Something like this?
# Remove everything after ; to give the status
status<- sub(';.*$', '', data$cancer.problems)
# Remove everything before the last ; to give tissue
# In case a no ; in the string this goes wrong; correct
tissue<- sub('^.*;[ \n]*', '', data$cancer.problems)
tissue[! gre
On Fri, 23 Apr 2010, Worik R wrote:
I am sorry if this is documented in apply's dcumentation or completely
obvious, I could not find or work it out.
Well, try
?apply
and focus on the 'Value:' section, first para.
To me, that behavior seems consistent with other functions in
the [ts
On Thu, 22 Apr 2010, arnhol...@appstate.edu wrote:
I am trying to build a windows 32 bit version of R 2.11.0 from source on a
machine running
windows 7 - 64 bit while running as the machine's administrator.
I am able to run "make all recommended"...However, once I attempt to build the
bitmap f
Hi folks,
Here is the problem. I am giving an example .I want to find a measure
of similarity or dissimilarity among ranking (of students of a same class
of size say 50)by two judges. But instead of observing the rank of all the
50 students
(Where we could have used rank correlation measures)in eac
Fabulous! I managed to get close with t(), but had obviously missed the step
of setting the rownames first.
Thanks for your help!
David
-Original Message-
From: Ista Zahn [mailto:istaz...@gmail.com]
Sent: Friday, 23 April 2010 2:29 PM
To: Gobbett, David (CSE, Waite Campus)
Cc: r-help@r
Hi David,
There are many ways, including
rownames(propsum) <- propsum$coverClass
propsum$coverClass <- NULL
t(propsum)
Best,
Ista
On Fri, Apr 23, 2010 at 5:43 AM, wrote:
> Greetings all,
>
> I am having difficulty transposing, reshaping, flipping (not sure which) a
> data frame which is read
Greetings all,
I am having difficulty transposing, reshaping, flipping (not sure which) a data
frame which is read from a DBF file. I have tried using t(), reshape() and
other approaches without success. Can anyone please suggest an way (elegant or
not) of flipping this data around ?
The init
Thank you all for the great help...
I appreciate!
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h
Thank you!
Best Regards
Henrik
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h
I need help in developing the R syntax for a before-after control
intervention design (BACI). Each cell of the 2-way table has multiple
replicates-i.e., each replicate, in both the treatment and control groups,
is measured both before and after the treatment period. I am having
trouble in specif
Sorry for this late answer (I've had a seriously nonmaskable interrupt).
Since I have technical questions not related to R, I take the liberty to
follow this up by e-mail.
I might post a followup summary if another R problem arises...
Emmanuel Charpentier
Abhishek:
Thank you!
Thomas:
that worked out well, thank you again!
I also tried to use lm, and as expected in this case, I almost got the same
estimates of the parameters as in the MLE-case.
Best Regards
Henrik
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Ok sorry for bad explanation from my side
What I want. I have a txt file name is (table3.txt) this file contains 1293
rows and some of these row will have 1 column and some of them will have up
to may be 40 column. For example
that worked out well, thank you again!
I also tried to use lm, and as expected in this case, I almost got the same
estimates of the parameters as in the MLE-case.
Best Regards
Henrik
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SAS can merge two data set A, B in different way, A or B, A and B, A not B,
Can R merge function do the same way?
Thanks
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Sent from the R help mailing
I am trying to build a windows 32 bit version of R 2.11.0 from source on a
machine running
windows 7 - 64 bit while running as the machine's administrator.
I am able to run "make all recommended"...However, once I attempt to build the
bitmap files I get the following:
C:\Rsource\R-2.11.0\src\gn
Dear fellow R-help members,
I hope to seek your advice on how to parse/manage a dataset with hundreds of
columns. Two examples of these columns, 'cancer.problems', and
'neuro.problems' are depicted below. Essentially, I need to parse this into
a useful dataset, and unfortunately, I am not familiar
Hello everyone,
I'm trying to plot the initial and final size of some tadpoles and look at
their growth rates (slope of line). They are divided into 6 densities, and
so far I have plotted the initial and final sizes (these are means for a
pool), and color coded for the 6 densities, but I want a l
Claus O'Rourke wrote:
Dear all,
I have a couple of short noob questions for whoever can take them. I'm
from a very non-stats background so sorry for offending anybody with
stupid questions ! :-)
I have been using logistic regression care of glm to analyse a binary
dependent variable against a c
Dear R-list members,
I have just downloaded R version 2.11.0. Then I installed
package gdata. At the end of the installation, a warning message
said that package gtools could not be found. Package gdata
was, after the installation, included in the "Package Index"
in the help files. Messages duri
thank you! this really helps!
