Do you actually need the intermediate result (the vector of 1's and 0's), or
just the result - the total number of columns?
Is the number you're comparing to different for each column?
Assuming the answers are "just the result" and "comparing to the same
number"
x <- matrix(c(4,5,7,2),nc=2)
n
Hi
r-help-boun...@r-project.org napsal dne 28.01.2010 06:21:40:
>
> i have a simple question. If i have a 2x2 matrix with [,1] and [,2] i
want to
> test each of these to see if they are below some number. If each
component
> in column is below the number then it returns a 1. Now from this resu
HI
r-help-boun...@r-project.org napsal dne 28.01.2010 04:35:29:
> > Hi All,
> >
> > I'm conducting a meta-analysis and have taken a data.frame with
multiple
> > rows per
> > study (for each effect size) and performed a weighted average of
effect
> > size for
> > each study. This results in a re
i have a simple question. If i have a 2x2 matrix with [,1] and [,2] i want to
test each of these to see if they are below some number. If each component
in column is below the number then it returns a 1. Now from this result I
would like to add the number of 1's that came up. How can i do this?
--
Hi All,
I'm conducting a meta-analysis and have taken a data.frame with multiple
rows per
study (for each effect size) and performed a weighted average of effect size
for
each study. This results in a reduced # of rows. I am particularly
interested in
simply reducing the additional variables in th
Dear Kim,
The standard R function anova() produces sequential ("type I") tests; the
Anova() function in the car package can produce "type-III" tests (it
performs "type-II" tests by default), but you must be careful with contrast
coding if there are terms in the model related by marginality.
I hop
Dear GlenB,
The allEffects() function in the effects package can make these plots.
I hope this helps,
John
> -Original Message-
> From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org]
On
> Behalf Of GlenB
> Sent: January-27-10 9:09 PM
> To: r-help@r-project.org
> Su
Dear R-users,
Â
I have seen many times posts about Fourier transform, and I
am trying to do one right now. Before to apply any scripts, I wonder whether it
could properly apply to my problem, and even though itâs not a
statistics-helpers mailing list maybe one of you would be able to answer my
Why do you think we speak SAS here?
anova(fm, test = "Chisq")
will get you a sequential analysis of variance table.
library(MASS)
dropterm(fm, test = "Chisq")
will show you the effect of removing the *non-marginal* terms one at a time.
What more does anyone need?
Bill Venables
CSIRO/CMIS Clev
Here is a rough example
require(MASS)
fm <- lm(medv ~ ns(dis, 3) + ns(nox, 4), Boston)
termplot(fm, se = TRUE)## produces the plots
pv <- predict(fm, type = "terms") ## gets the two terms
Bill Venables
CSIRO/CMIS Cleveland Laboratories
-Original Message-
From: r-help-boun
Hi All,
I'm using glm() in R to perform Poisson regression, I'm wondering if its
possible to get equivalent Type 1 / Type 3 Analysis (similar to one in PROC
GENMOD).
Thanks,
Kim
[[alternative HTML version deleted]]
__
R-help@r-project.org mail
> Hi All,
>
> I'm conducting a meta-analysis and have taken a data.frame with multiple
> rows per
> study (for each effect size) and performed a weighted average of effect
> size for
> each study. This results in a reduced # of rows. I am particularly
> interested in
> simply reducing the additiona
Yes, reinstalling it worked. I wonder what changed to cause this,
especially if it happened to someone else?
And I was a bit worried because I think tcl/tk is installed elsewhere
too. In /usr/local/lib, there is a tcl 8 and tcl 8.5. How do I clean up
this install?
Thanks,
Jim
On 1/27/10 5:07 PM,
Hello,
I'm trying to permute a vector of positive integers > 0 with the constraint
that each element must be <= twice the element before it (i.e. for some
vector x, x[i] <= 2*x[i-1]), assuming the "0th" element is 1. Hence the
first element of the vector must always be 1 or 2 (by assuming the "0t
Hi all,
I have imported xlsx file (Excel 2007) into R using the following scripts.
