Works wonderfully. I am very happy that I eventually found this post :)
Daniel.
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On Mon, Jun 21, 2010 at 8:38 PM, David Winsemius wrote:
>
> On Jun 21, 2010, at 9:18 PM, Duncan Murdoch wrote:
>
>> On 21/06/2010 9:06 PM, G FANG wrote:
>>>
>>> Hi,
>>>
>>> I want to get the unique set from a large numeric k by 1 vector, k is
>>> in tens of millions
>>>
>>> when I used the matlab
The original question was about a matrix, not a vector and this is much slower:
x <- sample(10, size=13584763, replace=T)
dim(x) <- c(13584763, 1)
system.time(unique(x))
So the solution would be:
unique(as.vector(x))
>>>
From: Duncan Murdoch
To:G FANG
CC:
Date: 22/Jun/2010 1:20p
Subjec
On Jun 21, 2010, at 9:18 PM, Duncan Murdoch wrote:
On 21/06/2010 9:06 PM, G FANG wrote:
Hi,
I want to get the unique set from a large numeric k by 1 vector, k is
in tens of millions
when I used the matlab function unique, it takes less than 10 secs
but when I tried to use the unique in R wi
I'm trying to use RSQLite statement to cycle through a large database
in "chunks" via the fetch(...,n=2). As far as I can tell,
however, it keeps re-fetching the same beginning set of rows -- any
ideas what might be wrong with the following code? The select
statement is pulling from multiple
On 21/06/2010 9:06 PM, G FANG wrote:
Hi,
I want to get the unique set from a large numeric k by 1 vector, k is
in tens of millions
when I used the matlab function unique, it takes less than 10 secs
but when I tried to use the unique in R with similar CPU and memory,
it is not done in minutes
Hi,
I want to get the unique set from a large numeric k by 1 vector, k is
in tens of millions
when I used the matlab function unique, it takes less than 10 secs
but when I tried to use the unique in R with similar CPU and memory,
it is not done in minutes
I am wondering, am I using the function
Hi Carlo,
One "quick" way to verify that the fixed effects parts are the same, is to
examine the design matrices that "gamm" passes on to lme. They should be the
same if the interpretation is correct. If you want to follow the mixed effect
relation to its end, why not specify "REML" as the fi
The usual method is either
lis <- vector("list")
or, nearly equivalently,
lis <- list()
If you know in advance how many components the list will have, there can be a
slight advantage in using
lis25 <- vector("list", 25)
if e.g. you know the list will be of length 25.
Bill Venables.
---
Hi Christos,
thanks for your kind reply, I agree entirely with your interpreation.
In the first model comparison, however, "anova" does seem to work
according to our interpretation, i.e. the "df" are equal in the two model.
My intuition is that the "anova" command does a fixed-effect test rather
Use
result <- vector("list", n)
to make a list of length n, all of whose
components are NULL.
Bill Dunlap
Spotfire, TIBCO Software
wdunlap tibco.com
> -Original Message-
> From: r-help-boun...@r-project.org
> [mailto:r-help-boun...@r-project.org] On Behalf Of Peter Langfelder
> Sent:
On Jun 21, 2010, at 7:18 PM, song song wrote:
May I ask how to initialize a list?
usually I will use " result=list(0) " to do this. is this right?
There is now something in that list, namely an element whose value is
zero. If you append to it with the c() function, the 0 will still be
t
On Mon, Jun 21, 2010 at 4:18 PM, song song wrote:
> May I ask how to initialize a list?
>
> usually I will use " result=list(0) " to do this. is this right?
It works, but it is cleaner to use
results=list()
The difference is that list(0) will have one component that contains
the number zero, w
On Jun 21, 2010, at 6:50 PM, CC wrote:
Hi all!
I am trying to extract output information from the survfit function
in order
to generate a matrix of select output for multiple factors.
Specifically, I am interested in extracting the number of events (in
the
output below: 106, 2, 3). The v
May I ask how to initialize a list?
usually I will use " result=list(0) " to do this. is this right?
