On Aug 9, 2011, at 02:38 , Kathie wrote:
> Thanks a lot all of you
>
> Yes, you're right.
>
> However, as i know, "do.call" calls its function once, but "apply(or sapply
> etc)" not. So, I think do.call is faster than apply. That's why i am trying
> to use do.call.
>
> Am I right??
You're not
Hi Remko
After thinking about try and tryCatch the problem was catching the error
what about ?captureOutput
Regards
Duncan
At 14:28 09/08/2011, you wrote:
> Hi Remko,
>
> How about ?try
>
> Hope it helps,
>
> Tsjerk
>
Not quite, because then the code chunk in the final doc. will have this
tr
Hello,
I can't seem to add transparency to any color ramp I create using
colorRampPalette(). Can someone tell me if it is possible to create transparent
colour ramps?
I am attempting to map shaded relief under elevation data. I know I can use the
terrain.colors() with the alpha option, but I
I am trying to convert a matlab code to R.
Most of the conversion statements are simple, but problem is with return.
Since it's a recursive function it's a bit complicated. Anyway in matlab
we can have return statment like
[price, notional] = functionname()
and also for the same function...
not
> Hi Remko,
>
> How about ?try
>
> Hope it helps,
>
> Tsjerk
>
Not quite, because then the code chunk in the final doc. will have this
try() around it as well - not too pretty for a user manual.
remko
> On Aug 9, 2011 5:30 AM, "Remko Duursma" wrote:
>
> Dear R-helpers,
>
>
> sorry if this i
Hi David,
Thank you very much. Problem solved.
sapply() and lapply() are so powerful that even I have read their documents
several times, still lots of tricky stuff to learn and try.
Thank you again!
Richard
David Winsemius wrote:
>
>
> > sapply(c("hsp", "dal"), function(x) locpoly(x=ts, y=
Hi:
David evidently left the ddply() part to me :)
Here's one way to summarize the data and get a plot in ggplot2.
Firstly, thank you for the dput(); you score extra points for that :)
I put that output in an object named results.
## Step 1: Summarize the data in plyr
library('ggplot2') # als
Hi,
I'm a new user of R. I'm using package copula implemented in R. I want
to know how to test goodness of fit of student's t copula for 3
dimensional cases using real world data. In manual gof test has been
performed on the copula families generated from rcopula function that
i understood as rand
Hi Remko
?try
?tryCatch
Below are some posts that may give you an idea
http://finzi.psych.upenn.edu/R/Rhelp02/archive/35608.html
http://finzi.psych.upenn.edu/Rhelp10/2010-June/243576.html
http://finzi.psych.upenn.edu/R/Rhelp02/archive/35604.html
http://finzi.psych.upenn.edu/Rhelp10/2008-Septemb
On Aug 8, 2011, at 11:01 PM, Richard Ma wrote:
Hi all,
I have a data frame called "rst", see below:
--
# This is a paste able example
# In case you don't have "KernSmooth" package installed, please
uncom
In regard to my question
Prof. Warren (Victoria University of Wellington, NZ) suggested the line:
assign(paste("freq.list",i,sep="."),freq.list)
instead of the lines:
filename<-paste("freq.list", i, "txt", sep=".")
write(freq.list, file=filename[[1]], sep="", append=FALSE)
Hi all,
I have a data frame called "rst", see below:
--
# This is a paste able example
# In case you don't have "KernSmooth" package installed, please uncomment
below line.
# install.packages("KernSmooth")
li
Hi R help,
I am trying to determine how nls() generates a function based on the
self-starting SSlogis and what the formula for the function would be.
I've scoured the help site, and other literature to try and figure
this out but I still am unsure if I am correct in what I am coming up
with.
***
Thanks a lot all of you
Yes, you're right.
However, as i know, "do.call" calls its function once, but "apply(or sapply
etc)" not. So, I think do.call is faster than apply. That's why i am trying
to use do.call.
Am I right??
--
View this message in context:
http://r.789695.n4.nabble.com/on-do-c
Dear R-helpers,
sorry if this is obvious, but I can't find this in the documentation.
I am using Sweave, and have some code that does not actually work - but I
want to include it anyway, including the error message that R produces.
But on running Sweave() on my .Rnw file, it simply halts when i
On 11-08-08 9:58 PM, thmsfuller...@gmail.com wrote:
On Mon, Aug 8, 2011 at 6:08 PM, peter dalgaard wrote:
On Aug 9, 2011, at 00:29 , Dennis Murphy wrote:
Hi:
Here are a couple of ways; there may well be better ones.
