Hi all
I'm having a problem when using Sweave. Here is a minimal example.
My input file (eg, test.Snw) looks like this:
<>=
data(cars)
m1 <- lm( dist~speed, data=cars ); coef( m1 )
@
<>=
<>
@
<>=
data(cars)
m1 <- lm( dist~speed, data=cars )
@
<>=
<>
@
After running Sweave over this
A recent announcement as a follow up to this:
http://blogs.esri.com/Dev/blogs/geodatabase/archive/2010/12/13/File-Geodatabase-API-details.aspx
Still requires ESRI software, but will allow some other projects to
read the format if ArcRequired is available.
Cheers, Mike.
On Tue, Dec 7, 2010 at 7:
Hi Peter,
On Mon, Dec 13, 2010 at 5:26 PM, Peter Langfelder
wrote:
> Just in case no one knowledgeable answers, here's my shot in the dark
I switch between Windows and Linux so I'm always in the dark ;)
> (I'm mostly a linux user)... the compiler is looking for .h files in
> the directories lis
Hi Joe,
Just for info, I've done this in the past by applying lowess followed
by diff to a vector, then identifying points with change of sign in
the diffs.
Michael
On 14 December 2010 14:22, Joe Stuart wrote:
> Never mind. I did find this package, which seems to do the trick. Thanks
>
> http:/
Never mind. I did find this package, which seems to do the trick. Thanks
http://rgm2.lab.nig.ac.jp/RGM2/R_man-2.9.0/library/msProcess/man/msExtrema.html
On Mon, Dec 13, 2010 at 9:05 PM, Joe Stuart wrote:
> Hi,
> I was wondering if anyone knows of a package that contains the ability
> for peak/va
> -Original Message-
> From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org] On
> Behalf Of joeponzio
> Sent: December-13-10 4:13 PM
> To: r-help@r-project.org
> Subject: [R] Schedule R to run automatically
>
>
> Current I have raw data from several projects that is w
Hi,
I was wondering if anyone knows of a package that contains the ability
for peak/valley detection. Here is an example of what I'm looking for,
only problem is that it's written in Matlab.
http://www.billauer.co.il/peakdet.html
Thanks for any help in advance.
-Joe
On Dec 13, 2010, at 9:21 PM, Bastiaan Bergman wrote:
That doesn't work, one would get two different answers depending on
the
order of execution.
The physics is: Overlay error on a Silicon wafer. One wafer has many
flash
fields, each flash field has multiple locations where the overlay
er
Reed, Nicola exeter.ac.uk> writes:
> I was hoping to get some advice regarding the testing of interactions,
> when one factor is modelled as a
> random effect...
> I have a model with binomial error structure where the response
> variable is the proportion of time spent at
> the main sett (anima
FYI,
I've added evalWithTimeout() to R.utils v1.6.0 (now on CRAN). It
utilizes the built-in setTimeLimit() feature of R.
You can either have it throw an error, which you then have to catch,
or you can have it just give a warning that your evaluation timed out
and then silently continue. From ex
That doesn't work, one would get two different answers depending on the
order of execution.
The physics is: Overlay error on a Silicon wafer. One wafer has many flash
fields, each flash field has multiple locations where the overlay error is
measured (as: dX,dY offset). If one contemplates that th
I am not even sure what model you are trying to run, you are talking about
regression slopes for x1 being coef1, and coef2 being the slope for x2,
where are you getting coef3 from, is it in your data?
Joe King
206-913-2912
j...@joepking.com
"Never throughout history has a man who lived a life of e
Dear list,
The "starting" solution proposed by Duncan Murdoch is an *excellent*
start for Sweave'ing. One can trivially redefine Sweave to start using it
quasi-transparently (to use it transparently would require patching
Sweave, which would be worth some failsafes and possibly options
tinkeri
Current I have raw data from several projects that is written to a drive on a
daily basis. I would like to run a certain R syntax against these data sets
(varying somewhat from data set to data set) every day at, say, 7am (with no
human interaction). Is this possible to set up in windows or unix
I always enjoy these direct comparisons between different software packages.
