Hi!
How can I fit a loess curve to an array (384 x 2).
How can I obtain the equation for thi fi?
Thanks in advance.
--
View this message in context:
http://r.789695.n4.nabble.com/How-to-it-a-loess-curve-and-obtain-the-equation-in-R-tp3927622p3927622.html
Sent from the R help mailing list archiv
Thank for this hint. I installed RStudio and it in the night and test it few
hour. It is a great tool.
Jörg
Am 20.10.2011 22:43 schrieb "Liviu Andronic" :
>
> On Thu, Oct 20, 2011 at 7:29 PM, Bogaso Christofer
> wrote:
> > Dear all, the company I work for has Matlab installed for
> > statistica
Here's another way, using the reshape2 package:
library(reshape2)
d <- dcast(df, vial ~ measure, value_var = 'value')
d$diff <- with(d, B - A)
> d
vial A B diff
11 12 26 14
22 30 45 15
33 27 325
44 6 34 28
HTH,
Dennis
On Fri, Oct 21, 2011 at 3:31 PM, Nathan Miller
Try this,
library(grid)
grid.newpage()
grid.text("text")
HTH,
baptiste
On 22 October 2011 13:26, wrote:
>
> I noticed that the text() command adds text to a plot. Is there a way to
> either make the plot blank or add text to a "blank sheet". I would like
> to "plot" a page that contains just
Hi Michael:
The necessary argument to geom_smooth() is weight, not weights (my
fault, sorry), so try this instead:
ggplot(PearsonLee, aes(x = parent, y = child)) +
geom_point(size = 1.5, position = position_jitter(width = 0.2)) +
geom_smooth(method = lm, aes(weight = frequency,
Thanks Martin.
Actually I want to do a "cyclic loess", so I chose Affy. How may I find
other packages that perform Cyclic loess?
--
View this message in context:
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Sent from the R help
On Oct 21, 2011, at 8:14 PM, Rich Shepard wrote:
On Fri, 21 Oct 2011, David Winsemius wrote:
The only variable in that dataframe with what appears to be a
continuous
value (which is how I would expect "total dissolved solids" to be
measured) is "quant" Are you saying that the value of quant
I have had the following problem with R 2.10, 2.13.1, and 2.13.2, running on
Ubuntu linux 10.04, xubuntu 11.10, and a version of Redhat (I think 5).
rnorm.sobol is producing impossible random values, and occasionally the
routine crashes. Here are samples of the output and the crash message.
librar
Sure.
The simplest way is to call plot.new() directly, with no arguments.
That will give you a square plot with range of 0-1 on each
axis (roughly).
If you want a more complex underlying plot, that's possible too.
If you take a look at ?par, you'll see options for all the different
components of
Hi Hardy,
I would double check the PATH variable in Windows. You can check it through
the control panel, command prompt, or PowerShell. If the correct path to R is
not included, you will need to edit it (the PATH environment variable). I do
not know a way to permanently edit it from the comma
Thank-you for the replies. I would say that the function xtabs() is
the simplest method. And thanks for pointing out that a table is also
an array, as I clearly wasn't aware of that.
On 2011-10-21, at 19:07, Gabor Grothendieck wrote:
> On Fri, Oct 21, 2011 at 7:04 PM, Gabor Grothendieck
> wrot
I noticed that the text() command adds text to a plot. Is there a way to
either make the plot blank or add text to a "blank sheet". I would like
to "plot" a page that contains just text, no plot lines, labels, etc.
Suggestions?
Kevin
[[alternative HTML version deleted]]
_
On Fri, 21 Oct 2011, David Winsemius wrote:
The only variable in that dataframe with what appears to be a continuous
value (which is how I would expect "total dissolved solids" to be
measured) is "quant" Are you saying that the value of quant is measuring
something with different units depending
Hello,
I'm used to working with R in estimation of distributions and statistical
models. I'd like to estimate a simple model of an output y(t) based on a
concentration as independent variable, using a timed series of experimental
data; I've seen this I think somewhere in R? I'd appreciate to h
Hello,
I recently updated to R version 2.13.2. With R version 2.10.0, I often
created and installed R packages, however, I cannot do this since updating.
