Thanks you,
I can get the length of aa with length(unlist(aa)). If aa has 4 dimensions, I
imagine I'd need to do
max(sapply(aa,sapply,sapply,length)
How can I do this in a generic way? That is in a loop. I am clear about the
exit condition for the loop.
d<-1
start loop
if d = length(unl
Dear list,
I am intersted in estimating movement based kernel densities for fish that were
relocated at fixed receivers positioned along the coast. These data tend to
display both a drift movment between receivers and a random movement component
that can be estimated from the mean and the vari
Hi all,
I am needing to create a wavelet Basis matrix such that f=Bw where f is the
signal, B the basis matrix and, w the weight matrix. I am not concerned
about w which I can easily obtain from most wavelet packages. Is there a
package/ function that can create the B matrix (supposing it is a Haa
Hello,
I made a boucle that put data inside N matrix. So for N=45, I have M1:M45.
Then I want to make a sn.em on each columns of each matrix. I don't know how
to call a i matrix (matrix(i) / matrix[i]) for i in 1:45.
Here is the code to make M1:M45
numberOfConfig8min <- length(numberOfCloseNonM
On Jan 24, 2012, at 4:25 PM, Curt Seeliger wrote:
Yes, you're right about this being a floating point issue. I guess I
wasn't clear enough that this was already understood. I'd have
responded
earlier the response somehow missed my mailbox.
My question is rather whether there is a work aro
Thank you very much. I'll look into the r project listserv you suggested.
Unrelated: Ecological Models and Data in R is one of my favorite
mathematical ecology textbooks and a fantastic resource.
On Tue, Jan 24, 2012 at 9:30 PM, bbolker [via R] <
ml-node+s789695n4326186...@n4.nabble.com> wrote:
Dallas drakeresearchlab.com> writes:
> I am currently testing species co-occurrence patterns using null models and
> the oecosimu() function within the vegan() package. My issue is that none of
> the methods appear to be the ones that I want. The methods listed are r0,
> r1, r2, r2dtable, swap, t
Hi Assa,
I think you should back up and tell us what you're trying to
accomplish. You can replace characters in the column just as you do in
a vector. But I think that is not what you're trying to do. Are you
trying to split the column into three different columns? If so you can
look at the colspl
I think you are getting stuck on the same regexp problem as before
(i.e., once again the dollar sign is being interpreted as the
beginning of the line rather than an actual dollar sign)
If I understand your question, might I suggest something much easier?
x = data.frame(a = c("$1034.23","1,230"),
So I'll preface this with the admission I have no idea what
moving-tiles or boot.tilt are and so I may be in way over my head, but
if you are having trouble fitting your bootstrap procedure into one of
those provided in package, it's not hard to roll your own with
replicate() in base R.
The key is
On 12-01-24 2:46 PM, Stephen P Molnar wrote:
I keep finding the Win32\Huer virus in colorspace_1.1-1.zip for R x64 2.14.1
running MS Windows 7. As a result I am not able to use rattle or
ChemometricsWithR. I have tried several different mirrors with the same
result. Fortunately AVG has caught
Yes, I think you are overcomplicating: it's perfectly valid to
subscript by names. (In fact, it's generally preferred to trying to
use the $ for programming because it's so much more flexible) I.e.,
lapply( phList, function(df) get(df)[, c("ID", "DATE_DISPENSED",
"TG_NAME1", "TG_NAME2", "TG_NAME3"
You can use the assign() function. E.g., assign("a", 3,)
But the more R thing to do is to create a list of your results (which
you can name) and to handle that whole object. Then if you want to do
things to each object you create, it's as simple as lapply
Michael
On Tue, Jan 24, 2012 at 7:27 PM,
Hi
I have data in the following format:
itemsperson1 person2
- - --
car honda,toyotahonda
bikesuzuki suzuki
pant Lee Levis, Lee
shirt Van_housen Hollister
house rented
I'm skeptical that CRAN would produce a bug, but it's not unheard of
for anti-viruses to not like its compiled code. Are you able to
compile locally? That might make it more comfortable -- if you do so,
you could also white list those files (since you made them)
Not a perfect workaround, but AV te
[R] False Virus detection with colorspace package? [Tue Nov 8 00:44:37 CET 2011]
https://stat.ethz.ch/pipermail/r-help/2011-November/294875.html
/H
On Tue, Jan 24, 2012 at 11:46 AM, Stephen P Molnar
wrote:
> I keep finding the Win32\Huer virus in colorspace_1.1-1.zip for R x64 2.14.1
> running M
paste(text, collapse = " ")
Michael
On Tue, Jan 24, 2012 at 3:41 PM, mdvaan wrote:
> Thanks for the quick response. I get the latter part, but reading the text
> from MS word into R is problematic. I am able to read in (scan) all unique
> elements (following sep=" ") from the text, but unable to
I wouldn't characterize the requirement to provide R code as simply "nuts and
bolts", but rather a preference for precision in communication. Very definitely
there are theoretical discussions here, but for such discussions short R
examples are used to make sure the concepts are understood.
