Ravi Varadhan jhmi.edu> writes:
> dist <- function(A, B) {
> # Frobenius norm of A - B
> n <- nrow(A)
> sum(abs(B - A))
> }
>
See http://mathworld.wolfram.com/FrobeniusNorm.html for a definition of the
Frobenius norm.
Erwin
--
Hi Klaus,
This problem can be cast as a linear sum assignment problem (LSAP), and solved
using the `solve_LSAP' function in the "clue" package. I show how to solve a
slightly more general problem of finding a permulation of matrix A (n x n) that
minimizes the Frobenius distance to a given matr
Hi,
I was wondering: I've got a dataset where I've got student 'project's
nested within 'school's, and 'division' (elementary, junior, or
senior) at the student project level. (Division is at the student
level and not nested within schools because some students are
registered as juniors & others
On Jan 15, 2010, at 4:50 PM, Shawn Morrison wrote:
Is there a readily available function to calculate the effect of
variables from a poisson GLM on the response variable?
My situation is as follows:
I have developed a poisson GLM model and have obtained the
coefficients, SEs, etc However,
On Sat, 16 Jan 2010, Vera wrote:
Thanks for your help so far, everyone.
Thomas: I haven't looked very deep into the survey package yet, so I
don't know if what I'm looking for is actually missing or if I just
haven't found it yet.
What is "missing", from my point of view at the moment, is some
Could you at least show how you were plotting it when you got the error. It
is not clear what you are trying to plot. The statement
plot("insert_file_name_here") did not make sense.
On Fri, Jan 15, 2010 at 5:48 PM, cobbler_squad wrote:
>
> Hello,
>
> As a result of running linear discriminant
Hello,
As a result of running linear discriminant analysis, I need to be able to
plot the resulting file. I am not sure what the best way to do this is. So
far I have tried regular plot("insert_file_name_here") command but the error
it gives me is Error in plot.new() : figure margins too large
h
Is there a readily available function to calculate the effect of
variables from a poisson GLM on the response variable?
My situation is as follows:
I have developed a poisson GLM model and have obtained the coefficients,
SEs, etc However, I am somewhat stuck on interpreting a coefficient in
e
Thanks for your help so far, everyone.
Thomas: I haven't looked very deep into the survey package yet, so I
don't know if what I'm looking for is actually missing or if I just
haven't found it yet.
What is "missing", from my point of view at the moment, is some kind
of global weighting function th
On Fri, 15 Jan 2010, vivi ane wrote:
is there a function in R equivalent to the "weight by"-command in SPSS?
I'm working with survey datasets and the data need to be weighted by a
survey/ probability/ design weight (to compensate for different
probabilities to be included in the sample in each c
Hi Aaron,
try the argument "statistic=mean". Then boot() will give you the mean
turn angle in your actual data (which appears to be 6 degrees, judging
from what you write), as well as the means of the bootstrapped data.
Then you can get (nonparametric) bootstrap CIs by
quantile(boot$t,probs=c
Please try to follow the posting guide and give a reproducible example,
as below:
R> library(randomForest)
randomForest 4.5-34
Type rfNews() to see new features/changes/bug fixes.
R> iris2 = iris[-5]
R> iris.rf = randomForest(Petal.Width~., iris2, maxnodes=4, ntree=50)
R> nodesize(iris.rf)
Error:
?Startup
Read this help page **carefully**. It tells you what happens when R starts
up. The profile file is executed with **only the base package loaded**, and
read.table is not in the base package.
If you replace your read statement with
data <- utils::read.table("data")
it would work (if the
On Jan 15, 2010, at 5:13 PM, vivi ane wrote:
Hi,
is there a function in R equivalent to the "weight by"-command in
SPSS?
I'm working with survey datasets and the data need to be weighted by a
survey/ probability/ design weight (to compensate for different
probabilities to be included in the
Hi,
is there a function in R equivalent to the "weight by"-command in SPSS?
I'm working with survey datasets and the data need to be weighted by a
survey/ probability/ design weight (to compensate for different
probabilities to be included in the sample in each country). The
weight variables are i
Saleem,
I have no idea about this, but may be you can use other data.frame name
instead of "data" because data is a name of a function (see ?data).
good luck
milton
On Fri, Jan 15, 2010 at 3:33 PM, saleem mukhtar wrote:
> Hello,
>
> I am running R on cygwin for windows.