I coded this up in AD Model Builder which is freely available at
http://admb-project.org ADMB calculates exact derivatives via automatic
differentiation so it tends to be more stable for these difficult problems.
The p
Dear all,
I am relatively new to R. I would like to know how can we write the
realizations (for example generated through rnorm or runif) in to a data
file. It would be very inefficient to first generate values and then write
them in to file using "write" function. Instead, is there a way to ge
On Dec 13, 2010, at 8:46 PM, Bastiaan Bergman wrote:
Hello,
I want to model my data with the following model:
Y1=X1*coef1+X2*coef2
Y2=X1*coef2+X2*coef3
Note: coef2 appears in both lines
Xi, Yi is input versus output data respectively
How can I do this in R?
I got this far:
lm(Y1~X1+X2
Hello,
I want to model my data with the following model:
Y1=X1*coef1+X2*coef2
Y2=X1*coef2+X2*coef3
Note: coef2 appears in both lines
Xi, Yi is input versus output data respectively
How can I do this in R?
I got this far:
lm(Y1~X1+X2,mydata)
now how do I add the second line of t
On Dec 13, 2010, at 3:07 PM, Barry Rowlingson wrote:
On Mon, Dec 13, 2010 at 7:36 PM, Steve Sidney
wrote:
Oh dear oh dear!!! another arrogant statistician/scientist
One asks for help and instead one gets an ear full!!!
we're statisticians. we love data. we hate seeing it go to waste.
ev
On Mon, Dec 13, 2010 at 4:33 PM, Joshua Wiley wrote:
> Hi All,
>
> I am trying to compile R 2.13.0 r53834 on 64-bit Windows 7 (home
> premium) using Rtools212.exe from Duncan Murdoch's site. I (think) I
> followed the installation guide for Windows. When installing Rtools,
> made sure I was inst
Take a look at package xtable.
Bryan
On 12/13/10 7:31 PM, "Chris Fonnesbeck" wrote:
> I'm hoping someone with some experience generating tables in Sweave will be
> able to solve this problem for me. I'm experiencing some inconsistency with
> the way floating point numbers are displayed -- for
Hi All,
I'm getting some weird problems with merge(), which give me the
Error in match.names(clabs, names(xi)) :
names do not match previous names
Error.
I've found other people discussing this error, but they don't seem to match
my situation, and the strange thing is that changing the order
Hi All,
I am trying to compile R 2.13.0 r53834 on 64-bit Windows 7 (home
premium) using Rtools212.exe from Duncan Murdoch's site. I (think) I
followed the installation guide for Windows. When installing Rtools,
made sure I was installing 64-bit tools (including tcltk), etc. I
created a copy of
I'm hoping someone with some experience generating tables in Sweave will be
able to solve this problem for me. I'm experiencing some inconsistency with the
way floating point numbers are displayed -- for some tables, they will be in
standard notation, e.g.
11±26
while in others, it uses exp
Tony -
Try
do.call(rbind,lapply(paste('X',1:i,sep=''),get))
(You've created the names, but you need to tell R to use
the objects which have those names. That's what get() does.)
You'd probably be better served by putting the
data frames you create into a list as they are created,
rathe
Hello,
I have data frames X1 to X19
I want a simple way to bind them as the next run(s) will generate many
more sequential data frames.
I tried the following with i = 19:
> my.list <- as.list(paste("X",1:i,sep=""))
> new.data <- do.call("rbind", my.list)
> new.data
[,1]
[1,] "X1"
[2,
Jared -
Actually I didn't realize that nls would accept a formula
until I tried my simple example in reaction to your post :-)
I don't recall nls() ever reporting the cause of the singular
gradient as being bad starting values -- I know I spend a lot
of time in my lectures on non-linear regr
Greetings ~
I need some assistance determining an appropriate approach to analyzing
multivariate binary response data, and how to do it in R.
The setting: Data from an assay, wherein 6-hours-post-fertilization zebrafish
embryos (n=20, say) are exposed in a vial to a chemical (replicated 3 times
Hello,
I am having trouble doing a split plot analysis of variance with lme. The
study design is ponds split in two, one side of each pond was a control and
the other was one of three chemical treatments. Each pond side was sampled
three times, response variable is the mean of twenty animals.
