No, that's basically the solution I had already come up with (see the
last line of code from my original post)
but, Yes, I'm thinking this might be the simplest way (even though it
might not scale well to millions of elements )
On Dec 31, 1:17 pm, Dennis Murphy wrote:
> Hi,
>
> Is this what you
I am not too sure if this is what you are after, but I just created a new
factor for the panel:
# create a new factor
d1$newFactor <- factor(paste(d1$DS1, "+", d1$DS2, "+", d1$DS3))
xyplot(Y1+Y2+Y3~X1|newFactor,data=d1,group=ID)
On Thu, Dec 31, 2009 at 6:25 AM, Santosh wrote:
> Dear R experts,
On Dec 31, 2009, at 5:46 PM, William Dunlap wrote:
mytable$duration <- mytable$end_time - mytable$start_time
mytable
start_timeend_timeduration
1 2009-12-31 15:27:00 2009-12-31 15:27:00 0 secs
2 2009-12-31 16:27:00 2010-01-01 15:27:00 82800 secs
...
11 2010
> -Original Message-
> From: r-help-boun...@r-project.org
> [mailto:r-help-boun...@r-project.org] On Behalf Of Gabor Grothendieck
> Sent: Thursday, December 31, 2009 3:15 PM
> To: donahc...@me.com
> Cc: r-help@r-project.org
> Subject: Re: [R] iterating over a data frame the R way?
>
> Thi
This iterates functions f over successive rows of mytable:
apply(mytable, 1, f)
or if you want to use SQL on R data frames then see sqldf
http://sqldf.googlecode.com
On Thu, Dec 31, 2009 at 5:52 PM, wrote:
> In this specific case I'm going to do another select, from a different table
> with th
Bill Dunlap
Spotfire, TIBCO Software
wdunlap tibco.com
> -Original Message-
> From: r-help-boun...@r-project.org
> [mailto:r-help-boun...@r-project.org] On Behalf Of Peng Yu
> Sent: Thursday, December 31, 2009 2:16 PM
> To: r-h...@stat.math.ethz.ch
> Subject: [R] How x[, 'colname1'] i
In this specific case I'm going to do another select, from a different
table with the where clause being based on the start_time and end_time.
select * from table_name where time >= start_time and time <= end_time;
On Dec 31, 2009, at 3:57 PM, John Kane wrote:
Uh what do you want to do to i
On Fri, Jan 1, 2010 at 4:24 PM, milton ruser wrote:
> Hi Peng,
>
> If I undertood your point, try this:
>
> x<-runif(10)
> y<-runif(10)
> z<-runif(10)
> w<-runif(10)
>
> myDF<-data.frame(cbind(x,y,z,w))
> myDF
>
> myDF[,c("w","z")]
Thank you!
But this is not what I'm asking. I want to know how R
Hi Peng,
If I undertood your point, try this:
x<-runif(10)
y<-runif(10)
z<-runif(10)
w<-runif(10)
myDF<-data.frame(cbind(x,y,z,w))
myDF
myDF[,c("w","z")]
Happy new year
miltinho
On Thu, Dec 31, 2009 at 5:15 PM, Peng Yu wrote:
> I don't see where describes the implementation of '[]'.
>
>
I don't see where describes the implementation of '[]'.
For example, if x is a matrix or a data.frame, how the lookup of
'colname1' is x[, 'colname1'] executed. Does R perform a lookup in the
a hash of the colnames? Is the reference O(1) or O(n), where n is the
second dim of x?
__
baptiste auguie wrote:
> 2009/12/19 David Winsemius :
>> On Dec 19, 2009, at 9:06 AM, baptiste auguie wrote:
>>
>>> Dear list,
>>>
>>> In a little numbers game, I've hit a performance snag and I'm not sure
>>> how to code this in C.
>>>
>>> The game is the following: how many 8-digit numbers have t
Uh what do you want to do to it/them?