In other words, when I type in Rcmd build -binary PACKAGENAME I receive an
error message: "Rcmd is not recognized as an internal...". I sus
On Oct 21, 2011, at 6:17 PM, Rich Shepard wrote:
On Fri, 21 Oct 2011, David Winsemius wrote:
What problem are you trying to solve?
What I need now is to compare TDS (total dissolved solids) with
specific
conductivity and the ions that are normally comprise TDS. Before
running any
regr
On Fri, Oct 21, 2011 at 7:04 PM, Gabor Grothendieck
wrote:
> On Fri, Oct 21, 2011 at 4:15 PM, Luk Arbuckle wrote:
>> Consider the following data frame
>>
>> X <- data.frame(Titanic)
>>
>> Does anyone know of an easy way to convert X into a multidimensional
>> array? Example that doesn't work
>>
Thanks Duncan! I wish I had the time to work on something like that, but I
have to stay focused on research.
Thanks again for your extensive help! Have a good weekend everyone!
Ben
On Fri, Oct 21, 2011 at 4:24 PM, Duncan Murdoch wrote:
> On 11-10-21 3:38 PM, Ben qant wrote:
>
>> Hello,
>>
>> I
On Fri, Oct 21, 2011 at 4:15 PM, Luk Arbuckle wrote:
> Consider the following data frame
>
> X <- data.frame(Titanic)
>
> Does anyone know of an easy way to convert X into a multidimensional
> array? Example that doesn't work
>
> X <- as.array(X, dim=c(4,2,2,2))
>
> To do what I need, X needs to
You are probably looking for the structable and related functions in the vcd
package.
Be sure to read the vignettes
library(vcd)
X <- data.frame(Titanic)
XS <- structable(~Class+Sex+Age+Survived, data=X)
as.table(XS)
is.array(XS)
Rich
On Fri, Oct 21, 2011 at 5:56 PM, Luk Arbuckle wrote:
> I nee
Hi,
It shouldn't be so complicated. What about simply:
> td
vial measure value
21 A12
11 B26
42 A30
32 B45
63 A27
53 B32
84 A 6
74 B34
> td <- td[order(td$vial, td$measure),] # make s
Hi all,
Say I have a data frame something like the one below with different sample
vials, measured before(B) and after(A) some process, with a value recorded
at each measurement point
vialmeasurevalue
1 B26
1 A12
2 B 45
2
On 11-10-21 3:38 PM, Ben qant wrote:
Hello,
I'm looking for help putting an interactive rgl package 3d device on the web
so that it maintains full functionality. Where should I start? Is it
possible? Is there an example I can see? (Note: I'm also looking at putting
other normal plots on the web.
Hello Dr. Snow,
With regard to your response from earlier this month:
When I copy and paste your code I get what is expected, the 2 subplots line
up on the same y-value. What version of R are you using, which version of
subplot? What platform?
I'm still troubled by the fact that layout and sub
On Fri, 21 Oct 2011, David Winsemius wrote:
What problem are you trying to solve?
What I need now is to compare TDS (total dissolved solids) with specific
conductivity and the ions that are normally comprise TDS. Before running any
regression models I need to look at these data from three p
On Oct 21, 2011, at 4:38 PM, Rich Shepard wrote:
On Fri, 21 Oct 2011, David Winsemius wrote:
How are we to determine which lines contain information about the
"relationships" of param=="TDS" with whatever cases or variable has
values
of "Cond" and "SO4"? Are you really trying to compare two
I need something that will work with any, possibly very large, data
frame. This dataset is only a very small example.
On 2011-10-21, at 17:31, David L Carlson wrote:
> How about?
>
>> x <- array(Titanic, dim=c(4,2,2,2))
>> str(x>
> num [1:4, 1:2, 1:2, 1:2] 0 0 35 0 0 0 17 0 118 154 ...
