Hi:
On Tue, Jul 20, 2010 at 5:37 PM, Glen Barnett wrote:
> Hi Dennis,
>
> Thanks for the reply.
>
> Yes, that's easier, but the conversion to a matrix with rbind has
> converted the output of that final function to a numeric.
>
If you look at the output of lapply(attitude, f), you'll see that t
On Tue, Jul 20, 2010 at 6:37 PM, H Rao wrote:
> Hi,
>
> Is there a function to get the last(or first) day of the week, given the
> week number of the year?
>
> For eg, week number for 7/20 is 29 as obtained by format(Sys.Date(),"%U"),
> is there a function which returns 7/25 - the last day of week
Hi,
I'm trying to replicate your program. It may be not the same as yours, hope
it helps.
## Create a vector of numbers
cip <- seq(1.0,2.5,by=0.1)
## Create ecdf function
Fn <- ecdf(cip)
## Create f function
f <- function(x){(1-Fn(x))^4}
## Create integrate function
## Because the integrate
Hello UseR cpnference participants,
could you give us some impressions of the conference so far (for those of us
who stayed at home ..)?
And will there be photos be made available ?
Thanks,
Friedrich Schuster
Dompfaffenweg 6
69123 Heidelberg
_
On Jul 20, 2010, at 6:37 PM, H Rao wrote:
Hi,
Is there a function to get the last(or first) day of the week, given
the
week number of the year?
For eg, week number for 7/20 is 29 as obtained by
format(Sys.Date(),"%U"),
is there a function which returns 7/25 - the last day of week # 29
see ?sp::overlay and section 5.2 of Applied Spatial Data Analysis with R
I see there is now also raster::overlay, but I can't claim experience
with that funciton (however my impression is that the raster package
is a powerful tool for working with potentially very large rasters in
R).
hth,
Kingsf
I'm not that familiar with this type of data.
I just had a similar issue, but had a GIS person do it in Arc view.
But maybe try some of the following functions?
Match
%in%
Plus I'll forward U the replies I got to my post
Good luck :-)
-Original Message-
From: r-help-boun...@r-project.o
On 7/20/10 8:14 PM, David Winsemius wrote:
>
> On Jul 20, 2010, at 7:21 PM, Joshua Wiley wrote:
>
>> Hi Nicolas,
>>
>> You nee to explicitly wrap it in print() when it is inside a loop (if
>> I'm not mistaken also when inside a function). With lattice loaded,
>> you can find the specific print m
On Jul 20, 2010, at 8:37 PM, Glen Barnett wrote:
Hi Dennis,
Thanks for the reply.
Yes, that's easier, but the conversion to a matrix with rbind has
converted the output of that final function to a numeric.
I included that last function in the example secifically to preclude
people assuming t
Hi Dennis,
Thanks for the reply.
Yes, that's easier, but the conversion to a matrix with rbind has
converted the output of that final function to a numeric.
I included that last function in the example secifically to preclude
people assuming that functions would always return the same type.
I g
Hi All,
I have a problem to create a variable that is a function of an integral of
another function.
The problem is the following:
I have a variable called cip. I have to create another variable called bip
that is a function of the former variable cip and also the cumulative
distribution funct
On Jul 20, 2010, at 7:21 PM, Joshua Wiley wrote:
Hi Nicolas,
You nee to explicitly wrap it in print() when it is inside a loop (if
I'm not mistaken also when inside a function). With lattice loaded,
you can find the specific print methods by methods(print) .
The interpreter handles finding
My last query related to this referred to a problem with not being able to
store data. A suggestion was made to try to convert the data returned by
fitdist into a data.frame before using rbind. That failed, but provided the
key to solving the problem (which was to create a data.frame using the
va
Ty sir!
--
View this message in context:
http://r.789695.n4.nabble.com/Y-axis-break-tp2295499p2296347.html
Sent from the R help mailing list archive at Nabble.com.
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEAS
Hi Nicolas,
You nee to explicitly wrap it in print() when it is inside a loop (if
I'm not mistaken also when inside a function). With lattice loaded,
you can find the specific print methods by methods(print) . From your
example:
pdf("temp1.pdf", width=8, height=8)
for(k in 1) {
print(wireframe(
Hi,
I'm hitting a strange problem where pdf plots that I'm trying to make
are blank, only when produced from within a loop. The pdf contains 0 page.
