i had some great success with mosiacplots...
http://stat.ethz.ch/R-manual/R-patched/library/graphics/html/mosaicplot.html
http://stat.ethz.ch/R-manual/R-patched/library/graphics/html/mosaicplot.html
...does anyone know of any other hidden gems out there that allow you to
examine the relationshi
Evidently it just needed a little more tweaking...
http://n2.nabble.com/Need-help-solving-the-unexpected-string-constant-error-td4077984.html#a4078425
Hopefully all this will work out...
- Original Message
From: Jason Rupert
To: R-help@r-project.org
Sent: Fri, November 27, 2009 6:1
My apologies to all of you. I sent this email to the wrong email list :)
Best,
Jorge
2009/11/27 Jorge Ivan Velez <>
> Buenas noches César,
>
> Tal y como se estipula en la sección 8.1 de [1], la R 32-bits funciona en
> Windows 64-bits aunque con las limitaciones de RAM que todos conocemos (sol
yeah, my mistake is that i did not make the data "c" into a zoo class.
now the problem solved.
thank you everybody
2009/11/27 Gabor Grothendieck
> We will need a minimal reproducible example (as per last line on every
> message to r-help) to answer as trying it with made up data seems to
> work
On Nov 27, 2009, at 9:39 PM, David Winsemius wrote:
I get a different result, undoubtedly because I have different
packages loaded:
> showMethods(plot)
Function "plot":
> sessionInfo()
R version 2.10.0 Patched (2009-10-29 r50258)
x86_64-apple-darwin9.8.0
locale:
[1] en_US.UTF-8/en_US.UTF
I get a different result, undoubtedly because I have different
packages loaded:
> showMethods(plot)
Function "plot":
> sessionInfo()
R version 2.10.0 Patched (2009-10-29 r50258)
x86_64-apple-darwin9.8.0
locale:
[1] en_US.UTF-8/en_US.UTF-8/C/C/en_US.UTF-8/en_US.UTF-8
attached base packages
Peng Yu gmail.com> writes:
>
> I want an 'apply' function that can give me results by bind the result
> from each function call of g. Could somebody let me know how to do it?
>
> g<-function(x){
[snip]
> }
>
> x=1:3
>
> sapply(x,g)
do.call(rbind,sapply(x,g))?
I'm not a programmer either, if by "programmer" you mean one who took
a computer science degree and is employed with some title that implies
a creator of code. I am a user of software toward particular purposes.
The purposes need to be defined in sufficiently specific manner to
guide that
Buenas noches César,
Tal y como se estipula en la sección 8.1 de [1], la R 32-bits funciona en
Windows 64-bits aunque con las limitaciones de RAM que todos conocemos (solo
puedes usar hasta 4 GB de RAM en el mejor de los casos). Para instalarlo
sólo descarga el ejecutable usual de CRAN, haz doble
I want an 'apply' function that can give me results by bind the result
from each function call of g. Could somebody let me know how to do it?
g<-function(x){
if(x==1){
rbind(c(1,3,8))
} else if(x==2) {
rbind(c(4,7,2), c(3,7,3)) #if I use line, sapply() below gives me a list
#rbind(
I posted the full extent of this question to Nabble, but essentially I'm having
difficulty determining the route cause of the "unexpected string constant"
error in the zp2ssg2.R (which I'm trying to port over from Octave).
Here is my current Nabble posting:
http://n2.nabble.com/Need-help-solvi
Dear All,
I am looking at discriminating among several individuals based on a few
variable sets (I think some variables do not make sense unless they are
entered together, so I "force" them into the models together, hence
datasets). I have done so with linear discriminant analysis (LDA) using
Dear R-Users!
The most recent entries on orthogonal regression that I have found on
this list date back to 2005.
Is there, by now, any package available that allows for a multivariate
orthogonal regression in R?
Thanks and best regards.
Georg
georg.blind at gmx.net
_
The following I do not understand, but then I did'nt really use
S4 methods ...