>
> File R1234 contains
Has anyone sucessfully used the maxnodes feature in randomForest? I tried
setting it, but when it is non-NULL I always get back a forest in which all
trees have size 1. I am using a continuous response (regression). Any help
would be appreciated.
Thanks.
[[alternative HTML version deleted]
As a general rule, you really do not want to edit graphs by
pointing/clicking/dragging. It may seem an easy way to make some
modifications, but in the long run it will become more of a headache than a
help. Better to create a script with the commands to create the plot, then if
there is some
Here is an example that may be helpful.
A <- matrix(c(-3,5,4,-2),nrow=2,byrow=TRUE)
eigs <- eigen(A)
eigs
$values
[1] -7 2
$vectors
[,1] [,2]
[1,] -0.7808688 -0.7071068
[2,] 0.6246950 -0.7071068
The eigenvectors may be scaled differently because they are not unique
(or have
Thanks for the replies! The answer is that barplot() returns the x
coordinates of the bars.
On Fri, Jan 15, 2010 at 12:01 PM, Rex C. Eastbourne <
rex.eastbou...@gmail.com> wrote:
> How can I write text inside a bar of a barplot? I tried using text(), but I
> am only able to specify the numeric y-
On Fri, Jan 15, 2010 at 10:00 AM, Ben Bolker wrote:
> John Kane yahoo.ca> writes:
>
>>
>> I've only been using R for about 2.5 years but and I'm not all that good but
> I vote for <- .
>>
>> I think the deciding factor is in RSiteSearch() and the various manuals.
>>
>> Almost everything I see u
Hello,
I am running R on cygwin for windows.
File R1234 contains
data <- read.table("data")
q()
On the command line I type
R --no-save -q R_PROFILE=R1234
returns
Error: could not find function read.table
THanks.
__
R-help@r-project.org m
On 1/13/10 11:21 AM, James W. MacDonald wrote:
Hi Colin,
The pkgDepTools package from Bioconductor will help with question
#1:
http://bioconductor.org/packages/2.5/bioc/html/pkgDepTools.html
I am not positive on this, but I believe this package is also used
to determine the reverse dependencie
How can I write text inside a bar of a barplot? I tried using text(), but I
am only able to specify the numeric y-coordinate. The different columns of
my barplot correspond to factors and not numbers, so I don't know how to
access the horizontal positions of the bars. I tried fiddling with differen
Dear R-helpers
I am running a simple mixed effects model using lme(). The call looks
like this:
fit <- lme(Analyte~Sample, data=Data, random=~1 | Run)
I am particularly interested in the estimated random effects. When I
print the 'fit' object, it looks something like example below:
(...)
Ra
Hi All,
I'm new to R so please bear with me. I have a dataset with 337 turn angles
ranging from -180 to 180 degrees. I need to bootstrap (sample with
replacement) 1,000 times to create expected average turn angle with 95% CIs.
The code is pretty straightforward (<-boot(data =, statistic
Try this:
`class<-`(lapply(1:length(QuanImpUnsold),
function(idx)c(QuanImpUnsold[[idx]], PARCELS[[idx]])), "by")
On Fri, Jan 15, 2010 at 5:06 PM, L.A. wrote:
>
>
> Hey Guys,
> It sure seems I get stuck on things that should be easy.
> Heres my question:
>
> PARCELS<-by(ResImp[ , "ACCOUNTNO"], R
Hey Guys,
It sure seems I get stuck on things that should be easy.
Heres my question:
PARCELS<-by(ResImp[ , "ACCOUNTNO"], ResImp["Property"], length)
> PARCELS
Property: UNSOLD
[1] 9053
---
Property: SOL
Just to comment on this bit :
> For one thing, you cannot index a csv file or a data.frame. If you have to
> repeatedly select subsets of your large data set, creating an index on the
> relevant column in the sqlite table is an absolute life saver.
This is one reason the data.table package was
On Fri, Jan 15, 2010 at 5:30 PM, Janko Thyson
wrote:
> Dear List,
>
> I am not really familiar with any other language than R, but I’ve heard that
> in other languages there is something called “self referencing”.