Here are a couple of R-type commands on a data.frame.
mydata <- data.frame(vec1 = seq(19,109, by=10),
vec2 =seq(30,120, by=10))
mydata[,1]+mydata[,2]
apply(mydata, 2, mean)
--- On Thu, 12/31/09, donahc...@me.com wrote:
> From: donahc...@me.com
> Su
Hi,
Is this what you wanted?
untable <- function(tab) rep(names(tab), as.vector(tab))
lapply(my.table.list, untable)
$x
[1] "a" "a" "b" "b" "c"
$y
[1] "a" "a" "b" "c" "d" "d"
$z
[1] "c" "d" "d"
HTH,
Dennis
On Thu, Dec 31, 2009 at 12:37 PM, david.schruth wrote:
> Hello,
>
> I'm trying to co
I am creating a lattice plot with
with(ordgdp, xyplot(delivery~AAR | GDP_ID, xlab="AAR", ylab="Actual
Arrival Rate"))
which works, and gives me 48 plots, one for each GDP_ID.
But I would like to put the number of hours that each GDP lasted on the
relevant plot. This is given by the following table
Hello,
I'm trying to construct an overall summary table from a list of
tables.
my.list <- list(x=c('a','b','a','b','c'), y=c
('a','d','c','a','b','d'),z=c('d','d','c'))
my.table.list <- lapply(my.list, table)
normally this might be really easy:
master.table <- table(unlist(my.list))
But as it
Happy New Year everyone.
I have what I hope is a simple-to-answer question. In the code sample
below, I'm using a tile plot to plot a continuous measure and overlaying the
plot with labels. I need to print the labels in courier, but there appears
to be no way to override the default font setting
You might want to be more specific about what you (exactly) intend to
do. Reading the posting guide might help you get better answers.
There are a few packages and functions to do what (I think) you
desire. There is the train function in the caret package, the errorest
function in ipred and
Hi,
I have a data frame that was create by issuing a select against my
sqlite database. I want to get each row from the data frame and use
the each of the column values. The data frame looks like this:
start_timeend_time
09:30:00 10:00:00
10:00:01 10:30:00
etc
Can a point m
To heck with print(), use R's debugging capabilities instead:
trace ( minBMI, browser )
Be sure to ?trace and ?browser so you can figure out how to
interactively debug.
Eric
On 12/31/09 6:29 AM, John Sorkin wrote:
I have written a function that contains runs
lm()
vif() and
glm()
When th
In the meantime, try this.
library(XML)
theurl <- "http://www.aarresaari.net/jobboard/jobs.html";
download.file(theurl, "tmp.html")
txt <- readLines("tmp.html")
txt <- htmlTreeParse(txt, error=function(...){}, useInternalNodes = TRUE)
g <- xpathSApply(txt, "//p", function(x) xmlValue(x))
head(grep
> -Original Message-
> From: r-help-boun...@r-project.org
> [mailto:r-help-boun...@r-project.org] On Behalf Of John Sorkin
> Sent: Thursday, December 31, 2009 6:30 AM
> To: r-help@r-project.org
> Subject: [R] Obtaining partial output from a function that
> does not run to completion.
>
>
Thanks, looking forward to that!
Happy New Year!
-Lauri
2009/12/31 Duncan Temple Lang :
> Hi Lauri.
>
> I am in the process of making some changes
> to the encoding in the XML package. I'll take a look
> over the next few days. (Not certain precisely when.)
>
> D.
>
>
>
> Lauri Nikkinen wrote:
>
Try to not use 'attach', or if you do, at least do a 'detach'. Use 'with'
or just fully qualify the names. 'attach' can lead to other problems.
Every time you use it, you will get similar messages.
On Thu, Dec 31, 2009 at 10:50 AM, Gerald I. Evenden <
geraldi.even...@gmail.com> wrote:
> I do no
John Sorkin wrote:
Duncan,
Thank you, however, if you will look at my function (bottom of this Email
message), you will see that I have used print(). It appears that the print
function is not run until the entire function completes running.
No, statements are run in the order you give them
I do not know if I have a problem or not.
The R script at the end of this email seems to
run properly and a I get a boxplot that looks
proper but I get the long string of messages
during execution of the script looking like:
...
