Guy Green wrote:
>
> I wonder if someone can give some pointers on alternatives to linear
> regression (e.g. Loess) when dealing with multiple variables.
>
>
For two variables, there is also interp.loess in package tcp. It can be
rather slow depending on the parameters, so I fear a generaliza
chinna wrote:
>
> i am connecting to the database and i am getting data then how can i get
> forecasted results of this
> using R project.
>
A tourist in Berlin asks: "How do I get to the Philharmony?"
Berliner: Pratice!
Dieter
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I have a table having the data as follows
country Revenue
us $68967
aus $60087
newz $78965
china $67846
i am connecting to the database and i am getting data then how can i get
forecasted results of this
using R project.
--
View this message in contex
Chinna,
glad to hear that you are connected to your db.
About your reports: we don't know what you are looking for, so how on earth
can we help you.
As already pointed out:
List Requirements:
"
PLEASE do read the posting guide
[1]http://www.R-project.org/posting-guide.html
and provide commente
Hi,
after some research now i am connecting to the database
.but i am not getting any reports can u please tell me any suggestions
or ideas.
Regards
chinna.
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https:
Hi Bart, Thanks for the answer.
connecting to a db, extracting the data you want, analyse this and put in a
report, with graphs isn't that hard, but if you are starting out, you have
to accept that you will have to learn the basics.
I am learning R .after some reserch now i am connectin
Exactly what results are you expecting? Your 'match' has the same variables
in both locations and will therefore return the first match:
> match(TazProperties..$Props,TazProperties..$Props)
[1] 1 1 1 4 4 4 4 8 8 8 8 8
so you are getting the results that you ask for.
On Mon, Feb 22, 2010 at 5:42
I have a concern with the sentiment expressed: When one is new
to a language, it is often not easy to know where to start in the
available documentation. It's hard to RTFM when one does not know which
FM2R.
I currently subscribe to email help for three other open source
collabo
Hi Sergio,
Having singular Dmat is certainly a problem.
I can see two possibilities:
1) try to eliminate X1,...,X9, so that you are left with P1,...,P6 only.
2) if you can not do this, add eps*X1^+...+eps*X9^2 to your matrix Dmat so that
it is positive definite (eps is a small positive number). Y
Hi friends, Thanks for the answers..
now i am connecting to database but i dont know how to generate reports with
that data
can anyone please help me.
if possible give the documents for report generation.
thanks in advance.
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Hi Uwe,
Thank you for your email.
I need to compute one value indicating to the performance of knn but I dont
know anything other than MSE. Can you please tell me how I do that?
Many thanks,
Nancy
> Date: Mon, 22 Feb 2010 17:19:48 +0100
> From: lig...@statistik.tu-dortmund.de
> To: nan
Frank,
you can collect multiple arguments into a single \item{}
You example simplified becomes
\item{x, y, contrasts}{see \code{\link{glm}}}
Rich
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Hi, Ivan:
p.s. If you'd like to generate reports using LaTeX, I suggest you
also try "(LaTeX <- ???LaTeX)".
###
Are you trying to read standard text or csv files? If yes, then try
"?read.table" at a command prompt.
Or are you trying to connect directly from R
You can compute the conditional probability that your variable equals k given
that it is non-zero. For example, if X has poisson distribution with parameter
lambda then
P(X=k/X!=0) = P(X=k)/(1-P(X=0)) = (exp(-lambda)/(1-exp(-lambda))*lambda^k/k!
Now you can find lambda for which the sum of square
Hi, Ivan:
Are you trying to read standard text or csv files? If yes, then try
"?read.table" at a command prompt.
Or are you trying to connect directly from R to a database system?
