And here is one more SQL solution. This one uses the window functions
in PostgreSQL and is slightly more compact and even closer to the pure
R version in our prior post. We quote Count so its not regarded as
the reserved word of the same name. Note that if RpgSQL is loaded then
sqldf will automati
Try this ave solution noting that summing Count * (stain == "none")
over each group gives the Count in its stain=="none" row and ave
causes that Count value to be repeated for every row of the group so
we get a vector that can be subtracted from Count:
transform(DF, calib = Count - ave(Count * (st
On Mar 12, 2010, at 5:27 PM, Sam Albers wrote:
Hello all,
I have not been able to find an answer to this problem. I feel like
it might
be so simple though that it might not get a response.
Suppose I have a dataframe like the one I have copied below (minus the
'calib' column). I wish to cre
Hi:
Here's a ddply solution to your problem (package plyr):
library(plyr)
# within group function to apply; assumes that 'none' is first obs in group
# x will be the Count variable in the call...
subt2 <- function(x) x - x[1]
head(df)
rep Count stain
11 1522.0none
21 147.0
Consider using the indices instead of the matrices themselves. You can pass
a list of indices and then reference the two matrices any way you want to
compute the return value.
On Fri, Mar 12, 2010 at 6:49 AM, Michal Szewczyk wrote:
>
> Hello,
>
> I am struggling to overcome following problem:
>
Try this
# set up test data
# BOD1 and BOD2 are same as built in BOD
BOD1 <- BOD2 <- BOD
env <- .GlobalEnv
object.names <- objects(pattern = "BOD", env)
# change col names of BOD1 to A & B. Ditto for BOD2.
for(nm in object.names) names(env[[nm]]) <- c("A", "B")
On Thu, Mar 11, 2010 at 7:33 AM,
Everyone is being too complicated.
c( A[1,2] , A[3,3] )
will do what you ask.
A <- matrix(seq(1,9),nrow=3)
c( A[1,2] , A[3,3] )
[1] 4 9
But I would assume you have some more general
problem in mind, and I do not know if this simple
approach will meet those needs.
-Don
At 3:26 PM
Hi, I am trying to use F test or Chi-square test to test if 2 5-parameter (A,
B, xmid, scal and H) logistic curves are parallel based on residual sum of
squares.
What's usually done is to first fit the 2 curves using a constraint (or global)
model where all parameters are kept the same except f
Thanks to all for the replies. I'll post back here when I get things
working (...in a couple of days).
Nikos
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https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/post
On Mar 12, 2010, at 5:29 PM, Kindra Martinenko wrote:
Hi all,
I have the following 7 x 7 matrix. I am trying to figure out how to
label the columns to something more descriptive other than [,1], [,2],
etc.
I have tried the c(x,y,z,) function, but I get a error returned
stating that my vectors
Hello,
On Fri, Mar 12, 2010 at 3:27 PM, Sam Albers wrote:
> Hello all,
>
> I have not been able to find an answer to this problem. I feel like it
> might
> be so simple though that it might not get a response.
>
> Suppose I have a dataframe like the one I have copied below (minus the
> 'calib' co
Dear Kindra,
I think you are talking about...
matrix(1:9, nrow=3, dimnames=list(NULL, c("First","Second","Third")))
First Second Third
[1,] 1 4 7
[2,] 2 5 8
[3,] 3 6 9
If I am correct, what you are missing is that "dimnames" requires a
list with two e
Hello,
I'm trying to use StatEt on my kubuntu karmic system. I've set
everything up according to the website and a guide pdf I've got, but
when I start the R session, or issue a command, I get a "An internal
error occurred during: "R Object Browser Update"." error;
Any ideas on what to look
On 12-Mar-10 22:29:07, Kindra Martinenko wrote:
> Hi all,
> I have the following 7 x 7 matrix. _I am trying to figure out
> how to label the columns to something more descriptive other
> than [,1], [,2], etc.
> I have tried the c(x,y,z,) function, but I get a error returned
> stating that my vector
On 12-Mar-10 19:41:22, Ali Tofigh wrote:
> On Fri, Mar 12, 2010 at 14:27, Ted Harding
> wrote:
>> However, all that was a long time ago. Check 'page' in your
>> newer R!