*library(RODBC)
*
*setwd("...") *
*query <- odbcConnectExcel2007(xls.file = "GI 2010.xlsx", readOnly = TRUE)
dat <- sqlQuery(query, "select * from [sheet1$]", as.is = TRUE, na.strings =
"exp")*
*dat* cont
Check the package doBy as well (pretty handy for analysis of grouped data).
library(doBy)
summaryBy(PM~ID,data=d,FUN=median)
HTH,
-Girish
--
View this message in context:
http://n4.nabble.com/median-of-grouped-data-tp1311971p1312386.html
Sent from the R help mailing list archive at Nabble.com.
On Jan 27, 2010, at 9:09 PM, GlenB wrote:
I have an additive model of the following form :
zmdlfit <- lm(z~ns(x,df=6)+ns(y,df=6))
I can get the fitted values and plot them against z easily enough,
but I
also want to both obtain and plot the two additive components (the
estimates
of the
I have an additive model of the following form :
zmdlfit <- lm(z~ns(x,df=6)+ns(y,df=6))
I can get the fitted values and plot them against z easily enough, but I
also want to both obtain and plot the two additive components (the estimates
of the two additive terms on the RHS)
I've been looking
yes, but the outcome graphs are almost the same, that mean it does not
calculated in a cumulative way , if you apply the following code, then run
hi(x), and then recta(x), you will see how the shape are similar to the
frequency of Amino Acid in the matrix. i am looking for a code that can do
thi
On 01/28/2010 09:52 AM, Jose Narillos de Santos wrote:
Finally I´m very near on the graph I want...
The code is this (based on your guide):
First I read this data on the M.txt file:
Player TYr Dec
Jose20 14
Pepe12 16
Andres 15 12
Guille 16 14
Pedro 18 19
Hi,
I have a matrix of size 19x512x20 in R. I want to export this file into
another format which can be imported into MATLAB.
write.xls or write.table exports only one dimension.
please send a code if possible. I am very new to R and have been struggling
with this.
Thanks !
Gopi
[[altern
Hello all,
I am using quartz (on OS X obviously) to produce PDFs and PNGs from my
plots, for later inclusion in LaTeX.
I am typically using something like:
plot(0)
dev.print(quartz, file="foo.pdf", width=5, height=3)
dev.print(quartz, file="foo.png", width=5, height=3, dpi=72)
I want the sizes
How it represents data internally should not be important as long as
you can do what you want. SQL is declarative so you just specify what
you want rather than how to get it and invisibly to the user it
automatically draws up a query plan and then uses that plan to get the
result.
On Wed, Jan 27,
Hi Jan
Is
.XMLRPC("http://localhost:9000";, "Cytoscape.test", .opts = list(verbose =
TRUE))
the command you used? If not, what did you use?
Can you debug the .XMLRPC function (e.g. with options(error = recover))
and see what the XML that was sent to the server, i.e. the cmd variabl
On Wed, Jan 27, 2010 at 11:11 PM, Rolf Turner wrote:
>
> ?sample
>
And/Or read Knuth.
Does this sound like a homework problem?
--
blog: http://geospaced.blogspot.com/
web: http://www.maths.lancs.ac.uk/~rowlings
web: http://www.rowlingson.com/
twitter: http://twitter.com/geospacedman
pics: ht
?sample
On 28/01/2010, at 12:06 PM, jshort wrote:
Hi
I've recently been trying to solve some probability questions in R,
but am
having trouble.
This is one question thats been causing some hair loss:
Given the set of integers S = {1,2,3,4,5,6,7,8,9,10}, create a
function F(S)
that u
Like this?
d = read.table(textConnection("ID PM
adt_01 25.255
adt_01 225.36
adt_01 14.2325
adt_02 15
adt_02 12.3
adt_03 15.2
adt_03 148.3
adt_03 25.5
adt_03 14.25"),head=T)
d
d$PM <- as.numeric(d$PM)
ddply(d,.(ID),numcolwise(median))
Felipe D. Carrillo
Supervisory Fishery Biologist
Hi
I've recently been trying to solve some probability questions in R, but am
having trouble.
This is one question thats been causing some hair loss:
Given the set of integers S = {1,2,3,4,5,6,7,8,9,10}, create a function F(S)
that uniformly and randomly rearranges these integers.
For exampl
The manual
R Installation and Administration
available from CRAN should help with this.
I believe that one needs sys admin privileges for the default
location, but that it is not difficult to change. (and it's
"packages", not "modules")
-Don
At 4:34 PM -0600 1/27/10, Vadlamani, Satish {
Finally I´m very near on the graph I want...