>
>
You have to convert the long numbers to time objects; they are kept as
POSIXct values so just apply as.POSIXct() to them. However, you may
just want to store the time data as a string containing the same info:
try this,
library(quantmod)
tck = "YHOO"
filename = paste(tck, ".txt", sep="")
while(T
How about?
> x <- array(Titanic, dim=c(4,2,2,2))
> str(x>
num [1:4, 1:2, 1:2, 1:2] 0 0 35 0 0 0 17 0 118 154 ...
--
David L Carlson
Associate Professor of Anthropology
Texas A&M University
College Station, TX 77843-4352
-Original Message-
From
Hi,
I have been given a set of around 300 files where there are 5 files
corresponding to each chunk.
E.g. Chunk 1 for chr1 contains these 5 files:
chr1.one.phased.impute2.chunk1
chr1.one.phased.impute2.chunk1_info
chr1.one.phased.impute2.chunk1_info_by_sample
Try something like this:
plot(x,type="o", pch = c(5,rep(NA,9)))
for, e.g., every 10th point.
Michael Weylandt
On Fri, Oct 21, 2011 at 5:18 PM, zugi young wrote:
> Hi,
>
> I would like to produce a plot with a symbol on every nth point in a time
> series data, like the one in the following:
>
>
Hi,
I would like to produce a plot with a symbol on every nth point in a time
series data, like the one in the following:
http://www.phon.ucl.ac.uk/home/yi/ProsodyPro/EnglishFocus.png
x <- seq(-100,1000,25)
plot(x,type="l")
Could someone help me out with the above example?
Thanks
Your memory shouldn't be capped there, try ?memory.size and ?memory.limit.
Background less things.
Good luck,
Ken Hutchison
On Oct 21, 2554 BE, at 11:57 AM, D_Tomas wrote:
> My apologies for my vague comment.
>
> My data comprises 400.000 x 21 (17 explanatory variables, plus response
On Fri, 21 Oct 2011, David Winsemius wrote:
How are we to determine which lines contain information about the
"relationships" of param=="TDS" with whatever cases or variable has values
of "Cond" and "SO4"? Are you really trying to compare two disjoint groups
on some statistic like the means and
Consider the following data frame
X <- data.frame(Titanic)
Does anyone know of an easy way to convert X into a multidimensional
array? Example that doesn't work
X <- as.array(X, dim=c(4,2,2,2))
To do what I need, X needs to be converted into an array of dimensions
c(4,2,2,2) in this case, not
The most important thing is the point termed "C" (on the image):
http://r.789695.n4.nabble.com/file/n3926631/courbe_temp%C3%A9rature.png
which is the first point (time, temperature) where temperature stabilizes
after the temperature drop (end of feeding). The definition of that
particular point i
My apologies for my vague comment.
My data comprises 400.000 x 21 (17 explanatory variables, plus response
variable, plus two offsets).
If I build the full model (only linear) I get:
Error: cannot allocate vector of size 112.3 Mb
I have a 4GB RAM laptop... Would i get any improvemnt on a 8G
Has anyone here implemented Jon Kleinberg's burst detection algorithm
("Bursty and Hierarchical Structure in Streams"
http://www.cs.cornell.edu/home/kleinber/bhs.pdf)?
I'd rather not reimplement if there's already running code available
Thanks,
-s
[[alternative HTML vers
On Oct 21, 2011, at 3:02 PM, Rich Shepard wrote:
On Fri, 21 Oct 2011, David Winsemius wrote:
First you need to clarify whether "TDS" is the name of a column or a
possible value in a column named "param". This whole painful
multi-question process would be greatly accelerated if you offered
str
Hello,
I'm looking for help putting an interactive rgl package 3d device on the web
so that it maintains full functionality. Where should I start? Is it
possible? Is there an example I can see? (Note: I'm also looking at putting
other normal plots on the web.) I'd like to stay within R as much as
On Fri, 21 Oct 2011, David Winsemius wrote:
First you need to clarify whether "TDS" is the name of a column or a
possible value in a column named "param". This whole painful
multi-question process would be greatly accelerated if you offered
str(chemdata).