[[alternative HTML version deleted]]
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https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the post
Hi,
I have the following data
data1 <- data.frame(count = c(0,1,1,2,4,5,13,16,14), weeks = 1:9,
treat=c(rep("1mg",3),rep("5mg",3),rep("10mg",3)))
and I am using
library(splines)
to fit
glm.m <- glm(count~bs(weeks)+as.factor(treat),family=poisson,data=data1)
and I am inte
Hi,
>From my understanding, GAMs as well as GAMMs can be represented as
>(generalized) mixed models (Simon discusses this in the last chapter of his
>book; a condensed overview from a Bayesian perspective is given in the
>following paper by Y. Zhao, J. Staudenmayer, B. A. Coull and M. P. Wand
Hi all!
I am trying to extract output information from the survfit function in order
to generate a matrix of select output for multiple factors.
Specifically, I am interested in extracting the number of events (in the
output below: 106, 2, 3). The variable names represented in my function
(ee) ar
Thanks for your help, Bert,
on your points:
1. I was not aware of such a list, I will check it out.
2. As you said Pinheiro and Bates (2000) advocate anova LR test for random
effect with the SAME fixed effect. My question was exactly related to this
point... are the fixed effect the same in this
On 21/06/10 20:32, Aline Deschamps wrote:
Thank you for your mail and the attached documents.
You're most welcome :-)
I've read the article and I found it very interesting, but I have some
questions :
- The 5 steps in this article are for creating a choice set for one
respondent, are they?
Y
Hey all,
Here's a website I've been working on for the NPS to help move them toward
using R (took some of T. Philippi's stuff and spruced it up a bit; also
added some of my own material). I've tried to integrate interactivity in
the website to help make learning R less painful (tooltip for parsi
?prop.table probably.
RSiteSearch at R Site Search http://finzi.psych.upenn.edu/nmz.html
or ?RSiteSearch would probably given you the anwser in about 30 seconds.
--- On Mon, 6/21/10, Erin Hodgess wrote:
> From: Erin Hodgess
> Subject: [R] tables
> To: "R help"
> Received: Monday, June 21,
On Jun 21, 2010, at 2:46 PM, Erin Hodgess wrote:
Dear R People:
I have generated the following table:
table(zza$DEATH,zza$GENDER)
F M
2009-04-21 0 1
2009-04-22 4 2
2009-04-24 6 0
2009-04-25 1 3
2009-04-26 2 0
2009-04-28 3 0
2009-04-29 2 2
On Mon, 21 Jun 2010, Duplisea, Daniel wrote:
Hello. Given this group assignment vector x:
x= rep(letters[1:3],c(9,21,9))
I would like to know the number of all possible unique permutations of x
and also obtain the matrix of them.
Do you mean what would
ncol( unique( replicate( Inf,
Thanks Hadley for taking the interest here.
The data sets are a bit large and I have placed them available for your
download on
http://master.kvindesland.no/R/
You will find datasets in both Rdata and dput format. It seems that some
data sets works nicely and others do not even if they come from
Bert Gunter
Genentech Nonclinical Statistics
> -Original Message-
> From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org]
> On Behalf Of Joris Meys
> Sent: Monday, June 21, 2010 12:09 PM
> To: Carlo Fezzi
> Cc: r-help@r-project.org
> Subject: Re: [R] {Spam?} Re: mgcv,
>-Original Message-
>From: r-help-boun...@r-project.org
[mailto:r-help-boun...@r-project.org]
>On Behalf Of Joris Meys
>Sent: Monday, June 21, 2010 5:32 AM
>To: Patrick Burns
>Cc: r-help@r-project.org
>Subject: Re: [R] Popularity of R, SAS, SPSS, Stata...
>
>On Mon, Jun 21, 2010 at 11:15
>-Original Message-
>From: r-help-boun...@r-project.org
[mailto:r-help-boun...@r-project.org]
>On Behalf Of Patrick Burns
>Sent: Monday, June 21, 2010 5:16 AM
>To: r-help@r-project.org
>Subject: Re: [R] Popularity of R, SAS, SPSS, Stata...
