The reason is the following image
http://img545.imageshack.us/i/maptoregion.jpg/
In the picture above you will find the indexes for each cell.
Also you will see that I place that matrix inside a x,y region that spans from
-1 to 1. I am trying to write one function that will get as argument a (x,y
On Tue, 25 Jan 2011, Tom La Bone wrote:
I recall that my problem on Windows was related to having a number of stray
versions of GTK+ installed. I went back and deleted all versions and
reinstalled the latest GTK+ and that seemed to fix things. However, when I
went to do any work of substance ggo
zerfetzen wrote:
>
> Is it possible in Sweave to put \Sexpr{} inside <<>>? This is a bad
> example, but here goes:
>
> <>
> Age <- 5
> @
>
> <<>>
> x <- \Sexpr{Age}
> @
> ...
>
It's good to have a simplified example, but your's is so much simplified
that it is difficult to understand. I kno
Hi:
>From the function's Description on its help page:
The hazard.ratio.plot function repeatedly estimates Cox regression
coefficients and confidence limits within time intervals. The log hazard
ratios are plotted against the mean failure/censoring time within the
interval.
It would appear
Hi:
Here are two more candidates, using the plyr and data.table packages:
library(plyr)
ddply(X, .(x, y), function(d) length(unique(d$z)))
x y V1
1 1 1 2
2 1 2 2
3 2 3 2
4 2 4 2
5 3 5 2
6 3 6 2
The function counts the number of unique z values in each sub-data frame
with the same x and y
Thanks all. Dennis provided the answer I was looking for - deviance(lm).
Cheers,
Brian
On Tue, Jan 25, 2011 at 8:48 PM, Dennis Murphy wrote:
> Hi:
>
> On Tue, Jan 25, 2011 at 10:36 AM, Greg Snow wrote:
>
>> It is not clear what you are doing or why you are doing it. If you tell
>> us your ul
On Jan 25, 2011, at 9:58 PM, eric wrote:
I want to use diff to take the differences in a column "Close" of a
data
frame "y". But I'd like to do it using the transform function so a
new data
frame is created with a difference column. The problem is that diff
gives
one less than the numbe
Hello I am using the fPortfolio package and I see there is the option in the
model slot "objRisk" which permits the user to define its own objective
function. I have the ebook Portfolio Optimization with Rmetrics and there it
says examples on this option are on the advanced version of the book, whi
Hi,
Is it possible in Sweave to put \Sexpr{} inside <<>>? This is a bad
example, but here goes:
<>
Age <- 5
@
<<>>
x <- \Sexpr{Age}
@
I'm trying to get it to display x <- 5, rather than x <- Age. It's probably
so obvious I'm going to feel sorry for having to ask, just the same, I'm
stumped.
Hi:
On Tue, Jan 25, 2011 at 10:36 AM, Greg Snow wrote:
> It is not clear what you are doing or why you are doing it. If you tell us
> your ultimate goal we may be able to help you find a way that does not
> require all the computing that you are doing.
>
> How do you get your coefficients? Are
big thanks for all answers !
--
View this message in context:
http://r.789695.n4.nabble.com/Extract-NA-data-rows-tp3235568p3237309.html
Sent from the R help mailing list archive at Nabble.com.
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https://stat.ethz.ch/
thank Millo for your very valuable reply
The political situation in Italy may be better than in china.
And wish logik function could be supported in FE models too.
If then ,Splm will be more welcome.
thanks for your all works for useR.
Millo Giovanni wrote:
>
> Dear useR,
>
> although I
I recall that my problem on Windows was related to having a number of stray
versions of GTK+ installed. I went back and deleted all versions and
reinstalled the latest GTK+ and that seemed to fix things. However, when I
went to do any work of substance ggobi locked up and became unresponsive.
Neve
Dear R users,
apologies for the total beginner's question. I would like to create a
barchart for some temperature values with the y axis on the right hand
side of the plot. On this plot would like to overlay some time series
data (in the form of a line) for some other variable called Index.
The y
On Tue, Jan 25, 2011 at 5:12 PM, Phil Spector wrote:
> ?do.call
Erik, Phil, thanks!