Yes, I did on a different thread, bu
Thanks very much, Dennis. See below for something I don't understand.
On 10/21/2011 12:15 PM, Dennis Murphy wrote:
Hi Michael:
Here's one way to get it from ggplot2. To avoid possible overplotting,
I jittered the points horizontally by ± 0.2. I also reduced the point
size from the default 2 an
Did you perhaps send an HTML message? As detailed in the Posting
Guide, those get scrubbed by the mail-server.
On Oct 21, 2011, at 10:48 AM, seanstcl...@verizon.net wrote:
--
David Winsemius, MD
West Hartford, CT
__
R-help@r-project.org mailing li
Beautiful! It works perfectly, thanks!
kb
On Oct 21, 7:42 am, Jim Lemon wrote:
> On 10/21/2011 06:25 AM, Kerry wrote:
>
> > Can someone please help me out with this? The ggplot2 suggestion works
> > great but I've spent a few days trying to figure out how to plot 2
> > variables with it and I'm
thanks for the help. but with that code it is possible to save the current
quotes in a text file(only the date-time in the first columnis not
preserved). when i used read.table and tried to convert it into an xts
object it shows error as it cannot take the indices as time object. same
case happens
Hallo,
it seems as if something did not work with my first email
I would like to estimate parameters of a general extreme value (GEV)
distribution using maximum likelihood as implemented in the gev.fit function of
package ismev. If I do the follwing:
y.training<- c(22, 22, 18, 19, 18, 18, 22,
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
Awesome, thank you so much for this! I plan to play around with this
more next week with my actual data, but it provides a lot more options
than I had before I posted. The link will help too.
kb
On Oct 20, 8:18 pm, Dennis Murphy wrote:
> AFAIK, you can't 'add' two ggplot2 graphs together; the pr
I have the following code:
c <- file("c:/temp/r/SkuSalesModel.br", "rb")
s <- unserialize(c)
close(c)
rm(c)
And it worked as late as yesterday. Today when I came in I get the
following error:
Error in .Call("R_unserialize", connection, refhook, PACKAGE = "base") :
negative length vectors ar
Perhaps:
require(forecast)
?auto.arima #
Or look into package fitAR. The first performs seasonal optimization so it is
likely better for your application.
Ken Hutchison
On Oct 21, 2554 BE, at 1:59 PM, Flávio Fagundes wrote:
> Hi people,
>
> I´m trying to development a simple routine to ru
On Oct 21, 2011, at 2:09 PM, Rich Shepard wrote:
On Fri, 21 Oct 2011, David Winsemius wrote:
The last part ("in the same column") does not make sense, since I was
interpreting the term "parameter" to mean a value in a particular
column. Assuming these are R NA's then logical indexing:
wit
Hi Dennis!
Fantastic, great, wonderful, beautiful.
I slightly changed your code to adapt it to my situation:
ggplot(DF.2, aes(x=file.name, y=value,
fill=codes))+geom_histogram(position="stack", stat="identity") +
labs(x="document", y="number of codings")
###
file.name codes
On Fri, 21 Oct 2011, David Winsemius wrote:
The last part ("in the same column") does not make sense, since I was
interpreting the term "parameter" to mean a value in a particular column.
Assuming these are R NA's then logical indexing:
with( chemdata, chemdata[!is.na(param1) & !is.na(param2)
Hi people,
I´m trying to development a simple routine to run many Arima models result
from some parâmeters combination.
My data test have one year and daily level.
A part of routine is:
for ( d in 0:1 )
{ for ( p in 0:3 )
{ for ( q in 0:3 )
{ for ( sd in 0:1 )
{
On Fri, 21 Oct 2011, David Winsemius wrote:
The last part ("in the same column") does not make sense, since I was
interpreting the term "parameter" to mean a value in a particular column.
David,
That's what I meant: two values from the 'param' column.
