No, the axis can be ticked anywhere you wish:
plot(1:20, xaxt = "n")
axis(1, at = seq(1, 20, by = 2), label = paste(seq(1, 20, by = 2), "h"))
Michael
On Sat, Mar 17, 2012 at 11:00 PM, Jie Tang wrote:
> I have found that the dimension number of label must be equal with the
> dimension of the pl
I have found that the dimension number of label must be equal with the
dimension of the plot data by your this method.
if we have two data in every hour,it seems can not show the correct
tickment?
.plot(1:20, xaxt = "n")
axis(1, at = 1:10, label = paste(1:10, "h", sep = "")) # Happy axis!
2012/
On 2012-03-15 19:43, Aparna Sampath wrote:
Hi Sarah Goslee
Thanking you for replying to my doubt.
I downloaded the multtest package from CRAN and also went through the
package specific PDF file, they have given a list of functions which
includes the mt.transformV, mt.checkothers etc, that I am
Dear memberships,
I'm trying to estimate the following multivariate local regression model using
the "locfit" package:
BMI=m1(RCC)+m2(WCC)
where (m1) and (m2) are unknown smooth functions.
My problem is that once I get the regression done I cannot get the fitted
values of each of this
How about this --?
##Assumes you have read your data into data frame "Msg17"
## Capture unique values from data file's Column 3
Col3 <- unique(Msg17$V3)
#Captures length of the unique value vector
LCol3 <- length(Col3)
## Loop to sequentially select rows with the unique Col3 values
for (i in 1:
Dear all,
I use the function ctree() from the party library to calculate
classification tree models.
I want to validate models by 10-fold cross validation and estimate
mean and standard deviation of correct classification rates (CCR) from
the10 resulting confusion matrices.
So far I use the “write
Many Many thanks for your responses
--
View this message in context:
http://r.789695.n4.nabble.com/memory-i-am-getting-mad-in-reading-climate-data-tp4480671p4481296.html
Sent from the R help mailing list archive at Nabble.com.
__
R-help@r-project.org m
> One difficulty in getting the help pages to look beautiful is that the
> original input is so inconsistent, and package authors (naturally) get upset
> when CRAN starts rejecting packages because of errors that used to be
> ignored. The current output is definitely a compromise aimed at making m
On Mar 17, 2012, at 3:22 PM, Diann Prosser wrote:
Thank you for that explanation and solution David.
As a follow-up to ifelse working on vectors, earlier I tried to coerce
(?correct term?) the matrix into a vector but I still received the
same
result.
You can certainly "coerce" a matrix t
Slight correction to David's answer. See inline below.
On 2012-03-17 11:49, David Winsemius wrote:
On Mar 17, 2012, at 2:36 PM, Diann Prosser wrote:
Hi All,
I want to draw samples (n=4) from one of 2 triangular distributions
for
each value in a matrix. I am using an ifelse statement to try
Hi All:
> Every system has limits. If you have lots of money, then invest in a
> 64-bit system with 100GB of real memory and you probably won't hit its
> limits for a while. Otherwise, look at taking incremental steps and
> possibly determining if you can partition the data. You might
> consid
R> tmp <- tempdir()
R> dir.create(file.path(tmp, "a space"))
R> setwd(file.path(tmp, "a space"))
R> getwd()
[1] "/private/var/folders/ss/9z_gwf2j5bbbrhnv67_gh770gp/T/Rtmpg1MLIT/a
space"
On Sat, Mar 17, 2012 at 8:08 AM, David Winsemius wrote:
>
> On Mar 17, 2012, at 3:43 AM, André Smolarz wro
Another suggestion is to start with a subset of the data file to see
how much memory is required for your processing. One of the
misconceptions is that "memory is free". People think that with
virtual memory and other such tools, that there is no restriction on
what you can do. Instead of starti
On 17.03.2012 19:27, David Winsemius wrote:
On Mar 17, 2012, at 10:33 AM, Amen wrote:
I faced this problem when typing:
temperature <- get.var.ncdf( ex.nc, 'Temperature' )
*unable to allocate a vector of size 2.8 GB*
Read the R-Win-FAQ
>
By the way my computer memory is 4G and the ori
dput() is a way to print out your data in a covenient format for others to read
it into an R session. It has nothing to do with graphing.
You use the command dput(myfile) to output a data object or perhaps
dput(head(myfile, 10) to output a subset of your file.
Copy and paste into your email
Thank you for that explanation and solution David.
As a follow-up to ifelse working on vectors, earlier I tried to coerce
(?correct term?) the matrix into a vector but I still received the same
result. Should the following work, or does as.vector not work that way,
even though vect now prints as
I've figured this out, and am posting a solution below, in case it's of use to
others. Thanks.
