Dear Felipe,
Assuming you are not interested in the exact formulae that are used to
calculate each of these, from top to bottom it is:
minimum, lower quartile, median, upper quartile, maximum
If there are dots, these usually indicate outliers.
Please read ?boxplot for more details on what R wi
Try this:
x <- c(2,5,9,4,5,6,7,8)
u <- replicate(20, sample(x, replace = TRUE))
t(u)
The first argument of replicate() is the number of times to iterate the
process.
I believe you'll find that it does indeed do random sampling; each row
represents
a nonparametric bootstrap sample of x. There are
dump("x", file = "x.R")
file.show("x.R")
will get you most of the way.
-Original Message-
From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org] On
Behalf Of Steven Kang
Sent: Wednesday, 29 September 2010 3:11 PM
To: r-help@r-project.org
Subject: [R] String split and c
Hi Steven,
This should do it:
paste('"', unlist(strsplit(x, split="")), c(rep('",', length(x)-1), ""), sep="")
-Ista
On Wed, Sep 29, 2010 at 1:11 AM, Steven Kang wrote:
> Hi R users,
>
>
> I desire to transform the following vector consisting of repeated characters
>
> x <- rep(letters, 3)
> in
Hi R users,
I desire to transform the following vector consisting of repeated characters
x <- rep(letters, 3)
into this exact format (i.e a single string containing each characters in
quotation mark separated by comma between each; al ).
("a", "b", "c", "d", "a", "b", "c", "d",
Hello, does somebody know in a boxplot, what does each element in the
boxplot represent?
1. lines at the extremes of the dotted lines?
2. Extremes of the boxes
3. Black line in the middle of the box?
4. notches?
Thank you
Felipe Parra
[[alternative HTML version deleted]]
__
I'm on windows xp. I use R 2.11.1 GUI
- Original Message -
From: Greg Snow
To: raje...@cse.iitm.ac.in, r-help
Sent: Wed, 29 Sep 2010 00:48:51 +0530 (IST)
Subject: RE: [R] break function execution
Ctrl-C works on some platforms, it would help us to help you if we knew which
OS you are u
Hi Michael
testdat <- replicate( 50, growth[ sample(nrow(growth), 8, rep=TRUE) ] )
testdat will then be a matrix of 8 x 50 = 400 rows where each lot of 8
is a sample.
Alternatively you can do...
testdat <- replicate( 50, growth[ sample(nrow(growth), 8, rep=TRUE) ],
simplify=FALSE )
Now testdat
I have R randomly sampling my array made up of 2 columns of data. Here is
my code randomly sampling 5 different rows from my dataset to create a new
dataset of 8 rows of data:
testdat<-growth[sample(5,8,replace=T),]
Now I want to tell R to repeat this function 50 times and give me the
On Tue, Sep 28, 2010 at 5:02 PM, statquant2 wrote:
>
> Hello all,
> the test I provided was just to pinpoint that for loading once a big csv
A file that can be read in under 2 seconds is not big.
> file with read.csv was quicker than read.csv.sql... I have already
> "optimized" my calls to read.
On Tue, Sep 28, 2010 at 9:47 PM, Leonardo Monasterio
wrote:
> In the function bellow I want to find the maximum value of v,
> subject to the constrain that the sum of x is equal to 1.
> I want to maximize:
> v<-t(x)%*%distance%*%x
>
> Subject to:
> sum(x)=1
>
> Where:
> "x" is a vector n X 1
> "
Hi,
For my dissertation, I have used xtable profusely. I'm also a fan of
extended captions in the text. However, these captions are unwieldy in the
List of Tables, so I'd like to use the short caption option available with
regular \caption usage. Is this possible?
Thanks,
Cuz
--
View this messa
Hi everyone,
I am doing an analysis of reviews in IMDB and am running into trouble getting
my data into the right shape for analysis.
