On 1/13/10, Trafim Vanishek wrote:
> this is the output result
> > Rk[47] <= RB[21]
> [1] FALSE
>
> > Rk[47]
> [1] 0.002842007
>
> > RB[21]
> [1] 0.002842007
>
I would suspect that, if you're looking at all the digits, the two are
not exactly the same. I would try
round(Rk[47], 10) <= round
hello
I need a clarification.
in logistic regression, saturated model having all combinations and
interactions of variables should be constructed in this way ? :
> rsat2=glm(cbind(landp,landa) ~
as.factor(rlito)*as.factor(rslp)*as.factor(rasp)*as.factor(rplc)*as.factor(rwi),family=
binomial(li
On Wed, 13 Jan 2010, Nathan S. Watson-Haigh wrote:
Can anyone point me in the right direction for decompressing text files that
are compressed as tar.gz or zip files?
?unztar
?unz
?unzip
Note that neither .tar.gz nor .zip formats are restricted to a single
file and more usually hold a collec
On 01/12/2010 04:36 PM, dwalcerz wrote:
>
> This is a solution I am posting for a problem that others may have.
>
> If you want to:
> 1. Place lattice graphics from R into an Adobe InDesign document, and
> 2. Use the export as eps function in R to maximize resolution (it is much
> better than e
Dear all,
Does anybody know the probable reason why <= gives false when it should give
true?
These two variables are of the same type, and everything works in the cycle
but then it stops when they are equal.
this is the output result
> Rk[47] <= RB[21]
[1] FALSE
> Rk[47]
[1] 0.002842007
> RB[21
Can anyone point me in the right direction for decompressing text files that are
compressed as tar.gz or zip files?
Cheers,
Nathan
--
Dr. Nathan S. Watson-Haigh
OCE Post Doctoral Fellow
CSIRO Livestock Industries
University Drive
Townsvil
A few suggestions:
Don't mix ' and "
Use paste()
Don't include an extraneous ;
SymA<- "SPY"
Sym1<-
paste("http://ichart.finance.yahoo.com/table.csv?s=",SymA,"&ignore=.csv",sep="";)
Symbol<- read.csv(Sym1, stringsAsFactors=F)
On Jan 12, 2010, at 10:03 PM, B S wrote:
>
> Hi-
>
> I would
Hi-
I would like to be able to change the value of SymA below and download a file
from the corresponding URL. Hardcoded, this line works fine:
Symbol<-
read.csv("http://ichart.finance.yahoo.com/table.csv?s=SPY&ignore=.csv";,
stringsAsFactors=F)
However, when I incorporate using a variable
On Tue, Jan 12, 2010 at 8:58 PM, Simon Knapp wrote:
> Not sure if there are any 'recommended' visualisations, but the following
> is
> a start (you will need to tune the scaling of the x-axis label and state
> identifiers).
>
> In the plot produced, the widths of the 'columns' are proportional o
Not sure if there are any 'recommended' visualisations, but the following is
a start (you will need to tune the scaling of the x-axis label and state
identifiers).
In the plot produced, the widths of the 'columns' are proportional of
purchases occurring in the state, and the height of the 'boxes'
Hi,
I wonder anyone knows what causes the error message "select: bad file
descriptor" in the multicore package. This error sometimes occurs and
sometimes doesn't. I couldn't find any documentation on this error about
this package.
thanks
Jeff
__
R-hel
On Tue, Jan 12, 2010 at 5:26 PM, Rex C. Eastbourne wrote:
> Let's say I have data in the following schema that describes the number of
> purchases a company has received from each County in the US:
>
> State | County | Purchases
> ---
> NJ | Mercer | 550
> CA |
You might try this to get the data into a dataframe that would be easier to
process. You can subset and split the dataframe to look at different
combination.
> str01 <- "2007-10-12 11:50:05 state B. ,2007-10-12 11:50:05 state C.
,2007-10-12 13:23:24 state D. ,2007-10-12 13:23:43 state E. ,2007-10
Hi,
Is that okay to let R to read data set more than 1 rows and use it to do
some kernel density estimation? Thanks.