I've narrowed the problem to this minimal script that invariably
produces an empty pdf with my setup:
pdf("/local/scratch/1.pdf", width=8, height=8)
Hi,
Is there a function to get the last(or first) day of the week, given the
week number of the year?
For eg, week number for 7/20 is 29 as obtained by format(Sys.Date(),"%U"),
is there a function which returns 7/25 - the last day of week # 29
TIA,
Rao.
[[alternative HTML version delete
Maureen Ryan ucdavis.edu> writes:
>
> Hi,
> I have three years of species presence/absence data for a set of ~100
> ponds, with a list of associated habitat characteristics (park, vegetation,
> hydroperiod, etc.). The datasets differ slightly by year because some ponds
> were dry in some y
Thank you very much to all of you for the responses!
Phil, the following two examples worked well in re-categorizing. Is there
any way I can retain my original data.frame format? Once I re-categorize
the data, the format becomes numeric and the original column names are not
retained. I probably
Hi
split.screen() works by maintaining a set of par(fig) settings, so that
a call to screen() is essentially a call to par(fig=).
Hence, an explicit par(fig=) call mucks up the plot
arrangement made by screen().
Are you trying to use par(fig) to split up a split.screen() screen into
even sm
On Tue, Jul 20, 2010 at 2:34 PM, harsh yadav wrote:
> Hi,
>
> I am running a query using sqldf() [package : sqldf]. The query is:-
>
> userid <- 5
> taskid <- 5
>
> tab1 <- fn$sqldf("SELECT tobiiEvents.data1, tobiiEvents.data2,
> events.`timestamp` as tobiiTime
> FROM tobiiEvents
> INNER JOIN eve
So the answer is yes.
Install the MySQL Workbench application on your XP box
and work out the URL, account name and password, and
port connection issues to the reomte MySQL database.
You should then have a MySQL driver available.
Set up a User DSN or System DSN to the remote database
using O
Sigbert,
for a first idea see Duncan Murdoch's article about the new help system
in one of the last issues.
Best,
Uwe
On 19.07.2010 20:16, Sigbert Klinke wrote:
Hi,
from the documentation of help.search I think that fields like "concept"
and "keywords" in the R help database exists. How ca
Sorry, it was a typo:)
http://r.789695.n4.nabble.com/break-axis-using-plotrix-td803987.html#a803987
-
A R learner.
--
View this message in context:
http://r.789695.n4.nabble.com/Y-axis-break-tp2295499p2296254.html
Sent from the R help mailing list archive at Nabble.com.
__
Hi.
Thank for your reply. However, the link you provided don't works (for me at
least).
Regards,
Phil
--
View this message in context:
http://r.789695.n4.nabble.com/Y-axis-break-tp2295499p2296202.html
Sent from the R help mailing list archive at Nabble.com.
___
I see. Thank you, David. One more question: How can one obtain bootstrapped
standard errors for these regression coefficients. I tried the boot.rq
procedure, but the results do not look right.
Steve
--
Steve McDonald
Assistant Professor of Sociology
North Carolina State University
Phone: 919-5
On 20.07.2010 06:24, cob wrote:
Thanks for the response. I used this command:
.libPaths(c("C:\\Program Files\\R\\R-2.11.1\\library\\slam",.libPaths()))
No, the .libPaths() should contain "C:\\Program
Files\\R\\R-2.11.1\\library" or the same with single forward slashes.
If that is already
On Sun, Jul 18, 2010 at 6:44 PM, jlwoodard wrote:
>
> Hi Phil and Jeff,
> Thanks so much for taking the time to help me solve this issue! Both
> approaches work perfectly. Each of your approaches helped me learn more
> about what R can do. I really appreciate your help!
Hi John,
Now that
Dear all,
I have a very short code written in Mathematica which I would need to get
translated for use in R.
I'm not an expert in Mathematica (which is why I would not
feel comfortable with doing the translation myself), but the code is very
short (probably 30-40 lines) and looks quite simple fro
Hi AAditya,
I really wasn't trying to be rude. Sarcastic, yes. Rude, no.
