Is there any way to include comments in the html output of R2HTML? Or
is there any other function in any package that produces an html
output including comments, commands and output of the commands.
Vikas Rawal
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http
Le 17/07/10 08:23, noclue_ a écrit :
Currently, we have developed an R package for our company's internal use (at
least for now). I have successfully built the package and generated zip
file which can be easily installed. However, I am not sure how to generate
the big HELP file in PDF.
Right
Currently, we have developed an R package for our company's internal use (at
least for now). I have successfully built the package and generated zip
file which can be easily installed. However, I am not sure how to generate
the big HELP file in PDF.
Right now, I have about 30+ Rd files for t
I use XEmacs + ESS, and looking for ways to add text to a region of
code, I see it is quite easy
with C-x r t. Thanks for your great advice.
On Fri, Jul 16, 2010 at 7:32 PM, Erik Iverson wrote:
> On 07/16/2010 06:59 PM, Joshua Wiley wrote:
>>
>> Hello,
>>
>> Is there an way to easy comment of se
Dear List,
I used spec and envi for cca in ade4. (both are data.frame)
However, there is a message telling that
error in if (nf > rank) nf <- rank R
missing value in TRUE/FALSE
Please kindly help how to modify the code below.
Thank you.
Elaine
code
rm(list=ls())
spec <-read.csv("c:/migration
Dear List,
I tried to conduct cca using csv data but failed.
The message said that data.frame is required.
Please kindly share how to convert a csv-imported file to a data.frame.
Thank you.
Elaine
code
rm(list=ls())
spec <-read.csv("c:/migration/M_R_20100718_winterM_spec_vegan.csv",header=T,
r
As it says, (at least) one of your rows is all zeros. CCA cannot handle such
sites.
You might want to try something like this:
m.cca <-
cca(WinterM_ratio ~ topo_mean + coast + prec_max +
temp_min + evi_min, data = datam,
subset = rowSums(WinterM_ratio) > 0) ### Note.
(Note that you do n
Dear List,
I tried to do cca based on species data and environmental variables (formula
instead of community data).
However, there was an error saying row sums must be >0.
I searched the previous related messages but found few solutions.
Please kindly help and thank you in advance.
code
This is
On Thu, Jul 15, 2010 at 10:45 AM, jdellava wrote:
>
> Hi,
>
> I am trying to create a variable counting the number of individuals based on
> two variables. I am able to do it or one variable, but not two. In SAS I was
> able to sort by two variables and use a first. statement to create the
> count
On 07/16/2010 06:59 PM, Joshua Wiley wrote:
Hello,
Is there an way to easy comment of sections of code? I was thinking
something along the lines of
\dontrun{
codeline 1
codeline k
}
but that could be used in regular script files. When I am still
working on a script, I often want to bein
Dear list
I found package anacor very user-friendly but wanted to learn more after
reading the publication "a simple..." and its manual.
Please kindly help with the following questions and thanks in advance.
1. is it possible to implement lm formula in anacor?
2. is there manual to a
I think this is a question for R-devel so I'm
cross-posting there with apologies.
I've just acquired a Windows 7 64-bit box and
also will need RMySQL eventually.
Is there any information about issues involved
with compiling RMySQL for Windows 64-bit?
Steven McKinney
Statistician
Molecular Oncol
Hi, you can try plot3d
library(rgl)
plot3d(x=x[,2],y=x[,3],z=rowMeans(x[,2:4]))
-
A R learner.
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That's a great idea. Thanks!
