David!
...
>
> It means the author either doesn't know the 'sample' function, or wants you
> to understand how to use 'rbinom', or that's just the way she thinks.
>
>>> Could someone help? Thanks so much,
>>>
X1<-c("A","B")[rbinom(n,1,0.6)+1]
X2<-c("C","D")[rbinom(n,1,0.1)+1]
>
>
> C.f.
>
On Jan 4, 2012, at 8:46 PM, David Winsemius wrote:
On Jan 4, 2012, at 7:43 PM, Robert Baer wrote:
-Original Message- From: lynn.tsai
Sent: Wednesday, January 04, 2012 3:38 PM
To: r-help@r-project.org
Subject: [R] a quick question about "rbinom"
Hello, I have the following code using
> d <- data.frame(x=c(1,NA,3,4,5), y=c(2,4,6,8,9), row.names=paste("No.",1:5))
> predict(lm(y~x, data=d, na.action=na.omit))
No. 1 No. 3 No. 4 No. 5
2.2 5.8 7.6 9.4
> d$y - predict(lm(y~x, data=d, na.action=na.omit))
[1] -0.2 -1.8 -1.6 -1.4 6.8
Warning message:
In d$y - pre
Hi, thank you all for replying.
First, it's not a homework. I'm learning R and the CFA (configural frequency
analysis). I am trying to understand this part of the code so that I can
modify it and run a simulation for power analysis of CFA.
Thanks again.
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View this message in context:
http://
On Wed, 4 Jan 2012, John wrote:
It's also a storage hog using several times the space a simple ASCII or
UTF-8 message does. HTML email also offers a convenient way to slip worms
and trojans on systems. Also, since there are various "dialects" of HTML,
documents in one dialect may not display t
On Tue, 03 Jan 2012 21:29:57 -1000
Jeff Newmiller wrote:
> It may be "mainstream" but it really isn't as easy to use or as
> universally readable as plain text.
>
> There are other forums to meet this "need", such as
> stackoverflow.com.
It's also a storage hog using several times the space a
On Jan 4, 2012, at 8:10 PM, Yoo Jinho wrote:
Dear all,
I have found some difference of the results between multinom()
function in
R and multinomial logistic regression in SPSS software.
The input data, model and parameters are below:
choles <- c(94, 158, 133, 164, 162, 182, 140, 157, 146,
On Jan 4, 2012, at 7:43 PM, Robert Baer wrote:
-Original Message- From: lynn.tsai
Sent: Wednesday, January 04, 2012 3:38 PM
To: r-help@r-project.org
Subject: [R] a quick question about "rbinom"
Hello, I have the following code using rbinom, but I don't
understand what
*"+1"* means i
Marc Schwartz-3 wrote
>
> See ?as.formula and ?paste
>
> Something along the lines of the following should work:
>
> Args <- c("one", "two", "three")
>
>> Args
> [1] "one" "two" "three"
>
>> paste(Args[1], "~", Args[2])
> [1] "one ~ two"
>
>> as.formula(paste(Args[1], "~", Args[2]))
> o
Dear all,
I have found some difference of the results between multinom() function in
R and multinomial logistic regression in SPSS software.
The input data, model and parameters are below:
choles <- c(94, 158, 133, 164, 162, 182, 140, 157, 146, 182);
sbp <- c(105, 121, 128, 149, 132, 103, 97, 12
Michael, thank you for your post, I learned a lot.
Why is it that people prefer na.exclude to na.omit?
-
Isaac
Research Assistant
Quantitative Finance Faculty, UTS
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Sent from the R help ma
-Original Message-
From: lynn.tsai
Sent: Wednesday, January 04, 2012 3:38 PM
To: r-help@r-project.org
Subject: [R] a quick question about "rbinom"
Hello, I have the following code using rbinom, but I don't understand what
*"+1"* means in the code. Could someone help? Thanks so much,
X1
On Jan 4, 2012, at 5:31 PM, Justin Haynes wrote:
homework or not,
?rbinom
should be plenty.
I didn't think so. I thought that the answer was:
?"["
--
David.
On Wed, Jan 4, 2012 at 1:38 PM, lynn.tsai
wrote:
Hello, I have the following code using rbinom, but I don't
understand
On 01/04/2012 06:09 AM, Peder Bacher wrote:
Hi
Being able to do object oriented programming in R is really good. I
now started using the Reference Classes and really like it.
