On 13/07/10 19:16, Erik Iverson wrote:
Raubertas, Richard wrote:
I agree that 'list' is a terrible package name, but only secondarily
because it is a data type. The primary problem is that it is so generic
as to be almost totally uninformative about what the package does.
For some reason pack
On Thu, Jul 15, 2010 at 7:24 AM, chakri_amateur wrote:
[...]
> wri write.graph ("F://new", "pajek") <- decompose.graph(g, mode="weak",
> max.comps=NA,
> min.vertices= 20)
>
>
> But even that doesn't work
No wonder, writing computer programs is not just typing in random
words and let the co
Try this:
a <- data.frame(timestamp=c(3,5,8), mylabel=c("abc","def","ghi"))
b <- data.frame(timestamp=c(1:10))
txt <- as.character(a$mylabel)
nrepeat <- diff(c(a$timestamp,nrow(b)))
b$mylabel <- c( rep(NA, a$timestamp[1]), rep(txt,
diff(c(a$timestamp,nrow(b )
greetings,
Remko
--
Dear R users,
I am using plm packege in R to build my model, but from the result I can't
quite figure out what it is... Can anyone tell me why? Am I missing
something?
R Results:
*> ar1<-plm(formula=ADOP~lag(ADOP,1)+PE+WOR,
+ data=well, effect="time",model="within")
> summary(ar1)*
Oneway (time
Dear Peter Ehlers,
Thanks.
In decompose help page of 'R' It's clearly mentioned that the output of
decompose command is a separate graph for each component .
It is true that, Variable in which I stored my output is not a graph object.
I tried the following command also - To directly save
I have been trying to produce a histogram that has two groups (male and female
snakes) on the same graph (either superimposed or each frequency bar appears
side by side). I found a couple of functions for superimposed histogram written
by other people.
The below is the codes I used for my data c
Hi,
I am brand new to the world of R, so please bare with me while I goof my way
through a question.
I am attempting to trial using R with MySQL.
The MySQL server is on a Linux box and I am using the Windows (32bit XP)
version of R.
I have installed RMySQL successfully, however when I load it
Ok that was quick, I found the problem. I put a bin folder in and copied the
dll from above that folder and put it in.
HOWEVER:
Now I get this error:
Error : .onLoad failed in loadNamespace() for 'RMySQL', details:
call: inDL(x, as.logical(local), as.logical(now), ...)
error: unable to load
Hi R,
Just like a Poisson regression model, is there a package in R to do
Extreme Value Regression model? Thanks.
Thanks and Regards,
Shubha Karanth
This e-mail may contain confidential and/or privileged i...{{dropped:13}}
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Thanks Alan and Gabor. Alanâs code appears to be the simplest to run and
Gabor provided some further insight.
TschüÃ
Tony Meissner
Principal Scientist (Monitoring)
Resources Monitoring Group
Science, Monitoring and Information Division
Department for Water
"Imagine" ©
â¢(ph) (08) 8595 220
This is one way:
df<- data.frame(Time=as.POSIXct("2009-01-01", format="%Y-%m-%d") + seq(0,
60*60*24*365-1, 60*60),
lev.morgan=3+runif(24*365),
lev.lock2=3+runif(24*365),
flow=1000+rnorm(24*365, 200),
direction=runif(24*365, 0
On Thu, Jul 15, 2010 at 12:52 AM, Meissner, Tony (DFW)
wrote:
> I have a data frame (morgan) of hourly river flow, river levels and wind
> direction and speed thus:
> Time hour lev.morgan lev.lock2 lev.lock1 flow direction
> velocity
> 1 2009-07-06 15:00:00 15 3.266
Hi All,
I have a dataset, longitudinal in nature, each row is a 'visit' to a clinic,
which has numerous data fields and a count variable for the number of
'events' that occurred since the previous visit.
