On Apr 8, 2011, at 20:33 , vikas wrote:
> if X is a binomial variate with parameters n and p, find E[1/(X+1)]
>
(A) This is not a list for helping people with their homework
(B) This is to be solved using pencil and paper. R can't help you there.
(C) Once you have a solution, you can check the
Please ignore this message. Just testing something
Apologies for taking up bandwidth.
cheers,
Rolf Turner
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PLEASE do read the posting guide http://www
Hi Ajss,
You instantiated mt as a vector, not a list. Try:
row <- c(3,4,6,4,5)
mt <- vector("list", length(row)) # list with length of "row" elements
for (i in 1:5){
mt[[i]] <- matrix(nrow=row[i], ncol=4)
}
mt
Or in one line:
mt <- lapply(1:5, function(x) matrix(nrow = x, ncol = 4))
mt
Hope th
The two models you fit are quite different. The first is a binomial model
equivalent to
fm <- glm(I(y == "a") ~ x, binomial, df)
which you can check leads to the same result. I.e. this model amalgamates
classes "b" and "c" into one.
The second is a multivariate logistic model that considers
Here's how to do it in Haskell.
First define fibs to be an infinite list. Since Haskell is lazy, the list
isn't actually created until needed.
The function zipWith takes three arguments: a function and two lists. (It is
similar to sapply except that it takes a function and two lists.) It applies
Hi all
I need to deal with a number (say, 5) of diferent ordered matrices
simultaneously in my computational work. I tried to define these matrices
through looping, but got an error message:
row <- c(3,4,6,4,5)
mt <- c()
for (i in 1:5){
mt[i] <- matrix(nrow=row[i],ncol=4)
}
mt
Kindly help
Y
Hi,
I am studying using SVM functions of e1071 package to do prediction, and I
found during the training data are "factor" type, then svm.predict() can
predict data directly by categories; but if response variables are "numerical",
the predicted value from svm will be continuous quantitative nu
Dear R users:
In my research I need to come up with a method to measure the
smoothness for a closed curve (looks like ellipse, but actually not).
I was working on calculating Hurst Exponent using 2 dimensional
dataset.
I checked fArma, Randomfields and several functions in fractal
packages, but c
Hi,
I tried to add a progress bar to my script, but it seems the "txtProgressBar"
function will wipe out what I want to print before it(for example - the "Hello"
in following script), and the parameters "title" and "label" do not work
either. How can I put a title for the progress bar? or is th
The age of this post makes me hope there is an easy response from someone.
When I do the following with Orthodont built-in dataset:
library(nlme)
OrthoFem<-Orthodont[Orthodont$Sex=="Female",]
fm1OrthF.lis<-lmList( distance ~ age,data = OrthoFem)
I get the same error:
Error in function (clas
if X is a binomial variate with parameters n and p, find E[1/(X+1)]
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Dear Tal and Achim:
Thank you both for your assistance.
I followed Achim's suggestions and got what I needed on a Windows machine
with R2.12.2 installed. As I needed to run the task on a Windows machine
with R2.11.1 I used the package rpart.plot (by Stephen Milborrow) to create
my charts.
Best
Thanks for the reply. I looked at this before as I saw you had posted this,
but this either doesn't work in my situation, or I am using it wrong.