The list is frequented by people ranging from leading statistics
professors to students looking for someone to do their homework for
them. I only receive the digest form of the r-help list and saw that
someone had alread
On Jul 20, 2010, at 2:45 PM, Farley, Robert wrote:
"Read the help page for density more carefully. Especially the bw and
from arguments."
Yes, it was my inability to make sense of the help page that
motivated my email.
My distances range from 0.4 to 7.6 but the density plot ranges from
Hi,
I have three years of species presence/absence data for a set of ~100
ponds, with a list of associated habitat characteristics (park, vegetation,
hydroperiod, etc.). The datasets differ slightly by year because some ponds
were dry in some years and not in others. My goal is to look at ha
On Jul 20, 2010, at 1:05 PM, confusedcius wrote:
Hi there,
I entered over 2000 lines of data into R from SQLite
How?
and saved it in R as a
data.frame,
How?
but the data.frame only gives the first 500 lines. Is there any
way to either increase the default limit or to determine which o
Will something like the %in% statements below help?
x1 <- 1
x2 <- 5
y1 <- c(2,3)
y2 <- c(4,5)
y3 <- c(7,8)
x1 %in% y1 ||x2 %in% y2
x1 %in% y1 ||x2 %in% y3
--- On Tue, 7/20/10, Jim Maas wrote:
> From: Jim Maas
> Subject: [R] simplify if statement in R ?
> To: r-help@r-project.org
> Receiv
But perhaps not on outdated versions of R < 2.10.0 .
Uwe Ligges
On 19.07.2010 00:55, Joshua Wiley wrote:
Hi Grace,
I'm using the UCLA mirror and this code installs equate fine for me.
#install the package (note that the quoted name)
install.packages("equate")
#load the package
library(eq
On 20-07-2010, at 20:30, litao.ext [via R] wrote:
> yes, the matrix is symmetric.
>
> But when I apply normalize upon rows, I expect to get the following result:
> > apply( a, 1, normalize )
> [,1] [,2] [,3] [,4] [,5]
> [1,] 0.00 0.25 0.50 0.75 1.00
> [2,] 0.00 0.25 0.50 0.75 1.00
>
"Read the help page for density more carefully. Especially the bw and
from arguments."
Yes, it was my inability to make sense of the help page that motivated my
email.
My distances range from 0.4 to 7.6 but the density plot ranges from -2 to 10.
"from=0" seems to hide the negative portion
Josh,
Thank you for your help. The latter method does exactly what I want in one line
of code per variable.
Also, fyi, I just came across another method that uses %in% in place of == when
NA's are present in
the test condition variable data and it too works. So my new code is now:
PBTCHE$ANY
On 20/07/2010 12:18 PM, Tra, Yolande wrote:
Hi,
I could not locate library ts in the CRAN website. Please help.
The ts package was a base package, but it was merged into the stats
package 5 or 6 years ago. You probably want a more current reference.
Duncan Murdoch
___
Hi,
I am running a query using sqldf() [package : sqldf]. The query is:-
userid <- 5
taskid <- 5
tab1 <- fn$sqldf("SELECT tobiiEvents.data1, tobiiEvents.data2,
events.`timestamp` as tobiiTime
FROM tobiiEvents
INNER JOIN events ON events.eventid = tobiiEvents.eventid
WHERE tobiiEvents.subtype =
On 20/07/2010 2:11 PM, Jim Maas wrote:
I found a form of the if statement that works but it is very long. I'm
attempting to check the value of of two different variables to see if
they evaluate to either of two different values, which will result in a
division by 0 in the final equation. This
Hi Jim,
Without a reproducible example I can't test my solution against yours,
but does this do what you are looking for?
#Some Sample data
x0.trial01 <- 1
x1.trial01 <- 2
npt01 <- 2
if(any(c(x0.trial01, x1.trial01) %in% c(0, npt01))) {
x0.trial01.in <- x0.trial01 + 0.5
x1.trial01.in <- x1.t
yes, the matrix is symmetric.