Yi
--
Yi Du
Ph. D student in Economics
University of Missouri
Department of Economics
118 Professional Building
Columbia MO 65211
1-573-239-6467
[[alternative HTML
Let's say I have data in the following schema that describes the number of
purchases a company has received from each County in the US:
State | County | Purchases
---
NJ | Mercer | 550
CA | Orange | 23
I would like to visualize what states contribute the m
tmp <- scan()
0 2 1 0 1 0 2 1 2 3 0 0 0 0 1 0 0 2 3 1
dat <- matrix(tmp, byrow=T, ncol=4)
apply(dat, 2, function(x, min.val, max.val) {
tmp <- table(x)/length(x)
res <- rep(0, max.val - min.val + 1)
res[as.numeric(names(tmp)) - min.val + 1] <- tmp
res
}, 0, 3)
Should do it (but I
Greg
Nice problem: I wasted my whole day on it :-)
I was explaining my plan for a solution to a colleague who is a
computer scientist, he pointed out that I was trying to re-invent the
wheel known as dynamic programming. here is my code, apparently it is
called "bottom up dynamic programming".
Tena koe Elaine
Check the information about setting graphics parameters by typing
?par # or help(par)
at the R prompt. In particular, check cex.lab, cex.col and las
HTH
Peter Alspach
> -Original Message-
> From: r-help-boun...@r-project.org
> [mailto:r-help-boun...@r-project.o
Dear ,
As a newbit to R learning boxplot,
please kindly share how to rotate y axis lable by 90 degrees or 180
degrees clockwise.
Also, please advise how to resize the label font and change its color.
Thank you
Elaine
[[alternative HTML version deleted]]
Hi Hari,
You have not given examples of 'list1.bp.files.names' or
'list2.bp.files.names' and hence it is difficult to determine what the code
is trying to achieve. I will assume you want to create all pairwise merges
of the attached files. If this is indeed what you are doing, the problem is
not a
I think I figured this out. I should not have put the Driver name in
braces. Changing it from {MySQL} to MySQL seems to work.
-Original Message-
From: Marcus, Jeffrey
Sent: Tuesday, January 12, 2010 6:09 PM
To: 'r-help@r-project.org'
Subject: Problems connecting with MySQL using odbcDriv
Kai,
Your question is best addressed to "r-sig-fina...@stat.math.ethz.ch" as
it is finance related question.
Jude
___
Jude Ryan
Director, Client Analytical Services
Strategy & Business Development
UBS Financial Services Inc.
1200 Harbor Boulevard,
I am sure I'm doing something wrong here but not sure what.
Our system administrator recently installed UnixODBC and the MyODBC
driver on a Linux box running Linux version 2.6 x86_64.
I have an .odbc.ini file in my home directory with following lines:
[mydb]
Description = MySQL server on my-se
On 12.01.2010 21:07, Alexander Shenkin wrote:
Hi Alessia,
Note that, while your physical limit might be 6 GB, Windows memory
management allows more memory than that to be allocated (aka Virtual
Memory, or at least that's what they called it in XP). Windows swaps
out memory from RAM to the hard
Dear R-users,
actually i try to parse some state protocols for my work. i an easy
stetting the code below works fine, if states are reached only once. in
harder settings it could be possible that one state gets visited more
times. in this case for me its interesting to see how much waiting tim
I re-read the solution that you posted and realized where my thinking
was going wrong. Sorry (again!) for being a thicko.
cheers,
Rolf Turner
On 13/01/2010, at 9:19 AM, Greg Snow wrote:
How trivial is probably subjective, I don't think it is much above
trivial. I w
Jiiindo wrote:
> Colleagues,
> How i can solve this error when i install SJava package
A more recent version of SJava is available with
> source('http://bioconductor.org/biocLite.R')
> biocLite('SJava')
rJava is an alternative.
Martin
> Thanks
>
> R CMD INSTALL -c /usr/lo
Hello.
I am not certain even how to search the archives for this particular question,
so if there is an obvious answer, please smack me with a large halibut and send
me to the URLs.
I have been experimenting with fitting curves by using both maximum likelihood
and maximum spacing estimation te
Hi Jim,
I am want to merge two files into one file :
Here is my code . But the problem with this is that I am getting the 2nd
file appended to the first when i write temp3 in my code to the text file. I
am not sure what mistake I am doing .
also find the test files to run the code .