Take the example in the function:
tmp <- barplot(1:4)
updateusr(tmp[1:2], 0:1, 1:2, 0:1)
lines(1:4, c(1,3,2,2), lwd=3, type='b',col='red')
But I want
step # 1
?read.csv
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> -Original Message-
> From: r-help-boun...@r-project.org
> [mailto:r-help-boun...@r-project.org] On Behalf Of Benjamin Tyner
> Sent: Friday, April 08, 2011 6:48 PM
> To: r-help@r-project.org
> Subject: [R] best practice(s) for retrieving a local variable
> from a closure
>
> Greetings,
Hi Felipe,
On Fri, Apr 8, 2011 at 7:54 PM, Luis Felipe Parra
wrote:
> Hello, I am runnning a program on R with a "big" number of simulations and
> I am getting the following error:
>
> Error: no se puede ubicar un vector de tamaño 443.3 Mb
>
> I don't understand why because when I check the mem
Hello, I am runnning a program on R with a "big" number of simulations and
I am getting the following error:
Error: no se puede ubicar un vector de tamaño 443.3 Mb
I don't understand why because when I check the memory status in my pc I get
the following:
> memory.size()
[1] 676.3
> memory.siz
?integrate
From: r-help-boun...@r-project.org [r-help-boun...@r-project.org] On Behalf Of
cindy Guo [cindy.g...@gmail.com]
Sent: Friday, April 08, 2011 9:21 PM
To: r-help@r-project.org
Subject: [R] integration
Hi, All,
I have a density function with 3 v
try this:
> a=c(2,NA,NA,NA,2,2,NA,2,NA,2)
> b=c(NA,1,1,NA,2,2,2,2,2,2)
> c1 <- ifelse((!is.na(a) & a == 1) | (!is.na(b) & b == 1)
+ , 1
+ , ifelse((!is.na(a) & a == 2) | (!is.na(b) & b == 2)
+ , 2
+ , NA
+ )
+ )
> cbind(a, b, c1)
On Fri, Apr 8, 2011 at 9:48 PM, Benjamin Tyner wrote:
> Greetings,
>
> Say I have defined
>
> mp <- function(a) function(x) x^a
>
> f2 <- mp(2)
>
> and I would like to retrieve the "a" which is local to f2. Two options come
> to mind;
>
> get("a", envir=environment(f2))
> eval(substitute(a), e
Greetings,
Say I have defined
mp <- function(a) function(x) x^a
f2 <- mp(2)
and I would like to retrieve the "a" which is local to f2. Two options
come to mind;
get("a", envir=environment(f2))
eval(substitute(a), environment(f2))
I'm curious if one of these is preferred over the other
Hi, All,
I have a density function with 3 variables which is defined on some
irregular domain, and I want to get the marginal distribution of each
variable. Is there any function doing this?
A simple example is p(x,y,z)=x*y*z*I(xy>z). So each marginal distribution is
a function of the other two v
Thanks Deepayan!
I neglected to mention that I would want to retain ticks as well for the
boxed panel(s), so perhaps something like
xyplot(y ~ x|f,
data = Data,
layout=c(2,1),
scales=list(relation="free",alternating=FALSE),
par.settings = list(axis.line=list(col = "tran
Perfect. Thank you.
-Mitch
-Original Message-
From: Phil Spector [mailto:spec...@stat.berkeley.edu]
Sent: Friday, April 08, 2011 8:03 PM
To: Downey, Patrick
Cc: r-help@r-project.org
Subject: Re: [R] Finding elements in a character vector
match(list.a,list.b)
match(list.a,list.b)
- Phil Spector
Statistical Computing Facility
Department of Statistics
UC Berkeley
Hello,
I have two character vectors: list.a and list.b. Every element of list.a
appears somewhere in list.b. Not all elements of list.b are in list.a, and
some elements of list.b appear multiple times in list.a. I want to create a
new vector (index) of the same length as list.a where the nth eleme
On 11-04-08 4:56 PM, Rice, Terri wrote:
Hi. I am trying to run perl script from R. Here's what happens.
setwd("C:\\Terri\\perl")
getwd()
[1] "C:/Terri/perl"
list.files()
[1] "hello.pl" "lines1_10.txt" "try_my.pl" "try_my.txt"
system("hello.pl")
Warning message:
In system("hello.pl
As pointed out by Ista, please read the help file.
"write.csv and write.csv2 provide convenience wrappers for writing CSV files.
They set sep, dec and qmethod, and col.names to NA if row.names = TRUE and
TRUE otherwise. "
From: John Kane
To: r-help ; San
Do you mean a test something such as this?
> fisher.test(matrix(c(502,498,490, 510), nrow = 2))
Fisher's Exact Test for Count Data
data: matrix(c(502, 498, 490, 510), nrow = 2)
p-value = 0.6228
alternative hypothesis: true odds ratio is not equal to 1
95 percent confidence interval:
I believe write.csv had been revamped and some options are no longer available.