On Fri, Jul 16, 2010 at 5:02 PM, RICHARD M. HEIBERGER wrote:
> if (FALSE) {
> codeline 1
>
> codeline k
> }
>
>
> On Fri, Jul 16, 2010 at 7:59 PM, Joshua Wiley
> wrote:
>>
>> Hello,
>>
>> Is there an way to easy comment of sections of code? I was thinking
>>
if (FALSE) {
codeline 1
codeline k
}
On Fri, Jul 16, 2010 at 7:59 PM, Joshua Wiley wrote:
> Hello,
>
> Is there an way to easy comment of sections of code? I was thinking
> something along the lines of
>
> \dontrun{
> codeline 1
>
> codeline k
> }
>
> but that could be used in regul
Hello,
Is there an way to easy comment of sections of code? I was thinking
something along the lines of
\dontrun{
codeline 1
codeline k
}
but that could be used in regular script files. When I am still
working on a script, I often want to being using what is done, but I
would like the par
Hello
I have a table of this kind:
functionx1 x2 x3
2.232 1 1 1.00
2.242 1 1 1.01
2.732 1 1 1.02
2.770 1 2 1.00
1.932 1 2 1.01
2.132 1 2 1.02
3.2
Yes, this is problem. Thanks for the suggestion. I had deleted the N/A
values later in the script but should have taken care of them in this first
step.
Thanks very much
Jared
On Fri, Jul 16, 2010 at 4:11 PM, Peter Ehlers wrote:
> On 2010-07-16 13:38, Jared Stabach wrote:
>
>> I've seen a f
On 2010-07-16 13:38, Jared Stabach wrote:
I've seen a few threads about this, but none that seem to answer my problem
I have a list of .txt files in a directory that I am reading into R and row
binding together. I am using the following code to do so:
# Directory where files are found
my.txt.f
You need to understand the difference between a variable and a value.
In your case that doesn't work, you are supplying a value, "trait.value".
but you have no file named "trait.value".
In the case that does work you are supplying a variable, trait.value, and
the value contained in that variable
Hi Karena,
On Fri, Jul 16, 2010 at 11:23 AM, karena wrote:
> So, as we all know, when using "read.csv", we need to use qutation mark out
> side the filename which we wanna read in. At first, for line 8, I wrote:
> read.csv("trait.file"), at last line, I wrote:
> funcname(folder/hyper.csv), but
Hi:
I'm guessing that your time variable is not defined with a class that
respects (time) ordering, so your first if statement is meaningless. In the
absence of further information, either create a meaningful time/date
variable or at the very least, an ordered factor.
Given what you've provided,
On Fri, Jul 16, 2010 at 2:46 PM, PeterTucker wrote:
>
> Hi - I am something of a newbie and am a little perplexed. When (trying to)
> modify a table I issue the following commands with subsequent errors
>
> sqldf("alter table Korea drop column code", dbname = "mydb")
> error in statement: near "d
Did you ever find a solution for this?
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Hello,
I'm trying to do some differential equation modeling in R using the
package 'deSolve.' Briefly, I'm trying to use the law of mass action
(the details of which aren't really important) to structure a vector
of rate equation which will be passed into an ODE function and solved
with associate
I am feeling rather dumb right now.
I created what I thought was a data.frame as follows:
aaa <- lapply(split(moreinfo,list(moreinfo$m_id),drop = TRUE), fun_m_id)
m_id_default_res <- do.call(rbind, aaa)
print("==")
m_id_default_res
print("==
Hello,
I am trying to find a direct way to write a nested if of sorts to find data
for a specific time range for a specific day (across a range of days) and
have exhausted my abilities with the manuals I have at hand. I have a good
deal of data of this approximate form:
day time price
1
Following is a function that I wrote (It is working well). It's a simple one,
nothing complicated. The only question that I have is a qutation mark issue,
I guess.
#
funcname <- function(trait.file){#line1
setwd('/root/sub
Hello Everyone,
Â
This is my first attempt to do something in R. As a precursor to a Willingness
to Pay analysis, I want to conduct a Mixed Conditional Logit analysis but am
unsure how to proceed because of some nesting within my data.
Â
Below is some data and code that illustrate what Iâm t
Hi - I am something of a newbie and am a little perplexed. When (trying to)
modify a table I issue the following commands with subsequent errors
sqldf("alter table Korea drop column code", dbname = "mydb")
error in statement: near "drop": syntax error
or
sqldf("alter table Korea rename column
Try this:
library(XML)
readHTMLTable("http://extranet.pheur.org/4DLink1/4DCGI/Web_View/mono/198";,
which = 5)
On Fri, Jul 16, 2010 at 4:08 PM, Bart Joosen wrote:
>
> Marsh,
>
> you are absolutely right, I forget the link to the db.