~50k rows, ~2k unique subjects so ~25 rows/visits per subject, some have 50
some have 3 or 4
I have a data frame (morgan) of hourly river flow, river levels and wind
direction and speed thus:
Time hour lev.morgan lev.lock2 lev.lock1 flow direction
velocity
1 2009-07-06 15:00:00 15 3.266 3.274 3.240 1710.6 180.282
4.352
2 2009-07-06 16:00:00
Dear useRs,
How to save the correlations corresponding to the
significance levels from ACF function
Thanks
nuncio
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Research Scientist
National Center for Antarctic and Ocean research
Head land Sada
Vasco da Gamma
Goa-403804
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I'm using R2wd and ESS. ESS-mode doesn't let one fill wdBody() calls,
and printing out of Emacs (M-x print-buffer or M-x print-region) doesn't
wrap, so I miss most of the text on printed listings. What do others
do to address that?
Thanks,
Bill
- -
Hi All,
I have a dataset, longitudinal in nature, each row is a 'visit' to a clinic,
which has numerous data fields and a count variable for the number of
'events' that occurred since the previous visit.
~50k rows, ~2k unique subjects so ~25 rows/visits per subject, some have 50
some have 3 or
Thanks for the help. That sorted it out straight away.
Duncan Murdoch wrote:
On 14/07/2010 12:01 PM, Steve Pederson wrote:
Hi,
I can't seem to install R from source. I've downloaded the latest
Rtools211.exe from http://www.murdoch-sutherland.com/Rtools/ & done a
full installation of that and
Dear Sarah,
[snip...]
"I know that samples within each facility cannot be treated as independent,
so I need an approach that accounts for (1) clustering within facilities
and"
You could just use lm() & some planning. The data from within a specific
facility can be fit with a model to generate par
emorway engr.colostate.edu> writes:
>
>
> Forum,
>
> I'm a grad student in Civil Eng, took some Stats classes that required
> students learn R, and I have since taken to R and use it for as much as I
> can. Back in my lab/office, many of my fellow grad students still use
> proprietary softwa
On 07/14/2010 06:22 PM, emorway wrote:
Forum,
I'm a grad student in Civil Eng, took some Stats classes that required
students learn R, and I have since taken to R and use it for as much as I
can. Back in my lab/office, many of my fellow grad students still use
proprietary software at the behes
If the system is sparse and you have a really large cluster to play
with, then maybe (emphasis) PETSc/TAO is the right combination of tools
for your problem.
http://www.mcs.anl.gov/petsc/petsc-as/
Christos
It isn't beautiful, but I use this package to write excel files from linux.
http://github.com/armstrtw/Rexcelpoi
the basic idea is that each element of a list is written as a separate
sheet, but if a list element is itself a list, then all the elements
of that list are written to the same sheet (
On 07/14/2010 07:07 PM, Duncan Murdoch wrote:
It is capable of handling large data, but not that large in a single
matrix. The limit on the number of entries in any vector (and matrices
are stored as vectors) is about 2^31 ~ 2 billion. Your matrix needs
about 340 billion entries, so it's too big.
On 07/14/2010 06:10 PM, Douglas Bates wrote:
R stores matrices and other data objects in memory. A matrix of that
size would require
2e+06*17*8/2^30
[1] 2533.197
great, that is my understanding as well..
probably easier, rethink your problem.
yes. i am starting to do that now as i ha
On 07/14/2010 06:15 PM, Peter Dalgaard wrote:
A quick calculation reveals that a matrix of that size requires about
2.7 TERAbytes of storage, so I'm a bit confused as to how you might
expect to fit it into 16GB of RAM...
However, even with terabytes of memory, you would be running into the
(cu
Forum,
I'm a grad student in Civil Eng, took some Stats classes that required
students learn R, and I have since taken to R and use it for as much as I
can. Back in my lab/office, many of my fellow grad students still use
proprietary software at the behest of advisers who are familiar with the
On 14/07/2010 5:23 PM, paul s wrote:
hi -
i just started using R as i am trying to figure out how perform a linear
regression on a huge matrix.
i am sure this topic has passed through the email list before but could
not find anything in the archives.
i have a matrix that is 2,000,000 x 170
You also could use RExcel and write some VBA macros doing this task for you.