>
>I think there is a problem with the
>question:
>-Original Message-
>From: r-help-boun...@r-project.org
[mailto:r-help-boun...@r-project.org]
>On Behalf Of Ted Harding
>Sent: Sunday, June 20, 2010 9:01 PM
>To: r-help@r-project.org
>Subject: Re: [R] Popularity of R, SAS, SPSS, Stata...
...
>
>John and I discussed the snowball idea at so
Erin -
Here's a reproducible example that should help
answer your question:
set.seed(17)
df = data.frame(a=sample(letters[1:5],250,replace=TRUE),
+ b=sample(c('A','B'),250,replace=TRUE))
tt = table(df$a,df$b)
100 * prop.table(tt) # total of all percentages = 100
On Mon, Jun 21, 2010 at 11:45 AM, Yi wrote:
> Hi, Josh,
>
> Thank you very much! It is what I want!
> Because it is very obvious that the variance is not a constant in my linear
> model. So I am thinking about robust standand error. Any code works for this
> purpose in R?
I do not have much exper
Hi Carlo,
You should get the book of Simon Wood and read it thoroughly. It's all
explained in there, but it will lead me too far to copy it all in a
mail. In short : random effects are part of the error structure of the
model, not of the model itself. They're added to correct the error on
the para
I was missing the spam library.
I did some testing with m x m matrices (see below). Computing 'a' is the
villain. The computation time for 'a' is exponential in m. For a 100 by 100
matrix, the predicted time is about 20 seconds. Thus, 100,000 runs, would
take about 23 days.
library(igraph)
libr
Dear All:
My apologies, but my formatting of the original message was poor.
Here it is again with more appropriate spacing for copying into the
terminal.
I am using lmer() {lme4} to analyze results from a reciprocal
transplant experiment where the response variable is modeled as a
fu
Dear R People:
I have generated the following table:
> table(zza$DEATH,zza$GENDER)
F M
2009-04-21 0 1
2009-04-22 4 2
2009-04-24 6 0
2009-04-25 1 3
2009-04-26 2 0
2009-04-28 3 0
2009-04-29 2 2
However, instead of total counts in the F an
Hello R world,
Can't seem to get history expansion working in R under emacs 23.2 with ess on
mac osx. (Vincent Goulet's package). Even '!!' does not get me the previous
command. What could be wrong?
Thanks,
vj
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R-help@r-project.org mailing lis
Hello,
If you just want the mean and variance of log(y) try:
mean(log(y))
var(log(y))
if there is missing data, you can add na.rm=TRUE to both of those. If
you want the mean and variance of the predicted ys
mean(predict(linmod))
var(predict(linmod))
see
?mean
?var
?predict.lm #the specific m
Hi, folks,
As seen in the following codes:
x1=rlnorm(10)
x2=rlnorm(10,mean=2)
y=rlnorm(10,mean=10)### Fake dataset
linmod=lm(log(y)~log(x1)+log(x2))
After the regression, I would like to know the mean of y. Since log(y) is
normal and y is lognormal, I need to know the mean and variance of log(y)
Dear All:
I am using lmer() {lme4} to analyze results from a reciprocal
transplant experiment where the response variable is modeled as a
function of two fixed effects and their interaction.
Example data follow:
#library(lme4)
#library(gmodels)
env=c("r","r","w","w","r","r","w","w","r","r
Thank you all for your quick answers.
Best,
Phil
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ht
Hi Joris (CC Simon),
Thanks for your kind replies and for being so responsive.
I think this post boils down to two main questions (which I feel are very
important for gams modelling):
1- Is it appropriate to use LR tests in "gamm" to test model reduction?
2- If yes, which degrees of freedom shou
Dear R-List,
I try to use accented chars in a plot using odfWeave (see the example
below). I found the solution using the iconv command to write the
accented char "é". But, is somebody know another solution not to have to
use iconv command every time ?
Thanks
Example :
<>=
par(mfrow=c(1,
Hello. Given this group assignment vector x:
x= rep(letters[1:3],c(9,21,9))
I would like to know the number of all possible unique permutations of x and
also obtain the matrix of them. Thus, each vector should still contain 9*a,
21*b and 9*c, but case assigment must be different for one case (d
On Mon, 21 Jun 2010, Filoche wrote:
Hi everyone.