Please help
The Below worked best for my purposes. Thanks everyone.
Data<-c("1131", "1132", "1731" ,"1732" ,"1821" ,"1822", "2221" ,"",
"2241" ,"2242","414342" ,"414371" ,"414372")
substr(Data,1,nchar(Data)-1)
LCOG1 wrote:
>
> Hello all,
> Frustrated and i know you can help
>
> I need to dr
On 13/01/2010, at 9:19 AM, Greg Snow wrote:
How trivial is probably subjective, I don't think it is much above
trivial. I would not have been surprised to see this question on
an exam in my undergraduate (300 or junior level) probability
course (the hard part was remembering the details f
To make a long story short I was doing some in-sample testing in which some
dynamically created regressors would end up either all true or all false
based on the validation portion. In my case a new mainframe configuration
(this is a crappy way to handle a level shift but I do what I can.) So here
Thank you very much for the code Bill! I only had to change very few things to
make it work for probit and lmer (instead of glmmPQL) and it works perfectly!
Here's my code (I had some trouble with the output style glm.dose, so I just
have it come out as an ugly list now, which isn't a problem
How trivial is probably subjective, I don't think it is much above trivial. I
would not have been surprised to see this question on an exam in my
undergraduate (300 or junior level) probability course (the hard part was
remembering the details from that class from over 20 years ago). My favori
Your code is doing too many needless things.
The following takes about one second on my slow Vista laptop.
n <- 500
mat <- matrix(1:(n*n), n)
v <- n:1
z <- 2*1:(n/2)
w <- c(z, rev(z))
for(i in seq_len(n)){
for(j in seq_len(n)){
if(v[j] + w[i] <= n)(mat[i,j] <- NA)
}
}
rownames(mat) <- v
c
> -Original Message-
> From: r-help-boun...@r-project.org
> [mailto:r-help-boun...@r-project.org] On Behalf Of Etienne Stockhausen
> Sent: Tuesday, January 12, 2010 10:59 AM
> To: r-help@r-project.org
> Subject: [R] Making routine faster by using apply instead of for-loop
>
> Hey everybod
Try this:
substr(Data,1,nchar(Data)-1)
Steve
>>>
From: LCOG1
To:
Date: 13/Jan/2010 9:15 a.m.
Subject: [R] Drop last numeral
Hello all,
Frustrated and i know you can help
I need to drop the last numeral of each of my values in my data set. So for
the following i have tried the ?substri
In addition to the substring and regular expression solutions, if you are
certain that everything will be numeric (and integer as in your examples), then
you could just convert to numeric, divide by 10, and then drop the decimal
(floor or as.integer).
--
Gregory (Greg) L. Snow Ph.D.
Statistica
Hi Alessia,
Note that, while your physical limit might be 6 GB, Windows memory
management allows more memory than that to be allocated (aka Virtual
Memory, or at least that's what they called it in XP). Windows swaps
out memory from RAM to the hard disk and back when necessary (please
excuse the
thank you guys. All the columns of my data are numeric.
I tried both methods, and they both work.
I appreciate your help.
-k
--
View this message in context:
http://n4.nabble.com/how-to-handle-missing-values-when-importing-data-in-R-tp1012298p1012397.html
Sent from the R help mailing list arc
Also try
sub('[0-9]$', '', Data)
[1] "113" "113" "173" "173" "182" "182" "222" "222" "224"
[10] "224" "41434" "41437" "41437"
HTH,
Dennis
On Tue, Jan 12, 2010 at 10:36 AM, LCOG1 wrote:
>
> Hello all,
> Frustrated and i know you can help
>
> I need to drop the last numeral of
On Tue, 2010-01-12 at 10:28 -0800, kellys17 wrote:
> Hi,
>
> I am currently working on some data and feel that NMDS would return an
> excellent result. With my current data set however I have been experiencing
> some problems and cannot carry out metaMDS. I have tried with a few smaller
> data se
Data<-c("1131", "1132", "1731" ,"1732" ,"1821" ,"1822", "2221" ,"",
"2241" ,"2242","414342" ,"414371" ,"414372")
Bldgid<-substring(as.character(Data),1,nchar(Data)-1)
-Original Message-
From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org]
On Behalf Of LCOG1
Sent: Tu
Hello all,
Frustrated and i know you can help
I need to drop the last numeral of each of my values in my data set. So for
the following i have tried the ?substring but since i have to specify the
length, but because my data are of varying lengths it doenst work so well
Data<-c("1131", "1132
Nice --- am I missing something or was this closed form solution not
entirely trivial to find?