>
> Here’s what I’m trying to get an answer for:
> Suppose there is a function that
netrunner wrote:
>
> I am a newbie in R. I would like to use the panel.bpplot function on my
> data set but I have some problems. Can this function work on matrix? My
> data set have some NaN and when I run panel.bpplot function it returns
> error due to the presence of NaN. How Can I solve thi
netrunner wrote:
Hi everybody,
I am a newbie in R. I would like to use the panel.bpplot function on my data
set but I have some problems. Can this function work on matrix? My data set
have some NaN and when I run panel.bpplot function it returns error due to
the presence of NaN. How Can I solve
Dear List,
I am not really familiar with any other language than R, but Ive heard that
in other languages there is something called self referencing.
Heres what Im trying to get an answer for:
Suppose there is a function that takes as its input a value of a slot of an
S4 object. The function
gmx.de> writes:
>
> Dear R-experts,
>
> this is not a direct R-problem but I hope you can help me anyway.
>
> I would like to minimize || PG-I || over P, where P is a p x p permutation
matrix (obtained by permuting the rows
> and/or columns of the identity matrix), G is a given p x p matrix
Hi everybody,
I am a newbie in R. I would like to use the panel.bpplot function on my data
set but I have some problems. Can this function work on matrix? My data set
have some NaN and when I run panel.bpplot function it returns error due to
the presence of NaN. How Can I solve this?
Thank you s
On 01/15/2010 01:49 AM, Bart Joosen wrote:
>
> One way could be to first select only the unique ID's, sample this and then
> select only the relevant records:
>
> strQuery = "SELECT ID from tblFoo;"
> IDs <- sqlQuery(channel, strQuery)
> sample.IDs <- sample(IDs,10)
> strQuery = paste("SELECT ID
Walther, Alexander googlemail.com> writes:
>
> Dear list,
>
> i try to set up a GUI with gWidgets. For this project, RGtk2 is
> required. By loading the package, i encounter the following error prompt:
>
> ---C Symbolname "S_gtk_icon_factory_new" not in DLL for package "RGtk2"-
--
>
This sou
If you use
fit1<-glm(y~x,offset=offset,family=poisson(link=log))
you will get values for the Null deviance and residual deviance along with
degrees of freedom for these parameters. One of these deviances divided by its
degrees of freedom might be what you are looking for. but I am not sure.
Per
On Thu, 14 Jan 2010, Erin Hodgess wrote:
Hi R People:
I'm teaching a statistical computing class using R starting next week
(yay!) and I have an opinion type question, please.
I'm old school and use "<-" in an assignment.
However, I'm starting to see the "=" in the literature.
Which should I
On Fri, 15 Jan 2010, Barry Rowlingson wrote:
On Fri, Jan 15, 2010 at 6:57 AM, Ted Harding
wrote:
There is at least one context where the distinction must be
preserved. Example:
pnorm(1.5)
# [1] 0.9331928
pnorm(x=1.5)
# Error in pnorm(x = 1.5) : unused argument(s) (x = 1.5)
pnorm(x<-1.5)
John Kane yahoo.ca> writes:
>
> I've only been using R for about 2.5 years but and I'm not all that good but
I vote for <- .
>
> I think the deciding factor is in RSiteSearch() and the various manuals.
>
> Almost everything I see uses <- . Why introduce = when it is not used
normally? It w
On Jan 15, 2010, at 9:46 AM, Titus von der Malsburg wrote:
On Fri, Jan 15, 2010 at 09:19:23AM -0500, David Winsemius wrote:
On Jan 15, 2010, at 5:59 AM, Titus von der Malsburg wrote:
Mean and variance of Poisson distributed data are specified by \rho.
How can I estimate \rho for a set of me
On Fri, Jan 15, 2010 at 08:33:52AM -0700, Peter Ehlers wrote:
> Why would anyone complain? You're free to call it 'applesauce'
> if that suits you.
Good idea, I will do this from now on! ;-)
> What do you mean by 'general way to fit a distribution'?
> Maximum likelihood might be one way.
Somebo
Hi all,
This question is more stats related than R related, but as I will be doing
these analyses in R, there may be some programming questions to follow. I
figured it best to start here.
To keep things relatively simple, assume that I recently fielded a survey
over three weeks. I have three di
Titus von der Malsburg wrote:
On Fri, Jan 15, 2010 at 09:19:23AM -0500, David Winsemius wrote:
On Jan 15, 2010, at 5:59 AM, Titus von der Malsburg wrote:
Mean and variance of Poisson distributed data are specified by \rho.