But when I apply normalize upon rows, I expect to get the following result:
> apply( a, 1, normalize )
[,1] [,2] [,3] [,4] [,5]
[1,] 0.00 0.25 0.50 0.75 1.00
[2,] 0.00 0.25 0.50 0.75 1.00
[3,] 0.00 0.25 0.50 0.75 1.00
[4,] 0.00 0.25 0.50 0.75 1.00
[5,] 0.00 0.25
Hi there,
I entered over 2000 lines of data into R from SQLite and saved it in R as a
data.frame, but the data.frame only gives the first 500 lines. Is there any
way to either increase the default limit or to determine which of the
original lines should be in the output (e.g. maybe the last 500 i
Dear R users,
I have some question about Varimax rotation of the loadings obtained from a
PCA.
Imagine X is a field where the rows are the observations and the columns are
the variables. I obtain the loadings (L), the principal components (PC) and
the percentage of the variance for each mode (PVa
Hi,
I could not locate library ts in the CRAN website. Please help.
Yolande
[[alternative HTML version deleted]]
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-pr
I try to utilize some operations on rows in a matrix using command 'apply'
but find a problem.
First I write a simple function to normalize a vector (ignore error
handling) as follows:
normalize = function( v ) {
return( ( v-min(v) ) / ( max(v) - min(v) ) )
}
The function works fine for
On Mon, Jul 19, 2010 at 11:12 PM, Christian Raschke
wrote:
> but in the end I have other cases, where the logical vector is
> obtained from other operations or where the value that is assigned is
> different case by case; for example,
>
> levels(something.long)[levels(something.long) %in% LETTERS
plotrix can do it.
There is a post about axis break.
http://r.789695.n4.nabble.com/template/NodeServlet.jtp?tpl=reply&node=2295499
-
A R learner.
--
View this message in context:
http://r.789695.n4.nabble.com/Y-axis-break-tp2295499p2295998.html
Sent from the R help mailing list archive at
I found a form of the if statement that works but it is very long. I'm
attempting to check the value of of two different variables to see if
they evaluate to either of two different values, which will result in a
division by 0 in the final equation. This first if statement works for me
__
On 20/07/2010 12:42 PM, Jannis wrote:
Dears,
do you know whether it is possible to include any square parantheses (brackets)
in an expression to use it as an axis label?
e.g. I would like to have a label like (with the sub and superscripts correct):
"speed [m s^-1]"
I know how to combine an
On Jul 20, 2010, at 12:42 PM, Jannis wrote:
Dears,
do you know whether it is possible to include any square parantheses
(brackets) in an expression to use it as an axis label?
e.g. I would like to have a label like (with the sub and
superscripts correct):
"speed [m s^-1]"
Not exactl
Dears,
do you know whether it is possible to include any square parantheses (brackets)
in an expression to use it as an axis label?
e.g. I would like to have a label like (with the sub and superscripts correct):
"speed [m s^-1]"
I know how to combine an expression with text via paste, but as
Works on OSX 10.5.8 + R2.11.1
--
David.
On Jul 20, 2010, at 1:36 PM, Henrique Dallazuanna wrote:
I don't know if this works in OSX, but in XP:
plot(0)
title('\u00ae - \u2122')
On Tue, Jul 20, 2010 at 2:22 PM, Dennis Fisher
wrote:
Colleagues,
What is the easiest means to embed a:
Thank you very much for your effort!
But is there a measure, which can compare the goodness of fit of regression
models with and without the intercept? Can I only compare them in terms of
sum of squares residual?
--
View this message in context:
http://r.789695.n4.nabble.com/Correct-statistical
Hi Mike,
Probably the simplest way from what you have done would be to just set
any NA values in the column to 0:
DF$ANYEF[is.na(DF$ANYEF)] <- 0
Alternately, you can try this. It should work, but it is far from elegant.
DF$ANYEF <- with(DF, ifelse(
rowSums(cbind(PSOUGHT1, PSOUGHT2, PSOUGHT3)
Try this, assuming your data is consistent:
> x <- read.table(textConnection('"NoReduction" "NoReduction"
+ "Reduction""Reduction"
+ "NoReduction" "NoReduction"
+ "NoReduction" "NoReduction"
+ "Reduction""Reduction"
+ "Red
I don't know if this works in OSX, but in XP:
plot(0)
title('\u00ae - \u2122')
On Tue, Jul 20, 2010 at 2:22 PM, Dennis Fisher wrote:
> Colleagues,
>
> What is the easiest means to embed a:
>® (registered)
> or
>⢠(trademark)
> sign in text in a graphic. I would like to u
litao.ext wrote:
>
> I try to utilize some operations on rows in a matrix using command 'apply'
> but find a problem.