I ought to compile the various clever solutions given in this thread
someday, it's fascinating!
Thanks,
baptiste
2010/1/12 Greg Snow :
> This also has a closed form solution:
>
>> choose(16+8-1,7) - c
On 13/01/2010, at 3:40 AM, BXC (Bendix Carstensen) wrote:
I have noted that the later versions of Rcmd check cleans out the
directory pkg.Rcheck so that only package-manual.log and package-
manual.pdf are left.
Formerly the package-manual.tex was around too --- very handy for
various purpos
This also has a closed form solution:
> choose(16+8-1,7) - choose(7+8-1, 7) - 7*choose(6+8-1,7)
[1] 229713
--
Gregory (Greg) L. Snow Ph.D.
Statistical Data Center
Intermountain Healthcare
greg.s...@imail.org
801.408.8111
> -Original Message-
> From: r-help-boun...@r-project.org [mailt
What is the structure of the data that you are reading in? Are you using
'read.table', 'scan', etc.? Are all the columns numeric, or do you just
want to change some of them? If you have used 'na.strings' to cause the
values of the missing data to be set to NA, then you can iterate through the
ap
Hey everybody,
I have a small problem with a routine, which prepares some data for
plotting.
I've made a small example:
c=10
mat=data.frame(matrix(1:(c*c),c,c))
row.names(mat)=seq(c,1,length=c)
names(mat)=c(seq(2,c,length=c/2),seq(c,2,length=c/2))
v=as.numeric(row.names(mat))
w
Mario Valle wrote:
>
> [sorry, forgot some details...]
>
> I'm using optim(param, fun, method='L-BFGS-B', lower=lo, upper=up) to
> minimize a certain function.
> Often the minimization ends with the message:
> ERROR: ABNORMAL_TERMINATION_IN_LNSRCH
>
> What is optim() trying to say?
> What hav
I have done ancova with categorical and continuous predictor variables.
The categorical predictor variable shows significant effect on the dependent
variable.
I would like to do a post-hoc test to see which groups in the categorical
variable differ.
I have explored Tukey test in multcomp package.
The last 2 lines of your code can be replaced with:
M <- replicate(1000, sample(Y,5,replace=FALSE) )
--
Gregory (Greg) L. Snow Ph.D.
Statistical Data Center
Intermountain Healthcare
greg.s...@imail.org
801.408.8111
> -Original Message-
> From: r-help-boun...@r-project.org [mailto:r-h
Mario,
It seems likely that your function is not smooth in the parameters. This
may create problems for some optimizers that require smoothness. However, I
was able to get good convergence with `spg' function in my "BB" package.
Here is how it works:
> require(BB)
Loading required package: B
On 12-Jan-10 17:46:47, karena wrote:
> hi, I have a question about importing data in R.
>
> I want to import a file which has missing value in it, and the missing
> values are denoted as ".", I want to first read in the file, and then
> change the "." into the number zero "0".
>
> how can I do th
Hi Steve,
Thank you so much for your reply. I really needed to know how SVM works without
removing the class label while receiving it in the formula parameter. It does
not if I remove the class label.
Cheers,
Amy
> Date: Sat, 9 Jan 2010 15:48:49 -0500
> Subject: Re: [R] svm
> From: ma
Hi,
I am currently working on some data and feel that NMDS would return an
excellent result. With my current data set however I have been experiencing
some problems and cannot carry out metaMDS. I have tried with a few smaller
data sets which I created for practice sake and this has worked fine.
I have a challenge that I want to share with the group.
This is not homework (but I may assign it as such if I teach the appropriate
class again) and I have found one solution, so don't need anything urgent.
This is more for fun to see if others can find a better solution than I did.
The chall
Hi, tim,
thank you very much for the reply, but I am really a new user. How to change
all NAs to zero?
thanks again.
karena
jholtman wrote:
>
> ?read.table
>
> na.strings='.'