The code is this (based on your guide):
First I read this data on the M.txt file:
Player TYr Dec Jose 20 14 Pepe 12 16 Andres 15 12 Guille 16 14 Pedro 18
19 Luis 14 19 Raul 18 15 Pepe 7 5
MC<-read.table("MC.txt",header=T,sep="",dec=",")
#I read
Hi:
I have a question about installing R (and modules) on a Unix system (AIX).
Can I just gunzip (or the equivalent) the installation files into my home
directory or will I need someone with root access to install R? I am hoping
that the answer is the former (I can unzip all files to a directory
From: hammadi jbeli
Date: Tue, 26 Jan 2010 23:40:47 +0100
I have used R formulation style and I found this in some R documentations.
Sorry, that makes no sense. I would recommend you go back to your
original dataset and pick a very small subset of it--with only 2
variables, for example.
Why yes. If you keep reading the helpfile for merge, you come to this bit:
Value:
A data frame. The rows are by default lexicographically sorted on
the common columns, but for ‘sort = FALSE’ are in an unspecified
order.
sort=FALSE doesn't preserve your order; instead it gives you
Hello,
I have the following data1 (index are chars):
index
1 008823
2 012689
3 004503
4 002991
5 012689
6 002845
7 012689
8 012395
9 012689
10 009302
11 002845
12 006669
13 008823
14 009302
15 025340
16 012689
and data2 in this format (index2 are chars):
index2 tic
1
John Fox wrote:
Dear James,
The tcltk package is part of the standard R distribution. I'm not sure why
it isn't working. You might try reinstalling R or posting a question to the
R-SIG-Mac list about tcltk not working. If you do the latter, you'll
probably get a more informative response if you
Erik Iverson wrote:
I think you want ?order
On second read, I think you want to do this without having to specify
all 18 variables in an order call... something like this (with only 3
variables)
v1 <- sample(rep(1:10, each = 2))
v2 <- sample(1:20)
v3 <- sample(1:20)
tmp <- data.frame(v1, v
Hi,
It's easy with ggplot2,
cols = matrix(c("#F7FBFF", "#DEEBF7", "#C6DBEF", "#9ECAE1", "#6BAED6",
"#4292C6", "#2171B5", "#08519C" ,"#08306B"), ncol=3)
library(ggplot2)
m = melt(cols)
qplot(factor(X1),factor(X2),data=m, fill=value, geom="tile") +
scale_fill_identity()
HTH,
baptiste
2010/1/2
I think you want ?order
Juanjuan Chai wrote:
Hi, I have a data frame read from a .csv file, with columns
V1,V2,V3...,V18, per say, and I want to sort this data frame according
to V1, and then V2, then V3..., and so on. Is there any fast way to get
around with this problem?
Thanks.
-JJ
_
Hi, I have a data frame read from a .csv file, with columns
V1,V2,V3...,V18, per say, and I want to sort this data frame according
to V1, and then V2, then V3..., and so on. Is there any fast way to
get around with this problem?
Thanks.
-JJ
__
R-
Hi,
Is it possible to create a heatmap for say a 3x3 matrix of data where every
color is pre-assigned?
I can easily create a matrix of hex colors but when I try to use that matrix
as the parameter for the 'col' option it doesn't work. If it's possible to
just display a matrix of hex colors that w
Dear James,
The tcltk package is part of the standard R distribution. I'm not sure why
it isn't working. You might try reinstalling R or posting a question to the
R-SIG-Mac list about tcltk not working. If you do the latter, you'll
probably get a more informative response if you provide the inform
Tena koe Maria
?tapply
Specifically:
tapply(yourData$PM, yourData$ID, median)
HTH
Peter Alspach
> -Original Message-
> From: r-help-boun...@r-project.org
> [mailto:r-help-boun...@r-project.org] On Behalf Of "María del
> Pilar Márquez"
> Sent: Thursday, 28 January 2010 7:06 a.m
Tena koe Gepeto
Not sure if the following helps since you have not been very specific in
your question:
plot(1:10)
text(3,2,'*')
text(5,2,'*5')
text(4,2,'5*5')
text(4,5,'17\n4')
text(6,5,'17\\n4')
Hei kona ra ...