How can I estimate \rho for a set of measurements in R?
rho <- mean(
adapted from the help files of rowsum
x <- matrix(runif(100), ncol=5)
group <- sample(1:8, 20, TRUE)
xsum <- rowsum(x, group)
sweep(xsum, 1, table(group), "/")
or
aggregate(x, list(group), mean)[-1]
b
2010/1/15 Joel Fürstenberg-Hägg :
>
> Hi all,
>
>
>
> I want to calculate the row wise mean o
One way to add the text is to use a list with named elements for the row and
column names:
> (M <- matrix(1:9, ncol=3, byrow=TRUE,
+ dimnames=list(" "=LETTERS[1:3],
+ "THIS IS AN EXAMPLE\nOF a 3x3 MATRIX"=LETTERS[1:3])) )
THIS IS AN EXAMPLE
OF a 3x3 MATRIX
A B C
Dear ExpeRts,
I have the scatter plot matrix as given below. I would like the different
"sub-plots" in the scatter plot matrix to be colored differently. How do I get
all points shown in the upper-left plot (on position (1,1) in the scatter plot
matrix) to be plotted in blue, and the points sho
Dear list,
i try to set up a GUI with gWidgets. For this project, RGtk2 is
required. By loading the package, i encounter the following error prompt:
---C Symbolname "S_gtk_icon_factory_new" not in DLL for package "RGtk2"---
Any suggestions how to fix this? And: is there a good resource for
gWi
Thanks for your answer.
I've thought of the possibility of an index when using a SQLite database, but
as you mentioned, I don't really benefit from it in regard of rather small
data sets.
What I am considering as a problem when using csv files is the occurrence of
data redundancy: When I wan't
Hello!
The question is simple: What is the escape sequence for a new line when
using Hershey fonts? I obviously tried '\n' but it didn't work (see the
sample below). I looked at 'demo(Hershey)' but all it only shows escape
sequences for printable characters.
The sample I've been using to t
Dear R-experts,
this is not a direct R-problem but I hope you can help me anyway.
I would like to minimize || PG-I || over P, where P is a p x p permutation
matrix (obtained by permuting the rows and/or columns of the identity matrix),
G is a given p x p matrix with full rank and I the identity
I've only been using R for about 2.5 years but and I'm not all that good but I
vote for <- .
I think the deciding factor is in RSiteSearch() and the various manuals.
Almost everything I see uses <- . Why introduce = when it is not used
normally? It will just confuse the students who are try
On Fri, Jan 15, 2010 at 09:19:23AM -0500, David Winsemius wrote:
>
> On Jan 15, 2010, at 5:59 AM, Titus von der Malsburg wrote:
>
> >Mean and variance of Poisson distributed data are specified by \rho.
> >How can I estimate \rho for a set of measurements in R?
>
> rho <- mean(x)
Yeah, thanks :-)
On Jan 15, 2010, at 5:59 AM, Titus von der Malsburg wrote:
Mean and variance of Poisson distributed data are specified by \rho.
How can I estimate \rho for a set of measurements in R?
rho <- mean(x)
David Winsemius, MD
Heritage Laboratories
West Hartford, CT
___
Hi all,
I want to calculate the row wise mean of groups of columns in a matrix M. All
columns belonging to the same group have the same column name. My idea is to
create a new vector V containing these column names, but after first removing
the duplicates. Then I would calculate the means u
Thanks, Henrique
I *do* need to preserve the type of each list element (num or chr).
Thus, a first step might be
> as.data.frame(testlist, stringsAsFactors=FALSE)
shape cell.fill back.fill scale.max
1 0 red white 100
2 0 blue white 100
3 2 green
On 14.01.2010 11:11, Marius Hofert wrote:
Dear R-Users,
I would like to color the data in a splom according to their position in the matrix, i.e.
I would like to have all data shown in the upper left corner to be blue, all entries
below that to be black, and the data to the right to be all r
You can access the sources yourself.
How to find the right file is described in
Ligges, U. (2006): R Help Desk: Accessing the Sources. R News 6 (4),
43-45. http://cran.r-project.org/doc/Rnews/Rnews_2006-4.pdf
Best wishes,
Uwe Ligges
On 15.01.2010 10:54, Federico Bonofiglio wrote:
hello R-W
Ok.
