Hello all,
I am wondering if there is a way to specify sampling weights for an ols
model using sample weights.
For instance, right now, my code is:
fit.ex<-lm(y~x1+x2+x3+...xk,data=dataset,weights=weightvariable.)
summary(fit.ex)
But, there is almost no difference in the coefficients nor standa
Hi
> Re: [R] Setting NA to blank
>
> I asked because I thought it'd solve an issue I had. I was actually
being
> quite rash in asking this question and for that, I apologize.
>
> I wanted to know because I was attempting to create a heatmap where the
NA
> values would not be shown while all th
Using install packages pull-down, I chose a mirror and then package rJava.
Then it said that it cannot remove the rJava package already installed.
Then when I typed library(rJava) it said there was no rjava package.
Isn't that rather contradictory for R?
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View this message in context:
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Kenneth,
Thanks for the reply. I checked the original data. There is no space. I even
manually added a space to one value. After reading in with read.xls, the
value has two spaces. The reason I don't like it is I am going to do some
comparison with another dataset, which is supposed to be the same
Maybe in the original there are some "ghost" spaces after ng/ml,
verify them.
Any way you can erase the first and the last white spaces with gsub
function.
HTH
Kenneth
El lun, 09-05-2011 a las 22:44 -0500, Jun Shen escribió:
> Dear list,
>
> I used read.xls to read in an excel file, which has
Dear list,
I used read.xls to read in an excel file, which has both character and
numeric columns. Everything seems fine except in the last column, I have
this character value "ng/ml". When reading in, read.xls seems to add a space
at the end of it, became "ng/ml ". How can I prevent read.xls doin
Look at the solve.QP() function in the "quadprog" package.
Ravi.
From: r-help-boun...@r-project.org [r-help-boun...@r-project.org] On Behalf Of
vioravis [viora...@gmail.com]
Sent: Monday, May 09, 2011 10:46 PM
To: r-help@r-project.org
Subject: [R] SQP wi
I am trying to optimize function similar to the following:
Minimize x1^2 - x2^2 - x3^2
st x1 < x2
x2 < x3
The constraint is that the variables should be monotonically increasing. Is
there any package that implements Sequential Quadratic Programming with
ability include these constraints???
Dear Friends,
I have been trying to save multiple 3x3 (mfrow=c(3,3) graphics inside a loop
using tiff figure format (not using PDF or savePlot functions) with no
success. Could you please help?
Here is a simplified example code:
dat=data.frame (ID=rep(1:10,each=10),IDV=rep(seq(1:10),times=10))
Thanks David! I got a solution, though maybe not optimal. In the zzz.r file
of the R package, I include the folloing code:
.onLoad <- function(libname,pkgname) {
myoptions <- list(ngs.python="sage -python",ngs.macs="macs14")
if(exists("myoptions",.GlobalEnv))
options(.GlobalEnv$my
In case anyone else is having similar problems, it turns out it may have been
an issue with the interface I was using (R Studio). When I close R Studio
and tried it again through R it installed without the error message.
Chris.
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View this message in context:
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I'm trying to use the package rgl for a research project. I've used it in the
past, but now when I try to re-install it after updating to R 2.13.0 I'm
getting the following error:
Warning in install.packages :
package ‘rgl’ is not available (for R version 2.13.0)
Is there any way to get R to re
I got a netCDF file from a climate group and wanted to aggregate the data.
The file summary looks like this
library(ncdf)
nc=open.ncdf("NCEP_prec_1949_58.nc")
> nc
[1] "file NCEP_prec_1949_58.nc has 4 dimensions:"
[1] "Time Size: 14608"
[1] "lat Size: 99"
[1] "lon Size: 199"
[1] "DateStrLen
Here is one way:
df <- data.frame(Value = rnorm(30),
Group = sample(c('A','B','C'), 30,
replace = TRUE))
## make a little function to do the job
iNumber <- function(f) {
f <- as.factor(f)
X <- outer(f, levels(f), "==")+0
rowSums(X * apply(X, 2, cumsum))
}
Hello list,
I am looking to create a figure for my dataset using splom, where there is a
splom subplot for each level of a factor within, for example, a 2x2 layout.
For each subplot, I wish to put the r-value between each variable pair in
the lower panel. The code I have thus far is below, using
I used the DLL export viewer to what is the table name being exported. It is
showing as VALUEAHROPTIMIZE_. This is the name of the function we have used
plus the underscore.