> Actually its a webpage for each monograph number:
>
> http://
Hello Joshua and Wu,
Thank you for your excellent solutions.
Joshua
- Original Message -
From: "Joshua Wiley"
To: "Shuhua Zhan"
Cc: r-help@r-project.org
Sent: Friday, July 16, 2010 12:39:22 PM GMT -05:00 US/Canada Eastern
Subject: Re: [R] how to skip a specific value when using apply() f
On Fri, Jul 16, 2010 at 1:59 PM, Davis, Brian wrote:
> I have a text processing problem I'm hoping someone can help me solve. This
> issue it this.
>
> I have a character string in which I need to delete a variable number of
> characters from the string. The string itself contains the number
On Mon, Jul 12, 2010 at 8:16 AM, Jun Shen wrote:
> Dear Deepayan,
>
> Thank you for taking the time to look into this issue.
>
> I have a data object called "Data", please find it at the end of the
> message. Then I can run the code below separately in the console.
[...]
> ##
Dear David,
> I managed to install Sage on Windows (via a Linux VM), but I cannot find any
> documentation on how to use R from Sage. Maybe I
> should use the web interface of Sage to avoid having to install R on the VM.
In the Sage command line, you can type
sage: r?
to get some very basic in
Hi Jared:
Is it possible you're using read.table with variable names in line 1 but not
using header = TRUE as an argument?
HTH,
Dennis
On Fri, Jul 16, 2010 at 12:41 PM, Erik Iverson wrote:
>
>
>
>
>> I think I have identified the problem such that when I identify the
>> structure of some of t
Dear R-list members,
I´m using the package "survey" and I need to find a function for
multinomial logistic regression in a complex design. The functions that
I see are only for dicotomic and ordinal variables.
Thank you!
Rosario Austral
De: "r-help-requ...@r-
I think I have identified the problem such that when I identify the
structure of some of the files that I am reading in, columns are labeled as
"Factors". In other files, the same columns are labeled as numeric
values. Is there a way to assign the data structure to these columns in the
dataf
I've seen a few threads about this, but none that seem to answer my problem
I have a list of .txt files in a directory that I am reading into R and row
binding together. I am using the following code to do so:
# Directory where files are found
my.txt.file.directory <- "C:/Jared/Data/Kenya/Wildeb
On Wed, Jul 14, 2010 at 10:12 AM, Neil123 wrote:
>
> Hi,
>
> I have the following dataset and I would like to create a dotplot with
> confidence limits:
>
> CAT1 CAT2 MEAN Lower
> Upper
> 1 1 1 0.619
Hi,
On Fri, Jul 16, 2010 at 5:18 PM, CC wrote:
> I am sure this is a very basic question:
>
> I have 600,000 categorical variables in a data.frame - each of which is
> classified as "0", "1", or "2"
>
> What I would like to do is collapse "1" and "2" and leave "0" by itself,
> such that after re-c
I would have thought this to be relatively elementary, but I can't find it
mentioned in any of my stats texts.
Please consider the following:
library(fitdistrplus)
fp = fitdist(y,"exp");
rate = fp$estimate;
sd = fp$sd
fOneWeek = exp(-rate*7); #fraction that happens within a week - y is
m
Hi:
See ? levels. Here's a toy example:
> x <- factor(sample(0:2, 10, replace = TRUE))
> x
[1] 1 2 1 0 2 2 2 2 2 1
Levels: 0 1 2
> levels(x) <- c(0, 1, 1)# Change level 2 to 1
> x
[1] 1 1 1 0 1 1 1 1 1 1
Levels: 0 1
HTH,
Dennis
On Fri, Jul 16, 2010 at 10:18 AM, CC wrote:
> I am sure t
Marsh,
you are absolutely right, I forget the link to the db.
Actually its a webpage for each monograph number:
http://extranet.pheur.org/4DLink1/4DCGI/Web_View/mono/198
http://extranet.pheur.org/4DLink1/4DCGI/Web_View/mono/731
...