Though, I have one problem: I cannot find a way to update a method on
an existing object.
The flexibility that scriptin
A direct answer to your question:
On Wed, Jan 4, 2012 at 4:38 PM, lynn.tsai wrote:
> Hello, I have the following code using rbinom, but I don't understand what
> *"+1"* means in the code. Could someone help? Thanks so much,
>
>> X1<-c("A","B")[rbinom(n,1,0.6)+1]
>> X2<-c("C","D")[rbinom(n,1,0.1)+
FWIW, the integral of a mixture density is the same mixture of the
CDFs, so you can use the pbeta functions:
pcustom <- function(x) (pbeta(x,2,6) + pbeta(x,6,2))/2
albyn
Quoting Gerhard :
Am Dienstag, 3. Januar 2012, 19:51:36 schrieb Prof. Dr. Matthias Kohl:
D <- AbscontDistribution(d = f
R functions should not alter their arguments,
except for 'replacement' functions that are called on
the left side of an assignment operators (e.g., x[1]<-10
calls the replacement function `[<-`).
R functions cam use their enclosing environments to save
state. E.g., the following makeStack functio
On Jan 4, 2012, at 4:08 PM, dood wrote:
Dear R users,
This probably a really noob question, but I'm stuck. I'd like to
pass some
variables from bash to R as strings. I can successfully pass
variables using
commandArgs(), the problem is that I end up with an array.
Huh? You should be get
Thanks, guys!
I am using Rscript at the moment and will definitely try littler.
Li Sun
2012/1/4 Rainer M Krug :
> -BEGIN PGP SIGNED MESSAGE-
> Hash: SHA1
>
> On 04/01/12 10:39, Uwe Ligges wrote:
>>
>>
>> On 03.01.2012 21:22, Li SUN wrote:
>>> Thanks, Rolf, Justin and Uwe!
>>>
>>> Actua
On 12-01-04 11:41 AM, suse wrote:
Thank you! It works now.
But I still don't understand, how all these expressions, "", paste, group,
eval... have to be used together. (For example, I first tried
expression(sm[w,grass]) but it didn't work, and I couldn't find, why (and
when) commas are interpret
homework or not,
?rbinom
should be plenty.
On Wed, Jan 4, 2012 at 1:38 PM, lynn.tsai wrote:
> Hello, I have the following code using rbinom, but I don't understand what
> *"+1"* means in the code. Could someone help? Thanks so much,
>
> > X1<-c("A","B")[rbinom(n,1,0.6)+1]
> > X2<-c("C","D")
Homework?
If not, context?
-- Bert
On Wed, Jan 4, 2012 at 1:38 PM, lynn.tsai wrote:
> Hello, I have the following code using rbinom, but I don't understand what
> *"+1"* means in the code. Could someone help? Thanks so much,
>
>> X1<-c("A","B")[rbinom(n,1,0.6)+1]
>> X2<-c("C","D")[rbinom(n,1,0.
Hello, I have the following code using rbinom, but I don't understand what
*"+1"* means in the code. Could someone help? Thanks so much,
> X1<-c("A","B")[rbinom(n,1,0.6)+1]
> X2<-c("C","D")[rbinom(n,1,0.1)+1]
--
View this message in context:
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> Hi,
>
> Is there an easy way to add symbols to a line in a scatter plot, so that
> only a few symbols are added per line (a line drawn based on a large set
> of
> data points) , in order to distinguish several lines in one graph (not a
> symbol for each data point as is the default in plot()).
