != "NULL") {
if
On 12-04-04 5:15 PM, Sam Steingold wrote:
* Duncan Murdoch [2012-04-04 17:00:32 -0400]:
There's no warning when you mask a function with a non-function at top
level, and little need for one, because R does the right search based on
the fact that you're making a function call:
c
[1] 1
c(1,2)
Thank you Jeff for your input. I did realize just after posting the question
that the summary fn returns an object whose "slots" can be read and that the
slot containing the coefficient information is a matrix. Here is how I got the
desired results through the following code in "mypanel" functi
Hi Ted,
On 2012-04-04 15:06, Ted Harding wrote:
Greetings!
I want to have the coefficients that R uses in shapiro.test()
for the Shapiro-Wilk test for a prticular sample size, i.e.
the a[i] in
W = Sum(a[i]*x[i])/(Sum(x[i] - mean(x))^2)
(where the x[i] are sorted). Two questions:
Q1:
Is the
Thanks, Chuck. That looks about right.
And I would have provided repro code, but I was forced to write it in
Matlab on account of corporate rules, and haven't translated to R yet.
Carl Witthoft writes:
> Hi,
> While playing with quantile-quantile plots, I wrote up some code which
> plots s
?summary.lm
-Roy
On Apr 4, 2012, at 4:47 PM, John Sorkin wrote:
> Please forgive my re-sending this question. I did not see any replies from my
> prior post. My apologies if I missed something.
>
> Is the sigma from a lm, i.e.
>
> fit1 <- lm(y~x)
> summary(fit1)
> summary(fit1)$sigma
>
> the
Please forgive my re-sending this question. I did not see any replies from my
prior post. My apologies if I missed something.
I would like to have a figure with two graphs. This is easily accomplished
using mfcol:
oldpar <- par(mfcol=c(1,2))
plot(x,y)
plot(z,x)
par(oldpar)
I run into trouble
Please forgive my re-sending this question. I did not see any replies from my
prior post. My apologies if I missed something.
Is the sigma from a lm, i.e.
fit1 <- lm(y~x)
summary(fit1)
summary(fit1)$sigma
the RMSE (root mean square error)
Thanks,
John
John David Sorkin M.D., Ph.D.
Chief, Bios
Thanks again Michael,
I finally had a little time today to look ar the zoo documentation.
But I do not understand R and am incompetent to figure out how to
use zoo to get the quick plot of unequal interval time series
presented in the first posting (yes it's equal interval,
but pretend it is not).
take a look at ?paste
paste(yourmatrix, sep='\t', collapse='')
On Wed, Apr 4, 2012 at 2:58 PM, kickout wrote:
> Having problems with the write.table function. I can write a tab delimited
> file just fine, but for each line in my matrix its inputs a carriage return
> when i dont want it to.
>
> F
On Apr 4, 2012, at 5:58 PM, kickout wrote:
Having problems with the write.table function. I can write a tab
delimited
file just fine, but for each line in my matrix its inputs a carriage
return
when i dont want it to.
For example my matrix might be:
ID V1 V2 V3
FARY1004 1 2 3
FARY2067 2 3
Having problems with the write.table function. I can write a tab delimited
file just fine, but for each line in my matrix its inputs a carriage return
when i dont want it to.
For example my matrix might be:
ID V1 V2 V3
FARY1004 1 2 3
FARY2067 2 3 1
FARY4587 2 2 2
And I want the written File to b
On Apr 4, 2012, at 6:10 PM, Sarah Goslee wrote:
I just tried it, because I'm curious that way.
If I search for
"load functions into R"
I get only this thread.
If I search for
load functions into R
(no quotes), I get the referenced discussion from Henrik Bengtsson:
ttps://stat.ethz.ch/pipermai
Are you aware that the summary function normally returns a data value that you
can extract values from and format to your hearts desire?
try
str(coef(summary(tmp)))
and read ?mle-class
(and try to provide a reproducible example next time)
---
On 05/04/12 10:10, Sarah Goslee wrote:
I just tried it, because I'm curious that way.