On Dec 13, 2010, at 23:23 , Justin Fincher wrote:
> I apologize for the lack of example. I was trying not to be too long
> winded. Below is the first portion of my function that is causing the
> error. (I'm including both calls to cor(), though it quits after the first
> throws an error). I do
Hi,
I can certainly understand not wanting to be long winded, and no
damage done. Here's a link to the R news file:
http://cran.stat.ucla.edu/src/base/NEWS and if you search in your
browser for "cor() and cov()" you should find what happened.
At any rate, I could not fully check your code beca
I apologize for the lack of example. I was trying not to be too long
winded. Below is the first portion of my function that is causing the
error. (I'm including both calls to cor(), though it quits after the first
throws an error). I do not believe he has redefined cor() as he is a novice
user a
Phil,
This is great! I had no idea nls would accept functions in the formula
position. My apologies for not including data to reproduce my issue.
dat<-data.frame(X=c(-13.0,-11.0,-10.0,-9.5,-9.0,-8.5,-8.0,-7.5,-7.0,-6.5,-6.0,-5.0,
-13.0,-11.0,-10.0,-9.5,-9.0,-8.5,-8.0,-7.5,-7.0,-6.5,-6.0,-5.0),
Y=
On Dec 13, 2010, at 12:48 , Saul Sternberg wrote:
>
> This message also reports wrong estimates produced by lmRob.fit.compute()
> for nested factors when using the correct contrast matrix.
>
> And in these respects, I have found that S-Plus behaves the same way as R.
>
> Using the three availa
Hi Fincher,
cor() only works on numeric arguments now (as of R 2.11 or 2.10 if
memory serves). So, I would update your function to ensure that you
are only passing numeric data to cor() and the error should go away
(it will probably be easier on you if you can update your version of R
to the late
On Mon, Dec 13, 2010 at 12:30 AM, Emmanuel Charpentier
wrote:
> Therefore, I let this problem to sleep. However, I Cc this answer (with
> the original question below) to Max Kuhn and Friedrich Leisch, in the
> (faint) hope that this feature, which does not seem to have been missed
> by anybody in
Please provide a reproducible example!
E.g., use ?dput to dump a minimal data.frame that
exhibits this issue on the newest version of R.
Justin Fincher wrote:
Howdy,
I have written a small function to generate a simple plot and my
colleague is having an error when attempting to run it. Esse
Howdy,
I have written a small function to generate a simple plot and my
colleague is having an error when attempting to run it. Essentially I loop
through categories in a data frame and take the average value for each
category The categories are in $V1, subset first then mean taken and
concaten
Firstly apologies that I didn't see Ben's original response, thanks.
(Found that I had my subscription to the list disabled, so only received
mails to my address directly.)
Also I shouldn't have had the 'knee-jerk' re-action that I did and
should have followed Bert's advice by not replying, bu
Folks:
This is off topic, but I believe many R-Help participants would be
interested in this. My apologies to my British colleagues, who
probably already know about this, and to others for whom this is a
waste of their time.
Dr. Ben Goldacre, a British Physician and science columnist, has
written
Greetings
In attempting to create a date variable based on month (e.g.,
February, April, etc.) and year (e.g., 2006) data, wherein I converted
Month to a factor with Jan=1...Dec=12, I used the following command:
data$Date<-mdy.date(month=data$Month,day=15,year=data$Year)
however, I get a mes
I tried hard to write an automagic script to configure LyX so that you
don't need to go to the instructions on CRAN
(http://cran.r-project.org/contrib/extra/lyx/):
http://yihui.name/en/2010/10/how-to-start-using-pgfsweave-in-lyx-in-one-minute/
This works for LyX 1.6.x and major OS'es with probabi
Excellent, thank you all!
William Dunlap wrote:
attr(terms(formula), "response") is 1 if
the formula has a left hand side and 0
otherwise.
At a lower level, you can look at
length(formula): 2 means there is no LHS,
3 means there is (any other value indicates
that someone made a call object that
On 2010-12-13 11:36, Steve Sidney wrote:
Oh dear oh dear!!! another arrogant statistician/scientist
One asks for help and instead one gets an ear full!!!