The following object(s) are masked from dat ( position 8 ) :
Hi Lauri.
I am in the process of making some changes
to the encoding in the XML package. I'll take a look
over the next few days. (Not certain precisely when.)
D.
Lauri Nikkinen wrote:
> Hi,
>
> I'm trying to get data from web page and modify it in R. I have a
> problem with encoding. I'm no
Duncan,
Thank you, however, if you will look at my function (bottom of this Email
message), you will see that I have used print(). It appears that the print
function is not run until the entire function completes running.
John
John David Sorkin M.D., Ph.D.
Chief, Biostatistics and Informatics
On Dec 31, 2009, at 8:29 AM, John Sorkin wrote:
I have written a function that contains runs
lm()
vif() and
glm()
When the glm() blows up with an error message, I don't get the
output from either the lm() or vf() even thought neither lm() nor
vif() have any problems . How can I force the
On 31/12/2009 9:29 AM, John Sorkin wrote:
I have written a function that contains runs
lm()
vif() and
glm()
When the glm() blows up with an error message, I don't get the output from
either the lm() or vf() even thought neither lm() nor vif() have any problems .
How can I force the function
Shall we assume that you are using a Mac? If so what version? This
information would be neatly summarized if you posted the results of
sessionInfo().
Using my web-browser I find there is no directory at R-Forge with this
name:
http://R-Forge.R-project.org/bin/macosx/universal/contrib/2.10
I have written a function that contains runs
lm()
vif() and
glm()
When the glm() blows up with an error message, I don't get the output from
either the lm() or vf() even thought neither lm() nor vif() have any problems .
How can I force the function to print sequential results rather than wait
Thanks Brian,
> This is as documented on the help page for Ops (the page in base, not
> the one in Methods) which is linked from ?"|". For background you
> should also read the reference on that help page.
Unfortunately I have no access to that book.
> You are wrong in asserting that the inte
Hello,
When I install the package Rsafd, I get the following message.
> install.packages("Rsafd",repos="http://R-Forge.R-project.org
",dependecies=TRUE)
Warning in install.packages("Rsafd", repos = "http://R-Forge.R-project.org";,
:
argument 'lib' is missing: using '/Users/aajd/Library/R/2.10/l
Hello everyone,
I have a question about trees. I am writing my own clustering
algorithm in R and I would like to save results to a tree, so that I
could print it, just like hclust does.
Basically this is agglomerative method for networks/matrices (I am
writing it all on matrices, so no network pa
Hi,
I'm trying to get data from web page and modify it in R. I have a
problem with encoding. I'm not able to get
encoding right in htmlTreeParse command. See below
> library(RCurl)
> library(XML)
>
> site <- getURL("http://www.aarresaari.net/jobboard/jobs.html";)
> txt <- readLines(tc <- textConn
Dear R experts,
Wish you all a HAPPY NEW YEAR!
How do I go about plotting (using lattice) overlays of an ID (group=ID)
observed, fitted data in each panel of a multiple panel plot (each panel
identified by DS1 + DS2 + DS3)? "x" variable is X1 in the accompanying
section of a dataset. each individu
Peter Ehlers wrote:
actual_mean <- mean( range)
actual_sd <- sd( range)
expected_mean <- 218.213483146067
expected_sd <- 159.277118043936
...
Your code is not reproducible, but it seems fairly clear
that you haven't yet read the help pages for identical()
and all.equal(); or, if you have, you
Dear Steve,
If I undertood you have a list of "data.frame"?.
Have you tried:
NewData<-rbind(data.frame(myData[1]),data.frame(myData[2]))
Please, send us a str(object) so the experts can help you
bests
milton
On Thu, Dec 31, 2009 at 1:05 AM, stevemew wrote:
>
> My "R" problem..
>
> I want
My "R" problem..
I want to join two lists but am so for not having any luck. Can anyone
assist ?
Variable: myData[1]
"Data.Id" "Data.Length" "Data.Weight"
"1" 12 12
"2" 45 23
Variable: myData[2]
"Data.Id"
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