>
On Jan 4, 2012, at 3:08 PM, dood wrote:
> Dear R users,
>
> This probably a really noob question, but I'm stuck. I'd like to pass some
> variables from bash to R as strings. I can successfully pass variables using
> commandArgs(), the problem is that I end up with an array. So, for example:
>
>
apply(expand.grid(x, y, z, stringsAsFactors=F), 1, paste, collapse=' ')
On Wed, Jan 4, 2012 at 8:32 AM, jeremy wrote:
> Hi all,
>
> I'm trying to combine exhaustively several character arrays in R like:
> x=c("one","two","three")
> y=c("yellow","blue","green")
> z=c("apple","cheese")
>
> in or
Try expand.grid() to create all the combinations. Then just collapse
them with paste():
apply(expand.grid(x, y, z), 1, paste, collapse = " ")
Cheers,
Josh
On Wed, Jan 4, 2012 at 8:32 AM, jeremy wrote:
> Hi all,
>
> I'm trying to combine exhaustively several character arrays in R like:
> x=c("
On Jan 4, 2012, at 10:32 AM, jeremy wrote:
> Hi all,
>
> I'm trying to combine exhaustively several character arrays in R like:
> x=c("one","two","three")
> y=c("yellow","blue","green")
> z=c("apple","cheese")
>
> in order to get concatenation of
>
> x[1] y[1] z[1] ("one yellow apple")
> x[1
? expand.grid
Michael
On Wed, Jan 4, 2012 at 10:32 AM, jeremy wrote:
> Hi all,
>
> I'm trying to combine exhaustively several character arrays in R like:
> x=c("one","two","three")
> y=c("yellow","blue","green")
> z=c("apple","cheese")
>
> in order to get concatenation of
>
> x[1] y[1] z[1] ("o
Hi. You can use expand.grid here
expand.grid(x,y,z)
Andrija
On Wed, Jan 4, 2012 at 5:32 PM, jeremy wrote:
> Hi all,
>
> I'm trying to combine exhaustively several character arrays in R like:
> x=c("one","two","three")
> y=c("yellow","blue","green")
> z=c("apple","cheese")
>
> in order to get co
>
> One thing R could do better is to provide a standard way to view README and
> similar files before installing a package. That might have helped here.
>
Agreed... right now, the R documentation points to a straightforward,
one-line way to download and install packages from the R command line,
Dear R users,
This probably a really noob question, but I'm stuck. I'd like to pass some
variables from bash to R as strings. I can successfully pass variables using
commandArgs(), the problem is that I end up with an array. So, for example:
> Args <- commandArgs(TRUE)
> Args
[1] "one" "two"
Hello,
If you want to apply the same procedure to all elements of an object, check
out the '*apply' functions.
In this case,
x=c("one","two","three")
y=c("yellow","blue","green")
z=c("apple","cheese")
lapply(x, function(x) paste(x, y))
gives a good picture of what you want to do, just transfo
Thank you for the advice; this is very helpful. I will see how they feel
about installing Inkscape. I'll also work on getting R installed in a
Windows environment so I can produce .emf and .wmf files. I found one
old message on this list from someone who had luck doing this by running
R with Wi
Dear Community,
I'd like to plot an rq object the same way I do with a lm one, is it
possible? Something like this
plot(rqmodel , 1:4, id.labels=rownames(pga1)); where
rqmodel <- rq(log(vd) ~ v1 + log(v2) +log(v3) + v4 + v5 ,data =dat)
Thanks in advance and apologies, I'm pretty newbie with t
Hi Michael,
Thanks for your answer! sorry I didn't see this rule... No problem,
I'll try to figure it out by myself.
Thanks for your indication though!
Thomas
2012/1/4, Michael Weylandt [via R] :
>
>
> Unfortunately, there's a general no-homework rule because we never
> know what your instructo
Hello,
Try 'as.vector' or 'as.numeric'
x <- as.ts(rnorm(20))
y <- as.ts(rnorm(20))
plot(x)
plot(as.vector(lag(x,-9)),as.vector(y),type="p") # works
plot(as.numeric(lag(x,-9)),as.numeric(y),type="p") # also works
Rui Barradas
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thanks, it works!
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Sent from the R help mailing list archive at Nabble.com.
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R-help@r-project.org mailing list
https://stat.ethz.ch/mailm
Thank you! It works now.
But I still don't understand, how all these expressions, "", paste, group,
eval... have to be used together. (For example, I first tried
expression(sm[w,grass]) but it didn't work, and I couldn't find, why (and
when) commas are interpreted here differently). So: Is there
Hi,
Is there an easy way to add symbols to a line in a scatter plot, so that
only a few symbols are added per line (a line drawn based on a large set of
data points) , in order to distinguish several lines in one graph (not a
symbol for each data point as is the default in plot()).
Thanks a lot!
Hi all,
I'm trying to combine exhaustively several character arrays in R like:
x=c("one","two","three")
y=c("yellow","blue","green")
z=c("apple","cheese")
in order to get concatenation of
x[1] y[1] z[1] ("one yellow apple")
x[1] y[1] z[2] ("one yellow cheese")
x[1] y[2] z[1]("one blue apple")
Hi, i try to plot ts data on x-y coordiante
I want my data to be points, but somehow it always comes out with lines and
# linked bwtween data,
i used plot(lag(x,-9),y,type="p"), x and y are time series data
is there anyway to remove those lines?