On Thu, Apr 22, 2010 at 7:00 PM, jim holtman wrote:
> ?strptime
>
> Read the documentation and you will find reference to "%OSn"
>
> > x <- strptime('13:45:34.123', format="%H:%M:%OS")
> > x
> [1] "2010-04-22 13:45:34"
> > format(x, format="%H:%M:%OS3")
> [1] "13:45
Thank you very much Dieter and Don. This solves my problem. :)
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confusionMatrix in the caret package can be used to replace your
manual procedure.
You could try using RWeka, the R interface to the java Weka software.
Once you have it working you could then directly interface your java
program to Weka without involving R.
On Thu, Apr 22, 2010 at 9:29 PM, Claus
Hi all,
I have a dataset similar to the following
NameDateValue
A 1/01/2000 4
A 2/01/2000 4
A 3/01/2000 5
A 4/01/2000 4
A 5/01/2000 1
B 6/01/2000 2
B 7/01/2000 1
B 8/01/2000 1
I would like R
Hi ,
This maybe a bug. I checked my another package, the same problem occurred.
See below for detailed information.
##check log##
* using log directory 'D:/StatSoft/R/MyPackage/sbar.Rcheck'
* using R version 2.10.1 (2009-12-14)
* using session charset: ISO8859-1
* checking for file 'sbar/DESCRIPT
Dear all,
I have a couple of short noob questions for whoever can take them. I'm
from a very non-stats background so sorry for offending anybody with
stupid questions ! :-)
I have been using logistic regression care of glm to analyse a binary
dependent variable against a couple of independent var
You are plotting the entire lattice plot (including axes, margins etc)
in the grid viewport. What you want to do is to call the panel
function, panel.levelplot(), instead.
However, why not just
mm <- map('worldHires', plot = FALSE)
levelplot(z~x+y,xyz, mm = mm, panel = function(..., mm) {
pan
Hi
I'm looking for a package to perform quality control, normalization and
analysis of high throughput cell-based chemical screens. I know that the
cellHTS2 package provides this for siRNA screens.
Does anybody know if something like what I'm looking for exists?
Thank you!
Gabriele Zoppoli,
On 2010-04-21 21:13, zhenjiang xu wrote:
R experts,
Is there anyway to reorder inside each group? In the following example, the
bar of year 1932 is always plotted before the bar of year 1931, may I change
the order inside each groups of bars?
Do you mean a different order in different panels?
Or use this handy-dandy function:
smode<-function(x){
xtab<-table(x)
modes<-xtab[max(xtab)==xtab]
mag<-as.numeric(modes[1]) #in case mult. modes, this is safer
themodes<-names(modes)
mout<-list(themodes=themodes,modeval=mag)
return(mout)
}
I am sorry if this is documented in apply's dcumentation or completely
obvious, I could not find or work it out.
Given an matricies Q: 2x3, R:1x3 and S:1x2
apply(Q, 1, '-', R) is 3x2 and apply(Q, 2, '-', S) is 2x3
Why?
cheers
Worik
> Q
[,1] [,2] [,3]
[1,]123
[2,] 10 11 1
I'm using randomSurvivalForest to predict survival from a rather small
sample. As it's not enough data to have training and validation set, I
rely on the "Estimate of error rate" computed by the randomForest. If I
understand the method correctly, it repeatedly partitions the data into
varying t
You don't have to use map() to draw the map.
m <- map(..., plot = FALSE)
xyplot(y ~ x, m, type = "l", aspect = "iso",
par.settings = list(axis.line = list(col = "transparent")))
or inside a panel function, assuming appropriate scales:
panel.xyplot(m$x, m$y, ...)
On 23 April 2010 04:38, David
Thank you Burt Gunter and David Winsemius,
I confirmed David's comment.
One must use type=c("p","g")
in order to get both the grid and points.