## test with raw
library(inline)
code <- '
unsigned char *bPtr = RAW(AS_RAW(b));
Rprintf("inside f(), b is 0X%02x\\n", *bPtr);
return(R_NilValue);'
f <- cfunction(sig=signature(b="raw"),
On Mar 17, 2012, at 2:36 PM, Diann Prosser wrote:
Hi All,
I want to draw samples (n=4) from one of 2 triangular distributions
for
each value in a matrix. I am using an ifelse statement to try to
define
which distribution to draw from.
From the output, I can see that the ifelse statement
Hi All,
I want to draw samples (n=4) from one of 2 triangular distributions for
each value in a matrix. I am using an ifelse statement to try to define
which distribution to draw from.
>From the output, I can see that the ifelse statement is choosing the correct
distribution, however, my n=4 si
I don't know, see if this helps.
http://askubuntu.com/questions/53146/how-do-i-get-add-apt-repository-to-work-through-a-proxy
--
View this message in context:
http://r.789695.n4.nabble.com/Apt-get-tp4453839p4480997.html
Sent from the R help mailing list archive at Nabble.com.
__
On Mar 17, 2012, at 10:33 AM, Amen wrote:
I faced this problem when typing:
temperature <- get.var.ncdf( ex.nc, 'Temperature' )
*unable to allocate a vector of size 2.8 GB*
Read the R-Win-FAQ
By the way my computer memory is 4G and the original size of the
file is
1.4G,netcdf file
I
On Mar 17, 2012, at 10:17 AM, Jie Tang wrote:
hi
I plot a series of observation data every minutes in a day as the
attachment below
plot(wnd,type='l',lty=1,col='red',lwd=1,xlab=xxlab,ylab=yylab,ylim=YY)
In the figure, the x-axis tickment is the number of data How can I
change
it
fore exam
Thanks. .Call is better. But how do I get the actual value of the byte (0F)?
(Updated code below. I does not compile if I use as_RAW(*b), so I suppose
that's not the method I should use.)
## test with raw
library(inline)
code <- 'Rprintf("inside f(), b is 0X%x (compare %X%x)\\n", AS_RAW(b),
On 17 March 2012 at 14:34, Dan Kelley wrote:
| I am having trouble handing "raw" data to a C function, using "cfunction", as
demonstrated in the function and output pasted below. Can anyone suggest what
I'm doing incorrectly? Thanks. Dan Kelley [Dalhousie University].
Don't use the .C conven
I am having trouble handing "raw" data to a C function, using "cfunction", as
demonstrated in the function and output pasted below. Can anyone suggest what
I'm doing incorrectly? Thanks. Dan Kelley [Dalhousie University].
1. TEST FILE
library(inline)
code <- 'Rprintf("inside f(), b is 0X%x\
Hi!
I constructed a model where most of the variables are linearly related to
each other. However, the dependent variable is dichotomous, which means I
should not try to fit a linear relationship between the other variables,
which are continuos, and this variable. I'm wondering how I would have to
Thanks for taking the time to post the solution to your loop to matrix
dilemma. I had a similar problem and your post helped me quickly move
through this challenge. Thanks again.
--
View this message in context:
http://r.789695.n4.nabble.com/Storing-output-vector-form-a-loop-as-a-matrix-tp827822
I am getting theses values when I disply my ncdf file
1e+34 -1e+34 -1e+34 -1e+34 -1e+34 -1e+34 -1e+34 -1e+34
[227,] -1e+34 -1e+34 -1e+34 -1e+34 -1e+34 -1e+34 -1e+34 -1e+34 -1e+34 -1e+34
[228,] -1e+34 -1e+34 -1e+34 -1e+34 -1e+34 -1e+34 -1e+34 -1e+34 -1e+34 -1e+34
[229,] -1e+34 -1e+34 -1e+34 -1e+34
hi
I plot a series of observation data every minutes in a day as the
attachment below
plot(wnd,type='l',lty=1,col='red',lwd=1,xlab=xxlab,ylab=yylab,ylim=YY)
In the figure, the x-axis tickment is the number of data How can I change
it
fore example 1h 2h 3h 4h and so on ?
someone has told me that
I faced this problem when typing:
temperature <- get.var.ncdf( ex.nc, 'Temperature' )
*unable to allocate a vector of size 2.8 GB*
By the way my computer memory is 4G and the original size of the file is
1.4G,netcdf file
I don't know what is the problem.Any suggestion please
I tried also
memor
Hi Michael,
So the coalesce functions don't do what I thought they did. I'll just use
ifelse() then unless anyone makes it clear I should do something different.
Thanks,
Paul
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/
> I am plotting several lines in one figure by such codes. But it is strange
> that
>
> only this first tickment of x-axis is shown.