>
> Then change all NAs to zero df$col[is.na(df$col)] <- 0
>
> On Tue, Jan 12, 2010 at 12:46 PM, karena wrote
Dear friends,
I have a table like this, I have A B C D ... levels, the first column
you see is just the index, and there are different numbers in the
table.
A B C D ...
10 2 1 0
21 0 2 1
32 3 0 0
40 0 1 0
50 2 3 1
...
I want to calculat
On 12/01/2010 10:47 AM, Rosario Garcia Gil wrote:
Dear colleges
I need to get the p values for a table with 15000 entries of t values. Does any
of you know how to do it? I can, of course, get one by one but that is not
sensible.
Put the t values into a vector, then use pt() in an appropria
?read.table
na.strings='.'
Then change all NAs to zero df$col[is.na(df$col)] <- 0
On Tue, Jan 12, 2010 at 12:46 PM, karena wrote:
>
> hi, I have a question about importing data in R.
>
> I want to import a file which has missing value in it, and the missing
> values are denoted as ".", I w
On Sat, Jan 9, 2010 at 1:21 AM, Werner W. wrote:
> I would like to estimate a quadratic almost ideal demand system in R which is
> estimated usually by nonlinear seemingly unrelated regression. But there is no
> such function in R yet
The "systemfit" package has the function nlsystemfit() for est
hi, I have a question about importing data in R.
I want to import a file which has missing value in it, and the missing
values are denoted as ".", I want to first read in the file, and then change
the "." into the number zero "0".
how can I do that?
thank you,
karena
--
View this message in c
Attached a script that reproduces the problem.
My function is fold.val() and at the end seems the curve contained in
lnsrch.dat is fitted quite well, but optim generates the error.
Thanks again!
mario
-
I'm using optim(param, fun, method='L-BFGS-B', lowe
I see, now I got it.
and thanks for the example with matrix.
best
alessia
2010/1/12 Martin Maechler :
>> "am" == alessia matano
>> on Mon, 11 Jan 2010 16:20:57 +0100 writes:
>
> am> Many thanks for it.
> am> However it is strange that when I put the numbers rather than ncol(R)
Laetitia,
I was just responding to your comment that "R complains
about a syntax error". But I realize now that "2x" would
probably cause an "unexpected symbol" error.
Here's what I get when I run your loop; what do you get?
> for (x in 1:(nrow(dat)-1)) {
+ a <- as.character(dat[(2x-1),1])
Err
You can edit the barplot function to do this:
mybarplot <-
function (height, width = 1, space = NULL, names.arg = NULL,
legend.text = NULL, beside = FALSE, horiz = FALSE, density = NULL,
angle = 45, col = NULL, border = par("fg"), main = NULL,
sub = NULL, xlab = NULL, ylab = NULL, xlim
Dear R-users,
I am using R version 2.10.1 under windows.
In a barplot, I want to mark one of the bars with a special border color.
For example:
barplot(c(3, 7, 11), border = c(NA, "red", NA))
But how to do this when the bars are stacked?
for example:
barplot(matrix(1:6, ncol=3)) # border of seco
Dear colleges
I need to get the p values for a table with 15000 entries of t values. Does any
of you know how to do it? I can, of course, get one by one but that is not
sensible.
Thanks
Rosario
__
R-help@r-project.org mailing list
https://stat.ethz.c
This is a solution I am posting for a problem that others may have.
If you want to:
1. Place lattice graphics from R into an Adobe InDesign document, and
2. Use the export as eps function in R to maximize resolution (it is much
better than exporting as a metafile or bitmap), and
3. Use long st
You forgot a lot of details. Can you send us more information about the
"fn" and also some minimal code that can reproduce the problem?
Ravi.
---
Ravi Varadhan, Ph.D.
Assistant Professor, The Center on Aging and H
[sorry, forgot some details...]
I'm using optim(param, fun, method='L-BFGS-B', lower=lo, upper=up) to
minimize a certain function.
Often the minimization ends with the message:
ERROR: ABNORMAL_TERMINATION_IN_LNSRCH
What is optim() trying to say?
What have I to change in my function to make the
I'm using optim() to minimize a certain function.