>
> Thanks for the tip. But I don't understand what page is supposed to
> do. For example,
>
> page(1:3)
>
> simply displays
Here you go:
require(BB)
fn <- function(x, s){
f <- rep(NA, length(x))
f[1] <- digamma(x[1]) - digamma(x[1]+x[2]) - s[1]
f[2] <- digamma(x[2]) - digamma(x[1]+x[2]) - s[2]
f
}
nr <- 10
smat <- matrix(runif(2*nr, -3, -1), nr, 2)
soln <- matrix(NA, nr, 2)
for (i in 1:nr) {
ans <- dfsane(
Hi all,
I have the following 7 x 7 matrix. I am trying to figure out how to
label the columns to something more descriptive other than [,1], [,2],
etc.
I have tried the c(x,y,z,) function, but I get a error returned
stating that my vectors need to be the same length. Do I need to
convert this to
Hello all,
I have not been able to find an answer to this problem. I feel like it might
be so simple though that it might not get a response.
Suppose I have a dataframe like the one I have copied below (minus the
'calib' column). I wish to create a column like calib where I am subtracting
the 'Co
On Fri, Mar 12, 2010 at 9:52 PM, Bob Green wrote:
>
> I have to create a plot with a print density of 600 dpi . Within R, is there
> a way to determine the print density of a plot?
>
> Any assistance is much appreciated,
A PostScript, embedded PostScript, or PDF file has essentially
infinite dpi
Thank you Dennis, I've got the idea now.
However, a followup question to make sure I'm not wasting my time.
If I specify the precise CV folds to use, should I not get the same
tree every time?
e.g. here I have an hypothetical time sequence observed with error
from 3 sites 's'
If I specify to l
I have to create a plot with a print density of 600 dpi . Within R,
is there a way to determine the print density of a plot?
Any assistance is much appreciated,
regards
Bob
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apjawor...@mmm.com wrote:
Thanks for the quick reply.
No, I did not run into any problems so far. I have been using the PLS
package and the modelling functions seem to work just fine.
In fact, even if I let the data.frame convert the x matrix to separate
column, the "y ~ x" modeling syntax
On Mar 12, 2010, at 4:14 PM, paaventhan jeyaganth wrote:
Dear all,
how can i get rid of the text in the calibration plot below the x-
axis.
http://en.wikipedia.org/wiki/Correction_fluid
David Winsemius, MD
West Hartford, CT
__
R-help@r-pro
On Fri, Mar 12, 2010 at 7:06 PM, Nilza BARROS wrote:
> It would be a form that is filled daily, but some fields were tabulated and
> other fields would be filled with only the opinions of users.
>
> Currently, my form is a Word document that is the filling and printed. At
> the end of every month
Dear all,
how can i get rid of the text in the calibration plot below the x-axis.
thanks
Paaveen
_
Check your Hotmail from your phone.
[[alternative HTML version deleted]]
Here is a suggestion:
tapply(mat[,2], as.factor(m[,1]), sum)
Cheers,
/Ali
On Fri, Mar 12, 2010 at 15:28, Juliet Ndukum wrote:
> mat is a matrix with X and Y values.
>> mat
> X Y
> [1,] 56 20
> [2,] 56 21
> [3,] 2 50
> [4,] 3 46
> [5,] 18 77
> [6,] 57 12
> [7,] 57 36
> [8,] 95 4
Hi Juliet,
Here are two options:
with(mat, aggregate(Y, list(X), sum))
with(mat, tapply(Y, list(X), sum))
See ?aggregate and ?tapply for more information.
HTH,
Jorge
On Fri, Mar 12, 2010 at 3:28 PM, Juliet Ndukum <> wrote:
> mat is a matrix with X and Y values.
> > mat
> X Y
> [1,] 56
Hello, I am trying to modify some functions in an existing package. I can get a
function by just typing the name in the console, but how can I get all the
functions in a package? the ./R/ subdirectory has files xx.rdb and xx.rdx which
I can not decompress with 7-zip or with unzip, unrar etc. The
I would just get row indices:
row.indices <- as.vector(sapply(0:25 * 5 + 1, function(x)
{sort(sample(x:(x+4), 2))}))
new.data.fram <- your.data.frame[row.indices, ]
Cheers,
/Ali
On Fri, Mar 12, 2010 at 15:06, Hosack, Michael wrote:
> Fellow R users,
>
> I am stumped on what would seem to be som
mat is a matrix with X and Y values.