>
> plot(winddata$v1,type='l',
> lty=1,col='black',lwd=1,xlab=xxlab,ylab=yylab,ylim=YY, xaxt = "n")
> par(new=T)
> plot(winddata$v2,type='l',
> lty=1,col='blue',lwd=1
Please ask Mac-specific questions on R-sig-mac and questions involving
compilation on R-devel (see the posting guide).
Setting your language to English would increase considerably the number
of people who understand the error messages.
On 17/03/2012 12:43, Mark Heckmann wrote:
Hello R GUI e
You use dput to put your data into an email so we can know what your input is.
---
Jeff NewmillerThe . . Go Live...
DCN:Basics: ##.#. ##.#. Live Go...
Did you look at the example I gave you when you asked this question 10
days ago? I'll repeat for completeness
op <- par()
par(ask = TRUE)
plot(1:10) # Unhappy axis
plot(1:10, xaxt = "n")
axis(1, at = 1:10, label = paste(1:10, "h", sep = "")) # Happy axis!
par(ask = op$ask)
The (good) advice to u
hi
I plot a series of observation data every minutes in a day as the
attachment below
plot(wnd,type='l',lty=1,col='red',lwd=1,xlab=xxlab,ylab=yylab,ylim=YY)
In the figure, the x-axis tickment is the number of data How can I change
it
fore example 1h 2h 3h 4h and so on ?
someone has told me that
R community,
I feel almost embarrassed to ask this question as it is strange behavior. When
I think there's a bug around R or a package I ask "Self it's not a bug what
dumb thing are you doing?"
I'm running version 2.14.2 (2012-02-29) on a Windows 7 machine using the
standard rgui
Ever since
I don't think any of these are doing what you want -- they just scan a
list of arguments for the first non-null argument (with some small
differences in implementation). They're more programming utilities
than data analysis tools. It sounds like it's going to be easier to
whip something up with ife
Hello!
I have a problem creating a fitting plane through my 3d-data set. here is a
sample how my set looks like (x,y,z (with z increasing)):
> dataset
[,1] [,2] [,3]
[1,] -1.3712 -3.1551 10
[2,] -1.2690 -3.0751 10
[3,] -1.1216 -2.9768 10
[4,] -0.9875 -2.898
My guess is that you're not getting what you expect from operator
precedence: note that
1:3 - 1
1:(3-1) #Not equal
If that doesn't fix it, you can use options(error = recover) to find
the values of your logical conditions at the exact moment an error is
thrown and see which one is NA but my money
I don't believe you did anything wrong here, just that integrate()
itself isn't (can't?) be vectorized.
E.g.,
x <- integrate(function(x) x^2, 0, 2)
y <- integrate(function(x) x^2, 0, c(2,3))
identical(x, y) # FALSE -- so there's a difference.
# Take a look
str(x)
str(y)
# It's just in the call
On 17-03-2012, at 10:27, diond wrote:
> Hi,
>
> I'm an R beginner and I'm struggling with what should be a rudimentary task.
>
> My data is along these lines:
>
> ID name1 name2 name3 name4
> Class 0 1 0 2
> Var1 A B C A
> Var2 B C C A
> Var3 C A B A
>
> etc.
>
> I'm using the following:
>
Hello All,
Need to coalesce some columns using R. Looked online to see how this is done.
One approach appears to be to use ifelse. Also uncovered a coalesce function in
the BBmisc, emoa, and microbenchmark packages.
Trouble is I can't seem to get it to work in any of these packages. Or perhaps
On Mar 17, 2012, at 3:43 AM, André Smolarz wrote:
Bonjour,
J'utilise R sous Mac OS X 10.6.8 et je souhaiterais savoir s'il est
possible d'utiliser la commande "setwd()" avec un nom de réperoire
contenant des espaces ?
Si oui, comment faire ?
I had no trouble using setwd() with a folder nam
On Mar 17, 2012, at 5:27 AM, diond wrote:
Hi,
I'm an R beginner and I'm struggling with what should be a
rudimentary task.
My data is along these lines:
ID name1 name2 name3 name4
Class 0 1 0 2
Var1 A B C A
Var2 B C C A
Var3 C A B A
etc.
I'm using the following:
foo <- data.frame(t(rea
On 03/17/2012 12:53 AM, Jeff Newmiller wrote:
for(indx in 1:(length(bin.05)-3))
>>> if ((bin.05[indx] == test.pattern[1])&& (bin.05[indx+1] ==
>>> test.pattern[2])&& (bin.05[indx+2] == test.pattern[3]))
>>> return.values$count.match.pattern[1] =
>>> return.values$coun
Dear David and Micheal,
thanks for your suggestion. Vectorize does what I need.