--- On Fri, 4/8/11, Santosh wrote:
> From: Santosh
> Subject: [R] a bug in "write.csv"?
> To: "r-help"
> Received: Friday, April 8, 2011, 4:18 PM
> Dear Rxperts!
>
> A simple example where "write.csv" does not see
Dear R users,
I am using package mice and I am getting the error "
Error in if (meth[j] != "") { : argument is of length zero." I have tried using
several different versions of R (even the one that will be coming out this
month) to no avail. I am using RStudio as my interface with R. Also note t
Hi. I am trying to run perl script from R. Here's what happens.
> setwd("C:\\Terri\\perl")
> getwd()
[1] "C:/Terri/perl"
> list.files()
[1] "hello.pl" "lines1_10.txt" "try_my.pl" "try_my.txt"
> system("hello.pl")
Warning message:
In system("hello.pl") : Impossible to run C:\Terri\perl\hel
Please read the documentation where this is clearly explained. See ?write.csv
Best,
Ista
On Fri, Apr 8, 2011 at 4:18 PM, Santosh wrote:
> Dear Rxperts!
>
> A simple example where "write.csv" does not seem to accept user specified
> arguments.. Why?
>
> write.csv(t(1:10),"./te1.csv",quo=F,col.nam
Dear Rxperts!
A simple example where "write.csv" does not seem to accept user specified
arguments.. Why?
write.csv(t(1:10),"./te1.csv",quo=F,col.names=F)
Warning message:
In write.csv(t(1:10), "./te1.csv", quo = F, col.names = F) :
attempt to set 'col.names' ignored
However, write.table does
Hello,
I am interested in using the hscat command in the gstat package to create
h-scatterplots of snow depth measurements over a given area (spatial
autocorrelation). Unfortunately I do not understand how to format my data
for import into R for use with the hscat command. I have checked the gstat
On 04/08/2011 11:11 AM, Doug Elias wrote:
Greetings, all ...
I'm trying to find documentation on the use of the "local()" function, and
am drawing a complete blank; would someone please send me a pointer to where
I can learn what it is intended for, and how to correctly use it?
Hi Doug --
?lo
Hi,
The problem is that (a == 1 | b == 1) returns some NAs. NAs are not
treated as strictly TRUE or FALSE. From the documentation (see
?ifelse) "Missing values in 'test' give missing values in the result".
You need to use a construct designed to force a TRUE/FALSE value OR
something that handle
On 08/04/2011 2:11 PM, Doug Elias wrote:
Greetings, all ...
I'm trying to find documentation on the use of the "local()" function, and
am drawing a complete blank; would someone please send me a pointer to where
I can learn what it is intended for, and how to correctly use it?
Try ?local. As
Hi Tal:
Thanks for your quick reply.
I tried to create a classification tree.
The problem is that the branches overlap the text in the ellipses (inner
nodes) and rectangles (terminal nodes) - At times this makes it difficult
for the reader to correctly process the results. One way to overcome
Greetings, all ...
I'm trying to find documentation on the use of the "local()" function, and
am drawing a complete blank; would someone please send me a pointer to where
I can learn what it is intended for, and how to correctly use it?
Many thanks!
Doug
[[alternative HTML version delet
I have used R for years but run into a seemingly simple problem involving
'ifelse'. condensed code like this
a=c(2,NA,NA,NA,2,2,NA,2,NA,2)
b=c(NA,1,1,NA,2,2,2,2,2,2)
#I want to combined a and b into c so that c would be a valid number either a
or b is not missing
c=ifelse(a==1|b==1,1,ifelse
HI,
Thank you, I will try this, and let you know about the results.
Thanks once again.
Gauri
2011/4/8 Steve Lianoglou
> Hi,
>
> First: Please make sure you CC R-help when responding to messages on
> the list so that more people can help you, and more people can benefit
> from help that is prov
Hi Achim:
I will give it a try and let you know how it goes.
Thanks.