-
I've been struggling to get a loop to work. I want to create a new
variable in each loop with data from some function.
for example:
# part of the names for the variables to be created
Frags <- c("F04", "F05", "F07", "F09", "F11", "F13", "F14", "F17", "F18",
"F19", "P20", "Main")
for(obs in Frags
Hi all,
I want to loop through a series of data frames and append them into one data
frame, however I do not want all columns of the original data frames to be
in the new data frame. I have the following code:
phList<-c('ph2010','ph2009','ph2008','ph2007','ph2006') #Name of original
data frames
Hello,
I am trying to create individual concentration-time spaghetti plots sorted
by dose, and within each dose to show two different colors for a
categorical variable (gender). I cant find a way to add the color for
gender. Groups=ID enables individual lines for each subject. If I use
groups=
Dear R helpers
I'm experimenting with the 'kohonen' package and have two questions. I've
been following examples in the package manual and the paper from the Journal
of Geostatistical software (October 2007, Volume 21, Issue 5.).
I've set up a file with the 'animals' data (see attached file) wh
Hi,
I am having difficulty in training a neural network using the package
"neuralnet". My neural network has 2 input neurons (covariates), 1 hidden layer
with 2 hidden neurons and 2 output neurons (responses). I am training my
neural network with a dataset that has been transformed so that ea
Another way would be a which statement.
good_dataset=data[,which(colSums(data)!=0)]
I believe this depends on how the data are structured though.
--
View this message in context:
http://r.789695.n4.nabble.com/drop-columns-whose-rows-are-all-0-tp4324231p4325474.html
Sent from the R help maili
Thanks for the quick response. I get the latter part, but reading the text
from MS word into R is problematic. I am able to read in (scan) all unique
elements (following sep=" ") from the text, but unable to past everything
together again. Any id on how to solve this? It looks like this now:
text
I am currently testing species co-occurrence patterns using null models and
the oecosimu() function within the vegan() package. My issue is that none of
the methods appear to be the ones that I want. The methods listed are r0,
r1, r2, r2dtable, swap, tswap. However, I want to know how to go about
i
I keep finding the Win32\Huer virus in colorspace_1.1-1.zip for R x64 2.14.1
running MS Windows 7. As a result I am not able to use rattle or
ChemometricsWithR. I have tried several different mirrors with the same
result. Fortunately AVG has caught and quarantined the problem, but the
colorspace
Hi,
I am attempting to plot survival curves estimated by cox proportional
hazards regression model. The formula for the model is this:
F.cox.weight <- coxph(Surv(Lifespan, Status) ~ MS + Weight + Laid + MS:Laid
+ Weight:Laid, data = LongF)
MS = Mating status (mated/virgin)
Weight = adult female
Hi People,
Thus anyone have a good solution for this problem:
a database called DB.
index <- sample(1:nrow(DB), size=0.2*nrow(BD))
test <- DB[index,]
train <- DB[-index,]
One of the variables in this database contais a target variable with two
values 0 and 1.
Imagine now that i want to constr
Michael
One way to get an idea about 'groupiness' is a method described by Box
and Ramirez (1992) "Cumulative Score Charts", Qual. Rel. Eng. Int., 8,
17-27 and in a book by Box and Luceno (1997) Statistical Control by
Monitoring and Feedback Adjustment, Wiley Interscience, New York. This
type
On 1/24/2012 2:47 PM, Ajay Askoolum wrote:
Given a variable aa in the workspace, some of its attributes are:
typeof(aa)
[1] "list"
mode(aa)
[1] "list"
length(aa)
[1] 2
How do I retrieve the maximum indices, in this case 2,3,4? The variable itself
is:
aa
[[1]]
[[1]][[1]]
[[1]][[1]][[1]
Exactly. It is very complicated to get them to run under Windows.