Assuming these are R NA's then logica
Here is the code I am running:
library(nls2)
modeltest<- function(A,mu,l,b,thour){
out<-vector(length=length(thour))
for (i in 1:length(thour)) {
out[i]<-b+A/(1+exp(4*mu/A*(l-thour[i])+2))
}
return(out)
}
A=1.3
mu=.22
l = 15
b = .07
thour = 1:25
Yvals<-modeltest(A,mu,l,b,thour)-.125+runif(25)/4
On Oct 21, 2011, at 1:04 PM, Rich Shepard wrote:
On Fri, 21 Oct 2011, Weidong Gu wrote:
No easy way out with missing data problems, all imputations are
based on
some strong and untestable assumptions.
Thanks for the insights.
Let me rephrase my question in a way that should work: is th
Hi:
Your approach to computing the means is not efficient; a better way
would be to use the aggregate() function. I would start by combining
the grouping variable and the three prediction variables into a data
frame. To get the groupwise mean for all three prediction variables,
you can use a formu
On Fri, 21 Oct 2011, B77S wrote:
I know in my experience "Cond" (conductivity??) doesn't vary much within a
stream except for during high flow events, and I would imagine the same is
true for TDS.
This is generally true, but not in the streams with which we're working.
TDS values, for exampl
I believe you could also set your subscription to NOMAIL and then read the
posts from the R-help archive. This would also allow you to post to R-help
since you are still subscribed.
Hope this is helpful,
Dan
Daniel Nordlund
Bothell, WA USA
> -Original Message-
> From: r-help-boun...@
On Fri, 21 Oct 2011, Weidong Gu wrote:
No easy way out with missing data problems, all imputations are based on
some strong and untestable assumptions.
Thanks for the insights.
Let me rephrase my question in a way that should work: is there a way to
subset my comprehensive data frame ('ch
On Fri, 21 Oct 2011, Luke Miller wrote:
The following produces something very similar to David's method:
plot(1,1, xlab = expression(paste("Conductivity (", mu, "S / cm)")))
but with a slightly different slash character. I think David's method
is more "correct", but I've used the above method in
I know in my experience "Cond" (conductivity??) doesn't vary much within a
stream except for during high flow events, and I would imagine the same is
true for TDS. If these are all low flow values, you could possibly
determine a mean/median value to use for the missing data points. Obviously
this
Sounds like you are dealing with missing data problem. At default, lm
or glm would only keep observations with complete records (complete
case analysis). This can be problematic if you have many missing
variables and missing values occur not completely at random (i.e.,
missing values are dependent
The following produces something very similar to David's method:
plot(1,1, xlab = expression(paste("Conductivity (", mu, "S / cm)")))
but with a slightly different slash character. I think David's method
is more "correct", but I've used the above method in the past with
some success.
On Fri, Oct
Alternatively, since you are on gmail you can set up a folder and filter so
all r-help emails bypass you inbox and go right to an r-help folder (or
something). I find it very useful for just browsing during down time so I
can offer my assistance or move to an 'r-keepers ' folder the for little
gem
Hi Michael:
Here's one way to get it from ggplot2. To avoid possible overplotting,
I jittered the points horizontally by +/- 0.2. I also reduced the point
size from the default 2 and increased the line thickness to 1.5 for
both fitted curves. In ggplot2, the term faceting is synonymous with
condit
Because of regulatory requirement changes over several decades and weather
conditions preventing site access the variables in my data set have
different lengths. I'd like guidance on how to perform linear regressions
and other models with these variables.
For example, there are 2206 rows for
You can get the same results with the cut() function in R:
cut(cars$speed, breaks=quantile(cars$speed, probs=c(0:15/15)), labels=1:15,
include.lowest=TRUE)
--
David L Carlson
Associate Professor of Anthropology
Texas A&M University
College Station, TX 7
On Fri, 21 Oct 2011, David Winsemius wrote:
plot(1,1, xlab=expression(Conductivity~"("*mu*S/cm*")") )
Thank you, David. It did not occur to me to look for a help page. I'll
read that now that I looked and found it.