If I search for
"load functions into R"
I get only this thread.
If I search for
load functions into R
(no quotes), I get the referenced discussion from Henrik Bengtsson:
ttps://stat.ethz.ch/pipermail/r-help/20
I just tried it, because I'm curious that way.
If I search for
"load functions into R"
I get only this thread.
If I search for
load functions into R
(no quotes), I get the referenced discussion from Henrik Bengtsson:
ttps://stat.ethz.ch/pipermail/r-help/2008-September/173606.html
As in so many a
Greetings!
I want to have the coefficients that R uses in shapiro.test()
for the Shapiro-Wilk test for a prticular sample size, i.e.
the a[i] in
W = Sum(a[i]*x[i])/(Sum(x[i] - mean(x))^2)
(where the x[i] are sorted). Two questions:
Q1:
Is there a readymade R function from which I can extract t
On 04/04/12 22:32, Bert Gunter wrote:
Rolf:
Google on "load functions into R."
A post referencing source() (from Henrik Bengtsson is the first hit.
Tried that just now. The only hits I got were to *your* post; no hits
on any post from Henrik Bengtsson.
These things are never as easy and str
Hello,
Roslina Zakaria wrote
>
> HI,
>
>
>
> I would like to extract data in a specific way. For example, the rainfall
> data
>
>
>
> 0,0,1.5,0,0, 3,1,2.5,0,0,0,0, 2.3,0,0,0, 2.1,1.4,0,0,0, 3,2,1,0,0,0...
>
>
>
> data_1: 1.5, 2.3 ( a single nonzero data between zeros data
Have you looked at plyr?
Generally, ldply works well for this sort of thing.
--
View this message in context:
http://r.789695.n4.nabble.com/convert-a-list-to-a-data-frame-tp4532206p4533257.html
Sent from the R help mailing list archive at Nabble.com.
I am new to R and have been spinning my wheels on the following.
*Issue:* I have a membership to a website, and I want to grab data from
the website using download.file().
download.file(url, destfile, method, quiet = T, mode = "w", cacheOK = TRUE)
The R Documentation is helpful. However, I have
json_dir is a list of JSON lists mapping lat/long route points between
locations using CloudMade's API.
post_url is the URL of the HTTP request
for (n in json_dir) {
i = i + 1
if (typeof(json_dir[[i]]) != "NULL") {
if (i == 1) {
dat_add
Hello,
>
> The by function does not seem to allow two variables in the Indices
> argument:
>
Yes it does, but you must use a list of variables.
(Read the help for 'by': INDICESa factor or a list of factors, each of
length nrow(data).)
mydata <- read.table(text="
C1 C2 C3
1 x 1
1 x 2
1
you need to subtract the length of gap in y-axis.
Good luck!
--
View this message in context:
http://r.789695.n4.nabble.com/Plotting-lines-and-points-on-the-second-plot-when-using-gap-plot-in-plotrix-tp804226p4533129.html
Sent from the R help mailing list archive at Nabble.com.
_
Hi Peter,
Thanks! This was very helpful and worked perfectly.
Naomi
On Apr 4, 2012, at 4:52 PM, Peter Alspach wrote:
Tena koe Naomi
There are lots of ways to do this. Here are a couple (note I've
made a minor modification to your example):
naomi
C1 C2 C3
1 1 x 1
2 1 x 2
3 1 y
On Apr 4, 2012, at 4:54 PM, Sam Steingold wrote:
* Sam Steingold [2012-04-04 14:58:15 -0400]:
1. the strings I replaced with and are very long; I wish I
could replace them in the object all, not just in text
i.e., I have a long list with elements with long names.