# (1) Use the get() function:
mean_on_element=function(data, elem_name) {
Thank you for that. I had to do some tweaking, but I managed to get it
working. In case anyone wants to do something similar, here's my solution.
n = sample(1:50,25)
g = gray(1-(n/max(n))) # the subtraction from 1 reverses the colors. rev()
just reverses the order of the colors.
image(as.matrix
On 08/08/2011 05:04 PM, Mike Williamson wrote:
Hi All,
I have tried to find an answer within documentation, but I cannot:
o How can call a class "slot" without knowing the name a priori?
E.g., let's say I use the "pcaMethods" library to create a "pcaRes"
object. How can I call parts
On Mon, Aug 8, 2011 at 6:08 PM, peter dalgaard wrote:
>
> On Aug 9, 2011, at 00:29 , Dennis Murphy wrote:
>
>> Hi:
>>
>> Here are a couple of ways; there may well be better ones.
>>
>> # (1) Use the get() function:
>> mean_on_element=function(data, elem_name) {
>> with(data, mean(get(elem_name)
On Mon, Aug 8, 2011 at 6:08 PM, peter dalgaard wrote:
>
> On Aug 9, 2011, at 00:29 , Dennis Murphy wrote:
>
>> Hi:
>>
>> Here are a couple of ways; there may well be better ones.
>>
>> # (1) Use the get() function:
>> mean_on_element=function(data, elem_name) {
>> with(data, mean(get(elem_name)
On Aug 8, 2011, at 7:51 PM, Jeffrey Joh wrote:
Here is a sample of what I'm trying to do:
structure(list(C_lo = c(0.00392581816943354, 0.00901222644518829,
0.00484396253385175, 0.00822377400482716, 0.00780070460187192,
0.00952688235337435), C_hi = c(0.00697755827622381,
0.0123301031600017,
Hi
? list.files
There have been recent posts of a similar thread of working with
multiple files.
I do not know anything about msSet and msProcess
Regards
Duncan
Duncan Mackay
Department of Agronomy and Soil Science
University of New England
ARMIDALE NSW 2351
Email: home mac...@northnet.com
Is it this?
https://stat.ethz.ch/pipermail/r-devel/2011-July/061540.html
Try a recent version of R 2.13.1 patched
On Tue, Aug 9, 2011 at 1:53 AM, Colin Ford wrote:
> Hi Pete,
>
> I thought it might be something to do with NA's when I first started but its
> not. I've attached both the image ou
On 08/08/2011 8:04 PM, Mike Williamson wrote:
Hi All,
I have tried to find an answer within documentation, but I cannot:
o How can call a class "slot" without knowing the name a priori?
See ?slot.
E.g., let's say I use the "pcaMethods" library to create a "pcaRes"
object. How ca
Hi All,
I have tried to find an answer within documentation, but I cannot:
o How can call a class "slot" without knowing the name a priori?
E.g., let's say I use the "pcaMethods" library to create a "pcaRes"
object. How can I call parts of that object without using the specific
names of
Hi Tyler --
On 08/08/2011 12:54 PM, Tyler Gruhn wrote:
I just signed up for R Help, so please let me know if I'm doing this
incorrectly.
Better to provide an informative subject line -- "microarray heatmap
memory use" ?
I've been working with R for a couple of weeks, attempting to process
Here is a sample of what I'm trying to do:
structure(list(C_lo = c(0.00392581816943354, 0.00901222644518829,
0.00484396253385175, 0.00822377400482716, 0.00780070460187192,
0.00952688235337435), C_hi = c(0.00697755827622381, 0.0123301031600017,
0.0113207627868435, 0.0112887993422598, 0.01856724
On Aug 8, 2011, at 11:53 AM, Colin Ford wrote:
Hi Pete,
I thought it might be something to do with NA's when I first started
but its not. I've attached both the image output and the data.
No, you haven't. Probably was an unacceptable file type.
Its almost as if the blocks in the heatmap a
Hi Pete,
I thought it might be something to do with NA's when I first started but its
not. I've attached both the image output and the data. Its almost as if the
blocks in the heatmap are not quite meshing together? I've tried heatmap.2 as
well and that gave the same result. I also just tried t
Dear R afficianados!