Roy
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R-help@r-project.org mailing list
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PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and
I want to use diff to take the differences in a column "Close" of a data
frame "y". But I'd like to do it using the transform function so a new data
frame is created with a difference column. The problem is that diff gives
one less than the number of elements in the original data frame. So
transfo
On 2011-01-25 17:22, Jim Moon wrote:
Thank you for the response, Peter.
The approach:
write.table(format(df,
drop0trailing=FALSE),file='df.txt',quote=F,sep='\t',row.names=F)
surprisingly still results in some loss of trailing 0's.
Here are a couple more (essentially identical) ways:
# 1.
df
Hi:
Here's one approach:
f <- function(df) {
rs <- with(na.exclude(df), tapply(y, strata, sum)/tapply(x, strata,
sum))
u <- transform(subset(df, is.na(y)), y = x * rs[strata])
transform(df, y = replace(y, u$id, u$y))
}
f(df)
The function works as follows:
(1) With the rows of
On Jan 25, 2011, at 4:50 PM, Alaios wrote:
Hello
I would like to ask you if it is possible In R Cran to change the
default way of addressing a matrix.
for example
matrix(data=seq(from=1,to=4,nrow=2,ncol=2, by row numbering) # not
having R at this pc
will create something like the followi
Nicolas -
Along with returning a value, the return function passes
control back to the caller of the function. So any statement
after a return statement will just be ignored.
In R the way this is handled is by returning a list. Change
return(pop)
return(grid.dens)
to
return(list(pop=pop
On 2011-01-25 17:08, Hongying Li wrote:
Dear all,
I always encounter a crash when running hazard.ratio.plot from rms package with
my predictor as a factor.
It works fine when the predictor is a continous score.
Anyone encounters this too? Is this a bug or something?
Could you define "crash" f
According to my experience, you should NOT download the GTK version
from GGobi's website. That version won't work for R 2.12.0 and rggobi.
So first, remove that version of GTK; then follow the instructions
from library(RGtk2) to download and install the more recent version of
GTK+. Then everything
On Jan 25, 2011, at 2:25 PM, Ryan Utz wrote:
Hi R-users,
I'm trying to find an elegant way to count the number of rows in a
dataframe
with a unique combination of 2 values in the dataframe. My data is
specifically one column with a year, one with a month, and one with
a day.
I'm trying to
Hi All,
I have a for loop inside the function and I cannot get UUU to give me an
updated grid.dens object when I run the function (it does update when I
run just the for loop). Here's a simplified version of my function:
UUU=function(pop, grid.dens) {
for (i in 1:10){
Food=grid.dens[pop$yloc
On 2011-01-25 17:22, Jim Moon wrote:
Thank you for the response, Peter.
The approach:
write.table(format(df,
drop0trailing=FALSE),file='df.txt',quote=F,sep='\t',row.names=F)
surprisingly still results in some loss of trailing 0's.
What version of R?
I'm using R version 2.12.1 Patched (2010-1
Thank you for the response, Peter.
The approach:
write.table(format(df,
drop0trailing=FALSE),file='df.txt',quote=F,sep='\t',row.names=F)
surprisingly still results in some loss of trailing 0's.
df:
EFFECT2 PVALUE
1 0.0230.88080
2 -0.260 0.08641
3 -0.114 0.45200
df.txt:
EFFECT2PV
On 2011-01-25 16:16, Jim Moon wrote:
Hello, All,
How can I maintain the decimal places when using write.table()?
Jim
e.g.
df:
EFFECT2 PVALUE
1 0.0230.88080
2 -0.260 0.08641
3 -0.114 0.45200
write.table(df,file='df.txt',quote=F,sep='\t',row.names=F)
write.table(format(df, drop0tr
Dear all,
I always encounter a crash when running hazard.ratio.plot from rms package with
my predictor as a factor.
It works fine when the predictor is a continous score.
Anyone encounters this too? Is this a bug or something?
Thanks,
Lilian
[[alternat
On Tue, 25 Jan 2011 16:16:37 -0800,
Jim Moon wrote:
> Hello, All, How can I maintain the decimal places when using
> write.table()?
Have a look at ?format.data.frame
--
Seb
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Dear list,
I´m wondering if there is something analogous to the TukeyHSD function
that could be used for parametric terms in a GAM. I´m using the mgcv
package to fit models that have some continuous predictors (modeled as
smooth terms) and a single categorical predictor. I would like to do
post
Hello, All,
How can I maintain the decimal places when using write.table()?