how do I replace
On Thu, Apr 5, 2012 at 8:24 AM, Marie-Pierre Sylvestre
wrote:
> Hello everyone,
> I want to do a meta-analysis of case-control studies on which an OR was
> computed based on a continuous exposure. I have found several several
> packages (metafor, rmeta, meta) but unless I misunderstood their main
> * Duncan Murdoch [2012-04-04 17:00:32 -0400]:
>
> There's no warning when you mask a function with a non-function at top
> level, and little need for one, because R does the right search based on
> the fact that you're making a function call:
>
>> c
> [1] 1
>> c(1,2)
> [1] 1 2
why then am I get
> * Duncan Murdoch [2012-04-04 17:00:32 -0400]:
>
> There's no warning when you mask a function with a non-function at top
> level, and little need for one, because R does the right search based on
> the fact that you're making a function call:
>
>> c
> [1] 1
>> c(1,2)
> [1] 1 2
why then am I get
HI,
I would like to extract data in a specific way. For example, the rainfall data
0,0,1.5,0,0, 3,1,2.5,0,0,0,0, 2.3,0,0,0, 2.1,1.4,0,0,0, 3,2,1,0,0,0...
data_1: 1.5, 2.3 ( a single nonzero data between zeros data)
data_2: 3.1, 2.5, 2.1,1.4 ( two nonzero data between zero
HI,
I would like to extract data in a specific way. For example, the rainfall data
0,0,1.5,0,0, 3,1,2.5,0,0,0,0, 2.3,0,0,0, 2.1,1.4,0,0,0, 3,2,1,0,0,0...
data_1: 1.5, 2.3 ( a single nonzero data between zeros data)
data_2: 3.1, 2.5, 2.1,1.4 ( two nonzero data between zeros data)
On 12-04-04 4:52 PM, Sam Steingold wrote:
Since R has the same namespace for functions and variables,
c<- 1
kills the global function, which can be restored by
c<- get("c",mode="function")
Is there a way to prevent R from overriding globals
or at least warning when I do that
or at least warn
> * Sam Steingold [2012-04-04 14:58:15 -0400]:
>
> 1. the strings I replaced with and are very long; I wish I
> could replace them in the object all, not just in text
i.e., I have a long list with elements with long names.
how do I replace all these long names with something shorter?
ro
Since R has the same namespace for functions and variables,
> c <- 1
kills the global function, which can be restored by
> c <- get("c",mode="function")
Is there a way to prevent R from overriding globals
or at least warning when I do that
or at least warning when I replace a functional value with
Tena koe Naomi
There are lots of ways to do this. Here are a couple (note I've made a minor
modification to your example):
> naomi
C1 C2 C3
1 1 x 1
2 1 x 2
3 1 y 1
4 1 y 2
5 2 x 1
6 2 x 2
7 2 x 3
8 2 y 1
9 2 y 2
> tapply(naomi[,3], naomi[,1:2], function(x) x[length
Hello everyone,
I want to do a meta-analysis of case-control studies on which an OR was
computed based on a continuous exposure. I have found several several
packages (metafor, rmeta, meta) but unless I misunderstood their main
functions, it seems to me that they focus on two-group comparisons (bi
Hello,
I am relatively new to R, and I am trying to select the last
observation within a group, where the group is defined by two
variables. One of the variables is a date.
In the below example, C3 varies within C2, which varies within C1. I
need to select the last observation in C3 for 4
DEADLINE FAST APPROACHING – 8th Annual International R User Conference
useR! 2012, Nashville, Tennessee USA
Registration Deadlines:
Early Registration: Passed
Regular Registration: Mar 1- May 12
Late Registration: May 13 – June 4
On-Site Registration: June 12 – June 15
Please note: Nashville is
Herik's suggestion is an absolutely good practice which guarantees the
device is always closed. That is what I did in the knitr package, so
you can probably take a look at http://yihui.name/knitr/
Regards,
Yihui
--
Yihui Xie
Phone: 515-294-2465 Web: http://yihui.name
Department of Statistics, Iow
Thanks for the reply, Henrik. Process Explorer still shows the file
handle as being open, but R only shows the following:
> showConnections(all=TRUE)
description class mode text isopen can read can write
0 "stdin" "terminal" "r" "text" "opened" "yes""no"
1 "stdout""termina
See ?closeAllConnections
Suggestion to the maintainer of Sweave: "atomify" the figure
generation, e.g. use { pdf(); on.exit(dev.off()); {...}; } or similar,
instead of { pdf(); {...}; dev.off(); } possibly by leaving a copy of
the fault figure file for troubleshooting.