Is there any other reason for the function not getting recognized??? Thanks.
--
View this message in context:
http://r.78
You could use a function to do the job:
withinRange <- function(x, r = quantile(x, c(0.05, 0.95)))
x >= r[1] & x <= r[2]
dtest2 <- subset(dftest, withinRange(x))
-Original Message-
From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org] On
Behalf Of Robert A'gata
S
Hi,
I always have a question about how to do this best in R. I have a data
frame and a set of criteria to filter points out. My procedure is to
always locate indices of those points, check if index vector length is
greater than 0 or not and then remove them. Meaning
dftest <- data.frame(x=rnorm(1
?lchoose
?lgamma
?lfactorial
On Mon, May 9, 2011 at 7:45 PM, Jim Silverton wrote:
> I have some big combinations like:
> choose 784645433
>
> Can R compute these?
> Is there any package that does stirlings approximation in R?
>
> --
> Thanks,
> Jim.
>
> [[alter
I have some big combinations like:
choose 784645433
Can R compute these?
Is there any package that does stirlings approximation in R?
--
Thanks,
Jim.
[[alternative HTML version deleted]]
__
R-help@r-project.org ma
Dear list,
Is it possible to specify a contrast in options() that would create an
identity matrix for each factor in the model matrix?
For example, for each factor in 'dd' below, I can create an identity matrix
using contrasts = FALSE. Is it possible to set this in options(), so when I
create a mo
I asked because I thought it'd solve an issue I had. I was actually being
quite rash in asking this question and for that, I apologize.
I wanted to know because I was attempting to create a heatmap where the NA
values would not be shown while all the outputs with actual numerical value
will be sho
Does the following work for you?
> df2 <- transform(df, ObsID=ave(rep(0,length(Group)), Group,
FUN=seq_along))
> head(df2)
Value Group ObsID
1 -0.0025132 B 1
2 -1.2456156 A 1
3 -2.0531704 B 2
4 1.5861770 B 3
5 0.1900908 A 2
6 0.7197067
If I have a data frame something like:
Value=rnorm(30)
Group = sample(c('A','B','C'), 30, replace=TRUE)
df = data.frame(Value, Group)
It seems like it should be simple to create an 'ObsID' column which indicates
the observation order of each Value within each of the 3 groups. Somehow, I
can't q
Look at:
de Jong, P. and Penzer, J. (1998) Diagnosing shocks in time series. Journal of
the American Statistical Association. 93, 796-806.
A pdf is available at:
http://stats.lse.ac.uk/penzer/publications.html
-Roy M.
On May 9, 2011, at 1:32 PM, jpehsani wrote:
> Hi Berta,
>
> Did you have
Wow that is really interesting,
Sorry I was asleep when you emailed these.
And yes, of course, I had been trying to implement model 18, not 18s,
that was a typo, sorry.
I will have a look at the code you posted.
Thanks,
Alex
On 10 May 2011 02:18, peter dalgaard wrote:
> Hmm, I tried replacin
Hi Berta,
Did you have any luck finding code for the gradual permanent impact
intervention?
I am trying to fit two types of intervention effects for two different
models - a gradual and a sudden impact effect - and unable to find any code
on how to do this.
thanks
Jon
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View this message in c
An easy way to average every 30 minutes is using the aggregate function. First
I use the mod (%%) to get times as the next earliest possible 30 min time
increment.
bTime<- as.POSIXct(c( "2011-04-28 09:02:00 CDT","2011-04-28 09:02:00
CDT","2011-04-28 09:12:00 CDT","2011-04-28 09:14:00 CDT","20
John Kane's reply sums it up! (Though you could use "",
instead of " ", which would give you an "empty string"
instead of the "space" character; but the resulting
matrix would still consist entirely of "character"
elements).
However, the real reason I am following up is to ask
why you want the bla
On May 9, 2011, at 3:46 PM, David Winsemius wrote:
On May 9, 2011, at 9:40 AM, Pavan G wrote:
Hello All,
Let's say I have points on a x-y plane. x ranges from 0-2 and y
from 0-2.
There are points in quadrants x[0:1]---y[0:1] and in x[1:2]
y[1:2]. I
would like to get the mean and std o
Thank you kind sir!
On Mon, May 9, 2011 at 3:25 PM, John Kane wrote:
>
> (mat <- matrix(c(1,2,3,NA),2))
> mat[is.na(mat)] <- " "
> mat
>
> But if you have a numerical matrix it coverts the matrix to character.