Tudor
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Greetings All!
After much trial and error, and an exhaustive search of the archives, I'm
writing to solicit help with a problem.
I want to dynamically modify variable names and values as function arguments
inside a loop.
I have a canned function from a package that takes ellipsis (...) arguments
Try
Sys.setenv("LANGUAGE"="Fr")
Uwe Ligges
On 07.04.2011 10:29, Raji wrote:
Hi R-helpers,
Is it possible to localise the error messages/warnings that comes from
R.My application takes in a locale information.I used the following command
to set the locale in R.But in RGui, i still get the e
On 2011-04-08 09:26, Ben Bolker wrote:
Brittain Briber yahoo.com> writes:
Do you two or anyone
else out there happen to know if it is possible to specify the
width of the intervals in windrose? Is there
a parameter that I can pass along that would do this?
Below is a reproducible scri
I believe the solutions proposed ignore the recursive nature of the
original problem and hence produce wrong solutions.
P <- c(5, 7, 6.01, 6.01, 7)
m <- rep(6, 5)
S0 <- as.numeric(P>(m*1.005))
Then the original loop from Worik gives
S <- S0
for(i in 2:length(S)){
if(S[i]==0 && S[i-1] == 1){
Hi,
First: Please make sure you CC R-help when responding to messages on
the list so that more people can help you, and more people can benefit
from help that is provided. You can do so easily by replying with
"reply-all."
Now:
Look at the help for the lars function:
R> ?lars
You'll see that `x
1. I am not an expert on this.
2. However, my strong prior would be no, since because it is "exact" it has
to calculate all the possible configurations and there are a lot to
calculate with the values of n1 and n2 you gave.
-- Bert
On Fri, Apr 8, 2011 at 9:43 AM, Jim Silverton wrote:
> Is anyon
Thank you all for the astoundingly quick responses. I think that the
bounding open/closed braces approach sounds like the easiest solution for
the moment -- though I look forward to seeing this all automated in a future
version of R :)
Incidentally, I have indeed encapsulated much of the code as
Dear all,
Do you know how to check redundancy of variables and reduce the dimension in R?
It seems PCA can do this. Is there any other better way to implement in R? Many
thanks!
Bill
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Hi R community,
I posted a question on using the R maximum likelihood functions a short
while ago and got an email saying that some of the content was
"unprocessed". Hence, I am reposting the question just to be sure (sorry for
the multiple emails if both reached you).
My question is reagarding t
On 08/04/2011 1:29 PM, Jonathan P Daily wrote:
Would options(error = recover) be of some help?
No, that will probably be very confusing. The problem is that the
Windows GUI uses Ctrl-R as a short form of "cut from the editor, paste
to the console", and it will paste the whole text regardless
Hi:
After a number of false starts, I finally consulted Deepayan's book and the
example on p. 73, suitably adapted, yielded a solution. Add a variable for
the labels and then...
df$lab <- rep(1:6, each = 3)
bwplot(dv ~ f1 | f2, data = df, ylim = c(0.5, 1),
panel = function(x, y, ..., subscripts)
Would options(error = recover) be of some help?
--
Jonathan P. Daily
Technician - USGS Leetown Science Center
11649 Leetown Road
Kearneysville WV, 25430
(304) 724-4480
"Is the room still a room when its empty? Does the room,
the thing itself have purpose? Or do
Dear Peter,
Quantile regression is a nice tool but one that requires some statistical
training in order to use it and interpret the results properly. I suggest
backing up a bit.
Frank
Sheldrick,
Peter (Specialty Casualty UW Support) wrote:
>
> Sir or Madam:
>
> I am new to R and the
On 08/04/2011 12:40 PM, William Dunlap wrote:
Put an open brace in the first line of your file
and a close brace in the last line.
This shares an advantage with the method I suggested: if there's a
syntax error somewhere in the script, *nothing* will be executed. It
has the disadvantage of
Some of the functions that were the first in the TeachingDemos package were
originally written to help me visualize something, so it is not just teachers
demoing, but people demoing to themselves. It has become a bit of a misc
package with several utilities that are useful in themselves, but wh
Is anyone aware of a fast way of doing fisher's exact test for a series of 2
x 2 tables in R? The fisher.test is really slow if n1=1000 and n2 = 1000.