> showMethods(plot)
Function: plot (package graphics)
x="ANY"
x="lmList.confint"
x="merMCMC"
(inherited from: x="ANY")
> plot(x=moda0MCMC)
Error in as.double(y) :
cannot coerce type 'S4' to vector of type 'double
I'm not entirely sure I understand the problem, but one possible solution
would be to use some device like postscript that saves the graphics to a
file. (Or some other device appropriate for your intended use and OS.)
You could still save the data to a list if you wanted - just make it part
of wha
On Thu, Nov 26, 2009 at 6:56 PM, David Winsemius
wrote:
http://old.nabble.com/Export-kde-object-as-shapefile-tp26532782p26545381.html
Sent from the R help mailing list archive at Nabble.com.
__
R-help@r-project.org mailing list
https://stat.ethz.ch/ma
Hi Luis.
You can change the two lines
PROBLEM buf
WARN;
to the one line
warning(buf);
That should compile.
If not, please show us the compilation command for DocParse.c, i.e. all the
arguments
to the compiler, just above the error messages.
D.
Luis Tito de Morais wrote:
> Hi list,
Hi all,
I'm new to R. Having a functional background, I was wondering what's
the idiomatic way to iterate. It seems that for loops are the default
given there's no tail-call optimization.
I'm curious to know whether there is a way to transform the following
toy snippet into something that doesn't
Or Duek wrote:
Hi,
I just started with R and I found that there are many options to rearrange
the data to do mixed models.
I want to use the reshape function. I have 2 between subject variables and
one within.
I was able to change the data structure but still - the result of the aov
functions are
Hi list,
It may be a FAQ, but I searched the web and Uni of Newcastle Maths and Stats and
R mailing list archive on this issue but was unable to find a solution. I would
appreciate any pointer to help me solving this.
I am using R version 2.10.0 (2009-10-26) on linux mandriva 2010.0
I tried to i
Hello,
After some research, I didn't resolve my doubt yet...
Maybe I didn't explain very well my question... So, I have a bootstrap
simulation, but suppose just a simple part of my function:
teste <-function(x){
rw_mean_app<-rnorm(x, mean = 10, sd = 2)
rwy_mean_app<-rnorm(x, mean = 10, sd = 2)
rw
matritz[is.na(matritz)] <- 0
On Fri, Nov 27, 2009 at 04:15:45PM -0200, Romildo Martins wrote:
> Hello,
>
> how to replace the "NA" by number zero?
>
> > matrizt
> [,1] [,2] [,3][,4]
> [1,] 1.000NA NA NA
> [2,] 0
Hi,
I just started with R and I found that there are many options to rearrange
the data to do mixed models.
I want to use the reshape function. I have 2 between subject variables and
one within.
I was able to change the data structure but still - the result of the aov
functions are calculating ever
> -Original Message-
> From: r-help-boun...@r-project.org
> [mailto:r-help-boun...@r-project.org] On Behalf Of SJ Robson-Davis
> Sent: Friday, November 27, 2009 8:52 AM
> To: r-help@r-project.org
> Subject: [R] Modular inverses
>
> I want to find the inverse of an integer k mod p (prime.)
Hi,
Try this,
matrizt[is.na(matrizt)] <- 0
HTH,
baptiste
2009/11/27 Romildo Martins :
> Hello,
>
> how to replace the "NA" by number zero?
>
>> matrizt
> [,1] [,2] [,3] [,4]
> [1,] 1.000 NA NA NA
> [2,] 0.6717685 0
Hello,
how to replace the "NA" by number zero?
> matrizt
[,1] [,2] [,3][,4]
[1,] 1.000NA NA NA
[2,] 0.6717685 0.1453253 NA NA
[3,] 0.3971276 0.1493241 0.14532526 NA
[4,] 0.1493241 0.1453
Hi David,
Thank you for the response.