I'm writing a script to create a frequency list for multiple files.
I've written a "for" loop to iterate through the selected folder and
creating lists for each file. In the line "write(freq.list,
file=filename[[1]], sep="", append=FALSE)" I've written the individual
lists to
On Aug 9, 2011, at 00:29 , Dennis Murphy wrote:
> Hi:
>
> Here are a couple of ways; there may well be better ones.
>
> # (1) Use the get() function:
> mean_on_element=function(data, elem_name) {
> with(data, mean(get(elem_name)))
> }
> mean_on_element(data, 'x')
I suspect this goes belly-u
?predict.rpart
Weidong Gu
On Mon, Aug 8, 2011 at 6:08 PM, Jose Bustos Melo wrote:
> Hello Everyone,
>
> I'm doing a Classification trees with categorical explanatory variables using
> library rpart and I would like to do a prediction for some data imputs. I
> don't know where's a function or h
Hey that helps! Wish we could also throw an error if both were missing...
Thanks again!
Ben
On Mon, Aug 8, 2011 at 4:37 PM, Henrik Bengtsson wrote:
> Hi,
>
> you can do something like:
>
> setConstructorS3("Person", function(name, age) {
> # Check for missing arguments, but allow for empty
>
Dear Thierry,
Thanks a lot for pointing me to the right direction! I still have some
questions, really appreciate if you could provide any help:
Is there a relationship between the nested mixed model that I used vs. the
model that you gave (using biop location as random slope of pid), i.e.
Hi,
you can do something like:
setConstructorS3("Person", function(name, age) {
# Check for missing arguments, but allow for empty
# constructor calls, i.e. Person().
if (missing(name) && missing(age)) {
name <- NA;
age <- NA;
} else if (missing(name)) {
throw("Argument 'name'
Hi:
Here are a couple of ways; there may well be better ones.
# (1) Use the get() function:
mean_on_element=function(data, elem_name) {
with(data, mean(get(elem_name)))
}
mean_on_element(data, 'x')
# (2) Lose 'with' and use subscripting instead:
mean_on_element=function(data, elem_name) {
Hi Tom,
What exactly is this function supposed to do? Your immediate problem is that
you are passing it a string "x" and asking for a mean of the string "x"
(hence complaints that it's not numeric) but I'm a little confused as to
what this is supposed to do when it works.
If you just want the mea
Hello,
Using the R.oo package, how do I throw an error if a field is not present
when the user of the class creates the object?
Using the example in the R.oo package:
setConstructorS3("Person", function(name, age) {
if (missing(name)) name <- NA;
if (missing(age)) age <- NA;
extend(Objec
Hi All,
I want to enclose with() in a function mean_on_element. Obviously, it
is not working. The problem is how to specify the element name with a
function body. Does anybody have any suggestion? Thanks!
> data=list(x=1:10)
> with(data, mean(x))
[1] 5.5
>
> mean_on_element=function(data, elem_na
Hi:
Here are two ways you could do this, one using dcast() and one using xtabs():
batdat <- structure(list(Time = structure(c(1L, 1L, 1L, 1L, 2L, 2L, 2L,
2L, 3L, 3L, 3L, 3L, 4L, 4L, 4L, 4L, 5L, 5L, 5L, 5L, 6L, 6L, 6L,
6L), .Label = c("0:00", "0:15", "0:30", "0:45", "1:00", "1:15"
), class = "fact
Hello Everyone,
I'm doing a Classification trees with categorical explanatory variables using
library rpart and I would like to do a prediction for some data imputs. I don't
know where's a function or how can I do it?. Is there someone can help ?? ¿.
Here's the code that I'm using.
library(rp
Would the image() function do what you need?
n = sample(1:50,25);
g = gray(n/max(n)) # set up color palate
g = rev(g) # reverse so max is black instead of white
image(as.matrix(n),col=g) # Requires a matrix input
I think you should be able to handle axes/ labels/ etc as normal:
image(as.matrix(n
I just signed up for R Help, so please let me know if I'm doing this
incorrectly.
I've been working with R for a couple of weeks, attempting to process
microarray data. This means 20,000+ rows of data to work with x 24
columns. I am trying to produce heatmaps and found that the best
computer
Hallo!
Does anybody know a way to calculate the sample size for comparing AUC of ROC
curves against 'by chance' with AUC=0.5 (and/or against anothe AUC)?