Hopefully in the future, there will be Windows versions, but I guess
this will not happen in the very near future.
Regards,
Yihui
--
Yihui Xie
Phone: 515-294-2465 Web: http://yihui.name
Department of Statistics, Iowa State Universi
Statistical inference for group differences on groups determined from the data
yields incorrect results. Groups must be prespecified.
Bert
On Jan 24, 2012, at 2:55 PM, "HARROLD, Tim" wrote:
> You might want to provide an example? It's a pretty vague problem at the
> moment.
>
> If the data c
Now I install R 2.14.1 and I get:
packages 'qtbase', 'qtpaint' are not available (for R version 2.14.1)
Are you saying that the windows binaries are not available for *any* version
of R?
From: Tengfei Yin [mailto:yinteng...@gmail.com]
Sent: Tuesday, January 24, 2012 1:12 PM
To: David W
You might want to provide an example? It's a pretty vague problem at the moment.
If the data can be easily picked out by human eyes, you might want to think
about your criteria you're using to pick out a contaminated result. If you can
express it in such a way that you don't need to scan each ob
If you are using Windows, I'm afraid you have to give up because there
are no Windows binaries for these packages yet. If you are under Linux
or Mac, you can follow the instructions in
https://github.com/ggobi/cranvas/wiki
Regards,
Yihui
--
Yihui Xie
Phone: 515-294-2465 Web: http://yihui.name
Dep
Given a variable aa in the workspace, some of its attributes are:
> typeof(aa)
[1] "list"
> mode(aa)
[1] "list"
> length(aa)
[1] 2
How do I retrieve the maximum indices, in this case 2,3,4? The variable itself
is:
> aa
[[1]]
[[1]][[1]]
[[1]][[1]][[1]]
[1] 37531.52
[[1]][[1]][[2]]
[1] 62787.32
Hi all,
I just wanted to add that I am looking for a solution that's in R ... to
handle this...
And also, in a given sample, the correct data are of the majority and the
noise are of the minority.
Thank you!
On Tue, Jan 24, 2012 at 4:09 PM, Michael wrote:
> Hi all,
>
> I have data which are u
On Tue, Jan 24, 2012 at 5:10 PM, Kevin Burton wrote:
> I am stuck with R 2.14.0 for now because the COM interface that I am using
> (RandFriends) is still on 2.14.0. When I try to install this package (via
> the script) I get:
RAndFriends had 2.14.1 available several weeks ago. It is there as
R
I am stuck with R 2.14.0 for now because the COM interface that I am using
(RandFriends) is still on 2.14.0. When I try to install this package (via
the script) I get:
packages 'qtbase', 'qtpaint' are not available (for R version 2.14.0)
Is there an alternate way to install these packages?
Hi all,
I have data which are unfortuantely comtaminated by noise.
We knew that the noise is at different level than the correct data, i.e.
the noise data can be easily picked out by human eyes.
It looks as if there are two people that generated the two very different
data with different mean le
Sorry, this works
www.zdoor.home.xs4all.nl
Thank you,
Alex van der Spek
On 01/24/2012 07:21 PM, Duncan Murdoch wrote:
On 24/01/2012 11:55 AM, Alex van der Spek wrote:
Uploaded the DLL here:
http://www.filefactory.com/file/c2c56ad/n/Planck.dll
I get:
403 Forbidden
Request forbidden by
> * William Dunlap [2012-01-24 21:47:39 +]:
>
>> >> Oh, yeah, a reproducible example:
>> >>
>> >> read.csv from
>> >> =
>> >> a,b
>> >> 1,2
>> >> 3,4
>> >> 5,,6
>> >> 7,8
>> >> =
>> >> I want to be able to extract the data frame
>> >> a b
>> >> 1 1 1
> The previous line should be '
Johannes Radinger wrote on 01/24/2012 10:15:29 AM:
> Hello,
>
> I would like to reshape a dataframe into an array. This is kind a
> similar task as Excel performs with a Pivot table. To illustrate it:
>
> LOC <- factor(c(1,2,2,3,1,1))
> SPEC1 <- c(0,0,23,0,12,11)
> SPEC2 <- c(1,2,0,0,0,4)
>
>
It was supposed to be a joke :-(
On 1/24/12 4:15 PM, Gabor Grothendieck wrote:
On Tue, Jan 24, 2012 at 4:07 PM, Carl Witthoft wrote:
Like the t-shirt says, "There's no place like 127.0.0.1 "
Though I wasn't familiar with this I check the repositories list and CRAN
(extras) is selected in
> >> Oh, yeah, a reproducible example:
> >>
> >> read.csv from
> >> =
> >> a,b
> >> 1,2
> >> 3,4
> >> 5,,6
> >> 7,8
> >> =
> >> I want to be able to extract the data frame
> >> a b
> >> 1 1 1
The previous line should be '1 1 2', right?