I forgot to mention that I'd already tried what (I think) you propose
(adding ".form" to the end of the "lag", "log" and "diff") and I still
see the same results (posted below). Specifically, I still see no
lags, logs or diffs in my model.
Any other ideas?
On Nov 27, 2009, at 12:04 PM, Owen Powell wrote:
Hi David,
Thank you for the response.
I forgot to mention that I'd already tried what (I think) you propose
(adding ".form" to the end of the "lag", "log" and "diff") and I still
see the same results (posted below). Specifically, I still see no
I want to find the inverse of an integer k mod p (prime.) Is there a
function that can do this for me? I know i could simply write (k^(p-2)) %%
p, but i need to do this for large primes (above 100) and this gives the
warning message:
Warning message:
probable complete loss of accuracy in modulus
so
You might also note that the authors hint on the help page that one
might want to use the formula() operation on the result of dynformula.
Following that path would have gotten us to a more successful
conclusion.
> grun.fe <- plm(formula = formula(a),data=EmplUK)
> grun.fe
Model Formula: l
Great! That did the trick, thanks David.
To summarize for the list, to get "dynformula" to work (example):
R> a =
dynformula(emp~wage+capital,log.form=list(capital=FALSE,TRUE),lag.form=list(emp=2,c(2,3)),diff.form=list(FALSE,capital=TRUE))
it might be necessary to use:
R> plm(formula = formula
Morning folks (at least here on the western side of the U.S.)...
This morning I constructed a contour plot of some bivariate
distributions I'm working with. When I attempted to add a second
contour to the plot using a dashed line (lty=2), R immediately went
off to la-la land, requiring a f
> -Original Message-
> From: r-help-boun...@r-project.org
> [mailto:r-help-boun...@r-project.org] On Behalf Of Rob Steele
> Sent: Thursday, November 26, 2009 8:03 AM
> To: r-h...@stat.math.ethz.ch
> Subject: [R] Best way to preallocate numeric NA array?
>
> These are the ways that occur t
Erm... Maybe the sequence bit wont work ... A bit hasty there
And also the length check should be
if (length(x) != length(y) & !(length(x) == 1 | length(y) == 1)) stop
("inputs not compatible") # or something
I missed out the not!
-Original Message-
From: r-help-boun...@r-project.org
Hi,
You would also make your code more efficient and possible more readable
by doing
ReturnsGrid <-
function(x, y, m)
{
x + (seq.int(m) - 1) * (y - x) / m
}
(xx <- ReturnsGrid(0, 9, 3))
#[1] 0 3 6
And if you want to supply vector x and y you could do something like
(there are probably better
> I wonder how efficiently it is to do the following command on a frequent
> basis.
> nrow(matFF) <- nrow(matFF)+1
Obviously there is overhead (closing file, enlarging file, openeing file).
I recommend you measure yourself whether this is acceptable for you.
> no large file copying is needed ea
> My script generates a mixture of normal and ff objects.
> Very often I would like to save the workspace for
> each parameter setting, so that I can get back to it later on.
> Is there an easy way to do this,
> instead of needing to save individual ff objects separately?
With one save() you c
> The substitute() function can do it, but the bquote() function is the most
> convenient:
>
>> foo <- function(s) {
> + bquote(expression({
> + v <- .(s)
> + print(v)
> + }))
> + }
>> foo(10)
> expression({
> v <- 10
> print(v)
> })
>
> Duncan Murdoch
>
Thanks, after sending this em
Hi all,
I'm trying my best in changing the names of my experiments in the spectral
map.
My experiments are from six different time points, two as control and two
treated experiments.
I set have for each time point a different color .
Now I want to change the symbols so that I have for the treated
I'm not sure what you mean by 'multiplying by 10 and rounding'. I've tried to
re-organize the data and then create a ts object that is analogous to the
various sunspot datasets provided in the data package with R, but the matrix I
generate by binning the data into centuries (which would make th
Thanx.