You can essentially have the rcom R-centric solution or the
VBA-centric RExcel solution.
On Jul 14, 2010, at 12:19 AM, Marc Schwartz wrote:
> If I am correctly understanding what Eugen is trying to do, WriteXLS() won't
paul s wrote:
> hi -
>
> i just started using R as i am trying to figure out how perform a linear
> regression on a huge matrix.
>
> i am sure this topic has passed through the email list before but could
> not find anything in the archives.
>
> i have a matrix that is 2,000,000 x 170,000 the
On Wed, Jul 14, 2010 at 4:23 PM, paul s wrote:
> hi -
> i just started using R as i am trying to figure out how perform a linear
> regression on a huge matrix.
> i am sure this topic has passed through the email list before but could not
> find anything in the archives.
> i have a matrix that i
Wu Gong wrote:
> I have the same question about how to see the process behind a function. If I
> type sample in R, it really tells nothing about how R selects from a data
> set and creates samples.
>
> Thank in advance for any help.
>
> -
> A R learner.
Uwe Ligges. R Help Desk: Accessing th
I have the same question about how to see the process behind a function. If I
type sample in R, it really tells nothing about how R selects from a data
set and creates samples.
Thank in advance for any help.
-
A R learner.
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Correction:
b$label <- cut(b$timestamp, breaks=bks, labels=lbs, include.lowest = T,
right=F)
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hi -
i just started using R as i am trying to figure out how perform a linear
regression on a huge matrix.
i am sure this topic has passed through the email list before but could
not find anything in the archives.
i have a matrix that is 2,000,000 x 170,000 the values right now are
arbitra
I know this is a double post, but the subject line was really
misleading. Sorry again.
This is the first time that I have tried to update packages with a
tinkered around with .Rprofile. I start R with R --vanilla and it
does not load my .Rprofile, but when I issue the command
update.packages() R
Marc Schwartz wrote:
> You need to understand the difference between how a value is stored
> in an R object with full floating point precision versus how a value
> in R is displayed (printed) in the console with a print "method".
>
> In this case, wilcox.test() returns an object of class 'htest' (
If you don't mind avoiding a loop, here's one way to
solve your problem:
myDF =
data.frame(id=c(100,101),d1=c(.3,.3),d2=c(.4,.4),d3=c(-.2,.5),d4=c(-.3,.6),d5=c(.5,-.2),d6=c(.6,-.4),d7=c(-.9,-.5),d8=c(-.8,-.6))
doit =
function(x)c(x[1],sum_positive=sum(x[-1][x[-1]>0]),sum_negative=sum(x[-1][x[-
I take this case as cut a data set by breaks and assign each segment a label
name.
a <- data.frame(timestamp=c(3,5,8), mylabel=c("abc","def","ghi"))
b <- data.frame(timestamp=c(1:10))
bks <- c(a$timestamp,max(b$timestamp))
lbs <- a$mylabel
b$label <- cut(b$timestamp, breaks=bks, labels=lbs, inclu
Bogaso Christofer wrote:
Hi, there is a function Skewness() under fBasics package. If I type
"skewness", I get followings:
Case matters in R, so please be precise.
skewness
function (x, ...)
{
UseMethod("skewness")
}
Would be great if someone tell me how to see the co
This is the first time that I have tried to update packages with a
tinkered around with .Rprofile. I start R with R --vanilla and it
does not load my .Rprofile, but when I issue the command
update.packages() R downloads the packages as expected, but then seems
to load .Rprofile before compiling th
I have the following datasets:
id d1 d2 d3 d4 d5 d6 d7 d8
1 100 0.3 0.4 -0.2 -0.3 0.5 0.6 -0.9 -0.8
2 101 0.3 0.4 0.5 0.6 -0.2 -0.4 -0.5 -0.6
what I am trying to accomplish:
loop through the rows && do the following:
if the values from the columns of the current row >0
Hi, there is a function Skewness() under fBasics package. If I type
"skewness", I get followings:
> skewness
function (x, ...)