Rich
__
R-help@r-project.org ma
Vera,
The glht function in the multcomp package provides the capability you are
looking for.
The MMC functions in the HH package build on the ghlt function.
There are examples in ?MMC on data with more than one factor.
Rich
On Fri, Oct 21, 2011 at 4:55 AM, Vera Marjorie E. Velasco <
velas...@uni
i will include the data to read if if you so choose.
dat <- read.dta("http://quantoid.net/hw1_2011.dta";)
model in question:
mod99 <- glm(democracy ~ popc100kpc + ngrevpc, data=dat, family=binomial)
--
looking for average effects code, with error on mod99. popckpc is coded in
1
On Oct 20, 2011, at 8:22 PM, renee wrote:
Hello,
I am constructing a nomogram using cph and nomogram commands in Dr.
Harrell's Design/RMS package. The HR that I obtain for dichotomous and
categorical variables are identical to those that I obtain using STATA
stcox.
When posting to r-help it
On Oct 21, 2011, at 11:27 AM, Rich Shepard wrote:
For an axis label I want to include the Greek letter mu within the
string.
I've not found the proper way of including that expression within the
string.
What I want is "Conductivity (uS/cm)" with the 'u' replaced by mu.
When I
try "Conduc
On Oct 21, 2011, at 6:39 AM, knut-o wrote:
Hello
Is it possible to map a plot with horizontal lines like in the step-
plot,
but without the vertical lines?
There is no function named 'step-plot'. If you are talking about the
plot.stepfun function then look at the "verticals" argument.
For an axis label I want to include the Greek letter mu within the string.
I've not found the proper way of including that expression within the
string.
What I want is "Conductivity (uS/cm)" with the 'u' replaced by mu. When I
try "Conductivity (" expression(paste(mu)) "S/cm)" I get an error.
In the HistData package, I have a data frame, PearsonLee, containing
observations on heights of parent and child, in weighted form:
library(HistData)
> str(PearsonLee)
'data.frame': 746 obs. of 6 variables:
$ child: num 59.5 59.5 59.5 60.5 60.5 61.5 61.5 61.5 61.5 61.5 ...
$ parent
On Oct 21, 2011, at 1:57 AM, Jörg Reuter wrote:
Hi,
I am very happy. My problems are solved without one little thing:
(Iske <- matrix(c(1, 1, 1, 2, 2, 2, 1, 1, 1, 5, 1, 2, 2, 2, 1, 1, 1,
4, 4, 4, 4, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 5, 4, 4, 4, 4, 4, 4, 2,
2, 2, 2, 4, 5, 5, 5, 5, 5, 5, 5, 5, 5,
Hello
I am discovering R and I find it is really very powerful.
However, I find some newbie difficulties.
Here, I have a data frame with manu values that I want to calculate the
frequency (the nomber of line) of the some criteria.
For exemple here, I want it to print the number of occurence wher
Hi list
I am discovering R, and
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Address
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Tunisia
tel: +216 97 246 706 (+33640302046 jusqu'au 15/6)
fax: +216 71 391 166
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R-h
D_Tomas hotmail.com> writes:
>
> Hi,
>
> I am trying to fi a glm-poisson model to 400.000 records. I have tried biglm
> and glmulti but i have problems... can it really be the case that 400.000
> are too many records???
>
> I am thinking of using random samples of my dataset.
>
"I hav
On 21.10.2011 13:02, Lisa Henault wrote:
can i be taken off of this mailing list please?
is there another way that you can access this without having to get all the
emails??
[[alternative HTML version deleted]]
__
R-help@r-project.org maili
On 21/10/2011 6:39 AM, knut-o wrote:
Hello
Is it possible to map a plot with horizontal lines like in the step-plot,
but without the vertical lines?
Not in the basic plot function, but you can write your own fairly
easily, using segments(). For example:
x <- y <- 1:10
plot(x,y, type='n')
s
On Fri, Oct 21, 2011 at 6:24 AM, sarelseerower wrote:
> I am new to R and trying to understand time series objects.