> >> 2 3 4
> >> 3 7 8
Have you tried using count.f
> * Duncan Murdoch [2012-01-24 16:00:14 -0500]:
>
> On 24/01/2012 3:45 PM, Sam Steingold wrote:
>> I get this error from read.table():
>> Error in scan(file, what, nmax, sep, dec, quote, skip, nlines, na.strings, :
>>line 234 did not have 8 elements
>> The error is genuine (an extra field sep
On 25/01/12 09:45, Sam Steingold wrote:
I get this error from read.table():
Error in scan(file, what, nmax, sep, dec, quote, skip, nlines, na.strings, :
line 234 did not have 8 elements
The error is genuine (an extra field separator between 1st and 2nd element).
1. is there a way to see this
Gordon, Alan wrote on 01/24/2012 09:15:31 AM:
> Dear R users,
>
> I'm a new user to R and have a data set consisting of a number of
> variables (in a data frame). I wish to carry out a regression
> analysis of the first variable against all the rest in turn. I have
> used the following code to
Given your domain name, you might also get some use out of the
system() and system2() commands which allow the passing of strings to
the OS command line (and thus the use of tools like grep/sed/awk
within R)
E.g., an idiom I use pretty frequently for interactive data analysis:
(not really related,
Yes, you're right about this being a floating point issue. I guess I
wasn't clear enough that this was already understood. I'd have responded
earlier the response somehow missed my mailbox.
My question is rather whether there is a work around for correctly
displaying POSIXct values as charact
On Tue, Jan 24, 2012 at 4:07 PM, Carl Witthoft wrote:
> Like the t-shirt says, "There's no place like 127.0.0.1 "
>
>
>
>
>
> Though I wasn't familiar with this I check the repositories list and CRAN
> (extras) is selected in my installation (R-2.14.1). By the way, when trying
> Ryacas after wha
On Jan 24, 2012, at 20:41 , Thomas Lumley wrote:
> It's not meant for sampling weights. It's meant for precision
> weights. How best to include sampling weights in mixed models is a
> research problem at the moment, but you can rely on getting the wrong
> answer if you just use the weights= arg
Like the t-shirt says, "There's no place like 127.0.0.1 "
Though I wasn't familiar with this I check the repositories list and
CRAN (extras) is selected in my installation (R-2.14.1). By the way,
when trying Ryacas after what seemed to be a successful install, for a
simple example of
x <
On 25/01/12 05:14, Francisco wrote:
Hello,
I have a dataset with 40 variables, some of them are always 0 (each
row). I would like to make a subset containing only the columns which
values are not all 0, but I don't know how to do it.
I tried:
for(cut_column in 1:40) {
if(sum(dataset[,cut_co
On 24/01/2012 3:45 PM, Sam Steingold wrote:
I get this error from read.table():
Error in scan(file, what, nmax, sep, dec, quote, skip, nlines, na.strings, :
line 234 did not have 8 elements
The error is genuine (an extra field separator between 1st and 2nd element).
1. is there a way to see
dataset.1 <- dataset[, apply(dataset, 2, sum)>0]
Gregorio R. Serrano
2012/1/24 Francisco
> Hello,
> I have a dataset with 40 variables, some of them are always 0 (each row).
> I would like to make a subset containing only the columns which values are
> not all 0, but I don't know how to do it.
I get this error from read.table():
Error in scan(file, what, nmax, sep, dec, quote, skip, nlines, na.strings, :
line 234 did not have 8 elements
The error is genuine (an extra field separator between 1st and 2nd element).