> mat
X Y
[1,] 56 20
[2,] 56 21
[3,] 2 50
[4,] 3 46
[5,] 18 77
[6,] 57 12
[7,] 57 36
[8,] 95 45
[9,] 65 23
[10,] 33 25
[11,] 33 98
[12,] 63 96
[13,] 66 75
[14,] 99 54
[15,] 78 65
[16,] 75 69
[17,] 54 68
[18,] 54 67
[19,] 0 22
[20,] 14 74
[21
On 3/12/2010 3:06 PM, Hosack, Michael wrote:
> Fellow R users,
>
> I am stumped on what would seem to be something fairly simple.
> I have a dataframe that has a variable named 'WEEK' that takes
> the numbers 1:26 (26 week time-period) with each number repeated
> five times consecutively (once
Hi:
A ddply solution:
library(plyr)
somedata = data.frame(week=rep(1:26,rep(5,26)),day=rep(1:5,26))
# sample two rows out of five per week
daysamp <- function(x) x[sample(1:5, 2), ]
# Ram it through ddply:
ddply(somedata, .(week), daysamp)
First part of output:
week day
1 1 4
2 1
Hi Mike,
take an index vector that selects Monday and Tuesday out of each week,
and then run a restricted random permutation on this vector which only
permutes indices within each week. rperm() is in the sna package.
library(sna)
foo <- rep(c(TRUE,TRUE,FALSE,FALSE,FALSE),26)
your.data[foo[rpe
On Mar 12, 2010, at 3:06 PM, Hosack, Michael wrote:
Fellow R users,
I am stumped on what would seem to be something fairly simple.
I have a dataframe that has a variable named 'WEEK' that takes
the numbers 1:26 (26 week time-period) with each number repeated
five times consecutively (once for
Mike -
Perhaps these suggestions will be helpful:
somedata = data.frame(week=rep(1:26,rep(5,26)),day=rep(1:5,26))
res = by(somedata,somedata$week,function(x)x[sample(1:nrow(x),2),])
do.call(rbind,res)
or
do.call(rbind,lapply(split(somedata,somedata$week),
function(x)x[sample(
Andy,
Did you run into any kind of trouble?
I'm asking because I'm maintaining a package for spectroscopic data that heavily
uses "I (spectra.matrix)" ...
However, once you have the matrix safe inside the data.frame, you can delete the
"AsIs":
> a <- matrix (1:9, 3)
> str (a)
int [1:3, 1:
Fellow R users,
I am stumped on what would seem to be something fairly simple.
I have a dataframe that has a variable named 'WEEK' that takes
the numbers 1:26 (26 week time-period) with each number repeated
five times consecutively (once for each weekday, Monday through
Friday). Ex. 12
Hi,
I have the following question about creating data frames. I want to
create a data frame with 2 components: a vector and a matrix.
Let me use a simple example:
y <- rnorm(10)
x <- matrix(rnorm(150), nrow=10)
Now if I do
dd <- data.frame(x=x, y=y)
I get a data frame with 16 colums, but if
On Mar 12, 2010, at 2:15 PM, Natalie Van Zuydam wrote:
Hi,
I did quote the string and as I told read.table to strip.white I
also tried
it with no spaces.
"ASPIRIN DISP AAH" %in% tsf_data$name
[1] FALSE
"ASPIRINDISPAAH" %in% tsf_data$name
[1] FALSE
I have looked at the last lines of my y_d
On Fri, Mar 12, 2010 at 14:27, Ted Harding wrote:
> However, all that was a long time ago. Check 'page' in your
> newer R!
Thanks for the tip. But I don't understand what page is supposed to
do. For example,
page(1:3)
simply displays the text string "1:3" in less. And if I do
x <- 1:3
page(x)
On Mar 12, 2010, at 2:31 PM, David Winsemius wrote:
On Mar 12, 2010, at 9:26 AM, Nils Rüfenacht wrote:
Dear all!
I'm trying to get multiple values from a matrix by using a single
command.
Given a matrix A
A <- matrix(seq(1,9),nrow=3,ncol=3)
How can I get e.g. the values A[1,2] = 4 and
On Mar 12, 2010, at 9:26 AM, Nils Rüfenacht wrote:
Dear all!
I'm trying to get multiple values from a matrix by using a single
command.
Given a matrix A
A <- matrix(seq(1,9),nrow=3,ncol=3)
How can I get e.g. the values A[1,2] = 4 and A[3,3] = 9 with a
single command and without using a
Another approach may be useful. Back in May 2003 I raised a
similar query: How to divert R output into a separate X window
(in Linux) where it would apear after being piped through 'less'.