So, to use densityplot well,
we must be quite aware of the options
for panel.xyplot!
Cordially,
Giles Crane
On Apr 22, 2010, at 4:52 PM, Bert Gunter wrote:
" Must one compose a panel function?"
Depending on what you want exactly, no. Add the argument
type="g"
to your call.
(e.g.
densityplot(~fallrates, groups = prepost,type="g",...
)
See ?panel.xyplot and recall that lattice passes down argum
Another solution (whether this is better/worse, prettier/uglier, etc./etc. is
in the eye of the beholder):
library(TeachingDemos)
x0 <- rnorm(100)
x0[ 0 %<% x0 %<% 1.5 ]
Hope this helps,
--
Gregory (Greg) L. Snow Ph.D.
Statistical Data Center
Intermountain Healthcare
greg.s...@imail.org
801.40
" Must one compose a panel function?"
Depending on what you want exactly, no. Add the argument
type="g"
to your call.
(e.g.
densityplot(~fallrates, groups = prepost,type="g",...
)
See ?panel.xyplot and recall that lattice passes down arguments that it
does not know what to do with to the p
Dear R users,
I have been plotting several graphics in only one page. I intend to plot
only one legend in each page.
Since the graphics are inside a loop I have to do it automatically.
The main problem is that inside the loop I work with differente types of
variables, I mean , the range is differe
Greetings.
How can I insert gridlines
in the following density plot call?
Must one compose a panel function?
'data.frame': 46 obs. of 2 variables:
$ fallrates: num 5.2 7.1 7.1 9.8 3.7 7.5 5 6.2 1.5 2.9 ...
$ prepost : Factor w/ 2 levels "post","pre": 2 2 2 2 2 2 2 2 2 2 ...
library(latt
Why does:
nm <- intersect(names(d1),names(d2))
identical(d1[,nm], d2[,nm])
not do it?
-- Bert
Bert Gunter
Nonclinical Biostatistics
467-7374
http://devo.gene.com/groups/devo/depts/ncb/home.shtml
-Original Message-
From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-proje
Thanks for those pointers making some progress now
The following will put the levelplot on to the map, but the not with the
co-ordinates aligned...
The level plot appears on a slightly larger scale compared to the underlying
map.
In both the map and levelplot, the coordinates are in lon, lat
Paul
Just as in your implied analogy there are significant differences
beneath the surface between these programs despite superficial
similarities.
You will soon get frustrated trying to use both simultaneously as you
will not be sure that the critical step you've discovered in one will
wor
Ah.
Close to what David suggested...
Try:
?which.max
Contact
Details:---
Contact me: tal.gal...@gmail.com | 972-52-7275845
Read me: www.talgalili.com (Hebrew) | www.biostatistics.co.il (Hebrew) |
www.r-statistics.com (English
Hi
On 23/04/2010 12:10 a.m., Tal Galili wrote:
Hello Peter,
Thank you, and the R core team, for the new release.
I see that in R 2.11.0 there is now support for rendering of raster (bitmap)
images through rasterImage().
I am wondering - can this be used to create a texture/fill-pattern for
hi
Hi
Sounds like the 'compare' package might do some of what you want.
Paul
On 23/04/2010 1:41 a.m., Doran, Harold wrote:
I wonder if there is a more efficient way to do this task. Suppose I
have two data frames, such as
d1<- data.frame(x = c(1,2,3), y = c(4,5,6), z = c(7,8,9))
d2<- d1[, c('y'
On Apr 22, 2010, at 3:45 PM, tamas barjak wrote:
Hi All!
I have a problem that I do not know it how it is necessary to query
an index
belonging to a given value.
I bit hard to tell without an example but suspect you want:
?which
--
David Winsemius, MD
West Hartford, CT
___
Hi All!
I have a problem that I do not know it how it is necessary to query an index
belonging to a given value.
Somebody would help?
[[alternative HTML version deleted]]
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https://stat.ethz.ch/mailman/listin
Hi,
The permutation test for two samples in R is function perm.test(). I could
not figure out what is the statistics it estimate and how many permutation
it did in default?