--
Thanks,
Jim.
[[alternative HTML version deleted]]
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ht
Put an open brace in the first line of your file
and a close brace in the last line.
I encourage people with scripts long enough that this
is a problem to divide up their work into functions
that a shorter script calls. (This is akin to UCSD
Pascal on the Osbourne II that refused to deal with
a f
On 08/04/2011 11:47 AM, algorimancer wrote:
I too am encountering this problem. When I have a large script, if I select
all in the editor and then ctrl-r to run, if it encounters a stop() function
it simply prints an error message and continues to execute the remainder of
the script, as opposed
On 08/04/2011 9:20 AM, DEBERGH Patrick wrote:
hello
I am at the very beginneing of using the R program
I just don't understand how one can save a programfile
For exemple, if I type in R 23+456 and want to save this file under a ceratin
name to reload it later, i just don't get the way to do
Look at the updateusr function in the TeachingDemos package.
--
Gregory (Greg) L. Snow Ph.D.
Statistical Data Center
Intermountain Healthcare
greg.s...@imail.org
801.408.8111
> -Original Message-
> From: r-help-boun...@r-project.org [mailto:r-help-bounces@r-
> project.org] On Behalf Of
I too am encountering this problem. When I have a large script, if I select
all in the editor and then ctrl-r to run, if it encounters a stop() function
it simply prints an error message and continues to execute the remainder of
the script, as opposed to terminating execution at that line. The qu
Brittain Briber yahoo.com> writes:
> Do you two or anyone
> else out there happen to know if it is possible to specify the
> width of the intervals in windrose? Is there
> a parameter that I can pass along that would do this?
> Below is a reproducible script in which you can see
> the uneven
For simple permutation tests I usually just code it up in regular R without
worrying about any packages. R is powerful enough that it is simple to do a
permutation test in only a few lines ( or sometimes just one long line). And
that way you know exactly what it is doing.
--
Gregory (Greg) L
On 08/04/2011 9:16 AM, nferr...@fceia.unr.edu.ar wrote:
I'm working in Rosario, Argentina, trying to plot some contours.
I found the function "draw.contour" created by James Forester at
R-bloggers. If you take a look at that function you'll see it's very
useful!
But I have a problem with it and
On Fri, 8 Apr 2011, tudor wrote:
Dear useRs:
I try to plot an rpart object but cannot get a nice tree structure plot. I
am using plot.rpart and text.rpart (please see below) but the branches that
connect the nodes overlap the text in the ellipses and rectangles. Is there
a way to get a clean
Thanks
That is it really simple.
Ronaldo
Em 08-04-2011 07:48, Mario Valle escreveu:
> paste(teste, collapse="+")
>
> ciao!
> mario
>
> On 08-Apr-11 12:44, Ronaldo Reis Junior wrote:
>> teste <- c("A","B","C")
>
--
1ª lei - Suas férias começam após a defesa e entrega de sua dis
Hi,
On Fri, Apr 8, 2011 at 10:33 AM, gauri j wrote:
> hi,
> I have problem in following code, error is occurred. I have attached my data
> herewith. and my code is as following,
>> library(lars)
> Loaded lars 0.9-8
> Warning message:
> package 'lars' was built under R version 2.12.2
>> x<- read.t
I'm assuming that English is not your first language. In light of that, I
would suggest that you post your question in a language that we both
speak: R. Please include:
1) E-step and M-step functions.
2) The proposed optim/maxLik call.
Mostly because (at least optim) does not have a parameter c
Thanks a lot, Jeremy!
It's working perfectly.
With best regards
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Dear users,
I want to set up R to use one R-script directory and one R-library (directory
for packages) for many end-users. I try to do this by using one network-share.