If yes, which database system? This can be done from R, but as far as I
know, finding the functions an
The following construct in Rd files has always been accepted by R:
\arguments{
\item{formula}{}
\item{family}{}
\item{data}{}
\item{weights}{}
\item{subset}{}
\item{na.action}{}
\item{start}{}
\item{offset}{}
\item{control}{}
\item{model}{}
\item{method}{}
\item{x}{}
\it
On Feb 22, 2010, at 8:13 PM, Chunhao wrote:
Dear R users,
I have a question how to use 2 "ifelse" to sort my data. Such as
from 11 to 20 assign to A; 6 to 10 assign to B, and the rest of them
assign
to C
a<-1:20
tt<-ifelse(a>10, "A",no=ifelse( 5< a <=10, "B", "C"))
Two way comparisons a
Hi,
As far as I understand, D is the value of (Kolmogorov-Smirnov) statistic and
p-value is the probability to get that (or greater) value for normally
distributed variables (so in your case you would most probably reject the
hypothesis that your data is normal).
--- On Tue, 23/2/10, Bosken w
Tena koe Edward
It is difficult to know the best approach from the information supplied,
but using unlist() at the appropriate place in your code, maybe
unlist(stats[[i]]$means), will probably get you where you want to be.
HTH .
Peter Alspach
> -Original Message-
> From: r-help-bou
a <- 1:20
tt <- ifelse(a > 10, "A", ifelse(a > 5, "B", "C"))
The problem you have is with '5 < a <= 10'. Such double sided inequalities are
used in mathematics but not in R. Here you only need the first part, but if
you did need both you would need to write
5 < a & a <= 10
Look carefully and
Dear R users,
I have a question how to use 2 "ifelse" to sort my data. Such as
from 11 to 20 assign to A; 6 to 10 assign to B, and the rest of them assign
to C
a<-1:20
tt<-ifelse(a>10, "A",no=ifelse( 5< a <=10, "B", "C"))
Many Thanks
Chunhao
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Hi all,
I have a dataset of 2000 numbers ( it's noise measured with a scoop )
Now i want to know of my data is normal distributed (Gaussian distribution).
I did already:
- 68-95-99.7 test
- Q-Q-plot
and now i used "nortest library" and the Lilli.test()
However i don't understad the output?
HI,
Please try to setup environment variable DISPLAY on your remote machine.
ex,
csh:
setenv DISPLAY localhostIPAddress:20.0
or bash
export DISPLAY=localhostIPAddress:20.0
where localhostIPAddress is your IP address of your current working
machine (local machine)
Usually, I just use localhost
Howdy y'all,
I am looking to use the match function to match a data attribute to another
data frame but i need it to do so on two criteria to ensure an appropriate
match. The following matches incorrectly. I know the example looks
pointless but its just an example. Perhaps there is another wa
Dear Xin,
Le lundi 22 février 2010 à 09:53 -0800, xin wei a écrit :
> hi, Kevin and K.Elo:
> thank you for the suggestion. Can you be more specific on these? (like how
> exactly get into x-switch or man ssh). I am totally ignorant about linux and
> SSH:( Memory limitation forces me to swi
On Feb 22, 2010, at 8:27 PM, ewaters wrote:
Related questions to this have been asked before, but I have tried all
options they gave me unsuccessfully (do.call and unlist).
I start with three lists of summary statistics, 100 elements each,
which I
bind together:
None of this represents
George,
Unless, Venn Diagrams are produced as lattice objects, I don't think you can
save them to modify or update later on. However, if you are just looking for
a shortcut to avoid calling the plotting function again and again you could
use the recordPlot() and replayPlot() functions. Add this l
Related questions to this have been asked before, but I have tried all
options they gave me unsuccessfully (do.call and unlist).
I start with three lists of summary statistics, 100 elements each, which I
bind together:
statslist <- as.data.frame(cbind (means, vars, mcrs))
I then take 100 sampl
Hello,
I am plotting data as a venn diagram but would like to be able to control how
it is plotted like a lattice object.
Right now, it plots right away. I would like to name it and then plot at will.
I thought to convert the whole thing to a PostScript file then get it back into
R via grImport
You probably want to ask the author of the its package directly about that.