So much for the much vaunted helpful R community.
But thanks anyway, I guess you were trying
Steve
Ouch!!
I didn't offer advice e
Erik -
Perhaps the "response" attribute of the terms() function?
formula1 = formula(y ~ x + z)
formula2 = formula(~x + z)
attr(terms(formula1),'response')
[1] 1
attr(terms(formula2),'response')
[1] 0
Although there may be more direct ways.
- Phi
attr(terms(formula), "response") is 1 if
the formula has a left hand side and 0
otherwise.
At a lower level, you can look at
length(formula): 2 means there is no LHS,
3 means there is (any other value indicates
that someone made a call object that the
parser would not make).
Bill Dunlap
Spotfire,
Hello,
Does anyone know of a function that will determine whether
or not a formula object has a left hand side?
I.e., can differentiate between
y ~ x + z
and
~ x + z
Perhaps I'm overlooking the obvious...
Thanks!
__
R-help@r-project.org mailing l
On Mon, Dec 13, 2010 at 7:36 PM, Steve Sidney wrote:
> Oh dear oh dear!!! another arrogant statistician/scientist
>
> One asks for help and instead one gets an ear full!!!
>
> So much for the much vaunted helpful R community.
>
> But thanks anyway, I guess you were trying
Steve,
we're
Steve Sidney mweb.co.za> writes:
>
> Oh dear oh dear!!! another arrogant statistician/scientist
>
> One asks for help and instead one gets an ear full!!!
>
> So much for the much vaunted helpful R community.
>
> But thanks anyway, I guess you were trying
>
> Steve
>
I know I shoul
On Mon, Dec 13, 2010 at 2:12 PM, Ashta wrote:
> Thanks Sarah,
>
>> 1. to shade or color (blue) the curve using the criterion that any values
>> greater than 11,000
>
> I think I was not clear in the above point. I want shade not the line but
> the area under the curve,
Here's an example of how to
Oh dear oh dear!!! another arrogant statistician/scientist
One asks for help and instead one gets an ear full!!!
So much for the much vaunted helpful R community.
But thanks anyway, I guess you were trying
Steve
On 2010/12/13 08:17 PM, Bert Gunter wrote:
Inline below. -- Bert
On Mon
Hi,
stepAIC generic plot function creates useful graphics for the diagnosis of
multiple regressions. To create predicted versus observed plots, I use to
look for the coefficients, copy them by hand, calculate R², then plot. Is
there a more automated way to plot predicted versus observed with its
Googles Huge Change and How it affects you.
Anyone can now post bad reviews and kill your rank.
We post good reviews and improve your rank.
We post good reviews to keep others from killing your rank.
Google: Judge, Jury and Online Shopping Executioner
Google rank is based on rev
You could also use aggstat() of package tdisplay (available at
http://forums.cirad.fr/logiciel-R/viewtopic.php?t=3367). See the help
page.
> mydata <- data.frame(
+ y1 = c(NA, rnorm(n = 8, mean = 10, sd = 5), NA),
+ y2 = c(rep(NA, 2), rnorm(n = 6, mean = 10, sd = 5), rep(NA, 2)),
+ y3
Thanks Sarah,
> 1. to shade or color (blue) the curve using the criterion that any values
greater than 11,000
I think I was not clear in the above point. I want shade not the line but
the area under the curve,
and
Your last line of code,
segments(x0=mean(test1), y0=0, y1=curveheight)
gave me th
Thorn,
Here's how I do it:
retval <- list(as.name('lm'),
formula=as.formula(paste(Response, "~", Explan,
sep='')),
data=as.name(Data))
#... optionally add other arguments
retval <- eval(as.call(retval))
Dave
From:
"Thaler, Thorn, LAUSANNE, Appl
Here's one way to do what I think you want:
test<- rnorm(5000,1000,100)
test1 <- subset(test, subset=(test > 1100))
d <- density(test)
plot(d, main="Density of production", xlab="")
lines(d$x[d$x > 1100], d$y[d$x > 1100], col="blue", lwd=2)
curveheight <- d$
- --- included message
i try to calculate the probabilty to survive a given time by using the
estimated survival curve by kaplan meier.