Caveman
On Thu, Jan 14, 2010 at 5:19 PM, Marcus, Jeffrey
wrote:
> Orvalho:
> Thanks for pointing our RMySQL. The reason is that we have similar data
> stored in both SQL server and MySQL databases and I want to reuse code as
> much as possible.
>
> Jeff
>
>
> -Original Message-
That's it, thanks a lot to all of you!
Uli
Henrique Dallazuanna schrieb:
> In grep use: grep("x$", names(data)).
>
> '$' matchs 'x' in the end of string
>
> On Fri, Jan 15, 2010 at 11:14 AM, Uli Kleinwechter
> wrote:
>
>> Jim Lemon schrieb:
>>
>>> On 01/15/2010 07:10 PM, Uli Kleinwechte
Uli Kleinwechter a écrit :
data[,grep("x",names(data))][is.na(data[,grep("x",names(data))])]<-0
thanks a lot. I'm just afraid that grep matches any occurence of "x" in
the variable name. So variables which would contain "x" at any position,
not necessarily only at the last one would be sel
This gives the result you asked for:
DF <- as.data.frame(testlist)
lapply(split(DF, 1:nrow(DF)), unclass)
although it might be good enough to just do this depending on what you need:
DF <- as.data.frame(testlist)
split(DF, 1:nrow(DF)
On Fri, Jan 15, 2010 at 8:09 AM, Michael Friendly wrote:
>
In grep use: grep("x$", names(data)).
'$' matchs 'x' in the end of string
On Fri, Jan 15, 2010 at 11:14 AM, Uli Kleinwechter
wrote:
> Jim Lemon schrieb:
>> On 01/15/2010 07:10 PM, Uli Kleinwechter wrote:
>>> Dear all,
>>>
>>> I'm looking for a way to replace NA's with 0 for a number of variables
Try this:
#'1) But apply converts all to 'character'
apply(as.data.frame(testlist), 1, as.list)
#2)
lapply(split(x <- as.data.frame(testlist), 1:nrow(x)), as.list)
On Fri, Jan 15, 2010 at 11:09 AM, Michael Friendly wrote:
> I have a list of vectors, all forced to be the same length:
>
> testlis
fingers too fast; didn't need the enclosing 'list':
> testlist <- list(
+ shape=c(0, 0, 2),
+ cell.fill=c("red","blue","green"),
+ back.fill=rep("white",3),
+ scale.max=rep(100,3)
+ )
>
> wanted <- lapply(seq(length(testlist[[1]])), function(x){
+ # iterate for each element of the lis
On 1/15/10, vikrant wrote:
> can I edit my chart as in Excel.
>
Sort of, using playwith. You can always try to place the the plot call
inside playwith(). For example,
require(playwith)
playwith(plot(1:10))
Liviu
__
R-help@r-project.org mailing list
ht
Hello all,
I want to call R from java. And I have a expression in Java as a String,
example : (variable 1 + variable 2)* variable 3 and i want R calculate this
expression. How can I do?
ex:
Java
-int x1,x2;
-float x3;
-String s=( x1.toString()+x2.toString() ) * x3.toString();
R:
calculate e
Does this do it:
> testlist <- list(
+ shape=c(0, 0, 2),
+ cell.fill=c("red","blue","green"),
+ back.fill=rep("white",3),
+ scale.max=rep(100,3)
+ )
>
> wanted <- lapply(seq(length(testlist[[1]])), function(x){
+ # iterate for each element of the list
+ result <- lapply(names(test
Jim Lemon schrieb:
> On 01/15/2010 07:10 PM, Uli Kleinwechter wrote:
>> Dear all,
>>
>> I'm looking for a way to replace NA's with 0 for a number of variables
>> which share the same ending and which constitute a subset of a data
>> frame.
>>
>> Say, for example, there is
>>
>>> data<- data.frame(a
I have a list of vectors, all forced to be the same length:
testlist <- list(
shape=c(0, 0, 2),
cell.fill=c("red","blue","green"),
back.fill=rep("white",3),
scale.max=rep(100,3)
)
> str(testlist)
List of 4
$ shape: num [1:3] 0 0 2
$ cell.fill: chr [1:3] "red" "blue" "green"
$ bac
Dear Vladimir,
You can use a logistic regression. First define Y0 as 30 - Y. Then Y is
the number of days with headache and Y0 the number of days without.