>
> --- On Mon, 5/9/11, Dat Mai wrote:
>
> > From: Dat Mai
> > Subject: [R] Setti
On May 9, 2011, at 9:40 AM, Pavan G wrote:
Hello All,
Let's say I have points on a x-y plane. x ranges from 0-2 and y from
0-2.
There are points in quadrants x[0:1]---y[0:1] and in x[1:2]
y[1:2]. I
would like to get the mean and std of the points in the x[0:1]
y[0:1]
quadrant alone
Dear Gabor,
Thanks for your help. I was trying to do what you ask me and I've found the
solution.
> with(teste,sprintf("INSERT INTO OBS (date,T_2M,TMAX_2M,TMIN_2M) VALUES
(%s, %5.2f, %5.2f, %5.2f,%s)",date2,T_2M,TMAX_2M,TMIN_2M,Station_NO))
Error in sprintf("INSERT INTO OBS (date,T_2M,TMAX_2M,TMI
(mat <- matrix(c(1,2,3,NA),2))
mat[is.na(mat)] <- " "
mat
But if you have a numerical matrix it coverts the matrix to character.
--- On Mon, 5/9/11, Dat Mai wrote:
> From: Dat Mai
> Subject: [R] Setting NA to blank
> To: r-help@r-project.org
> Received: Monday, May 9, 2011, 2:46 PM
> Hey A
Hi,
On Mon, May 9, 2011 at 9:40 AM, Pavan G wrote:
> Hello All,
> Let's say I have points on a x-y plane. x ranges from 0-2 and y from 0-2.
> There are points in quadrants x[0:1]---y[0:1] and in x[1:2]y[1:2]. I
> would like to get the mean and std of the points in the x[0:1]y[0:1]
> quadr
All right then--I shall get bash away. Thanks a lot.
On Mon, May 9, 2011 at 2:55 PM, Deepayan Sarkar
wrote:
> On Mon, May 9, 2011 at 8:23 PM, Dat Mai wrote:
> > Thanks for the help! Though, when I do this, I get a message saying
> "Error
> > using packet 1 value where TRUE/FALSE." Would that hav
On Mon, May 9, 2011 at 8:23 PM, Dat Mai wrote:
> Thanks for the help! Though, when I do this, I get a message saying "Error
> using packet 1 value where TRUE/FALSE." Would that have anything to do with
> this set of code?
It might. (As we don't know what you "did", we can't really say.)
> On Sun
Hey All,
I have a matrix m, and I wish to set all the NA values to blank. How would I
do so?
--
Best,
Dat Mai
PhD Rotation Student
Albert Einstein College of Medicine
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h
On 09/05/2011 11:57 AM, Ron Michael wrote:
Dear all, I would really appreciate if somebody can help me to understand what does the
phrase "Vectorize your function" mean? And what is the job of Vectorize()
function in doing that? I have read many threads where experts suggest to Vectorize the
f
On 09/05/2011 1:31 PM, David Winsemius wrote:
On May 9, 2011, at 11:57 AM, Ron Michael wrote:
> Dear all, I would really appreciate if somebody can help me to
> understand what does the phrase "Vectorize your function" mean? And
> what is the job of Vectorize() function in doing that? I have
Is there R software available for doing approximate matching of personal
names?
I have data about the same people produced by different organizations and
the only matching key I have is the name. I know that commercial solutions
exist, and I know I code code this from scratch, but I'd prefer to bu
One way, assuming your timestamps are POSIXct format:
truncInterval <- function ( x, dx=as.difftime(1,units="days") ) {
xn <- as.numeric( x )
result <- xn - xn %% as.numeric( dx, units="secs" )
class( result ) <- 'POSIXct'
result
}
truncInterval( as.POSIXct(c("2011-04-28 09:20:00", "2011-04-28 09
On Mon, May 9, 2011 at 10:20 AM, Nicole Gross-Camp
wrote:
> I have what I hope is a simple question - is it possible to do time series
> analysis on a small data set specifically only four data points?
>
>
>
> I have collected human threat data (mean number of threats per kilometre
> walked/ surve
Hi
I have fitted an arima model to a monthly series of length 113.