Often the minimization ends with the message:
ERROR: ABNORMAL_TERMINATION_IN_LNSRCH
What is optim() trying to say?
What have I to change in my function to make the minimization succeed?
Do you think using BBoptim() instead of optim() changes anyth
Thanks a lot for help! :)
I've invented a more complicated way to make it work:
f <- as.formula(paste("data.y~", paste( names(data.x), collapse = "+")))
fml<-glm(f, data=data.x,family=binomial)
Try this:
glm(y ~ ., family = binomial, data = data, ...)
--
View this message in context:
http:
Thanks Ted, it's exactly what I'm after. Thanks for the help.
--
View this message in context:
http://n4.nabble.com/Conditional-Sampling-tp1012072p1012180.html
Sent from the R help mailing list archive at Nabble.com.
__
R-help@r-project.org mailing li
Hello everybody,
Is it possible to coax legend() into displaying more than one simbol per
line in legend? I have a graph like the one attached to this mail; I would
like to reorganize the legend in such a way that the duplicate text would be
omitted, i.e., the first line would read "increasing
f
Hello,
I have a problem, when I run read.fasta.pdb I get this error:
pdb/seq: 1 name: dcluster.1
Error: subscript out of bounds
My FASTA file is the sequence of the bovine insuline.
Thanks in advance,
Rg
--
View this message in context:
http://n4.nabble.com/problem-with-bio3d-package-tp10121
Try this:
glm(y ~ ., family = binomial, data = data, ...)
On Tue, Jan 12, 2010 at 9:45 AM, npobedina wrote:
>
> Hi!
> I'm trying to run logistic regression on a dataset which is contained in
> dataframe "data" ("y" is in the first col, and 28 parameters for the model).
> How can I write formula
Hi!
I'm trying to run logistic regression on a dataset which is contained in
dataframe "data" ("y" is in the first col, and 28 parameters for the model).
How can I write formula for function `glm` without listing explicitly all 28
paramaters?
`glm(data[,1]~data[,2]+data[,3]+data[,4]+...,family=bin
I have noted that the later versions of Rcmd check cleans out the directory
pkg.Rcheck so that only package-manual.log and package-manual.pdf are left.
Formerly the package-manual.tex was around too --- very handy for various
purposes.
Is there a way to generate the .tex - version of the manual
On 12-Jan-10 14:00:24, ehcpieterse wrote:
> Thanks Ted, your solution does make perfect sense.
>
> The only question I still have is that I would like to sample
> the remaining 5 observations after I have randomly selected the
> first 10. Given the initial 10, I would like to sample the
> followin
On 1/12/2010 12:12 AM, Johannes Hüsing wrote:
Tal Galili schrieb:
My specific problem is called:
Minimum vertex cover for a hypergraph
I know nothing about the problem at hand, but on the Wikipedia
page it says that the problem can be formulated as an integer
linear program. There is an R pack
Dear Peter,
thank you for the suggestion.
Unfortunately the star did not help. Did it work for you? For me it seems
incomplete somehow.
Laetitia
From: Peter Ehlers [ehl...@ucalgary.ca]
Sent: Tuesday, January 12, 2010 09:54 AM
To: Laetitia Schmid
Cc: Steve
Would the following work, or is there a reason why it would not?
risk.set <- 1:100
first.10 <- sample(risk.set, 10)
remainder <- setdiff(risk.set, first.10)
for ( i in 1:1000 )
{
next.5 <- sample(remainder, 5)
do.something.with(next.5)
}
Best,
Magnus
On 1/12/2010 9:00 AM, ehcpiet
> "am" == alessia matano
> on Mon, 11 Jan 2010 16:20:57 +0100 writes:
am> Many thanks for it.
am> However it is strange that when I put the numbers rather than ncol(R)
am> (a matrix with ncol=36698) it worked. Look below
>> dim(res2)
am> [1] 170471 25822
>> D
Thanks Ted, your solution does make perfect sense.
The only question I still have is that I would like to sample the remaining
5 observations after I have randomly selected the first 10. Given the
initial 10, I would like to sample the following 5 say 1,000 times to get a
simulated conditional sa
Thanks Steve!