I'll just post in here the way I solved it in case someone happens to
need something similar in the future. It may not be the most elegant
way, but it worked!
yes = "small"
no = "large"
data3$group = ifelse(data3$SIE < 50.64593,yes,no)
Peter Ehlers wrote:
Peter Ehlers wrote:
Vitória
Hi,
If you execute the following code it works but I wouldn't use grid if I
were you as a vector as this name is already used by R (check
help(grid)) and it explains why you have to define it in the function.
ReturnsGrid = function(x,y,m){
grid <- numeric(m)
for (i in 1:m){
grid[i] <- x + (
On 27/11/2009 11:04 AM, Saptarshi Guha wrote:
Hello,
I have a function that creates an expression object with some variables
substituted e.g
foo <- function(s){
expression({
v <- s
print(v)
})
}
Thus foo returns an expression, however the expression has the symbol 's'
contained with
Hi,
The error message,
Error in grid[i] <- x + (i - 1) * (y - x)/m :
object of type 'closure' is not subsettable
indicates that "grid" is actually known to R as a function (type grid
to see its definition). You can define your own variable with the same
name, but that needs to be done before t
Hi,
You need to create the grid object before you can assign values to it. Try
ReturnsGrid = function(x,y,m){
grid <- numeric()
for (i in 1:m){
grid[i] <- x + (i-1)*(y-x)/m
}
grid
}
On Fri, Nov 27, 2009 at 11:00 AM, Anastasia wrote:
> Hello,
>
> I am new to R program, therefore, I am sorry i
Duijvesteijn, Naomi wrote:
Hi R-ers,
I am struggling with my x-axis in a association plot. What I would like is
to place the labels of the x-axis between the tick markers and normally the
labels are printed at the place where the tick marker is placed. I don’t
want to move the
Hello,
I have a function that creates an expression object with some variables
substituted e.g
foo <- function(s){
expression({
v <- s
print(v)
})
}
Thus foo returns an expression, however the expression has the symbol 's'
contained within it and thus returns an error when eval'd e.g
On Nov 27, 2009, at 10:25 AM, ram basnet wrote:
Dear all,
I have querry on how to extract the data by matching between two
data set where one has the same elements multiple times?
For example, I have two matrix X and Y.
X
[,1][,2] [,3]
1 A 5 P
2 B 6
Hello,
I am new to R program, therefore, I am sorry if this is a really stupid
question.
I wrote a simple function and for some reason it doesn't work
ReturnsGrid = function(x,y,m){
for (i in 1:m){
grid[i] <- x + (i-1)*(y-x)/m
}
grid
}
xx=ReturnsGrid(0,9,3)
Thanks a lot!
[[alternati
On 11/27/2009 10:25 AM, ram basnet wrote:
> Dear all,
> I have querry on how to extract the data by matching between two data set
> where one has the same elements multiple times?
>
> For example, I have two matrix X and Y.
>> X
>[,1][,2] [,3]
> 1 A 5 P
> 2 B 6
Dear all,
I have querry on how to extract the data by matching between two data set where
one has the same elements multiple times?
For example, I have two matrix X and Y.
> X
[,1] [,2] [,3]
1 A 5 P
2 B 6 P
3 C 7 P
4 D 5 Q
5 E
On Nov 27, 2009, at 10:25 AM, Owen Powell wrote:
Hello list,
I'm following the paper (http://www.jstatsoft.org/v27/i02/paper) on
how to use "plm" to run panel regressions, and am having trouble with
what I believe should be something very basic.
When I run the command (p.9 in the paper):
R>
Hello list,
I'm following the paper (http://www.jstatsoft.org/v27/i02/paper) on
how to use "plm" to run panel regressions, and am having trouble with
what I believe should be something very basic.
When I run the command (p.9 in the paper):
R>
dynformula(emp~wage+capital,log=list(capital=FALSE,TR
On Nov 27, 2009, at 9:55 AM, chris carleton wrote:
Hi All,
I'm trying to analyze some time series data and I have run into
difficulty. I have decadal sun spot data and I want to separate the
very regular periodic function from the trend and noise. I looked
into using stl(), but the freq
Hello list,
I'm following the paper (http://www.jstatsoft.org/v27/i02/paper) on how to
use "plm" to run panel regressions, and am having trouble with what I
believe should be something very basic.