This has the advantage that, if you choose to do it this way,
it leaves your R console untouched. I raised the
I'm considering going back to that version (or switching to Eclipse)
because the newer Tinn-R version requires pacakges Tinn-r and Hmisc and
something is aliasing functions in xtable which blows up my Sweave
runs. For the time being I'm using cut-paste.
On 3/12/2010 10:41 AM, jim holtman wrot
Sounds like a job for sweave or perhaps one of the packages brew or
odfWeave. See also the xtable package, perhaps. You would then be able to:
-- read the latest data file
-- have R produce all tabular summaries, analyses, plots
-- output all the results in a nicely formatted template (report)
wi
Hi,
I did quote the string and as I told read.table to strip.white I also tried
it with no spaces.
"ASPIRIN DISP AAH" %in% tsf_data$name
[1] FALSE
"ASPIRINDISPAAH" %in% tsf_data$name
[1] FALSE
I have looked at the last lines of my y_data object and there is a problem
with the file that I'm goin
I think you can use package animation. See http://animation.yihui.name/
.
HTH,
David L. Reiner
-Original Message-
From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org]
On Behalf Of Flana
Sent: Friday, March 12, 2010 12:14 PM
To: r-help@r-project.org
Subject: [R] Exportin
It would be a form that is filled daily, but some fields were tabulated and
other fields would be filled with only the opinions of users.
Currently, my form is a Word document that is the filling and printed. At
the end of every month they are analyzed and the reasons for delays are
tabulated and
Try this:
diag(A[c(1,3),c(2,3)])
2010/3/12 Nils Rüfenacht :
> Dear all!
>
> I'm trying to get multiple values from a matrix by using a single command.
>
> Given a matrix A
>
> A <- matrix(seq(1,9),nrow=3,ncol=3)
>
> How can I get e.g. the values A[1,2] = 4 and A[3,3] = 9 with a single
> command
842752|ASPIRIN DISP AAH|TABS|75MG|2.9 is taken directly from my y_data text
file.
If I search for ASPIRIN DISP AAH %in% y$name I get: FALSE. Despite the
fact that it is there in the text file that I loaded into y. There must be a
problem with my input.
tsf_data <- read.table("feb09_267_presc_i
use a matrix of n x 2 to index. For details: sec. 5.3 "Index matrices" in the
introduction.
HTH Claudia
Nils Rüfenacht wrote:
Dear all!
I'm trying to get multiple values from a matrix by using a single command.
Given a matrix A
A <- matrix(seq(1,9),nrow=3,ncol=3)
How can I get e.g. the val
Hi All,
Thank you in advance for your help.
I made an agent-based model in R and I plot it using image() each
timestep creating a nice animation. I can't seem to find in any of the
R codes a means to export the series of images so that they can be
played as a movie or animation.
Thank you again.
Dear all,
I have the following problem:
I have been using the routine "optim" in order to maximize a joint
likelihood (basically a mixture with modeled weights) with quantitative
variables..so far so good.
Now I need to plug into the model a categorical variable (namely, age
classes).
Obviousl
Hello,
I am struggling to overcome following problem:
I have matrix Vf and matrix V, which both have 3 columns and I want to
create a spline function basing on coordinates from this matrices (more
precisely coordinates of function nr 1: x are taken from Vf[,1] and y are
taken from V[,1] respecti
Dear all!
I'm trying to get multiple values from a matrix by using a single
command.
Given a matrix A
A <- matrix(seq(1,9),nrow=3,ncol=3)
How can I get e.g. the values A[1,2] = 4 and A[3,3] = 9 with a single
command and without using any loop? My first idea was to generate a
row- and a
These are some of the reasons I have stuck with version 1.19.4.7 of Tinn-R;
it still works fine.
On Fri, Mar 12, 2010 at 10:09 AM, stephen's mailinglist account <
stephen4mailingli...@googlemail.com> wrote:
> On 12 March 2010 14:27, teck-corp wrote:
> >
> > Hi Stephen,
> >
> > Thanks a lot for y
On Wed, Mar 10, 2010 at 12:08:52AM -0800, hvollmeier wrote:
>
> James,
>
> you may post your question to the R-SIG finance group with a small example.
> If I understand your problem correctly it's like converting tick data of
> financial time series into aggregates. (to 1-minute, hourly, daily
Hi Henrique,
Great.