Thanks a lot
--
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http
Am Dienstag, 3. Januar 2012, 19:51:36 schrieb Prof. Dr. Matthias Kohl:
> D <- AbscontDistribution(d = function(x) dbeta(x, 2, 6) + dbeta(x,6,2),
> low = 0, up = 1, withStand = TRUE)
Dear all,
thank you all again for your help.
So, summing up, (in case this might be useful to other beginners -
Brian,
FYI, I had previously installed tcl-devel but had overlooked tk-devel
on the OS. Now that I've installed tk-devel on the OS, the following
sequence of commands has succeeded:
sudo ./configure --with-tcltk
sudo make
sudo make check
sudo make install
R
...
> library("tcltk")
Loading Tcl/Tk
do s[1] and s[-1] do what you're looking for?
those are just to display... if you want to change s, you need to reassign
it or fiddle with namespacing. however, I'd say it is better to write R
code as though data structures are immutable until you explicitly re-assign
them rather than trying to de
summary: Specifically, how does one do stack/FIFO operations in R?
Generally, how does one code functions with side effects in R?
details:
I have been a coder for years, mostly using C-like semantics (e.g.,
Java). I am now trying to become a scientist, and to use R, but I don't
yet have the sens
On 01/04/2012 09:25 AM, Prof Brian Ripley wrote:
On 04/01/2012 17:12, William Dunlap wrote:
Re
> How can I avoid the warning message altogether?
?closeAllConnections
I think of calls to closeAllConnections() in the same
way that I think of calls to rm(list=objects()):
they both can remove thin
On Jan 4, 2012, at 11:30 AM, Mark Leeds wrote:
hi: does anyone know if it's possible and, if so, where there's an
example,
of putting the output of summary(lm) right on the plot of the data
itself.
If the answer is to use capture.output and then text, I'll try that
but I
was thinking the
On Jan 4, 2012, at 3:47 PM, Dan Abner wrote:
Hello everyone,
How does one pass multiple arguments of a user defined function to
that
function when called within sapply()?
I have the following:
myna<-function(x,miss.val) {x[x %in% miss.val]<-NA;x}
mydataNA3<-sapply(mydataNA,c(x=myna,miss.
Hello everyone,
How does one pass multiple arguments of a user defined function to that
function when called within sapply()?
I have the following:
> myna<-function(x,miss.val) {x[x %in% miss.val]<-NA;x}
> mydataNA3<-sapply(mydataNA,c(x=myna,miss.val=c(9,99)))
Error in match.fun(FUN) :
'c(x =
On Jan 4, 2012, at 3:21 PM, Rich Shepard wrote:
On Wed, 4 Jan 2012, David Winsemius wrote:
Nothing attached. I don't know what you entitled teh "compressed
dput output" but it did not pass the filters of the mailserver and
you did not copy me.
David,
It must have been stripped off as t
On Wed, 4 Jan 2012, David Winsemius wrote:
Nothing attached. I don't know what you entitled teh "compressed dput output"
but it did not pass the filters of the mailserver and you did not copy me.
David,
It must have been stripped off as too large (14K).
Regardless, I solved the problem:
On Jan 4, 2012, at 16:32 , David Winsemius wrote:
>
> On Jan 4, 2012, at 9:17 AM, peter dalgaard wrote:
>
>>
>> On Jan 4, 2012, at 14:57 , Milan Bouchet-Valat wrote:
>>
>>> Le mercredi 04 janvier 2012 à 08:41 -0500, Dan Abner a écrit :
Hello everyone,
I have the following call
Nothing attached. I don't know what you entitled teh "compressed dput
output" but it did not pass the filters of the mailserver and you did
not copy me. If chemdata is available as a text file, hten make sure
its extension is .txt and then attach it.
--
David.
On Jan 4, 2012, at 1:31 PM, R
On Jan 4, 2012, at 19:21 , Duncan Murdoch wrote:
> On 12-01-04 12:25 PM, Prof Brian Ripley wrote:
>>
>>
>> Rather than using a sledgehammer, use showConnections(all=TRUE) to see
>> all connections, and close the ones you want to (and its help page shows
>> you how).