As I have a list with the numbers of interest (l<- c(198, 731,
Your code between calls to sink() does not generate any output. Hence,
nothing will be diverted to the file. To illustrate this point,
consider
for(i in 1:10) i
This produces no output. However,
for(i in 1:10) print(i)
produces output as expected.
-Matt
On Fri, 2010-07-16 at 13:34 -0400, Ad
Hi Davis,
Please try ??regex
gsub("(\\-|\\+)([0-9]+)(\\w*)(\\w)", replacement="\\4", x)
-
A R learner.
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Sent from the R help mailing list archive at
Hi:
Here's a simple example (divide through by 10 for your case):
x <- 1:10
y <- rnorm(10, x, s = 0.3)
clr <- ifelse(x <= 5, 'red', 'blue')
plot(x, y, col = clr)
HTH,
Dennis
On Fri, Jul 16, 2010 at 6:08 AM, azam jaafari wrote:
> Hi
>
> I want to draw a plot from observed and predicted data an
Hi:
Hadley's solution is certainly preferred here due to its relative
simplicity. I just wanted to correct an error from my earlier post.
On Thu, Jul 15, 2010 at 2:08 PM, Dennis Murphy wrote:
> Hi:
>
> I sincerely hope there's an easier way, but one method to get this is as
> follows,
> with d
I have a text processing problem I'm hoping someone can help me solve. This
issue it this.
I have a character string in which I need to delete a variable number of
characters from the string. The string itself contains the number of
characters to be deleted. The number of characters to be d
Hi Albyn,
Thank you very much for the suggestion.
I managed to install Sage on Windows (via a Linux VM), but I cannot find
any documentation on how to use R from Sage. Maybe I should use the web
interface of Sage to avoid having to install R on the VM.
Best regards,
David
On 10-07-14 10:2
Do you want to replace specific values of a data set?
df <- sample(c(0,1,2),600,replace=T)
table(df)
df[df==2]<-1
table(df)
-
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Sent from t
Sorry about that. Still new to this... The code below should be
reproducible.All R2 should just be 1, and I should write 1 to
R2outputKKNN.txt 10 timesnothing is happening. Appreciate the efforts
to help!
for (i in 1:10)
{
adata = 1:5
bdata = 6:10
lm <- lm(adata
This is not reproducible, and does not look minimal. You'll get better
answers, and probably solve many issues on your own, if you construct
small examples that illustrate the same problem you're having with your
real data.
Addi Wei wrote:
iterations <- 100
nvars <- 4
combined <- rbind(scale
iterations <- 100
nvars <- 4
combined <- rbind(scaleMiceTrain, scaleMiceTest)
reducedSample <- combined
reducedSample <- subset(reducedSample, select = -pID50)
reducedSample <- subset(reducedSample, select = -id)
for (i in 1:iterations)
{
miceSample <- sample(combined[,-c(1,2)],nvars, repl
I am sure this is a very basic question:
I have 600,000 categorical variables in a data.frame - each of which is
classified as "0", "1", or "2"
What I would like to do is collapse "1" and "2" and leave "0" by itself,
such that after re-categorizing "0" = "0"; "1" = "1" and "2" = "1" --- in
the en
On 7/16/2010 6:00 AM, r-help-requ...@r-project.org wrote:
Message: 5
Date: Thu, 15 Jul 2010 03:36:21 -0700 (PDT)
From: Bart Joosen
To:r-help@r-project.org
Subject: [R] Access web content from within R
Message-ID:<1279190181074-2289953.p...@n4.nabble.com>
Content-Type: text/plain; charset=us-ascii
On Fri, Jul 16, 2010 at 12:38 PM, Erin Hodgess wrote:
> I have several data sets, which begin early in 2002 and run until
> yesterday. They do not have observations every day. For example:
>> xd1[1:10]
> 2002-02-25 2002-02-26 2002-02-28 2002-03-01 2002-03-04 2002-03-05 2002-03-07
> 7
Hi szhan,
I think Joshua gives all you wants -- scale is a really good function.