{
UseMethod("skewness")
}
Would be great if someone tell me how to see the codes of this function.
2ndly suppose I create following function:
fn1
On 2010-07-13 12:11, Robert Peter wrote:
Hello!
I am trying to scale the outliers in a boxplot. I am passing "pars =
list(boxwex=0.1, staplewex=0.1, outwex=0.1)" to the boxplot command. The
boxes are scaled correctly, but the circles (outliers) are not scaled at
all, and thus pretty big compared
On Jul 14, 2010, at 3:19 PM, Michael Haenlein wrote:
> Dear all,
>
> I have a txt file of the following format that describes the relationships
> between a network of a certain number of nodes.
>
> {4, 2, 3}
> {3, 4, 1}
> {4, 2, 1}
> {2, 1, 3}
> {2, 3}
> {}
> {2, 5, 1}
> {3, 5, 4}
> {3, 4}
> {2,
On 14/07/2010 4:19 PM, Michael Haenlein wrote:
Dear all,
I have a txt file of the following format that describes the relationships
between a network of a certain number of nodes.
{4, 2, 3}
{3, 4, 1}
{4, 2, 1}
{2, 1, 3}
{2, 3}
{}
{2, 5, 1}
{3, 5, 4}
{3, 4}
{2, 5, 3}
For example the first line
Another option could be:
df$var3 <- gsub(".*\\((.*)\\).*", "\\1", df$var2)
On Wed, Jul 14, 2010 at 3:21 PM, karena wrote:
>
> Hi,
>
> I have a data.frame as following:
> var1 var2
> 1 ab_c_(ok)
> 2 okf789(db)_c
> 3 jojfiod(90).gt
> 4 "ij"_(78)__op
Dear all,
I have a txt file of the following format that describes the relationships
between a network of a certain number of nodes.
{4, 2, 3}
{3, 4, 1}
{4, 2, 1}
{2, 1, 3}
{2, 3}
{}
{2, 5, 1}
{3, 5, 4}
{3, 4}
{2, 5, 3}
For example the first line {4, 2, 3} implies that there is a connection
betw
Try this:
text <- 'var1 var2
1 ab_c_(ok)
2 okf789(db)_c
3 jojfiod(90).gt
4 "ij"_(78)__op
5 (iojfodjfo)_ab'
df <- read.table(textConnection(text), head=T, sep=" ",quote="")
df$var3 <- gsub("(.*\\()(.*)(\\).*)","\\2",df$var2)
-
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On Wed, Jul 14, 2010 at 2:21 PM, karena wrote:
>
> Hi,
>
> I have a data.frame as following:
> var1 var2
> 1 ab_c_(ok)
> 2 okf789(db)_c
> 3 jojfiod(90).gt
> 4 "ij"_(78)__op
> 5 (iojfodjfo)_ab
>
> what I want is to create a new variable call
Hi,
I have a data.frame as following:
var1 var2
1 ab_c_(ok)
2 okf789(db)_c
3 jojfiod(90).gt
4 "ij"_(78)__op
5 (iojfodjfo)_ab
what I want is to create a new variable called "var3". the value of var3 is
the content in the Parentheses. so v
On Jul 14, 2010, at 2:16 PM, darckeen wrote:
>
> I was hoping that there might be some way to attach significance code like
> the ones from summary.lm to a dataframe. Anyone know how to do something
> like that. Here is the function i'd like to add that functionality to:
>
>
> add1.coef <- fu
hello everybody,
I would like to fit a model to a times series (testing set) for out of
sample predictions using garchFit(). I would like to keep the coefficients
of ARMA/GARCH model fixed (as found by fitting the model to my training
set). The arima fitting function has such an option for that
On 07/13/2010 07:46 PM, Raubertas, Richard wrote:
I agree that 'list' is a terrible package name, but only secondarily
because it is a data type. The primary problem is that it is so generic
as to be almost totally uninformative about what the package does.