>
> In older versions that
That works, but if all you want is one vertical line at 0, this will work
densityplot(~value, thedata.m, groups=variable,auto.key=list(columns=2),
panel = function(x, y, ...) {
panel.densityplot(x, ...)
panel.abline(v=0)
}
)
On Wed, 4 Jan 2012, David Winsemius wrote:
You didn't ask for what was duplicated, but rather what was NOT duplicated
with that code. In the case of a dataframe it is the entire row that is
tested.
My original question was what was duplicated, but ... I changed the
function by dropping the '
Anne,
Thank you for writing back, and for including your data.
I have two things here. First, I ran an a analysis of your data and have
my observations
on interpretation. Second, I answer your general question about glht and
TukeyHSD when there are interactions.
I illustrate how to get the same
On 04/01/2012 18:21, Duncan Murdoch wrote:
On 12-01-04 12:25 PM, Prof Brian Ripley wrote:
On 04/01/2012 17:12, William Dunlap wrote:
Re
> How can I avoid the warning message altogether?
?closeAllConnections
I think of calls to closeAllConnections() in the same
way that I think of calls to rm(
> -Original Message-
> From: r-help-boun...@r-project.org [mailto:r-help-bounces@r-
> project.org] On Behalf Of David Winsemius
> Sent: Wednesday, January 04, 2012 9:53 AM
> To: Uwe Ligges
> Cc: r-help@r-project.org; suse
> Subject: Re: [R] subscript with comma
>
>
> On Jan 4, 2012, at 10
On 12-01-04 12:25 PM, Prof Brian Ripley wrote:
On 04/01/2012 17:12, William Dunlap wrote:
Re
> How can I avoid the warning message altogether?
?closeAllConnections
I think of calls to closeAllConnections() in the same
way that I think of calls to rm(list=objects()):
they both can rem
On Jan 4, 2012, at 12:21 PM, Rich Shepard wrote:
On Tue, 3 Jan 2012, David Winsemius wrote:
burns.tds[ !duplicated(burns.tds) , ]
Apparently it does not matter if the site column in the data frame
is a
factor or a character, read.zoo() generates the same error. Applying
the
above pro
On Jan 4, 2012, at 10:51 AM, Uwe Ligges wrote:
On 04.01.2012 16:12, suse wrote:
Hi,
I want to write a word with subscript in a graph. Unfortunately, the
subscript contains a comma, so all my trials didn't work and I
didn't find
how to do it.
I want to write "sm" as normal text and "w,gra
On 04/01/2012 17:12, William Dunlap wrote:
Re
> How can I avoid the warning message altogether?
?closeAllConnections
I think of calls to closeAllConnections() in the same
way that I think of calls to rm(list=objects()):
they both can remove things that are not theirs to remove.
Calling
On Tue, 3 Jan 2012, David Winsemius wrote:
burns.tds[ !duplicated(burns.tds) , ]
Apparently it does not matter if the site column in the data frame is a
factor or a character, read.zoo() generates the same error. Applying the
above produces a long list starting with:
burns.tds[!duplicated(
Re
> How can I avoid the warning message altogether?
?closeAllConnections
I think of calls to closeAllConnections() in the same
way that I think of calls to rm(list=objects()):
they both can remove things that are not theirs to remove.
Calling gc() will close all unused connections, so
no
fExtremes::pgpd & pgev have always worked for me. Though, if I
remember right, the physical sciences and finance tend to use
reciprocal definitions for one of the parameters (can't remember which
-- xi in gpd perhaps?) so tread lightly.
Michael
On Wed, Jan 4, 2012 at 8:21 AM, David Winsemius wro
Dear all
I am trying to make an interaction plot among 6 variables; e.g. PH to be in
the x axis and the rest 5 variables in the y axis. The code that I am using is
the below:
The name of my file is e.g. spec so
> spec<-read.csv("spec.csv")
>head (spec)
>str(spec)
>names<-names(spec)[
hi: does anyone know if it's possible and, if so, where there's an example,
of putting the output of summary(lm) right on the plot of the data itself.
If the answer is to use capture.output and then text, I'll try that but I
was thinking there might be an example somewhere ? thanks.
[[alt
Unfortunately, there's a general no-homework rule because we never
know what your instructor wants you to figure out on your own (though,
a sincere thanks for admitting this was hw rather than trying to trick
us like so many). That said, I think your second function, while a
little clumsy, does wor
>
> thank you very much Petr. Yes, I meant densityplot form lattice.
>
> The code I gave plots the densities of both x1 and x2 in one panel.
> Could you show me how to integrate the function addline into the code so
> that a vertical line v=0 is added?