What is the right way to do that? as far as is see i cannot use the
predict-methods from the survival package?
end inclusion
The sur
For data frames the best is probably the View function (note capitol V) which
opens the data frame in a spreadsheet like window that you can scroll through.
For more complicated, list or list-like objects, look at TkListView in the
TeachingDemos package.
For more general investigation of data o
Hi All,
I generated 5000 samples using the following script
test<- rnorm(5000,1000,100)
test1 <- subset(test, subset=(test > 1100))
d <- density(test)
plot(d, main="Density of production")
abline(v=mean(test1)
I wanted to do the following but faced diffic
On Dec 13, 2010, at 12:20 PM, Roy Shimizu wrote:
Hi! I'm just getting started with R (and with the analysis of large
datasets in general). I have several beginner-level questions whose
answers I have not been able to find, and was hoping one of you would
be kind enough to throw me a cluebrick
An example is described here that you can adapt:
http://r.789695.n4.nabble.com/coloring-leaves-in-a-hclust-or-dendrogram-plot
-tt795496.html#a795497
HTH. Bryan
*
Bryan Hanson
Professor of Chemistry & Biochemistry
DePauw University, Greencastle IN USA
On 12/13/10 12:54 PM, "Soyeon
Inline below. -- Bert
On Mon, Dec 13, 2010 at 9:42 AM, Steve Sidney wrote:
> Thanks for the questions.
>
> 1) The data represents micro-organism counts and a count of zero in this
> case is highly unlikely given the info we have; including the other
> participants.
?? Censoring or an experiment
Dear all,
In a function I paste a string and convert it to a formula which I pass
to lm[e]. The idea is to write a function which takes the name of the
response variable and the explanatory variable and the data frame as an
argument and calculates an lm[e]. (see example below)
This works fine, bu
One possibility, though not as simple as what you ask for, is to use etxtStart
and friends from the TeachingDemos package.
Other possibilities include using gui interfaces to R, possibilities (though
they may do more than you ask, and color might be different) include emacs/ess;
vim; jgr; and o
What error do you get when using:
install.packages("A2R")
?
Contact
Details:---
Contact me: tal.gal...@gmail.com | 972-52-7275845
Read me: www.talgalili.com (Hebrew) | www.biostatistics.co.il (Hebrew) |
www.r-statistics.com (En
Thanks for the comments
Please see my reply to Stavros - the counts represent organisms and btw
both mean and the median are virtually unaffected by the removal of
these valuse.
Furthermore, experience rather than statistics indicates that these
values are in fact gross errors and as you of
I'm attempting to calculate a regression in R that I normally use Prism for,
because the formula isn't pretty by any means.
Prism presents the formula (which is in the Prism equation library as
Heterologous competition with depletion, if anyone is curious) in these
segments:
KdCPM = KdnM*SpAct*Vo
I want to change leaf color by group in hclust plot.
I've seen several answers about A2R package but I cannot install A2R
and Rtools in windows.
Do you know how to install A2R package in windows or how to change
leaf color by group in hclust plot?
Thank you in advance,
Soyeon
_
Hi Patrick,
Thanks! That worked perfectly!
M
--
View this message in context:
http://r.789695.n4.nabble.com/Projecting-data-on-a-world-map-using-long-lat-tp3081298p3085834.html
Sent from the R help mailing list archive at Nabble.com.
__
R-help@r-pro
Thanks for the questions.
1) The data represents micro-organism counts and a count of zero in
this case is highly unlikely given the info we have; including the other
participants.
2) The data is submitted in duplicate and then a standardised sum and
difference is established and is used to c
Thanks to R ... I just got myself a new ubuntu setup just an hour back! It
feels good! :-)
On Mon, Dec 13, 2010 at 8:46 PM, Bos, Roger wrote:
> I asked Jeff Horner that question a while back and he said it was Linux
> only. He doesn't have time to create a windows version.
>
>
> -Original Me
Hi! I'm just getting started with R (and with the analysis of large
datasets in general). I have several beginner-level questions whose
answers I have not been able to find, and was hoping one of you would
be kind enough to throw me a cluebrick or two.