1. is there a way to see this bad line 234 from R without diving into t
On Tue, Jan 24, 2012 at 07:05:37PM +0100, Petr Savicky wrote:
> On Tue, Jan 24, 2012 at 05:19:42PM +, yan jiao wrote:
> > Dear All,
> >
> > I'm wondering if there is a R function could give me all the
> > combinations of the grouping/cluster result, given the number of the groups.
> > e.g.
>
Dear all,
I just try to run the example in R brugs packages, but not only once. Loop is
added in this example. After several times (7, 11, or other random number),
there is an error message "r for windows gui front-end has stopped working".
This happened in two laptops with windows 7 and vista.
On Jan 24, 2012, at 11:17 AM, Taylor, Brian wrote:
> We were looking at conducting a pilot program with Dell to virtualize our lab
> environments. We are specifically looking at Dell/Citrix provisioning
> servers. The OS in this setup is streamed from the server on every boot. I
> was curio
On Tue, Jan 24, 2012 at 9:36 AM, Bert Gunter wrote:
> 1. It's an interaction in a formula not a multiplication.
>
>
> 2. Read the Help file. It says to use ltsreg not lmsreg.
>
> 3. But no P values will be given anyway. The reason is that exact
> distributions and therefore reliable P values or CI
On Tue, Jan 24, 2012 at 6:19 PM, Mohd masood wrote:
>
> Dear All
> I am trying to include sampling weights in multilavel regression analysis
> using packege lme4 using following codes
>
> print(fm1 <- lmer(DC~sex+age+smoker+alcohol+fruits(1|setting),
> dataset,REML = FALSE), corr = FALSE)
> prin
We were looking at conducting a pilot program with Dell to virtualize our lab
environments. We are specifically looking at Dell/Citrix provisioning servers.
The OS in this setup is streamed from the server on every boot. I was curious
if the R Project had any licensing stipulations in this ty
I think you can do this in hexadecimal. To see this, compare the HEX output
from rgb(1,0,0) and rgb(1,0,0,0.5):
#FF
#FF80
They differ only by the addition of the alpha digits hex 80 which are
(almost) half way between 00 and FF. Making a non-transparent scale
transparent is thus just a
Hello,
Point 3 is very simple, instead of 'print' use 'cat'.
Unlike 'print' it allows for several arguments and (very) simple formating.
{ cat("Error: Invalid date values in", DateNames[[i]], "\n",
TestDates[DateNames][[i]][TestDates$Invalid==1], "\n") }
Rui Barradas
--
View
Hi Kevin,
I haven't watched through the video yet, but I guess It's not ggplot2, just
like David pointed out, it's actually using a different graphic engine,
implemented in packages qtbase/qtpaint, which are hosted on Biocondcutor,
to install them, please run
source("http://www.bioconductor.org/
On Jan 24, 2012, at 1:15 PM, Kevin Burton wrote:
I just watched
http://www.youtube.com/watch?v=iSXNfZESR5I
and there is a section where Hadley Wickham showed demonstrated a
county map
of the US that was interactive. This is exactly what I would like.
I have
downloaded ggplot2 but sti
On Tue, Jan 24, 2012 at 05:19:42PM +, yan jiao wrote:
> Dear All,
>
> I'm wondering if there is a R function could give me all the
> combinations of the grouping/cluster result, given the number of the groups.
> e.g.
> 3 objects: x1 x2 x3, number of groups is 2
> so the result will be
> group
Hi,
I wouldn't know how to fill the data into the array form you want, but
you can get the aggregated data with
dfm <- melt( df )
dfc <- cast( dfm, LOC ~ variable, sum )
> dfc
LOC SPEC1 SPEC2
1 123 5
2 223 2
3 3 0 0
Hope this helps as a first step!
Rgds,
Raine
On 24/01/2012 11:55 AM, Alex van der Spek wrote:
Uploaded the DLL here:
http://www.filefactory.com/file/c2c56ad/n/Planck.dll
I get:
403 Forbidden
Request forbidden by administrative rules.
Duncan Murdoch
Appreciate if you can check to see if anything is wrong with this DLL. I
use dumpbi
I just watched
http://www.youtube.com/watch?v=iSXNfZESR5I
and there is a section where Hadley Wickham showed demonstrated a county map
of the US that was interactive. This is exactly what I would like. I have
downloaded ggplot2 but still failed to find out how to even read in and plot
some
I wish to proffer my sincere apologies to both you and the list. I had
not seen my posting appear -- it was initially held for moderator
approval, but I never saw that it was released. During the subscription
process, I had used an incorrect e-mail address and so withdrew the
post. Within my su
A) Reposting the same message as a separate thread is bad netiquette.