I want to use 2 different functions (in 2 packages) that have same name. for
instance, if I call the function, it will use the one in the last called
package. Is there a way to specify the package to use for a function?
Something like
Package
On Mon, 21 Jun 2010, Henrik Bengtsson wrote:
On Mon, Jun 21, 2010 at 4:23 PM, Gábor Csárdi wrote:
On Mon, Jun 21, 2010 at 4:17 PM, Duncan Murdoch
wrote:
[...]
The requirement is that the methods need to have signatures that contain all
the arguments of the generic. If the generic includes .
On Mon, Jun 21, 2010 at 6:58 AM, Thaler, Thorn, LAUSANNE, Applied
Mathematics wrote:
> Thanks, works as expected. But maybe I've to be a bit more clear about the
> reason why I'd like to have such a construct.
>
> In lattice you can define some parameters by passing a named list to
> par.setting
On Sun, 20 Jun 2010, Erin Hodgess wrote:
Dear R People:
Here is a little section of a data frame:
zzz[1:10,]
DATE GENDER AGE Co DEATH1
3945 2009-04-16 M 24Botulinic 23
3851 2009-04-16 M 35 Constitutional 23
8495 2009-04-16 F 49
On Jun 21, 2010, at 10:27 AM, David Riebel wrote:
I am using the lm function in R to fit several linear models to a
fair-sized dataset (~160 collections of ~1000 data points each). My
data have intrinsic, systematic uncertainty much greater than the
measurement errors on any individual point.
Sam Brown wrote:
Hi Michael
Thank you very much for the intel regarding eta^2. It is pretty much the sort of thing that I am wanting.
The latest developer version of the heplots package on R-Forge now
includes an initial implementation of etasq() for
multivariate linear models. Note that f
On Mon, Jun 21, 2010 at 2:29 PM, Filoche wrote:
>
> Hi everyone.
>
> I want to use 2 different functions (in 2 packages) that have same name. for
> instance, if I call the function, it will use the one in the last called
> package. Is there a way to specify the package to use for a function?
>
>
On Mon, Jun 21, 2010 at 4:23 PM, Gábor Csárdi wrote:
> On Mon, Jun 21, 2010 at 4:17 PM, Duncan Murdoch
> wrote:
> [...]
>> The requirement is that the methods need to have signatures that contain all
>> the arguments of the generic. If the generic includes ..., then the methods
>> can add other
On Jun 21, 2010, at 10:27 AM, ecvet...@uwaterloo.ca wrote:
I have a set of data with 12 readings for temperature per day, with
180 days. I want to find the average temperature of each day. I am
able to do this one by one, but with that many days to calculate the
average for, it will get ve
On Mon, Jun 21, 2010 at 3:48 PM, Aaron Plavnick/MSINVESTORS
wrote:
> I was wondering if anyone knew how to fit a series using a Garch-M (Garch
> in the mean) model. From what I gathered from the documentation, it does
>
Perhaps rgarch [1]? Also, you might get better help if you were
posting to r-s
package::function
On Mon, Jun 21, 2010 at 6:29 AM, Filoche wrote:
>
> Hi everyone.
>
> I want to use 2 different functions (in 2 packages) that have same name. for
> instance, if I call the function, it will use the one in the last called
> package. Is there a way to specify the package to use f
Hi everyone.
I want to use 2 different functions (in 2 packages) that have same name. for
instance, if I call the function, it will use the one in the last called
package. Is there a way to specify the package to use for a function?
Something like
Package1:myfunction(...)
Package2:myfunction(x
I have a set of data with 12 readings for temperature per day, with
180 days. I want to find the average temperature of each day. I am
able to do this one by one, but with that many days to calculate the
average for, it will get very long. I'm sure there is a faster way to
do this, I just d
Hi Jim,
that works perfectly.