When I run the command (p.9 in the paper):
R>
dynformula(emp~wage+capital,log=list(capital=FALSE,TR
Anastasia wrote:
> Dear all,
>
> I have the following problem which I cannot solve:
>
> data <- numeric (100)
> for (i in 1:100){
> p <- runif(1,min=0,max=1)
> data[i] <- rnorm(1,mean=2,sd=1)
> }
Er what is "p" doing in there. As far as I can see, you might as well do
data <- rnorm(200, 2,
Hi R-ers,
I am struggling with my x-axis in a association plot. What I would like is
to place the labels of the x-axis between the tick markers and normally the
labels are printed at the place where the tick marker is placed. I donât
want to move the tick marker (it gives the sw
Hi All,
I'm trying to analyze some time series data and I have run into difficulty. I
have decadal sun spot data and I want to separate the very regular periodic
function from the trend and noise. I looked into using stl(), but the frequency
of the time series data must be greater than 1 for s
Dear all,
I have the following problem which I cannot solve:
data <- numeric (100)
for (i in 1:100){
p <- runif(1,min=0,max=1)
data[i] <- rnorm(1,mean=2,sd=1)
}
ke <- density(data,bw="sj",n=61)
How can I now find the value of this density function for example ke(0),
ke(2) etc.
Maybe this is
On Nov 27, 2009, at 5:34 AM, Vitória Magalhães Piai wrote:
Hi,
I'm quite new using R and have got no one to help me get through it.
Hopefully someone can help me with one problem I've been struggling
with for the last hours!!
(Sorry if I'm using the wrong terminology as well!)
I have a d
I took the OP's variables, reversed the "direction" of the second y,
bundled them up in a dataframe and then assigned the grp. So starting
with the OP's code:
x<-seq(1,10,1)
y<-seq(1,10,1)
ci<-y*.10
ciupper<-y+ci
cilower<-y-ci
x2<-seq(1,5,.5)
y2<-seq(5, 1, -.5) #reverse second variable
ci2<-
Dear all,
A friend of mine requested me to analyze some data she has generated. I
am hoping for some advice on best way of properly analyzing the data as
I have never worked with such complicated or nested designs.
Here is the setup. She has taken material from 5 animals and each
material is
On Nov 26, 2009, at 3:23 PM, Jonhnny Weslley wrote:
I have a file in the following format:
Scenario1 Scenario1CIL Scenario1CIU Scenario2 Scenario2CIL
Scenario2CIU
60 57 62 45 48 50
110 101 111 51 50 52
120 117 122 64 62 66
192 190 194 79 75 79
where:
First column = Scenario1 mean value
Se
Peter Ehlers wrote:
Vitória Magalhães Piai wrote:
Hi,
I'm quite new using R and have got no one to help me get through it.
Hopefully someone can help me with one problem I've been struggling
with for the last hours!!
(Sorry if I'm using the wrong terminology as well!)
I have a data matrix
Vitória Magalhães Piai wrote:
Hi,
I'm quite new using R and have got no one to help me get through it.
Hopefully someone can help me with one problem I've been struggling with
for the last hours!!
(Sorry if I'm using the wrong terminology as well!)
I have a data matrix in which SIE is one of
Hi,
I have recently begun using the lattice package, and have been using
the wireframe command to visualise matrices which are model outputs. I
have been trying to plot two surfaces (from two matrices)
simultaneously in one panel, to visualise intersections etc., but
neither my attempts or trawlin
On Fri, Nov 27, 2009 at 9:21 AM, Peng Cai wrote:
> @ Peter: I got it, thanks a lot for all your help! And yes, as you said the
> "title" option in auto.key is redundant.