You can also make your own function work by setting an argument na.rm.
tmp1[tmp1==0]<-NA
student<- function(x){
x<-(x-mean(x,na.rm=T))/sd(x,na.rm=T)
return (x)
}
tmp4<-apply(tmp1, 2, student)
-
My understanding is that polr will do ordered logit but I am not sure if it
is also suited for rank ordered logit (or is there no such distinction)
I am thinking of following two situations
1. there is an ordered response (say small,medium,large coffee) and each
individual selects one of these op
Hello,
This does what you want. The simple solution is shorter but requires
that there is only one value you wish to exclude (e.g., 0). The
second works for any number of values you wish to exclude, but is
subsequently longer. Also there is no need to create your own
function to 'studentize', ?
Hello,
I am a new R user having transitioned over from S-plus recently. I have a
question that is probably very trivial but I am having trouble finding a
solution. In S-plus, graphic pages are created as tabs when multi-page
figures are created. I have shown the R code for xpose.VPC (a function
wi
I have several data sets, which begin early in 2002 and run until
yesterday. They do not have observations every day. For example:
> xd1[1:10]
2002-02-25 2002-02-26 2002-02-28 2002-03-01 2002-03-04 2002-03-05 2002-03-07
7 8 1 9 12 3 5
Hi Steve,
Thanks
Here is a tiny subset of the data:
> dput(head(moreinfo, 40))
structure(list(m_id = c(171, 206, 206, 206, 206, 206, 206, 218,
224, 224, 227, 229, 229, 229, 229, 229, 229, 229, 229, 233, 233,
238, 238, 251, 251, 251, 251, 251, 251, 251, 251, 251, 251, 251,
251, 251, 251, 251, 251,
subset(miceTrainSample, select = -plD50)
On Fri, Jul 16, 2010 at 11:22 AM, Addi Wei wrote:
>
> names(miceTrainSample)
> [1] "b_double" "KierA2" "KierFlex" "Q_VSA_POS" "pID50"
>
> In the above code, how do I delete "pID50" column to store the resulting
> object without indicating column "5".
Here is a way of creating a separate list of variable length vectors
that you can use in your processing:
> # read into a dataframe
> x <- read.table(textConnection("ABCTLengths
+ 14.00.001525878918c(1,2,3)
+ 14.00.001525878918c(1,2,6,7,8,3)
+ 14
Hello Nikhil and Wu,
Thank you very much for your reply!
What I want is to calculate the student's score column-wise by ignoring the
specific values such as zeros for example only using c(2,1) in column 8 in the
tmp1 and generate tmp2. I changed the zeros to NAs and modified my stud fun to
stude
Anyway, I have often wished that something like
new.mt.sample <- miceTrainSample[, -"pID50"]
would return miceTrainSample without the pID50 column. Here are three
alternative ways to do it.
# Method 1: Assign NULL to the column
new.mt.sample <- miceTrainsSample
new.mt.sample$pID50 <- NULL
# Me
Hi,
First: it's kind of hard to play along w/o some reproducible data. To
that end, you can paste into an email the output of:
dput(moreinfo)
If there are lots of rows in `moreinfo`, just give us the first ~10-20
dput(head(moreinfo, 20))
Anyway:
> At this point, each row in m_id_default_res
I guess your data frame is a little different from the reference, so your
as.logical doesn't work.
attach(Q)
FUN <- function(X, Y) {abs(X - Y)}
round(outer(rank(date)[colour=="b"],rank(date)[colour=="g"],FUN) +
outer(rank(number)[colour=="b"],rank(number)[colour=="g"],FUN))
detach(Q)
-
A
I must have missed something simple, but still, i don't know what.
I obtained my basic data as follows:
x <- sprintf("SELECT m_id,sale_date,YEAR(sale_date) AS
sale_year,WEEK(sale_date) AS sale_week,return_type,0.0001 +
DATEDIFF(return_date,sale_date) AS elapsed_time FROM
`merchants2`.`risk_input`
On Fri, Jul 16, 2010 at 11:26 AM, Erin Hodgess wrote:
> Dear R People:
>
> What is the best way to change a named numeric (in which the names are
> dates) to a time series, please?