B) Posting HTML email on this list is strongly discouraged.
C) You probably ought to read the posting guide.
D) This is a list about using R. Posting theoretical questions without
corresponding R code that illustrates what ho
Dear All,
I'm wondering if there is a R function could give me all the
combinations of the grouping/cluster result, given the number of the groups.
e.g.
3 objects: x1 x2 x3, number of groups is 2
so the result will be
group1:x1,x2; group2: x3
group1: x1;group2: x2,x3
group1: x1,x3;group2: x2
m
Uploaded the DLL here:
http://www.filefactory.com/file/c2c56ad/n/Planck.dll
Appreciate if you can check to see if anything is wrong with this DLL. I
use dumpbin to look at what is in the exports table of the DLL. No reason
for concerns there. I can work with this DLL from both VBA and Python.
Pyt
Hi Tal,
thank you very much for your reply. The xts-dataframe I am using is like:
example <- as.data.frame(structure(c(" 1", " 2", " 1", " 2", " 1", " 1", "
2", " 1", " 2",
" 1", " 2", " 3", " 1", " 1", " 2", " 2", " 3", " 1", " 2", " 2",
" 1", " 2", " 1", " 1", " 2", NA, " 2", NA, NA, " 1", "
Hello Everyone,
Still new to R. Wrote some code that finds and prints invalid dates (see
below). This code works but I suspect it's not very good. If someone could show
me a better way, I'd greatly appreciate it.
Here is some information about what I'm trying to accomplish. My sense is that
th
Ivan:
AFAICS you did not read my post carefully enough. Unquoted improper
identifiers trigger an error because the input cannot be parsed. It
has nothing to do with data.frame() .(**R EXPERTS, PLEASE CORRECT IF
WRONG**). Unquoted LEGAL names are accepted because that's how R works
-- they can be p
Try also
dataset[, colSums(dataset == 0) != nrow(dataset)]
HTH,
Jorge.-
On Tue, Jan 24, 2012 at 11:14 AM, Francisco <> wrote:
> Hello,
> I have a dataset with 40 variables, some of them are always 0 (each row).
> I would like to make a subset containing only the columns which values are
> not
On Jan 24, 2012, at 11:20 AM, Katarzyna Sawicka wrote:
Dear David,
Thanks for your reply. However, I can't see how this is a case. The
table is read into R from .csv file. The column Date has a factor
format then. If I don't change it to as.Date format and use the same
code, the 'text' f
> dataset<-data.frame(a=1:10,b=c(0,0,0,1,0,0,0,0,1,0),c=rep(0,10))
> apply(dataset,2,function(x) all(x==0))
a b c
FALSE FALSE TRUE
> dataset[,!apply(dataset,2,function(x) all(x==0))]
a b
1 1 0
2 2 0
3 3 0
4 4 1
5 5 0
6 6 0
7 7 0
8 8 0
9 9 1
10 10 0
On Tue, Ja
Sorry, I meant check.names = FALSE (d'oh!)
Michael
On Tue, Jan 24, 2012 at 11:33 AM, R. Michael Weylandt
wrote:
> I've usually understand the restrictions on syntactic names as being
> tied to the parser.
>
> E.g., how could R tell the difference between
>
> d <- data.frame(a = 3, `a-2` = 3, che
I've usually understand the restrictions on syntactic names as being
tied to the parser.
E.g., how could R tell the difference between
d <- data.frame(a = 3, `a-2` = 3, check.names = TRUE)
d$a-2 ## Equal to 1 or 3 ?