>
>
> @ All, Hi: I need to add percentage sign to y-axis labels (like 0%, 20%,
> ..., 100%). How can I get it. I'm using barchar
On Thu, Nov 26, 2009 at 6:22 AM, ychu066 wrote:
>
> i was trying to do a for loop for plotting the histograms , but it doesnt
> work properly
>
>> library(lattice)
>> columns <- 8:153
>> plots <- vector("list", length(columns))
>> j <- 0
>> for (i in columns)
> + {
> + plots[[ j <- j+1 ]] <- his
Thanks for the interesting reference to alphahull. It might be a good
starting point for placing e.g. a legend in a plot (I think the usual
techniques for this (gregmisc?) are a bit more brute-force.)
baptiste
2009/11/27 Kjetil Halvorsen :
> There is a package on CRAN implementing such an idea:
On Thu, Nov 26, 2009 at 12:09 AM, Titus Malsburg wrote:
> The documentation of xyplot could be improved here. It says:
>
> "If 'index.cond' is a list, it has to be as long as the number of
> conditioning
> variables, and the 'i'-th component has to be a valid indexing vector for
> the
> in
On Fri, Nov 27, 2009 at 1:13 AM, Kjetil Halvorsen
wrote:
> I think the subject says it all. I want to make a simple lattice plot,
> using xyplot with the
> argument type=c("l","a").
> The problem then is that in the resulting plot it is
> difficult/impossible to see which plot corresponds to t
See ?commandArgs
Also the getopt and optparse CRAN packages.
On Fri, Nov 27, 2009 at 4:20 AM, yonosoyelmejor
wrote:
>
> hello,I would like to ask a question,Is there any way to pass arguments to a
> script?I have this code:
>
> Invernadero<-read.table(file.choose(),header=T,sep=",")
>
> attach(In
hello,I would like to ask a question,Is there any way to pass arguments to a
script?I have this code:
Invernadero<-read.table(file.choose(),header=T,sep=",")
attach(Invernadero)
names(Invernadero)
Invernadero<-ts(Invernadero<-argument) //Here introduce the argument
plot(Hora,Invernadero,main=ar
Hi JorisMeys and thanks!
JorisMeys wrote:
>
> On Thu, Nov 26, 2009 at 1:04 AM, Tyler82
> wrote:
>>
>> Hi all!
>> I am working with R package cluster and I have a little problem:
>> let's say I have two datasets...first one ("A") is divided into 4
>> clusters
>> by means of Pam algorythm.
>> Le
Hi,
I'm quite new using R and have got no one to help me get through it.
Hopefully someone can help me with one problem I've been struggling with
for the last hours!!
(Sorry if I'm using the wrong terminology as well!)
I have a data matrix in which SIE is one of my variables. What I need to
Hi Brock,
Have you tried View() ?
Regards.
On Fri, Nov 27, 2009 at 7:46 AM, Brock Tibert wrote:
> Hi All,
>
> I am making a serious effort to try to learn R, but one hurdle I am facing
> is that I need to "see" the data as I walk through the examples in the
> packages. For instance, many exam
Hi all,
I have to ask this and I know that the reason is that I am a newbie with R
programming. So apologize if it is too obvious but I didn't find an answer
after googling and reading "An introduction to R". So i have return
data from 30 instruments and I am fitting a mixture of normal
distributi
Try this:
# each of these three show entire data set
wines
dput(wines)
View(wines)
# get help
?wines
# various info on data set
head(wines)
tail(wines)
summary(wines)
str(wines)
class(wines)
dim(wines)
# plotting
plot(wines)
# for a better plot see the example at the bottom of ?wines
On Thu, N
do you mind me asking what code you used to create that data frame and name
the groups 1 and 2?
David Winsemius wrote:
>
>
> On Nov 26, 2009, at 10:26 PM, Joe King wrote:
>
>> In the "filled bands" part of xYplot of the Hmisc package, is there
>> a way to
>> have multiple bands with multiple
Hello
On Fri, Nov 27, 2009 at 4:46 AM, Brock Tibert wrote:
> In short, I know that data() lists all of the available datasets,
> data("wines") will load the dataset wines, but how can I look at the raw data?