/Henrik
On Wed, Apr 4, 201
Hi all,
I am constructing a likelihood involving the following
lbeta(j + a, k - j + b)
where j,k are constants and a and b are parameters (>0).
While doing the optimization, the error sometimes occurs,
In lbeta(j + a, k - j + b) : underflow occurred in 'lgammacor'
Is there a way to avoid it?
Hello Folks,
When I run the document below through sweave, rgui.exe/rsession.exe
leaves a file handle open to the sweave-001.pdf graphic (as verified by
process explorer). Pdflatex.exe then crashes (with a Permission Denied
error) because the graphic file is locked.
This only seems to happen whe
I suppose I'll just report a LC10 using the dose.p function in the package
MASS using my glm fitted logistic regression on binomial data. Thanks
everyone for ideas & input! The LOEC seems to be a flawed
calculation...I'll research it. Again, thanks all!
On Mon, Apr 2, 2012 at 2:45 PM, Danielle
Thanks for your reply!
1. the strings I replaced with and are very long; I wish I
could replace them in the object all, not just in text
2. `all` is the result of
as.data.frame(do.call("rbind",l),stringsAsFactors = FALSE)
3. I get my data frame as
fr <- data.frame(audience =
Thanks everyone for the advice, you raise interesting points. Maybe the
best thing for me to do is do an ANOVA in R with binomial data (if
possible) and find the lowest dose that gives a significant difference from
the controls.
On Mon, Apr 2, 2012 at 2:45 PM, Danielle Duncan wrote:
> Hello, I us
> -Original Message-
> From: r-help-boun...@r-project.org
> [mailto:r-help-boun...@r-project.org] On Behalf Of Sam Steingold
>
> plot.glm <- function (x, y, file = NULL, xlab =
> deparse(substitute(x)),
> ylab = deparse(substitute(y)), main = NULL) {
> m <- glm(
> From: r-help-boun...@r-project.org
> [mailto:r-help-boun...@r-project.org] On Behalf Of Saruman
>
> I dont see how this answered the original question of the poster.
>
> He was quite clear: the value of the predictions coming out
> of RF do not
> match what comes out of the predict function u
Can't you just combine your matrices into a single matrix: rbind() or
cbind() should do the job.
Michael
On Wed, Apr 4, 2012 at 12:24 PM, uday wrote:
> Hi Liviu ,
> now I can see that function but the problem is that its only applicable for
> single data frame. as I wrote in my first post that I
Greetings,
I wish to conduct a meta-analysis for which the outcome is a continuous
variable measured on the same individuals before and after an intervention.
Hence, the comparison is not made between two groups, but within groups, at
diffrent times.
Each study reports the mean outcome and S
Hello,
uday wrote
>
> Hi Liviu ,
> now I can see that function but the problem is that its only applicable
> for single data frame. as I wrote in my first post that I got 2 different
> matrix with same dimensions ( 3x 12 here in example) , so if I plot normal
> plot using plot function
> plot(a
Okay, will do. Thanks for all the handy advice Gabor. Ugh, it's such a stupid
bug once I actually know what is going on. I need to go over my Unix
date/time format specifiers, and I'll probably use the rep function to
simplify and reducing the amount of code. A lot of that is definitely new to
me.