Thanks,
[[alternative HTML version deleted]]
__
R-help@r-project.org m
Hi All,
I built a mixed model with subject-specific variance structure in SAS and it
works quite well. Now I intended to implement the same model in R using lme
with "weights" option. Following is the SAS code and the corresponding R code:
SAS:
proc mixed data=source;
class id trial group valen
Oh man, totally missed that one! Thanks so much for the reminder.
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On Apr 22, 2010, at 3:05 PM, Jack T. wrote:
Hi I'm trying to import a large csv file without quotes around each
field.
This creates some problems when there are "#" characters in certain
strings
as R understands its comment field and ignores the rest of the line.
Here's an example:
var1
On Apr 22, 2010, at 2:05 PM, Jack T. wrote:
>
> Hi I'm trying to import a large csv file without quotes around each field.
> This creates some problems when there are "#" characters in certain strings
> as R understands its comment field and ignores the rest of the line.
>
> Here's an example:
Hi I'm trying to import a large csv file without quotes around each field.
This creates some problems when there are "#" characters in certain strings
as R understands its comment field and ignores the rest of the line.
Here's an example:
var1, var2, var3, var4
one, two, three, four
Use this
Hello Everyone,
My company purchased S-Plus before it was bought out by Tibco. My understanding
is that we own version 7.0 outright.
So far, I've been learning in R but thought I might also try working in S-Plus.
My understanding is that S-Plus has some useful extra features. Another
potent
On Apr 22, 2010, at 2:24 PM, Kevin Wright wrote:
Mixing base/lattice graphics can be tricky, but is possible.
http://www.bioconductor.org/CRAN/web/packages/gridBase/vignettes/gridBase.pdf
That could be quite useful in the future. Thanks for that.
Also, did you look at Chapter 13 of the la
Hi All,
I apologize if this is not the right forum for this question.
I know there used to be a package for R that connected to opentick's (open
source) stock market data. However, opentick closed up about a year ago.
Does anyone know of a similar package that connects to IQfeed's stock market
Perhaps this helps?
http://blog.revolution-computing.com/2009/01/multicolor-text-in-r.html
Kevin
On Thu, Apr 22, 2010 at 11:18 AM, Ottorino-Luca Pantani <
ottorino-luca.pant...@unifi.it> wrote:
> Dear R-users, the problem I'm facing today is to write a
> multicolor main title in a plot.
>
> I w
Try this:
apply(replace(v <- rbind(v1, v2, v3), is.nan(v), 0), 2, max)
On Thu, Apr 22, 2010 at 12:24 PM, Vlatka Matkovic Puljic <
v.matkovic.pul...@gmail.com> wrote:
> Only thing that when I put na.rm=FALSE,
> R is puting in v4 NA (as is largest)
> and I want to see NA as zero (0, smallest val
Mixing base/lattice graphics can be tricky, but is possible.
http://www.bioconductor.org/CRAN/web/packages/gridBase/vignettes/gridBase.pdf
Also, did you look at Chapter 13 of the lattice book?
http://lmdvr.r-forge.r-project.org/figures/figures.html
Kevin
On Wed, Apr 21, 2010 at 2:08 PM, David
Gabriele -
How about this:
> data<-c("A","A","A","B","B","C","D")
> data
[1] "A" "A" "A" "B" "B" "C" "D"
> table(data)
data
A B C D
3 2 1 1
Thanks,
Lee
". . . people who focus only on 'what is' will create more of 'what is.'
People who focus mostly on 'what could be' will begin to create 'wh
It now works. Thanks both.
Muhammad
Peter Ehlers wrote:
On 2010-04-22 11:09, Muhammad Rahiz wrote:
Hello everyone,
I'm trying to draw the non-linear regression curve to look at the
distance decay relationship between distance and correlation values. But
I'm not able to plot the curve a
On Apr 22, 2010, at 1:36 PM, Zoppoli, Gabriele (NIH/NCI) [G] wrote:
Hi
how can I find, in a vector of characters, which is the most
frequent one?