I have use
fit <- arima(x.ts, order = c(1,0,0),seas = list(order = c(1,2,1),12, method
= "CSS")
I'm a little confused because the series of residual has the first 46 values
equal to 0. From there the residuals are approximately
I am trying to call a FORTRAN subroutine from R. is.loaded is turning out to
be TRUE. However when I run my .Fortran command I get the following error:
Error in .Fortran("VALUEAHROPTIMIZE", as.double(ahrArray),
as.double(kwArray), :
Fortran symbol name "valueahroptimize" not in load table
On May 9, 2011, at 11:57 AM, Ron Michael wrote:
Dear all, I would really appreciate if somebody can help me to
understand what does the phrase "Vectorize your function" mean? And
what is the job of Vectorize() function in doing that? I have read
many threads where experts suggest to Vector
On Mon, May 9, 2011 at 12:59 PM, Nilza BARROS wrote:
> Hi, Thanks for your attentio.
>
> I have the data frame below:
>
>> head(Alldados)
> Station_NO date1 T_2M TMAX_2M TMIN_2M TD_2M PS FF_10M DD_10M
> 1 820420 110429/1200 22.5 NULL 22.4 22.2 NULL 0 0
> 2
Hi, Thanks for your attentio.
I have the data frame below:
> head(Alldados)
Station_NO date1 T_2M TMAX_2M TMIN_2M TD_2M PS FF_10M DD_10M
1 820420 110429/1200 22.5NULL22.4 22.2 NULL 0 0
2 820980 110429/1200 26.9NULL23.4 24.1 1010.2 2.9136
What is L_square? Is it Likelihood ratio/deviance statistic which is
reported by poLCA?
The predcell component contains observed and expected, isn't it easy
to get the residuals?
If you want the logit/logistic model, glm or lrm (rms) can do the job.
It is unrealistic to expect different software
You certainly can't assign a character string into a numeric column.
There is no reason to expect that to work.
Can you provide some clarity on what the problem is in terms of a very
small self contained example explaining what you get and what you
expected to get.
Regards.
On Mon, May 9, 2011 a
Dear Ruser,
Thank for your help.
I've just tried the command below and it works
Alldados[is.na(Alldados)]<-"NULL"
But I am facing other problem, since I need to format my data before feeding
my database.
I am using the command below:
with(Alldados,sprintf("INSERT INTO OBS
(date,T_2M,TMAX_2M,TMI
Dear all, I would really appreciate if somebody can help me to understand what
does the phrase "Vectorize your function" mean? And what is the job of
Vectorize() function in doing that? I have read many threads where experts
suggest to Vectorize the function, which will speed up entire calculati
Basically I do LCA, followed by some kind of analysis intended to validate the
solutions. For example, I would create latent class solutions for each gender
based on four dichotomic indicators of psychosis. Next, I would look at the
interaction of current psychiatric status (the classes) and p
Sure, sorry for not clarifying from the beginning.
LEM is a rather powerful software for conducting general loglinear analysis,
including latent class, logit, latent Markov, Event History models, etc. It's
very polyvalent.
Link to the software and document is at
http://www.tilburguniversity
On May 9, 2011, at 10:07 AM, Nilza BARROS wrote:
Dear R users,
I am reading data from a file where there are some missing that are
represented by -.00.
I am using the command below.
=My original data ===
PARM = TMPC;T12X;T12N;DWPC;PALT;SKNT;DRCT;P24M;CLCL
snipped
But I nee
On 2011-05-08 16:41, Worik R wrote:
Friends
I am trying to format a number to a string so 2189.745 goes to "2,189.35"
and 309283.929 goes to "309,283.93"
I have tried to use formatC(X, big.mark=",",drop0trailing=FALSE, format="f")
but it does not get the number of decimals correct. Specifying
I would use package chron and trunc()
One example from the help of trunc.times (modified):
lirary(chron)
tt <- times(c("12:13:14", "15:46:17"))
trunc(tt, times("00:30:00"))
HTH
Jannis
--- Schatzi schrieb am Mo, 9.5.2011:
> Von: Schatzi
> Betreff: [R] Round down to earliest hour or half
Hi
r-help-boun...@r-project.org napsal dne 09.05.2011 16:07:27:
> Nilza BARROS
> Odeslal: r-help-boun...@r-project.org
>
> 09.05.2011 16:07
>
>
> Dear R users,
>
> I am reading data from a file where there are some missing that are
> represented by -.00.
> I am using the command below.
Although this is not an R question actually, if I get such a
question in our consulting centre, my advice is:
Present a table of your 4 observations and that's it from a
quantitative point of view. There is no sense in modelling or testing
with 4 observations.