Thanks
Florian
On 21/06/2010 14:10, Jim Lemon wrote:
On 06/21/2010 09:51 PM, Florian Burkart wrote:
Hi together,
I am looking to plot a play symbol (e.g. a triangle with the tip facing
east) with the points command, but I noticed that this symbol is not
avai
Hello,
I was wondering if anyone knew how to fit a series using a Garch-M (Garch
in the mean) model. From what I gathered from the documentation, it does
not seem to be implemented in either fGarch, fSeries, or tSeries. Perhaps
there is an option that allows this functionality. Otherwise, if i
Joris,
Thank you, your solution did what I needed.
Steve Friedman Ph. D.
Spatial Statistical Analyst
Everglades and Dry Tortugas National Park
950 N Krome Ave (3rd Floor)
Homestead, Florida 33034
steve_fried...@nps.gov
Office (305) 224 - 4282
Fax (305) 224 - 4147
Dear all,
does anybody have experience with the open source database InfiniDB
http://www.infinidb.org/index.php? The contributor Calpont claims that it would
much faster than the standard MySQL for certain applications.
How would you install it that InfiniDB can run with the package RMySQL unde
No idea, do you have the right repository seledcted? Is there nay proxy
in your network that may change the download data for some reason? I
have not observed that before and I haven't seen similar reports before.
Best,
Uwe Ligges
On 21.06.2010 11:03, Rubén Roa wrote:
Dear ComRades,
I am ha
On Mon, Jun 21, 2010 at 4:17 PM, Duncan Murdoch
wrote:
[...]
> The requirement is that the methods need to have signatures that contain all
> the arguments of the generic. If the generic includes ..., then the methods
> can add other arguments, too. So with the generic for plot() as you show
> a
On 21/06/2010 9:31 AM, Gábor Csárdi wrote:
Dear all,
"Writing R Extensions" explicitly says that
A method must have all the arguments of the generic, including ...
if the generic does.
A method must have arguments in exactly the same order as the generic.
If the generic specifies de
You can't get them out of the plot function, but you can calculate
them from the fit. This code returns a matrix with the appropriate
rownames and colnames.
x1 <- treeresponse(iris.ct)
p <- matrix(
unlist(unique(x1)),
ncol=3,
byrow=T
)
colnames(p) <- levels(iris$Species)
rowname
It may be worthwhile tracking citations in "early adopter" journals such
as statistical methodology journals, then watching trends in later
adopter subject matter journals (in medical research this might be JAMA,
NEJM).
Frank
On 06/21/2010 08:11 AM, Kjetil Halvorsen wrote:
One should also t
On Mon, 21 Jun 2010, steve_fried...@nps.gov wrote:
Hello,
This is a re-submittal of question I submitted last week, but haven't rec'd
any responses.
I need to extract the probabilities used to construct the barplots
displayed as part of the graph produced by plot("ctree").
For example,
libr
I just updated spdep and I see that as.spam.listw works. Below is
sessionInfo
Furthermore, it may be straightforward to condense the adjacency
matrix *before* converting to graph which may help a little bit. You
can profile the code and see which part needs speeding up.
library(spdep)
lib
Patrick Burns wrote:
> I think there is a problem with the
> question: Not everyone thinks of R
> as a statistics program. Furthermore,
> I don't think it should be thought of
> as a statistics program.
>
> (Statistics is what stuffy professors
> do, I just look at my data and try to
> figure ou
Works great. Thanks much!
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https:
Dear all,
"Writing R Extensions" explicitly says that
A method must have all the arguments of the generic, including ...
if the generic does.
A method must have arguments in exactly the same order as the generic.
If the generic specifies defaults, all methods should use the same
defau
Hello,
This is a re-submittal of question I submitted last week, but haven't rec'd
any responses.
I need to extract the probabilities used to construct the barplots
displayed as part of the graph produced by plot("ctree").
For example,
library(party)
iris.ct <- ctree(Species ~ . , data = iris
Code is not runnable, so can't check why it goes wrong, but tried
already with as.character(save.tract$...) ?
Cheers
Joris
On Mon, Jun 21, 2010 at 3:15 PM, GL wrote:
>
> I am using the code below to extract census tract information.