Thanks!
Karl
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PL
Package pROC does the job - roc.test with parameter paired=F
Karl
- Ursprüngliche Mail
Von: Karl Knoblick
An: r-h...@stat.math.ethz.ch
Gesendet: Montag, den 27. Juni 2011, 12:19:48 Uhr
Betreff: Differences between ROC curves
Hallo!
Can anybody help with the comparison of ROC curve
Package pROC does the job - roc.test withparameter paired=F
Karl
- Ursprüngliche Mail
Von: Karl Knoblick
An: r-h...@stat.math.ethz.ch
Gesendet: Dienstag, den 21. Juni 2011, 23:19:17 Uhr
Betreff: Compare AUC of uncorrelated ROC curves
Hallo!
I want to compare two uncorrelated ROC curv
Howdy,
I am trying to make a simple monochrome heatmap from 1 row of data.
Essentially, I just want a long bar where black represents the max value in
the data, white is the minimum, and all values in between are interpolated
appropriately. I have tried using heatmap and heatmap.2, but both ha
I have 120 MS chromatograms containing two columns'Time' and 'Peak height'.
how do in create a msSet file which is required by all the functions of
'msProcess' to process these files.
I would appreciate help very much.
Thanks
Sharad
--
View this message in context:
http://r.789695.n4.nabble.com/m
Hi Hadley et all,
I am struggling with reshape2 and melt works and melt_check
(filtered151) seems fine
My cast command was acast (filtered151, Time ~ Species ~ Number)
> melt_check (filtered151)
Using time, Species as id variables
$id
[1] "time""Species"
$measure
[1] "Number"
When I exec
On 8/6/2011 9:21 AM, zhenjiang xu wrote:
Unfortunately the list names of my real data are irregular with mixed
digit and letters at the end. This is good idea though. It inspired me
to give another solution based on that:
x<- list(A=c("d", "e", "f"), B=c("d", "e"), C=c("d","g"))
tmp<- unlist(x,
Would someone tell me how they propose to go from "standard errors" to
confidence intervals*. I suspect Doug Bates would probably like to
know, also, as he has expended a lot of effort on this over the years,
I believe. :-)
-- Bert
* Note +/- 2 std errors is almost certainly not the right answ
Hi:
On Mon, Aug 8, 2011 at 10:07 AM, bjmjarrett wrote:
> Hi all,
>
> I’m trying to plot confidence intervals for the fitted values I get with my
> lme model in R.
Which fitted values? The ones conditional on the random effects or the
ones averaged over the random effects? The standard errors of
Hi:
Try this:
# Obtained from 'dput(dd)'
dd <- structure(list(AgeRange = structure(c(1L, 1L, 2L, 2L, 3L, 3L),
.Label = c("10-12",
"15-18", "30-40"), class = "factor"), AgeOfPerson = c(11L, 12L,
13L, 14L, 33L, 36L), PersonNo = 1:6, Year0 = c(0L, 0L, 1L, 1L,
3L, 4L), Year1 = c(1L, 1L, 2L, 3L, 5L, 4
Hi:
What is the connection between genot and cage? What is the purpose of
the levels fifteen, nine and fortyfive in eggs? Are these the numbers
of eggs per some type of batch whose total is 45?
Dennis
On Mon, Aug 8, 2011 at 7:00 AM, Jörg Stephan wrote:
> Hello R-Help-Team,
>
> I am doing a 3-wa
I think the problem may be there are multiple subjects with the same subject
number. I'll have to index by subject & date. I put together a zip file
with the original data set, the cleaned data set, and the code (with your
code integrated). It's called "clean.zip"
netfiles.umn.edu/users/patze003
Possiblyif any(grepl(4, x)) somehow returned true for a subject
that only had 1 & 2, the effect would be to return all 1s.