I have a 6-dimensional numeric array (which
On Mon, Dec 13, 2010 at 11:37 AM, matteop wrote:
>
> Hello R User,
>
> I am new in R and trying to migrate from SAS. I have to convert a table that
> look like this
>
> YEAR FIRM ID_NAME VALUE
> 1994 Microsoft John Doe 5
> 1994 Microsoft Mark
>>
>> Values to be ignored
>>
>> 0 - zero and 1 this is in addition to NA (null)
>>
>> The reason is that I need to use the log10 of the values when performing
>> the calculation.
>>
>> Currently I hand massage the data set, about a 100 values, of which less
>> than 5 to 10 are in this category.
>>
Hi everyone,
I am new to R and I have a beginner's question on Time Series: I have an
irregular time series that goes like this:
TIMESTAMP PRICE
2010-11-29 12:29:28 25.255
2010-11-29 12:30:47 25.255
2010-11-29 12:36:58 25.230
2010-11-29 12:43:14 25.235
2010-11-
Do it with aggregate(), something like this should do:
aggregate(.~cluster, FUN=summary, data=data)
Now if you don't want to run summary(), replace it with the function
you'd like.
HTH,
Ivan
Le 12/13/2010 17:17, effeesse a écrit :
what am I supposed to put into function(x)? The indicator for
An alternative way of getting summary statistics by a grouping
variable is to use describe.by in the psych package:
using Jim Lemon's example:
library(psych)
testmat<-data.frame(sample(1:14,50,TRUE),rnorm(50),runif(50)) #make
up the data
describe.by(test.mat,testmat[1]#get descriptive st
Can anybody tell me why this is happening?
> library( Defaults)
> ls()
[1] "class" "foo""mlct"
[4] "mlctTheme" "overlayFunction""pct"
[7] "pri""primaryFraction""reclassFractions"
[10] "reclassMatrix"
Hello R User,
I am new in R and trying to migrate from SAS. I have to convert a table that
look like this
YEARFIRMID_NAME VALUE
1994Microsoft John Doe5
1994Microsoft Mark Smith 3
1994Microsoft David Ring
Steve Sidney mweb.co.za> writes:
>
> Dear list
>
> I have quite a small data set in which I need to have the following
> values ignored - not used when performing an analysis but they need to
> be included later in the report that I write.
>
> Can anyone help with a suggestion as to how this
On Mon, Dec 13, 2010 at 8:20 AM, Ethan Arenson
wrote:
> Consider the following missing data problem:
>
> y = c(1, 2, 2, 2, 3)
> a = factor(c(1, 1, 1, 2, 2))
> b = factor(c(1, 2, 3, 1, 2))
> fit = lm(y ~ a + b)
> anova(fit)
>
> Analysis of Variance Table
>
> Response: y
> Df Sum Sq Mean
On 2010-12-13 07:29, PGZC wrote:
TukeyHSD(fit)
Error in UseMethod("TukeyHSD") :
no applicable method for 'TukeyHSD' applied to an object of class "lm"
TukeyHSD(anova)
Error in UseMethod("TukeyHSD") :
no applicable method for 'TukeyHSD' applied to an object of class
"function"
TukeyHSD
On Mon, Dec 13, 2010 at 4:55 PM, Jonathan P Daily wrote:
> ?Sweave
>
> LyX is a bit harder, although you can probably export LyX docs to a *.tex
> and Sweave those fairly painlessly.
>
LyX can play very nicely with Sweave and R.
For the 1.6.x series, you could get started here [1]. If that's not
e
what am I supposed to put into function(x)? The indicator for extracting the
subgroups?
data is the df. cluster={1,...,14}.
This is how I was compiling:
"for (i in 1:14) {
my.summary<-data$cluster==i c(mean(?),var(?))
summary(var_A~cluster, fun=my.summary,data=data)
summary(var_B~cluster, fun=m
Dear R users,
do you know how to print the latex "\odot" symbol subscripted to axes
labels?
Thank you in advance
Gaetano
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R
?Sweave
LyX is a bit harder, although you can probably export LyX docs to a *.tex
and Sweave those fairly painlessly.