Note that as.zoo has an its method and as.its has a zoo method and
they will allow you to convert back and forth between its and zoo so
you can effectively use the functionality of both packages:
# converting back and for
On Sat, 2010-02-13 at 11:33 -0800, Aisyah wrote:
> Hi
>
> Im currently trying to plot my NMDS data together with fitted variables
> (envfit funct) on an ordination plot. The plot function shows two
> displays="sites" and "sp". I was wondering how to plot it so that the sites
> come up as different
On Sat, 2010-02-13 at 13:57 -0500, David Winsemius wrote:
> On Feb 13, 2010, at 1:45 PM, David Winsemius wrote:
>
> >
> > On Feb 13, 2010, at 1:13 PM, Mark Heckmann wrote:
> >
> >> 1) I need to plot a legend containing the mathematical symbol
> >> greater-than-or-equal sign.
> >> And I want the
Can anyone show me how to add a log Pearson type III plot using the
evdistq() command to an extreme value plot using the lmom package?
Attached sample code below...
Thanks in advance,
Dave
library(lmom)
# annual maximum daily streamflows Mackenzie River
mackenzieRiver = c(26600, 30300, 34000,
Saeed Abu Nimeh wrote:
Try to install xming in your windows box
http://www.straightrunning.com/XmingNotes/. Make sure to run xming
before plotting.
Saeed
On Mon, Feb 22, 2010 at 12:46 PM, xin wei wrote:
hi, Guys:
thank you so much for all the suggestion. Now I seem to be able to set up
x11 for
Thanks Phil, I was also trying to get at something like that but couldn't
quite figure it out as quickly.
Mikkel, I guess for your specific example you would need to define ticks
like this:
ticks = seq(min(C$Time),max(C$Time),by='30 min')
-
Try http://prettygraph.com Pretty Graph , the ea
On Feb 22, 2010, at 5:11 PM, kupz wrote:
I have four boxplots, stacked on top of one another (vertically).
There are
five classes that the continuous variable is set against. The
problem I have
is the data for the second boxplot only contains values for four of
the five
classes.
I woul
Mikkel -
Suppose you want tick marks at every half hour:
ticks = seq(as.POSIXct('2010-02-22 12:00:00 PST'),
as.POSIXct('2010-02-22 17:00:00 PST'),by='30 min')
dotplot(Name ~ Time, data = C, horizontal = TRUE,scales=list(x=list(at=ticks)))
Hope this helps.
Try to install xming in your windows box
http://www.straightrunning.com/XmingNotes/. Make sure to run xming
before plotting.
Saeed
On Mon, Feb 22, 2010 at 12:46 PM, xin wei wrote:
>
> hi, Guys:
> thank you so much for all the suggestion. Now I seem to be able to set up
> x11 forwarding in PUTTY.
I have four boxplots, stacked on top of one another (vertically). There are
five classes that the continuous variable is set against. The problem I have
is the data for the second boxplot only contains values for four of the five
classes.
I would like to include the space in this graph so there i
I appreciate everyone's response.
I will look at the options found in stack overflow.
My issue is that i'm trying to load a file (.csv) relative to the R file. I
pass the directory structure around but that directory structure may be put
into something I'm unaware of.
If packages can solve this
Hi,
I'm drawing lattice dotplots with time along the x-axis as in:
C <-data.frame(c("A", "B"),Sys.time()+ rnorm(50)*3600)
names(C) <- c("Name", "Time")
dotplot(Name ~ Time, data = C, horizontal = TRUE)
On my display, the x-axis shows tick marks every two hours. I would like to
show something mo
The classic test for a properly set up X11 is to issue the command
xclock
at the prompt (on the linux box). (this assumes the linux box has
xclock installed, but that is highly likely)
If it works, the X11 forwarding is set up. If not, then, evidently
not, but in the latter case at least yo
On 22/02/2010 3:46 PM, xin wei wrote:
hi, Guys:
thank you so much for all the suggestion. Now I seem to be able to set up
x11 forwarding in PUTTY. however, I still could not get plot and I get the
following error msg:
Error in function (display = "", width, height, pointsize, gamma, bg, :
X1
Dear R-list
I'm on my way to start a new project on a rather big panel, consisting
of approximately 8 million observations in 30 waves of data and about
15 variables. I have a similar data set that is approximately 7
gigabytes in size.
Until now I have done my data management in SAS, and
I just installed it, and it worked fine.