dummy <- factor(c("2", "1", "NA", "4"))
foo(dummy)
> foo(dummy)
[1] 1 1 NA 2
Levels: 1 2 NA
note the internal representation of the dummy factor:
> as.numeric(dummy)
Here's a thought, when I execute it on a data frame with only the subject
and resp variables I have the same problem. But not on the subset of data
we've been working with. The difference between the full vector and the
subset vector is that the full vector contains NA's. Only 35 out of 17,000
t
On Mon, Aug 8, 2011 at 9:16 AM, Johannes Egner wrote:
> Hi,
>
> I'm removing non-unique time indices in a zoo time series by means of
> aggregate. The time series is bivariate, and the row to be kept only depends
> on the maximum of one of the two columns. Here's an example:
>
> x <- zoo(rbind( c(
I don't know lme models very well, but if you have standard errors for your
values, this shouldn't be too hard (as a last resort) using polygon()
For example
x = 1:10
y = x^2
y.Err = 2*x
y.Up = y + y.Err; y.Dn =y-y.Err
# This graph is actually quite ugly so don't copy the formatting
plot(x,y
Hi all,
I need to test gof of 3-dimensional t copula for my trivariate observed
data set. So I used the command
t.cop <- tCopula(c(0.785,0.283,0.613),dim=3,dispstr="un",df=6,df.fixed =
TRUE)
where c(0.785,0.283,0.613) is the correlation pattern of my data with 0.785
pearson correlation between
Hi all,
I’m trying to plot confidence intervals for the fitted values I get with my
lme model in R.
Is there any way I can plot this in the form of a shaded band, like the
output of geom_smooth() in ggplot2 package. ggplot2 seems to use only lm,
glm, gam, loess and rlm as smoothing methods.
Any
Thanks to Michael Weylandt and Josh Wiley for pointing me to the View()
function. It worked like a charm - once I learned that R is case-sensitive.
I told you I am new to R!
Ed
Ed Heaton
10318 Yearling Drive
Rockville, MD 20850-3517
Voice: (301) 424-8186
Mobile: (301) 520-7414
Fax: (301) 4
Hi Cheryl,
Here is an example of how to get the fixed and random effects
covariance matrices.
require(lme4)
(fm1 <- lmer(Reaction ~ Days + (Days|Subject), sleepstudy))
## fixed effects
vcov(fm1)
## random effects
VarCorr(fm1)
## for documentation, see
method?vcov("mer")
Hope this helps,
Josh
Hi,
Your use of "do.call" is essentially equal to "dpois(lt$y0,
exp(rowSums(t(X[lt$i,])*B[,1])))". You do not need to use "do.call", "sapply"
or "apply" will do, e.g.,
> sapply(1:nrow(lt), function(x) fc(lt[x,2],lt[x,1]))
[1] 0.1891356 0.1859965 0.3149658 0.3128512 0.2622549 0.2631122
Way
Original message
>Date: Wed, 3 Aug 2011 16:06:33 -0500 (CDT)
>From:
>Subject: Need help with xyplot
>To: r-help@r-project.org
>
>
>Consider I have the following data:
>
>AgeRange AgeOfPerson PersonNoFriendsAtYear0 FriendsAtYear1
>FriendsAtYear2 FriendsAtYear3
On Aug 8, 2011, at 11:16 AM, Kathie wrote:
Dear all,
Even though one of R users answered my question, I cannot
understand, so I
re-ask this question.
I am trying to use "do.call", but I don't think I totally understand
this
function.
Why are you trying to use do.call? It operates on a
On Aug 8, 2011, at 17:16 , Kathie wrote:
> Dear all,
>
> Even though one of R users answered my question, I cannot understand, so I
> re-ask this question.
>
> I am trying to use "do.call", but I don't think I totally understand this
> function.
It has nothing to do with do.call, the problem i
Hi Ed,
In addition to Michael's suggestion (which is probably what you want),
consider something like:
head(mtcars)
tail(mtcars)
or for just the corners, you could try a little function like this:
corner <- function(x, n = 3L, ...) {
stopifnot(length(n) == 1L)
if (n < 0L || n * 2 > min(dim(
Welcome to the dark-side!
I think the View() command will do what you want. This brings up a new
window that displays the data spreadsheet style and you can scroll wherever
you wish. If you want to do work in your command window, the head() and
tail() commands will be of help to you.
If you are j
These are shots in the dark, but you could try: running it in a clean
R session with only the necessary packages and data loaded; testing on
subsets of your data; examing the classes of all your variables and
make sure they are what is expexted; upgrading your version of R.
I just retested this on
Hi, all;
I'm new to R. Have been a SAS developer for over 20 years.