Hi Liviu ,
now I can see that function but the problem is that its only applicable for
single data frame. as I wrote in my first post that I got 2 different matrix
with same dimensions ( 3x 12 here in example) , so if I plot normal plot
using plot function
plot(ak[1,],pre[1,],type="l")
lines(ak[2,
Hi,
First, thank you to Duncan Mackay for getting me started processing dates
with R. Unfortunately, I need to do a little more than I initially expected.
I have 5K lines of data that look like this:
ID AREA DATE
0001 Center 2010-10-15
0002 Center 2010-01-02
0003 NorthWest
Hi,
I am using power.law.fit to get an mle-class object in tmp and print
summary(tmp), coef(tmp) and logLik(tmp). I wanted to print the std. error for
alpha separately as I want to show these values concisely in a graph legend.
coef(summary(tmp)) displays the alpha and std. error jointly, while
Bob O'Hara gmail.com> writes:
>
> On 4 April 2012 05:35, Jack Tanner hotmail.com> wrote:
>
> > samplesBgr("beta") # crash
> > samplesBgr("beta", plot=FALSE) # also crash
> >
> > Have you plotted your histories? I haven't used samplesBgr() much, so I
> don't know how stable it is (although I do
My $.01 contribution without having read the complete thread:
Some other process/service is locking your file/directory. There are
a few Windows tools out there helping your to narrow down exactly
which, e.g.
http://www.guidingtech.com/10175/tools-to-delete-locked-files-in-windows/
/Henrik
On 2012-04-03 20:03, Rmh wrote:
yes. See ?glht in the multcomp package, and the examples using glht in ?MMC in
the HH package.
Sent from my iPhone
Thank you very much for the clues. However, I can't figure out how to
construct the linfct in glht.
I also tried to inverse the computation b
On 03.04.2012 19:43, Drew Tyre wrote:
A final followup. I have identified a rather extreme workaround. The
problem arises when the function utils:::unpackPkgZip uses file.rename(...)
to move the unzipped binary package from the temporary directory that it
was unpacked into into the proper direc
??? What is a?
?str
str(a)
?do.call
On Wed, Apr 4, 2012 at 9:34 AM, Sam Steingold wrote:
> sorry, google does give a good start.
>
>> Google on "R convert list to data frame".
>
> as.data.frame(do.call("rbind",a))
>
> returns an object which I don't understand.
>> summary(f)
> name.Length
On Wed, Apr 4, 2012 at 10:12 AM, Petr Savicky wrote:
> On Wed, Apr 04, 2012 at 01:32:10PM +0200, paladini wrote:
> Var1 <- c("(1,2)", "(7,8)", "(4,7)")
> Var2 <- c("(1,5)", "(3,88)", "(12,4)")
> Var3 <- c("(4,2)", "(6,5)", "(4,4)")
> DF <- data.frame(Var1, Var2, Var3, stringsAsFactors=FALSE)
sorry, google does give a good start.
> Google on "R convert list to data frame".
as.data.frame(do.call("rbind",a))
returns an object which I don't understand.
> summary(f)
name.Length name.Class name.Modestatus
1 -none- characterLength:4445
1
How are you calculating the correlations? That may be part of the
problem, when you categorize a continuous variable you get a factor
whose internal representation is a set of integers. If you try to get
a correlation with that variable it will not be the polychoric
correlation.
Also do you need
On Wed, Apr 4, 2012 at 6:05 AM, David Winsemius wrote:
>
> On Apr 3, 2012, at 11:16 PM, David Lyon wrote:
>
>> Sorry that didnt work for me, any ideas?
>
>
> You _could_ indicate which package the image.plot function comes from. You
> _could_ include dput on a sufficient segment of `data1` to offe
Dear Sir,
I saw a question from a member in 2007 asking for regime switching model
and I am looking for the same kind of model.