>
> First I write a simple function to normalize a vector (ignore error
> handling) as follows:
> normalize = function( v ) {
> return( ( v-min(v) ) / ( max(v) - min(v) )
On Jul 20, 2010, at 1:14 PM, Heiman, Thomas J. wrote:
Hi Y'all,
I have some data in a table with 2 columns. There are two values:
"Reduction" and "No Reduction. " I am trying to make a new variable
change which recode the combinations from column 1 and 2 into a
single number. Here is a
You may want to take a look at the lavaan package and use the multigroup
analysis there (and see if you even need to group by country as well).
Otherwise, you could do something like
library(sem)
library(plyr)
cfa_func<-function(a.df){
cfa<-sem(ses.model, cov(a.df[,2:7], nrow(a.df)))
Colleagues,
What is the easiest means to embed a:
® (registered)
or
™ (trademark)
sign in text in a graphic. I would like to use mtext and avoid plotmath, if
possible. Ideally, the sign should be superscripted but I can easily sacrifice
that.
Optimally, I need a solution that
Thanks, Peter
This more or less corresponds to the solution I came to, modulo xyinch()
and atan2(x,y) = atan(x/y).
It is mostly intended as a replacement for arrows() in statistical
diagrams/plots where you want to
show a given range in a plot precisely without additional boundary lines.
It wo
Hi Y'all,
I have some data in a table with 2 columns. There are two values: "Reduction"
and "No Reduction. " I am trying to make a new variable change which recode
the combinations from column 1 and 2 into a single number. Here is a snippet
from the table:
[1,] "NoReduction" "No
Did you explore the "fOptions" package? Apart from lot of in-build
functionalities you would see there lot of good references on options
pricing.
Thanks,
--
View this message in context:
http://r.789695.n4.nabble.com/Option-pricing-models-tp2295760p2295842.html
Sent from the R help mailing list
David:
Thank you for your comments.
I do understand that absolute values of likelihoods by themselves aren't
meaningful, and only gain meaning when compared with others computed using
the same model but with differing parameter values (for example). That is
why I compute likelihoods myself for
On Tue, Jul 20, 2010 at 9:58 AM, wrote:
> For nls, the fixing (or masking) of parameters is not, to my knowledge,
> possible.
>
> This is something I've been trying to get in such routines for over 2
> decades. Masks are
> available, but not yet well documented, in Rcgmin and Rvmmin packages.
> H
R experts,
I have been unable to get the following ifelse statement to work as desired
when applied
to my data frame.
Example:
DF$ANYEF <-
with(DF,ifelse(PSOUGHT1=='ANY'|PSOUGHT2=='ANY'|PSOUGHT3=='ANY',PEFF,0))
# this statement will be replicated 16 times for 16 unique _EF variables ##
wrote in message
news:33466.129.6.253.2.1279634282.squir...@webmail02.uottawa.ca...
> For nls, the fixing (or masking) of parameters is not, to my knowledge,
> possible.
>
> This is something I've been trying to get in such routines for over 2
> decades. Masks are
> available, but not yet well do
On Jul 20, 2010, at 11:20 AM, Charles Annis, P.E. wrote:
Dear R-experts:
I am using survreg() to estimate the parameters of a Weibull density
having
right-censored observations. Some observations are weighted. To do
that I
regress the weighed observations against a column of ones.
When
Here is a function I use to convert a numeric value of the UNIX time to POSIXct
unix2POSIXct <- function (time) structure(time, class =
c("POSIXt", "POSIXct"))
On Tue, Jul 20, 2010 at 9:26 AM, Jim Hargreaves wrote:
> Dear List,
>
> After much searching with no success, I would like to ask
Consider using a 'list' to hold the matrices:
dataList <- lapply(1:47, function(num){
read.csv(paste('country', num, '.raw', sep=''), header=TRUE)
}
You can then access your data like:
dataList[[23]] for the 23rd file read in.