Peter Alspach
> -Original Message-
> From: r-help-boun...@r-project.org
Lazy evaluation.
Consider:
> funlist <- list()
> for (i in 1:5)funlist[[i]]<- eval(bquote(function(x)x^.(i)))
> str(funlist[[2]])
function (x)
- attr(*, "source")= chr "function(x)x^.(i)"
> funlist[[2]]
function(x)x^.(i)
> ## But...
> body(funlist[[2]])
x^2L
> body(funlist[[3]])
x^3L
>
Apparently tcltk is the issue. That hung my R. How do I reinstall tcltk?
On 1/27/10 3:06 PM, John Fox wrote:
> library(tcltk
> tk_choose.dir(getwd(), "Choose folder")
>
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PL
Dear Jim,
The Rcmdr (version 1.5.4) works for me under R64 (R 2.10.1) and Snow
Leopard. Without more information, it's hard to know what went wrong. Have
you checked whether tcltk works? For example, try
library(tcltk
tk_choose.dir(getwd(), "Choose folder")
I hope this helps,
John
---
Julia Tchernova wrote:
Hello!
I have a dataset with the dates and positions - Lat and Long columns
How do I make a scatter plot?
Do I have to cbind to combine the Lat and Long columns?
Any suggestions will be much appreciated!
Thank you
Julia
[[alternative HTML version deleted]]
Hi,
I remember asking a similar question some time ago, I don't know if
the matter has evolved since then,
http://groups.google.com/group/ggplot2/browse_frm/thread/a3df8a0d1ee335fb/e3bedd50fb9bd567?lnk=gst&q=theme#e3bedd50fb9bd567
There's also set_default_scale, somewhat related to your question
I'm going to be manipulating some 3-rd and 4-th rank tensors in
relatively high dimensions, and it would help a great deal to use only
the unique entries instead of repeating every operation 6 or 24 times.
Operations are tensor-matrix, tensor-vector, and tensor-tensor
multiplication.
Does any
typically, the apply family wants you to use vectors to run functions on.
However, I have a function, kruskal.test, that requires 2 arguments.
kruskal.test(Herb.df$Score,Herb.df$Year)
This easily computes the KW ANOVA statistic for any difference across
years
However, my data has multiple
Are you sure these are hdf5 files? If they are HDF4 files you will not
be able to load them with the hdf5 package. I am not aware of a HDF4
package for R but I might be wrong.
If it is a HDF4 file you might find the conversion utility at
http://www.hdfgroup.org/h4toh5/ useful.
Cheers,
1. Is it possible to set the point colors in a ggplot2 theme? For example,
to default to these colors:
scale_colour_manual(value = c("red", "orange", "yellow", "green", "blue")
2. Is it possible to set this theme in .Rprofile, similar to:
my.lattice.colors = function () { ...etc.}
option
On Wed, 27 Jan 2010, Gregory Gentlemen wrote:
Dear R-users,
Say that I have a sequence of zeroes and ones:
x <- c(1,1,1,0,0,0,0,1,1,1,0,0,0,0,1,1,1,0,0,0,0)
The sequences of ones represent segments and I want to report the
starting and endpoints of these segments. For example, in 'x', the fi
Hi,
On Wed, Jan 27, 2010 at 12:21 PM, wrote:
> Hello everybody,
> I would need some help from you.
> I am trying to fit a logistic model to some presence absence data of
> animals living on river islands. I have got 12 predictor variables and I am
> trying to use a stepwise forward method to fit
m <- c(1,4,2,3,7,5)
S <- "which(m==4)"
P <- parse(text=S)
R <- eval(P)
R
Before you do this, see fortune(106)
> fortune(106)
If the answer is parse() you should usually rethink the question.
-- Thomas Lumley
R-help (February 2005)
On Wed, Jan 27, 2010 at 8:59 AM, Joe Trubisz wrote:
> He
On 28/01/2010, at 2:59 AM, Joe Trubisz wrote:
Hello...
In other languages (e.g. php, perl), you have the ability to create a
valid string and execute the string to get the result. For example (in
pseudo-R):
S<-"which(m==4)"
R<-exec(S)
I know this does not work, but was wondering if there was
>
> question like this:
>
> I have data tag and phi, when tag are the same, then phi are the same. like
> below, tag have value 1 2 3 4 and phi have value .9 .3 1 0.