> a <- sample(letters[1:10], 100, replace=TRUE)
> table(a)
a
a b c d e f g h i j
10 7 7 13 7 12 1 14 15 14
> max(table(a))
[1] 15
Hi Gabriele,
This is one way but I'm sure that there is an optimal way of doing so...
x <- c("A","B","C","C","C","C","C","B","B")
name <- unique(x) # get unique characters
freq <- c()
for (a in 1:length(name)){
freq[a] <- sum(x==name[a])}# get frequency
out <- cbind(name,freq)
Hello,
What about
test <- c(rep(c("A","C","G","T"), 20),"C")
table(test)
I am not sure that is an apt representation of the data and problem
you are trying to solve. It also occurred to me that each character
may not be its own element in the vector. If that is so, you would
need to do somethi
On Apr 22, 2010, at 10:34 AM, Ted Harding wrote:
> On 22-Apr-10 15:19:45, Barry Rowlingson wrote:
>> On Thu, Apr 22, 2010 at 3:27 PM, peter dalgaard
>> wrote:
>>> ...that this Danish movie would have an official release today:
>>>
>>> http://www.imdb.com/title/tt1434443/
>>
>> Does it have musi
On 2010-04-22 11:09, Muhammad Rahiz wrote:
Hello everyone,
I'm trying to draw the non-linear regression curve to look at the
distance decay relationship between distance and correlation values. But
I'm not able to plot the curve as I'm struggling with the following
error ("parameters without sta
Hi
how can I find, in a vector of characters, which is the most frequent one?
Thanks
Gabriele Zoppoli, MD
Ph.D. Fellow, Experimental and Clinical Oncology and Hematology, University of
Genova, Genova, Italy
Guest Researcher, LMP, NCI, NIH, Bethesda MD
Work: 301-451-8575
Mobile: 301-204-5642
Em
Hi Uwe,
I downloaded R 2.11.0 and the latest version of nlme. I am still getting the
problem. I should also note that I got a message from Viechtbauer Wolfgang
saying that he had experienced a similar problem using nlme.
I have pasted the code below. (The data is generated in the first ~15
lines)
On Apr 22, 2010, at 12:24 PM, Steve Lianoglou wrote:
Hi,
On Thu, Apr 22, 2010 at 12:08 PM, karena wrote:
I need to create 10 matrices. say matrix 1-10.
matrix_1 is 1 by 1
matrix_2 is 2 by 2
matrix_3 is 3 by 3
.
.
.
matrix_10 is 10 by 10
I am just wondering if there are some function
Hello everyone,
I'm trying to draw the non-linear regression curve to look at the
distance decay relationship between distance and correlation values. But
I'm not able to plot the curve as I'm struggling with the following
error ("parameters without starting value in 'data': x") and found no
I'd like to have an online horizon=k forecast with Arima, something like:
library(forecast)
air.model = Arima(AirPassengers[0:100], c(1,0,1),
seasonal=list(order=c(0,1,1), period=12))
for(i in 0:(length(AirPassengers)-100)) {
air.model2 = Arima(AirPassengers[0:(100+i)], model=air.model)
You did not give a good description of your problem, or what you wanted as a
solution (what is a 'button'), or a reasonable idea of what you data is.
Here is one solution
x <- read.table(textConnection("Deafness, EYA4, DIAPH1, MYO7A, TECTA,
COL11A2, POU4F3, MYH9, ACTG1, MYO6"),
as.is=TRUE, se
Hi,
On Thu, Apr 22, 2010 at 12:08 PM, karena wrote:
>
> I need to create 10 matrices. say matrix 1-10.
>
> matrix_1 is 1 by 1
> matrix_2 is 2 by 2
> matrix_3 is 3 by 3
> .
> .
> .
> matrix_10 is 10 by 10
>
> I am just wondering if there are some functions in R that are similar to the
> macr
maybe
for (i in 1:10) assign(paste("matrix", i, sep="_"), matrix(nrow=i, ncol=i))
suffices?
On Thu, Apr 22, 2010 at 5:08 PM, karena wrote:
>
> I need to create 10 matrices. say matrix 1-10.
>
> matrix_1 is 1 by 1
> matrix_2 is 2 by 2
> matrix_3 is 3 by 3
> .
> .
> .
> matrix_10 is 10 by 1
Why don't use a list?
m <- list()
for(i in 1:10) {
m[[i]] <- matrix(NA, i, i)
}
then access them as m[[7]][1,6]
Ciao!
mario
On 22-Apr-10 18:08, karena wrote:
I need to create 10 matrices. say matrix 1-10.
matrix_1 is 1 by 1
matrix_2 is 2 by 2
matrix_3 is 3 by 3
.