For some reason package writers seem
On Wednesday 14 July 2010 09:06:01 pm Addi Wei wrote:
> I combined 2 data frames together using rbind... How do I unbind the data
> at a specific row to create 2 separate data frames?
>
if you have a column with an identifier: try split()
Example:
split(iris, iris$Species)
--
Friedri
Thanks a lot Matt,
Just if someone like to see how I called a C function from R with files as
argumets.
For simplicity, this example is copying the content of input file into
output file
-
My main program is :
source("parse.R")
parseGBest('gbest40.se
Woah! That's so awesome!
And now I've found even more functions of my drawing programs that can be
replaced with R.
Tom
2010/7/14 Marc Schwartz
> On Jul 14, 2010, at 1:38 PM, Thomas Levine wrote:
>
> > I've had two reasons for wanting to embed graphics in R pdf output.
> >
> > 1. I am plotting
I was hoping that there might be some way to attach significance code like
the ones from summary.lm to a dataframe. Anyone know how to do something
like that. Here is the function i'd like to add that functionality to:
add1.coef <- function(model,scope,test="F",p.value=1,order.by.p=FALSE)
{
a <- rbind(1:3, 4:6, 7:9, 10:12, 13:15)
a1 <- a[1:3,]
a2 <- a[4:5,]
a1
a2
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I combined 2 data frames together using rbind... How do I unbind the data at
a specific row to create 2 separate data frames?
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On Wed, 2010-07-14 at 04:31 -0700, Dr. Federico Andreis wrote:
> does anybody know of a package (working under Linux) for multilevel
> IRT modelling?
> I'd love to do this without having to go on WINSTEPS or the like..
The first place to look would be the special issue of the Journal of
Statistica
Hi All,
I'm trying to run a kernel principal component analysis on a corpus with 89769
text documents. I'm using the kpca command from the kernlab package. Here is
the code:
output<-kpca(text, kernel=worddot(type="spectrum", length=1))
The problem is that when I run the kpca, it bails
try:
print(counter)
flush.console() # force the output
On Wed, Jul 14, 2010 at 2:31 PM, Michael Haenlein
wrote:
> Dear all,
>
> I'm using a while loop in the context of an iterative optimization
> procedure. Within my while loop I have a counter variable that helps me to
> determine how long th
On Jul 14, 2010, at 1:38 PM, Thomas Levine wrote:
> I've had two reasons for wanting to embed graphics in R pdf output.
>
> 1. I am plotting something on top of a surface (It's actually a desk.) of
> which I have a picture and would like to place a picture underneath.
> 2. I can produce all of my
I suggest trying to write the data into .php file directly.
outfile <-paste(filepath,"distance",".php",sep="")
data <- "Distance=num"
num <- 1000
data <- sub("num", num,data)
write(data,file=outfile)
-
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I've had two reasons for wanting to embed graphics in R pdf output.
1. I am plotting something on top of a surface (It's actually a desk.) of
which I have a picture and would like to place a picture underneath.
2. I can produce all of my presentation slides in R without LaTeX but have a
few pictur
Dear all,
I'm using a while loop in the context of an iterative optimization
procedure. Within my while loop I have a counter variable that helps me to
determine how long the loop has been running. Before the loop I initialize
it as counter <- 0 and the last condition within my loop is counter <-
Hi all,
I am sure this is a well-studied stats problem, could anybody give me some
pointers?
It's similar to Canonical Correlation study.
We have a bunch of random variables, and want to figure out the set of
linear combinations of these variables, such that their mutual correlations
are all bo
Maybe I'm missing something, but after reading the reshape package, I'm still
not quite sure how reshaping the data will help me with storing the
previously used samples and preventing me from selecting previously used
samples in the future.