Key question: I want to know for each word in the IMDB, whether it is over- or
under-represented in a particular category (Rating x Genre). I was figuring o
Hello all,
the test I provided was just to pinpoint that for loading once a big csv
file with read.csv was quicker than read.csv.sql... I have already
"optimized" my calls to read.csv for my particular problem, but is a simple
call to read.csv was quicker than read.csv.sql I doubt that specifying
I am trying to get R to pick random integers from my dataset (i.e.
bootstrapping) with replacement. However, my attempts at this have been
unsuccessful. Here is a basic example of what I am doing:
I have a data vector of 8 integers (data= 2,5,9,4,5,6,7,8). I used the
sample function and it wo
wxffxw writes:
> So, is there any thing like the combination of eclipse and Jgr?
> If not, I am interested to develope something to fulfill this simple but
> very important function. But right now I have no idea where to start. Any
> suggestions?
If you are interested in developing such a browse
Please read the help page carefully, the very first line that describes the
function says, "Minimise a function subject to linear inequality constraints".
OP has a problem with equality constraints: sum(x) = 1.
Furthermore, if you want to solve a QP problem then it is better to use a
dedicate
Mike,
Try
growth[sample(1:length(growth)),]
to permute the rows.
Jonathan
On Tue, Sep 28, 2010 at 8:38 PM, Michael Larkin wrote:
> Thanks to the people on this list I was able to fix my code for randomly
> sampling. Thanks.
>
>
>
> Now, I am moving on to the next step and I ran into another
Hi everyone:
¡¡I am new to R and I have a really basic question.
I have already got a generalized linear model from some dataset, say y=b0
+ b1X1 + b2X2. Then I want to get the value of y provided, say, X1=1, X2=2.
And the confidence Intervals of this y.
I know I can just calculat
Thanks to the people on this list I was able to fix my code for randomly
sampling. Thanks.
Now, I am moving on to the next step and I ran into another snag. I have a
large dataset but I am starting with a small made-up dataset until I figure
it out. I have two columns of data (age and leng
The underlying data contained values that resulted in Factor instead of
number fields during the read.csv. Problem fixed!
I also introduced a typo while copying the error into my message, and as
for the poor variable naming, I'll be more careful.
Thanks x3! Corrected structure:
> str(CPU)
'dat
I got it to work. I didn't have the data listed as a vector (c in front of
the data). I copied Peter's code and it worked perfectly. Thanks!
Mike
From: Jonathan Christensen [mailto:dzhona...@gmail.com]
Sent: Tuesday, September 28, 2010 9:31 PM
To: Michael Larkin
Cc: r-help@r-projec
On 29 September 2010 09:47, Remko Duursma wrote:
>
>
> How about:
>
> y[y[,2] %in% x.samp[,2],]
>
> gives you the subset of y where values in the second column are restricted
> to your sample from x.
>
> You can then sample from this matrix, if you need to...
Just saw this reply tangled up in anot
Hello LB,
It's one of those problems that's basic but tricky :) I don't have an
elegant one-liner for it but here's a function that would do it...
function(xs, y) {
# sample matrix y such that col 2 of the sample matches
# col 2 of matrix xs
used <- logical(nrow(y))
yi <- integer(nrow(xs))
Hi,
I'm just learning to write R extensions in C and to embed R in C.
I was trying to get through the example in the help page on calling the .dll
directly (
http://cran.r-project.org/doc/manuals/R-exts.html#Calling-R_002edll-directly
).
When I compile I consistently get the error that getDLLVer
Mike,
It works for me:
> data <- 1:8
> sample(data,replace=TRUE)
[1] 6 4 5 2 5 8 7 2
Please provide a reproducible example, if possible, and the output of
sessionInfo().
Jonathan
On Tue, Sep 28, 2010 at 7:22 PM, Michael Larkin wrote:
> I am trying to get R to randomly select values from my d
On Tue, Sep 28, 2010 at 6:22 PM, Michael Larkin wrote:
> I am trying to get R to randomly select values from my dataset (i.e.
> bootstrapping) with replacement. However, my attempts at this have been
> unsuccessful. Here is a basic example of what I am doing:
>
> I have a data vector of 8 values
I am trying to get R to randomly select values from my dataset (i.e.
bootstrapping) with replacement. However, my attempts at this have been
unsuccessful. Here is a basic example of what I am doing:
I have a data vector of 8 values (i.e. data= 2,5,9,4,5,6,7,8). I used the
sample function and
Hi Steve,
The basic problem (as the error suggests) is that data of class
"factor" is not allowed in quantile.default. So one of the elements
of your list must be a factor. What are the results of: str(t) ?