.
Dear R-users, the problem I'm facing today is to write a
multicolor main title in a plot.
I would like to have 3/4 colors to help people in the
audience to visually realize what is what in a 4x2 plot array
On top of each plot I would like to have two lines.
The 1st line will indicate what is plo
I need to create 10 matrices. say matrix 1-10.
matrix_1 is 1 by 1
matrix_2 is 2 by 2
matrix_3 is 3 by 3
.
.
.
matrix_10 is 10 by 10
I am just wondering if there are some functions in R that are similar to the
macro variables in SAS. so I can create these 10 matrices by doing:
for (i in
On Apr 22, 2010, at 11:21 AM, Muhammad Rahiz wrote:
Hi all,
I would like to get the array index for a range of values, say 0 <
x < 1.5. I'm wondering if there is an alternative for the following
which I've done
x0 <- rnorm(100)
x1 <- ifelse(x0 > 0 & x0 < 1.5,"t","f")
x2 <- which(x1=="t"
On Apr 22, 2010, at 11:39 AM, Steve Lianoglou wrote:
Hi,
On Thu, Apr 22, 2010 at 11:21 AM, Muhammad Rahiz
wrote:
Hi all,
I would like to get the array index for a range of values, say 0 <
x < 1.5.
I'm wondering if there is an alternative for the following which
I've done
x0 <- rnorm(
Hi,
On Thu, Apr 22, 2010 at 11:21 AM, Muhammad Rahiz
wrote:
> Hi all,
>
> I would like to get the array index for a range of values, say 0 < x < 1.5.
> I'm wondering if there is an alternative for the following which I've done
>
> x0 <- rnorm(100)
> x1 <- ifelse(x0 > 0 & x0 < 1.5,"t","f")
> x2 <
On 22-Apr-10 15:19:45, Barry Rowlingson wrote:
> On Thu, Apr 22, 2010 at 3:27 PM, peter dalgaard
> wrote:
>> ...that this Danish movie would have an official release today:
>>
>> http://www.imdb.com/title/tt1434443/
>
> Does it have music by this composer:
>
> http://www.imdb.com/name/nm1731203
Only thing that when I put na.rm=FALSE,
R is puting in v4 NA (as is largest)
and I want to see NA as zero (0, smallest value)
2010/4/22 Vlatka Matkovic Puljic
> Thanx a lot! That's it!
>
> 2010/4/22 Duncan Murdoch
>
> On 22/04/2010 11:07 AM, Vlatka Matkovic Puljic wrote:
>>
>>> Hi!
>>>
>>> I h
Hi all,
I would like to get the array index for a range of values, say 0 < x <
1.5. I'm wondering if there is an alternative for the following which
I've done
x0 <- rnorm(100)
x1 <- ifelse(x0 > 0 & x0 < 1.5,"t","f")
x2 <- which(x1=="t",arr.ind=TRUE)
x0[x2]
Thanks.
--
Muhammad
___
Thanx a lot! That's it!
2010/4/22 Duncan Murdoch
> On 22/04/2010 11:07 AM, Vlatka Matkovic Puljic wrote:
>
>> Hi!
>>
>> I have v1, v2 and v3 (data in v. ranges 1 to 4)
>>
>> v1
>> [1] 1 1 1 1 NaN 1 1 4 1 1 3
>> v2
>> [1] 1 1 1 1 1 1 1 1 1 1 1
>> v3
>
On Thu, Apr 22, 2010 at 3:27 PM, peter dalgaard wrote:
> ...that this Danish movie would have an official release today:
>
> http://www.imdb.com/title/tt1434443/
Does it have music by this composer:
http://www.imdb.com/name/nm1731203/
and stills photography by:
http://www.imdb.com/name/nm208
Hi
I'm looking for a package to perform quality control, normalization and
analysis of high throughput cell-base chemical screens. I know that the
cellHTS2 package provides this for siRNA screens.
Does anybody know if something like what I'm looking for exists?
Thank you!
Gabriele Zoppoli,
On 22/04/2010 11:07 AM, Vlatka Matkovic Puljic wrote:
Hi!