This works fine as long as we don't use the snowfall package with parallel=TRUE
(sfInit(parallel=TRUE, cpus=4, type="SOCK")
I have been trying ot post through R-help and it asks me to subscribe. I have
subscribed may times but did not get a confirmation. can you check to see what
is wrong with my subscription. I can not post on the R-help mailing list at
this
time.
thanks
[[alternative HTML version
hello
I am at the very beginneing of using the R program
I just don't understand how one can save a programfile
For exemple, if I type in R 23+456 and want to save this file under a ceratin
name to reload it later, i just don't get the way to do it
I can save it with the save function;I achei
I'm working in Rosario, Argentina, trying to plot some contours.
I found the function "draw.contour" created by James Forester at
R-bloggers. If you take a look at that function you'll see it's very
useful!
But I have a problem with it and James is trying to help me (but also
asked me to seek fo
Hi!
I'm very new user of R! I need to learn more about! My problems are to
create a time series with exiting data and to make an study:
1 ) I have column with DD-MM-YR, to transform from string text to date,
and use it as to use as time series, I've made the transformation with
command "as.d
Hi,
I am trying to add text to the bottom of a lattice bwplot with
multiple panels. I would like to add a label below each boxplot, but
the labels do not come from the data. I've tried the following, code:
f1 <- c(rep(c(rep("a", 3), rep("b", 3), rep("c", 3)), 2))
f2 <- c(rep("A", 9), rep("B", 9
Sir or Madam:
I am new to R and the use of quantile regeression. In addition, I am a
finance person not a true statistcian. Basic regression form is Y =
(Coefficient * Variable) + Error Term
I have results from a quantile regression where I used the Barro and
Roberts method with bootstrapping f
Dear Sir\ Madam
I am trying to maximise a complicated loglikelihood function via EM algorithm
which consists of two step "E-step and M-step"and in this case I need to
maximize the expected of like lihood function " which I get from E- step" and
take those estimates of parameter to update the E
Sorry, I left out the names() function in the last step.
Try this instead:
x <- data.frame(cbind(id=c(1,2,2,2,3,3,4,5,6,6), value=1:10))
id.table <- table(x$id)
x_new <- subset(x, id %in% names(id.table[id.table > 1]))
Jeremy
__
R-help@r-project.org mai
Running a binary logit model on the data
df <- data.frame(y=sample(letters[1:3], 100, repl=T),
x=rnorm(100))
reveals some residual deviance:
summary(glm(y ~ ., data=df, family=binomial("logit")))
However, running a multinomial model on that data (multinom, nnet)
reveals a residual deviance:
As I understand it, you are trying to subset the data frame to include only
rows with a non-unique id.
Try this:
x <- data.frame(cbind(id=c(1,2,2,2,3,3,4,5,6,6), value=1:10))
id.table <- table(x$id)
x_new <- subset(x, id %in% id.table[id.table > 1])
Jeremy
___
paul4 wrote:
>
> Hello all,
>
> I am new in R language . I want to forecast a univariate time series by
> arima model. Could you please help me finding a good document that
> describes this problem by a simple example and step by step ?
>
?arima
and follow the links in the "See also" section
Hi:
This seems to 'work':
xyplot(circumference~age, dat, groups=Tree, type='l',
col.line = c('red', 'blue', 'blue', 'red', 'red'))
After a little more fiddling around, this also works, and seems a bit less
kludgy:
dat$group2 <- factor(dat$group, labels = c('red', 'blue'))
xyplot(circu
Hello R users,
I have a problem to delete rows in a table which are not duplicated in order
of an id number
a short example:
x <- data.frame(cbind(id=c(1,2,2,2,3,3,4,5,6,6), value=1:10))
x_new <- x[which(duplicated(x$id)),]
> x_new
id value
3 2 3
4 2 4
6 3 6
10 610
Hi Chris,
Sorry for the late response. The following selects all students that have
never been suspended:
> with(susim, tapply(sus, id_r, function(x) all(x == 0)))
999881 999886 999890 999892 999896 999897
FALSE TRUE TRUE TRUE FALSE TRUE
> r <- with(susim, tapply(sus, id_r, function(x
Dear Tomas,
On Fri, 8 Apr 2011 10:24:45 +0200
Tomii wrote:
> Thank you for your response, but these changes doesn't seem to change
> anything, outcomes of effect command is still the same - error.