The function is used after you make a
I'm not a huge fan of this sort of solution because it doesn't make
sense for non-vector-shaped (i.e., matrix or data.frame) data. It only
works here because the matrix produced is a special 1xN case.
E.g.,
# Set up some data (and yes, I realize I'm using the trick I'm
speaking out against, but c
thank you very much Petr. Yes, I meant densityplot form lattice.
The code I gave plots the densities of both x1 and x2 in one panel.
Could you show me how to integrate the function addline into the code so
that a vertical line v=0 is added?
On 4 January 2012 15:55, Petr PIKAL wrote:
> Hi
>
>
Hi R helpers!
I have a question. I'm trying to create a function for an exercise. Here are
the arguments I should include:
x and y are numeric
z is a name ("plus","minus","multiply","divide")
and swap is logical.
Here is what the function should do:
When z="plus", then x+y is performed and so o
Hi
As you did not provide any data you probably can not get canned solution
> Hello everyone,
>
> I have two questions:
>
> 1)
>
> I want to create a subset of a data frame column-wise and simultaneously
> extract the row names into a "proper" variable. I tried this, but
received
> an error:
Hi
>
> Hi,
> A simple question I hope. I wish to add a single vertical line to a plot
> with several density plots.
> Here is a simplified example.
>
>
> thedata <- data.frame(x1=rnorm(100,1,1),x2=rnorm(100,3,1)) #create data
> thedata.m<-melt(thedata)
> densityplot(~value, thedata.
Hello everyone,
I have two questions:
1)
I want to create a subset of a data frame column-wise and simultaneously
extract the row names into a "proper" variable. I tried this, but received
an error:
> myleft<-mydata[c(id=row.names(mydata),"workshop","gender","q1","q2")]
Error in `[.data.frame`(
On 04.01.2012 16:12, suse wrote:
Hi,
I want to write a word with subscript in a graph. Unfortunately, the
subscript contains a comma, so all my trials didn't work and I didn't find
how to do it.
I want to write "sm" as normal text and "w,grass" in the subscript. Can
anybody help me?
And a mor
Maximizing f(x) = x'Ax makes sense only when A is negative-definite.
Therefore, this is the same as minimizing x'Bx, where B = -A, and B is
positive-definite.
In other words, you should be able to simply flip the sign of the original
matrix . This should yield a positive-definite matrix sinc
On Jan 4, 2012, at 9:17 AM, peter dalgaard wrote:
On Jan 4, 2012, at 14:57 , Milan Bouchet-Valat wrote:
Le mercredi 04 janvier 2012 à 08:41 -0500, Dan Abner a écrit :
Hello everyone,
I have the following call to sapply() and error message. Is the most
efficient way to deal with this to mak
Perhaps you are confusedthis is R-help
that said, it's very easy with
forecast:::forecast.Arima
in R
Michael
On Wed, Jan 4, 2012 at 8:38 AM, Antonio Tirri wrote:
> Hi, I have to forecast some value of a time series using an ARIMA(5,1,3)
> model.
>
> I saw in Matlab there isn't a funct
Hi,
A simple question I hope. I wish to add a single vertical line to a plot
with several density plots.
Here is a simplified example.
thedata <- data.frame(x1=rnorm(100,1,1),x2=rnorm(100,3,1)) #create data
thedata.m<-melt(thedata)
densityplot(~value, thedata.m, groups=variable,auto.k
Hi,
I want to write a word with subscript in a graph. Unfortunately, the
subscript contains a comma, so all my trials didn't work and I didn't find
how to do it.
I want to write "sm" as normal text and "w,grass" in the subscript. Can
anybody help me?
And a more general question: I read the help t
Hi, I have to forecast some value of a time series using an ARIMA(5,1,3)
model.
I saw in Matlab there isn't a function for ARIMA models because ARIMA
models are a type of Box-Jenkins models. But how to set parameters?
In the Box-Jenkins models
m = bj(data,[nb nc nd nf nk])
How to set nb, nc, n
Hi
Being able to do object oriented programming in R is really good. I
now started using the Reference Classes and really like it.
Though, I have one problem: I cannot find a way to update a method on
an existing object.
The flexibility that scripting gives (really needed for interactive
data an
Dear Max,
I'm having a little trouble following what you did and am also confused by the
subject of your posting. Is this a response to another message? Is it really
about getting sphericity tests?