Jim
e.g.
df:
EFFECT2 PVALUE
1 0.0230.88080
2 -0.260 0.08641
3 -0.114 0.45200
write.table(df,file='df.txt',quote=F,sep='\t',row.names=F)
df.txt:
EFFECT2PVALUE
0.023 0.8808
-0.26 0.08641
-0.114
On Tue, Jan 25, 2011 at 1:14 PM, Akram Khaleghei Ghosheh balagh
wrote:
> Hello ;
>
> Do you know what is the default value of starting value in glm ? glm(...,
> start=c(),... )
> I know that it is NULL by default but it need a value to start iteration .
> what is this value?
Actually the typical
Y'all,
I need to get the look of a "standard" fixed effect ANOVA table:
anova(aov(meas~op*part,data=fs))
Analysis of Variance Table
Response: meas
Df Sum Sq Mean Sq F value Pr(>F)
op 22.62 1.308 1.3193 0.2750
part 19 1185.43 62.391 62.9151 <2e-16 ***
op:part 3
Matthew -
Others will probably tell you about the folly of performing
1733 t-tests on groups with 4 observations each, but an alternative
to your approach would be to use R to solve your problem. (I'm
using var.equal=TRUE because that's what you're calculating, but
you might consider using the
You should try different tuning parameters; the defaults are not likely to work
for many datasets. I don't use the polynomial kernel too much but scale
parameter values that are really of could cause this. Unlike the rbf, I don't
know of any good techniques for estimating this.
Max
On Jan 25,
?do.call
Please provide a reproducible example if the help file is
not sufficient.
- Phil Spector
Statistical Computing Facility
Department of Statistics
Suppose I have a function, like list, that takes a variable number of
arguments, and I have those arguments in some vector x. How can execute the
function with the *contents* of x as its arguments? I.e., I don't want
list(x), but rather list(x[[1]], x[[2]], ..., x[[n]]), but I don't want to
spel
From: Leitch, Matthew C.
Sent: Monday, January 24, 2011 6:53 PM
To: 'i...@network-theory.co.uk'
Subject: question about the pt() calculation
Hello
Thank you for your time. I am a graduate student at the University of Texas
Medical Branch, and I was wondering if you could help me with a R progr
Suppose I have a function, like list, that takes a variable number of
arguments, and I have those arguments in some vector x. How can execute the
function with the *contents* of x as its arguments? I.e., I don't want
list(x), but rather list(x[[1]], x[[2]], ..., x[[n]]), but I don't want to
spell
On Tue, Jan 25, 2011 at 06:00:36AM -0800, vioravis wrote:
>
> I am trying to do binning on three variables (3d binning). The bin boundaries
> are specified by the user separately for each variable. I used the bin2
> function in the 'ash' package for 2d binning that involves only two
> variables bu
From: Leitch, Matthew C.
Sent: Monday, January 24, 2011 6:53 PM
To: 'i...@network-theory.co.uk'
Subject: question about the pt() calculation
Hello
Thank you for your time. I am a graduate student at the University of Texas
Medical Branch, and I was wondering if you could help me with a R progr
Hello
I would like to ask you if it is possible In R Cran to change the default way
of addressing a matrix.
for example
matrix(data=seq(from=1,to=4,nrow=2,ncol=2, by row numbering) # not having R at
this pc
will create something like the following
1 2
3 4
the way R address this matrix is from t
Your question has some similarities this paper: Alison Smith, Brian
Cullis, and Arthur Gilmour. The analysis of crop variety evaluation
data in Australia. Aust. N. Z. J. Stat., 43:129--145, 2001.
In that paper, the authors fit a mixed model with several random
effects. The variances are then held
Good afternoon,
I am working on a plot that requires custom legends to be placed in some
panels of the plot; other panels do not contain legends. The problem
that I run into is positioning of the legend in individual panels. In
particular, the 'x' and 'y' elements of the key-list are ignored by
d
Hi,
I am trying to manipulate a gls regression model output to adjust for use of
two-stage least squares. Basically, I want to estimate a model, then feed in
a new set of residuals, then re-calculate all of the model output (i.e. the
standard errors of the estimators, etc.). I have found some docu
See the note in the help page for ?predict.glm
Best,
Ista
On Tue, Jan 25, 2011 at 2:59 PM, Axel Urbiz wrote:
> Dear List,
>
> I think I'm going crazy here...can anyone explain why do I get the same
> predictions in train and test data sets below when the second has a missing
> input?