--
Jonathan P. Daily
Technician - USGS Leetown Science Center
11649 Leetown Road
Kearneysville WV, 25430
(304) 724-4480
"Is the room still a ro
Hi,
I was hoping to get some advice regarding the testing of interactions, when one
factor is modelled as a random effect...
I have a model with binomial error structure where the response variable is the
proportion of time spent at the main sett (animals were tracked for 28
consecutive days in
Dear list
I have quite a small data set in which I need to have the following
values ignored - not used when performing an analysis but they need to
be included later in the report that I write.
Can anyone help with a suggestion as to how this can be accomplished
Values to be ignored
0 - ze
Hi Sandy,
The way I'd describe it is that you expected the width parameter of
the position adjustment to be relative to the binwidth of the
histogram - but it's actually absolute, and it has to be this way
because there's currently no way for the position adjustment to know
about the parameters of
TukeyHSD(fit)
Error in UseMethod("TukeyHSD") :
no applicable method for 'TukeyHSD' applied to an object of class "lm"
> TukeyHSD(anova)
Error in UseMethod("TukeyHSD") :
no applicable method for 'TukeyHSD' applied to an object of class
"function"
> TukeyHSD(group)
Error in UseMethod("TukeyHS
TukeyHSD(fit)
Error in TukeyHSD(fit) : object 'fit' not found
> TukeyHSD(anova)
Error in UseMethod("TukeyHSD") :
no applicable method for 'TukeyHSD' applied to an object of class
"function"
> TukeyHSD(group)
Error in UseMethod("TukeyHSD") :
no applicable method for 'TukeyHSD' applied to an
Hello,
Are there any packages which allow for a good integration between R and
LaTex / LyX? I'm interested mainly in automatic (automagic?) imports of
plots/graphics.
Thanks in advance and best regards,
Eduardo de Oliveira Horta
[[alternative HTML version deleted]]
On 13/12/2010 10:13 AM, Uwe Wolfram wrote:
Dear R-Users,
I am currently trying to fit a tensorial function in its principal
coorinate system. The function is given by:
1~(x1^2 + x2^2 + x3^2 - chi0*(x1*x2 + x1*x3 + x2*x3))/eps0^2 + (x1 + x2
+ x3)/xi0
Where eps0 = 0.0066, chi0 = -0.66 and xi0 =
I asked Jeff Horner that question a while back and he said it was Linux
only. He doesn't have time to create a windows version.
-Original Message-
From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org]
On Behalf Of Santosh Srinivas
Sent: Saturday, December 11, 2010 8:3
Dear R-Users,
I am currently trying to fit a tensorial function in its principal
coorinate system. The function is given by:
1~(x1^2 + x2^2 + x3^2 - chi0*(x1*x2 + x1*x3 + x2*x3))/eps0^2 + (x1 + x2
+ x3)/xi0
Where eps0 = 0.0066, chi0 = -0.66 and xi0 = 0.011 are obtained from
experimental data usi
batchfiles is a set of batch, javascript and HTML
Application files that are useful for running R and
associated programs on Windows.
Version 0.6-0 updates them for the new architecture
specific directory structure in R 2.12.0 .
A few of the lesser used utilities have been dropped.
Each batchfil
Dear all,
I've written a small booklet on using R for biomedical statistics
(mostly focussed on cohort and case-control studies), available here
under a Creative Commons Attribution 3.0 License :
"A Little Book of R for Biomedical Statistics"
http://a-little-book-of-r-for-biomedi
CH,
How about any:
any("Tiger" == animal)
The function which will tell you the index if any match
which("Tiger" == animal.
You should also look at the match funciton.
Dave
From:
"C.H."
To:
R-help
Date:
12/13/2010 08:50 AM
Subject:
[R] check for item in vector
Sent by:
r-help-boun...
Hi CH,
Check
?is.element
?"%in%"
HTH,
Jorge
On Mon, Dec 13, 2010 at 9:48 AM, C.H. <> wrote:
> Dear R users,
>
> Suppose I have an vector like this:
>
> animal <- c("Tiger","Panda")
>
> I would like to know is there any function that check for the
> existence of certain item in a vector.
>
> e
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