This is my pseudo code thought process, but I'm not s
sample(data, 3, replace=FALSE)[,-1:2]
or
sample(data, 3, replace=FALSE)[,-c("id","pID50")]
Tyler
On Wed, Jul 14, 2010 at 1:17 PM, Addi Wei [via R] <
ml-node+2289092-1912443153-77...@n4.nabble.com
> wrote:
> id pID50 apol a_acca_acid a_aro a_base a_count
> 1 mol.11 3.63
Correction:
data[abs(data$price-avg)<=3*std,]
-
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Let's say your "data" has 2 columns: one is "date" and another is "price",
then
avg = mean(data$price, na.rm=T)
std = sd(data$price, na.rm=T)
The data after those unwanted removed should be:
data[data$price-avg<=3*std,]
-
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barbara horta e costa wrote:
>
>
> Sample Season Area Gear Depth
>1 W 1 5 1
>2 Sp 1 3 1
>2 Sp 1 5 1
>2 Sp 1 11 1
>
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PLEASE do read
I am resending this, as I believe it has not arrived on the mailing
list when I first emailed.
I have a set of labels arranged along a timeframe in a. Each label has
a timestamp and marks a state until the next label. The dataframe a
contains 5 such timestamps and 5 associated labels. This means,
I would use "melt" from the reshape package so that "sample" could be used,
rather than trying to process various selections of columns from a wide
data.frame.
"Addi Wei" wrote:
>
>Sorry to post multiple questions, but this is still related to the sample
>function.
>
>In my previous example, h
Hi Matthew and Jim,
Thanks for all the suggestions as always. Matthew's post was very
informative in showing how things can be done much more efficiently
with data.table. I haven't had a chance to finish the reshaping
because my group was a in rush,
and someone else decided to do it in Perl. Howev
Hi,
I have the following dataset and I would like to create a dotplot with
confidence limits:
CAT1 CAT2 MEAN Lower
Upper
1 1 10.619 0.392
0.845
2 1
Good afternoon,
Mango Solutions AG (Switzerland) is proud to announce the forthcoming BaselR
meeting.
Thank you to everyone who supported our inaugural BaselR meeting on April
28th; we were fortunate to have three excellent presentations which prompted
lively discussion - our thanks go to And
Sorry to post multiple questions, but this is still related to the sample
function.
In my previous example, how do I save/store the current sample so when I run
sample again (after analysis) I can exclude the samples that were previously
chosen.
For example if I have 180 factors or columns...an
On Wed, Jul 14, 2010 at 10:24 AM, Federico Andreis
wrote:
> I guess you could just use as an argument to sample
>
> data[,-c(1,2)]
>
> where 1 and 2 are id and pID50 column number
or if you do not know them and do not want to find out:
sample(data[ , - match(c("id", "x3"), names(data))], 3, repl
Pau,
Thanks a lot for your email, I found it very helpful. Please see below for
my reply, thanks.
-Jack
On Wed, Jul 14, 2010 at 10:36 AM, Pau Carrio Gaspar wrote:
> Hello Jack,
>
> 1 ) why do you thought that " larger C is prone to overfitting than smaller
> C" ?
>
*There is some statement
I guess you could just use as an argument to sample
data[,-c(1,2)]
where 1 and 2 are id and pID50 column number
On Wed, Jul 14, 2010 at 7:17 PM, Addi Wei wrote:
>
> id pID50 apol a_acca_acid a_aro a_base a_count
> 1 mol.11 3.63 -0.882267 -0.527967 -0.298197 -1.032380
id pID50 apol a_acca_acid a_aro a_base a_count
1 mol.11 3.63 -0.882267 -0.527967 -0.298197 -1.032380 0 -1.063410
2 mol.14 3.38 -1.007330 -0.527967 -0.298197 -1.032380 0 -1.063410
3 mol.19 3.18 1.153560 1.407910 -0.298197 1.254100 0 1.160080
4 mol.20
Hi all,
Maybe I missed some crucial context (I did not follow the example all
the way through). But of course ggplot will make legends based on
integers. For example:
dat <- data.frame(x=sample(1:10, 100, replace=TRUE),
y=sample(1:10, 100, replace=TRUE),
z=sampl
On 14/07/2010 12:01 PM, Steve Pederson wrote:
Hi,
I can't seem to install R from source. I've downloaded the latest
Rtools211.exe from http://www.murdoch-sutherland.com/Rtools/ & done a
full installation of that and Inno Setup.