On Tue, Jul 20, 2010 at 7:52 AM, Daniel Caro wrote:
> Hi R us
On Tue, Jul 20, 2010 at 5:54 PM, Gavin Simpson wrote:
> On Tue, 2010-07-20 at 08:24 -0400, Graves, Gregory wrote:
> > If you submit these lines, you end up with variable "vare.dis". I want
> > to export vare.dis to csv. Stuck I am.
>
> Hi Yoda ;-)
>
>
I want THIS on fortune() !
ahhahah
so
Hi all,
Had struggled in getting "Strata" in randomForest to work on this.
Can I get randomForest for each of its TREE, to get ALL sample from some
strata to build tree, while leaving some strata TOTALLY untouched as oob?
e.g. in below, how I can tell RF to,
- for tree 1 in the forest, to use
Hi there.
I bet this question have been answered many times, but I cant find a good
solution for my problem.
I would like to put a axis break (on y axis) on that flowing plot (let's say
between 20 and 80 in y).
y = c(runif(10, 1, 10), 100);
x = y + runif(11, 10, 50);
plot(x,y)
Is there any so
Hi Daniel,
Try this:
for(i in 1:47) {
assign(x = paste("data", i, sep = ""),
value = read.csv(file.path("country", i, ".raw", fsep = ""), header = TRUE),
envir = .GlobalEnv)
}
See ?assign for documentation.
Cheers,
Josh
On Tue, Jul 20, 2010 at 4:52 AM, Daniel Caro wrote:
> Hi R users,
Dear All,
I have a raster map of the class 'SpatialPointsDataFrame' and coordinates
of the class 'SpatialPoints'. I would like to retrieve the values that are
contained in the raster map at the specific locations given by the
coordinates.
Can anyone help me out?
Kind regards,
Katrin Fleischer
_
Hi R-experts,
I have been wasted aroun 2 days to understand Holt-Winter method for double
exponential smoothing.But concept was not clear to me.Please suggest me how
to determeine values of alpha ,beta,gamma.It is bit urgent .please help me
in understanding holtwinter parameter determination .
I
Hi,
I am currently doing a project in which I wish to calculate the
calculate the theoretical price of options using the following models:
1. Constant Elasticity of Variance (CEV) model
2. Merton's jump diffusion model
3. Variance Gamma model
I am not sure as to how to implement this in R. I requ
Hi R users,
I am new in R. I would like to perform confirmatory factor analysis
for a data set of countries. My data are:
data <- read.csv("ses.raw", header = TRUE)
attach(data)
names(data)
[1] "idcntry" "momed" "daded" "dadocu" "momocu" "hompos" "finan"
The country id is "idcntry", my
Hello,
I need a possibility to print a function from R in Java with "plot ()".
I have taken rJava package and have built up a connection (with the JRI).
But if I call plot () in Java, a R_Graphics window (with R_Graphics:Device
2 (ACTIVE)) opens without contents. If I click this window, whole
Hi R users,
I am a newbie and therefore the naive question. Sorry but I was unable
to find an answer online. I would like to read 47 data sets
(country1.raw, country2.raw, ... country47.raw) and save into a matrix
each time (data1, data2, data47).
for (i in 1:47){
data(?) <- read.csv(file.pat
Hi,
I successfully created 3 screens with the following:
fig.mat<-c(0,.5,.5,.5,1,1,0,0,.5,1,.5,1)
fig.mat<-matrix(fig.mat,nrow=3)
fig.mat
split.screen(fig.mat)
I can plot three different plots on those 3 screens, but when I try the
following:
(Trying to create three graphs with a common x-axis
On Tue, 2010-07-20 at 08:24 -0400, Graves, Gregory wrote:
> If you submit these lines, you end up with variable "vare.dis". I want
> to export vare.dis to csv. Stuck I am.
Hi Yoda ;-)
> library(vegan,logical.return = TRUE) #return=true verifies package is
> available
>
> library(MASS,logical.
Thank you so much! And in package 'base' no less...exactly what I needed!
On Tue, Jul 20, 2010 at 8:55 AM, David Winsemius wrote:
>
> On Jul 20, 2010, at 9:44 AM, Patrick McKann wrote:
>
> Hello all,
>>
>> I am trying to write a program in R in which I call a function multiple
>> times within a
Dear R-experts:
I am using survreg() to estimate the parameters of a Weibull density having
right-censored observations. Some observations are weighted. To do that I
regress the weighed observations against a column of ones.