Whenever I create a new table - you call them dataFrame objects - or modify
an existing one, I like to open the table in a grid with horizontal and
vertical sliders so that I can scan across the table and (especially) look
Hi Thomas,
I suspect part of the reason you did not get a response the first time
is that your example is not very easy to use. You say you have lists
of data frames, but we only have two data frames (which you said
worked fine). dput() is a nice way to provide example data if you
cannot/do not
H, I pulled out a portion of the data set to create the code for
posting. When I execute this on the data frame I get the following for
subject 8 which is clearly incorrect. I get this for all subjects who
originally had "1 & 2".
dat$respalt <- with(dat, ave(Slide1_RESP, factor(grid), FUN =
Dear all,
Even though one of R users answered my question, I cannot understand, so I
re-ask this question.
I am trying to use "do.call", but I don't think I totally understand this
function.
Here is an simple example.
> B <- matrix(c(.5,.1,.2,.3),2,
still no answer? I´ll try to be more precise and will ask on stack-overflow
too...
I´ve got multiple data.frames of gps- and temperature-data within a list.
One data.frame looks like:
GPS:
date time x.lat x.lon
1 22.05.11 13:50:37 53.57908 10.034599
2
Hmm, well I suppose it technically does "touch" in some sense still if
there are 1 & 2s, but it should just return it as is, not changed.
Thanks for the data, very easy! Here is what I get:
dat <- structure(list(subject = c(8L, 8L, 8L, 8L, 8L, 8L, 8L, 8L, 8L,
8L, 42L, 42L, 42L, 42L, 42L, 42L, 42L
Hi BJ,
Is this what you want?
Data1 <- structure(list(Site = structure(c(1L, 1L, 1L, 1L, 2L, 2L, 2L,
2L), .Label = c("Site1", "Site2"), class = "factor"), Fish_no = structure(c(1L,
2L, 3L, 4L, 1L, 2L, 3L, 4L), .Label = c("Fish1", "Fish2", "Fish3",
"Fish4"), class = "factor"), Length = c(10L, 13L,
Here's the code. I don't want it to even touch the vector if there are
already "1's & 2's"
structure(list(subject = c(8L, 8L, 8L, 8L, 8L, 8L, 8L, 8L, 8L,
8L, 42L, 42L, 42L, 42L, 42L, 42L, 42L, 42L, 42L, 42L, 6L, 6L,
6L, 6L, 6L, 6L, 6L, 6L, 6L, 6L), resp = c(2, 1, 1, 2, 1, 2, 1,
1, 1, 1, 4, 4, 2,
Help-list,
Sorry about the formatting problem, Josh. The following example data set(minor
difference from original) in plain text should make the problem clear.
Original data format:
Site Fish_no Length
Site1Fish110
Site1Fish213
Site1Fish314
Site1
On Mon, Aug 8, 2011 at 8:23 AM, Edward Patzelt wrote:
> Thanks Josh for the code to post I have been trying to figure out how to do
> that. Your code works except that it changes subjects that responded with
> "1 & 2" to all 1's. What does the "ave" argument mean in the execution of
Not in the
On Aug 8, 2011, at 10:00 AM, Jörg Stephan wrote:
Hello R-Help-Team,
I am doing a 3-way-nestedAnova and a very strange thing occurred. My
"Two-sample Kolmogorov-Smirnov test" (p=0.957) meet the requirement
of normal distribution, BUT if I have a look at the histogram it is
definitely not
Thanks Josh for the code to post I have been trying to figure out how to do
that. Your code works except that it changes subjects that responded with
"1 & 2" to all 1's. What does the "ave" argument mean in the execution of
the function?
library(car)
foo <- function(x) {
if (any(grepl(4, x))) {
Hi Paul
I've been gradually filling in the XMLSchema packages for different cases that
arise.
My development versions of SSOAP and XMLSchema get a long way further and I
have been trying
to find time to finish them off. Fortunately, it is on my todo list for the
next few weeks.
I have releas
Dear R-List,
I have carried out a factor analysis using fa (psych) with nfactors=2,
rotation="oblimin" and fm="pa". Now I have to report both pattern AND
structure matrix. As I have understood R-Documentation, this can be obtained
by setting the "oblique.scores" argument TRUE (structure matrix) o
Hello R-Help-Team,
I am doing a 3-way-nestedAnova and a very strange thing occurred. My
"Two-sample Kolmogorov-Smirnov test" (p=0.957) meet the requirement of
normal distribution, BUT if I have a look at the histogram it is
definitely not normally distributed. I never had something like that a
Hi,
I'm removing non-unique time indices in a zoo time series by means of
aggregate. The time series is bivariate, and the row to be kept only depends
on the maximum of one of the two columns. Here's an example:
x <- zoo(rbind( c(1,1), c(1.1, 0.9), c(1.1, 1.1), c(1,1) ),
order.by=c(1,1,2,
Hello,
Is there a way to get the Var-Cov matrix from the LMER function?