I tried a similar thing but used
list( replicate(6, list(para1 = 1:5, para2 = 5:9), simplify = FALSE) )
and didn't work. Seems I don't need list(...).
Thanks.
Zhongyi
On Fri, Mar 12, 2010 at 11:56 AM, Henrique Dallazuanna wrote:
> You can do this also, using replicate:
>
>
That is not so. 842752 does not exist in y$item_code and ASPIRIN has
a code of 22730.
> 842752 %in% y$item_code
[1] FALSE
> subset(y, name == "ASPIRIN")
item_codename formulation_code strength bnf_code
850 22730 ASPIRIN TABS300MG4.7.1
855 22780 ASPIRIN
You can do this also, using replicate:
replicate(6, list(para1 = 1:5, para2 = 5:9), simplify = FALSE)
On Fri, Mar 12, 2010 at 2:51 PM, Zhongyi Yuan wrote:
> Hi Jim,
>
> Dennis Murphy solved my problem by the following code.
> Thank you for you suggestion. Will check out listBuilder function too.
-- Forwarded message --
From: Natalie Van Zuydam
Date: Fri, Mar 12, 2010 at 5:49 PM
Subject: Re: [R] sqldf not joining all the fields
To: David Winsemius
Dear David
I'm not sure what the problem is as for every item code there is a
corresponding information in the y_data. For
Hi Jim,
Dennis Murphy solved my problem by the following code.
Thank you for you suggestion. Will check out listBuilder function too.
best,
Zhongyi
# (2) A little more general: prespecify the number of list components
# and run a one-line loop to populate the list
> l <- vector('list', 6)
>
After using pipe() to view output in less, the pipe becomes invalid:
$ p <- pipe("less")
$ capture.output(1:100, file=p)
$ p
Error in summary.connection(x) : invalid connection
$ close(p)
Error in close.connection(p) : invalid connection
Is this a bug? Other uses of pipe works differently:
$ p <
If I assign the file input to y_data and change you sqldf to
> z <- sqldf("select * from x_data left join y_data using
(item_code)"); z
I can replicate your result. Even after changing the types of the two
item_code fields to match I still get the same result and when I see
to what degre
On 12-03-2010, at 13:25, PtitBleu wrote:
>
> Hello,
>
> I'm looking for a R-package to solve such an equation :
>
> http://n4.nabble.com/file/n1590462/iv.png
>
> which is one current-voltage equation of a solar cell.
?uniroot
Berend
__
R-help@
Sorry! It is the end of the day for me.
So
dput(x)
structure(list(prochi = c("CAO713", "CAO713", "CAO713",
"CAO713", "CAO713", "CAO713", "CAO713", "CAO713",
"CAO713", "CAO713"), prescribed_date = c("22/06/2001",
"28/04/2000", "10/04/2000", "03/07/2000", "
Yes, its not clear what data was used. Please provide a single email
that contains code that can be copied from R and pasted into another
session that will reproduce the problem.
x_data <- ...dput output goes here...
y_data <- dput output goes here ...
library(sqldf)
... rest of code ...
or else
Sorry! It is the end of the day for me.
So
dput(x)
structure(list(prochi = c("CAO713", "CAO713", "CAO713",
"CAO713", "CAO713", "CAO713", "CAO713", "CAO713",
"CAO713", "CAO713"), prescribed_date = c("22/06/2001",
"28/04/2000", "10/04/2000", "03/07/200
For programming you should start with "Writing R Extensions" (just scan the
sections that don't apply to you yet). I would also recommend "S poetry" by
Patrick Burns (http://www.burns-stat.com/) and "S Programming" by Venables and
Ripley.
--
Gregory (Greg) L. Snow Ph.D.
Statistical Data Cente
You have now given two different assignments to x_data and none to
y_data:
The str( from the file access offering:
> str(x_data)
'data.frame': 2848 obs. of 5 variables:
$ item_code : int 100 110 150 160 161 164 200 210 212 220 ...
$ name: chr "NEONACLEX K" "NEONACLEX"
The y_data file has over 9000 rows in it so I thought it would be more
practical to give you the file to download
--
View this message in context:
http://n4.nabble.com/sqldf-not-joining-all-the-fields-tp1590786p1590833.html
Sent from the R help mailing list archive at Nabble.com.
__
What about y_data?