>
> I have 2 vectors, one containing rainfall values (lets call the vector
> "rain") and the other the time/date in seconds (lets call it "time"). Is
> there a method to create a ti
> npy <- length(events1[, "obs"])/(diff(range(ardieres[, "time"],
+ na.rm = TRUE)) - diff(ardieres[c(20945, 20947), "time"]))
This line is from the mannual "A user's Guide to POT Approach". I am just
trying to ask why the values 20945, 20947 are used??
Regards
On Fri, Oct 21, 2011 at 4:19 PM, R.
How about posting a reproducible sample, so that we can see what is going on?
Read the posting guide!!!
--
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Sent from the R help mailing list archive at Nabble.com.
Thanks for the tips/adviceI actually used a different solution to
circumvent this, but Uwe's solutions would also work
--
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Sent from the R help mailing list archive at Nabble.com.
___
Október 19-től 21-ig irodán kívül vagyok, és az emailjeimet nem érem el.
Sürgős esetben kérem forduljon Kárpáti Edithez (karpati.e...@gyemszi.hu).
Üdvözlettel,
Mihalicza Péter
I will be out of the office from 19 till 21 October with no access to my emails.
In urgent cases please contact Ms. Ed
Dear Helper,
I have a spatial lines data frame object 'spRiverDf'. The data frame consists
of numbers {0,1,...,5}. And I have a vector 'colorS' of length 6 with different
colours.
If I make a plot with spplot I get a plot of the lines - colours depending on
there number in the data frame colum
>
> On Oct 21, 2011, at 09:01 , Martin Maechler wrote:
>
>>> "ARE" == Alex Ruiz Euler
>>>on Wed, 19 Oct 2011 14:05:16 -0700 writes:
>>
>>ARE> Motion supported. Very.
>>
>>ARE> On Wed, 19 Oct 2011 15:40:14 +0200
>>ARE> peter dalgaard wrote:
>>
Argh!
Someone
Hi,
I am trying to fi a glm-poisson model to 400.000 records. I have tried biglm
and glmulti but i have problems... can it really be the case that 400.000
are too many records???
I am thinking of using random samples of my dataset.
Many thanks,
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PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
can i be taken off of this mailing list please?
is there another way that you can access this without having to get all the
emails??
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Hello
Is it possible to map a plot with horizontal lines like in the step-plot,
but without the vertical lines?
Thanks, knut
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Hi Michael,
Thanks for the help.
Yes, I have gone through the document for ?outlier. As it removes one
outlier at a time, being new to R, I was woondering is there any function
available for removing multiple outliers whithout calling say rm.outlier for
n number of time because n is not finite he
I am new to R and trying to understand time series objects.
I have 2 vectors, one containing rainfall values (lets call the vector
"rain") and the other the time/date in seconds (lets call it "time"). Is
there a method to create a time series object simply by giving the "rain"
and "time" vectors
Dear members,
I'm trying to estimate a varying coefficients model using the local polynomial
estimation method in two case (univariate and bivariate) and with two smooth
functions.
In the univariate case I use:
m1<-smooth.lf(x=lp(z1,by=x1,deg=1,h=0.7,ev=z1)+lp(z3,by=expl2,deg=1,h=0.7,ev=z1
On 21/10/2011 9:36 AM, Ben qant wrote:
Hello,
Using the rgl package, I can set the device window to any dimension (that I
have tested):
par3d(windowRect=c(1,1,700,700))
With windows I can't get the window to span from the top to the bottom of
the monitor. In the following, no matter how large t
On Fri, 21 Oct 2011, Duncan Mackay wrote:
Without a dataset I am not sure what you need.
Duncan,
Part of the problems I'm trying to resolve come from changing priorities
from my client and the regulators. I end up stopping one process and
starting on a different one. But, that's life in the
Hello,
Using the rgl package, I can set the device window to any dimension (that I
have tested):
par3d(windowRect=c(1,1,700,700))
With windows I can't get the window to span from the top to the bottom of
the monitor. In the following, no matter how large the ypinch value gets it
stops, leaving ab
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