Muhammad Rahiz | Doctoral Student in Regional Climate Modeling
Climate Research Laboratory, School of Geography & the Environment
Oxford University Centre for the Environment
South Parks Road, Oxford, OX1 3QY, United Kingdom
Tel: +44 (0)
A few years ago, I work with Stuart Gage who had developed a Heat /
Precipitation Index as a measure of drought severity. It works just as
well if not better than the Palmer Drought Index.
You can find the formula in this only pdf report: Climate Variability in
the North Central Region:
http:/
Colleagues,
How i can solve this error when i install SJava package
Thanks
R CMD INSTALL -c /usr/local/lib/R/SJava_0.69-0.tar.gz
* installing to library ‘/usr/local/lib/R/site-library’
* installing *source* package ‘SJava’ ...
checking for java... /usr/lib/jvm/java-6-sun/bin/jav
On 12-Jan-10 12:58:13, ehcpieterse wrote:
> Hi,
>
> I am hoping someone can help me with a sampling question.
>
> I am using the following function to sample 10 unique observations:
> x <- sample(1:100, 10, replace=F)
> Given the first 10 observations, I need to sample another 5 unique
> observat
Pharmacokinetic and pharmacodynamic modeling and simulation
By Dr. Jan Freijer
March 18, 2010
Amsterdam, The Netherlands
http://www.can.nl/events/details.php?id=57
This course is aimed at users of R or S-PLUS in the bio-pharmaceutical
sciences who would like to use R for clinical trial s
See help(grepl) so using built in data frame CO2 this gets rows whose
Plant column start with Qn:
subset(CO2, grepl("^Qn", Plant))
On Tue, Jan 12, 2010 at 6:17 AM, Jean-Baptiste Combes
wrote:
> Hello,
>
> I use R 2.10, and I am new in R (I used to use SAS and lately Stata), I am
> using XP.
>
>
It's works perfectly ! ;) Thank you very much !!
M & A
On Tue, Jan 12, 2010 at 11:56 AM, Jim Lemon wrote:
> On 01/12/2010 09:41 PM, Mister Vanhalen wrote:
>
>> Hello,
>>
>> I have a graphic and I want to plot the yaxis AND ylab on the right.
>> I manage to plot axis on the right with axis(4) bu
Hi,
I am hoping someone can help me with a sampling question.
I am using the following function to sample 10 unique observations: x <-
sample(1:100, 10, replace=F)
Given the first 10 observations, I need to sample another 5 unique
observations from the remainder. I essentially want to do a Monte
Hi,
you can permute array dimensions using aperm():
x <- 1 : 24
z <- array(x, dim=c(6,2,2))
y <- aperm(z,perm=c(3,2,1))
y[1,1,]
HTH,
Stephan
Kohleth Chia schrieb:
Dear all,
When I coerce a vector into a multi dimensional array, I would like R to start
filling the array along the last dimen
Dear all,
When I coerce a vector into a multi dimensional array, I would like R to start
filling the array along the last dimension, then the 2nd last etc.
Let's jump straight into an example.
x <- 1 : 24
y <- array(dim=c(2,2,6))
I would like to have:
y[1,1,1] = 1
y[1,1,2] = 2
...
y[1,1,6] = 6
Hi,
Does anyone know a way to estimate the existence of a temporal trend (each unit
of the sample is a count) by resting the possible effect of a covariate (i.e.
climatic factor)?
I have periodical counts of several species of waterbirds during the last 13
years and I want to know if, resting
On Jan 12, 2010, at 6:17 AM, Jean-Baptiste Combes wrote:
Hello,
I use R 2.10, and I am new in R (I used to use SAS and lately
Stata), I am
using XP.
I have a data which has a data.frame format called x.df (read from a
csv
file). I want to take from this data observations for which the
Hi!
Jean-Baptiste Combes wrote:
> Hello,
>
> I use R 2.10, and I am new in R (I used to use SAS and lately Stata), I am
> using XP.
>
> I have a data which has a data.frame format called x.df (read from a csv
> file). I want to take from this data observations for which the variable
> "Code" sta
Hi Jean-Baptiste,
two points:
1) Your variable "df" is a *local* variable which you define in your
function myfunc(), so it is not known outside myfunc(). When you ask
is.data.frame(df), R looks at the global definition of df - which is the
density function of the F distribution. To make your
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