I also saw a "project" named RSNL but I don't know if this one is
available and if we can have access to the code to change things if
needed... actually I used to buil
Carl Witthoft writes:
> Hi,
> While playing with quantile-quantile plots, I wrote up some code which
> plots something strangely different. Here's the pseudocode:
>
> testhist <- hist(sample_data)
> refhist <- hist(rnorm(n, mean=0,sd=1)) # for some large-ish n
> cumtest <- cumsum(testhist)
> cu
On Wed, Apr 04, 2012 at 01:32:10PM +0200, paladini wrote:
> Hello,
> I want to do a cluster analysis with my data. The problem is, that the
> variables dont't consist of single value but the entries are pairs of
> values.
> That lokks like this:
>
>
> Variable 1:Variable2: Variable3:
On Tue, Apr 3, 2012 at 6:22 PM, Peter Ehlers wrote:
> On 2012-04-03 15:49, ilai wrote:
>>
>> Try to plot the points first followed by vis.gam(...,type='contour',
>> color='bw', add=T) instead of vis.gam followed by points.
>>
>> HTH
>
>
> Or, if vis.gam gives you default scales that you wish to pr
Try
A[[1]] <- NA
(It is of course up to you to do the tests, presumably using if(), to
decide when to assign NA to the list element.)
-Don
--
Don MacQueen
Lawrence Livermore National Laboratory
7000 East Ave., L-627
Livermore, CA 94550
925-423-1062
On 3/31/12 7:53 PM, "michaelyb" wrot
You can create distance matrices for each Variable, square them, sum them,
and take the square root. As for getting the data into a data frame, the
simplest would be to enter the three variables into six columns like the
following:
data
[,1] [,2] [,3] [,4] [,5] [,6]
[1,]1215
On Wed, Apr 4, 2012 at 5:04 PM, uday wrote:
> Hi Liviu ,
> thanks for post , but I could not find findFn('spaghetti') , I can see the
> following functions in sos package
> Extract.findFn
> findFn
>
After installing 'sos', use the 'findFn()' function. For example, run
findFn('spaghetti')
See the
Hi Liviu ,
thanks for post , but I could not find findFn('spaghetti') , I can see the
following functions in sos package
Extract.findFn
findFn
grepFn
hits
installPackages
PackageSum2
PackageSummary
print.findFn
sortFindFn
summary.findFn
unionFindFn
writeFindFn2xls
--
View this messag
On Apr 4, 2012, at 11:30 AM, R. Michael Weylandt > wrote:
I'm not sure what your definition of easier would be, but there are
some style things you might want to be aware of:
I) the name is likely to hit up against the S3 generic plot() when
applied to a glm object. This might lead to str
I'd like to make the distinction between the purpose of factors, i.e.,
what they are intended for, and how that purpose is accomplished.
Their purpose is for use in statistical models. The simplest example is
analysis of variance, where predictors are commonly referred to as
factors. Factors in R
I'm not sure what your definition of easier would be, but there are some style
things you might want to be aware of:
I) the name is likely to hit up against the S3 generic plot() when applied to a
glm object. This might lead to strange bugs at some point.
II) you can test !is.null once and use
Please first search yourself before posting.
Google on "R convert list to data frame".
-- Bert
On Wed, Apr 4, 2012 at 8:11 AM, Sam Steingold wrote:
> I have a huge list (returned by fromJSON) with elements like this:
>
> $`zz/3260`
> $`zz/3260`$name
> [1] "myname"
>
> $`zz/3260`$status
> [1] "a
I am sure a common need is to plot a scatterplot with some fitted
line(s) and maybe save to a file.