> sessionInfo()
R version 2.10.1 (2009-12-14)
i386-pc-mingw32
locale:
[1] LC_COLLATE=English_United States.1252 LC_CTYPE=English_United
States.1252
[3] LC_MONETARY=English_United States.1252 LC_NUMERIC=C
[5] LC_TIME=English_United States.1252
attached ba
If you restructure your code as a bunch
of functions calling functions instead of
scripts sourcing scripts then the problem
would largely go away. Put the functions
into a package with a namespace and it
becomes more reliable.
Bill Dunlap
Spotfire, TIBCO Software
wdunlap tibco.com
> -Origi
On Mon, Feb 22, 2010 at 4:10 PM, Marc Schwartz wrote:
> It would be helpful to attach the .Rnw SWeave file (if small) or post it
> someplace that we can look at it, along with any data to replicate your
> process.
Sure, you can grab both at http://wart.highsecure.ru/report.tar.gz
(Be warned, th
On 22/02/2010 3:44 PM, Rob Forler wrote:
Hello,
Is there a way to find where a script is located within a script? getwd()
doesn't do what I want because it depends on where R was called from. I want
something like source("randomFile") and within randomFile there is a
function called whereAmI() w
There was a brief discussion about this on stackoverflow -
http://stackoverflow.com/questions/1815606/rscript-determine-path-of-the-executing-script.
-
Try http://prettygraph.com Pretty Graph , the easiest way to make R-powered
graphs on the web.
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Firstly, don't cross-post.
Second, take a look at the archives on both these lists for answers to
your questions.
'its' is rather old, and not where you want to be looking.
Take a look at xts for fast time-series manipulation like you need,
specifically to.period, endpoints, and align.time. The
Not directly what you're asking for, but sourceTo() of R.utils has an
argument 'chdir=FALSE' that when TRUE will change the working
directory to the directory of the script being evaluated.
/Henrik
On Mon, Feb 22, 2010 at 9:44 PM, Rob Forler wrote:
> Hello,
>
> Is there a way to find where a scr
Hello,
I have a series of intraday (high-frequency) price data in the form of POSIX
timestamp followed by the value.
I sucesfuly loaded that into "its" package object. I would like to create
from it a regularly spaced time series of prices (for example 1min, 5min,
etc apart) so i could calcualte re
hi, Guys:
thank you so much for all the suggestion. Now I seem to be able to set up
x11 forwarding in PUTTY. however, I still could not get plot and I get the
following error msg:
Error in function (display = "", width, height, pointsize, gamma, bg, :
X11 I/O error while opening X11 connectio
Hello,
Is there a way to find where a script is located within a script? getwd()
doesn't do what I want because it depends on where R was called from. I want
something like source("randomFile") and within randomFile there is a
function called whereAmI() which returns c:\blah\blah2\randomFile.R
In
Hi,
> I have been looking at a draft of Doug Bate's book on mixed effects models
> (http://lme4.r-forge.r-project.org/book), and in chapter one (section "1.4.2
> Matrices and Vectors in the Fitted Model Object", to be exact) he refers to
> the
> function env() for checking the environment of a fi
Hi, I recently ran into the problem that I needed a Siegel-Tukey test for
equal variability based on ranks. Maybe there is a package that has it
implemented, but I could not find it. So I programmed an R function to do
it. The Siegel-Tukey test requires to recode the ranks so that they express
vari
Bill Dunlap
Spotfire, TIBCO Software
wdunlap tibco.com
> -Original Message-
> From: r-help-boun...@r-project.org
> [mailto:r-help-boun...@r-project.org] On Behalf Of Anthony Damico
> Sent: Monday, February 22, 2010 11:50 AM
> To: r-help@r-project.org
> Subject: [R] Re-assigning variab
See ?get and ?assign
On Mon, Feb 22, 2010 at 4:49 PM, Anthony Damico wrote:
> Is there any way to get the last line of this code to double the contents of
> a and b without naming them directly?