>
> my question is, how can I get the result like
> tag=c(1,2,3,4) and corresponding phi=c(.9,.3,1,0)
>
> tag phi
> 2.3
> 1
question like this:
I have data tag and phi, when tag are the same, then phi are the same. like
below, tag have value 1 2 3 4 and phi have value .9 .3 1 0.
my question is, how can I get the result like
tag=c(1,2,3,4) and corresponding phi=c(.9,.3,1,0)
tag phi
2.3
1.9
2.3
31
2
Good morning,
I would like to know if is possible somebody can help me with this please:
I would like to calculate the median of grouped data, this is an example:
IDPM
adt_01 25.255
adt_01 225.36
adt_01 14.2325
adt_02 15
adt_02 12.3
adt_03 15.2
adt_03 148.3
adt_03 25.5
adt_03 14.25
I
Duncan, thanks.
To the point, R supports -(2**31-1) to 2**31-1 or -2147483647 to +2147483647
-2147483648 is a valid signed integer but returns NA.
Signed integers are -2147483648 to 2147483647
Glenn D Blanford, PhD
NAIL lab, PM NSI, Fort Monmouth, NJ
glenn.blanf...@us.army.mil
Scientific Research
Hello everybody,
I would need some help from you.
I am trying to fit a logistic model to some presence absence data of
animals living on river islands. I have got 12 predictor variables and I am
trying to use a stepwise forward method to fit the best logistic model to
my data. I am using the
Hi all,
I am trying to use and place in a graph some alt characters such as
"*".. Could you help me?
Thanks
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posti
Hi interested readers,
I have a function that creates several functions within a loop and I would like
them to be returned for further use as follows:
Main.Function(df,...){
# df is a multivariate data
funcList<-list(NULL)
for (i in 1:ncol(df)){
temp<-logspline(df[,i],...) # logspline density es
Hello...
In other languages (e.g. php, perl), you have the ability to create a
valid string and execute the string to get the result. For example (in
pseudo-R):
S<-"which(m==4)"
R<-exec(S)
I know this does not work, but was wondering if there was an
equivalent mechanism that I cannot fin
On my Mac (Snow Leopard and R64), I had been using Rcmdr nicely. But now
when I do
> library(Rcmdr)
the tk libraries load, but the Rcmdr window never appears.
> library(Rcmdr)
Loading required package: tcltk
Loading Tcl/Tk interface ...
>
And if I try to do anything else, R goes to 100% cpu and ha
Thank you so much Eik. This is what I used, and it genereated 530 files of
triple graphs in less than a minute.
dev.copy(win.metafile, file = paste(myV,"emf",sep="."), width = 7, height =
10, pointsize = 12)
dev.off()
Thanks again,
Jerry Floren
Minnesota Department of Agriculture
--
View thi
Try this:
unique(cbind(tag, phi))[order(unique(tag)),]
On Wed, Jan 27, 2010 at 4:13 PM, song song wrote:
>> question like this:
>>
>> I have data tag and phi, when tag are the same, then phi are the same. like
>> below, tag have value 1 2 3 4 and phi have value .9 .3 1 0.
>>
>> my question is, h
> question like this:
>
> I have data tag and phi, when tag are the same, then phi are the same. like
> below, tag have value 1 2 3 4 and phi have value .9 .3 1 0.
>
> my question is, how can I get the result like
> tag=c(1,2,3,4) and corresponding phi=c(.9,.3,1,0)
>
> tag phi
> 2.3
> 1.9
Hi Jerry,
have a look at ?paste and perhaps ?win.metafile too.
something like
> file = paste(myV,"emf",sep=".")
will do the trick.
cheers.
Jerry Floren schrieb:
Greetings,
I am trying to write multiple .emf graphs to individual files.
Our data is from agricultural laboratories where individ
> -Original Message-
> From: r-help-boun...@r-project.org
> [mailto:r-help-boun...@r-project.org] On Behalf Of Gregory Gentlemen
> Sent: Wednesday, January 27, 2010 9:31 AM
> To: r-help@r-project.org
> Subject: [R] Function for describing segements in sequential data
>
> Dear R-users,
>
> sqldf("select * from BOD order by Time desc limit 3")
Exactly. SQL requires use of order by. It knows the order, but it isn't
ordered. Thats not good, but might be fine, depending on what the real goal
is.