I have this:
plot.glm <- function (x, y, file = NULL, xlab = deparse(substitute(x)),
ylab = deparse(substitute(y)), main = NULL) {
m <- glm(y ~ x)
if (!is.null(file))
p
I have a huge list (returned by fromJSON) with elements like this:
$`zz/3260`
$`zz/3260`$name
[1] "myname"
$`zz/3260`$status
[1] "active"
$`zz/3260`$vectors
$`zz/3260`$vectors$`vector/241`
$`zz/3260`$vectors$`vector/241`$channel
[1] "channel/300"
$`zz/3260`$vectors$`vector/241`$targets
$`zz/326
On Wed, Apr 4, 2012 at 4:22 PM, uday wrote:
> I would like to plat some spaghetti plots from my data , ma data is as
>
See:
require(sos)
findFn('spaghetti')
Liviu
> follows
> ak[1:3,]
> [,1] [,2] [,3] [,4] [,5] [,6] [,7]
> [,8] [,9]
> [1,] 0.3211745
I would like to plat some spaghetti plots from my data , ma data is as
follows
ak[1:3,]
[,1] [,2] [,3] [,4] [,5] [,6] [,7]
[,8] [,9]
[1,] 0.3211745 0.4132568 0.5649930 0.6920562 0.7760113 0.8118568 0.8609301
0.9088819 0.9326736
[2,] 0.3159234 0.407
Dear all,
I have a large dataset of randomly generated weighed sample for which I
wish to compute a kernel density estimate.
I have used the "np" package successfully for smaller datasets, however
for the larger ones, they take too long when
using the cross validation options for bandwidth sele
On Apr 4, 2012, at 8:19 AM, Petr PIKAL wrote:
Hi
Dear Petr,
thanks for taking your time.
For this input, the first element should be selected since there are
more
than 3 more dates within one year (basically, all other dates are
within
one year) and at least one of them is more than
Found solution.
I've changed the library and functions to open and read sockets.
Using base package I wrote:
msg3<-"function=subscribe|item=MI.EQCON.1|schema=last_price;ask;bid"
msg4<-"function=unsubscribe"
#open socket connection
socketPointer<-socketConnection('localhost', port=5333, server=FAL
Hi there,
do you know if there is a package that fits spatio temporal autoregressive
models in R?
thanks
vasilis
--
View this message in context:
http://r.789695.n4.nabble.com/STAR-Spatio-Temporal-AutoRegressive-models-tp4531793p4531793.html
Sent from the R help mailing list archive at Nabble.com
On Wed, Apr 4, 2012 at 1:47 AM, knavero wrote:
> Here's a case where it doesn't work. Again, the problem is that when I use
> the rbind or concatenate functions, the 2012 data set seems to go ahead of
> the 2010 and 2011 portions of the data set. The problem seems dependent on
> the text files I r
No problem -- best of luck with it: the zoo package is one of the best
documentation-wise and I'd advise you to look at the available
vignettes when you have time.
Vignettes are extended documentation included in some packages that
give a more systematic presentation than can be given in the help
Make that
bmd(fit, 0.01)
in my previous post.
Jarno
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PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-con
Hello,
I want to do a cluster analysis with my data. The problem is, that the
variables dont't consist of single value but the entries are pairs of
values.
That lokks like this:
Variable 1:Variable2: Variable3: ...
(1,2) (1,5) (4,2)
(7,8) (3,88)
Dear Danielle,
At least in industrial toxicology (my original background) the recent
tendency has been to use benchmark dose (BSD) approach instead of NOEL
or NOAEL approach due to various problems with the definition and
estimation of NO(A)EL. In R this can be achieved using the packages
drc and
On Apr 3, 2012, at 9:25 PM, Melrose2012 wrote:
I am trying to plot the logistic regression of a dataset (# of
living flies
vs days the flies are alive) and then fit a best-fit line to this
data.
Here is my code:
plot(fflies$living~fflies$day,xlab="Number of Days",ylab="Number of
Fruit
F
Hi
>
> Dear Petr,
>
> thanks for taking your time.
>
> For this input, the first element should be selected since there are
more
> than 3 more dates within one year (basically, all other dates are within
> one year) and at least one of them is more than 3 month later.
>
> In the meantime,
On 12-04-03 12:25 PM, Marc Girondot wrote:
Indeed I get this error message when I install the library using R CMD
INSTALL but not within the GUI (in MacOsX). Good to know that R CMD
INSTALL is more verbose and permits to track bug.
I followed up in R-sig-mac, and it turns out the reason you did
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