On Fri, Mar 12, 2010 at 12:14 PM, Newbie19_02 wrote:
>
> dput(x_data)
>
> structure(list(prochi = c("CAO713", "CAO713", "CAO713",
> "CAO713", "CAO713", "CAO713", "CAO713", "CAO713",
> "CAO713", "CAO713"), prescribed_date = c("22/06/2001"
Please provide code that I can just copy from your post and paste into
my session. Either provide dput output as requested or provide the
files on the internet together with code that reads them off the
internet.
On Fri, Mar 12, 2010 at 12:06 PM, Newbie19_02 wrote:
>
> http://n4.nabble.com/file
y_data <- read.table("feb_267_presc_items_tsf.txt", header = TRUE, sep = "|",
quote = "\"'",
dec = ".",as.is = TRUE,na.strings = "NA",colClasses = NA,
nrows = 3864284,
skip = 0, check.names = TRUE,fill=TRUE,
strip.white = TRUE, blank.lines.skip = TRU
dput(x_data)
structure(list(prochi = c("CAO713", "CAO713", "CAO713",
"CAO713", "CAO713", "CAO713", "CAO713", "CAO713",
"CAO713", "CAO713"), prescribed_date = c("22/06/2001",
"28/04/2000", "10/04/2000", "03/07/2000", "09/01/2001", "16/10/2001",
"16/08/20
http://n4.nabble.com/file/n1590804/feb09_267_presc_items_tsf.txt
feb09_267_presc_items_tsf.txt
is the total file for y so if I use the command line with the total data for
y then I get the output specified in z
Thanks,
Natalie
--
View this message in context:
http://n4.nabble.com/sqldf-not-jo
Try the View command.
On Fri, Mar 12, 2010 at 11:15 AM, Ali Tofigh wrote:
> I'm using R under Linux. Since the help function in R can use the
> program less to display text, I'd like to know if it is possible for a
> user to do the same. It would be very helpful to be able to view large
> objects
Can you show the output of dput(x_data) and dput(y_data).
On Fri, Mar 12, 2010 at 11:56 AM, Newbie19_02 wrote:
>
> Dear R users,
>
> I have two data frames that were read from text files as follows:
>
> x_data <- read.table("x.txt", header = TRUE, sep = "|", quote = "\"'",
> dec =
Is this what you want?
> pairs(iris[,-5], lower.panel=NULL)
Also look at the pairs2 function in the TeachingDemos package for a way to plot
one set of variables against another set.
--
Gregory (Greg) L. Snow Ph.D.
Statistical Data Center
Intermountain Healthcare
greg.s...@imail.org
801.408.811
Dear R users,
I have two data frames that were read from text files as follows:
x_data <- read.table("x.txt", header = TRUE, sep = "|", quote = "\"'",
dec = ".",as.is = TRUE,na.strings = "NA",colClasses = NA,
nrows = 3864284,
skip = 0, check.names = TRUE,fill=TRUE
I am not seeing an immediately evident way of doing that.
Bear in mind that pairs() is essentially a wrapper to automate the process of
using par(mfrow = c(rows, columns)) and setting other graphical parameters such
as margins, which sets up the grid of individual plots within the overall
graph
On Wed, Mar 10, 2010 at 6:13 PM, baptiste auguie
wrote:
> not with the theme, as far as I know, but you can do:
>
> set_default_scale("fill", "discrete","grey")
Can I set default shape in similar way? I tried this:
set_default_scale("shape", "discrete", 19)
Error in get(paste("Scale", firstUpper
On Fri, Mar 12, 2010 at 11:18, David Winsemius wrote:
>
> On Mar 12, 2010, at 11:15 AM, Ali Tofigh wrote:
>
>> I'm using R under Linux. Since the help function in R can use the
>> program less to display text, I'd like to know if it is possible for a
>> user to do the same. It would be very helpfu
That works, thanks. In addition, is there a way to specify the color and
symbol for some of the figures in the panel, but not all of them? Seems that
the color and symbol arguments apply to all the figures in the panel.
Thanks,
-Jack
On Fri, Mar 12, 2010 at 11:16 AM, Marc Schwartz wrote:
> On M
On Mar 12, 2010, at 11:15 AM, Ali Tofigh wrote:
I'm using R under Linux. Since the help function in R can use the
program less to display text, I'd like to know if it is possible for a
user to do the same. It would be very helpful to be able to view large
objects (matrices/dataframes etc) using
?optim
RSiteSearch("nonlinear equation solver")
CRAN task view (optimization)
Do a little work for your own before asking other to work for you.
mario
On 12-Mar-10 13:25, PtitBleu wrote:
Hello,
I'm looking for a R-package to solve such an equation :
http://n4.nabble.com/file/
On Mar 12, 2010, at 10:09 AM, Jack Luo wrote:
> Hi,
>
> I am trying to use function pairs to plot the scatterplot, but I only want
> to keep the upper triangle, what's the argument to do this?