Best,
Uwe Ligges
On 09
Dan Abner wrote:
> I am attempting to use the %in% operator with the ! to produce a NOT IN
> type of operation.
Just use the ‘%nin‰’ operator in the ‘Hmisc’ package. :-)
--
Karl Ove Hufthammer
__
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https://stat.ethz.ch
I have what I hope is a simple question - is it possible to do time series
analysis on a small data set specifically only four data points?
I have collected human threat data (mean number of threats per kilometre
walked/ survey) every 3 months in eight different sites (four with an
experimenta
Thanks for the help! Though, when I do this, I get a message saying "Error
using packet 1 value where TRUE/FALSE." Would that have anything to do with
this set of code?
On Sun, May 8, 2011 at 3:00 PM, Deepayan Sarkar
wrote:
> On Fri, May 6, 2011 at 10:21 PM, Dat Mai wrote:
> > Hello all,
> >
> >
Trolling? (but see in line below)
On Mon, May 9, 2011 at 5:12 AM, Martyn Byng wrote:
> I wonder if someone with more experience than me on using R to summarise
> by group wants to post a reply to this
>
> http://www.analyticbridge.com/group/sasandstatisticalprogramming/forum/t
> opics/why-still-u
Hmm, I tried replacing the x's in the model with their principal component
scores, and suddenly everything converges as a greased lightning:
> Z <- princomp(cbind(x1,x2,x3))$scores
> Z <- as.data.frame(princomp(cbind(x1,x2,x3))$scores)
> names(Z)<- letters[1:3]
> optimx(rep(0,8),lnl, hessian=TRUE
Dear R users,
I am reading data from a file where there are some missing that are
represented by -.00.
I am using the command below.
=My original data ===
PARM = TMPC;T12X;T12N;DWPC;PALT;SKNT;DRCT;P24M;CLCL
STNYYMMDD/HHMM TMPC T12X T12N DWPC PALT
SKN
I have times and would like to round down to the earliest 30 minute
increment. For instance, a time of
2011-04-28 09:02:00
(the as.numeric value = 1303999320)
I would like it to be rounded down to:
2011-04-28 09:00:00
(the as.numeric value = 1303999200)
Any ideas of how to do this?
-
In theo
Thank you very much all for your time.
For now I am doing this with a simple for loop as some times lapply,sapply
makes things more complex
(or in other words I am not that experience using it).
Best REgards
Alex
--- On Mon, 5/9/11, Patrick Breheny wrote:
> From: Patrick Breheny
> Subject: R
On 05/09/2011 09:52 AM, Duncan Murdoch wrote:
In general, the expression x[[1:2]] is not meaningful, as the elements
of the list may be of different type, with no way to concatenate them.
That's the wrong explanation: the expression x[[1:2]] is meaningful,
but it means the same thing as x[[1]]
On 09/05/2011 9:18 AM, Patrick Breheny wrote:
On 05/09/2011 08:58 AM, Alaios wrote:
> Dear all,
> I would like to ask your help concerning an error message I get.
>
> I have the following struct
>
> str(CRagentInTime[[1]])
> List of 2
>$ timelag: int 0
>$ CRagent:List of 50
> ..$
On 05/09/2011 09:24 AM, Alaios wrote:
So the only thing that might work is a for..loop to collect all these together?
Best REgards
Alex
You could also use sapply:
x <- list(list(One="a",Two=c("b","c")),list(One="d",Two=c("e","f")))
sapply(x,'[[',"Two")
[,1] [,2]
[1,] "b" "e"
[2,] "c"
Hello All,
Let's say I have points on a x-y plane. x ranges from 0-2 and y from 0-2.
There are points in quadrants x[0:1]---y[0:1] and in x[1:2]y[1:2]. I
would like to get the mean and std of the points in the x[0:1]y[0:1]
quadrant alone. Is there a straight forward way to do it?
I asked a
On May 9, 2011, at 15:24 , Alaios wrote:
> So the only thing that might work is a for..loop to collect all these
> together?
An implicit loop using lapply/sapply might be more like it:
lapply(CRagentInTime[[1]]$CRagent[1:10], "[[", "sr")
Notice that fancy indexing usually requires "[", not "[
So the only thing that might work is a for..loop to collect all these together?