>
> y <- rn
Hi Simon,
You almost had it! Just need to move the negation outside the rest of
the logic, and remove the quotes from year. Not actually tested (no
data), but I think
newdata<- subset(bpa, !(State=="Connecticut" & year<2010))
should do it.
Best,
Ista
On Tue, Jan 25, 2011 at 1:34 PM, Simon Kiss
Dear List,
I think I'm going crazy here...can anyone explain why do I get the same
predictions in train and test data sets below when the second has a missing
input?
y <- rnorm(1000)
x1 <- rnorm(1000)
x2 <- rnorm(1000)
train <- data.frame(y,x1,x2)
test <- data.frame(x1)
myfit <- glm(y ~ x1 + x2,
On Tue, Jan 25, 2011 at 2:06 PM, cameron wrote:
>
> I know a lot of people asked similar questions like this. I have tried using
>
> read.xls ()
> Error in .Call("ReadXls", file, colNames, sheet, type, from, rowNames, :
> Incorrect number of arguments (11), expecting 10 for ReadXls
>
> read.tab
Hi Ryan,
One option would be
X$a <- paste(X$x, X$y, sep=".")
table(X$a)
Best,
Ista
On Tue, Jan 25, 2011 at 2:25 PM, Ryan Utz wrote:
> Hi R-users,
>
> I'm trying to find an elegant way to count the number of rows in a dataframe
> with a unique combination of 2 values in the dataframe. My data is
Hi,
I am creating a correlation based graph for the data 27 X 3040.
I am not sure if I am allocating enough space for the data.
I am using the following .R file (which is an example for geneData)!
http://r.789695.n4.nabble.com/file/n3236801/sampleClimate.R
sampleClimate.Rhttp://r.789695.n4.nabbl
Hello ;
Do you know what is the default value of starting value in glm ? glm(...,
start=c(),... )
I know that it is NULL by default but it need a value to start iteration .
what is this value?
Thanks;
[[alternative HTML version deleted]]
__
R-
Hi!! Im doing my graduated work in Onion Curves Growth with Nonlinear Models,
I'm amateur in R so i have doubt how i put or program next models,
http://r.789695.n4.nabble.com/file/n3236748/96629508.png
Also, i cant derivate for Gauss Model, and Richard Model dont have funtion,
If someone could
I know a lot of people asked similar questions like this. I have tried using
read.xls ()
Error in .Call("ReadXls", file, colNames, sheet, type, from, rowNames, :
Incorrect number of arguments (11), expecting 10 for ReadXls
read.table or read.csv (Wrong table format)
odbcConnectExcel have
Dear colleagues, I have a dataset that looks as below.
I would like to make a new dataset that excludes the cases which are joint
conjunctions of particular state names and years, so Connecticut and 2010,
Maryland and 2010 and Vermont and 2010.
I'm trying the following subset code:
newdata<- s
If you want count:
xtabs( ~ x + y, X)
or sum:
xtabs(z ~ x + y, X)
On Tue, Jan 25, 2011 at 5:25 PM, Ryan Utz wrote:
> Hi R-users,
>
> I'm trying to find an elegant way to count the number of rows in a
> dataframe
> with a unique combination of 2 values in the dataframe. My data is
> specifi
Hi R-users,
I'm trying to find an elegant way to count the number of rows in a dataframe
with a unique combination of 2 values in the dataframe. My data is
specifically one column with a year, one with a month, and one with a day.
I'm trying to count the number of days in each year/month combinati
Dear list,
When I use the predict.glm method on a glm fitted object, I get the
following warning message:
In addition: Warning message:
> In predict.lm(object, x) :
> prediction from a rank-deficient fit may be misleading
As the documentation says this happens if "the fit is rank-deficient, som
On 2011-01-25 08:08, Brian J Mingus wrote:
Apologies for this simple question -
Given the number of comparisons I need to do it has become somewhat
laborious to compute the SSE manually. I first have to extract the
coefficients, build the model and run the model on the data. So far I
haven't fou
It is not clear what you are doing or why you are doing it. If you tell us
your ultimate goal we may be able to help you find a way that does not require
all the computing that you are doing.