As a side note, since t() is a function, using t as a variable name
can be a bit confu
Thanks a lot, Ista!
On Tue, Sep 28, 2010 at 10:00 AM, Ista Zahn wrote:
> Hi Dimitri,
> I'm not proficient with base graphics, but here is a ggplot solution:
>
> my.data.m <- melt(my.data, id="date")
> my.data.m$pn <- "+"
> my.data.m[my.data.m$variable %in% c("y", "z"), "pn"] <- "-"
> my.data.m$va
A list (t) that I'm trying to pass to quantile() is causing this error:
Error in quantile.default(t, probs = c(0.9, 9.95, 0.99))
factors are not allowed
I've successfully use lists before, and am having difficulty finding my
mistake. Any suggestions appreciated!
-Steve
_
Ah, that's interesting - thanks Bill. That's certainly on the right
track for me (Titus, you too ?) especially if the subpattern argument
accepted a vector of multiple group indices.
As you say, this is straightforward in C. I'd be happy to (try to)
make a patch for the R sources if there was some
When using a wireframe, I need to move the colorkey from the "right"
position (default0 towards the plot. I have also needed to adjust the
height and used the code
colorkey=list(T,space='right',height=.5)
I have looked at documents (within levelplot) but cannot find a way to
move the colorkey ot
On Tue, Sep 28, 2010 at 1:24 PM, statquant2 wrote:
>
> Hi, after testing
> R) system.time(read.csv("myfile.csv"))
> user system elapsed
> 1.126 0.038 1.177
>
> R) system.time(read.csv.sql("myfile.csv"))
> user system elapsed
> 1.405 0.025 1.439
> Warning messages:
> 1: closing unus
Hello I am trying to create an xts object from a data frame that has numeric
and string variables. when I create the object all my variables are
converted to string, this is my original data frame:
> head(DatosF)
FECHA CIERRE HORA DE CIERRE SESION/RUEDA PLAZO (De regreso para SIML,
Repos e INTB)
constrOptim() can do linear and quadratic programming problems! See the
following example from the help document.
## Solves linear and quadratic programming problems
## but needs a feasible starting value
#
# from example(solve.QP) in 'quadprog'
# no derivative
How about:
y[y[,2] %in% x.samp[,2],]
gives you the subset of y where values in the second column are restricted
to your sample from x.
You can then sample from this matrix, if you need to...
greetings,
Remko
--
View this message in context:
http://r.789695.n4.nabble.com/drawing-samples-bas
Hi
It is a bug. A fix has been committed.
Thanks for the report!
Paul
On 29/09/2010 10:15 a.m., Ben Bolker wrote:
Barry Rowlingson lancaster.ac.uk> writes:
My point is that in regular text, ylab plots it where it then goes outside
the borders.
With the use of expressions - the text just
On Tue, Sep 28, 2010 at 9:30 AM, Struve, Juliane
wrote:
>
> Hi,
>
> in this self-contained example the file the same error message appears as
> when I read in my original results files.
>
> library (zoo)
> library(chron)
> #generate example data
> Fish_ID=1646
> Date <- "01/01/2004 00:01:00"
>
I would like to fit a glm with Poisson distribution and log link with a known
dispersion parameter. I do not want to estimate the dispersion parameter. I
know what it is, so I simply want to fix it at a constant for this and other
models to follow. My simple, no covariate model is:
Tall.glm<
No. That would not work for equality constraints.
This is quadratic programming problem. Check out `quadprog' or any other
quad programming packages in R.
If you have more general, nonlinearly constrained optimization you can use
any one of the 3 following packages:
1. `spg' function in "BB"
It would help if you were to tell up which package you are talking about. I
take it this is the survival package and this is the proportioanl hazards
fitting function for case-cohort data.
You would have seen earlier in the code that
method <- match.arg(method)
so at that stage 'method'
Hi, everyone. I have what I hope will be a simple coding question. It seems
this is a common job, but so far I've had trouble finding the answer in
searches.