Best REgards
Alex
--- On Mon, 5/9/11, Patrick Breheny wrote:
> From: Patrick Breheny
> Subject: Re: [R] Recursive Indexing Failed
> To: "Alaios"
> Cc: "R-help@r-project.org"
> Date: Monday, May 9, 2011, 2:18 PM
>
On 05/09/2011 08:58 AM, Alaios wrote:
Dear all,
I would like to ask your help concerning an error message I get.
I have the following struct
str(CRagentInTime[[1]])
List of 2
$ timelag: int 0
$ CRagent:List of 50
..$ :List of 3
.. ..$ CRmap: num [1:256, 1:256] NA NA NA NA NA NA NA NA
On Mon, May 9, 2011 at 5:42 PM, David Winsemius wrote:
>
> On May 9, 2011, at 12:35 AM, Deepayan Sarkar wrote:
>
>> On Mon, May 9, 2011 at 2:20 AM, Thomas Lumley wrote:
>>>
>>> On Mon, May 9, 2011 at 6:35 AM, Deepayan Sarkar
>>> wrote:
On Sat, May 7, 2011 at 1:55 AM, Raphael Mazor
>>>
Dear all,
I would like to ask your help concerning an error message I get.
I have the following struct
str(CRagentInTime[[1]])
List of 2
$ timelag: int 0
$ CRagent:List of 50
..$ :List of 3
.. ..$ CRmap: num [1:256, 1:256] NA NA NA NA NA NA NA NA NA NA ...
.. ..$ xy : num [1:2] 10 177
On May 9, 2011, at 13:40 , Alex Olssen wrote:
> Hi Mike,
>
> Mike said
> "is this it, page 1559?"
>
> That is the front page yes, page 15*6*9 has the table, of which the
> model labelled 18s is the one I replicated.
>
However, the R code you posted will at best replicate model 18. For 18s, yo
On 05/09/2011 01:19 AM, Pawan Kakchingtabam wrote:
Sir,
Kindlly Guide me how to get the R CELFILES. I have install R but I cannat asses
the command:
Data<- ReadAffy()
and I got the error:
Error in AllButCelsForReadAffy(..., filenames = filenames, widget = widget, :
No cel filennames speci
> Dear users,
>
> In a study with recurrent events:
> My objective is to get estimates of survival (obtained through a Cox
> model) by rank of recurrence and by treatment group.
> With the following code (corresponding to a model with a global
> effect of the treatment=rx), I get no error and m
Dear all,
I am trying to using a mixed-design ANOVA to analyze my data. I have two
between subject variables: location (2 different locations) and age group
(young and old), and one within-subject variable: valence (positive,
neutral, negative).
I am looking at an Stevens(one between, two within)
Sir,
Kindlly Guide me how to get the R CELFILES. I have install R but I cannat asses
the command:
Data <- ReadAffy()
and I got the error:
Error in AllButCelsForReadAffy(..., filenames = filenames, widget = widget, :
No cel filennames specified and no cel files in specified
directory:C:/Docum
> Date: Mon, 9 May 2011 22:06:38 +1200
> From: alex.ols...@gmail.com
> To: pda...@gmail.com
> CC: r-help@r-project.org; da...@otter-rsch.com
> Subject: Re: [R] maximum likelihood convergence reproducing Anderson Blundell
> 1982 Econometrica R vs Stata
The test in the rms package's residuals.lrm function is the le Cessie - van
Houwelingen - Copas - Hosmer unweighted sum of squares test for global
goodness of fit. Like all statistical tests, a large P-value has no
information other than there was not sufficient evidence to reject the null
hypothe
On May 9, 2011, at 12:35 AM, Deepayan Sarkar wrote:
On Mon, May 9, 2011 at 2:20 AM, Thomas Lumley wrote:
On Mon, May 9, 2011 at 6:35 AM, Deepayan Sarkar
wrote:
On Sat, May 7, 2011 at 1:55 AM, Raphael Mazor
wrote:
Is it possible to create weighted boxplots or violin plots in
lattice?
I
On 09.05.2011 14:03, arnab.ma...@dc.ibm.com wrote:
Dear Uwe,
I already have gone through that document. But I could not find the
solution.
I tiold you that help page points us to the help page for
?DEoptim.control
and that one has an argument "trace".
Please read both, my original message a
Dear Uwe,
I already have gone through that document. But I could not find the
solution.