How do you get your coefficients? Are you using lm? Have you looked at the
resid function?
--
Gregor
Thank you both, very much.
Using the identity function I() is a very nice trick, but it still feels
like a trick.
Using ggplot makes the most sense to me.
ggplot(df, aes(x=x, y=y, colour=factor(type))) +
geom_point(size=1) +
geom_smooth()
Thank you very much for taking the time to
On 1/25/2011 9:44 AM, Felipe Carrillo wrote:
try this:
qplot(x, y, data=df, colour=factor(type), size=I(1)) + geom_smooth()
Felipe very nicely answered the "how" of your question. I thought I'd
followup with the "why."
Using qplot, it assumes that you are giving a set of aesthetic mappings.
Now I understand what the difference between a primitive and a
non-primitive!
Thanks for the clarification!
Ivan
Le 1/25/2011 18:03, Bert Gunter a écrit :
Well, I'm not Prof. Ripley, but the answer is: Look at the code.
seq_len, seq.int, and seq_along call Primitives, which are implemented
in C
Hi
I would really appreciate some help with my code for coxme...
My data set
I'm interested in survival of animals after an experiment with 4
treatments, which was performed on males and females. I also have two
random factors:
Response variable: survival (death)
Factor 1:
With large numbers of points you might want to consider hexagonal binning
instead of scatter plots. I don't know of any tools that both do the binning
and take groups into account, but you could think it through and work something
out.
--
Gregory (Greg) L. Snow Ph.D.
Statistical Data Center
I
after using options(error=utils::recover) option, following is the output. if
i am correct this means that in ksvm there is some problem, but really could
not understand. could anyone please tell me what is wrong...
any help will be great
thank you so much..
Enter a frame number, or 0 to
try this:
qplot(x, y, data=df, colour=factor(type), size=I(1)) + geom_smooth()
Felipe D. Carrillo
Supervisory Fishery Biologist
Department of the Interior
US Fish & Wildlife Service
California, USA
http://www.fws.gov/redbluff/rbdd_jsmp.aspx
- Original Message
> From: Gene Leynes
> T
Hello R user,
I have following data frame:
df=data.frame(id=c(1:10),strata=rep(c(1,2),c(5,5)),y=c(
10,12,10,NA,15,70,NA,NA,55,100),x=c(3,4,5,7,4,10,12,8,3,15))
and I would like to replace NA's with:
instead of first NA tapply(na.exclude(df)$y,na.exclude(df)$strata,sum)[1]*
*7 */tapply(na.exclu
Greetings all,
I am failing to install the package rggobi on windows 7 with R 2.12.0.
On R 2.11.1, the package was installed fine.
I asked for help on the rggobi google group 4 days ago, and didn't receive
any help, so I was wondering if someone here might have a suggestion.
Here are the details
Can anyone illuminate the following for me?
How can I get rid of the blue line in the key in the second plot?
## Create a simple data frame
df=data.frame(x=1:1000, y=2*1:1000+rnorm(1000,sd=1000),
type=sample(letters[1:2],1000, replace=TRUE))
## Very nice! Almost what I want
qplot(x, y, d
Inline below.
-- Bert
On Tue, Jan 25, 2011 at 7:48 AM, Henrique Dallazuanna wrote:
> Try this:
>
> expand.grid(seq(startpos, endpos, by = diff(c(startpos, endpos)) /
> nrow(sr)),
> seq(startpos, endpos, by = diff(c(startpos, endpos)) / nrow(sr)))
>
> On Tue, Jan 25, 2011 at 1:29 PM, Ala
Good Evening,
I would like to work with multivariate polynomials (x and y variables).
I know that there is a package called multipol but I am not sure that supports
my needs.
I use a function (in reality legendre.polynomials) which creates me the
polynomials I want.
For example the following ret
Well, I'm not Prof. Ripley, but the answer is: Look at the code.
seq_len, seq.int, and seq_along call Primitives, which are implemented
in C, and therefore MUCH faster than seq(), which is implemented as
pure R code (and is also a generic, so requires method dispatch).