"Gabor Grothendieck" wrote in message
news:971536df1001270629w4795da89vb7d77af6e4e8b
Hi,
On Wed, Jan 27, 2010 at 12:31 PM, Gregory Gentlemen
wrote:
> Dear R-users,
>
> Say that I have a sequence of zeroes and ones:
>
> x <- c(1,1,1,0,0,0,0,1,1,1,0,0,0,0,1,1,1,0,0,0,0)
>
> The sequences of ones represent segments and I want to report the starting
> and endpoints of these segments
On 27/01/2010 10:50 AM, Blanford, Glenn wrote:
Duncan, thanks.
To the point, R supports -(2**31-1) to 2**31-1 or -2147483647 to +2147483647
-2147483648 is a valid signed integer but returns NA.
Signed integers are -2147483648 to 2147483647
Yes, R uses the -2147483648 encoding to store the in
Dear R-users,
Say that I have a sequence of zeroes and ones:
x <- c(1,1,1,0,0,0,0,1,1,1,0,0,0,0,1,1,1,0,0,0,0)
The sequences of ones represent segments and I want to report the starting and
endpoints of these segments. For example, in 'x', the first segment starts at
location 1 and ends at 3,
Just as an aside, the scatterplot3d package does things like this very
cleverly. Essentially, when you create a plot with scatterplot3d, the function
actually returns functions with values set so that points3d(), for example,
"knows" the axis scaling.
Best,
--
Wolfgang Viechtbauer
Probably so that the end of the arrow does not overplot the labels.
Kevin
On Wed, Jan 27, 2010 at 10:28 AM, Martin Ivanov wrote:
> Dear forum,
> I need to create biplot graphic. I took a look at the code of the
> biplot.default function from the stats package and I found that the arrows
> for
Ram:
You do not say how many cases (rows in your dataset) you have, but I suspect
it may be small (a few hundred, say).
In any case, what you describe is probably just a complicated way to
generate random numbers -- it is **highly** unlikely that any meaningful,
replicable scientific results woul
Dear forum,
I need to create biplot graphic. I took a look at the code of the
biplot.default function from the stats package and I found that the arrows for
the variables are multiplied by a coefficient of 0.8 before plotting:
...
if (var.axes)
arrows(0, 0, y[, 1L] * 0.8, y[, 2L] * 0.8,
On 27/01/10 - 08:54, Gabor Grothendieck wrote:
> One approach would be to use one of the URL shortening services to
> define a shorter URL. The shorter URL would then appear rather than
> the long original one (although there would still be a URL shown so
> its not quite the functionality you ask
Joel,
The list strips off binary attachments. But Ista is correct - to
diagnose your problem
(one that I've never encountered), we need to see a short odfWeave
input file (including
data - random numbers are fine) that we can actually run, and see
table cells that
work and do not work. There's pre
Greetings,
I am trying to write multiple .emf graphs to individual files.
Our data is from agricultural laboratories where individual soil samples are
tested for various plant nutrients, for example, ammonium nitrogen,
phosphorus, and zinc. Basically, there are three important columns: the
labor
On Wed, 27 Jan 2010 14:15:28 +0100 Ivan Calandra wrote:
> From my experience (which is limited), it seems to me that '
> (apostrophe) and " (quotation marks) are the same in R: they are both
> used for strings. The only difference would be taste.
> But I've recently read about the difference be
Mike Babyak wrote:
Hi All,
I have a quick question about using plot.Predict now that the rms package
uses lattice. I'd like to add tick marks along the regression line, which
is given by data=llist(variablename) in the plot call. The ticks show up
fine, but I'd like to alter the color. I know
On 1/27/2010 10:00 AM, Richardson, Patrick wrote:
> Is there a way (with a simple plot) to select all observations greater than a
> certain value and plot them with a different color than the rest of the
> observations in the plot? (i.e. for all observations greater than 10, I want
> to plot the
Attached is the "input" file ("modele_rapport.odt") and one example of
output file ("rapport_Abstention2.odt") (I run a loop with the same report
generated for different datasets). I hope this is what you are looking for ?