Thanks & Regards
Arnab Kumar Maity
|| IBM Global Process Services ||
|| 2nd Floor, VBC Solitaire ||
|| 47 & 49, Bazullah Road || T Nagar ||
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|| Email: arnab.ma...@dc.ibm.com ||
On 09.05.2011 13:47, arnab.ma...@dc.ibm.com wrote:
Dear Uwe,
Which help file you are talking about?
The one you get when typing
?DEoptim
which one do you think is more appropriate for getting help on DEoptim ?
Uwe
Thanks& Regards
Arnab Kumar Maity
|| IBM Global Process Services ||
On 9/05/2011 10:40 p.m., Samuel Le wrote:
Dear all,
Is there a function in R to convert a matrix or a data.frame into an html table?
Many thanks,
Samuel
xtable() in the xtable package can do this (at least to some extent). It
is commonly used to write LaTeX but there is an option to prod
Dear Uwe,
Which help file you are talking about?
Thanks & Regards
Arnab Kumar Maity
|| IBM Global Process Services ||
|| 2nd Floor, VBC Solitaire ||
|| 47 & 49, Bazullah Road || T Nagar ||
|| Chennai - 600017 || India ||
|| Email: arnab.ma...@dc.ibm.com ||
|| Ph: +91 8939390048 ||
Hi Mike,
Mike said
"is this it, page 1559?"
That is the front page yes, page 15*6*9 has the table, of which the
model labelled 18s is the one I replicated.
"did you actually cut/paste code anywhere and is your first
coefficient -.19 or -.019?
Presumably typos would be one possible problem."
-0.
Have a look at hwrite() in the hwriter package:
http://www.embl.de/~gpau/hwriter/index.html
If x is a data frame, the following will do it:
> library("hwriter")
> hwrite(x, "x.html")
Cheers,
Greg
---
Gregoire Pau
EMBL Research Officer
http://www.embl.de/~gpau/
On 09/05/11 12:40, Samuel Le wrot
On 08.05.2011 19:54, eric wrote:
I tried to update my packages using update.packages()
I got the following message:
The downloaded packages are in
‘/tmp/RtmpyDYdTX/downloaded_packages’
Warning in install.packages(update[instlib == l, "Package"], l, contriburl =
contriburl, :
'lib
On 09.05.2011 11:06, arnab.ma...@dc.ibm.com wrote:
Dear R users,
During the the running of DEoptim function which belongs to "DEoptim"
package it automatically gives the output like the following:
Iteration: 1 bestvalit: 181.379847 bestmemit:0.2264991.395852
Iteration: 2 bestvalit: 1
Hello, Samuel,
take a look at the package R2HTML.
Hth -- Gerrit
On Mon, 9 May 2011, Samuel Le wrote:
Dear all,
Is there a function in R to convert a matrix or a data.frame into an html table?
Many thanks,
Samuel
-
D
On Thu, 05-May-2011 at 06:13AM -0700, Joel wrote:
|>
|> jholtman wrote:
|> >
|> > a <- readLines(textConnection('setting1="value1"
|> > setting2="value2"
|> > setting3="value3"
|> > setting4="value4"'))
|> > closeAllConnections()
|> > # change values
|> > ac <- sub('setting4="value4"', 'setting
Dear all,
Is there a function in R to convert a matrix or a data.frame into an html table?
Many thanks,
Samuel
[[alternative HTML version deleted]]
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R-help@r-project.org mailing list
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PLEASE do
Peter said
"Ahem! You might get us interested in your problem, but not to the
level that we are going to install Stata and Tsp and actually dig out
and study the scientific paper you are talking about. Please cite the
results and explain the differences."
Apologies Peter, will do,
The results wh
Dear R-help.
I am studying Dataming using R and I am going to make Rule Based
Classification's R code.
But I searched for Rule Based Classification throught Google, I have
failed to find out the package for R.
Would you recommend R some packages which can make Rule Based
Classification?
Best Reg
Dear R users,
During the the running of DEoptim function which belongs to "DEoptim"
package it automatically gives the output like the following:
Iteration: 1 bestvalit: 181.379847 bestmemit:0.2264991.395852
Iteration: 2 bestvalit: 14.062649 bestmemit:2.2903575.597838
Iteration:
On May 9, 2011, at 11:12 , Martyn Byng wrote:
> I wonder if someone with more experience than me on using R to summarise
> by group wants to post a reply to this
Not really (but how did those people manage to overlook by()?). However,
another matter
PLEASE DO NOT BE SO B***DY LAZY AND START A
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