I have v1, v2 and v3 (data in v. ranges 1 to 4)
v1
[1] 1 1 1 1 NaN 1 1 4 1 1 3
v2
[1] 1 1 1 1 1 1 1 1 1 1 1
v3
[1] 1 1 1 1 1 1 1 1 1 1 1
I want R to compare entrie
Hi!
I have v1, v2 and v3 (data in v. ranges 1 to 4)
v1
[1] 1 1 1 1 NaN 1 1 4 1 1 3
v2
[1] 1 1 1 1 1 1 1 1 1 1 1
v3
[1] 1 1 1 1 1 1 1 1 1 1 1
I want R to compare entries in v1,v2,v3 and in v4 to put largest value
(NA=0).
For
...that this Danish movie would have an official release today:
http://www.imdb.com/title/tt1434443/
http://filmz.dk/film/r/trailers/24836
--
Peter Dalgaard
Center for Statistics, Copenhagen Business School
Solbjerg Plads 3, 2000 Frederiksberg, Denmark
Phone: (+45)38153501
Email: pd@cbs.dk
Thanks a lot for the help, but it’s not what I needed.
--
View this message in context:
http://r.789695.n4.nabble.com/R-loop-tp1979620p2020386.html
Sent from the R help mailing list archive at Nabble.com.
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R-help@r-project.org mailing list
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I am unfamiliar with how to use coin, but it looks like it should be doable -
the vignette in coin.pdf does a Page test. The wikipedia page for Page's
test explains how this is related to the Jonckheere-Terpstra test, which
seems to suggest if it can do one it should be able to do the other. Add t
Hi Kate,
the function does not directly return the calculated density values, however
those can be recomputed through the internal function .smoothScatterCalcDensity
This function is not exported from the grDevices name space, so you need to use
the full qualifier:
dat <- cbind(rnorm(100), rnorm
On 22/04/2010 8:09 AM, carol white wrote:
Hi,
Is an R package built under Unix (package.tar.gz) could be installed on other
platforms like windows or Mac? The compressed tar file (.tar.gz) built under
Unix doesn't seem to be uncompressed under windows (unzip under windows instead
of gunzip). H
On 22.04.2010 15:34, David Winsemius wrote:
On Apr 22, 2010, at 8:09 AM, carol white wrote:
Hi,
Is an R package built under Unix (package.tar.gz) could be installed
on other platforms like windows or Mac? The compressed tar file
(.tar.gz) built under Unix doesn't seem to be uncompressed unde
On Apr 22, 2010, at 9:41 AM, Doran, Harold wrote:
I wonder if there is a more efficient way to do this task. Suppose I
have two data frames, such as
d1 <- data.frame(x = c(1,2,3), y = c(4,5,6), z = c(7,8,9))
d2 <- d1[, c('y', 'x')]
The first dataframe d1 has more variables than d2 and the
Hi,
This idea was also discussed when Paul Murrell first announced the
grid.raster function to R-devel,
http://tolstoy.newcastle.edu.au/R/e8/devel/09/12/0912.html
My personal conclusion was that vector fill patterns are generally
better in terms of resolution and speed. Of course the situation mi
Jun,
I created a function called "pageNum" that does exactly what you want for
both 'base' and 'lattice' graphics. You can find it here:
http://ryouready.wordpress.com/2009/02/17/r-good-practice-adding-footnotes-to-graphics/
Kevin
On Wed, Apr 21, 2010 at 7:23 PM, Jun Shen wrote:
> David, Dun
I wonder if there is a more efficient way to do this task. Suppose I have two
data frames, such as
d1 <- data.frame(x = c(1,2,3), y = c(4,5,6), z = c(7,8,9))
d2 <- d1[, c('y', 'x')]
The first dataframe d1 has more variables than d2 and the variable columns are
in a different order.
So, what I
On Apr 22, 2010, at 5:33 AM, Simon Goodman wrote:
Thanks for the suggestions Unfortunately contour won't in this
case as it
expects the x,y values to be in an ascending sequence.
?order
David Winsemius, MD
West Hartford, CT
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R-help@r
On Apr 22, 2010, at 8:09 AM, carol white wrote:
Hi,
Is an R package built under Unix (package.tar.gz) could be installed
on other platforms like windows or Mac? The compressed tar file
(.tar.gz) built under Unix doesn't seem to be uncompressed under
windows (unzip under windows instead of
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