> save.tract$state, save.tract$county and save.tract$tract are r
>
> I am looking for code for modeling recurrent events with R, Especially
> Andersen Gill Model /PWP models. I would greatly appreciate it if
> anyone can
> advise of refferences / books / other relevant information. thanks in
> advance.
The survival package does this in depth. For detailed ex
Try this also:
replace(example, example > threshold, threshold)
On Mon, Jun 21, 2010 at 7:34 AM, Jim Hargreaves wrote:
> Dear List,
>
> I have a list of length ~1000 filled with numerics. I need to replace the
> elements of this list that are above a certain numerical threshold with the
> value
One should also take into account the other R list. For example, as of
today the number of subscribers to
R-help-es (R-help for spanish speakers) is 290, increasing.
Kjetil Halvorsen
On Sun, Jun 20, 2010 at 6:28 PM, Muenchen, Robert A (Bob)
wrote:
>
>
>>-Original Message-
>>From: r-help-
I am using the code below to extract census tract information.
save.tract$state, save.tract$county and save.tract$tract are returned as
factors. In the last three statements, I need to save the actual value of
the factor, but, instead, the code is yielding the position of the factor.
How do I inst
I think you have misunderstood the code! In case [B] below (sampling
uniformly over the area within the circle) the assignment
r <- sqrt(runif(n))
does just that: The radius distribution (of r) is not uniform;
the distribution of r^2 is uniform, and r^2 "is proportional to the
circle area".
In
Hi together,
I am looking to plot a play symbol (e.g. a triangle with the tip facing
east) with the points command, but I noticed that this symbol is not
available. Is there a way of turning symbol types 24 or 25 to face east?
If not, what is the easiest way to achieve a play symbol?
Thanks
On 06/21/2010 09:51 PM, Florian Burkart wrote:
Hi together,
I am looking to plot a play symbol (e.g. a triangle with the tip facing
east) with the points command, but I noticed that this symbol is not
available. Is there a way of turning symbol types 24 or 25 to face east?
If not, what is the ea
Hi Thierry,
unfortunately, that does not seem to work for me.
On 10/06/2010 14:19, ONKELINX, Thierry wrote:
Hi Florian,
Have you tried to replace each '\n' with '\r\n'. That did the trick for
me.
HTH,
Thierry
ir.
Sorry Ted
The code for the circle is in error, the radius distribution should be
proportional to the circle area not
uniform. Better / simple to sample from the (-1,1) square uniformly and reject
where x^2+y^2 > 1
Heberto
From: r-help-boun...@r-project.org
Dear list,
I am using glm's to predict count data for a fish species inside and outside
a marine reserve for three different methods of monitoring.
I run glms and figured out the best model using step function for each
methods used.
I predicted two values for my fish counts inside and outside the
Dear Mr.Zeileis & all.
(1) Â Â Â Thx for your reply. Yes, I am talk about the function zeroinfl()
from the package "pscl". I want to use Newton Raphson to get parameter   Â
      estimation ZINB, so I try this:
You shouldn't use sapply/lapply for this but use the indices
> set.seed(1)
> r <- round(runif(10,1,10))
> treshold <- 5
> head(r)
[1] 3 4 6 9 3 9
> system.time( r[ r>threshold ] <- threshold )
user system elapsed
0 0 0
> head(r)
[1] 3 4 5 5 3 5
On Mon, Jun 21, 2010 a
Hi,
You should use the sapply/lapply for such operations.
> r<-round(runif(10,1,10))
> head(r)
[1] 3 7 6 3 2 8
> filt<-function(x,thres) ifelse(x system.time(r2<-sapply(r,filt,thres=5))
user system elapsed
3.360.003.66
> head(r2)
[1] 3 5 5 3 2 5
To return a list, replace "
try 'na.locf' in the zoo package
On Mon, Jun 21, 2010 at 7:52 AM, Patrick Hausmann
wrote:
> Dear list,
>
> I'm trying to replace NA-values with the preceding values in that column.
> This code works, but I am sure there is a more elegant way...
>
> df <- data.frame(id = c("A1", NA, NA, NA, "B1",
Dear list,
I'm trying to replace NA-values with the preceding values in that column.