I have two matrices (x and y) with a different number of observations in
each. I need to draw a random sample without replacement of observa
Dear R-users,
I am trying to estimate a state space model of the form
(1) b_t = G * b_t-1 + w_tw_t ~ N(0,W)
(2) y_t= A' * x_t + H' * b_t + v_t v_t ~ N(0,V)
(Hamilton 1984: 372)
In particular my estimation in state space form looks like
(3) a3_t = 1 * a3_t-1 + w_t w_t
Barry Rowlingson lancaster.ac.uk> writes:
> > My point is that in regular text, ylab plots it where it then goes outside
> > the borders.
> > With the use of expressions - the text just doesn't show up.
> > Originally I thought it was because of my miss-use of expressions, until I
> > figured it
I suspect the problem is that table() is not displaying the correct
length. Try
table(n, useNA="ifany")
--Susan
>Message: 75
>Date: Mon, 27 Sep 2010 11:41:24 -0700
>From: Henrik Bengtsson
>To: Ben Bolker
>Cc: r-help
>Subject: Re: [R] Problem with unlist
>Message-ID:
>
>Content-Type
Dear R users,
In the function bellow I want to find the maximum value of v,
subject to the constrain that the sum of x is equal to 1.
I want to maximize:
v<-t(x)%*%distance%*%x
Subject to:
sum(x)=1
Where:
"x" is a vector n X 1
"distance" is a matrix n*n and it is given.
(In practice, the numbe
On Tue, 28 Sep 2010, Mark Miller wrote:
I justed wanted to provide a description of how I was able to view source
code of a function.
First download the Program R package containing the function. Specifically,
download the file that ends in "tar.gz". This is a compressed file. Expand
the c
On 29/09/2010 6:24 a.m., statquant2 wrote:
Hi, after testing
R) system.time(read.csv("myfile.csv"))
user system elapsed
1.126 0.038 1.177
R) system.time(read.csv.sql("myfile.csv"))
user system elapsed
1.405 0.025 1.439
Warning messages:
1: closing unused connection 4 ()
Hi,
I'm using "by" to summarize by multiple groups, and want to extract the
returned into a pretty dataframe. I'm trying to find a simple way to
name the rows of the data frame. I'd like it to be something like
index1.val1.index2.val2 where the index1 and index2 are the names of the
indice
Dear all,
I am reading the cch function source code. But I can not understand the
following codes. Please help me.
What's the fitter here?
fitter <- get(method)
out <- fitter(tenter = tenter, texit = texit, cc = cc, id = id, X = X, ntot
= nn, robust = robust)
[[alternative HTML version
On Tue, Sep 28, 2010 at 12:18 PM, Greg Snow wrote:
> Ctrl-C works on some platforms, it would help us to help you if we knew which
> OS you are using, which version of R you are using, and in some cases whether
> you are using the GUI or Terminal version of R.
>> Hi,
>>
>> I have an R function
The instructions below are for examining files from a source code file.
For package binaries, the R code may be in a binary file (.rdb).. Then
the following will help.
The first thing to try is to
Download and install the package and type library(packagename)
Type the function name (without the
Also ?sprintf for another approach.
--
Gregory (Greg) L. Snow Ph.D.
Statistical Data Center
Intermountain Healthcare
greg.s...@imail.org
801.408.8111
> -Original Message-
> From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-
> project.org] On Behalf Of Johannes Huesing
> Sent:
Ctrl-C works on some platforms, it would help us to help you if we knew which
OS you are using, which version of R you are using, and in some cases whether
you are using the GUI or Terminal version of R.
--
Gregory (Greg) L. Snow Ph.D.
Statistical Data Center
Intermountain Healthcare
greg.s...@
I justed wanted to provide a description of how I was able to view source
code of a function.
First download the Program R package containing the function. Specifically,
download the file that ends in "tar.gz". This is a compressed file. Expand
the compressed file using, for example, "WinZip"
To speed things up, you certainly want to give R more clues about your
data files by being more explicit by many of the arguments (cf.
help(read.table), especially specifying argument 'colClasses' makes a
big difference.
/Henrik
On Tue, Sep 28, 2010 at 10:24 AM, statquant2 wrote:
>
> Hi, after t
?constrOptim
--
View this message in context:
http://r.789695.n4.nabble.com/constrained-optimization-which-package-tp2717677p2717719.html
Sent from the R help mailing list archive at Nabble.com.