Thanks
[[alternative HTML version deleted]]
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R
On Aug 8, 2011, at 8:04 AM, Jörg Stephan wrote:
Hello R-Help-Team,
I am doing a 3-way-nestedAnova and a very strange thing occurred. My
"Two-sample Kolmogorov-Smirnov test" (p=0.957) meet the requirement
of normal distribution, BUT if I have a look at the histogram it is
definitely not n
Hello R-Help-Team,
I am doing a 3-way-nestedAnova and a very strange thing occurred. My
"Two-sample Kolmogorov-Smirnov test" (p=0.957) meet the requirement of
normal distribution, BUT if I have a look at the histogram it is
definitely not normally distributed. I never had something like that a
On 08/08/2011 02:04 AM, You Na wrote:
Hi there,
I got a problem when trying to read in a .cel file using ReadAffy().
R codes:
require(affy)
Please ask questions about Bioconductor packages on the Bioconductor
mailing list
http://bioconductor.org/help/mailing-list/
Make sure your packages
On 08/08/2011 8:21 AM, Duncan Murdoch wrote:
On 08/08/2011 4:34 AM, Kathie wrote:
> Dear all,
>
> I am trying to use "do.call", but I don't think I totally understand this
> function.
>
> Here is an simple example.
>
>
>
> > B<- matrix(c(.5,.1,
On 08/08/2011 4:34 AM, Kathie wrote:
Dear all,
I am trying to use "do.call", but I don't think I totally understand this
function.
Here is an simple example.
> B<- matrix(c(.5,.1,.2,.3),2,2)
> B
[,1] [,2]
[1,] 0.5 0.2
[2,] 0.1 0.3
> x<
Hi,My major problem with R was always the quality of the output. Recently I
found R2wd, which solved this problem. R2wd makes it possible to write output
directly to a word file, end to produce high-quality tables.I have two problems
with R2wd, however.1. The documentation says it is possible t
Hello,
I must start by saying that I am an R novice and am sorry if this is a
no-brainer...
I have an csv file that contains a grid of 300x300 data points. Each point
represents
a 1Km square on a map. Each point is either a floating point number or NA. I
load the
data in with:
data <- read.
Wir sind bis am 20. August in den Ferien und werden keine e-mails beantworten.
Bei dringenden Fällen melden Sie sich bei Stefanie von Felten
steffi.vonfel...@oikostat.ch
We are on vacation until 20. August. In urgent cases, please contact Stefanie
von Felten steffi.vonfel...@oikostat.ch
__
Hi there,
I got a problem when trying to read in a .cel file using ReadAffy().
R codes:
require(affy)
ReadAffy(filenames="CH1.CEL")
It failed and I got the error,
Error in read.celfile.header(as.character(filenames[[1]])) :
Is CH1.CEL really a CEL file? tried reading as text, gzipped text, b
I'm repeating the post. Has anyone written a routine for this R? Thanks.
--
View this message in context:
http://r.789695.n4.nabble.com/Re-Bruno-s-Panel-LSDVC-tp3680824p3726719.html
Sent from the R help mailing list archive at Nabble.com.
__
R-help@r-p
Thank you both for your reply. I went with the cosine function for similarity
and used it with apply to get a measure of distance.
Ravi
--
View this message in context:
http://r.789695.n4.nabble.com/Distance-between-a-vector-and-matrix-rows-tp3726268p3726610.html
Sent from the R help mailing lis
Dear all,
I am trying to use "do.call", but I don't think I totally understand this
function.
Here is an simple example.
> B <- matrix(c(.5,.1,.2,.3),2,2)
> B
[,1] [,2]
[1,] 0.5 0.2
[2,] 0.1 0.3
> x <- c(.1,.2)
> X <- cbind(1,x)
> X
Hi
If you go to the list of contributed packages have a look at the ones
that have ordinal in their description.
You have not told us what your data is or what you need
Regards
Duncan
Duncan Mackay
Department of Agronomy and Soil Science
University of New England
ARMIDALE NSW 2351
Email: ho
1 - 100 of 106 matches
Mail list logo