It's not really possible to help you with so little information; if you send a
reproducible examp
Hadley -
Thanks for your answers. I didnt think of it that way and what you say makes
complete sense. Truthfully, however, I dont care to maintain an equal area for
each increment. When discussing frequency distributions on the rose, having a
diagram with equally spaced intervals would be mor
Hi Tudor,
What type of tree did you create? (classification or regression?)
Could you give an explanation as to what is not looking nice?
Contact
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Philipp,
I would do the following with ggplot2:
# Set up data
require(ggplot2)
dat <- Orange
dat$group <- ifelse(dat$Tree%in%c('1','4','5'), 'A', 'B')
# Specify the ggplot group aesthetic as Tree
g1 <- ggplot(data = dat, aes(x = age, y = circumference, group=Tree))
# Specify the geom_point and
On Apr 8, 2011, at 8:06 AM, Philipp Pagel wrote:
Dear ExpeRts,
I am trying to plot a bunch of growth curves and would like to get
some more control over groups and line colors than I seem to have.
Example:
# make some data
dat <- Orange
dat$group <- ifelse(dat$Tree%in%c('1','4','5')
Use 'diff' to determine where the changes are:
> S <- sample(0:1,30,TRUE)
> S
[1] 0 0 1 1 0 1 1 1 1 0 0 0 1 0 1 0 1 1 0 1 1 0 1 0 0 0 0 0 1 0
> which(diff(S) == -1)
[1] 4 9 13 15 18 21 23 29
>
then use the indices for the other processing.
On Thu, Apr 7, 2011 at 10:30 PM, Worik R wrote:
> Fr
On Apr 8, 2011, at 4:24 AM, Tomii wrote:
Thank you for your response, but these changes doesn't seem to change
anything, outcomes of effect command is still the same - error.
Tomas
On Fri, Apr 1, 2011 at 5:03 AM, John Fox wrote:
Dear Tomas,
Write the model as
mreg01 = lm(enep1 ~ enpres *
Dear ExpeRts,
I am trying to plot a bunch of growth curves and would like to get
some more control over groups and line colors than I seem to have.
Example:
# make some data
dat <- Orange
dat$group <- ifelse(dat$Tree%in%c('1','4','5'), 'A', 'B')
# plot
xyplot(circumference~age, dat, gr
Try this:
reshape(rat_dat, direction = 'wide', idvar = 'period', timevar = 'name')
On Fri, Apr 8, 2011 at 4:44 AM, Sandeepa Ramakrishnan <
sandeepa_ramakrish...@yahoo.com> wrote:
>Dear R helpers,
>
> Thanks a lot for your kind help. The xtab function suggested by Mr.
> Henrique Dallazua
Hi:
I didn't see anything on first blush from the mod1 or summary(mod1) objects,
but it's not too hard to compute:
> names(mod1)
[1] "coefficients" "icoef" "var"
[4] "var2" "loglik""iter"
[7] "linear.predictors" "frail" "fvar"
[10] "df"
On Apr 7, 2011, at 9:46 PM, mavkoup wrote:
I have a for loop with counter i and I'm producing plots where I
ultimately
want to label the axes:
"Entry a_i from P^q", where a, P and q are just letters, and i is
the value
of the for loop counter.
I've tried various combinations of paste, ex
Dear useRs:
I try to plot an rpart object but cannot get a nice tree structure plot. I
am using plot.rpart and text.rpart (please see below) but the branches that
connect the nodes overlap the text in the ellipses and rectangles. Is there
a way to get a clean nice tree plot (as in the Rpart Mayo
I installed R 2.12 and it works now, thank you Wolfgang.
Servus
Cheba
> library(metafor)
Error: This is R 2.11.0, package 'metafor' needs >= 2.12.0
2011/4/8 cheba meier
> I have just installed the package as
>
> > install.packages("metafor")
> --- Please select a CRAN mirror for use in this s
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