>
See this [1].
[1] http://www.mail-archive.com/r-help@r-project.org/msg66111.html
Livi
Are you using mgcv:::gam? To get plot data suitable for making plots of smooth
effects, you probably need to use `predict.gam' to evaluate the smooth curves
(and standard errors) at a nice regular set of points for plotting. Also
don't forget that the residuals shown on plot.gam are the `partial
Dear users,
I am struggling with this issue. I want to estimate a VAR(1) for three
variables, say beta1 beta2 beta3, using monthly observations from January
1984 to September 2009. In-sample period January 1984 to December 2003,
out-of-sample January 2004 to September 2009. This is what I have don
We will need a minimal reproducible example (as per last line on every
message to r-help) to answer as trying it with made up data seems to
work for me. If c is very long try cutting it down to the smallest
you can get it to and still produce the error, e.g.
cc <- c[1:10]
rollapply(cc, ...)
and
I'm curious about why no one has answered my question below. I
can't imagine it would be because no one knows how to answer, it
must be something basic I am ignorant about. But I have never seen
such a pattern, it seems strange to me that a class with an empty
definition is automatically virtua
Dear All,
At least in three different GNU/Linux systems, the parallel function
from the multicore package leaves defunct (zombie) R processes.
For instance
library(multicore)
parallel(1:5)
collect()
After collect, the child process (with pid as given by collect) is
left defunct. (If we run th
Hello,
I'm taking several physiological measurements on participants (e.g.,
skin conductivity, heart rate, etc.). I know that those participants
belong to one of three groups (from another measurement), and I'm
looking to find the physiological measurement that best describes
group membership. The
Hi
There is one issue which I encountered recently with this type of
behaviour,
mat<-matrix(NA,5,4)
fix(mat)
put some number in any cell and close fix
mat
col1 col2 col3 col4
[1,] NA NA NA NA
[2,] NA NA NA NA
[3,] NA NA NA NA
[4,] NA NA NA NA
[5,] NA N
Brock Tibert wrote:
Hi All,
I am making a serious effort to try to learn R, but one hurdle I am facing is that I need to
"see" the data as I walk through the examples in the packages. For instance, many
examples on the web start by a command like data("wines"). How can I actually view what
On Fri, 27 Nov 2009 15:19:11 +0800 Saji Ren wrote:
> I want to get a rolling estimation of the stdev of my data.
There is a 'runsd' in the 'caTools' package which does exactly this.
--
Karl Ove Hufthammer
__
R-help@r-project.org mailing list
https://
There are different ways to inspect the conent of a data frame. For example,
>View(CO2)
2009/11/27 Brock Tibert :
> Hi All,
>
> I am making a serious effort to try to learn R, but one hurdle I am facing is
> that I need to "see" the data as I walk through the examples in the packages.
> For i
, November 27, 2009 4:00 PM
To:
Cc: "Brock Tibert" ;
Subject: Re: [R] Learning R - View datasets
guohao.hu...@gmail.com wrote:
> Please check the following pdf file.
> http://tw.nextmedia.com/applenews/article/art_id/32119622/IssueID/20091127
>
Besides a beautiful blond gir
On Thu, 26-Nov-2009 at 11:03PM -0800, Julia Cains wrote:
|> Dear Sir,
|>
|> Thanks again for your help. Sir, actually I am working on a data containing
84 months and the corresponding savings (core) balances and non-core balances
and I am plotting a stacked bar.
|>
|> The original code I am us
guohao.hu...@gmail.com wrote:
> Please check the following pdf file.
> http://tw.nextmedia.com/applenews/article/art_id/32119622/IssueID/20091127
>
Besides a beautiful blond girl, I do not recognize any pdf here...
Could you provide a direct link?
Thanks!
mario
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