__
R-help@r-project.org mailing list
https://stat.ethz
gaussllego gmail.com> writes:
> I would also like to know if there's a trully reliable,recommended wavelet's
> library in R(In the sense that if,for example, there's some library that's
> often used in scientific projects or mentioned in articles).
I don't know, but I would suggest that you t
Dear R users,
I want to find the maximum value of v, subject to the constrain that
the sum of x is equal to 1.
So, I want to maximize:
v<-t(x)%*%distance%*%x
Subject to:
sum(x)=1
Where:
"x" is a vector n X 1
"distance" is a matrix n*n and it is given.
(In practive, the number of n can go up to
Hi, after testing
R) system.time(read.csv("myfile.csv"))
user system elapsed
1.126 0.038 1.177
R) system.time(read.csv.sql("myfile.csv"))
user system elapsed
1.405 0.025 1.439
Warning messages:
1: closing unused connection 4 ()
2: closing unused connection 3 ()
It seems that
Hi djmuseR!
Hi everybody!
Thanks for your answer djmuseR (I've just discovered the sos library and
it's really useful,xD)...
I would also like to know if there's a trully reliable,recommended wavelet's
library in R(In the sense that if,for example, there's some library that's
often used in scien
Well, try following the correct conventions ...
1. Double click on an .Rdata file, which is produced by saving from R,
and it will open.
2. Drag and drop a .R or any text file into an open R window and it
will source the contents.
This is probably documented somewhere .. maybe in the RW FAQ.
--
Hi Kye,
I have never gotten .R files to work quite like other types (e.g.,
double-clicking a .PDF) in Windows. AFAIK there is no simple way to
do it, because you do not edit scripts directly in R (I am happy to be
corrected if someone knows better). For general use, I would just
open R first and
I am new to using R. I installed R on my computer (Windows) and everything
things appears to be just fine. However, I have a simple script RTest.R
that does a few simple calculations. When I double-click the RTest.R icon,
I get an Information dialong box which says, "ARGUMENT 'C:\Documents and
S
Hi,
There is a very handy feature of boxplot() that will handle this
easily. You can write formulae of the form:
scores ~ groups
For your sample data:
# read in data
dat <- read.table(textConnection("
id cat value
1 a12
2 a23
3 a14
4 b2
5 b3
6 c9
7 c8
Hi,
I have a data set in the following format:
id cat value
1 a12
2 a23
3 a14
4 b2
5 b3
6 c9
7 c8
8 c10
9 d30
I would like to set up boxplots for each category. The actual category names
are long and many so I would like this to be split
> -Original Message-
> From: r-help-boun...@r-project.org
> [mailto:r-help-boun...@r-project.org] On Behalf Of Michael Bedward
> Sent: Tuesday, September 28, 2010 12:46 AM
> To: Titus von der Malsburg
> Cc: r-help@r-project.org
> Subject: Re: [R] Regular expressions: offsets of groups
>
Si ce message ne s'affiche pas correctement, [1]visualisez la version en
ligne
[2]Remplissez ce formulaire pour ne plus recevoir notre newsletter.
A réception, celui-ci sera pris en compte.
References
Visible links
1. http://ase.e
Hi
I'm trying to fit arima models with the arima() function and I have two
questions.
##
##1. ##
##
I have n observations for my time series. Now, no matter what
arima(p,d,q)- model I fit, I always get n residuals. How is that possible?
For example: If I try this out myself on an AR(
Hi,
predict(model_fit, se.fit=TRUE)
see ?predict.lm for details.
-Ista
On Tue, Sep 28, 2010 at 12:16 PM, Brima wrote:
>
> Hi all,
>
> This is very basic but for a starter nothing is. I have a simple linear
> regression I am using to predict some values and I need the standard error
> of the pr
Try this:
df[1,] <- as.character(df[1,])
On Tue, Sep 28, 2010 at 8:48 AM, Nicola Sturaro Sommacal (Quantide srl) <
mailingl...@sturaro.net> wrote:
> Hi!