I have set R_HOME as C:\R (and also tried using C:\R\R-2.11.1)
Hello R community:
Here is another question,
How can I estimate a differential equation parameters based on a data set?
If you know where I can find some examples will be better,
Thanks again, and cheers,
Oscar Rodriguez Gonzalez
Mobile: 519.823.3409
PhD Student
Canadian Resear
syrvn wrote:
Thanks again for your quick reply.
I understood your procedure but now it is even more strange why my
conversion does not work.
In your example, the NA values are in "brackets" and what your
procedure does is to
convert these values into NA and then it seems to be possible to us
I'm using R x64 2.11.0(windows)
I was trying to load workspace I saved some days ago, but got the
error:
ReadItem: unknown type 63, perhaps written by later version of R.
Has anyone come across the same problem? Any solutions?
Many thanks
yan
*
On Jul 14, 2010, at 10:17 AM, Andrea Foulkes wrote:
> Hi,
>
> I just installed version 2.11.1 on my Mac OS X 10.5.2. When I try running R
> from my xterm, I get the following error:
>
> Error in loadNamespace(name) : there is no package called 'lme4'
> Fatal error: unable to restore saved data
Frédéric Holzwarth uni-leipzig.de> writes:
>
> Hello there,
>
> is there a way to update a model, which was called by "bugs()"? For
> instance starting with few iterations and then updating more and more,
> as is possible inside the WinBUGS-window. If set "debug=TRUE", then the
> window rema
On Wed, Jul 14, 2010 at 05:51:17PM +0200, will.ea...@gmx.net wrote:
> Dear all,
>
> how can I use R on a 64-bit Windows Server 2003 machine (24GB RAM) with more
> than 3GB of working memory and make full use of it.
>
> I started R --max-mem-size=3G since I got the warning that larger values are
Thanks again for your quick reply.
I understood your procedure but now it is even more strange why my
conversion does not work.
In your example, the NA values are in "brackets" and what your
procedure does is to
convert these values into NA and then it seems to be possible to use
data.matrix to
On Wed, Jul 14, 2010 at 11:17 AM, Andrea Foulkes
wrote:
> Hi,
>
> I just installed version 2.11.1 on my Mac OS X 10.5.2. When I try running R
> from my xterm, I get the following error:
>
> Error in loadNamespace(name) : there is no package called 'lme4'
> Fatal error: unable to restore saved data
You need to understand the difference between how a value is stored in an R
object with full floating point precision versus how a value in R is displayed
(printed) in the console with a print "method".
In this case, wilcox.test() returns an object of class 'htest' (as noted in the
Value sectio
Hi,
I can't seem to install R from source. I've downloaded the latest
Rtools211.exe from http://www.murdoch-sutherland.com/Rtools/ & done a
full installation of that and Inno Setup.
I have set R_HOME as C:\R (and also tried using C:\R\R-2.11.1)
After successfully running 'tar xf R-2.11.1.tar
More importantly than just that they are factors, NA is actually a
level of X3. If it was a factor column, but NA was not a level, than
in the conversion to numeric, it would not change into a 4, but it is
a level (in fact the 4th level), so it becomes a 4. From ?factor here
is the recommended wa
Dear all,
how can I use R on a 64-bit Windows Server 2003 machine (24GB RAM) with more
than 3GB of working memory and make full use of it.
I started R --max-mem-size=3G since I got the warning that larger values are
too large and ignored.
In R I got:
> memory.size(max=FALSE)
[1] 10.5
> memory
Hi Peter,
Thanks for your response. Yes, I am interested in P-values smaller
than 1e-16. Below a certain value they may not tell much about
significance but are useful for ordering (ranking), for example,
differentially expressed genes in microarray data. Something similar
is done by sequence sim
Well, as the author of two CRAN packages with short names (tis and
fame), I maintain that short names can be fairly informative. The fame
package is an interface to FAME time series databases, and the tis
package implements the tis (TimeIndexedSeries) class and support classes
that it needs.
When
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