Then the model looks like: glm(cbind(Y, Y0) ~ X1 + X2 + X3, family =
"binomial")
HTH,
Thierry
Barry Rowlingson wrote:
On Fri, Jan 15, 2010 at 6:57 AM, Ted Harding
wrote:
There is at least one context where the distinction must be
preserved. Example:
pnorm(1.5)
# [1] 0.9331928
pnorm(x=1.5)
# Error in pnorm(x = 1.5) : unused argument(s) (x = 1.5)
pnorm(x<-1.5)
# [1] 0.9331928
x
Try this:
m[prop.table(rowSums(is.na(m))) < 0.1,]
2010/1/15 Joel Fürstenberg-Hägg :
>
> Hi all,
>
>
>
> I would like to remove rows from a matrix, based on the frequency of missing
> values. If there are more than 10 % missing values, the row should be deleted.
>
>
>
> I use the following to cal
Joel,
try this:
# sample matrix
m <- matrix(sample(c(1:10, NA),150,replace=T),byrow=T,ncol=15)
# nr of missing values per row
nacounts <- apply(m, 1, function(x)length(x[is.na(x)]))
# new matrix
newm <- m[nacounts/ncol(m) < 0.1,]
greetings,
Remko
--
Hi all,
I would like to remove rows from a matrix, based on the frequency of missing
values. If there are more than 10 % missing values, the row should be deleted.
I use the following to calculate the frequencies, thereby getting a new matrix
with the frequencies:
freqNA=rowMeans(is.
theFiles <- list.files(inputdir, full=T, pattern="\\.[eE][xX][tT]$")
for (file in theFiles){
...
}
On Fri, Jan 15, 2010 at 11:43 AM, Albert Vilella wrote:
> Hi all,
>
> I'm trying to process all files with a certain extension "*.ext" in a
> directory like this:
>
>> R --slave --args /my/dir < di
Albert,
try something like this:
extfiles <- list.files(pattern=".ext")
for(f in extfiles){
process.data(f)
#etc
}
greetings,
Remko
-
Remko Duursma
Post-Doctoral Fellow
Centre for Plants and the Environment
University of Western Sydney
H
Hi all,
I'm trying to process all files with a certain extension "*.ext" in a
directory like this:
> R --slave --args /my/dir < dir_plot.r
where I then I want to do something like:
myarg <- commandArgs()
inputdir <- myarg[length(myarg)]
print(inputdir)
"for file with extension "*.ext in inputdi
Joel Fürstenberg-Hägg wrote:
>
>
>
> I have two question. First, I wonder how to remove a part of the column
> names in a matrix? I would like to remove the "_ACCX" or "_NAX" part
> below. Is there a method where the "_" as well as all characters after i
> can be removed?
>
> Secondly, I wou
On 13.01.2010 05:43, Hao Cen wrote:
Hi,
I wonder anyone knows what causes the error message "select: bad file
descriptor" in the multicore package. This error sometimes occurs and
sometimes doesn't. I couldn't find any documentation on this error about
this package.
As the R-help footer tel
On Fri, Jan 15, 2010 at 11:26 AM, vikrant wrote:
>
> Can I save R graphs as a R objects ?
I have seen that feature in the rkward GUI (which is by the way the BEST GUI
I have seen for a long time!), but I haven't played with that feature a lot,
so I can not comment on your second question.
By t
On 15.01.2010 11:23, vikrant wrote:
If anybody can provide me a link it will be very much helpful
See package RODBC.
Uwe Ligges
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide h
You can use the recordPlot function from base package also
On Fri, Jan 15, 2010 at 7:26 AM, vikrant wrote:
>
> Can I save R graphs as a R objects ? IF yes then if I click this R object
> can I edit my chart as in Excel.
> Please suggest your views
> --
> View this message in context:
> http://n4
vikrant wrote:
>
> Is it possible to connect R with Ms SQL Server 2005 ? If Yes how to
> connect it and can you please provide some tutorial for it?
>
It's easiest using RODBC. Using Control Panel/Administrator/Data Sources
(Free translation from German, might be slightly off), create a sourc
Hi!