>
>> str(y1)
> Named int [1:730] 102 145 147 120 132 125 137 103 128 130 ...
> - attr(*, "names")= chr [1:730] "200
Hi Addi,
On Fri, Jul 16, 2010 at 3:22 PM, Addi Wei wrote:
>
> names(miceTrainSample)
> [1] "b_double" "KierA2" "KierFlex" "Q_VSA_POS" "pID50"
>
> In the above code, how do I delete "pID50" column to store the resulting
> object without indicating column "5". The code below does the trick, b
Did you try:
library(MASS)
?polr
?
Contact
Details:---
Contact me: tal.gal...@gmail.com | 972-52-7275845
Read me: www.talgalili.com (Hebrew) | www.biostatistics.co.il (Hebrew) |
www.r-statistics.com (English)
-
Here is the original question:
What is the best way to change a named numeric to a time series
> str(y1)
Named int [1:730] 102 145 147 120 132 125 137 103 128 130 ...
- attr(*, "names")= chr [1:730] "2006-01-01" "2006-01-02"
"2006-01-03" "2006-01-04" ...
>
y2 <- zoo(y1,order=names(y1))
Perfec
Dear R People:
What is the best way to change a named numeric (in which the names are
dates) to a time series, please?
> str(y1)
Named int [1:730] 102 145 147 120 132 125 137 103 128 130 ...
- attr(*, "names")= chr [1:730] "2006-01-01" "2006-01-02"
"2006-01-03" "2006-01-04" ...
>
Thanks in adv
names(miceTrainSample)
[1] "b_double" "KierA2""KierFlex" "Q_VSA_POS" "pID50"
In the above code, how do I delete "pID50" column to store the resulting
object without indicating column "5". The code below does the trick, but I
wish to delete the column by specifying "-pID50" instead of "5".
We need to know how you're doing this, with a minimal example that we
can run. Most graphics devices accept a file or filename argument, so
that's one way. If you're using the pdf device, multiple plots will
create multiple pages in the final output..
linda.s wrote:
I made a plot, but after
I made a plot, but after I made a second plot, the previous plot was
gone. How can I save all the plots in a file (I do not manually copy
and paste them one by one)?
Thanks.
Linda
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Is there a package in R that can run rank-ordered logit?
Thanks,
Suresh
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PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented,
hey, guys, all these methods work perfectly. thank you!!
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Hi Duncan,
That fixed it. Many thanks indeed, I now know what to do if it happens
again,
Philip
-Original Message-
From: Duncan Murdoch [mailto:murdoch.dun...@gmail.com]
Sent: 16 July 2010 16:00
To: Philip Whittall
Cc: r-help@r-project.org
Subject: Re: [R] Packages built before R 2.10
On 16/07/2010 10:57 AM, linda.s wrote:
Hi.
I am a beginner. What is the difference between:
x<-2
and
x=2
It depends on the context. "x <- 2" always assigns the value 2 to the
variable named x. Typed as an isolated command, that's what "x = 2"
does too. However, when used as an argument
On 16/07/2010 10:51 AM, Philip Whittall wrote:
I should have added that this problem is not serious under 2.10 as you
only get a Warning and everything works
> require(candisc)
Loading required package: candisc
Loading required package: car
Loading required package: heplots
Warning message:
pa
Hi.
I am a beginner. What is the difference between:
x<-2
and
x=2
Thanks.
Linda
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Hello to all!
I am new with R and I need your help.
I'm trying to read a file which contests are similar to this:
ABCTLengths
14.00.001525878918c(1,2,3)
11.00.001716613824c(1,1,4)
So all the columns are numeric values, except Lengths, which is supp
I should have added that this problem is not serious under 2.10 as you
only get a Warning and everything works
> require(candisc)
Loading required package: candisc
Loading required package: car
Loading required package: heplots
Warning message:
package 'car' was built under R version 2.9.2 and
On 16/07/2010 10:41 AM, Philip Whittall wrote:
Hi Duncan,
Many thanks for the response. I did indeed re-install car and this is
what occurred ...