>
> #create variables a and b
> a<-5
> b<-10
>
> #store variable names a and b in variables c and d
>
I have been looking at a draft of Doug Bate's book on mixed effects models
(http://lme4.r-forge.r-project.org/book), and in chapter one (section "1.4.2
Matrices and Vectors in the Fitted Model Object", to be exact) he refers to the
function env() for checking the environment of a fitted lmer objec
Is there any way to get the last line of this code to double the contents of
a and b without naming them directly?
#create variables a and b
a<-5
b<-10
#store variable names a and b in variables c and d
c<-"a"
d<-"b"
e<-c(c,d)
#loop through both variables
for (i in e){
#print the numbers five
On 02/22/2010 08:46 AM, Jay wrote:
> Tahnk you. But, when I try the command you both suggested I get a NULL
> as the results.
>
>> names(object1 @ x.values)
> NULL
>
> Where did I go wrong?
>
>
> On Feb 22, 4:34 pm, David Winsemius wrote:
>> On Feb 22, 2010, at 8:05 AM, Jay wrote:
>>
>>
>>
>>>
I've managed to successfully use R (based on a remote Linux server) and have th
e graphics piped back to me via SSH on a windows machine..
Take a look at XMing on the windows side, along with PuTTY.
On 2/22/2010 2:41 PM, Vojtěch Zeisek wrote:
Dne Po 22. února 2010 19:33:45 Kevin E. Thorpe n
Dne Po 22. února 2010 19:33:45 Kevin E. Thorpe napsal(a):
> K. Elo wrote:
> > Hi!
> >
> > 22.02.2010 19:53, xin wei wrote:
> >> hi, Kevin and K.Elo:
> >> thank you for the suggestion. Can you be more specific on these? (like
> >> how exactly get into x-switch or man ssh). I am totally ignorant abou
Hi all,
Thank you for the reactions!
It works.
Gr. Bosken
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Dear R-help members,
This message is to remind you that the submission deadline for abstracts
for the R User Conference, useR! 2010, is one week away:
Submission deadline: Monday, March 1, 2010
The deadline for early registration is also Monday, March 1, 2010.
I encourage you all to su
Dear all,
I am trying to test goodness of fit. I assume that a data follow Poisson or
Negative binomial distribution. I can test the goodness of fit in case of no
truncated data. However, I could not find any good function or packages when
a data is truncated.
For example, a frequency table
Hello,
I have a large matrix (foo), I have to split by weeks and in which measures
start at different points of time.
Now I am looking for the number of the week, in which a specific value
appears. I do not need the date or any other information from a row, but
(due to structure of result table)
Hi,
You just need to install X11 windows software on windows, such as
xming, and start xming before ssh -X use...@remotehost
Hope this helps.
On 2/22/10, xin wei wrote:
>
>
> thank you for reply. I just type: hist(x) from SSH terminal, expecting a
> histogram to pop up like what i got under
I don't now whether or not this is less "kludgy" than the explicit loop
(loops are implicitly used anyway), but
Reduce(function(x1,x2)gsub(x2,"something else",x1),x, init=y)
does it using gsub. Note, however, that this will **not** work if the
"something else" regular expression itself contained
Here are a few possibilities using gsubfn in the gsubfn package
x <- c("one","two")
y <- paste(rep(x,2),"blah")
library(gsubfn)
# 1
gsubfn("\\w+", w ~ if (w %in% x) "something else" else w, y)
# 2
gsubfn("\\w+", list(one = "something else", two = "something else"), y)
# 3
L <- sapply(x, functio
Hello Hrishi,
That worked great, and in the process I learned some new ways of going about
writing R code. Thank you very much for helping me out!
Eric
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Sent from the R help mai
Hi emorway,
You are right. I tried the command only with one year's data, in which case
it plots month names as labels. But for multiple years, the labels become
years. I found this old post useful -
http://n4.nabble.com/Month-tick-marks-on-a-plot-td879121.html#a879121.
Picking the code from the
K. Elo wrote:
Hi!