David you suggest me that I didn't built the function in a manner that
would vectorize. Could you please explain me what's wrong?
Thanks,
Mauro
>
> On Mar 15, 2012, at 6:08 AM, Mauro Rossi wrote:
>
>> Dear R users,
Hello R GUI experts,
I having some trouble installing qtbase.
I installed a recent version of Qt and cmake.
Unfortunately I am a rookie when it comes to installation procedures.
Below I attached the (shortened) terminal output.
I erased some parts that reported no failures.
I am especially suspic
Of course, perfection has no end. Why did you think pie was
irrational? Didn't make sense? True Oval fits Elliptical patterns.
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www
Hello R friends,
I've got error message as follows;
>
> n<-0
> roc<-array(0,c(ti-1,1))
> avgroc<-0
>
> for(i in 1:ti-1){
+ if(orientation=="in"){
+ if(eff_p1[i,1,i]==1 && eff_p1[i,1,ti-1]<1 && ed[i,1]>d[i,1]){
+ roc[i,1]<-(1/eff_p1[i,1,ti-1])^(1/(ed[i,1]-d[i,1]))
+ n<-n+1
+ }
+ }
the display of colors on the command line is not in teh scope of R but
depends on the terminal you're using.
If you're using Linux and a bash terminal, you can try to print control
characters for colors like described in Arch Wiki:
https://wiki.archlinux.org/index.php/Color_Bash_Prompt#List_of_colo
Hi,
I'm an R beginner and I'm struggling with what should be a rudimentary task.
My data is along these lines:
ID name1 name2 name3 name4
Class 0 1 0 2
Var1 A B C A
Var2 B C C A
Var3 C A B A
etc.
I'm using the following:
foo <- data.frame(t(read.table("file", header=FALSE)))
but of course no
It is a "ts" object.
Thanks for the suggestion I'll try it out.
--
View this message in context:
http://r.789695.n4.nabble.com/Basic-Quantmod-help-needed-tp4479513p4480190.html
Sent from the R help mailing list archive at Nabble.com.
__
R-help@r-proje
Bonjour,
J'utilise R sous Mac OS X 10.6.8 et je souhaiterais savoir s'il est
possible d'utiliser la commande "setwd()" avec un nom de réperoire
contenant des espaces ?
Si oui, comment faire ?
Merci par avance
A. Smolarz
[[alternative HTML version deleted]]
But so much confusion. Please consider using another language for
your statistics problem. C++ is much more natural for expressing
object-orientation. Most statistics have shapes in hyperspace that
have already been analyzed to the Nth degree.
__
R-he
RColorBrewer {RColorBrewer}
Creates nice looking color palettes especially for thematic maps
On 2012-3-14 22:55, Jie Tang wrote:
hi everyone .
Now I want to draw several lines in one frame.And it seems needs more
colors except for blue red,black .Where can i found these color name or
define s
Much better! Thanks.
On 2012-3-17 18:02, Prof Brian Ripley wrote:
On 17/03/2012 09:34, De-Jian Zhao wrote:
Rename the functions after loading the library.
library("wavelets")
dwt.wavelets <- dwt
library("waveslim")
dwt.waveslim <- dwt
Then use dwt.wavelets and dwt.waveslim instead.
Please,
On 17/03/2012 09:34, De-Jian Zhao wrote:
Rename the functions after loading the library.
library("wavelets")
dwt.wavelets <- dwt
library("waveslim")
dwt.waveslim <- dwt
Then use dwt.wavelets and dwt.waveslim instead.
Please, not necessary!
Use wavelets::dwt or waveslim::dwt to distinguish th
Rename the functions after loading the library.
library("wavelets")
dwt.wavelets <- dwt
library("waveslim")
dwt.waveslim <- dwt
Then use dwt.wavelets and dwt.waveslim instead.
On 2012-3-17 17:03, Jie Tang wrote:
hi everyone .
I am trying to use some packages but there are some functions have
What about just setting them to missing and plotting?
md <- yourdata
md[md==0] <- NA
My other idea depending how you want the plot to look would be to try something
where 0 values get a blank colour or null plotting value
On Mar 16, 2012, at 22:53, Noah Silverman wrote:
> Hi,
>
> i have som
hi everyone .
I am trying to use some packages but there are some functions have the same
name in different package.
for example
dwt function
both in packages wavelets and waveslim
dwt(X, filter="la8", n.levels, boundary="periodic")
How can I avoid mixing them up ?
--
TANG Jie
Email: totang
I think what ever I say applicable to window (operating system).  Start "R",
In "Rgui" menu, click open "edit", you will find "GUI preference", clik open
it. You will find "Rgui configuration editor". According to  ur wish, change
the columns to around "90" (it is a small exercise). Then
62 matches
Mail list logo