This code works, but I am sure there is a more elegant way...
df <- data.frame(id = c("A1", NA, NA, NA, "B1",
NA, NA, "C1", NA, NA, NA, NA),
value = c(1:12))
rn <- c(rownam
Hi,
I have a number of multilevel models and I would like some Latex outputs
of them. I usually use the "apsrtable" package, but it does not accept
"lme" outputs. Neither does the "mtable" function in the "memisc"
package. Is there any good alternative that I am missing?
Thanks, Jonas
___
I know this is an old thread but, since the issue posted here has not been
solved, if someone is still needing help, I suggest to have a loook at
http://www.gisos.de/blog/articles/5/jri-and-eclipse-first-steps
--
View this message in context:
http://r.789695.n4.nabble.com/Java-to-R-interface-tp8
On 21/06/2010 2:49 AM, Peter Dalgaard wrote:
Duncan Murdoch wrote:
On 20/06/2010 6:36 PM, Muenchen, Robert A (Bob) wrote:
-Original Message-
From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org]
On Behalf Of Ivan Calandra
Sent: Sunday, June 20, 2010
I have spdep 4.58. Perhaps it is deprecated in the new version. Try looking
for sparse matrix representation in the help files for spdep
Nikhil
On Mon, Jun 21, 2010 at 6:10 AM, Daniel Malter wrote:
>
> as.spam.listw is an unknown function. Is it in a different package?
>
> Daniel
>
> other att
On Fri, Jun 18, 2010 at 5:19 PM, David Wyllie wrote:
> Hi
>
> Thanks, but maybe I'm not making myself clear enough here.
> I think I'm already doing what you suggest, below the line # plot with fits
> .. in the original mail.
>
> I have made a little progress. I wish to apply a panel function to
Thanks, works as expected. But maybe I've to be a bit more clear about the
reason why I'd like to have such a construct.
In lattice you can define some parameters by passing a named list to
par.settings. Suppose I want to superpose two lines and use colors different
from the default:
xyplot(
"magic" code:
example[example>threshold] <-threshold
Cheers
Joris
On Mon, Jun 21, 2010 at 12:34 PM, Jim Hargreaves wrote:
> Dear List,
>
> I have a list of length ~1000 filled with numerics. I need to replace the
> elements of this list that are above a certain numerical threshold with the
> val
Dear List,
I have a list of length ~1000 filled with numerics. I need to replace
the elements of this list that are above a certain numerical threshold
with the value of the threshold.
e.g
example=list(1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 9, 8, 7, 6, 5, 4, 3, 2, 1)
threshold=5
example=(1, 2, 3, 4,
as.spam.listw is an unknown function. Is it in a different package?
Daniel
other attached packages:
[1] spdep_0.5-11coda_0.13-5 deldir_0.0-12
maptools_0.7-34 foreign_0.8-38 nlme_3.1-96 MASS_7.3-3
[8] Matrix_0.999375-31 lattice_0.17-26 boot_1
On 2010-06-21 3:30, Thaler, Thorn, LAUSANNE, Applied Mathematics wrote:
Hi everybody,
I'd like to have a list with two elements, where both elements have the same
value:
z<- list(a=1, b=1)
If it happens, that I've to change the value, I've to assure that I change
both. This is error prone. H
On Mon, Jun 21, 2010 at 11:15 AM, Patrick Burns
wrote:
>
> (Statistics is what stuffy professors
> do, I just look at my data and try to
> figure out what it means.)
Often those stuffy professors have a reason to do so. When they want
an objective view on the data for example, or an objective mea
Hi everybody,
I'd like to have a list with two elements, where both elements have the same
value:
z <- list(a=1, b=1)
If it happens, that I've to change the value, I've to assure that I change
both. This is error prone. Hence, a better way to achieve this is to define:
tmp <- 1
z <- list(a=tm
I think there is a problem with the
question: Not everyone thinks of R
as a statistics program. Furthermore,
I don't think it should be thought of
as a statistics program.
(Statistics is what stuffy professors
do, I just look at my data and try to
figure out what it means.)
On 20/06/2010 23:46
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