When I enter the data as 37 weighted observations, the parameter estim
This was just what I wanted, thanks!!
Am 20.07.2010 um 16:43 schrieb Duncan Murdoch:
> On 20/07/2010 10:09 AM, Mark Heckmann wrote:
>> will reformulate the question:
>>
>> I use strsplit() to split a string at the blanks. e.g.
>>
>> > strsplit("Split at blanks", " ")
>> [[1]]
>> [1] "Split" "a
On 20/07/2010 10:09 AM, Mark Heckmann wrote:
will reformulate the question:
I use strsplit() to split a string at the blanks. e.g.
> strsplit("Split at blanks", " ")
[[1]]
[1] "Split" "at" "blanks"
Now I would like to write something like a protected blank (like e.g.
in LaTex) into t
Hi,
I am new to clustering and was wondering why pvclust using "maximum"
as distance measure nearly always results in p-values above 95%.
I wrote an example programme which demonstrates this effect. I
uploaded a PDF showing the results
Here is the code which produces the PDF file:
---
Hi,
I'm using RGoogleDocs/RCurl to update a Google Spreadsheet. Everything
worked OK until this morning, when my ability to write into spreadsheet
cells went away. I get the following weird error:
Error in els[[type + 1]] : subscript out of bounds
Looking at the Google Docs API changelog, I see
Hi, you can define delimiters
strsplit("Split%at blanks", " |%")
-
A R learner.
--
View this message in context:
http://r.789695.n4.nabble.com/specify-blank-in-a-string-with-special-characters-tp2295453p2295639.html
Sent from the R help mailing list archive at Nabble.com.
Hi,
I am new to clustering and was wondering why pvclust using "maximum"
as distance measure nearly always results in p-values above 95%.
I wrote an example programme which demonstrates this effect. I
uploaded a PDF showing the results
Here is the code which produces the PDF file:
---
Mr. Feldman,
I would love nothing more than to reply to your wonderful email with just as
much sarcasm.
However, the fault lies with my question; I should have been more explicit.
It should have been phrased : Where can I find historical OVERNIGHT LIBOR
rates?
And surprisingly, we both use the
will reformulate the question:
I use strsplit() to split a string at the blanks. e.g.
> strsplit("Split at blanks", " ")
[[1]]
[1] "Split" "at" "blanks"
Now I would like to write something like a protected blank (like e.g.
in LaTex) into the string that does not get split
by strsplit(
For nls, the fixing (or masking) of parameters is not, to my knowledge,
possible.
This is something I've been trying to get in such routines for over 2
decades. Masks are
available, but not yet well documented, in Rcgmin and Rvmmin packages.
However, these use
an optim() style approach, which is q
On Jul 20, 2010, at 9:44 AM, Patrick McKann wrote:
Hello all,
I am trying to write a program in R in which I call a function
multiple
times within a loop. The problem is that sometimes the function
breaks down
while calling another function, and produces an error message that
breaks my
Hello all,
I am trying to write a program in R in which I call a function multiple
times within a loop. The problem is that sometimes the function breaks down
while calling another function, and produces an error message that breaks my
loop and the program stops. I would like to keep the loop ru
On Jul 20, 2010, at 9:26 AM, Jim Hargreaves wrote:
Dear List,
After much searching with no success, I would like to ask how I can
convert a unix/POSIX time (seconds since Jan 01, 1970) into a string
like "01/01/1970 00:00"
This is probably easily done with a system(date...) but it would
On Jul 20, 2010, at 9:25 AM, David Winsemius wrote:
On Jul 20, 2010, at 9:13 AM, Marcus Drescher wrote:
Hi all,
I have a dataframe with survey data. Now I want to calculate means
from several but not all columns (e.g. a1, a2, a3) and save them in
a new separate column (e.g. a).
Well t
Dear List,
After much searching with no success, I would like to ask how I can
convert a unix/POSIX time (seconds since Jan 01, 1970) into a string
like "01/01/1970 00:00"
This is probably easily done with a system(date...) but it would be
great if I could do it in R.
Kind Regards,
Jim Har
1 - 100 of 142 matches
Mail list logo