>
> Thanks,
>
> -Jack
Try setting the 'lower.panel' argument to NULL.
Compare:
pairs(USJudgeRatin
Hi,
On Fri, Mar 12, 2010 at 11:09 AM, Jack Luo wrote:
> Hi,
>
> I am trying to use function pairs to plot the scatterplot, but I only want
> to keep the upper triangle, what's the argument to do this?
I don't really understand what you're trying to ask, but does
upper.tri function help?
R> ?upp
A new resource along these lines is:
"Some hints for the R beginner"
http://www.burns-stat.com/pages/Tutor/hints_R_begin.html
If you have ideas on how to improve on it,
please let me know.
Pat
On 12/03/2010 09:41, ManInMoon wrote:
Hi,
A number of people have suggested "I read the manuals"..
I'm using R under Linux. Since the help function in R can use the
program less to display text, I'd like to know if it is possible for a
user to do the same. It would be very helpful to be able to view large
objects (matrices/dataframes etc) using less. This is preferable to
redirecting output to f
Hi,
I am trying to use function pairs to plot the scatterplot, but I only want
to keep the upper triangle, what's the argument to do this?
Thanks,
-Jack
[[alternative HTML version deleted]]
__
R-help@r-project.org mailing list
https://stat.et
Many people seem to have trouble defining '.trPaths' which is the set of
file names which TinnR uses to communicate with R; the user must be able to
create/write/read these files/folders.
In my Rprofile.site I have the single assingment:
.trPaths <- paste(paste(Sys.getenv("APPDATA"), "\\Tinn-R\\
On 12 March 2010 14:27, teck-corp wrote:
>
> Hi Stephen,
>
> Thanks a lot for your answer. Unfortunately this does not work for me
> neither.
> Could you maybe let me know what is written in you RprofileSite-file now?
>
> Best
> Dennis
> --
> View this message in context:
> http://n4.nabble.com/E
Dieter:
I had considered creating a special class, but you are right that it
was more than I (really) wanted to do. Setting the global digits
option is an excellent suggestion. Thank you. Right now I am working
with simple functions mostly to save myself a few steps.
Miguel:
I did not use pri
Hi, R users
We can create a form using R?
I would like to create a form where the information can be read by R.
Itneeds to be updated daily because I have to tabulate the reasons for
delays
in the generation of numerical models products.
I really appreciate any help,
Thanks in advance,
Nilza B
The manual R-exts, section 6.7.1 should help if you want to call rgamma() in C.
Regards,
Yihui
--
Yihui Xie
Phone: 515-294-6609 Web: http://yihui.name
Department of Statistics, Iowa State University
3211 Snedecor Hall, Ames, IA
2010/3/12 xie :
> rmaxwell() depends on rgamma(), so what you actu
rmaxwell() depends on rgamma(), so what you actually need is to
download R source (rgamma() might depend further on other functions,
though).
> library(VGAM)
> rmaxwell
function (n, a)
{
if (!is.Numeric(n, posit = TRUE, allow = 1))
stop("bad input for argument 'n'")
if (any(a <= 0)
Hi Stephen,
Thanks a lot for your answer. Unfortunately this does not work for me
neither.
Could you maybe let me know what is written in you RprofileSite-file now?
Best
Dennis
--
View this message in context:
http://n4.nabble.com/Error-Running-TinnR-with-R-tp876004p1590576.html
Sent from the
Yeah that's right; in that case implementing the print.myclass as you say
would be the best option.
Miguel
On Fri, Mar 12, 2010 at 2:17 PM, Dieter Menne
wrote:
>
>
> Miguel Porto wrote:
> >
> > Hmm... do something like that, no need to change the global option (I
> used
> > a
> > named vector in
Miguel Porto wrote:
>
> Hmm... do something like that, no need to change the global option (I used
> a
> named vector instead of a list, it's more convenient):
>
> eg <- function(x, digits=4) {
> xbar <- mean(x)
> sdx <- sd(x)
> value <- c(xbar, sdx)
> names(value) <- c("Mean of X", "SD of X")
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