Joel
On Wed, Jan 27, 2010 at 3:56 PM, Ista Zahn wrote:
> Joel, I still d
Is there a way (with a simple plot) to select all observations greater than a
certain value and plot them with a different color than the rest of the
observations in the plot? (i.e. for all observations greater than 10, I want to
plot them in red, but the rest of the observations remain black. W
Joel, I still don't see an example. I think you're making things more
difficult for yourself than you need to, but without an example I
don't know what exactly you're doing.
-Ista
On Wed, Jan 27, 2010 at 8:34 AM, Joel GOMBIN wrote:
> Hi,
>
> so to sum up, I'm making automated reports, in the for
Hello Matthew,
I do not have a direct answer to your problem, but you could try saving it
as an EPS and then rasterizing it using a graphics program (e.g., GIMP) to
whatever resolution you wanted.
Best luck finding a real solution.
Joshua
On Tue, Jan 26, 2010 at 9:05 AM, Matthew Walker
wrote
On Wed, Jan 27, 2010 at 8:56 AM, Matthew Dowle wrote:
> How many columns, and of what type are the columns ? As Olga asked too, it
> would be useful to know more about what you're really trying to do.
>
> 3.5m rows is not actually that many rows, even for 32bit R. Its depends on
> the columns and
Yes, checking it now, I see you are absolutely right. Sorry for this
confusion.
Cheers,
Olga
On 27.01.2010, at 12:45, Orvalho Augusto wrote:
RMySQL is for MySQL. MySQL is not MSSQL.
There is not RMSSQL. So the best you have something to conneto
MSSQL... RODBC or you may connect.
Or as Ji
Hi All,
I have a quick question about using plot.Predict now that the rms package
uses lattice. I'd like to add tick marks along the regression line, which
is given by data=llist(variablename) in the plot call. The ticks show up
fine, but I'd like to alter the color. I know the ticks are produc
How many columns, and of what type are the columns ? As Olga asked too, it
would be useful to know more about what you're really trying to do.
3.5m rows is not actually that many rows, even for 32bit R. Its depends on
the columns and what you want to do with those columns.
At the risk of sugge
One approach would be to use one of the URL shortening services to
define a shorter URL. The shorter URL would then appear rather than
the long original one (although there would still be a URL shown so
its not quite the functionality you asked for). For more info google
for: url shortening
On W
On 27/01/2010 8:36 AM, Luca Braglia wrote:
Hello *
is possible to have something like the LaTeX \href in Rd ?
\url doesn't fit very well, and I didn't find much about.
I have a long (external to the help system, a www one) url but i
would like it to be "hidden" from a small word with the link.
Hello *
is possible to have something like the LaTeX \href in Rd ?
\url doesn't fit very well, and I didn't find much about.
I have a long (external to the help system, a www one) url but i
would like it to be "hidden" from a small word with the link.
Please CC me! ;)
thanks in advance
Luca
Hi,
so to sum up, I'm making automated reports, in the form of tables. In each
cell of the table is an expression like (e.g.) :
\Sexpr{odfCat(round(summary(get(modele1))$coefficients[1,1],2))}
For most cells, after I run odfWeave, the results are correctly put and
formatted. But in some cells (
Hi everybody,
From my experience (which is limited), it seems to me that '
(apostrophe) and " (quotation marks) are the same in R: they are both
used for strings. The only difference would be taste.
But I've recently read about the difference between = and <- and I
thought that there might be
Read the article in R News 4/1.
2010/1/27 Robert Kalicki :
> Dear R community
>
> I would like to perform some statistical analysis on a data set containing
> the following items: date, time, index of observation and various
> covariates.
>
> The date and time are originally extracted in the follo
Dear R community
I would like to perform some statistical analysis on a data set containing
the following items: date, time, index of observation and various
covariates.
The date and time are originally extracted in the following format:
dd.mm. and hh:mm:ss respectively. R and more precisely
Hi Joel,
Can you paste a minimal example illustrating your problem?
Thanks,
Ista
On Wed, Jan 27, 2010 at 6:19 AM, Joel GOMBIN wrote:
> Hello,
>
> thanks to Sarah for her help. That works fine, except for one thing. When I
> generate my reports, using odfWeave(), some cells in my tables are filled
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