Let's suppose the values for the x axis are stored in 'values'.
barplot(values, col=c(rep("Red",3),rep(1,length(values)-8),rep("Blue",5)))
HTH,
Kimmo
vikrant kirjoitti:
> Suppose I need to draw a Grouped bar plot with 100 values on the X axis. Now
> my question is If I need to highlight sup
vikrant wrote:
Can I save R graphs as a R objects ? IF yes then if I click this R object
can I edit my chart as in Excel.
Please suggest your views
When you use the graphics functions from the lattice package (e.g.
xyplot) you can save them to a file (see ?save) because it creates an
object
Jon,
There are packages that fit mixtures of multivariate normals (mclust) and in
flexmix
one can also model multiple measures (with local independence assumption).
hth, Ingmar
On Fri, Jan 15, 2010 at 11:08 AM, Jon Toledo wrote:
>
> Iæe several packages for latent class analysis, but I was won
Barry Rowlingson wrote:
> On Fri, Jan 15, 2010 at 3:45 AM, Erin Hodgess wrote:
>
>> Hi R People:
>>
>> I'm teaching a statistical computing class using R starting next week
>> (yay!) and I have an opinion type question, please.
>>
>> I'm old school and use "<-" in an assignment.
>>
>>
> You call
Mean and variance of Poisson distributed data are specified by \rho.
How can I estimate \rho for a set of measurements in R?
Many thanks!
Titus
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posti
Prof Brian Ripley wrote:
>> I have zlib compressed strings (example is attached)
>
> What is that file? Not gzip compression:
>
> gannet% file compressed.txt
> compressed.txt: ASCII text, with very long lines
>
> since gzip uses a magic header that 'file' knows about. And even if
> the header
Hi,
this works aswell:
for(i in 1:ncol(data)) data[is.na(data[,i]),i] <- 0
i am sure there is way doing it with a member of the apply family, maybe
someone else has an idea.
Johannes
On Fri, Jan 15, 2010 at 9:51 PM, Jim Lemon wrote:
> On 01/15/2010 07:10 PM, Uli Kleinwechter wrote:
>
>> Dea
If anybody can provide me a link it will be very much helpful
--
View this message in context:
http://n4.nabble.com/Connecting-R-with-MS-SQL-server-2005-tp1014643p1014669.html
Sent from the R help mailing list archive at Nabble.com.
__
R-help@r-proje
Hi everyone,
The "problem" was the result of my historical misbehavior of embedding
links within certain font enhancements. This used to work, but no
longer. Any of you package maintainers who find that your links are
suddenly becoming literal text on the HTML help pages are likely to have
the
hello R-Wizards! again i'm invoking your presence!!
since all the fuss about the paradoxes on a computer algorithm generating
"caos" or un-determinancy, i recently grew quite curious about the mechanism
underlying the procedure of NUMBER RADOMIZATION.
could anyone of you, masters, attach me t
I´ve several packages for latent class analysis, but I was wondering if there
is a package for continuos variables, which allows latent prfile analysis.
Thanks for your help in advance,
J Toledo
___
Suppose I need to draw a Grouped bar plot with 100 values on the X axis. Now
my question is If I need to highlight suppose first three values by some
color say 'red' and also I need to highlight last 5 datavalues
by some color say 'blue' and the rest of the data in between I need not
display. Is
Is it possible to connect R with Ms SQL Server 2005 ? If Yes how to connect
it and can you please provide some tutorial for it?
--
View this message in context:
http://n4.nabble.com/Connecting-R-with-MS-SQL-server-2005-tp1014643p1014643.html
Sent from the R help mailing list archive at Nabble.co
Can I save R graphs as a R objects ? IF yes then if I click this R object
can I edit my chart as in Excel.
Please suggest your views
--
View this message in context:
http://n4.nabble.com/Can-I-save-R-graphs-as-a-R-objects-tp1014621p1014621.html
Sent from the R help mailing list archive at Nabbl
Hi,
I would like to ask for advice about best statistics method for
my problem.
I was done questionnaire about headache.
My data are:
Y - frequency of symptoms occur - times per month in range <0..30>
(where 30 is daily and zero for never)
and independent variables:
X1 - sex - category {M,F}
X2 -
1 - 100 of 110 matches
Mail list logo