Though for small n (up to a f
Dear List,
I am using function distCosine from package geosphere to a list of lat/lon
coordinates, and I want to calculate the great circle distance between a
pair of coordinates in the list and all other pairs --- essentially, the
output should be a matrix. I have been able to achieve this with t
Hi
r-help-boun...@r-project.org napsal dne 25.01.2011 10:58:36:
> ooh.. I have another question.
> What if I want to add the value in the vector a to the hello each time
it
> prints.
> Here is your output
>
> a <- c(2,3,5,5,5,6,6,7)
> mapply(rep, "hello", rle(a)$lengths, USE.NAMES = FALSE)
>
>
I would like to produce a bar plot with varying-width bars. Here is an example
to illustrate:
ww <- c(417,153,0.0216,0.0065,556,256,0.0162,0.0117,
+ 726,379,0.0358,0.0501,786,502,0.0496,0.0837,
+ 892,591,0.0785,0.0795)
yy<-t(t(array(ww,c(2,10
barplot(yy[,2*1:5],las=1,space=c(.1,.5),beside
I have a problem integrating the 'standard map' (
http://en.wikipedia.org/wiki/Standard_map
http://en.wikipedia.org/wiki/Standard_map ) with deSolve:
By using the modulo-operator '%%' with 2*pi in the ODEs (standardmap1), the
resulting values of P and Theta, should not be greater than 2pi. Becaus
Apologies for this simple question -
Given the number of comparisons I need to do it has become somewhat
laborious to compute the SSE manually. I first have to extract the
coefficients, build the model and run the model on the data. So far I
haven't found any method in R that will do this for me.
Try this:
expand.grid(seq(startpos, endpos, by = diff(c(startpos, endpos)) /
nrow(sr)),
seq(startpos, endpos, by = diff(c(startpos, endpos)) / nrow(sr)))
On Tue, Jan 25, 2011 at 1:29 PM, Alaios wrote:
> Greetings Friends,
> I would be grateful if you can help me undestand how to make
--- begin included message ---
Im an honours student at Monash University. I'm trying to analyse some
data for my project, which involved 2 treatments. My subjects were
exposed to both treatments, and i gave them 60 minutes to perform a
certain behaviour. 3 of my subjects performed the behaviour
I am trying to do binning on three variables (3d binning). The bin boundaries
are specified by the user separately for each variable. I used the bin2
function in the 'ash' package for 2d binning that involves only two
variables but didn't any package for similar binning with three variables.
Are t
Dear all,
Does anybody know why the following code returns an error message?
>library(MatchIt)
>library(Zelig)
>data(lalonde)
>
>m.out1<-matchit(treat~age+educ+black+hispan+nodegree+married
+re74+re75, method="full", data=lalonde)
>
>z.out1<-zelig(re78~age+educ+black+hispan+nodegree+married+re74+
ooh.. I have another question.
What if I want to add the value in the vector a to the hello each time it
prints.
Here is your output
a <- c(2,3,5,5,5,6,6,7)
mapply(rep, "hello", rle(a)$lengths, USE.NAMES = FALSE)
[[1]]
[1] "hello"
[[2]]
[1] "hello"
[[3]]
[1] "hello" "hello" "hello"
[[4]]
[1] "
Version:
R = 2.11.1
CARET = 4.68
--
View this message in context:
http://r.789695.n4.nabble.com/Train-error-subscript-out-of-bonds-tp3234510p3236251.html
Sent from the R help mailing list archive at Nabble.com.
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ht
> From: ggrothendi...@gmail.com
> Date: Mon, 24 Jan 2011 22:43:55 -0500
> To: megh700...@gmail.com
> CC: r-help@r-project.org
> Subject: Re: [R] Downloading data from internet
>
> On Mon, Jan 24, 2011 at 8:48 PM, Megh Dal wrote:
> > Dear all, I need to download an excel file from net, on whi
Greetings Friends,
I would be grateful if you can help me undestand how to make my R code more
efficiently.
I have read in R intoductory tutorial that a for loop is not used so ofter (and
is not maybe not that efficient) compared to other languages.
So I am trying to build understanding how to
fayazvf wrote:
>
> I am using calais api in R for text analysis.
> But im facing a some problem when fetching the rdf from the server.
> I'm using the getToHost() method for the api call but i get just a null
> string.