In addition:
(1) Why are you adding together the response matrices cbind(umsatz_t1,
umsatz_t2,
On Jan 4, 2012, at 9:53 AM, Dan Abner wrote:
Hello everyone,
After running the following code, I obtain this error message.
mydata <- read.table(textConnection(mystring),
+header=TRUE, sep=",",
+row.names="id", na.strings=" ")
mydata
Warning message:
closing unused connection 3 (
Hello everyone,
After running the following code, I obtain this error message.
> mydata <- read.table(textConnection(mystring),
+header=TRUE, sep=",",
+row.names="id", na.strings=" ")
> mydata
Warning message:
closing unused connection 3 (mystring)
=
However, when I attempt to run
On Jan 4, 2012, at 8:02 AM, Milan Bouchet-Valat wrote:
> Le mardi 03 janvier 2012 à 11:39 -0800, gregory benison a écrit :
>> If one attempts to install RODBC (via install.packages('RODBC'))
>> without having an ODBC driver installed, this error message results:
>>
>> checking sqlext.h presence..
On Jan 4, 2012, at 5:49 AM, Vincy Pyne wrote:
Dear R helpers,
I need to use KS and AD test for Generalized Pareto and Generalized
extreme value.
When I searched on these names "Generalized Pareto" and "Generalized
extreme value" I got plenty of hits (over 90 in one case and over 100
i
On Jan 4, 2012, at 14:57 , Milan Bouchet-Valat wrote:
> Le mercredi 04 janvier 2012 à 08:41 -0500, Dan Abner a écrit :
>> Hello everyone,
>>
>> I have the following call to sapply() and error message. Is the most
>> efficient way to deal with this to make sum(!is.na(x)) a function in a
>> separa
On 1/3/2012 9:36 PM, maximilian.mueller wrote:
Here is the syntax:
options(contrasts=c("contr.sum", "contr.poly"))
read.csv2("test21.csv") -> dat3
mod3 <- lm(cbind(umsatz_t1, umsatz_t2, umsatz_t3, umsatz_t4) +
cbind(ebitda_t1, ebitda_t2, ebitda_t3, ebitda_t4)
+ ~ 1, data=dat3)
idata3 <
OK thanks.
In my case I think it might be possible to work around this by reshaping my
data and then using lmlist() to run separate regressions for each data
group. lmlist() is new to me but it looks like it will do the job.
--
View this message in context:
http://r.789695.n4.nabble.com/Linear-
Dan,
It depends on what you want to achieve. I suspect you just want to remove
missing values before summing; if so, consider
sapply(x, sum, na.rm=TRUE)
instead. To make your code running, try
sapply(x, function(x) sum(!is.na(x)))
However, this would just count the number of non-missing value
Hi
Being able to do object oriented programming in R is really good. I now
started using the Reference Classes and really like it.
Though, I have one problem: I cannot find a way to update a method on an
existing object.
The flexibility that scripting gives (really needed for interactive data
an
Le mardi 03 janvier 2012 à 11:39 -0800, gregory benison a écrit :
> If one attempts to install RODBC (via install.packages('RODBC'))
> without having an ODBC driver installed, this error message results:
>
> checking sqlext.h presence... no
> checking for sqlext.h... no
> configure: error: "ODBC h
On Jan 4, 2012, at 7:41 AM, Dan Abner wrote:
> Hello everyone,
>
> I have the following call to sapply() and error message. Is the most
> efficient way to deal with this to make sum(!is.na(x)) a function in a
> separate line prior to this call?
Yes or inline using an anonymous/lambda function
More specifically.
I know that a condition for a VAR(p) process to be stable (weakly
stationary) is that the companion form of the equation (see AWESOME Pfaff
book analysis of integrated and cointegrated time series in R) as
eigenvalues of modulus <1.
My problem is that I want to generate such pr
Hello all,
I looking at package dse or vars or mAr
I know how to simulate a VAR(p) process, my problem is that most of those
processes are unstable (not weakly stationary).
Do anybody know how to generate a random VAR (or VARMA even better) process
that is weakly stationary?
Thanks
--
View this m
Le mercredi 04 janvier 2012 à 08:41 -0500, Dan Abner a écrit :
> Hello everyone,
>
> I have the following call to sapply() and error message. Is the most
> efficient way to deal with this to make sum(!is.na(x)) a function in a
> separate line prior to this call? If not, please advise.
>
> N.Valid
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