One of those strange eval things that makes alot of sense for an
interactive lan
Dear David,
Thanks for your reply. However, I can't see how this is a case. The table is
read into R from .csv file. The column Date has a factor format then. If I
don't change it to as.Date format and use the same code, the 'text' function
print the mean by the maximum on y ax regardless to th
On Jan 24, 2012, at 11:07 AM, Dan Abner wrote:
Hi everyone,
I am using Michael's approach (grepl()) to identify which columns
containing $ signs. I was hoping to incorporate this into a line of
code that would automatically 1) find which columns contain $ signs,
2) strip the $ and commas, and
Bert,
Thank you for correcting my inaccuracy. A quick look at the original
question might help you understand what I meant:
d<- data.frame(x = c(0, 1))
d<- data.frame(d, y = c(0,1))
names(d)[2]<- "a.-5"
d
x a.-5
1 00
2 11
d1<- data.frame(d, y = c(0,1))
d1
x a..5 y
1 00 0
2 11
Hello,
I have a dataset with 40 variables, some of them are always 0 (each
row). I would like to make a subset containing only the columns which
values are not all 0, but I don't know how to do it.
I tried:
for(cut_column in 1:40) {
if(sum(dataset[,cut_column])!=0) {
I'll try,
Here is a piece of code it fails for me, the error I get is always the same,
and it happens in most of my functions. The problem is always the same
trying to execute 'mtrace'.
Thanks!
--- execution --
> mtrace(index_remap)
Error in x[[i]] : subscript out of
Dear R users,
I'm a new user to R and have a data set consisting of a number of variables (in
a data frame). I wish to carry out a regression analysis of the first variable
against all the rest in turn. I have used the following code to do this
dd<-read.table("for loop.txt",header=T)
for (j in
Hello,
I would like to reshape a dataframe into an array. This is kind a similar task
as Excel performs with a Pivot table. To illustrate it:
LOC <- factor(c(1,2,2,3,1,1))
SPEC1 <- c(0,0,23,0,12,11)
SPEC2 <- c(1,2,0,0,0,4)
df <- data.frame(LOC,SPEC1,SPEC2) # original dataframe
a <-
array(NA,d
Hi, Michael,
Got it, thank you so much!
Chee
From: R. Michael Weylandt
Sent: Monday, January 23, 2012 11:33 PM
To: r-help ; Chee Chen
Subject: Re: [R] Help: read a proportion of high through-put data
Ok, it seems to have worked on my machine as well, but for some levels
you didn't mention be
For quantile normalization check out
normalize.quantiles in the Biocondcutor preProcess package. Also,
there is a Bioconductor mailing list for future where these topics
are discussed.
http://svitsrv25.epfl.ch/R-doc/library/preprocessCore/html/normalize.quantiles.html
On Sat, Jan 21, 2012 at 7:3
Hi everyone,
I am using Michael's approach (grepl()) to identify which columns
containing $ signs. I was hoping to incorporate this into a line of
code that would automatically 1) find which columns contain $ signs,
2) strip the $ and commas, and 3) convert the result to a numeric
vector.
I have
Hi andreas,
Please give a sample of your data, and how you want it to be after the
manipulation.
Consider using
?dput
Contact
Details:---
Contact me: tal.gal...@gmail.com | 972-52-7275845
Read me: www.talgalili.com (Hebrew) | w
Hi Deivit,
Can you offer a self contained example of r code when the function fails
for you?
Contact
Details:---
Contact me: tal.gal...@gmail.com | 972-52-7275845
Read me: www.talgalili.com (Hebrew) | www.biostatistics.co.il (He
Ivan:
On Tue, Jan 24, 2012 at 6:47 AM, Ivan Calandra
wrote:
> By "it works anyway", I mean that you can have a dash in a column name,
> there is no error or even warning.
> I guess that some functions would throw an error or warning, depending on
> the requirements, but data.frame() doesn't.
Thi
I wish to perform moving tiles bootstrap resampling on some gridded data
meteorological data. I've many years experience with S-Plus, but it has
no way to perform a moving-tiles bootstrap. Within R I've learned how to
use quadratresample() with the spatstats package and would be happy to
simply
I am using the wireframe function from lattice package. The problem that I
have is very interesting. Namely, this is my code:
x= seq(-pi, pi, len = 20)
y=seq(-pi, pi, len = 20)
xyz= expand.grid(x = x, y = y)
xyz$z=sin(sqrt(xyz$x^2 +xyz$y^2))
trellis.par.set("axis.line",list(col="transpa
On Jan 24, 2012, at 8:12 AM, ksaw wrote:
Dear R-helpers,
I am trying to add an information about the mean value for each
variable
within each plot by adding text to the multiple plots in this way:
par(mfrow=c(2,2))
df$Date <- as.Date(df$Date, format="%d/%m/%Y")
for (i in 2:5){
plo
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