You haven't told us nearly enough for us to be able to reproduce
what you are
Le 25.01.2011 15:23, Rmh a écrit :
> g <- function(x) abs(f1(x)-f2(x))
>
> now you have one function and you can integrate it.
Thank you Rich.
Unfortunately I have no f1 and f2 functions, only a set of observed
points on two lines - and no idea about the underlying distribution to
create a funct
Xavier Robin unige.ch> writes:
> Hello,
>
> I need to integrate the absolute difference between two lines measured
> on different points.
>
> # For example :
> x <- seq(0, 1, 1/100)
> f_x <- runif(101) + x
> y <- seq(0, 1, 1/23)
> f_y <- runif(24) + (1 - y)
>
> plot(x, f_x, type="l")
> lines(y
Am 24.01.2011 14:08, schrieb Bart Joosen:
I think this is a problem with quotes.
If you look good, you see:
seiz.df<- sqlFetch(chnl, 'source.MAIN')
... 'source.main': table not found on channel
You asked "MAIN", but your db can't find "main".
If you use seiz.df<- sqlFetch(chnl, '\"source\".\"
The xlsReadWrite[Pro] package allows to natively read and write Excel
files (.xls) on the Win 32-bit platform.
Changes:
o fix bug with integer conversion (http://dev.swissr.org/issues/113)
PROBLEM: values outside the integer range (i.e. 12345678901) didn't give an NA
(and a warning
Dear Carlos,
please refrain from posting the same question umpteen times. Please
consider that code is hard to read and people might not have the time to
run your simulation etc. etc..
As I told you privately in response to your message on 18/1,
> Re: generating correlated effects, I tried this
g <- function(x) abs(f1(x)-f2(x))
now you have one function and you can integrate it.
Rich
Sent from my iPhone
On Jan 25, 2011, at 7:32, Xavier Robin wrote:
> Hello,
>
> I need to integrate the absolute difference between two lines measured
> on different points.
>
> # For example :
> x <-
What version of caret and R? We'll also need a reproducible example.
On Mon, Jan 24, 2011 at 12:44 PM, Neeti wrote:
>
> Hi,
> I am trying to construct a svmpoly model using the "caret" package (please
> see code below). Using the same data, without changing any setting, I am
> just changing the
Try this:
sweep(as.matrix(df), 2, as.matrix(df[1,]))
On Tue, Jan 25, 2011 at 7:20 AM, Vincy Pyne wrote:
> Dear R helpers
>
> I have a dataframe as
>
> df = data.frame(x = c(1, 14, 3, 21, 11), y = c(102, 500, 40, 101, 189))
>
> > df
>x y
> 1 1 102
> 2 14 500
> 3 3 40
> 4 21 101
> 5 11 1
On 2011-01-25 01:20, Vincy Pyne wrote:
Dear R helpers
I have a dataframe as
df = data.frame(x = c(1, 14, 3, 21, 11), y = c(102, 500, 40, 101, 189))
df
x y
1 1 102
2 14 500
3 3 40
4 21 101
5 11 189
# Actually I am having dataframe having multiple columns. I am just giving an
exampl
Dear All,
I would like to ask you help with the following:
Assume that I have an area of 36 cells (or sub-areas)
sr<-matrix(data=seq(from=1,to=36),nrow=6,ncol=6,byrow=TRUE)
> sr
[,1] [,2] [,3] [,4] [,5] [,6]
[1,]123456
[2,]789 10 11 12
[3,] 13 14
Hello,
I need to integrate the absolute difference between two lines measured
on different points.
# For example :
x <- seq(0, 1, 1/100)
f_x <- runif(101) + x
y <- seq(0, 1, 1/23)
f_y <- runif(24) + (1 - y)
plot(x, f_x, type="l")
lines(y, f_y)
Then I would like to compute Integral( | f_x - f_y
Dear useR,
although I admit that getting the log likelihood is important, you must
concede that obtaining the parameter estimates is not bad either.
Regarding "craze", well there are crazier things in the world than this,
just look at the political situation in Italy.
Anyway, the loglik has alway
On 24.01.2011 23:53, Peter Langfelder wrote:
On Mon, Jan 24, 2011 at 2:47 PM, Yanika Borg wrote:
I am using the function permutations from the package *gregmisc*. However, I
am also making use of the package *e1071*, which also contains a function
called permutations. I want to use the functi
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