22.02.2010 19:53, xin wei wrote:
hi, Kevin and K.Elo:
thank you for the suggestion. Can you be more specific on these? (like how
exactly get into x-switch or man ssh). I am totally ignorant about linux and
SSH:( Memory limitation forces me to switch from windows to Lin
You can try the locfit package, which I believe can handle up to 5
variables. E.g.,
R> library(locfit)
Loading required package: akima
Loading required package: lattice
locfit 1.5-6 2010-01-20
R> x <- matrix(runif(1000 * 3), 1000, 3)
R> y <- rnorm(1000)
R> mydata <- data.frame(x, y)
R> str(m
Dne Po 22. února 2010 18:53:55 xin wei napsal(a):
> hi, Kevin and K.Elo:
> thank you for the suggestion. Can you be more specific on these? (like how
> exactly get into x-switch or man ssh). I am totally ignorant about linux
Hello,
in Linux You can plot as in Windows, for example using hist(x). Bu
Hi!
22.02.2010 19:53, xin wei wrote:
>
> hi, Kevin and K.Elo:
> thank you for the suggestion. Can you be more specific on these? (like how
> exactly get into x-switch or man ssh). I am totally ignorant about linux and
> SSH:( Memory limitation forces me to switch from windows to Linux
> c
Marianne,
The function substring2 from the Hmisc packages works nicely for me to
do this (without explicit gsub, though):
x<- c("one","two")
y<- paste(rep(x,2),"blah")
y
[1] "one blah" "two blah" "one blah" "two blah"
substring2(y,x)<- "something else"
y
[1] "something else blah" "something
Dear Jarret, Uwe, and Dan,
Sorry -- I missed the initial question. What's a bit odd here is that the
singularity occurs only in the computation of the modification indices. It
might help to look at the conditioning of the covariance matrix of the
parameter estimates (i.e., the eigenvalues or si
hi, Kevin and K.Elo:
thank you for the suggestion. Can you be more specific on these? (like how
exactly get into x-switch or man ssh). I am totally ignorant about linux and
SSH:( Memory limitation forces me to switch from windows to Linux
cluster.
Xin
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View this message in context:
Hi emorway,
It seems to me that all you need is one command:
plot(as.Date(cropped.cast1$date,"%Y-%m-%d"),cropped.cast1$Frac_ET_Satsfd_mean)
-
Try http://prettygraph.com Pretty Graph , the easiest way to make R-powered
graphs on the web.
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Hello Hrishi,
The command you suggested plotted the years on the x-axis only. It was the
same exact plot as the one I included in the original post.
Respectfully,
Eric
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Sent fr
Dear Users,
Consider a multivariate time series model:
a_1*y(t)-...-a_k*y(t-k)=b+[c_1*z(t)-...-c_j*z(t-j)]
i.e., a simple multivariate time series model with one exogenous variable.
I would like to know what package can I use to do the following, using R:
1) Select k and j jointly;
2) Estimate t
Preeti,
Could you please post a sample of your data and all the code? It is hard to
answer your question without knowing what "coords" and "act" are
-
Try http://prettygraph.com Pretty Graph , the easiest way to make R-powered
graphs on the web.
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Hi Mohamed,
Please read the posting guides for both, the R-help and BioC mailing
lists, so you learn the basics of how to ask questions on these
lists (and software related mailing lists in general). Following
those guides will greatly increase the chance that someone will
actually be willing (an
Try this:
rle(x)$length
On Mon, Feb 22, 2010 at 2:27 PM, Larson, TR wrote:
> Hello,
> I have a very long (~50,000) sequence of repeating numbers. The first 100
> are:
>
> [1] 0 0 0 0 0 0 0 0 0 0 0 429
> [13] 429 429 429 429 429 429 4
Hello,
I have a very long (~50,000) sequence of repeating numbers. The first
100 are:
[1] 0 0 0 0 0 0 0 0 0 0 0 429
[13] 429 429 429 429 429 429 429 858 858 858 858
858
[25] 858 1287 1287 1287 1287 1287 1716 2145
Tahnk you. But, when I try the command you both suggested I get a NULL
as the results.
> names(object1 @ x.values)
NULL
Where did I go wrong?