> utils:::menuInstallLocal()
package 'car' successfully unpacked and MD5 sums checked
> require(candisc)
Loading required package: candisc
Loading re
On 2010-07-16 7:56, Ralf B wrote:
Hi all,
when running KL on a small data set, everything is fine:
require("flexmix")
n<- 20
a<- rnorm(n)
b<- rnorm(n)
mydata<- cbind(a,b)
KLdiv(mydata)
however, when this dataset increases
require("flexmix")
n<- 1000
a<- rnorm(n)
b<- rnorm(n)
mydata<- cbin
Hi Duncan,
Many thanks for the response. I did indeed re-install car and this is
what occurred ...
> utils:::menuInstallLocal()
package 'car' successfully unpacked and MD5 sums checked
> require(candisc)
Loading required package: candisc
Loading required package: car
Error: package 'car' was buil
On 16/07/2010 9:50 AM, Philip Whittall wrote:
Dear list,
I am running R2.11.1 on 32 bit windows. I am receiving messages as
follows ...
> require(car)
Loading required package: car
Error: package 'car' was built before R 2.10.0: please re-install it
The package kohonen was another example.
Thi
Hi List,
Does R have a package that will do filtered back-projection? I'm a medical
physicist trying to produce an image of a dose cloud within a phantom using
software other than Matlab and wondered if R has this capability. I looked
through the imaging pages on the project site but didn't see
Hi all,
when running KL on a small data set, everything is fine:
require("flexmix")
n <- 20
a <- rnorm(n)
b <- rnorm(n)
mydata <- cbind(a,b)
KLdiv(mydata)
however, when this dataset increases
require("flexmix")
n <- 1000
a <- rnorm(n)
b <- rnorm(n)
mydata <- cbind(a,b)
KLdiv(mydata)
KL se
Dear list,
I am running R2.11.1 on 32 bit windows. I am receiving messages as
follows ...
> require(car)
Loading required package: car
Error: package 'car' was built before R 2.10.0: please re-install it
The package kohonen was another example.
This failure appears to be fatal and not only affec
> Can anyone tell me what is the difference between these two standard
> errors and how should I interpret the confidence intervals and std.err
> given these differences?
help(survfit.object) will give you the answer. The std in the object is
for the cumulative hazard, the printout uses a Taylor
Hi
I want to draw a plot from observed and predicted data and also shows threshold
and data before threshold are identified with different color from data after
threshold.
Suppose:
abserved data are 0 or 1
predicted data= 0 to 1
threshold=0.5
Thanks alot
[[alternative
> Could anyone advise me how can I implement classification and
> regression tree analyses for a circular response (angles)?
Rpart allows for user-defined splitting rules. You need to define a
function which is given y and an ordered x, and returns the 'goodness of
split' for each split point. Y
On Thu, Jul 15, 2010 at 11:08 PM, Dennis Murphy wrote:
> Hi:
>
> I sincerely hope there's an easier way, but one method to get this is as
> follows,
> with d as the data frame name of your test data:
>
> d <- d[order(with(d, Age, School, rev(Grade))), ]
> d$Count <- do.call(c, mapply(seq, 1, as.ve
On Thu, Jul 15, 2010 at 6:38 PM, chakri_amateur wrote:
[...]
> I want to extract the largest connected component (alias sub-graph) of the
> network. My input network is a large network of >1000 vertices and >15000
> arcs. From this, I want to take out only the largest cluster.
>
>> If you decompos
I think this is simpler but still not all that clean.
===
xx <- structure(list(ID = 1:9, Age = c(10L, 10L, 10L, 11L, 11L, 11L,
10L, 10L, 11L), School = c(1L, 2L, 1L, 1L, 1L, 2L, 1L, 1L, 2L
), Grade = c(98L, 97L, 92L, 90L, 80L, 70L, 80L, 7
its maybe not as simple as Teds solution but points to a more general
approach
reshape(mydata,direction="long",varying=names(mydata),v.names=c("id","x","y"))
Am 16.07.2010 13:27, schrieb Ralf B:
> I have the following data structure:
>
> n=5
> mydata <- data.frame(id=1:n, x=rnorm(n), y=rnorm(n),
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