>
> I have a table representing both absolute and relative frequency, for
> example (code to get example data under the signature):
>
>
Try
round(df,2)
for two decimal digits
Gabriela
2010/9/28, Nicola Sturaro Sommacal (Quantide srl) :
> Hi!
>
> I have a table representing both absolute and relative frequency, for
> example (code to get example data under the signature):
>
>ItalyGermany
> absolute100
Hi,
in this self-contained example the file the same error message appears as when
I read in my original results files.
library (zoo)
library(chron)
#generate example data
Fish_ID=1646
Date <- "01/01/2004 00:01:00"
Date <- as.POSIXct(strptime(Date,format="%m/%d/%Y %H:%M:%S"))
R2sqrt <-100
#p
Hi!
I have a table representing both absolute and relative frequency, for
example (code to get example data under the signature):
ItalyGermany
absolute100 105
relative 40.51 41.18
How can I print a different number of decimal digits? I try to tr
BINGO
we have the solution
thanks a lot both, Deepayan and Dennis, for your help
Christophe
On Tue, Sep 28, 2010 at 2:10 PM, Deepayan Sarkar
wrote:
> On Tue, Sep 28, 2010 at 12:59 PM, Christophe Bouffioux
> wrote:
> > Thanks for your help Peter
> > but the red marks on boxplot do not correspon
Hi all,
This is very basic but for a starter nothing is. I have a simple linear
regression I am using to predict some values and I need the standard error
of the prediction (forecast). Whats the easiest/bestway of getting this
error?
Best regards
--
View this message in context:
http://r.78969
Unless you tell us what model or what forecasting technique you want to
use, it seems to me that this is more a question about Statistics than
about using R.
Best,
Giovanni Petris
On Mon, 2010-09-27 at 23:02 +0100, Dr. Alireza Zolfaghari wrote:
> Hi list,
> I have a set of data which I want to
Hi Dimitri,
I'm not proficient with base graphics, but here is a ggplot solution:
my.data.m <- melt(my.data, id="date")
my.data.m$pn <- "+"
my.data.m[my.data.m$variable %in% c("y", "z"), "pn"] <- "-"
my.data.m$variable <- factor(my.data.m$variable, levels=c("a", "x", "y", "z"))
my.data.m$Date <- a
zozio32 gmail.com> writes:
>
>
> Hi
>
> I had to use a glm instead of my basic lm on some data due to unconstant
> variance.
>
> now, when I plot the model over the data, how can I easily get the 95%
> confidence interval that sormally coming from:
>
> > yv <- predict(modelVar,list
Thanks for all the suggestions. It seems that I still have to write my own code
after all.
But I am really surprised that no one has done it in a proper package yet.
KC
^_^
On 28/09/2010, at 9:18 PM, Dennis Murphy wrote:
> Hi:
>
> Try here:
>
> https://stat.ethz.ch/pipermail/r-he
Hi:
You might find this useful:
http://finzi.psych.upenn.edu/R/library/wavelets/html/ecg.html
You could also try package wmtsa, the Insightful Wavelet Methods for Time
Series Analysis package. But there's more :)
The results of this search also appear to dig up some useful packages and
functions
I'll check that book out and/or get help from the authors. But i was still
hoping there is some basic way to compare these 3d plots using R.
By the way, I figured out i can draw these plots using command "image" and
get a gradient heat map or topography map with gradients. Is there a
function in
On Tue, Sep 28, 2010 at 12:59 PM, Christophe Bouffioux
wrote:
> Thanks for your help Peter
> but the red marks on boxplot do not correspond to ex2 dataframe
> actually, it reproduce on each panel the same marks
> that is to say the 3 first lines of ex2
> So this is not correct
You are probably lo
On Mon, Sep 27, 2010 at 3:04 AM, Petr PIKAL wrote:
> Hi
> I noticed that nobody answered your question yet so here is my try.