On Feb 22, 4:34 pm, David Winsemius wrote:
> On Feb 22, 2010, at 8:05 AM, Jay wrote:
>
>
>
> > The function prediction() returns this:
>
> > Formal clas
OKKK
Thanks a lot for letting me know the subset function
Cheers
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R-help@r-project.or
Hello,
I am trying to plot selected data points to a preexisting persp plot
that satisfies a condition. I used the following statement -
text(coords[,1], coords[,2], names(act[which(act > 8.75)]), cex=0.7)
But I get all the points labeled, instead of the points that satisfy
the condition speci
I'm sure there is a clever way to do the following, but I've been unable to
find it on this forum or by writing my own functions. I have 8 years worth
of weekly data but would like to restrict the labels on the x-axis to months
only. I've included the first year's worth of data below.
My line
I have often found this to happen if the scale of one variable is
orders of magnitude different than the scale of other variables. Have
you tried inspecting the covariance matrix and log transforming any
such variables?
On Feb 22, 2010, at 8:14 AM, Uwe Ligges wrote:
On 20.02.2010 08:51
> > gsub(paste(x, collapse = "|"), "something else", y)
> [1] "something else blah" "something else blah" "something else blah"
> [4] "something else blah"
Many thanks! I didn't know about "collapse". Should have thought about
reading up in ?paste ...
Thanks
Marianne
--
Marianne Promberger P
And as long as the interval is symmetric about zero:
sum(abs(x) <= 2)
[1] 6
-Peter Ehlers
On 2010-02-22 9:18, Jorge Ivan Velez wrote:
Hi,
Here is a suggeston:
x<- c(-1.3, 1, -1.5, -1, 1.5, -2.5, 3, -0.5)
sum(x>=-2& x<=2)
[1] 6
HTH,
Jorge
On Mon, Feb 22, 2010 at 9:49 AM, Bosken<> wro
On Feb 22, 2010, at 10:25 AM, Marianne Promberger wrote:
> Dear list,
>
> I have two vectors:
>
> x <- c("one","two")
> y <- paste(rep(x,2),"blah")
>
> I want to replace all occurrences of each element of x in y with
> something else, so that y looks like this:
>
> y
> [1] "something else bla
gsub("one|two", "something else", y)
?
On Mon, Feb 22, 2010 at 4:25 PM, Marianne Promberger
wrote:
> Dear list,
>
> I have two vectors:
>
> x <- c("one","two")
> y <- paste(rep(x,2),"blah")
>
> I want to replace all occurrences of each element of x in y with
> something else, so that y looks lik
> -Original Message-
> From: r-help-boun...@r-project.org
> [mailto:r-help-boun...@r-project.org] On Behalf Of wendy
> Sent: Saturday, February 20, 2010 6:58 PM
> To: r-help@r-project.org
> Subject: [R] replicate matrix
>
>
> Hi all,
>
> I have a matrix, for example
> [,1] [,2]
> [
Dear list,
I have two vectors:
x <- c("one","two")
y <- paste(rep(x,2),"blah")
I want to replace all occurrences of each element of x in y with
something else, so that y looks like this:
y
[1] "something else blah" "something else blah" "something else blah"
[4] "something else blah"
I can do
On 20.02.2010 19:10, Nancy Adam wrote:
Hi all
I receive this error message: “Error in mymodel$MSE : $ operator is invalid
for atomic vectors”
When I use KNN.
This is the code:
library(e1071)
train<- rbind(iris3[,,1], iris3[,,2], iris3[,,3])
cl<- factor(c(rep("s",50), rep("c",50), rep("v"
See the footer of your message.
Uwe Ligges
On 22.02.2010 13:27, Wendy Qiao wrote:
Dear R team,
As this is a university email address with very small inbox limit, can I
please change my R email subscription to another email address instead of
this one? My new email address is wendy2.q...@gma
Hi,
Here is a suggeston:
> x <- c(-1.3, 1, -1.5, -1, 1.5, -2.5, 3, -0.5)
> sum(x >=-2 & x<=2)
[1] 6
HTH,
Jorge
On Mon, Feb 22, 2010 at 9:49 AM, Bosken <> wrote:
>
> Hi all,
>
> I take a simple dataset like this:
>
> -1.3
> 1
> -1.5
> -1
> 1.5
> -2.5
> 3
> -0.5
>
> Now I want to count how man
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