>
> If you want to see what objects are in your environment you can use ls()
> but its output is only names of objects. Here is a function I use a long
> time for checking
Hi:
I did this in ggplot2, which seemed easier than the approach you tried in
lattice's bwplot() - as far as I can tell, you want to plot the unique value
of v1b as a red dot in each boxplot. To that end,
ex <- data.frame(v1 = log(abs(rt(180, 3)) + 1),
v2 = rep(c("2007", "2006", "
On Tue, Sep 28, 2010 at 6:52 AM, Titus von der Malsburg
wrote:
> On Tue, Sep 28, 2010 at 9:46 AM, Michael Bedward
> wrote:
>> What Titus wants to do is akin to retrieving capturing groups from a
>> Matcher object in Java.
>
> Precisely. Here's the description:
>
> http://download.oracle.com/jav
Hi,
I am trying to generate a binary mixed logit model which contains only
individual specific data (no alternative specific data). Each observation is
contained within one line (data shape = "wide"). For example:
Individual ID Dependent variableIndependent variable 1
..In
trb1 [Tue, Sep 28, 2010 at 12:12:01PM CEST]:
[...]
> Also, how can I combine several variables in text
> i.e. suppose I have
> a <- "one"
> b <- "two"
> then what expression can I place in
> title(main=...)
> in terms of a and b to give an output title of
> "one, two"
> i.e. a then b separated
On Tue, Sep 28, 2010 at 9:46 AM, Michael Bedward
wrote:
> What Titus wants to do is akin to retrieving capturing groups from a
> Matcher object in Java.
Precisely. Here's the description:
http://download.oracle.com/javase/1.4.2/docs/api/java/util/regex/Matcher.html#start(int)
Gabor's lookbe
I need your kind help regarding the following:
I wish to know is there any way to use R in Visual Basic environment. I want
to develop a VB application where R can be embedded (R will work as a back
end statistical engine). If available, please provide me some source of
study materials/articles av
Hi!!
I'm looking for a package in R for time series analysis using wavelets( I'm
interested on extractingt information from electrocardiograms with the aim
of study the heart rate variability) so i want to know which package is the
best for me. I've thinking about using some of those(you can reco
Hi:
Try here:
https://stat.ethz.ch/pipermail/r-help/2006-September/113156.html
HTH,
Dennis
On Mon, Sep 27, 2010 at 7:27 PM, Kohleth Chia wrote:
> Dear all,
>
> I am trying to look for a built in function that performs the cochran Q
> test.
> that is, cochranq.test(X)
> where X is a contingenc
On Tue, Sep 28, 2010 at 10:35 AM, Tal Galili wrote:
> My point is that in regular text, ylab plots it where it then goes outside
> the borders.
> With the use of expressions - the text just doesn't show up.
> Originally I thought it was because of my miss-use of expressions, until I
> figured it
Hi:
Perhaps this might be useful:
tst <- read.table(textConnection("
+plate.id well.id Group HYB rlt1
+ 1 P1 A1 Control SKOV3hyb 0.190
+ 2 P1 A2 Control SKOV3hyb 0.210
+ 3 P1 A3 Control SKOV3hyb 0.205
+ 4 P1 A4 Control SKOV3hyb 0.206
Hi,
I have an R function that executes for a little over a minute. When the
function starts running, the R interface freezes and doesnt change until the
function exits cleanly. Is there someway I can force the function to exit
without messing up the interface?(An equivalent of Ctrl-C)
Additio
Thanks for your help Peter
but the red marks on boxplot do not correspond to ex2 dataframe
actually, it reproduce on each panel the same marks
that is to say the 3 first lines of ex2
So this is not correct
Christophe
On Mon, Sep 27, 2010 at 6:18 PM, Peter Ehlers wrote:
> On 2010-09-27 4:54, Ch
try this:
a <- "one"
b <- "two"
paste(a, b, sep = ", ")
I hope it helps.
Best,
Dimitris
On 9/28/2010 12:12 PM, trb1 wrote:
Hi all,
how can I manually create a data.frame or similar object to display in a
textplot, that omits column and row numbers/headings?
Also, how can I combine sever
In the date.frame/ text plot, would it be possible to change the font size of
one of the lines?
Thanks
--
View this message in context:
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Hi all,
how can I manually create a data.frame or similar object to display in a
textplot, that omits column and row numbers/headings?
Also, how can I combine several variables in text
i.e. suppose I have
a <- "one"
b <- "two"
then what expression can I place in
title(main=...)
in terms of a
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